what flora eat? pliz tell me someone​

Answer:

Answer: There are 1.53 moles present in   molecules of water in a beaker.

Explanation:

According to the mole concept, there are  molecules present in 1 mole of a substance.

So, number of moles present in  molecules are calculated as follows.

Thus, we can conclude that there are 1.53 moles present in   molecules of water in a beaker.

Explanation:

Answer:

12,096 mg of antibiotics

Explanation:

cuz honeyyy:

160lb=72 kg

6mg twice a day so daily 12mg

12mg per kg so 12×72 =864

for 14 days is :864×14=12,096

Answer:

See explanation

Explanation:

Specific activity of an enzyme is defined as a measure of the rate of reaction between enzyme and substrate.

In the study of enzyme kinetics, specific activity is particularly regarded to be the amount of substrate converted by the enzyme per milligram of protein per unit of time. It is thus a reliable measure of enzyme activity per milligram of total protein.

On the other hand, the turnover number is defined as a measure of the number of conversions achieved by a substrate molecule in one second at a particular active site depending on the specific enzyme concentration.

Since specific activityof the enzyme is the ratio of the enzyme activity to enzyme concentration, then specific activity can be used as a measurement of enzyme purity.

M = 3.0 mol/L

V = 4 L

n

M = n / V

n = MV

n = (3.0 mol/L)(4 L)

n = 12 mol

Therefore, the number of moles of NaCl present is 12 mol.

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Answer 12 mol

Explanation: [tex]C_{M} = \frac{n}{V} ==> n = C_{M} *V=4*3=12 mol[/tex]

Answer:

4

Explanation:

Answer:

[tex]n_{Mg}=3.50molMg\\\\ n_{Cl}=7.00molCl\\\\n_O=28.0molO[/tex]

Explanation:

Hello there!

In this case, according to the given information it turns out possible for us to realize that one mole of the given compound, Mg(ClO₄)₂, has one mole of Mg, two moles of Cl and eight moles of O; thus, we proceed as follows:

[tex]n_{Mg}=3.50molMg(ClO_4)_2*\frac{1molMg}{1molMg(ClO_4)_2}=3.50molMg\\\\ n_{Cl}=3.50molMg(ClO_4)_2*\frac{2molCl}{1molMg(ClO_4)_2}=7.00molCl\\\\n_O=3.50molMg(ClO_4)_2*\frac{8molO}{1molMg(ClO_4)_2}=28.0molO[/tex]

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Answer:

Like any compound ending in '-ane', hexane is an alkane. It is commonly referred to as n-hexane and classified as a saturated hydrocarbon

Answer:

its saturated

cus its like

CnH2n+2

Answer:

132 amu

Explanation:

ammonium sulphate is [tex](NH_4)_{2} SO_4[/tex]

to calculate molecular weight we need

atomic weight of the element of the compound

here ammonium sulphate is formed by two elements

2 nitrogen , 8 hydrogen , 1 sulphur amd 4 oxygen

atonomic number of nirogen is 14 , hydrogen is 1 , sulphur has 32 and oxygen has 16

so lets calculate molecular weight of ammonium sulphate

2*14 + 8*1 + 1*32 + 4*16

28 + 8 + 32 + 64

132 amu

[tex] \huge \mathbb{ HI !!}[/tex]

Although caffeine (a stimulant found in coffee and tea) is a relatively complicated molecule, it's only eight atoms of carbon, ten of hydrogen, four of nitrogen and two of oxygen – C8H10N4O2. This kind of representation is called a molecular formula – it tells us what kind of atoms we have, and how many of each.

There are 10 hydrogen atoms in one mole of caffeine.

Caffeine belongs to the methylxanthine category of nervous system stimulants. It's just a cognitive booster that improves alertness but also attentional performance.

Caffeine's chemical formula would be C8H10N4O2, that indicates it contains eight carbon atoms, ten hydrogen atoms, four nitrogen atoms, and two oxygen atoms.

So it can be seen that , 10 hydrogen resent in caffeine molecule.

To know more about caffeine

https://brainly.com/question/9255669

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Explanation:

don't know .............

.....how

Answer:

a  lipped cylindrical glass container for laboratory use

Explanation:

Answer:

The hydride ion,H−is a stronger base, so it will abstract a proton from the water. As the water will give protons, so water will work as an acid and an acid-base reaction will take place. Hydride ions get protons from water and form hydrogen gas and hydroxide ions.

