What do you mean by 184x9302

Answer:

3, -6, 12, -24, 48

Step-by-step explanation:

Given:

Therefore,

[tex]a_1=3[/tex]

[tex]a_2=-2 \cdot a_1=-2 \cdot 3=-6[/tex]

[tex]a_3=-2 \cdot a_2=-2 \cdot -6=12[/tex]

[tex]a_4=-2 \cdot a_3=-2 \cdot 12=-24[/tex]

[tex]a_5=-2 \cdot a_4=-2 \cdot -24=48[/tex]

Example of sphere with a volume

[tex]\pi = 6.15[/tex]

Answer:

[tex]f(x)=-(x+8)(x-2)[/tex]

Step-by-step explanation:

Start by factoring out a -1...

[tex]f(x)=-(x^2+6x-16)[/tex]

Now, we have to find two integers that multiply to get -16 and have a sum of 6:

(-2)*8=-16

-2+8=8-2=6

Using this, we can split 6x into -2x and 8x...

[tex]f(x)=-(x^2-2x+8x+16)[/tex]

Factor  the first and second half separately...

[tex]f(x)=-[(x^2-2x)+(8x-16)]\\f(x)=-[x(x-2)+8(x-2)]\\[/tex]

Since both x and 8 are being multiplied by x-2, we can combine them to get...

[tex]f(x)=-(x+8)(x-2)[/tex]

Answer:

I think the answer is 500$ in total

Step-by-step explanation:

I did it adding then subtracting.

Answer:

2/3

Step-by-step explanation:

Probability of choosing an eclair = 1/15

This means that there is 1 eclair in every 15 sweets.

As there are 3 eclairs, there are 3 x 15 = 45 sweets in total.

Now we can write an expression for the total number of sweets and solve for x:

Total number of sweets = 3 + (2x + 6) + x = 45

⇒ 3x + 9 = 45

⇒ 3x = 45 - 9

⇒ 3x = 36

⇒ x = 36 ÷ 3

⇒ x = 12

Now we have found x, we can determine the number of humbugs in the jar by substituting x = 12 into 2x + 6:

(2 x 12) + 6 = 30

So the probability the sweet is a humbug is 30 / 45 = 2/3

Answer:

f^-1(x) = (x +5)/3

also = 1/3 x + 5/3

Step-by-step explanation:

Just to be clear, the ^-1 has nothing to do with negative exponents. It just unfortunately looks the same as a negative exponent.

Anyway, there's three basic steps. First write y instead of f(x). Then switch the x and y. Then solve for y.

f(x) = 3x - 5

write y in place of f(x).

y = 3x - 5

SWITCH x and y.

x = 3y - 5

SOLVE for y.

-3y + x = -5

-3y = -x - 5

y = (-x - 5)/-3

y = (x + 5)/3

OR

y = (1/3)x + 5/3

f^-1(x) = 1/3 x + 5/3

Answer:

I think that the selected answer is correct

Step-by-step explanation:

Answer:

Its step 3 which needs correction.

Step-by-step explanation:

step 3 is deeply a mistake, the step 3 correction is correct that the total sum of interior angles which is 180 degrees is equal to the angle of total straight line angle. Step 2 is correct that when angle m plus angle p sums, they mix up to 180 degrees and its adjacent supplementary angles.

Answer:

Step-by-step explanation:

1/9x5/4

5/36

You multiply across

5*1 = 5

9*4 = 36

5/36

Hope this helps!

The product of (x + 3)² demonstrates the closure property of multiplication. [tex]\rm x^{2} + 6x + 9[/tex] is a polynomial. Option D is correct.

Polynomial is an algebraic expression that consists of variables and coefficients. Variable are called unknown. We can apply arithmetic operations such as addition, subtraction, etc. But not divisible by variable.

A set is closed under an operation when we do that operation on the member of the set and we always get a set member.

Given

An expression is (x + 3)²

On simplifying, we have

[tex]\rm (x + 3)(x + 3)\\\\x (x + 3) + 3 (x + 3)\\\\x^{2} +3x +3x +3^2\\\\x^{2} +6x + 9[/tex]

Thus, [tex]\rm x^{2} + 6x + 9[/tex] is a polynomial.

