Water (2470 g ) is heated until it just begins to boil. If the water absorbs 5.47x105 J of heat in the process,
what was the initial temperature of the water?
Express your answer with the appropriate units.

Answers

Answer 1

Answer:

47.01 °C

Explanation:

Q = mcΔt

Mass of water = 2470g

c or specific heat capacity of water = 4.18 J °C g

Q = 5.47 x 10⁵ J, which is expanded 547,000 J

No idea what Δt is, but we do know the water began to boil, and we know that water's boiling point is 100°C, so the final temperature had to be 100°C.

547,000 J = (2470) x (4.18) x (Δt)

Rearrange equation for Δt

(547,000) / (2470 x 4.18) = Δt

Δt = 52.98°C

But we're not done. We're trying to find the INITIAL TEMPERATURE of the water, not the TEMPERATURE CHANGE. We already have the final temperature, which is 100°C, and now we have how much the initial temperature rose by to get to 100°C.

All that we have to do now is 100 - 52.98 = 47.02°C

The initial temperature of the water is 47.02°C


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Answer:

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Here, this may help you:

https://brainly.in/question/28298343

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Which sub atomic particle always determines the elemental identity of an atom

Answers

Answer:

The proton determines the identity of an element.

It’s a proton hope this helps

Write the rate law for the following reaction given that the order of A = 2, B = 1, and C = 0. A + B + C ———> D + E

If the concentration of C is doubled, what will happen to the rate of the reaction?

Answers

Answer:

The rate law is:

[tex]\displaystyle \text{Rate} & = k[A]^2[B][/tex]

Doubling the concentration of C will have no effect on the rate of the reaction.

Explanation:

We want to write the rate law for the reaction:

[tex]\displaystyle A + B + C \longrightarrow D + E[/tex]

Where the order of A, B, and C are 2, 1, and 0, respectively.

The rate law will have the form:
[tex]\displaystyle \text{Rate} = k [A]^m[B]^n[C]^p[/tex]

Where m, n, and p are their respective order of reactions.

Hence, the rate law is:
[tex]\displaystyle \begin{aligned} \text{Rate} & = k[A]^2[B][C]^0\\ \\ & = k[A]^2[B] \end{aligned}[/tex]

Because the order of reaction to C is 0, changing its concentration will have no effect on the rate law.

Help please I’ll give 5 stars

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umm i really dont know it

What is the percent composition of each element in CaCO 3 ? ( Mass of Element divided by mass of Compound) x 100

Answers

Answer:

molar mass of CaCO3=40+12+3(16)

=100 gmol-1

Ca percent composition=40/100*100%

=40%

C percent composition=12/100*100%

=12%

0 percent composition=48/100*100%

=48%

Answer:

Since we're sticking with theoretical values instead of experimental, Percent Composition would be (Molar Mass of the element) / (Molar mass of compound) x 100%

Molar mass of Calcium: 40g/mol

Molar mass of Carbon: 12g/mol

Molar mass of Oxygen: 16g/mol

Molar mass of CaCO3 (Calcium Carbonate) = (40) + (12) + (16)*3 = 100g/mol

Percentage composition of Calcium = [tex]\frac{40}{100} \ * \ 100 =[/tex] 40% of Calcium

Percentage composition of Carbon = [tex]\frac{12}{100} \ * \ 100 =[/tex] 12% of Carbon

(For the next one, there are 3 oxygen, so it'd be 16x3 = 48g/mol)

Percentage composition of Oxygen = [tex]\frac{48}{100} \ * \ 100 =[/tex] 48% of Oxygen

A student investigates the motion of a toy vehicle. The student graphs 40 seconds of data from the investigation.



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The vehicle was traveling at a constant speed.

The vehicle was accelerating at a constant rate.

The speed of the vehicle was increasing.

The acceleration of the vehicle was increasing.

Answers

Although we do not have the graph needed to answer this question, we can confirm that if the toy were to be accelerating, one should see this on the graph as a curved line.

How can we know if the toy was accelerating?

When graphing motion in terms of distance over time, we can use the shape of the line in the graph to determine if the speed is constant or if there is an acceleration present. If the line is straight, the speed is constant, but if there is a curve, there will be acceleration.

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Answer:

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what is one advantage of using a computer over a graphic calculator?

Answers

Answer:

Computers are more useful for quick calculations.

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give brainliest pls

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Answers

Answer:

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2. What is the common name for NH3?

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Scientific knowledge be used to solve a practical problem through all of the above which are:

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Answers

Answer:

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Answers

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here

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Answer:

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hope it helps,God bless

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Answers

Answer:

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explain how matter and energy cycle through the Chaparral

Answers

Answer:

the scrubby plants in the chaparral biome fix CO2 from the atmosphere through photosynthesis and store carbon as starch. The energy from these carbohydrates is passed on to animals and insects that consume the plants. These primary consumers will pass on the carbon’s energy to other animals that prey on them. When plants or animals die and decompose, the carbon in their bodies returns to the earth. Fossil fuels, which are made from ancient decomposed matter, release carbon back into the atmosphere as CO2 when they are burned

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True or false?

Answers

False because a outer shell does not have protons and 10 elections

Suppose we redefine the standard state as P= 2 bar . Find the new standard ΔfG∘ values of the following substances.
a) HCl(g)
b) N2O(g)
c) H(g)

Answers

We have that the new values of the following substances HCl(g), N2O(g), H(g) is that the remain the same as

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Standard ΔfG∘ values of substances.

Question Parameters:

s P= 2 bar

HCl(g)

N2O(g)

H(g)

Generally the equation for the Change in Heat energy  is mathematically given as

dG=dH-TdS

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dH=CpdT

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Hence, dG=dH-TdS remains the same

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The second law of thermodynamics states that all energy transformations result in an increase in entropy (disorder). If so, how does photosynthesis, which is an energy transformation, create order rather than disorder

Answers

Answer: Through photosynthesis carbon dioxide and water is converted to glucose which is more ordered.

Explanation:

Besides that initial consideration there is solar energy being added to the reaction which might be worth noting.

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A student had a 15 cm long glass stirring rod with a density of 1.500 g/cm3. They
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Answers

The density of the larger broken piece from the original piece would remain 1.500 g/cm3

Density

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The ratio of mass to the volume of a substance is constant.

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