The average rate of change is 12 the interval from x=3 to x=5.
How to find the average rate of change of something?Let the thing that is changing be y and the thing with which the rate is being compared is x, then we have the average rate of change of y as x changes as:
[tex]\text{Average rate} = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]
where when
[tex]x = x_1, y = y_1\\and \\x = x_2, y = y_2[/tex]
Given:
Interval; x = 3 to x = 5
We can represent these by
[tex]x_1 = 3\\x_2 = 5[/tex]
The corresponding y values are as follows
When x = 3, y = 8
When x = 5, y = 32
This will also be represented
[tex]y_1 = 8\\y_2 = 32[/tex]
The average rate of change is then calculated as follows
[tex]\text{Average rate} = \dfrac{y_2 - y_1}{x_2 - x_1}\\\\\\m = \dfrac{32 -8}{5-3}\\\\m = \dfrac{24}{2}\\\\m = 12[/tex]
Hence, the average rate of change is 12.
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what is the answer to −1.4+(−1.2)
Answer:
-2.6
Step-by-step explanation:
-1.4+(-1.2)
-1.4-1.2=-2.6
Hope this helps!
If not, I am sorry.
Please Help I Don't Understand
Answer:
90
Step-by-step explanation:
The angles are on either side of the line are in proportion.
Hence,
⇒ [tex]\frac{10}{8} = \frac{x}{72}[/tex]
⇒ [tex]\frac{5}{4} = \frac{x}{72}[/tex]
⇒ [tex]x = \frac{5 \times 72}{4}[/tex]
⇒ [tex]x = 5 \times 18[/tex]
⇒ x = 90
Let's see
[tex]\\ \rm\Rrightarrow \dfrac{8}{10}=\dfrac{72}{x}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{4}{5}=\dfrac{72}{x}[/tex]
[tex]\\ \rm\Rrightarrow 4x=360[/tex]
[tex]\\ \rm\Rrightarrow x=90[/tex]
I will give BRAINLIEST
Half of the road the boy walked at a speed of 6 m / min, the other half - at a speed of 4 m / min. Calculate the average walking speed of a boy
Answer:
5
Step-by-step explanation:
6 + 4 is 10
Half of 10 is 5
Simplify the following expression:
(x+3)-[(x+2)(x³ - 1)]
O A. - x4 - 2x - x+2
OB. -x-2x³ +2x+5
OC. --2x³ +1
OD. -x-2x²+2x+5
Simplification form of the provided expression is -x⁴-2x³+2x+5 option (B) is correct.
What is an expression?It is defined as the combination of constants and variables with mathematical operators.
The options are:
A) -x⁴ - 2x - x + 2
B) -x⁴ - 2x³ + 2x + 5
C) -2x³ + 1
D) -x - 2x² + 2x + 5
We have an expression:
= (x + 3) - [(x + 2)(x³ - 1)]
[tex]\rm =x+3-\left(x+2\right)\left(x^3-1\right)[/tex]
[tex]\rm =x+3-x^4+x-2x^3+2[/tex]
[tex]\rm =-x^4-2x^3+2x+3+2[/tex]
[tex]\rm =-x^4-2x^3+2x+5[/tex]
Thus, simplification form of the provided expression is -x⁴-2x³+2x+5 option (B) is correct.
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ASAP ASAP ASAP ASAP!!!!! Pls help me
I didn’t study r.I.p
Answer:
1) Scalene
2) Equilateral
3) Isosceles
4) Right
5)Obtuse
Step-by-step explanation:
The requried correct match for the given triangle and its sides and angle has been shown.
Following the given characteristic the match of the the properties of triangle is given as:
Type of Triangle: Characteristics
Scalene: all side lengths and angles are different sizes
Equilateral: all side lengths are equal and all angles are 60°
Isosceles: two sides and their base angles are equal
Right: one angle is 90°
Obtuse: one angle is greater than 90°
Thus, the required match shown above is the correct match.
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(b) Work out the value of (√2+√8)^2
[tex]~~~\left(\sqrt 2 + \sqrt 8 \right)^2\\\\=\left(\sqrt 2 \right)^2 + \left(\sqrt 8 \right)^2 +2 \sqrt 2 \sqrt 8\\\\=2+8+2\sqrt{2 \cdot 8}\\\\=10+2\sqrt{16}\\\\=10+2(4)\\\\=10+8\\\\=18[/tex]
How would I calculate the horizontal distance of a parabola?