More about the polynomial link is given below.

https://brainly.com/question/17822016

Answer:

Option D

Step-by-step explanation:

Answer:

false

Step-by-step explanation:

ray is a part of a line

hope it helps

Answer:

c²

Step-by-step explanation:

Finding the factors:

7c³=7×c×c×c

8c²=2×2×2×c×c

Here,

c×c is common in both terms

Hence,GCF=c²

Answer:

3.03%

Step-by-step explanation:

Given the following question:

[tex]\frac{34-33}{33} \times100=34-33=1\div33=0.0303030303\times100=3.0303030303[/tex]
[tex]3.0303030303[/tex]
[tex]0<5[/tex]
[tex]3.03[/tex]

33 to 34 is a "3.03 percent increase."

Hope this helps.

Answer:

8

Step-by-step explanation:

When you multiply 9 and 3 by 8 and then you subtract you get the same answer.

Answer:

[tex]n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }[/tex]

Step-by-step explanation:

[tex]a=p(1+\frac{r}{n} )^{nt}[/tex]

[tex]\frac{a}{p} =(1+\frac{r}{n} )^{nt}[/tex]

[tex]\sqrt[nt]{\frac{a}{p}} =(1+\frac{r}{n} )[/tex]

[tex]\sqrt[nt]{\frac{a}{p}} -1 =(\frac{r}{n} )[/tex]

[tex]n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }[/tex]

[ Do not confuse, as there are 2 n's, one in subject and another as power. We can never make the power or in a root, the subject. In order to solve for n, we have to make the character "n", the subject. ]

Step-by-step explanation:

hello,

simply knowing the formula will lead you to the answer easily.

formula to find the volume of a prism:

v = bh, where b = base area and h = height.

here, in the picture given, the :

h of the prism = 6m

base area = length * width

b = 8 cm × 7 cm

b = 56 cm²

thus, using v = bh,

v = 56 × 6

v = 336 cm³

please try to understand, and let me know if you have any questions,

have an amazing day! au revoir!

Answer:

Chip worked 7 weeks

Step-by-step explanation:

Set up as proportion and cross multiply to solve:

6 hours/1 week = 42 hours/x

x = 7

Answer:

10%

12.5%

13%

19%

Step-by-step explanation:

First write all of the amounts as a percent.

1/8 = 12.5%

13%

.10 = 10%

19%

Then you can order them from least to greatest.

10%, 12.5%, 13%, and then 19%

hope this helps

Answer:

-1

Step-by-step explanation:

(x^2 - 8) / ( x+6)

Let x = -2

(( -2)^2 -8)/ ( -2+6)

(4-8)/(-2+6)

-4/4

-1

Answer:

( -1 )

Step-by-step explanation:

Given that,

[tex]\frac{(x^{2}-8) }{(x+6)}[/tex]

Also given that,

x = -2

So, to solve the above expression, you have to replace x with ( - 2 )

Let us solve.

[tex]\frac{(x^{2}-8) }{(x+6)}[/tex]

[tex]\frac{((-2^{2})-8) }{(-2+6)}[/tex]

[tex]\frac{4-8 }{(4)}[/tex]

[tex]\frac{-4 }{(4)}[/tex]

[tex]-1[/tex]

Hope this helps you :-)

Let me know if you have any other questions :-)

Answer:

29

Step-by-step explanation:

Let's set up an equation...

25%*116=x

We can first convert 25% to a fraction. We can convert any percentage into a fraction by simply putting the number over 100...

[tex]\frac{25}{100}*116=x[/tex]

We can simplify 25/100 by dividing the fraction by 25/25. Note we can only do this because 25/25 is equivalent to 1, therefore meaning we are dividing  the fraction by 1.

[tex]\frac{1}{4}*116=x\\\frac{116}{4}=x\\x=29[/tex]

Answer:

A.

Step-by-step explanation:

On graph A, all 4 points (G, P, R, and S) are all in the correct order. Options B and D are easy to eliminate because we know that none of the nests are actually at the center.

~~~~~~~~~~~~~~~~~~~~~~~~~~~

Let me know if you have any questions! Spread the love.

Answer:

A.

Step-by-step explanation:

Options A and B are the only number lines with the blue point at the right spot (You can see it is 1/2 mile away so it goes in the middle of 1 and 2). Between these 2 only number line A has the red dot in the right spot (it belongs at -0.25 which is 1 spot left of the center 0).

Answer:

[tex]y - 6 = 5[/tex]

equation are màthematical statements containing two algebraic expression on both sides of an "equal to (=)" sign.

Answer:

the answer is C/3

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    v/5-4-(v/4)=0

                 v

Simplify   —

                 4

  v          v

 (— -  4) -  —  = 0

  5          4

STEP 2:

                v

Simplify   —

                 5

Equation at the end of step

2

:

  v          v

 (— -  4) -  —  = 0

  5          4

STEP 3:

Rewriting the whole as an Equivalent Fraction

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  5  as the denominator :

        4     4 • 5

   4 =  —  =  —————

        1       5  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

v - (4 • 5)     v - 20

———————————  =  ——————

     5            5  

Equation at the end of step 3:

 (v - 20)    v

 ———————— -  —  = 0

    5        4

STEP 4:

Calculating the Least Common Multiple :

4.1    Find the Least Common Multiple

     The left denominator is :       5

     The right denominator is :       4

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

5 1 0 1

2 0 2 2

Product of all

Prime Factors  5 4 20

     Least Common Multiple:

     20

Calculating Multipliers :

4.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 4

  Right_M = L.C.M / R_Deno = 5

Making Equivalent Fractions :

4.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      (v-20) • 4

  ——————————————————  =   ——————————

        L.C.M                 20    

  R. Mult. • R. Num.      v • 5

  ——————————————————  =   —————

        L.C.M              20  

Adding fractions that have a common denominator :

4.4       Adding up the two equivalent fractions

(v-20) • 4 - (v • 5)     -v - 80

————————————————————  =  ———————

         20                20  

STEP 5:

Pulling out like terms :

5.1     Pull out like factors :

  -v - 80  =   -1 • (v + 80)

Equation at the end of step 5:

 -v - 80

 ———————  = 0

   20  

STEP 6:

When a fraction equals zero :

6.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -v-80

 ————— • 20 = 0 • 20

  20  

Now, on the left hand side, the  20  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -v-80  = 0

Solving a Single Variable Equation:

6.2      Solve  :    -v-80 = 0

Add  80  to both sides of the equation :

                     -v = 80

Multiply both sides of the equation by (-1) :  v = -80

Answer:

35,887.1 because 38300×93.7 ➗ 100

Answer:

b,d

Step-by-step explanation:

80+3= 83 false

0+3=3 true

70+3= 73 false

60+3=63 true

69+3= 72 false

Hope this helps

[tex]\large\text{Hey there!}[/tex]

[tex]\large\textsf{x + 3}<\large\textsf{70}\\\\\huge\textbf{SUBTRACT 3 to BOTH SIDES}\\\\\large\textsf{x + 3 - 3}<\large\textsf{70 - 3}\\\\\huge\textbf{CANCEL out: 3 -3 because it give you 1}\\\\\huge\textbf{KEEP: 70 - 3 because it help what is}\\\huge\textbf{being compared to the x-value}\\\\\large\text{NEW EQUATION: \textsf{x}} < \large\textsf{70 - 3}\\\\\large\text{SIMPLIFY IT!}\\\\\large\textsf{x}< \large\textsf{67}\\\\\huge\textbf{Thus, your answer is: \boxed{\mathsf{x < 67}}}\huge\checkmark[/tex]

