What does 100+100-200+90+20=

Answer:

[tex]x=\frac{275}{62}[/tex] , [tex]y=\frac{127}{31}[/tex]

Step-by-step explanation:

We want to make the X's the same:

[tex]24x-15y=45[/tex]

[tex]24x+16y=172[/tex]

Because the signs of the X's are the same we subtract the 2 equations to make:

(I put the second one on top of the 1st)

[tex]31y=127[/tex]

So:

[tex]y=\frac{127}{31}[/tex]

Substitute y into either equation 1 or 2:

(I chose equation 1)

[tex]8x-5(\frac{127}{31})=15[/tex]

[tex]8x=5(\frac{127}{31}) + 15[/tex]

[tex]x=\frac{5(\frac{127}{31})}{8}[/tex]

So:

[tex]x=\frac{275}{62}[/tex]

Answer:

33.92

Step-by-step explanation:

40 x .2= 8

40-8= 32

32x.06=1.92

32+1.92= 33.92

Answer:

C

ON THE EDGE

Step-by-step explanation:

Answer:

13 in12

Step-by-step explanation:

Answer: the answer should be true

Answer:

The number 3 is more accurate

Answer:

Since the cost for each pie is $5 and $9, the first equation should be 5x+9y=133

Since there are fewer 8-inch pies, the second equation should be x=2y to balance the values.

Step-by-step explanation:

Answer:

1/a

Step-by-step explanation:

The value of x = -5/2

To solve this question we must understand the concept of indices.

Indices in mathematics show the power to which an expression or variable is raised.

Here, the correct format of the equation given in the question as follows:

[tex]\mathbf{2 \sqrt[3]{3x +2}} \mathbf{= \sqrt[3]{4x -9} }[/tex]

[tex]2(3x+2)^{1/3} = (4x -9)^{1/3} \\ \\ (6x + 4)^{1/3} =(4x -9)^{1/3}[/tex]

Multiply the power of both sides by 3

(6x + 4) =(4x -9)

6x - 4x = -9 + 4      

2x = -5

x = -5/2

Learn more about indices here:

https://brainly.com/question/10339517

Answer:

107.5

Step-by-step explanation:

20% of 70 = 14

70 - 14 = 66

10% of 45 = 4.5

45 - 4.5 = 41.5

66 + 41.5 = 107.5

[tex] \: \: \: \: \: \: [/tex]

[tex]1 + w[/tex]

Step-by-step explanation:

[tex]1 - w + w2[/tex]

[tex]1 - w + 2w[/tex]

[tex] = \: \: 1 + w[/tex]

Answer:

Step-by-step explanation:

Answer:

x=4

Step-by-step explanation:

log(2x-7) = 0

10^[log(2x-7)] = 10^0

2x-7 = 1

2x = 8

x = 4

Answer:

x=13

y=5

13-5=8

13+5=18

Step-by-step explanation:

Answer:

34.64m

Step-by-step explanation:

Tan30= x(height) /60

x=60tan30

=34.64m

Answer:

B (1, 8 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )

with (x₁, y₁ ) = A (- 3, 2 ) and (x₂, y₂ ) = B (x, y )

Calculate the midpoint values and equate to the corresponding coordinates of the given midpoint (- 1, 5 ) , that is

[tex]\frac{-3+x}{2}[/tex] = - 1 ( multiply both sides by 2 )

- 3 + x = - 2 ( add 3 to both sides )

x = 1

[tex]\frac{2+y}{2}[/tex] = 5 ( multiply both sides by 2 )

2 + y = 10 ( subtract 2 from both sides )

y = 8

Then point B = (1, 8 )

Answer: The equation is not an identity

==========================================================

Explanation:

We'll expand out the right hand side to see if we can simplify it to the left hand side. The stuff on the left will stay the same for each step.

I'll use  c = a+b as a way to help distribute.

[tex]a^4 + b^4 = (a+b)(a^3 - a^2b-ab^2 + b^3)\\\\a^4 + b^4 = c(a^3 - a^2b-ab^2 + b^3)\\\\a^4 + b^4 = a^3c - a^2bc-ab^2c + b^3c\\\\a^4 + b^4 = a^3(c) - a^2b(c)-ab^2(c) + b^3(c)\\\\a^4 + b^4 = a^3(a+b) - a^2b(a+b)-ab^2(a+b) + b^3(a+b)\\\\a^4 + b^4 = a^4+a^3b - a^3b-a^2b^2-a^2b^2-ab^3 + ab^3+b^4\\\\a^4 + b^4 = a^4+(a^3b - a^3b)+(-a^2b^2-a^2b^2)+(-ab^3 + ab^3)+b^4\\\\a^4 + b^4 = a^4-2a^2b^2+b^4\\\\[/tex]

Unfortunately, we can't go any further. We have a^4 and b^4 on the right hand side, but we also have the term -2a^2b^2 that didn't cancel out. Therefore, the original equation is not an identity.

----------------

Here's another way you can see that we don't have an identity.

Let's say we fixed 'a' to be equal to 1.

That means the equation

[tex]a^4 + b^4 = (a+b)(a^3 - a^2b-ab^2 + b^3)[/tex]

would turn into

[tex]1^4 + b^4 = (1+b)(1^3 - 1^2b-1b^2 + b^3)[/tex]

and simplify to

[tex]1 + b^4 = (1+b)(1 - b-b^2 + b^3)[/tex]

Now replace b with x and you'll have the two equations to represent the left and right hand sides

[tex]y = 1+x^4\\y = (1+x)(1-x-x^2+x^3)[/tex]

which you can graph on the same xy axis. You should note that the two equations produce different curves. The curves would need to be identical if we wanted an identity to happen.

Side note: you can pick other values for 'a' instead of just 1.

[tex]6 \times (3 + 8) \\ = (6 \times 3) + (6 \times 8)[/tex]

Answer:

(6×3)+(6×8)

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

No

Step-by-step explanation:

Answer:

Y= -5x + 6Y

Step-by-step explanation:

(-5, -2.5) to (1.5, 6)

Hello, again!! :p

I'm not sure about the whole equation because I was taught to solve it in a different way and I got the answer  =3 ± i√ 6 ,not a -3.

Sorry, I'm not sure if that was much help!

Answer:

-7 is the answer!! :) hope this helps

Answer:

24 units

Step-by-step explanation:

I dont know if im right but hope this helps!

Answer: How is this math

Step-by-step explanation: What can I help you with? I’m not sure what you’re asking

If a₀ = 0, and [tex]a_{i + 1} = a_i + 1[/tex], then

a₁ = a₀ + 1 = 0 + 1   ⇒   a₁ = 1

and

a₂ = a₁ + 1 = 1 + 1   ⇒   a₂ = 2

i hope it helped you :P

it was easyy!!!