Sodium hydride is the chemical compound with the empirical formula NaH. This alkali metal hydride is primarily used as a strong yet combustible base in organic synthesis. NaH is a saline (salt-like) hydride, composed of Na+ and H− ions, in contrast to molecular hydrides such as borane, methane, ammonia, and water.

Answer:

3.59x10⁻⁴ mol

Explanation:

Assuming ideal behaviour we can solve this problem by using the PV=nRT formula, where:

We input the data given by the problem:

And solve for n:

Answer:

the characteristics of primary standard substances are:

1.High purity.

2.Stability (low reactivity)

3.Low hygroscopicity

4.High equivalent weight

5.Non-toxicity.

Ready and cheap availability.

Answer:Muscle growth or “skeletal muscle hypertrophy,” as it's called at science parties) is the result of a complex process that adds more myosin “filaments” to each muscle fiber. This makes the “engine” of the cell bigger and stronger over time. ... This process is called muscle protein synthesis, or MPS. Skeletal muscle is composed of thread-like myofibrils and sarcomeres that form a muscle fiber and are the basic units of contraction. The 650 skeletal muscles in the human body contract when they receive signals from motor neurons, which are triggered from a part of the cell called the sarcoplasmic reticulum.

Answer: The mass of [tex]CO_2[/tex] produced is 12.32 g

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.  The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Given mass of ethane = 4.21 g

Molar mass of ethane = 30 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of ethane}=\frac{4.21g}{30g/mol}=0.140mol[/tex]

Given mass of oxygen gas = 31.9 g

Molar mass of oxygen gas= 32 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of oxygen gas}=\frac{31.9g}{32g/mol}=0.997mol[/tex]

The chemical equation for the combustion of ethane follows:

[tex]2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O[/tex]

By stoichiometry of the reaction:

If 2 moles of ethane reacts with 7 moles of oxygen gas  

So, 0.140 moles of ethane will react with = [tex]\frac{7}{2}\times 0.140=0.49mol[/tex] of oxygen gas

As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, ethane is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 2 moles of ethane produces 4 moles of [tex]CO_2[/tex]

So, 0.140 moles of ethane will produce = [tex]\frac{4}{2}\times 0.140=0.28mol[/tex] of [tex]CO_2[/tex]

We know, molar mass of [tex]CO_2[/tex] = 44 g/mol

Putting values in above equation, we get:

[tex]\text{Mass of }CO_2=(0.28mol\times 44g/mol)=12.32g[/tex]

Hence, the mass of [tex]CO_2[/tex] produced is 12.32 g

Answer:

[tex]Key=2.5x10^{-9}[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the equilibrium constant value for the reverse reaction:

[tex]2CO_2(g) \rightleftharpoons 2CO(g) + O_2(g)[/tex]

By knowing that the equilibrium expression is actually:

[tex]Key =\frac{[CO]^2[O_2]}{[CO_2]^2} =\frac{1}{Keg}[/tex]

Thus, we plug in and solve for the inverse of Keq to obtain Key as follows:

[tex]Key =\frac{1}{4.0x10^{-10}}\\\\Key=2.5x10^{-9}[/tex]

Regards!

Answer:

0.123 mol

Explanation:

Step 1: Convert 250 °C to Kelvin

We will use the following expression.

K = °C + 273

K = 250 + 273 = 523 K

Step 2: Calculate the number of moles of gas (n)

A gas occupies a container with volume (V) 3.2 L at a temperature (T) of 523 K and pressure (P) of 1.65 atm. We can calculate the number of moles of the gas using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.65 atm × 3.2 L / (0.0821 atm.L/mol.K) × 523 K = 0.123 mol

Answer:

A mixture of 3 moles of N2, 5 moles of CO2, and 10moles of Cl2 exert a total pressure of 1120 mmHg. What is the partial pressure of CO2?

Explanation:

According to Dalton's law of partial pressures:

The partial pressure of a gas can be determined by using the formula:

[tex]the partial pressure of a gas = mole fraction of the gas * total pressure[/tex]

Partial pressure of CO2:

[tex]partial pressure of CO2= total pressure * mole fraction of CO2\\\\Mole fraction of CO2=\frac{number of moles of CO2}{total number of moles of all the gases} \\mole fraction of CO2=\frac{5mol}{3mol+5mol+10mol} = 5/18\\Partial pressure of CO2=\frac{5}{18} * 1120mmHg\\ =311.1mmHg[/tex]

Hence, the partial pressure of CO2 is 311.1mmHg.