[tex]\large\textbf{It is an (O)(P)(E)(N) circle shaded to the LEFT side of the}\\\large\textbf{number starting at point 67.}[/tex]

[tex]\large\text{Good luck on your assignment \& enjoy your day!}[/tex]

Like term's coefficient are added in addition of algebraic terms. The simplified form of the given expression is [tex]x^3 + 8x^2 + 13[/tex]

Those terms which have same variables raised with same power.

For example, [tex]5t^3[/tex]  and [tex]6t^3[/tex] are like terms since variable is same, and it is raised to same power 3.

For example [tex]x^3[/tex] and [tex]3x^4[/tex] are not like terms as the variables are same but powers aren't same.

Constants who are in multiplication with variables are called coefficients of those variables.

Suppose we have

[tex]5x^2 + 6y[/tex]

Since those terms are not like terms, their coefficient won't be add and the expression we've got right now, is its simplest form and cannot be reduced more.

If we have, suppose,

[tex]4x + 5x^2 + 2x[/tex]

then we see that [tex]4x[/tex] and [tex]2x[/tex] are like terms, their coefficient can be added and thus, the simplified form would be

[tex](4+2)x + 5x^2 = 6x + 5x^2[/tex]

For the given case, the considered expression is simplified as:
[tex]= > (6x^2 - 3 + 5x^3) - (4x^3 - 2x^2 - 16)\\= 6x^2 - 3 + 5x^3 -4x^3 + 2x^2 + 16\\ = 5x^3 - 4x^3 + 6x^2 + 2x^2 - 3 + 16\\= (5-4)x^3 + (6+2)x^2 + 13\\= 1.x^3 + 8x^2 + 13 \\= x^3 + 8x^2 + 13[/tex]

(variables with 1 as coefficient is not written explicitly as 1 is factor of all measurements).

Sign multiply by

[tex]-ve \times (+ve) = -ve\\(-ve) \times (-ve) = +ve\\(+ve) \times (+ve) = +ve\\(+ve) \times (-ve) = -ve[/tex]

where -ve, +ve are sign of operands and result.

Thus, the simplified form of the given expression is [tex]x^3 + 8x^2 + 13[/tex]

Learn more about simplification of expressions here:

https://brainly.com/question/26437497

Empirical rule is defined for normal distributions. The percentage of the parts the lengths between 3.8 inches and 4.2 inches lie is: Option B: 68%

According to the empirical rule, also known as 68-95-99.7 rule, the percentage of values that lie within an interval with 68%, 95% and 99.7% of the values lies within one, two or three standard deviations of the mean of the distribution.

[tex]P(\mu - \sigma < X < \mu + \sigma) = 68\%\\P(\mu - 2\sigma < X < \mu + 2\sigma) = 95\%\\P(\mu - 3\sigma < X < \mu + 3\sigma) = 99.7\%[/tex]

where we had  

[tex]X \sim N(\mu, \sigma)[/tex]

where mean of distribution of X is [tex]\mu[/tex] and standard deviation from mean of distribution of X is [tex]\sigma[/tex]

For the given case, as it is given that the lengths of a lawn mower part are approximately normally distributed, let its lengths be tracked by a random variable X

Then, [tex]X \sim N(\mu =4, \sigma = 0.2)[/tex]

The needed percentage is

[tex]P(3.8 < X < 4.2)[/tex]

We can rewrite it as:

[tex]P(4-0.2 < X < 4 + 0.2)[/tex]

This is the percent of values lying under one standard deviation about the mean of X. Using the empirical rule, we get the percentage as:

[tex]P(\mu - \sigma < X < \mu + \sigma) = 68\%[/tex]

Thus,

[tex]P(4-0.2 < X < 4 + 0.2) = 68\%[/tex]

Thus, The percentage of the parts the lengths between 3.8 inches and 4.2 inches lie is: Option B: 68%

Learn more about empirical rule here:

https://brainly.com/question/13676793

Answer:

(3x²-3.5x+1)in²

Step-by-step explanation:

area of a triangle = ½(base × height)

= ½(2x-1)(3x-2)

= ½(6x²-4x-3x+2)

= ½(6x²-7x+2)

= 3x²-3.5x+1

A polynomial that represents the area of the triangle is (3x²-3.5x+1)in²