what is equivalent to 6.253x10-2

Answer:

π2,√80,12

Step-by-step explanation:

π2= 6.28

√80= about 8

12=12

Hope I could help!

Step-by-step explanation:

put 6x-10 in y=x-4

so

y = (6x-10) - 4

y = 6x-14

Answer:

I think ir is 2 -2

Step-by-step explanation:

hope it helps

Answer:

36

Step-by-step explanation:

So to find the last angle first. The formula is a power 2+b power 2=c power 2

So 9 power 2 is 81 and 12 power 2 is 144

144+81=225

the square root of 225 is 15. So x is 15

No we just have to do 9+12+15=36.

36 is the perimeter

The volume of a pyramid with a square base is 17.6 cubic centimeter.

Given the following data;

To find the volume of a pyramid with a square base;

Mathematically, the volume of a pyramid with a square base is given by the formula;

[tex]V = A(\frac{h}{3})[/tex]

Where;

First of all, we would determine the length of sides of the square base from its perimeter;

[tex]Perimeter \ of \ square = 4s\\\\9.9 = 4s\\\\s = \frac{9.9}{4}[/tex]

s = 2.475 cm

Next, we would determine the area of the square;

[tex]Area \ of \ a\ square = s^{2} \\\\Area \ of \ a\ square = 2.475^{2}[/tex]

Area of a square = 6.126 cm

Now, we would use the above value to find the volume of a pyramid with a square base.

Substituting the values into the formula, we have;

[tex]V = 6.126*(\frac{8.6}{3})\\\\V = 6.126*2.867[/tex]

Volume, V = 17.6 cubic centimeter

Therefore, the volume of a pyramid with a square base is 17.6 cubic centimeter

Find more information here: https://brainly.com/question/16627760

Answer:

H

Step-by-step explanation:

For F  - Median For Class 1 is 52.5 Median for Class 2 is 75 ( False )

For G - Range for class 2 is 75 Range for class 1 is 45.9 ( False )

For H - IQR for class 1 is 30.45 IQR for class 2 is 60 ( True )

For J - Minimum for Class 2 is 30 Minimum for Class 1 is 30 ( False )

Answer:

Y =-25x +225

Step-by-step explanation:

First you can count the gradient first. Use then you can count y intercept

Answer:

120

Step-by-step explanation:

reduce the fraction from

[tex]48 \times \frac{250}{100 } [/tex]

to

[tex]48 \times \frac{5}{2} [/tex]

then multiply and you get 24 × 5 which is 120

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{2h - 3 }\mathsf{>}\large\textsf{ 15}[/tex]

[tex]\large\text{ADD 3 to BOTH SIDES}[/tex]

[tex]\large\textsf{2h - 3 + 3 }>\large\textsf{ 15 + 3}[/tex]

[tex]\large\text{CANCEL out: \textsf{-3 + 3} because that gives you 0}[/tex]

[tex]\large\text{KEEP: \textsf{15 + 3} because it helps you solve for your h-value}[/tex]

[tex]\large\textsf{15 + 3 = \boxed{\large\textsf{\bf 18}}}[/tex]

[tex]\large\text{NEW EQUATION: \textsf{2h} }\mathsf{>}\large\textsf{ 18}[/tex]

[tex]\large\text{DIVIDE 2 to BOTH SIDES}[/tex]

[tex]\mathsf{\dfrac{2h}{2}>\dfrac{18}{2}}[/tex]

[tex]\large\text{CANCEL out: }\mathsf{\dfrac{2}{2}}\large\text{ because it gives you 1}[/tex]

[tex]\large\text{KEEP: }\mathsf{\dfrac{18}{2}}\large\text{ because it gives you your h-value is being compared to}[/tex]

[tex]\large\text{NEW EQUATION: }\mathsf{h > \dfrac{18}{2}}[/tex]

[tex]\mathsf{\dfrac{18}{2}}[/tex]

[tex]\mathsf{= 18\div 2}[/tex]

[tex]=\boxed{\mathsf{\large\textsf {\bf 9}}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf h > 9}}}\huge\checkmark\\\\\boxed{\boxed{\rm \bf It\ it\ an\ O P E N E D\ circle\ shaded}}\\\boxed{\boxed{\rm \bf to\ the\ right\ starting\ at\ point\ 9}}\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

[tex] \quad \quad \quad \quad\tt{2h - 3 > 15}[/tex]

[tex] \quad \quad \quad \quad\tt{2h - 3 > 15}[/tex]

[tex] \quad \quad \quad \quad\tt{2h - 3 + 3 > 15 + 3}[/tex]

[tex]\quad \quad \quad \quad\tt{2h \: \: \cancel{ \color{red}- 3 + 3} \: > 15 + 3}[/tex]

[tex]\quad \quad \quad \quad\tt{2h > 18}[/tex]

[tex]\quad \quad \quad \quad\tt{ \frac{2h}{2} > \frac{18}{2} }[/tex]

[tex]\quad \quad \quad \quad\tt{ \frac{ \cancel{ \color{red}2}h}{ \cancel{ \color{red}2}} > \frac{18}{2} }[/tex]

[tex]\quad \quad \quad \quad\tt{ h > \frac{18}{2} }[/tex]

[tex]\quad \quad \quad \quad\tt{ h > 9}[/tex]

[tex]\quad \quad \quad \quad \boxed{\tt { \color{green}h > 9}}[/tex]

________

#LetsStudy

Answer:

I'm sorry, I can help you with only this one :( ∠F = 44°

Step-by-step explanation:

∠F = 180° - (46° + 90°) = 44°

Answer: look at the picture

Step-by-step explanation: Hope this help :D

the total balloon are used is 2736

Answer:

D) y = -4/3x + 5

Step-by-step explanation:

Can be checked with a calculator or by replacing the variables into the equation.

Answer:

1. -1/2 1/2 1/4

2. -3.5 -3.6 -3.7

3. -1/10 -1/11 -1/12

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

25cm

Step-by-step explanation:

one the possibility 36 - 11 =25 the answer is 25

Answer:

Step-by-step explanation:

7 x 5 = 35

35/2 = 17.5

[tex]17.5ft^{2}[/tex]

The area of the given triangle is 17.5 ft²

Area is defined as the total space taken up by a flat (2-D) surface or shape of an object.

Given a triangle with base=7ft and height =5ft

We know that area of a triangle = 1/2 × base × height

Therefore, the area of a triangle = 1/2 (7)(5) = 17.5 ft²

Hence, the area of the given triangle is 17.5 ft²

For more references on area, click;

https://brainly.com/question/27683633

#SPJ2

Answer:

40 because 40 percent of 100 is 40. You can just multiply the number by the percentage $100x40%

Answer:

x = -[tex]\frac{2}{3}[/tex]

y = 2

Step-by-step explanation:

The process of elimination is a method of solving a system of equations. One must first manipulate one of the equations such that one of the variables shared between the two equations has the inverse coefficient of the same variable in the other equation. Therefore, when one adds the equations, the variable cancels. One can solve for the variable using inverse operations, and then backsolve to find the value of the first variable.

When given the following system:

y = 3x + 4

y + 6x = 3x

Use inverse operations so that both equations are solve for one variable,

y = 3x + 4

y = -3x

Add the systems so that one of the variables (x) cancels, this process is called the process of elimination;

y = 3x + 4

y = -3x

_________

2y = 4

Inverse operations,

2y = 4

y = 2

Now backsolve, find the value of (x) by substituting the value of (y) into the equation:

y = -3x

2 = -3x

x = -[tex]\frac{2}{3}[/tex]

Answer: No solution.

Step-by-step explanation:

Answer:

the second store has the better deal.

Step-by-step explanation:

12 ÷ 2 = 6

7.5 × 6 = 45

20.2 < 45

Answer:

x = [tex]\frac{1}{2}[/tex] , x = 1

Step-by-step explanation:

Given

[tex]\frac{2x}{x+3}[/tex] + [tex]\frac{3}{x-3}[/tex] = [tex]\frac{8}{x^2-9}[/tex] ← denominator is a difference of squares

[tex]\frac{2x}{x+3}[/tex] + [tex]\frac{3}{x-3}[/tex] = [tex]\frac{8}{(x+3)(x-3)}[/tex]

Multiply through by (x + 3)(x - 3) to clear the fractions

2x(x - 3) + 3(x + 3) = 8 ← distribute left side and simplify

2x² - 6x + 3x + 9 = 8

2x² - 3x + 9 = 8 ( subtract 8 from both sides )

2x² - 3x + 1 = 0 ← in standard form

(2x - 1)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = [tex]\frac{1}{2}[/tex]

x - 1 = 0 ⇒ x = 1

Answer:

no thanks for your number

Step-by-step explanation:

Have a great day

A right angled triangle with its side length is given. The sides of the triangle are 12ft , 13ft and 5ft. And we need to find out the value of cot A .

Here :-

We know :-

[tex]\tt\implies cot \theta = base / perpendicular [/tex]

Substitute the respective values :-

[tex]\tt\implies cot \theta = base / perpendicular\\\\\tt\implies\boxed{\red{\tt cot A = 12/5 }}[/tex]

Hence the required answer is 12/5.

Answer:

landslide

Step-by-step explanation:

Answer:

I believe that the answer might be the second one

Volcanic Eruption