Answer:
Explanation:
work done per unit time is caleed power.it's SI unit is watt.it depends upon time.
To help the plant photosynthesize more, leaves and stems
grow
the light.
what is average velocity??
Answer:
The average velocity of an object is its total displacement divided by the total time taken. In other words, it is the rate at which an object changes its position from one place to another. Average velocity is a vector quantity.
Explanation:
Hope it helpsCan somebody please answer this correctly I will give brainliest
How is the annostructure on the chocolate related to the nanostructure of the grating?
help me plss:(
Answer:
From butter in croissants to cocoa solids in chocolate, edible fats pack a flavor punch that delights like no other macronutrient we consume. Fats are the most energy dense macronutrients, providing more than twice as many kilocalories per gram as proteins or carbohydrates, which may be the reason we've developed a taste for them.
Explanation:
pls help will mark brainliest, pls
Answer:
The answer is true. This is correct.
Who's Madame Marie curie?
Explanation:
In 1911, Marie was awarded a second Nobel Prize in Chemistry for her discovery of the elements polonium and radium. In honor of the 100-year anniversary of her Nobel award, 2011 was declared the "International Year of Chemistry."
What are the si units
Answer:
The uniy which is accepted all over the world is called SI unit.
Explanation:
The system of measurement that is agreed by the international convention if scientists that is held in paris of France to adopt an international unit is called SI unit unit.
Two arrows are shot vertically upward. The second arrow is shot after the first one, but while the first is still on its way up. the initial speeds are such that both arrows reach their maximum heights at the same instant, although these heights are different. Suppose the that initial speed of the first arrow is 34 m/s and that the second arrow is fired 0.204081632653061 seconds after the first. Determine the initial speed of the second arrow.
Answer:
The initial speed of the second arrow is 33.8 m/s.
Explanation:
initial speed of first arrow, u = 34 m/s
Let the initial height of the second arrow is h.
Let they both reaches at maximum height H.
Let the time taken by the first arrow is t and the second arrow is t - 0.0204
Let the initial speed of the second arrow is u'.
Use first equation of motion for the first arrow.
v = u - gt
0 = u - gt
34 = gt ..... (1)
For the second arrow
v =u' - g (t - 0.0204)
0 = u' - gt + 9.8 x 0.0204
u' = 34 - 0.1999 = 33.8 m/s
what is a product made from no renewable resources
Answer:
a nail
Explanation:
Answer:
crude oil, natural gas, coal, and uranium. These are all resources that are processed into products that can be used commercially.
Explanation:
On what factors does critical velocity depend on
Explanation:
The critical velocity is that velocity of liquid flow, up to which its flow is streamlined (laminar)& above which its flow becomes turbulent. It's denoted by Vc & it depends upon: Coefficient of viscosity of liquid (η) Density of liquid. Radius of the tube.
Cart A with a mass equal to 24 kg is moving to the right at 3.2 m/s. It collides with Cart B that
has a mass of 32 kg and is moving to the left with a velocity of 12.8 m/s. After the collision,
Cart A has a velocity of 2.9 meters per second to the left. What is the speed of the Cart B after
the collision?
Answer:
Explanation:
According to the Law of Momentum Conservation, what happens after the collision has to equal what happened before the collision because momentum cannot be created nor destroyed; it has to go somewhere else. Like energy eventually dissipates into heat. The equation for this is:
[tex][m_Av_A+m_Bv_B)]_b=[(m_Av_A+m_Bv_B)]_a[/tex] and filling in our info, calling right positive and left negative:
[(24(3.2) + 32(-12.8)] = [(24(-2.9) + 32(vB)] and
[(77 - 410)] = [(-7.0 × 10¹ + 32vB)] and
-330 = -7.0 × 10¹ + 32vB and
-260 = 32vB so
vB = -8.1 m/s Thus, cart B is moving to the left at a velocity of 8.1 m/s
(I used the rules for sig dig very intentionally and correctly; I'm not sure how strict your teacher is about them. I require my students to use the rules to perfection, as I did here.)
One twin sets off on a long space voyage traveling at 0.9 c, while the other stays on Earth. When she returns 60 years later, the traveling sister has hardly aged at all, while her twin has aged 60 years. Which aspect of relativity is demonstrated in this situation
Answer:
This is the twin paradox.
4. A girl is sitting on a tire swing that is attached with a rope that is 2.1 m in length. Her dad pushes her with a speed of 3.0 m/s. If the centripetal force is 88 N, what is the mass of the girl?
Define emf of a battery?
Answer:
Electromotive force or EMF is equal to the terminal potential difference when no current flows. EMF (ϵ) is the amount of energy (E) provided by the battery to each coulomb of charge (Q) passing through.
While traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. What is the automobile's acceleration? (Remember that a negative value indicates a slowing down or deceleration.) don't forget to write the formula(1pt.) and the unit (1pt.)
