what is the average angular acceleration of a blu-ray disc as it plays an 6.0-h set of movies? (assume the disk is scanned starting at its inner radius moving outward. express your answer to two significant figures.)

Answer: this is true

Explanation:

if the object is moving and there is nothing stooping it, it will keep moving  

False. The most energetic region of the electromagnetic spectrum is NOT the microwave region. It is the Gamma rays.

What are Gamma rays?
The electromagnetic radiation with the shortest wavelength and maximum energy is known as a gamma ray. The wavelengths of gamma radiation are often less than a few tenths of an angstrom (1010 meter), yet the energy of gamma photons exceed tens of thousands of electron volts.

Gamma rays are created when radioactive atomic nuclei break apart and when certain subatomic particles decay. Pair annihilation, in which two photons are formed along with the disappearance of an electron and its antiparticle, a positron, also results in the production of gamma rays. Additionally, they can be produced when some unstable subatomic particles, such the neutral pion, decay.

Therefore, The most energetic region of the electromagnetic spectrum are gamma rays.

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The wavefront B is travelling at the speed(5000m/s) closest to that of a sound wave(6000m/s) travelling through solid.

The velocity of the sound waves in solids is nearly 6000 meters per second.

Let us check the velocity for all the three wave fronts,,

Wavefront A,

We know,

speed = distance/time taken

Distance travelled by the wavefront A is 10m,

Time taken by the wavefront A to travel the distance is 0.01 seconds,

Putting all the values,

Speed = 10/0.01

Speed = 1000m/s.

Speed of wavefront A is 1000m/s.

Wavefront B,

Again we know,

speed = distance/time taken

Distance travelled by the wavefront Bis 50m,

Time taken by the wavefront B to travel the distance is 0.01 seconds,

Putting all the values,

Speed = 50/0.01

Speed = 5000m/s.

Speed of wavefront B is 5000m/s.

Wavefront C,

We know,

speed = distance/time taken

Distance travelled by the wavefront C is 1000m,

Time taken by the wavefront C to travel the distance is 100 seconds,

Putting all the values,

Speed = 1000/100

Speed = 10m/s.

Speed of wavefront C is 10m/s.

Wavefront D,

Again using the formula,

speed = distance/time taken

Distance travelled by the wavefront is 2000m,

Time taken by the wavefront to travel the distance is 2000 seconds,

Putting all the values,

Speed = 2000/2000

Speed = 1m/s.

Speed of wavefront D is 1m/s.

As we can see, The speed of wavefront B is closest to the speed of sound waves in solids.

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Mass of air that escapes the tank is M =2.8075 kg and  the amount of heat transferred to the tank is Q = 1008.942 kj

In physics, mass is a numerical representation of inertia, which is a basic characteristic of all matter. The resistance a body of matter offers to a change in its speed or location as a result of the application of a force is what it is in essence. The change a force applies produces a change that is smaller the more mass a body has. The kilogramme, which is defined in terms of Planck's constant as equal to 6.62607015 1034 joule second, is the unit of mass in the International System of Units (SI). One kilogramme times one square metre per second squared is equivalent to one joule. Accurate measurements of Planck's constant are used to determine the kilogramme since the second and the metre are already defined in terms of other physical constants.When a body breaks up into fragments, the mass also breaks up into bits, thus the total mass of all the pieces equals the original mass.

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The frequency of light  is 3.88x10^23Hz

E = 1.55 x J/ mol

E = hv

v = (1.55 x /1mol  x 1mol/6.023 x )/6.626 x 10^34

velocity = 3.88x10^23 s-1

since 1 Hz = 1/ s = 1

velocity =3.88x10^23 Hz

The portion of the electromagnetic spectrum contains the electromagnetic radiation that the human eye perceives as light or visible light. Visible light typically possesses wavelengths between 400 and 700 nanometers (nm) or frequencies between 750 and 420 terahertz, which are halfway between infrared and ultraviolet (with longer wavelengths) (with shorter wavelengths).

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Sample question: What is the frequency of light when the energy for a mole of photons is 1. 55 × 1013 j?.

A full circuit is required for the flow of electrical current, and all electrical energy transmissions need the formation of a circuit with two wires—one going to the recipient and the other going back to the sender.

The construction of a circuit with two wires—one going to the recipient and the other back to the sender—is necessary for all electrical energy transmissions in order for current to flow. Due to the fact that all wireless signals are essentially delivered as electromagnetic signals rather than electrical signals, electromagnetic interference, often known as EMI, is a common problem in wireless communications.

This suggests that any interference with an electromagnetic signal (wave) may cause it to be amplified, destroyed, or lost (assuming constructive interference).

The interference brought on by electromagnetic disturbance is known as electromagnetic interference. Radio frequency interference is another name for it. We refer to interference that occurs in the radio frequency spectrum as radio frequency interference.

These days, wireless communication is expanding at an unprecedented rate. Over a large concentration, a small spectrum is available. Because of this, there is a greater likelihood of mutual interference. The performance of the device and the channel can both be impacted by a slight electromagnetic disturbance. It is crucial to keep interference at a minimal for better wireless performance.

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Answer:486.1 J

Explanation:

Visible light , The process by which plants convert carbon dioxide, water, and sunshine into oxygen and sugar-based energy is known as photosynthesis.

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13.13 m/s is the velocity of the truck was when a truck of mass 3170 moving in the opposite direction collides with the car and the 2 vehicles stop immediately without sliding.

Momentum of car= 1850(22.5)=41625 kg m/s

Momentum of car = momentum of truck

Let the speed of truck = v m/s

Momentum of truck= v(3170)=3170 v  kgm/s

3170v = 41625

v = 13.13 m/s

Speed of truck = 13.13 m/s

The pace at which a moving object changes position as seen from a certain point of view and as measured by a particular time standard is known as its velocity.

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Answer:

it's 2250meters and 2.25km

Explanation:

speed= distance÷time

75=distance÷30

75×30=distance

2250 m= distance

To convert meters into Kilometres we divide by 1000 so,

2250÷1000

2.25 Km

The constant acceleration of the plane is 7.33 m/[tex]s^{2}[/tex].

Use this formula of acceleration, [tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as

[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as,

a =  [tex]v^{2}[/tex] - [tex]u^{2}[/tex]   / 2s

v = velocity

s = distance

a = acceleration

Put the values in this formula, a =  [tex]v^{2}[/tex] = [tex]u^{2}[/tex]  / 2s

a = (240× 240) - (200 × 200)/ 2 × 1200

a = 7.33 m/[tex]s^{2}[/tex]

Hence, the constant acceleration of the plane is 7.33 m/[tex]s^{2}[/tex].

Acceleration is the rate of change of velocity per unit time. It is vector quantity and its S.I. unit is m/[tex]s^{2}[/tex].

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0.145 Newton is the required steady force of each rocket if the satellite is to reach 32 rpm in 5.0 min , starting from rest

mass of satellite ( M ) = 3500 kg

radius of satellite ( r )  = 4.4 m

mass added by each rocket ( m ) = 220 kg

Angular speed of satellite = 32 rpm

Time = 5 mins  

moment of inertia

[tex]I=1/2Mr^2+4mr^2[/tex]

M = 3500 kg  m = 220 kg,  r =4.4 m

I=33880+17036

Insert values into equation ( 1 )

I =20416 kg-m^2

angular acceleration

∝ = ω / t

= ( 2π×32 ) /  3600×5

= 0.0112 rad/s²

steady force required by each rocket

Τ = I × ∝     ( 1 )

T = 4rF

Equation ( 1 ) becomes

4rF = I × ∝

Force = I×∝ / 4r

= ( 228×0.0112 ) / 4×4.4

=2.56/17.6

= 0.145 N .

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1. The acceleration of the cyclist is 0.42 m/s²

2. The total distance travelled by the cyclist is 2437.5 m

1. How to determine the acceleration    

We can obtain the acceleration of theration of the cyclist as follow:

a = (v – u) / t

a = (25 – 12.5) / 30

a = 12.5 / 30

a = 0.42 m/s²

Thus, the acceleration is 0.42 m/s²

2. How to determine the total distance

We'll begin by obtaining the distance travelled in the first 30 s. This can be obtained as follow:

s = (u + v)t / 2

s = [(12.5 + 25) × 30] / 2

s = [37.5 × 30] / 2

s = 1125 / 2

s = 562.5 m

Next, we shall determine the distance in the next 60 second.

s = vt

s = 25 × 60

s = 1500 m

Next, we shall determine the distance in the last 15 seconds.

s = (u + v)t / 2

s = [(25 + 0) × 15] / 2

s = [25 × 30] / 2

s = 750 / 2

s = 375 m

Finally, we shall determine the total distance travelled.

Total distance = 562.5 + 1500 + 375

Total distance = 2437.5 m

Thus, the total distance travelled is 2437.5 m

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2 and 23/75 as a percentage is 2.30666666666. Hope this helps! :)

In the case of a paramecium moving at a constant speed, there is no net force acting on it.

The paramecium's cilia exerts a force on water that is equal to the force that the water exerts on the paramecium's cilia, according to Newton's third law.

The strength of the viscous force the water is exerting on the paramecium will be equal to the strength of the force the paramecium's cilia are exerting on the water.

How does Paramecium use cilia?

Cilia, or tiny strands like hair, cover the whole surface of parasites like cilia, which beat rhythmically to move them and guide bacteria and other food particles into their mouths.

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The effective resistance of two equal resistors connected in series is twice that of a single resistor, reducing the amount of current flowing in the circuit.

The effective resistance of two resistors connected in series is the sum of their individual resistances. Given two resistors with resistance values R1 and R2, the effective resistance, Rx, is given by:

Rₓ = R₁ + R₂        

If the resistance values of these resistors are equal, say R, then equation 1 becomes:

Rₓ = R + R

Rₓ = 2R

That is, their effective resistance is twice as strong as their individual resistances. In other words, when two equal resistors are connected in series, their effective resistance is twice the resistance of each resistor.

Ohm's law states that voltage (V) is the product of current (I) and resistance (R) i.e.

V = IR

I = V/R

We can conclude that as resistance decreases, current increases and vice versa.

As a result, connecting the two equal resistors described above in series reduces the amount of current flowing compared to having just a single resistor.

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Answer:  

Explanation:

at first the rock is at rest so initial velocity is zero
after accelerating it reaches a final velocity
we are supposed to find that final velocity


[tex]v^{2} = u^{2} +2ax[/tex]
v= final velocity
u= initial velocity
x= distance
a= acceleration

[tex]v^{2} = 0^{2} + 2(9.8)(14.4)[/tex]
[tex]v^{2} = 282.24[/tex]
[tex]v= \sqrt{282.24}[/tex]
[tex]v= 16.8 m/s[/tex]

A swimmer needs to cross a river as quickly as possible. The swimmer’s speed in still water is 1.35 m/s.

(a) If the river’s current speed is 0.60 m/s and the river is 106.68 m wide, it will take the time swimmer to cross the river is (t) = 72.57 S, if he swims so that his body is angled slightly upstream while crossing, and he ends up on the far bank directly across from where he started.

(b) If he points his body directly across the river and is therefore carried downstream, it will take time to get across the river is (t)=72.57 S, and the distance downstream from his starting point will he end up is (S) = 43.542m.

Velocity means that the covered distance in a given time. In other words mathematically distance divided by time called velocity. It can be measured in m/s and cm/s.

(a)To calculate the time for the first case we are using the formula, S=vt.

The swimmer’s speed in still water is 1.35 m/s.=v₁=1.35j m/s.

the river’s current speed is 0.60 m/s.=v₂=0.60i m/s.

Now, let us apply the rule of relative velocity:

v=v₁+v₂=1.35j+0.60i

Or, |v|=√(1.35)²+(0.60)²

Or, |v|=1.47 m/s

Now we know the velocity of the water, v=1.47 m/s.

The wide of the river, S=106.68 m

Now we have to calculate the time to travel of the swimmer= t s

Now we put the values in above equation,

S=vt

Or, t=S/v

Or, t= 106.68/1.47

Or, t=72.57 s.

From the above calculation we can say that, If the river’s current speed is 0.60 m/s and the river is 106.68 m wide, it will take the time swimmer to cross the river is (t)=72.57 S

(b) If he points his body directly across the river and is therefore carried downstream, The time taken by the swimmer is the same as the first case.

So the time would be (t)=72.57 S.

The distance downstream from his starting point will he end up,

S = vt

Or, S= 0.6*72.57

Or, S=43.542

So according to the solution, If he points his body directly across the river and is therefore carried downstream, it will take to get across the river is (t)=72.57 S, and the distance downstream from his starting point will he end up is (S)=43.542m.

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Projectile motion is exemplified by actions like throwing a ball straight up,  a ball and giving it speed at an angle to the horizontal, or simply dropping something and letting it fall freely. Gravity is the only force acting on the object during projectile velocity.

Horizontal distance traveled by the ball is 29.86 m

Launch angle x  = 44 °

time period of flight = 2.5s

Time period of Projectile T = [tex]\frac{2u sin x}{g}[/tex]  , g=acceleration due to gravity

2.5 = [tex]\frac{2 X u sin 44}{9.2}[/tex]

Where u=initial velocity = 16.66 m/s

Range of Projectile is given by

R = [tex]\frac{u^{2} sin 2x }{g}[/tex]

R= [tex]\frac{16.66^{2} sin 2x44}{9.2}[/tex]

R =  29.86 m

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Answer:

Vx = 53 m / 4 sec = 13.25 m/s       horizontal speed

Vy = 2 sec* 9.80 m/sec^2 = 19.6 m/s      vertical speed

V = (13.25^2 + 19.6^2)^1/2 = 23.7 m/s

Check:

Range = V^2 sin 2θ / g

tan θ = 19.6 / 13.25 = 1.48     θ = 55.9 deg

R = 23.7^2 sin 112 deg / 9.8 = 53.1 m

Answer:

150J (joules)

Explanation:

25% efficiency of 1000J = 250J

40% efficiency of 1000J= 400J

400-250=150

With the use of range formula, also, in multiple of 180 degree, 59 and 239 degrees are the angles of projection.

A projectile in kinematic under physics can be defined as any object that is projected or thrown to take a trajectory path.

Given that a tennis player makes a return at a speed of 15 m/s and at height of 3m to land in the court at a horizontal distance of 12 m from her.

Let us assume that the ball fall at height 3m. U = 0. Let us find the time

h = ut + 1/2gt²

3 = 0 + 1/2 × 9.8 × t²

3 = 4.9t²

t² = 3/4.9

t² = 0.612

t = √0.612

t = 0.782 s

Total time T = 2t

T = 2 × 0.782

T = 1.564 s

The possible angles of projection of the ball can be calculated by using the range formula

R = UcosФT

12 = 15cosФ × 1.564

12 = 23.46cosФ

cosФ = 12 / 23.46

cosФ = 0.512

Ф = [tex]Cos^{-1}[/tex] (0.512)

Ф =  59. 2 degree

Ф = 59°

Therefore,  the possible angles of projection of the ball are 59° and 239°

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The transfer of momentum increases when the velocity of the marble increases and vice versa.

The transfer of momentum increases when the mass (number of marbles) increases and vice versa.

The momentum of a single marble can be calculated from the product of its mass and velocity.

If two marbles together are moving at the same speed as a single marble, the two marbles will have greater momentum because of their greater mass.

Momentum can be shown as a vector because the direction of the momentum of a body is specified.

The momentum of a body is the product of the mass and the velocity of the body.

Mathematically;

Since the velocity of an object is a vector, the momentum of a body is also a vector.

The momentum of a body is directly proportional to its mass and velocity.

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The submarine is 288.04 meters below the surface of the water.

As we can see,

The submarine is making an angle of 40.5° with the water surface and moving down till a displacement L of 397 meters.

The displacement L moved by the submarine will have two components because displacement is a vector quantity.

One along water surface Lcos(40.5°) and one along the line perpendicular to water surface Lsin(40.5°).

The depth D of the submarine below the water surface is along the line perpendicular to the water surface.

Here,

D = Lsin(40.5°)

Value of cos 40.5°is 0.76.

So,

D = 397×0.76

D = 288.04 meters.

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The total time taken by the feather to fall to the surface of moon will be 1.29 seconds.

Given is a feather dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s².

The second equation of motion is -

S = ut + 1/2 at²

We can write -

[S] = 1.4 m

[a] = 1.67 m/s²

[u] = 0 m/s

Using the second equation of motion -

S = ut + 1/2 at²

S = 1/2 at²

1.4 = 1/2 x 1.67 x t²

1.4 = 0.835 x t²

t = 1.29 seconds

Therefore, the total time taken by the feather to fall to the surface of moon will be 1.29 seconds.

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The angular difference between true north and magnetic north is called declination.

What is declination?

Declination is the said to be the angle between magnetic north and geographic north in the horizontal plane that changes with time and geographic location. The true north or geographic north is a fixed point on the globe that points towards the north pole directly while the magnetic north unlike the true north changes over time, and it is the direction a compact needle points to as it aligns with the earth's magnetic field.

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The solution to this ques is available in the image.

Given,

Force= 1N

Mass= 0.11kg

Time= 5sec

Force= mass X accelaration

Accelaration= velocity/ time

Speed=distance/ time

Hence, the speed is 45 m/s and the distance is 225 m.

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Answer:

So, at moon g’=1.62 m/s^2

Therefore, mg’=99N (as given , where m is the mass )

so, m=99/1.62 =61.11 kg

hence, weight on earth will be mg( where g is the acceleration due to gravity at earth, 9.8m/s^2)

61.11*9.8=598.878 N will be the weight on earth

Explanation:

hope it helps

120 centimeters per second, is the wave speed or wave velocity.

Wave velocity is the amount of distance a wave travels in one unit of time. The rate at which a particle disturbance like a crest or trough or compression or rarefaction spreads in a medium is known as the particle's propagation speed.

Given,

Amplitude (A) = 2cm,

Frequency (f) = 12hz,

Time period [tex]T=\frac{1}{f} =\frac{1}{12} s[/tex]

The horizontal distance between the closest peak or trough, respectively, is referred to as the wavelength. A crest's distance from the closest tough was specified. The distance between a crest and the closest crest is therefore two times that distance.

This is the wave length :

λ=(2)(5)

=10cm

The wave velocity or wave speed is given by:

v = λf

v=(10)(12)

=120 cm/s

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