The force needed to accelerate a car at 5 m / s² that has a mass of 3,000 kg is 15 KN
F = m a
F = Force
m = Mass
a = Acceleration
m = 3000 kg
a = 5 m / s²
F = 3000 * 5
F = 15000 N
F = 15 KN
According to Newton's second law of motion, the force is equal to the rate of change of momentum of the object.
Therefore, the acceleration of the car is 15 KN
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Which of the following atoms has the smallest radius?
The Periodic Table
A. Cesium (Cs)
B. Potassium (K)
C. Sodium (Na)
D. Lithium (Li)
Answer:
answer= lithium
Explanation:
electronic configuration
a truck of mass 2.40×103kg is moving at 25.0 m/s . when the driver applies the brakes, the truck comes a stop after traveling 48.0 m . how much time is required for the truck to stop?
The time required by the truck moving with speed 25.0 m/s and covering the distance 48.0 m is 3.84 seconds.
What is speed?
The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time, making it a scalar quantity.
As given in the question,
the initial speed of the truck when brakes are applied (u) = 25 m/s.
Final speed (v) = 0 m/s
The distance covered after brakes are applied (s) = 48 m.
By the Newton's equation of motion
[tex]v^2 = u^2 + 2as[/tex]
Putting values from the question from the question.
0 = (25)^2 + 2a(48)
a = -6.51 m/s^2
Now by the equation,
v = u + at
Putting value from question
0 = 25 - 6.51 t
t = 25/6.5
t = 3.84 seconds
Therefore, time taken is 3.84 seconds.
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Which of the following can be considered mechanical energy?
A. a hot bowl of soup
B. plant growth
C. doing bicep curls
C. doing bicep curls.
Explanation:
why? A. is considered thermal energy.
B. is considered solar energy to chemical energy.
a transformer has 1,400 turns in the primary coil and 100 turns in the secondary coil. if the primary coil is connected to a 120 v outlet and draw 0.04 a, what is the current of the secondary coil?
0.56 A is the current of the secondary coil.
transformer is the device that transfer electric energy from one AC circuit to another.
we know that ;
I ∝ 1/n;
where I IS CURRENT and n is NUMBER OF TURNS.
(I) secondary = X A
(n) secondary = 100
(I) primary = 0.04 A
(n) primary = 1400
USING THIS-----> I ∝ 1/n;
=>
0.04 A/X A =100/1400
=>X=0.56 A
as the current in the transformer is inversely proportional to the number of turns so 0.56 A is the current in the secondary coil.
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Consider the following system, where F = 120 N, m = 1 kg, and M = 5 kg. What is the magnitude of the force with which one block acts on the other?
Consider the following system, where F = 120 N, m = 1 kg, and M = 5 kg. Force exerted by the lighter block on the heavier block is F_2=20N
What is the magnitude of the force?F = 120N
m = 1kg
M = 5kg
Generally, the equation for acceleration is mathematically given as
[tex]a=\frac{F}{m+M} \\\\a=\frac{120}{1+5} \\[/tex]
a=20m/s^2
Let's formulate the heavier block's equation of motion.
F_1=F-F_2
Ma=F-F_2
It is estimated that the lighter block will exert the following force on the heavier block:
[tex]&F_2=\mathrm{F}-\mathrm{Ma} \\&F_2=120-(5 *20) \\[/tex]
F_2=20N
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4. A vehicle is moving at 5 ms. How long will it take to stop at a distance of 15m
Answer:
time is 3 seconds.
Explanation:
formula is given in the picture
Stephen learned that any two objects exert a gravitational force on each other. If the distance between two objects triples, the gravitational force between them will change by a factor of what?.
The gravitational force between them will change by a factor 1/9.
We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses objects. The magnitude of gravitational force can be determined as
F = G.m1.m2 / R²
where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.
From the question above, we know that
R2 = 3R1
By substituting the following parameters, we get
F2/F1 = G.m1.m2 / R2² / G.m1.m2 / R1²
F2/F1 = G.m1.m2 / (3R1)² / G.m1.m2 / R1²
F2/F1 = 1/9
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a force of 40N stretches a wire through 3.0 cm what force will stretch it through 5.0cm and through what length will a force of 100N stretch it ?what assumption have you made
When the extension of the spring becomes 5 cm, the applied force is 66.67 N.
