What does the prefix trans-indicate?

Answer:

88,88 % de O y 11,11 % de H

Explanation:

La composición porcentual se define como la masa que hay de cada mol de átomo en 100g. Las moles de agua en 100g son:

Masa molar agua:

2H = 2*1g/mol = 2g/mol

1O = 1*16g/mol = 16g/mol

Masa molar = 2 + 16 = 18g/mol

100g H2O * (1mol / 18g) = 5.556 moles H2O.

Moles de hidrógeno:

5.556 moles H2O * (2mol H / 1mol H2O) = 11.11 moles H

Moles Oxígeno = Moles H2O = 5.556 moles

La masa de hidrógeno es:

11.11mol * (1g/mol) 11.11g H

La masa de oxígeno es:

5.556 mol * (16g / 1mol) = 88.89g O

Así, el porcentaje de O es 88.89% y el de H es 11.11%. La opción correcta es:

Answer: I think it would be -23

Explanation:

Answer: hello your question has some missing details attached below is the missing details

answer : 25.5%  ( B )

Explanation:

Determine percentage yield

molar mass = 35 g/mol

mass of Li₃N(s) = 70 g

product  LiH(s) = 8.0 g ( actual yield )

theoretical yield ( LiH ) =  4 * 7.95  = 31.8 g

percentage yield = actual yield * 100 / theoretical yield

                            = 8 * 100/31.8

                            = 25.5%

Answer:

A. Li= 5.6 g O2= 6.4 g

Explanation:

Lithium oxide, Li2O, is an oxide that contains 2 moles of Li and 1 mole of O per mole of oxide. To solve this question we must find the mass of each atom in the molecule as follows:

2Li = 2*6.941g/mol = 13.882g/mol

O = 1*16g/mol = 16g/mol

Molar mass Li2O:

16+13.882 = 29.882g/mol

The mass of lithium is:

12g * (13.882g/mol / 29.882g/mol) = 5.6g Li

And the mass of oxygen:

12g * (16g/mol / 29.882g/mol) = 6.4g O

Right answer is:

The above given statement is true.

A homogeneous mixture comprised of two or more components is referred to as a solution. Because they are consistently scattered at the molecular or ionic level, the components in a solution are evenly mixed and have a constant composition.

Until the reaction between the two solutions is complete, a solution of known concentration is gradually added to a solution of unknown concentration in a titration. The endpoint, or point at which the reaction is finished, is often identified by a color change that takes place after an indicator is added to the solution being titrated.

The reaction has achieved its endpoint when the solution in the flask changes color, and the new color persists even after the solution is gently shaken. At this time, the titration should be halted. By doing this, it is possible to precisely determine the concentration of the unknown solution and the volume of titrant added to the solution.

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Answer:

d

Explanation:

the answer is d is that correct

Answer:

K2O Potassium oxide

Explanation:

ur best try is to copy and paste and change some words.

Answer:

their mobile electrons

Explanation:

I did it step by step so It would be easier to understand:)

Answer:

7800 cells

Explanation:

The number of Escherichia coli cells N after n generations is given by

N = 2ⁿ × N₀ where N₀ = initial population

Now making N₀ subject of the formula, we have

N₀ = N/2ⁿ

Since n = 8 and N = 1,996,800 cells, substituting the values of the variables into the equation, we have

N₀ = N/2ⁿ

N₀ = 1,996,800 cells/2⁸

N₀ = 1,996,800 cells/256

N₀ = 7800 cells

So, the initial population of Escherichia coli cells is 7800 cells.

Answer: There are [tex]2.032 \times 10^{25}[/tex] molecules [tex]S_{2}[/tex] gas are in 756.2 L.

Explanation:

It is known that 1 mole of any gas equals 22.4 L at STP. Hence, number of  moles present in 756.2 L are calculated as follows.

[tex]Mole = \frac{Volume}{22.4 L}\\= \frac{756.2 L}{22.4 L}\\= 33.76 mol[/tex]

According to mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] molecules.

Therefore, molecules of S present in 33.76 moles are calculated as follows.

[tex]1 mol = 6.022 \times 10^{23}\\33.76 mol = 33.76 \times 6.022 \times 10^{23}\\= 2.032 \times 10^{25}[/tex]

Thus, we can conclude that there are [tex]2.032 \times 10^{25}[/tex] molecules [tex]S_{2}[/tex] gas are in 756.2 L.