Answer:
Acceleration = -0.75 m/s²
Explanation:
Given the following data;
Initial velocity = 24 m/s
Final velocity = 15 m/s
Time = 12 seconds
To find the acceleration of the automobile;
Acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac {final \; velocity - initial \; velocity}{time}[/tex]
Substituting into the formula, we have;
[tex] Acceleration = \frac{15 - 24}{12}[/tex]
[tex] Acceleration = \frac{-9}{12}[/tex]
Acceleration = -0.75 m/s²
Therefore, the automobile is decelerating because its final velocity is lesser than its initial velocity, leading to a negative value.
particles that are found in the sun's plasma
Answer:
This plasma mostly consists of electrons
An elephant pushes with 2000 N on a load of trees. It then pushes these trees for 150 m. How much work did the elephant d
Answer:
300000
Explanation:
2000×150= 300000
Which of the following changes occurs during nuclear fission?
A. Energy is absorbed from the surroundings.
B. Atomic nuclei combine to form a larger nucleus.
C. Energy is converted into mass.
D.
The parent nucleus splits into lighter daughter elements.
Reset
Answer:
The parent nucleus splits into lighter daughter elements
Explanation:
Nuclear fission involves the splitting of nucleus of a lighter element with smaller particles
28. The mass of a steel building frame is 5500 kg. What power is used to raise it to a helght of 5.0 m If the work is done in 12.0 seconds?
Remember to include your data, equation, and work when solving this problem.
Answer:
2292W
Explanation:
Use the formula for energy first:
[tex]E=D*M[/tex]
Where E = Energy || D = Distance || M = Mass.
Solve that equation:
E = 5 * 5500 ==> 27500J
To find power, divide energy per time:
27500J / 12s =~ 2292W
Did it in a rush, any problems message me
As shown in the diagram below, a 1 kg rock tied to a rope is
swung by a boy. This rock has a constant speed of 5 m/s,
and the length of the rope is 1 m. The rock's angular
momentum is
Answer:
Explanation:
Angular momentum has a formula of L = mvr. Fillingin:
L = (1.0)(5.0)(1.0)
L = 5.0 kg*m/s
Given the following reactants, what are the most likely products?
A ball is dropped from rest out of a high window in a tall building for 5 seconds. Assuming we ignore air resistance and assume upwards to be positive. A) What will be the final velocity of the ball B) What is the height of the building if it hits the ground after those 5 seconds.
Answer:
what is the upwards force?
Answer:
final velocity=-49m/s and height=122.5
Explanation:
u=0,t=5s,v=?
v=u+gt
v=0+(-9.8)5
v=-49m/s
h=ut+1/2gt*2
h=0(5)±1/2(-9.8)5*2
h=-122.5 or 122.5
but height=122.5 because height cannot be negative
PLEASE HELP 40 POINTS
Liar, not even 40 points....
A 4kg and 5kg bodies moving on a frictionless horizontal surface at a velocity of ( -6i )m/s and ( +3 )m/s respectively. Collide a head on elastic collision. What is the velocity ( magnitude and direction) of the each body after collision?
Answer:
4 kg → +4 m/s
5 kg → -5 m/s
Explanation:
The law of conservation of momentum states that:
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'left side → velocities before collisionright side → velocities after collisionYou'll notice that we have two missing variables: v₁' & v₂'. Assuming this is a perfectly elastic collision, we can use the conservation of kinetic energy to set the initial and final velocities of the individual bodies equal to each other.
v₁ + v₁' = v₂ + v₂'Let's substitute all known variables into the first equation.
(4)(-6) + (5)(3) = (4)v₁' + (5)v₂' -24 + 15 = 4v₁' + 5v₂' -9 = 4v₁' + 5v₂'Let's substitute the known variables into the second equation.
(-6) + v₁' = (3) + v₂' -9 = -v₁' + v₂' 9 = v₁' - v₂'Now we have a system of equations where we can solve for v₁ and v₂.
-9 = 4v₁' + 5v₂' 9 = v₁' - v₂'Use the elimination method and multiply the bottom equation by -4.
-9 = 4v₁' + 5v₂' -36 = -4v₁' + 4v₂'Add the equations together.
-45 = 9v₂'-5 = v₂'The final velocity of the second body (5 kg) is -5 m/s. Substitute this value into one of the equations in the system to find v₁.
9 = v₁' - v₂'9 = v₁' - (-5) 9 = v₁' + 5 4 = v₁'The final velocity of the first body (4 kg) is 4 m/s.
We can verify our answer by making sure that the law of conservation of momentum is followed.
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂' (4)(-6) + (5)(3) = (4)(4) + (5)(-5)-24 + 15 = 16 - 25 -9 = -9The combined momentum of the bodies before the collision is equal to the combined momentum of the bodies after the collision. [✓]
(answer it or get reported) Please answer it w the steps
Answer;
The mass value for the above kinetic energy equation is 400.0000 kg. This is equal to:
■ 400,000.0000 g.
■ 14,109.6000 ounces.
■ 881.8480 pounds.