The length produced by a force of 100 N is 7.5 cm.
What is spring constant?The spring constant of a spring is also known as force constant, is the ratio of force to the extension of a spring.
The force constant of a spring describes how stiff a spring is or how tough a spring is.
The force constant of the given spring is calculated as follows;
k = F/x
where;
F is the applied force on the springx is the extension of the springk is the spring constantThe extension of the spring = 3 cm = 0.03 m
The force is given as 40 N
K = 40 N / 0.03 m
K = 1,333.33 N/m
If the extension of the spring becomes 5 cm, the applied force is calculated as follows;
F = kx
F = 1,333.33 x 0.05
F = 66.67 N
The extension produced by a force of 100 N;
x = F/k
x = 100/1,333.33
x = 0.075 m = 7.5 cm
The assumption made is that the applied force is directly proportional to the extension of the spring.
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HELP!!Use complete sentences to answer these questions.
1. Share an example from your house or neighborhood that represents a physical change occurring.
2. Share an example from your house or neighborhood that represents a chemical change occurring.
It is a multistep plan or strategy that allows you to achieve your goals.
1.
A kayaker is paddling across a river at 2.50m/s with a Northeastern direction (45 degrees N of E). A current pulls him with a velocity of 1.25m/s East. What is the kayakers resultant velocity?
According to the given statement The kayaker has a resultant velocity is ||v + w|| ≈ 2.80 m/s.
What is the velocity of resultant?An object's total vector velocity is the sum of its component vector velocities. The scalar product of an object's mass and acceleration vector equals the sum of the vector forces acting on it.
Briefing:The kayaker has velocity vector
v = (2.50 m/s) (cos(45º) i + sin(45º) j )
v ≈ (1.77 m/s) (i + j )
and the current has velocity vector
w = (1.25 m/s) (cos(315º) i + sin(315º) j )
w ≈ (0.884 m/s) (i - j )
The kayaker's resultant velocity is the sum of these:
v + w ≈ (2.65 m/s) i + (0.884 m/s) j
The kayaker has a resultant velocity of ||v + w|| ≈ 2.80 m/s in a direction θ such that
tan(θ) = (0.884 m/s) / (2.65 m/s)
θ ≈ 18.4º
or about 18.4º north of east.
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The complete question is -
A kayaker paddling 2.50 m/s at an angle of 45° (northeast) and the current is moving 1.25 m/s at an angle of 315° (southeast). What is the kayaker's resultant velocity?
3.
- The north and south poles of a
solenoid change with
A the type of material in the core
B the number of loops in the coil
C the tightness of loops in the coil
D the direction of the current
"The direction of the current."
A solenoid's north and south poles are determined by two variables. two factors: the winding direction and the direction in which the stream flows (clockwise or counter-clockwise). The positive pole of the power source (such as a battery) should be determined first, followed by the end of the solenoid that will be connected to it.
Now, determine which way the winding is going by peering down the solenoid tube. The south pole is present if the positive wire is rotated clockwise, and the north pole is present if it is rotated counterclockwise. In conclusion, the magnetic south pole is always in reference to the positive wire clockwise.
The magnet's poles will be created as a result of current flowing through the solenoid, and the clock face rule in a solenoid is used to predict their positions. According to the rule, the south pole will be formed if you gaze through a solenoid at a location where the current runs in a clockwise direction. On the other hand, the north pole will be visible if viewed from the side where the current is flowing counterclockwise.
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find the stationary front located in northwestern canada. the likely air mass to the west of the stationary front is a air mass which is likely to be than the air mass to the east.
According to air masses classification, we can assume that to the west of the stationary front in northwestern Canada there is a maritime Polar (mP) air mass which is likely to be warmer than the air mass to the east. Option B) mP, warmer.
What are the air masses?
Air masses are horizontal extensions of moving air in which humidity, temperature, and physical properties are homogeneous.