Answer:

Percentage yield = 36.75%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C + O₂ —> CO₂

Next, we shall determine the mass of C that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C = 12 g/mol

Mass of C from the balanced equation = 1 × 12 = 13 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Next, we shall determine the theoretical yield of CO₂. This can be obtained as follow:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Therefore, 9.50 g of C will react to produce = (9.50 × 44) / 12 = 34.83 g of CO₂.

Thus, the theoretical yield of CO₂ is 34.83 g.

Finally, we shall determine the percentage yield of the reaction. This can be obtained as follow:

Actual yield of CO₂ = 12.8

Theoretical yield of CO₂ = 34.83 g

Percentage yield =?

Percentage yield = Actual yield / Theoretical yield × 100

Percentage yield = 12.8 / 34.83 × 100

Percentage yield = 1280 / 34.83

Percentage yield = 36.75%

Answer:

When red cabbage is treated with an acid or a base, it produces anthocyanin, a water-soluble pigment that changes color. In acidic situations with a pH less than 7, the pigment turns red, whereas in alkaline (basic) situations with a pH more than 7, the pigment turns bluish-green.

Explanation:

Answer:

1.Write the balanced chemical equation.

2.Convert the units of the given substance (A) to moles.

3.Use the mole ratio to calculate the moles of wanted substance (B).

4.Convert moles of the wanted substance to the desired units.

Explanation:

Answer:

O2 is the limiting reactant.

Explanation:

Hello there!

In this case, according to the given information about this reaction, one could identify the limiting reactant by performing a mole ratio of H2S to SO2 and O2 to SO2:

[tex]14.3molH_2S*\frac{2molSO_2}{2molH_2S}=14.3molSO_2 \\\\17.1molO_2*\frac{2molSO_2}{3molO_2}=11.4molSO_2[/tex]

Thus, since 17.1 moles of O2 yields fewer moles than 14.3 moles of H2S, we infer the former is the limiting reactant.

Regards!

Answer:

The correct answer is - d. hydrogen bonding.

Explanation:

Water has strong hydrogen bonds between its molecules that require a very high amount of energy in order to break. Water molecules are joined together or bound with a strong intermolecular force called hydrogen bonds.

These bonds require more kinetic energy which means more temperature or heat in order to break the bonds and turn into steam and this is the reason it has a high boiling point.

Answer:

[Cr(NH3)6.]C13

Explanation:

Alfred Werner's coordination theory (1893) recognized two kinds of valency;

Primary valency which are nondirectional and secondary valency which are directional.

Hence, the number of counter ions precipitated from a complex depends on the primary valency of the central metal ion in the complex.

We must note that it is only these counter ions that occur outside the coordination sphere that can be precipitated by AgNO3.

If we consider the options carefully, only [Cr(NH3)6.]C13 possess counter ions outside the coordination sphere which can be precipitated when treated with aqueous AgNO3.

Answer:

aa

Explanation:

There is a lowercase a on both sides.

Answer:

[tex]rate = k[C] {}^{2} [D] {}^{2} \\ 7.5 \times {10}^{ - 3} = k {(0.25)}^{2} {(0.50)}^{2} \\ k = \frac{7.5 \times {10}^{ - 3} }{ {(0.25)}^{2} {(0.50)}^{2} } \\ k = 0.48 \: {mol}^{ - 3} {dm}^{9} {s}^{ - 1} [/tex]

Answer:

W = -262 J.

Explanation:

Hello there!

In this case, according to the given information, we can recall the definition of work in terms of constant pressure and variable volume as follows:

[tex]W=P(V_2-V_1)[/tex]

So we plug in the given pressure and volumes to obtain:

[tex]W=0.822atm(1.20L-4.35L)\\\\W=-2.60atm*L[/tex]

Now, we convert this number to J (Pa*m³) by using the shown below conversion factor:

[tex]W=-2.60atm*L*\frac{101325Pa}{1atm} *\frac{1m^3}{1000L}\\\\W=-262J[/tex]

Regards!