Answer:

Percentage of copper in sample = 60%

Explanation:

Given:

Mass of copper = 150 gram

Mass of brass = 250 gram

Find:

Percentage of copper in sample

Computation:

Percentage of copper in sample = [Mass of copper / Mass of brass]100

Percentage of copper in sample = [150/250]100

Percentage of copper in sample = [0.6]100

Percentage of copper in sample = 60%

Answer:

7

Explanation:

took test

Answer:

2 moles of ammonia gas (NH₃) reacts with 5/2 moles of oxygen gas (O₂) to produce 2 moles of nitrogen monoxide gas (NO) and 3 moles of liquid water (H₂O)

Explanation:

The chemical equation is:

NH₃(g) + O₂(g)⇒ NO(g) + H₂O(I)

First, we have to distinguish which are reactants and which are products.

Reactants ⇒ left side: NH₃ (ammonia gas) and O₂ (oxygen gas)

Products ⇒ right side: NO (nitrogen monoxide) and H₂O (water)

Thus, ammonia gas reacts with oxygen gas to produce nitrogen monoxide gas and liquid water.

The reaction is not balanced, because it does not has the same number of atoms of each chemical element in both sides. To balance, we have to write a coefficient of 3 for H₂O, then a coefficient of 2 for NH₃ (to balance H atoms), then a coefficient of 2 for NO, and finally a coefficient of 5/2 for O₂ (to obtain 5 atoms of O in both sides):

2 NH₃(g) + 5/2 O₂(g)⇒ 2 NO(g) + 3 H₂O(I)

According to the balanced equation, 2 moles of ammonia gas (NH₃) reacts with 5/2 moles of oxygen gas (O₂) to produce 2 moles of nitrogen monoxide gas (NO) and 3 moles of liquid water (H₂O).

Answer:

hi!

Explanation:

Well, some things I would do is to know the Periodic Table font and back. Know they elements and their class and atomic number and weight. Know how many atoms make up each element and how many protons, neutrons, and elements are in each atom.

Answer:

1/....

Explanation:

If we say acceleration 'a' is inversely proportional to mass 'm', then

a=1/m.

Answer:

may be the answer is Heat and pressure - melting - cooling

Answer:

It should have about 70-80 pounds of air pressure.

Answer:

5 lbs is what I read on the internetluv </3

Answer:

Explanation:

It can be determined by measuring the Ph. D is incorrect.

C: is wrong because if you are making something acidic, you are increasing the H+

B: is the correct answer.

A: pH decreases. H+ increases which makes the Ph decrease. It is an oddity of the formula that makes this happen.

Answer:

There are 0.5 mole in 20g of argon.

Explanation:

40 g of argon = 1mole

Then 20g of argon is,

→ 1/40 × 20

→ 0.5 mole

Answer:

[tex]n = \frac{mass}{molar \: mass} \\ n = \frac{20g}{39.948 \frac{g}{mol} } \\ n = 0.5 \: mol \: of \: argon[/tex]

Explanation:

hope this makes sense

:)

Answer:

342.15 g/mol

..........

Answer:

Elementos.

Explicación:

Los elementos son las sustancias puras que están formadas por el mismo tipo de átomos, es homogéneo y no se puede descomponer por medios químicos. El elemento tiene el mismo tipo de átomos que son similares en tamaño y forma. Es un tipo de materia pura que tiene solo un tipo de átomos y no se puede descomponer más porque no está hecha de dos sustancias, es solo una sustancia, por eso no se puede descomponer por medios químicos.

Answer: cuhh

Explanation:

Explanation:

this is ur answer i hope.........

Answer:

The temperature on the graph is higher at point 5 than at point 1.  The correct answer is the last answer choice that you showed.

Explanation:

The temperature at point 1 is -10 degrees Celsius, while the temperature at  point 5 is 120 degrees Celsius. This is a 1300% increase.

See the calculation here: https://www.calculatorsoup.com/calculators/algebra/percent-change-calculator.php?v_1=-10&v_2=120&action=solve

I hope this helps.  

Answer:

Explanation:

The answer is C Enthaply and entropy because temperature plays a big role in reactions

Answer:

c

Explanation:

a p e x :)

Answer:

1. Hidracidas a. MX

2 Acidas c. MHXO

3. Oxacidas  b. MXO

4. Basicas d. M(OH)X

Explanation:

¡Hola!

En este caso, de acuerdo con el concepto de sal, la cual está generalmente dada por la presencia de al menos un metal y un no metal, es posible encontrar cuatro tipos de estas; hidrácidas, oxácidas, básicas y ácidas, en las que las primeras dos son neutras pero la segunda tiene presencia de oxígeno, la tercera tiene iones hidróxido adicionales y la cuarta iones hidrógeno de más.

Debido a la anterior, es posible relacionar cada pareja de la siguiente manera:

1. Hidracidas a. MX

2 Acidas c. MHXO

3. Oxacidas  b. MXO

4. Basicas d. M(OH)XO

En las que M se refiere a un metal, X a un no metal, H a hidrógeno y O a oxígeno.

¡Saludos!