what is the answer to this question?​

Answer:

Vav=d/t

Explanation:

Because the question already gave d=90m and t=20s. Because the car is the thing that can not travel the same distances at the same times.So the equation is V[tex]\\_{av}[/tex]=[tex]\frac{d}{t} \\[/tex]

Answer:

17.42 g of glucose, C₆H₁₂O₆

Explanation:

From the question given above, the following data were obtained:

Mass of water = 300.7 g

Molar solution = 0.322 M

Mass of glucose =.?

Next, we shall convert 300.7 g to L. This can be obtained as follow:

1000 g = 1 L

Therefore,

300.7 g = 300.7 g × 1 L / 1000 g

300.7 g = 0.3007 L

Next, we shall determine the number of mole of glucose in the molar solution. This can be obtained as follow:

Volume of solution = 0.3007 L

Molar solution = 0.322 M

Mole of glucose =?

Molar solution = mole / Volume

0.322 = mole of glucose / 0.3007

Cross multiply

Mole of glucose = 0.322 × 0.3007

Mole of glucose = 0.0968 mole

Finally, we shall determine the mass of glucose, C₆H₁₂O₆, needed to produce prepare the solution. This can be obtained as follow:

Mole of C₆H₁₂O₆ = 0.0968 mole

Molar mass of C₆H₁₂O₆ = (12×6) + (1×12) + (16×6)

= 72 + 12 + 96

= 180 g/mol

Mass of C₆H₁₂O₆ =?

Mole = mass /Molar mass

0.0968 = Mass of C₆H₁₂O₆ / 180

Cross multiply

Mass of C₆H₁₂O₆ = 0.0968 × 180

Mass of C₆H₁₂O₆ = 17.42 g

Thus, 17.42 g of glucose, C₆H₁₂O₆ is needed to prepare the molar solution.

Answer:b

Explanation:

Right

Answer:B because all of the atoms exploded AND GRAVITY WAS CREATED AND forced molecules together (God caused it btw)

Explanation:The BIBLE

Answer:

D

Explanation:

The question is incomplete, the complete reaction equation is;

The concentration of a hydrogen peroxide solution can be determined by titration

with acidified potassium manganate(VII) solution. In this reaction the hydrogen

peroxide is oxidised to oxygen gas.

A 5.00 cm3 sample of the hydrogen peroxide solution was added to a volumetric flask

and made up to 250 cm3 of aqueous solution. A 25.0 cm3 sample of this diluted

solution was acidified and reacted completely with 24.35 cm3 of 0.0187 mol dm–3

potassium manganate(VII) solution.

Write an equation for the reaction between acidified potassium manganate(VII)

solution and hydrogen peroxide.

Use this equation and the results given to calculate a value for the concentration,

in mol dm–3, of the original hydrogen peroxide solution.

(If you have been unable to write an equation for this reaction you may assume that

3 mol of KMnO4 react with 7 mol of H2O2. This is not the correct reacting ratio.)

Answer:

2.275 M

Explanation:

The equation of the reaction is;

2 MnO4^-(aq) + 16 H^+(aq) + 5H2O2(aq) -------> 2Mn^+(aq) + 10H^+ (aq) + 8H2O(l)

Let;

CA= concentration of MnO4^- =  0.0187 mol dm–3

CB = concentration of H2O2 = ?

VA = volume of MnO4^- = 24.35 cm3

VB = volume of H2O2 = 25.0 cm3

NA = number of moles of  MnO4^- = 2

NB = number of moles of H2O2 = 5

From;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB = CAVANB/VBNA

CB = 0.0187 * 24.35 * 5/25.0 * 2

CB = 0.0455 M

Since  

C1V1 = C2V2

C1 = initial concentration of H2O2 solution = ?

V1 = initial volume of H2O2 solution =  5.0 cm3

C2 = final concentration of H2O2 solution= 0.0455 M

V2 = final volume of H2O2 solution = 250 cm3

C1 = C2V2/V1

C1 = 0.0455 * 250/5

C1 = 2.275 M

Answer:

[tex]T_{eq}=28.9\°C[/tex]

Explanation:

Hello!

In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

[tex]Q_{Cd}+Q_{W}=0[/tex]

Thus, we insert mass, specific heat and temperatures to obtain:

[tex]m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0[/tex]

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

[tex]T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}[/tex]

Now, we plug in to obtain:

[tex]T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C[/tex]

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

Best regards!