Determine the small gravitational force F which the copper sphere exerts on the steel sphere. Both spheres are homogeneous, and the value of r is 50 mm. Express your result as a vector.
Solution :
We know that the volume of sphere is given by :
[tex]$V=\frac{4}{3}\pi r ^3$[/tex]
Given r = 50 mm
The density of copper is :
[tex]$\rho_c = 8910 \ kg/m^3$[/tex]
The density of steel is :
[tex]$\rho_s = 7830\ kg/m^3$[/tex]
Therefore, mass of copper is :
[tex]$m_c= V . \rho$[/tex]
[tex]$m_c= \frac{4}{3} \pi (0.05)^3 \times 8910$[/tex]
= 4.665 kg
= 4665 g
Similarly, mass of steel is :
[tex]$m_s= V . \rho$[/tex]
[tex]$m_s= \frac{4}{3} \pi (0.025)^3 \times 7830$[/tex]
= 0.512 kg
= 512 g
Now the distance between the centers of the particles is by Pythagoras theorem,
[tex]$l^2=(4r)^2+(2r)^2$[/tex]
l = 4.472 x r
= 4.472 x 50
= 224 mm
= 0.224 m
From the law of gravitation,
We know, [tex]G = 6673 \times 10^{-11} \ m^3 / kg-s^2[/tex]
∴ [tex]$F=G\times \frac{m_c \times m_s}{l^2}$[/tex]
[tex]$F=6.673 \times 10^{-11}\times \frac{4.665 \times 0.512}{(0.224)^2}$[/tex]
[tex]$F = 3.176 \times 10^{-9} \ N$[/tex]
Now,
[tex]$\alpha = \tan^{-1} \left( \frac{2r}{4r}\right)$[/tex]
= [tex]$26.56^\circ$[/tex]
Therefore, we can write it in the vector form as
[tex]$\text{F}=F(-i . \cos \alpha - j. \sin \alpha)$[/tex]
[tex]$\text{F}=3.176 \times 10^{-9}(-i . \cos 26.56 - j. \sin 26.56)$[/tex]
[tex]$\text{F}=(-2.840\ i- 1.420 \ j) \times 10^{-9} \ N$[/tex]
5. Alex worked out for 4 hours and lost 3 lbs. during that time. What is the range of water that he should drink in ounces after his workout?
9 ounces bc if he does then he wont be so like ugh I'm out of wonder land yeah 9 ounces deffo
Find the temperature of a mixture obtained by mixing 32 grams of water at a temperature of 22 degrees Celsius with 88 grams of water at a temperature of 75 degrees Celsius.
Answer:
60.87 °C
Explanation:
Applying,
Heat lost = heat gain
cm'(t₂-t₃) = cm(t₃-t₁).............. Equation 1
Equation 1 can futher be simplified to
m'(t₂-t₃) = m(t₃-t₁)................Equation 2
Where m' = mass of the hot water, m = mass of the cold water, t₁ = initial temperature of the cold water, t₂ = initial temperature of the hot water, t₃ = temperature of the mixture.
From the question,
Given: m' = 88 g, m = 32 g, t₁ = 22°C, t₂ = 75°C
Substitute these values into equation 2
88(75-t₃) = 32(t₃-22)
6600-88t₃ = 32t₃-704
32t₃+88t₃ = 6600+704
120t₃ = 7304
t₃ = 60.87 °C
ACELLUS PHYSICS HELP!!
A 6.93*10-4 C charge has a potential energy U = -3.09 J at a point in space. What is the electric potential V at that point? Include the sign, + or - . (Unit = V)
Answer:
Potential difference, V = -0.000224 Volts
Explanation:
Given the following data;
Quantity of charge = 6.93*10-4 C
Energy = -3.09 J
To find the electric potential V at that point?
Mathematically, the energy transferred per unit of charge is given by the formula;
E = QV
Where:
E is the energy
Q is the quantity of charge
V is the potential difference.
Substituting into the formula, we have;
[tex] -3.09 = 6.93*10^{-4} * V [/tex]
[tex] V = \frac {6.93*10^{-4}}{-3.09} [/tex]
Potential difference, V = -0.000224 Volts
Choices:
A. Most kinetic energy and least potential energy
B. Most potential energy and least kinetic energy
C. Potential energy is equal to kinetic energy
D. Potential energy is increasing
E. Potential energy is decreasing
F. Kinetic energy is increasing
G. Kinetic energy is decreasing
Directions: Write one letter from the choices above in each of the spaces.
1. When the minion hits the ball at position one, what choices best describe the energy present. (choose 3)
___________, ___________, _____________
2. Position 2 (choose 2) ____________, ___________
3. Position 3 (choose 3) _____________, ____________, ______________
4. Position 4 (choose 2) ______________, _____________
5. Position 5 (choose 2) ______________, _____________
6. Positions 6 (right when the ball is about to touch the ground ___________, ____________, _____________
Answer:
I think there's a pdf for the questions you need
WorksheetKineticVsPotentialEnergy.pdf
Explanation: