Something that is falsely advertised to help different health issues. An example could be Eyeball massagers
a measure of change in velocity in a measure of time is
[tex]\\ \sf\Rrightarrow Acceleration=\dfrac{\Delta V}{t}[)tex]
In simplified form
[tex]\\ \sf\Rrightarrow Acceleration=\dfrac{dv}{dt}[/tex]
The rate of change of velocity with respect to time period is called acceleration.SI units-m/s^2How can you use a simple model to describe a wave and its features?
Answer:
Explanation:
Use mathematical representations to describe a simple model for waves that includes how the amplitude of a wave is related to the energy in a wave. Patterns can be used to identify cause and effect relationships.
Which element forms more com-
pounds than all the other elements
combined?
Answer:
Terms in this set (7) Which element forms more compounds than all the other elements combined? Carbon.
Explanation:
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What is an example of bad energy efficiency but good energy conservation?
Answer:
Energy conservation relies on people cutting back on activities that consume energy—by turning off lights or driving less or using appliances less often.
Explanation:
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how many kilojoules is this?
Answer:
How to convert joules to kilojoules
One joule is equal to thousandth of a kilojoule:
1J = 0.001kJ
The energy in kilojoules E(kJ) is equal to the energy in joules E(J) divided by 1000:
E(kJ) = E(J) / 1000
Example
Convert 500 joules to kilojoules.
The energy E in kilojoules (kJ) is equal to 500 joules (J) divided by 1000:
E(kJ) = 500J / 1000 = 0.5kJ
Joules to kilojoules conversion table
Energy (J) Energy (kJ)
1 J 0.001 kJ
2 J 0.002 kJ
3 J 0.003 kJ
4 J 0.004 kJ
5 J 0.005 kJ
6 J 0.006 kJ
7 J 0.007 kJ
8 J 0.008 kJ
9 J 0.009 kJ
10 J 0.01 kJ
20 J 0.02 kJ
30 J 0.03 kJ
40 J 0.04 kJ
50 J 0.05 kJ
60 J 0.06 kJ
70 J 0.07 kJ
80 J 0.08 kJ
90 J 0.09 kJ
100 J 0.1 kJ
200 J 0.2 kJ
300 J 0.3 kJ
400 J 0.4 kJ
500 J 0.5 kJ
600 J 0.6 kJ
700 J 0.7 kJ
800 J 0.8 kJ
900 J 0.9 kJ
1000 J 1 kJ
2000 J 2 kJ
3000 J 3 kJ
4000 J 4 kJ
5000 J 5 kJ
6000 J 6 kJ
7000 J 7 kJ
8000 J 8 kJ
9000 J 9 kJ
10000 J 10 kJ
100000 J 100 kJ
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itz by Riddhi
A bullet of mass M1 is fired towards a block of mass m2 initially at rest at the edge of a frictionless table of height h as in the figure. The initial speed of the bullet is vi . Consider two cases, a completely inelastic one and an elastic one,where the bullet bounces off the block. inelastic case elastic case a bullet inside no bullet inside A B A' B' What is the ratio of the flight time; i.e., tAB tA′B′ ?
The ratio of time of flight for inelastic collision to elastic collision is 1:2
The given parameters;
mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂Considering inelastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\[/tex]
The time of motion of the system form top of the table is calculated as;
[tex]v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)[/tex]
Considering elastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2[/tex]
Apply one-directional velocity
[tex]u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1[/tex]
Substitute the value of [tex]v_1[/tex] into the above equation;
[tex]m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)[/tex]
where;
[tex]v_2[/tex] is the final velocity of the block after collision
Since the bullet bounces off, we assume that only the block fell to the ground from the table.
The time of motion of the block is calculated as follows;
[tex]v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)[/tex]
The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;
[tex]\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2[/tex]
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A firecracker is placed in the middle of a room. When the firecracker explodes the parts of the firecracker scatter in all different directions. The total combined momentum of all the parts of the firecracker added together after the explosion must be
A.
more than before the explosion.
B.
less than before the explosion.
C.
can not tell from the given information
D.
the same as before the explosion.
Because momentum is a vector quantity, the total combined momentum of all the parts of the firecracker added together after the explosion must be the same as before the explosion. The correct answer is D
Given that a firecracker is placed in the middle of a room. This means that the firecracker is at rest. That is its momentum is equal to zero. When the firecracker is lit up, it will move in a certain velocity before it explodes. Since the total combined momentum of all the parts of the firecracker scatter in all different directions are considered, that is added up, then momentum will always be conserved. That is,
The momentum of an object before explosion will always be equal to the momentum of the object after explosion.
Because momentum is a vector quantity, in which we must consider it magnitude and direction, the best answer to this question is option D.
That is,
The total combined momentum of all the parts of the firecracker added together after the explosion must be the same as before the explosion
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The gravitational force on Mars is about 38% of Earth. What would a cat weighing 15 pounds on Earth weigh on Mars?
Answer: 5.7
Explanation: 38% of 15.
The weight we experience ourselves and the ability to stand in the ground is due to the gravitational pull of earth. If this pull is lower we feel weight loss. So the cat will have a weight of 5.7 pounds or 2.58 kg in mars where the gravitation is about 38% of earth.
What is gravitational force?Gravitational force is a kind force by which a body attracts other objects into its centre of mass. Earth have strong gravitational effect on objects and thus we are all standing on the surface and everything falling from a height hits the ground.
As the mass of the object increases, gravitational effect also increases. The weight experienced by a body is the product of its mass and gravity. Thus massive body have greater weight.
Our mass is constant everywhere but weight will change according a change in gravity. Mars have only 38% of gravity of earth. Thus the cat weighing 15 pounds on earth will loss its weight in mars by 38%.
Thus, 15 × 38/100= 5.7 pounds will be the weight of the cat in mars.
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Solve the science problem
Answer:
1.hydrogen
2.helium
3. lithium
4.beryllium
5.boron
6.carbon
7.nitrogen
8.oxygen
9.fluorine
10.neon
What two things related to sedimentary rocks do you see at the Grand Canyon ?
Answer:
sandstone and mudstone
Explanation:
what is the unit of measurement for expressing the intensity of sound
Describe the way that distance is changing in relation to tiMe
Answer:
DistaNcE chanGes iN relAtiOn tO TiMe Bc ThE fuRthEr yOu Go ThE mOrE TiMe goeS bY
Explain how energy changes in the spring toy below when it goes downstairs.
Given what we know, we can confirm that the spring toy uses the transfer of potential gravitational energy into kinetic energy of motion in order to fall down the stairs.
How does the toy do this?The toy stores potential energy. It does this using gravity. Once it begins to fall, it uses the momentum from each fall to continue to do so. With each fall, its stored potential energy is transferred to kinetic energy.Therefore, we can confirm that the spring toy uses its position at the top of each stair as a source of potential energy, which using the momentum from the last fall, it transfers into the kinetic energy of motion as it falls, all through the help of gravity.
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A 1.5 kg ball has a velocity of 12 m/s just before it strikes the floor. Find the impulse on the ball if the ball bounces up with a velocity of 10 m/s.
Hi there!
Recall:
Impulse = Change in momentum
I = Δp = mΔv = m(vf - vi)
Let the direction TOWARDS the floor be POSITIVE, and AWAY be NEGATIVE.
Plug in the givan values:
Δp = 1.5(-10 - 12) = -33 Ns
**OR, the magnitude: |-33| = 33 Ns
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(answer choices: applied force, normal force, friction, electrical force, magnetic force and gravitational force)
(question in picture)
Answer:
3
Explanation:
because they are pushing a body
A vertical spring stretches 9.6 cm when a 1.3 kg block is hung from its end. (a) Calculate the spring constant. This block is then displaced an additional 5.0 cm downward and released from rest. Find the (b) period, (c) freque
Answer:
F = - K x
a) K = 1.3 kg * 9.8 m/s^2 / .096 m = 133 kg/sec^2
b) ω = (K/m)^1/2 angular frequency of SHM
ω = (133 / 1.3)^1/2 = 10.1 / sec
f = 2 π ω = 6.28 * 10.1 / sec = 63.5 / sec
P = 1/f = .0157 sec
Calculate the weight of the object of mass
20kg. (g= 10 m/s^2)
Answer:
mass= 20kg
g=10m/s2
weight is F=mg
F=20×10
F=200N
A vector consists both?
Answer:
magnitude and a direction
Explanation:
car was moving in a straight road of length 320 km it covered 240 km with an average velocity 75 km/hr then it ran out of fuel and stopped for 0.6 hr until it was refueled and completed its journey with a velocity 100 km/hr so the average velocity during the whole journey
The average velocity of the car for the whole journey is 69.57 km/h.
The given parameters:
Length of the road, L = 320 kmDistance covered = 240 km at 75 km/htime spent refueling, t₂ = 0.6 hrFinal velocity, = 100 km/hrThe time spent by the before refueling is calculated as follows;
[tex]t = \frac{d}{v} \\\\t_1 = \frac{240}{75} \\\\t_1 = 3.2 \ hours[/tex]
The time spent by the car for the remaining journey;
[tex]t_3 = \frac{320 - 240}{100} \\\\t_3 = 0.8 \ hr[/tex]
The total time of the journey is calculated as follows;
[tex]t = t_1 + t_2 + t_3\\\\t = 3.2 \ hr \ + \ 0.6 \ hr \ + \ 0.8 \ hr\\\\t = 4.6 \ hours[/tex]
The average velocity of the car for the whole journey is calculated as follows;
[tex]v = \frac{total \ distance }{total \ time} \\\\v = \frac{320}{4.6} \\\\v = 69.57 \ km/h[/tex]
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True or false? Gas pressure is caused by molecules in a gas colliding with the walls of their container.
Answer:True
The number of molecules hitting the unit surface per unit time increasethe gas pressure increases.
A payload of mass m, where m
Answer:
where m < M is delivered to the space station. Soon after, the space station's orbit is adjusted so that it is 50 km ...
A payload of mass m, where m<M, is delivered to the space station.
What is payload?The maximum mass that the vehicle is capable of moving is referred to as the mass's payload. The carrying capacity of a packet or other transmission data unit is referred to as a payload.
The phrase, which has military roots, is frequently used in relation to malicious code that can be executed and cause harm. A payload is a section of code that runs when hackers take advantage of a weakness. In other words, it's a module for an exploit.
It typically consists of a few commands that will execute on the targeted operating system in order to steal data and carry out other malicious deeds (such as keyloggers).
Therefore, A payload of mass m is sent to the space station, where m<M.
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Why does the size of a white dwarf affect its visual luminosity?
Answer:
A typical white dwarf has a carbon and oxygen mass similar to the Sun, but is much smaller in size (similar to the Earth). It is much hotter (25,000 K), but because of its small size its luminosity is low. ... Some very nearby white dwarf stars can be observed directly through telescopes, though they are extremely faint.
Explanation:
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write of the following does not represent electrical power in a circuit ?
(a) I²R
(b) IR²
(c)VI
(d) V²/R
I need help!
A car has a mass of 1,200 kg and the road can provide a maximum force of 24 kN on the car what is the maximum acceleration?
Answer:
The acceleration of the car with the mass of 1200kg and a force of 11 × 10³N is 9.17m/s²
Explanation:
Other than temperature, which property also has an effect on the rates of chemical reactions?
A.Color of reactants
B.Concentration of reactants
C.Solubility of reactants
D.Volume of reactants
Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants. The correct answer is B
The rate of chemical reaction means how chemical react with respect to time or as a function of time. The rate of chemical reaction tells us the speed or how fast chemicals react.
There are many factors that can affect the rate of chemical reaction. Temperature is one of them. Increase in temperature will increase the rate at which chemical react.
The color of reactants, solubility of reactants and volume of reactants have nothing to do with the rate of chemical reaction.
Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants.
Other factors affecting the rate of chemical reaction are:
the physical state of the reactants surface area temperature and the presence of a catalystTherefore, the correct answer is option B
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The practice of science can answer only scientific questions. And scientific questions guide the design of investigations. What must be true of the possible answers to a scientific question? A. They are popular with a majority of scientists. B. They agree with all prior experiments. O C. They can be supported by evidence. O D. They lead to increased funding of scientific research.
Answer:
They must be supported by evidence.
Explanation:
Every scientific theory or scientifc claim must have scientific evidence.
Two 3.0g bullets are fired with speeds of 40.0 m/s
and 80.0 m/s, respectively. What are their kinetic
energies? Which bullet has more kinetic energy? What is the ratio of their kinetic energies?
[tex] = \sf \frac{1}{2} m {v}^{2} [/tex]
Kinetic energy of the 1st bullet [tex] \sf = \frac{1}{2} \times m1 \times {(v1)}^{2} \\ \sf= \frac{1}{2} \times 0.003 \times {(40)}^{2}J \\ \sf = \frac{1}{2} \times 0.003 \times 1600J \\ \sf = 2.4J[/tex]Kinetic energy of the 2nd bullet [tex] \sf = \frac{1}{2} \times m2 \times {(v2)}^{2} \\ \sf= \frac{1}{2} \times 0.003 \times {(80)}^{2}J \\ \sf = \frac{1}{2} \times 0.003 \times 6400J \\ \sf = 9.6J[/tex] So, the 2nd bullet which has greater velocity has more kinetic energy.Therefore, the ratio of their kinetic energies[tex] \sf = \frac{2.4J}{9.6J} \\ \sf= \frac{24}{96} = \frac{1}{4} \\ \sf = 1 : 4[/tex]
Answer:
The kinetic energies of the bullets are 2.4 J and 9.6 J.
The bullet having greater velocity has more kinetic energy.
The ratio of their kinetic energies is 1 : 4.
Hope you could get an idea from here
Doubt clarification - use comment section.
The kinetic energy of the two bullets are 2.4 J and 9.6 J respectively.
The ratio of the kinetic energy of the bullets is 1:4.
What is kinetic energy?The kinetic energy of an object is the energy possessed by the object due to its motion.
The kinetic energy of the two bullets is calculated as follows;
[tex]K.E_1 = \frac{1}{2} \times 0.003 \times 40^2 = 2.4 \ J\\\\K.E_2 = \frac{1}{2} \times 0.003 \times 80^2 = 9.6 \ J[/tex]
Ratio of the kinetic energy of the bullets is calculated as follows;
[tex]K.E_1 : K.E_2 = 2.4: 9.6 \ = \ 1: 4[/tex]
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How many neutrons are in K-37?
Answer:
18 neutrons
Explanation:
Potassium is nuimber 19 on periodic table, so when the mass equals 37, you simply subtract 37-19 to get 18
potassium usually has a mass of 39, so when we have potassium 37, it is two less neutrons than normal
Compare and contrast synthesis and decomposition reactions.
Answer:
Synthesis reactions are chemical reactions where two elements combine to make a product. Decomposition reactions are chemical reactions where a reactant produces another product, usually two, or even more. This is when the bonds in the compound are broken apart to make new compounds.
Explanation: