Frederick Taylor created a series of guidelines known as the "motion study principles" to boost productivity at work. Time study, motion study, fatigue study, etc technique conduct research are the four divisions into which they fall.
What is motion study principles?Motion studies are the study of actions like lifting, putting things down, standing, changing direction, and other actions that are made when performing routine work.
In order to execute the task effectively in less time, unnecessary moves are attempted to be removed. The following three headings comprise the fundamentals: Making use of the human body. The layout of the workplace. Machinery and tools design.
Motion study principles will be the which will help in designing or putting films into a particular order. Also how the routine works are being made is suggested.
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1)A wheel is used to turn a valve stem on a water valve. If the wheel radius is 1 foot and the stem, (axle), radius is .5 inches, what is the mechanical advantage of the wheel and axle? 2)How much resistance force can ideally be overcome when an effort of 80 lbs is applied to the wheel of the water valve in problem 1? 3)What is the linear distance traveled when a 2.5' diameter wheel makes one revolution? 4)A compressor motor has a 1.00 inch output shaft (axle) that drives a 4.00inch pulley (wheel). If the motor output shaft supplies 24 lbs of force, ideally how much force does the pulley apply to the drive belt wrapped around it? 5) If the belt pulley's force is measured to be 4 lbs, what is the AMA wheel and axle here?6) What is the efficiency of the compressor motor – belt pulley wheel and axle?
Answer:
for 13
Explanation:
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Complete the sentence to identify a useful advance in the culinary arts.
The Egyptians invented
, which they used to store
for many years.
Answer:
silos to store grains
Explanation:
I got it from PLATO... hope this helps...
A broad range of subjects are included in the culinary arts. Food science and nutrition, ingredient quality, seasonality, flavors and textures, presentation and plate layout, and more are some of these. There are numerous specialties, sub-niches, and job titles that fall within this broad category.
What are the characteristics of culinary arts?Additionally, to help students become more well-rounded cooks, a variety of cooking techniques, numerous recipes, new ingredients, and various flavor profiles are presented to them.
The term “culinary arts” is used to refer broadly to the processes involved in preparing, cooking, plating, presenting, and serving food. It relates to meals and the goods, not sweets or breads. That make up a meal, such as appetizers, side dishes, and main courses.
Therefore, Students who pursue a culinary education have the opportunity to study under several of the industry's best chefs.
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Water and air quality are critical issues facing human society.
True
False
Humans impact the physical environment in many ways: overpopulation, pollution, burning fossil fuels, and deforestation. Changes like these have triggered climate change, soil erosion, poor air quality, and undrinkable water.
definition of ceramics
Answer:
Ceramics are generally made by taking mixtures of clay, earthen elements, powders, and water and shaping them into desired forms. Once the ceramic has been shaped, it is fired in a high temperature oven known as a kiln. Often, ceramics are covered in decorative, waterproof, paint-like substances known as glazes.
Explanation:
Answer:
made essentially from a nonmetallic mineral (such as clay) by firing at a high temperature.
Explanation:
When block C is in position xC = 0.8 m, its speed is 1.5 m/s to the right. Find the velocity of block A at this instant. Note that the rope runs around the pulley B and a pin attached to block C, as indicated.
Answer:
The answer is "2 m/s".
Explanation:
The triangle from of the right angle:
[tex]\to (x_c-0.8)+(1.5+y_4) +\sqrt{x_c^2 + 1.5^2}= constant[/tex]
Differentiating the above equation:
[tex]\to V_c +V_A+ \frac{X_cV_c}{\sqrt{x_c^2 +1}}=0\\\\\to 1-V_A+ \frac{0.8 \times 1.5}{\sqrt{ 0.8^2+1.5}}=0\\\\[/tex]
[tex]\to V_A= \frac{1.2}{\sqrt{ 0.64+1.5}}+1\\\\[/tex]
[tex]= \frac{1.2}{ 1.46}+1\\\\= \frac{1.2+ 1.46}{ 1.46}\\\\ = \frac{2.66}{1.46}\\\\= 1.82 \ \frac{m}{s}\\\\= 2 \ \frac{m}{s}[/tex]
what is 2+2 equal to
Answer:
4
or
22
Explanation:
how to update android 4.4.2 to 5.1 if there isnt any update available
Answer:
You cant update it if there isin´t any update available lol
Explanation:
The hydrofoil boat has an A-36 steel propeller shaft that is 100 ft long. It is connected to an in-line diesel engine that delivers a maximum power of 2490 hp and causes the shaft to
The question is incomplete. The complete question is :
The hydrofoil boat has an A-36 steel propeller shaft that is 100 ft long. It is connected to an in-line diesel engine that delivers a maximum power of 2590 hp and causes the shaft to rotate at 1700 rpm . If the outer diameter of the shaft is 8 in. and the wall thickness is [tex]$\frac{3}{8}$[/tex] in.
A) Determine the maximum shear stress developed in the shaft.
[tex]$\tau_{max}$[/tex] = ?
B) Also, what is the "wind up," or angle of twist in the shaft at full power?
[tex]$ \phi $[/tex] = ?
Solution :
Given :
Angular speed, ω = 1700 rpm
[tex]$ = 1700 \frac{\text{rev}}{\text{min}}\left(\frac{2 \pi \text{ rad}}{\text{rev}}\right) \frac{1 \text{ min}}{60 \ \text{s}}$[/tex]
[tex]$= 56.67 \pi \text{ rad/s}$[/tex]
Power [tex]$= 2590 \text{ hp} \left( \frac{550 \text{ ft. lb/s}}{1 \text{ hp}}\right)$[/tex]
= 1424500 ft. lb/s
Torque, [tex]$T = \frac{P}{\omega}$[/tex]
[tex]$=\frac{1424500}{56.67 \pi}$[/tex]
= 8001.27 lb.ft
A). Therefore, maximum shear stress is given by :
Applying the torsion formula
[tex]$\tau_{max} = \frac{T_c}{J}$[/tex]
[tex]$=\frac{8001.27 \times 12 \times 4}{\frac{\pi}{2}\left(4^2 - 3.625^4 \right)}$[/tex]
= 2.93 ksi
B). Angle of twist :
[tex]$\phi = \frac{TL}{JG}$[/tex]
[tex]$=\frac{8001.27 \times 12 \times 100 \times 12}{\frac{\pi}{2}\left(4^4 - 3.625^4\right) \times 11 \times 10^3}$[/tex]
= 0.08002 rad
= 4.58°
53. The plan of a building is in the form of a rectangle with
centerline dimension of outer walls as 9.7mx14.7m. The
thickness of the wall in super structure is 0.30m. Then its
plinth area is
a) 150m
b) 145m2
c) 145.5m
d) 135.36m
.
Answer: 150m
Explanation:
The following can be depicted from the question:
Dimensions of outer walls = 9.7m × 14.7m.
Thickness of the wall = 0.30 m
Therefore, the plinth area of the building will be:
= (9.7 + 0.30/2 + 0.30/2) × (14.7 × 0.30/2 + 0.30/2)
= 10 × 15
= 150m
The plinth area will be 150m.
Given information
Dimensions of outer walls = 9.7m × 14.7m.
Thickness of the wall = 0.30 m
Plinth area of the building = (9.7 + 0.30/2 + 0.30/2) × (14.7 × 0.30/2 + 0.30/2)
Plinth area of the building = 10 × 15
Plinth area of the building = 150m
Therefore, the Option A is correct.
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