Air masses can be classified according to their temperature (Cold or Warm), nature (continental -c- or maritime -m-), Origin region (Polar -P-, Artic -A-, Antarctic -AA-, Tropical -T-, Equatorial -E-)
Joining the previous classifications, we can identify different air masses
Continental Arctic and Antarctic air masses (cA and CAA)Maritime Artic air masses (mA)Continental Polar air masses (cP)Maritime Polar air masses (mP)Maritime Tropical (mT)Continental Tropical air masses (cT)Maritime Equatorial (mE)Maritime Polar air masses (mP)
These are cold and humid air masses that originate far from the poles and imply mild weather in coastal regions. In the winter they can be warmer than the continental Polar Air Masses (cP) and cooler in the summer. The masses that penetrate from the west are forced to rise when they encounter obstacles causing precipitation.Looking at the image, we will focus on the superior left area near the A. This is a red line with semicircles that represents a warmer front.
This red line comes from the west and moves forward to the northeast. Since this point is located near the coast, we can assume this is a maritime air mass.
These red lines, which represent worm fronts, suggest that to the west, the air is warmer than to the east.
The likely air mass to the west of the stationary front is a maritime Polar (mP) air mass which is likely to be warmer than the air mass to the east.
Option B) mP, warmer.
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Complete question
Find the stationary front located in northwesterm Canada.
The likely air mass to the west of the stationary front is ______ a air mass that is likely to be _____ than the air mass to the east.
A) cP: cooler
B) mP: warmer
C) cP: warmer
D) ml: warmer
A negatively charged conductor is brought in contact with a neutral conductor.
Which choice most accurately describes the motion of charge between these two objects?
The electrons in the charged object are attracted to the protons in the neutral object. Some of the electrons move from the
charged object to the neutral object, resulting in two negatively charged objects.
The protons in the neutral object are attracted to the charged object. Some of the protons move from the charged object
O to the neutral object. Finally, the neutral object becomes negatively charged, while the initial charged object becomes
neutral.
The protons in the neutral object are attracted to the charged object. Some of the protons move from the charged object
to the neutral object, resulting in two negatively charged objects.
The electrons in the charged object are attracted to the protons in the neutral object. Some of the electrons move from the
O charged object to the neutral object. Finally, the neutral object becomes negatively charged, while the initial charged
object becomes neutral.
When a negatively charged conductor is brought in contact with a neutral conductor, then both objects become charged negatively.
Conductors are substances through which electrons flow freely. When a conducting material has a charge, the charges repel and move away from each other, distributing themselves evenly about the outer surface .
Charging by conduction involves the contact between a charged and a neutral object. Therefore, when an uncharged conductor is brought in contact with a charged conductor, charge is shared between the two conductors and hence the uncharged conductor also gets charged.
Both objects have the same type of charge, during charging by conduction. If a negative object is used to charge a neutral object, then both objects become negatively charged.
Any charged object whether positively or negatively charged have an attractive interaction with a neutral object. Positively charged and neutral objects attract each other and similarly negatively charged and neutral objects attract each other.
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A place kicker must kick a football from a point 31.5 m from a goal. As a result of the kick, the ball must clear the crossbar, which is 3.05 m high. When kicked the ball leaves the ground with a speed of 20.2 m/s at an angle of 53° to the horizontal.
(a) By how much does the ball clear or fall short of clearing the crossbar?
(b) Does the ball approach the crossbar while still rising or while falling?
(a) The ball cleared the crossbar by 10.23 m.
(b) The ball approaches the crossbar while falling.
What is the maximum height reached by the ball?
The maximum height reached by the ball is calculated by applying the following kinematic equation as shown below;
H = u² sin²θ / 2g
where;
u is the initial velocity of the ballθ is the angle of projection of the ballg is acceleration due to gravityH = (20.2² x (sin 53)²) / (2 x 9.8)
H = 13.28 m
ΔH = 13.28 m - 3.05 m = 10.23 m
The horizontal distance travelled by the ball is calculated as follows;
R = u² sin(2θ) / g
R = (20.2² sin(2 x 53) ) / (9.8)
R = 40 m
Thus, the ball cleared the crossbar and since the maximum height travelled by the ball is far greater than the height of the crossbar, the ball will approach the crossbar while falling.
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When a plane descends from its cruising height to land on a runway, 78 400 000J of gravitational potential energy is transferred. If the mass of the plane is 40 000 kg, what was the cruising altitude of the plane before its descent?
The cruising altitude of the plane of mass 40000 kg before its descent is 196 m
U = m g h
U = Gravitational potential energy
m = Mass
g = Acceleration due to gravity
h = Vertical height
U = 78400000 J
m = 40000 kg
g = 10 m / s²
h = U / m g
h = 78400000 / 40000 * 10
h = 196 m
Gravitational potential energy is a type of energy related to gravity. It is energy acquired by an object due to its change in position in the presence of gravitational field.
Therefore, the cruising altitude of the plane before its descent is 196 m
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Which two wave features are specific to longitudinal waves?
There are four aspects of waves that only pertain to specific types of waves. Peaks and troughs are used to describe transverse waves. Compressions and rarefactions are used to describe longitudinal waves. Medium, wavelength, amplitude, and frequency are the four qualities that both types of waves have in common.
What are a longitudinal wave's two parts?In addition to longitudinal waves, which also move in the direction of the medium, there is another type of wave that does so: the transverse wave. While longitudinal waves are made up of compressions and rarefactions, transverse waves are made up of crests and troughs.
What features do longitudinal waves possess?In longitudinal waves, localized compression and rarefaction are observed. Compressions are regions of extremely high pressure because of the near proximity of the particles. Rarefactions are regions of low pressure because to the particles' enhanced dispersion.
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You are asked to consult for the city's research hospital, where a group of doctors is investigating the bombardment of cancer tumors with high-energy ions. The ions are fired directly toward the center of the tumor at speeds of 5. 5 ×106m/s. To cover the entire tumor area, the ions are deflected sideways by passing them between two charged metal plates that accelerate the ions perpendicular to the direction of their initial motion. The acceleration region is 5. 0 cm long, and the ends of the acceleration plates are 1. 5 m from the patient.
What sideways acceleration is required to deflect an ion 2. 0 cm to one side?
Express your answer to two significant figures and include the appropriate units
The sideways acceleration is required to deflect an ion 2. 0 cm to one side is [tex]6.56[/tex]×[tex]10^{12}[/tex] m/[tex]s^{2}[/tex].
Velocity = 5. 5 × [tex]10^{6}[/tex] m/s
acceleration region = L1 = 5.0 cm = 0.05 m
Ends of the acceleration plates = L2 1. 5 m
D = 0.02 m
a = [tex]\frac{2v^{2}d }{2L1L2+L1^{2}}[/tex]
Putting the values
a = 2×( 5. 5 × [tex]10^{6}[/tex])^2 × 0.02 m / 2 × 0.05m × 1.5m + (0.05m)^2
a = 1×10^12 m^2/s / 0.15m^2+2.5×10^-3m^2
a = 2 ×10^5 m^2/s / 0.1525 m^2
a = [tex]6.56[/tex]×[tex]10^{12}[/tex] m/[tex]s^{2}[/tex]
The sideways acceleration is required to deflect an ion 2. 0 cm to one side is [tex]6.56[/tex]×[tex]10^{12}[/tex] m/[tex]s^{2}[/tex].
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The sideways acceleration required to deflect an ion 2.0cm to one side is [tex]7.9*10^{12} m/s^{2}[/tex] expressed to 2 significant figures
Given the following:
V = 5.5 X10 m/s
Acceleration region (L[tex]^{1}[/tex]) = 5.0 cm long
Ends of the acceleration plates are L[tex]_{2}[/tex] = 1.5m from the patient
Now determine the sideways acceleration to deflect anion
d=2.0cm to one side.
Sideway acceleration is:
[tex]a=\frac{2V^{2}d }{2L_{1}L_{2}+L_{1} ^{2} }[/tex]
[tex]a=\frac{2*(5.5*10^{6})^{2}*0.02 }{(2*0.05*1.5)+0.05^{2} }[/tex]
[tex]a=7.9344*10^{12}m/s^{2} \\[/tex]
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A battery-powered lawn mower has a mass of 25.0 kg. If a student pushes the lawn
mower with 15.5 N of force, the lawn mower’s motor provides a force of 20.0 N, and
the grass provides a resistance force of 3.00 N, what is the net force and acceleration
of the lawn mower?
The net force of the lawn mower is 32.5 N and acceleration is 1.62 m/s^2.
The student pushes the lawn mower with 15.5 force and the lawn mower's motor provides 20.0 N force. The grass has a resistance force 3.0 N which is in opposite direction to the student's and lawn mower's forces. So, the net force is given,
F = 15.5 N + 20.0 N - 3.0 N = 32.5 N
According to Newton's second law, we know the relation between acceleration and force applied. Force is equal to mass times acceleration. The mass of the lawn mower is 25.0 kg.
[tex]a=\frac{F}{m}[/tex]
a = 32.5/20 = 1.62 m/s^2
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in about 1915, henry sincosky of philadelphia suspended himself from a rafter by gripping the rafter with the thumb of each hand on one side and the fingers on the opposite side (fig. 6-21). sincosky’s mass was 79 kg. if the coefficient of static friction between hand and rafter was 0.70, what was the least magnitude of the normal force on the rafter from each thumb or opposite fingers? (after suspending himself, sincosky chinned himself on the rafter and then moved hand-over-hand along the rafter. if you do not think sincosky’s grip was remarkable, try to repeat his stunt
The least magnitude of the normal force on the rafter from each thumb or opposite fingers is 276.5 Newtons.
As we know, henry is suspended by using his hands.
If he not going upward or downwards. we can conclude that the magnitude of all forces should be cancelling each other.
The force that is stopping the thumbs and the finger is frictional force.
Friction force f is a kind of force that comes into play when their is an actual slipping or the tendency to slip between any two contacted surface.
f = μN
where N is the normal force.
The net friction force should be equal to the total weight if the body,
Frictional force f by the fingers can be distributed equally in four parts,
mg = 4f
mg = 4μN
Mass is 79 Kg. g is 9.8m/s² and the value of μ is 0.7.
79 x 9.8 = 4 x 0.7 x N
N = 276.5 newtons.
So the least normal force on the each thumb and fingers is 276.5 N.
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The inner diameter of a small test-tube Can be measured accurately using
Answer:
the Vernier caliper
Explanation:
Answer:
Vernier caliper
PLSS MARK AS BRAINLIEST
If you ride a bike at a constant speed in a circle on a flat surface that has a coefficient of kinetic friction of 0.27. What is the centripetal acceleration of the bike?
The centripetal acceleration of the bike is 2.65 m/s².
What is centripetal acceleration?
Centripetal acceleration is the acceleration of an object moving in a circular track. This acceleration describes the rate of change of tangential velocity with time in the circular track.
The magnitude of the centripetal acceleration, can be determined by applying the formula for net force.
At constant speed, the centripetal acceleration of the bike is given as;
μmg = ma
μg = a
a = μg
where;
μ is coefficient of frictiong is acceleration due to gravitya = (0.27) x (9.8 m/s²)
a = 2.65 m/s²
Thus, the centripetal acceleration of the bike increases with increase in velocity.
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Find the force required to do 25 joule work when the force causes a displacement of 0.5m
Answer: Force required to 25 joule work when the force causes a displacement of 0.5m is 50N
Explanation: To calculate the work done we use the formula
W=F.s (1)
W= work done
F= force applied s= displacement
Given, work done W= 25 joules= 25 J
displacement s= 0.5m
∴From equation (1) we get the force required when work is done and displacement is given, that is
F[tex]=\frac{W}{s}[/tex] (2)
∴Force required [tex]F=\frac{W}{s}= \frac{25J}{0.5m}=50N[/tex]
(1 J is the work done by a force of 1 N acting over a displacement of 1 m and so 1 J= 1 Nm⇒ 1 N = 1 J/m)
ANS: Force required to do 25 J work when a force causes displacement of 0.5m = 50 N
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the motion of one particle of a gas is unaffected by the motion of other particles of the gas unless the particles _____.
The motion of one particle of a gas is unaffected by the motion of other particles of the gas unless the particles collide.
What causes the motion of particles?Heat is the primary cause of particle motion on Earth. The temperature of any substance is correlated with the energy of the atoms and molecules that comprise it. Energy is conserved, thus if one particle loses energy, another one acquires it.
What is the motion of particles of matter called?The components of matter are also continually in motion. They are energetic in motion. The kinetic theory of matter states that all matter is made up of particles that are constantly moving.
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Ted wants to hang a wall clock on the wall by using a string. if the mass of the wall clock is 0.250 kilograms, what should be the tension of the string so that it can sustain the weight of the wall clock? a. 0.245 newtons b. 2.45 newtons c. 0 newtons d. 4.90 newtons e. 0.120 newtons
Answer:
B. 2.45 Newtons
Explanation:
This is a tension force problem with only tension and the weight force acting on the object. Using Newton's second law F=ma, and there being no acceleration in the system, T-w=0. Using this, T=w. w=mg, therefore (.250kg)(9.8m/s^2) = 2.45 Newtons
Answer:
See image
Explanation:
Plato
if you have not already done so, convert 70 mmhg and 120 mmhg into si pressure units. now that your pressures are in si units, critically think about your original claim regarding the heart’s blood pressure as either gauge pressure or absolute pressure. how does this pressure compare to atmospheric pressure? justify your reasoning regarding gauge pressure vs. absolute pressure in terms of how the body pressure compares to atmospheric pressure, which is also a pressure that is being (nearly) uniformly externed on the body at all times.
70 mmHg will convert to 9.333kpa pressure SI units while 20 mmHg will convert to 16kpa pressure SI units.
Absolute pressure for 70 mmHg is 110.658kpa
Absolute pressure for 120 mmHg is 117.325kpa
Converting 70 mmHg and 120 mmHg into SI pressure units:
If 760 mmHg=101.325kpa
∴ 70 mmHg=?
= 70*101.325/760
=9.333kpa
So 70 mmHg will be 9.333kpa
If 760 mmHg=101.325kpa
∴120 mmHg=?
=120*101.325/760
=16kpa
So 120 mmHg will be 16kpa
Blood pressure is generally measured in mmHg because mercury is used in the thermometers, so it is convenient to measure the pressure by rise in height of mercury in the thermometer.
However pressure measured by the thermometer is always gauge pressure, given by:
[tex]P_{gauge} =P_{abs} -P_{0}[/tex], where [tex]P_{0}[/tex] is atmospheric pressure and [tex]P_{abs}[/tex] is absolute pressure.
We now calculate absolute pressure for [tex]P_{1}[/tex] 70 mmHg and [tex]P_{2}[/tex] 120 mmHg,
[tex]P_{1} abs=P_{1} g+P_{0}[/tex]
[tex]=101.325+9.333[/tex]
=110.658kpa
[tex]P_{2} abs=P_{2} g+P_{0[/tex]
=101.325+16
=117.325kpa
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in the winter sport of bobsledding, athletes push their sled along a horizontal ice surface and then hop on the sled as it starts to careen down the steeply sloped track. in one event, the sled reaches a top speed of 9.2 m/sm/s before starting down the initial part of the track, which is sloped downward at an angle of 9.0 ∘∘.
Due to the principle of energy conservation, the sled's initial potential and kinetic energy are identical to its ultimate kinetic energy. So the correct answer is vf =21.71 m/s.
According to no 12th law, additional forces are equal to M. A. Therefore, in this instance, MG sine data equals M. A. This will give us A. equals theta in the G symbol It will be the first equation at A. equals D B divided by D T. By using dx by DT, or D X by D T, we can multiply and divide. D X's indu D D. As a result, we shall obtain V D V by D X equals a. The second equation will be this.
The result of equation 192 is then that D V by D X equals G sign theta. Therefore, V D V is G scientology to be X equal. Now that D V equals integral energy, we can integrate this integral. G sign to D X to D. that we will receive G scientific data is equivalent to energy We Squire divided by two. X. We'll see. At X=0, nothing happens. We will have a speed of 9.2 m/s. 9.2 squared divided by two will equal C. 42.32 is what that comes to.
Then we divide Squire by two to get theta in the G sign. X + 42.32. Then, using this information, we can determine that we are equivalent to the root energy of two indu G sine theta into X plus 42.32. The numbers that are route off two can be changed to 9.8 m/s. Nine degree Squire In is 0.156. surplus food industry 1 40 m less 42.32. We shall therefore arrive at a quanto of 21.71 m/s by solving this.
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a sphere of mass 3.9 ✕ 10-4 kg is suspended from a cord. a steady horizontal breeze pushes the sphere so that the cord makes a constant angle of 32° with the vertical.
The push magnitude and the tension of the cord is 5.4 × 10^-4
What is cord ?
cord is the slender flexible material usually consisting of several stands or twisted together.
It is wired coverd in rubber or plastic which connects electrical equipment to an electricity supply.
The free body diagram as per the question with the tension of string T .
The force of gravity ~mg
The force of air ~f
Since the sphere is motionless the net force on it is 0.
And the x and y are the components of the equation are zero
Tsin + 0 = F
Tcos - mg= 0
Where ¥ = 32°
Thus we get
T= (3.9×10^-4 kg ) (9.8m/s^2)/cos32°
= 2.1×3.2×10^-4
Solving T
We can get the F =
(3.2×10^-4)sin 32° =
5.4 ×10^-4
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Qno6: Two singers are singing simultaneouldy with intensity level of 60 db of each in a hall.
a.is intensity of sound in the hall is doubled?
b.is the intensity level of the sound is doubled
The intensity of sound in each hall will not be doubled.
The intensity of sound may be defined as, the power carried by sound waves per unit area in a direction perpendicular to that area. The intensity of sound is measured in decibel i.e. the unit is written as (dB).
It can be formulated as ,
I = pv
Where, I is the intensity of the sound, p is the pressure of sound, v is the velocity of the particle. And here, I and v are vectors, therefore they both have a magnitude and a direction. The average direction of energy flow is represented by the direction of sound intensity.
Therefore, due to the fact that our hearing is not linear and dB is a logarithmic scale, even though the energy may have doubled, the perceived intensity has not. In actuality, one of the singers' voices may both hide the other's and have the potential to improve it.
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A toy train with a mass of 2 kg moving at 10 m/s collides with a 2-kg toy train that is
stationary. If the two trains move together after the collision, what will be their speed after impact
Because momentum will be conserved, their common speed after impact will be 5 m/s
Third Newton's Law of MotionThe third Newton's law of motion states that in any action, there will be equal and opposite reaction.
Given that a toy train with a mass of 2 kg moving at 10 m/s collides with a 2-kg toy train that is stationary. If the two trains move together after the collision, their speed V after impact can be calculated through the formula
M1U1 + M2U2 = (M1 + M2)V
The given parameters are
M1 = 2 kgU1 = 10 m/sM2 = 2kgU2 = 0V = ?Substitute all the parameters into the formula
2 × 10 + 2 × 0 = (2 + 2)V
20 = 4V
V = 20/4
V = 5 m/s
Therefore, their speed after impact is 5 m/s
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A cat chases a mouse across a 0.94 m high table. The mouse steps out of the way, and the cat slides off the table and strikes the floor 1.0 m from the edge of the table. The acceleration of gravity is 9.81 m/s 2 . What was the cat’s speed when it slid off the table? Answer in units of m/s
The speed of the cat when it slide off the table is 2.27 m/s
To obtain the answer to the given question, we'll begin by obtainig the time taken for the cat to strike the floor. This can be obtained as follow:
Height (h) = 0.94 mAcceleration due to gravity (g) = 9.81 m/s²Time (t) = ?h = ½gt²
0.94 = ½ × 9.81 × t²
0.94 = 4.905 × t²
Divide both side by 4.905
t² = 0.94 / 4.905
Take the square root of both side
t = √(0.94 / 4.905)
t = 0.44 s
How to determine the speedThe speed of the cat can be obatined as illustrated below:
Horizontal distance (s) = 1 mTime (t) = 0.44 sspeed (u) = ?s = ut
1 = u × 0.44
Divide both sides by 0.44
u = 1 / 0.44
u = 2.27 m/s
Thus, we can conclude that the speed of the cat is 2.27 m/s
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