Answer:

Too high voltage which can't be held by the fuse

Answer:

Physical and chemical changes can occur almost everywhere, even in our bodies! Food must be broken down into a form that our cells can use. When we eat, our bodies physically break down food into small pieces. Our bodies also chemically break down those small pieces of food into tiny organic molecules.

Explanation:

Answer:

Fractional distillation is a method for separating liquids with different boiling points. For example, liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation. ... The boiling point of ethanol is 78°C and the boiling point of water is 100°C.

Answer:

2. sea level rises sorry if it's wrong

Answer: 2

Explanation: that’s the answer for the quiz

Answer:

Security

Explanation:

A wireless network consists of good connection with fast speed, convenience, and reliability. Security is a major problem with wireless connection as someone can get your information by joining the same connection as you.

Answer:

[tex]h=12.9cm[/tex]

Explanation:

Hello!

In this case, since we can consider the beaker until the 100-mL mark as a cylinder, we can use the following equation to relate its diameter, vertical distance or height and volume:

[tex]V=\pi h\frac{d^2}{4}[/tex]

Thus, since we know the diameter, volume (which is equivalent to 600 cm³) and π, we can plug in to obtain:

[tex]600cm^3=\pi *h*\frac{(77.0mm)^2}{4}[/tex]

It means it is necessary to take the mm to cm and solve for h:

[tex]h=\frac{600cm^3}{\pi*\frac{(7.70cm)^2}{4}} \\\\h=12.9cm[/tex]

Best regards!

The distance between each 100 mL mark is 2.15 cm.

The volume of a cylinder is obtained using the formula;

V = πr^2h

Now, we have the following information;

Volume of the cylinder = 600. mL or 600 cm^3

Diameter of the cylinder = 77 mm or 7.7 cm

Radius of the cylinder = 7.7/2 = 3.85 cm

Height of the cylinder  = h

Hence;

600 = 3.142 × ( 3.85 )^2 × h

h = 600/3.142 × ( 3.85 )^2

h = 12.88 cm

There are six 100 mL marks on the beaker, the distance between each 100 mL mark =  12.88 cm/6 = 2.15 cm

Learn more about volume: https://brainly.com/question/12748872

Answer:

[tex]PNCl_2[/tex]

Explanation:

Hello!

In this case, when determining empirical formulas by knowing the by-mass percent, we first must assume the percentages as masses so we can compute the moles of each element:

[tex]n_P=\frac{26.73g}{30.97g/mol}=0.863mol\\\\n_N=\frac{12.09g}{14.01g/mol}=0.863mol\\\\n_C_l=\frac{61.18g}{35.45g/mol}=1.726mol[/tex]

Now, for the determination of the subscript of each element in the empirical formula, we divide the moles by the fewest moles (P or N):

[tex]P=\frac{0.863mol}{0.863mol}=1\\\\N= \frac{0.863mol}{0.863mol}=1\\\\Cl=\frac{1.726mol}{0.863mol}2[/tex]

Thus, the empirical formula is:

[tex]PNCl_2[/tex]

Regards!

Answer:

[tex]Mg(s)+2H^+(aq)\rightarrow Mg^{2+}(aq)+H_2(g)[/tex]

Explanation:

Hello!

In this case, since the writing of a net ionic equation first implies writing the complete molecular equation:

[tex]Mg(s)+2HCl(aq) \rightarrow MgCl_2(aq)+H_2(g)[/tex]

We can see that HCl and MgCl2 are ionized because they are aqueous, thus we write:

[tex]Mg(s)+2H^+(aq)+2Cl^-(aq) \rightarrow Mg^{2+}(aq)+2Cl^-(aq)+H_2(g)[/tex]

In such a way, we can cancel out the chloride ions as they are the spectator ones to obtain the net ionic one:

[tex]Mg(s)+2H^+(aq)\rightarrow Mg^{2+}(aq)+H_2(g)[/tex]

Best regards!

Answer:

C. Oxygen

Explanation:

Oxygen has 8 electrons and doesn't react with fluorine noble gases

Answer:

C3H8 + 5O2 ‐‐‐‐‐‐‐‐> 4H2O + 3CO2

Answer:

valence electrons

The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements. Every element in the first column (group one) has one electron in its outer shell.

Answer:

i just took it the answers is C

Explanation:

Answer:

B. Cell Type

Explanation:

that is the answer i believe

Answer:

option b- cell type

Explanation:

almost absolutely positive

Answer:

The Earth’s greenhouse effect is a natural consequence of the chemical makeup of its atmosphere. If it

were not for the greenhouse effect, life as we know it could not exist on Earth: it would be too cold. Our

atmosphere is made mostly of nitrogen and oxygen, but also contains several other gases. These include

carbon dioxide, methane, nitrous oxide, water vapor and ozone, which are known as greenhouse gases.

Greenhouse gases are released naturally through geologic processes and the metabolic activity of living

things. However, there is an ongoing debate over human effects on Earth’s global climate. Human industrial activity on the planet has increased the quantities of greenhouse gases through agriculture, manufacturing, power generation, and engines used for transportation. Key questions include: Is the average temperature of Earth increasing? Does the presence of human beings contribute to global warming? If the temperature of Earth does become warmer, how will it affect us?

Explanation:

Answer: 1.695x10^24 atoms

Explanation: 0.938 moles CO2 = 0.938xavogadro number molecules CO2, so number of atoms = 3x0.938x6.02214076x10^23 = 1.695x10^24

Answer:

One possible answer could be lemon juice

Explanation:

We had to do a water test, and I was looking up what pH levels were. Then I learned about it in school, so I know a thing or two about it :)

Possible other answers include stomach acid and cola.

Hope this helps!!

Answer:

50%

Explanation:

Let assume that there are:

"a" moles of CH4 & "b" moles of C2H2

Then by applying the ideal gas equation:

PV = nRT

[tex]16.8 \times 10^3 \times V = (a+b)RT[/tex]

Make (a+b) the subject of the formula:

[tex](a+b) = \dfrac{16800 \ V }{RT} mol[/tex] --- (1)

Since 1 mole of CH₄ yields 1 mol of CO₂ & 1 mol of C₂H₂ yields 2 moles of CO₂

Then;

the total moles of CO₂ = (a +2b)

Now:

[tex]25.3 \times 10^3 \times V = (a+ 2b)RT[/tex]

[tex](a + 2b) = \dfrac{25200 \ V}{RT \ mol}[/tex]    ---- (2)

∴

By solving the above equations

[tex]a = \dfrac{8400 \ V}{RT} \\ \\ b = \dfrac{8400 \ V}{RT}[/tex]

Hence, the estimate of the percentage of methane in the original mixture is:

[tex]= 100 \times \dfrac{a}{(a+b)}[/tex]

[tex]= 100 \times \dfrac{8400\dfrac{ \ V}{RT} }{8400\dfrac{ \ V}{RT} + 8400\dfrac{ \ V}{RT}}[/tex]

= 50%

Answer: a

Explanation:

Answer:

plants

Explanation:

because it produces ( i am a third grade student and don't know if it is right or not)

Answer:

78.4g

Explanation:

Given parameters:

Mass of copper (II) chloride  = 90g

Mass of sodium nitrate  = 120g

Unknown:

Mass of sodium chloride that can be formed  = ?

Solution:

The balanced chemical reaction is:

            CuCl₂   +   2NaNO₃ →   Cu(NO₃)₂   +   2NaCl

Let us find the limiting reactant. This reactant will determine the extent of the reaction of the amount of product that will be formed.

First, convert the masses to number of moles;

      Number of moles  = [tex]\frac{mass}{molar mass}[/tex]

Molar mass of   CuCl₂  = 63.5 + 2(35.5) = 134.5g/mol

Molar mass of NaNO₃   = 23 + 14 + 3(16) = 85g/mol

  Number of moles of CuCl₂ = [tex]\frac{90}{134.5}[/tex]  = 0.67mole

  Number of moles of NaNO₃  = [tex]\frac{120}{85}[/tex]  = 1.41mole

From the balanced reaction equation:

      1 mole of CuCl₂   would react with 2 moles of NaNO₃

     0.67mole of CuCl₂   would require   0.67 x 2  = 1.34mole of NaNO₃

So, CuCl₂ is the limiting reactant

     1 mole of CuCl₂ will produce 2 mole of NaCl

    0.67mole of CuCl₂ will therefore yield 0.67 x 2 = 1.34mole of NaCl

Mass of NaCl = number of moles x molar mass

  Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl  = 58.5 x 1.34  = 78.4g