What exponential expression is equal to 2^-5 . 2^8
[tex]~~2^{-5} \cdot 2^8\\\\=2^{-5+8}~~~~~~~~~~~~~~~~~~~~~;[a^m \cdot a^n = a^{m+n}]\\\\=2^3[/tex]
A pumpkin farmer collects 20 pumpkins randomly sampled from his pumpkin patch and weighs them. the mean
weight of the pumpkins is 26 lb. he wonders whether the weight of his pumpkins follows a normal distribution.
which answers are clear signs that the pumpkin weights are not normally distributed?
select all that apply.
the median pumpkin weight is 26 lb.
the median pumpkin weight is 35 lb.
75% of pumpkins in the sample have weights higher than the me
mean.
the median pumpkin weight is 10 lb.
about 68% of pumpkin weights are within one standard deviation of the mean.
The true statement about the pumpkin include:
the median pumpkin weight is 10 lbthe median pumpkin weight is 35 lb75% of pumpkins in the sample have weights higher than the mean.What is a median?The median is a value or quantity lying at the midpoint of a frequency distribution of observed values or quantities.
Here, the median pumpkin weight is 35 lb and 75% of pumpkins in the sample have weights higher than the mean.
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let x = -5/6 and y 4/3= . select all the expressions that have a positive value. select all that apply: a. x * y b. y/x c. x/y d. x + y e. x - y f. y - x
Step-by-step explanation:
A, ×* y = -10 / 9
B, y / x = -8 / 5
C, x / y = -5 / 8
D, x+ y = 1 / 2
E, x- y = - 13 / 6
F, y- x = 13 / 6
Anyone mind helping me solve this inequality? Step by step
By decomposing the figure in simpler shapes, we will see that the total area is:
a = 180 cm²
How to find the area of the composite figure?
Remember that the area of a rectangle of width W and length L is:
A = L*W
And the area of a triangle with base B and height H is:
A = B*H/2.
Then, the upper part can be seen as a rectangle of length of 6cm and width of 6 cm, with two triangles on the sides, such that each triangle has a base of 3cm and a height of 6cm.
So the area of that part is:
A = 6cm*6cm + 2*(3cm*6cm/2) = 54cm²
Now, the bottom triangle has a base of 12 cm, and a height of:
15cm - 6cm = 9cm
Then its area is:
A' = 12cm*9cm/2 = 54cm²
This means that the total area of the figure is:
total area = 54cm² + 54cm² = 108cm²
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4 out of every 7 students in a school eat a packed lunch. The rest eat a school meal.
Which of the following statements is correct?
47% of students eat a school meal
The ratio of school meal to packed lunch is 7 : 4
The ratio of packed lunch to school meal is 4 : 3
56% of students eat a packed lunch
What is the correct expanded form and value!!
Pls hurry asap
Answer:
The answer you selected is correct. Because, [tex]\frac{4}{5} ^{3\\}[/tex]is 4/5, 3 times.
Attached is more explanatory information
Step-by-step explanation:
Answer:
B. [tex]\frac{4}{5}\cdot\frac{4}{5} \cdot\frac{4}{5}=\frac{64}{125}[/tex]
Step-by-step explanation:
(4/5) is raised to a numerical power of 3.
This is NOT [tex]\frac{4}{5}(3)[/tex] and NOT [tex]\frac{4}{5}+\frac{4}{5}+\frac{4}{5}[/tex].Instead, (4/5) is being multiplied by itself 3 times.
This is correctly shown by: [tex]\frac{4}{5}\cdot\frac{4}{5} \cdot\frac{4}{5}[/tex]This can be solved by multiplying the numerators and denominators, which also looks like this: [tex]4^3=64[/tex] and [tex]5^3=125[/tex].The exact form is: [tex]\frac{64}{125}[/tex].The complete expansion is written as: [tex]\frac{4}{5}\cdot\frac{4}{5} \cdot\frac{4}{5}=\frac{64}{125}[/tex]
You have the correct option selected.
Determine the equation of the line with slope 3 that passes through the point M(1, 2).
3x + y = 1
3x - y = -1
3x - y = 1
Ox-3y=-1
Answer:
3x - y = 1
Explanation:
Equation formula:
y - y1 = m(x - x1)
where m is slope, (x1, y1) are coordinates
Find Equation:
⇒ y - 2 = 3(x - 1)
⇒ y = 3x - 3 + 2
⇒ -3x + y = -1
⇒ 3x - y = 1
Equation of line in point slope form
y-y1=m(x-x1)y-2=3(x-1)y-2=3x-3y=3x-13x-y=1What is the median of this data set? A. 56 B. 75 C. 45 D. 61
ASAP 55POINT
Answer:
ok soo
Step-by-step explanation:
45, 56, 61, 75
middle of 56 and 61 add them so 117 then half 117 which is 58.5-
what’s the area of the base
Answer:
16 square units
Step-by-step explanation:
16 square units
HELP!!! 100 PNTS+BRANLIEST TO QUICK AND CORRECT ANSWER!!!!!!!!
In the small town of Middleton, there are only two restaurants that serve pizza- a small family owned Italian restaurant and a new franchise pizza restaurant. In a recent review of the franchise, a food critic reported that the pizza was delicious as promised. The only negative review that the franchise received from the critic was in reference to the inaccurate delivery time quoted during the online order process. In response to the article, the franchise owner used a program to analyze the online pizza orders that took place during the week before the review. He chose to track the orders at 6pm each day. He recorded his results in the frequency table below. Use the frequency table to create a box and whisker plot of the On Time data values. In your final answer, include all calculations necessary to create the box and whisker plot. Use the frequency table to create a box and whisker plot of the Late data values. In your final answer, include all calculations necessary to create the box and whisker plot.
Answer:
Yes
Step-by-step explanation:
1. Yes , the data franchise owner is collecting, will be helpful in order to counter the criticism from the critic. As he has a record for every delivery they are making on daily basis.
2. The scenario is that for every fifth customer , the owner cross the four lines he makes. Thus a pack of five and easy to remember. As the data on regular week days is less, As can do the same for the third customer. Crossing the 2 lines for 3rd customer.
3. With this provision of crossing the third customer, the owner can have a better check on the late delivery. As it will bring in his notice earlier as compared to fifth crossing.
4. With the data as provided in the table, we can come to the conclusion that on weekends , i.e. both on time delivery and late deliveries are high in numbers. It must be because of high demand on that days. So owner must make some provision like hiring some more delivery boys for weekend in order to reduce the late deliveries.
What is the value of y when the value of x is 1?
Answer: y = 60
the value of y will be 60 when the value of x is 1.
Solution set = (1 , 60)
hope that helps...
Sean operates a lawn-cutting business. He charges $15 for a single lawn and $25 for a front and back lawn. Sean made $475 from 25 customers.
Write a system of equations
The system of equations that models the given situation is given as follows:
x + y = 25.15x + 25y = 475.What is a system of equations?A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are given as follows:
Variable x: Number of single lawns cut.Variable y: Number of front and back lawns cut.He had 25 customers, hence:
x + y = 25.
He charges $15 for a single lawn and $25 for a front and back lawn, and made a total of $475, hence:
15x + 25y = 475
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find the total area of the composite figure
719ft
office area=12(20)=240ft
storage=(20-12)(40-(12+15)=8(13)=104ft
home theater=25(15)=375ft
total area= 240+104+375=719ft
please help with this thank you!
Answer:
A. Half of
B. Twice
C. greater than
Step-by-step explanation:
The median of the box plot is the middle line of the box, so for set a it is approximately ten and for set b it is approximately 20. 10 is half of 20 and 20 is twice as much as 10.
Hope this helps
A container holds 50 electronic components, of which 10 are defective. if 6 components are drawn at random from the container, the probability that at least 4 are not defective is . if 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .
Answer:
See below for answers and explanations
Step-by-step explanation:
Problem 1
We know that there's a probability of [tex]p=\frac{40}{50}=\frac{4}{5}=0.8[/tex] of choosing an electronic component that is not defective and a probability of [tex]q=\frac{10}{50}=\frac{1}{5}=0.2[/tex] of choosing an electronic component that is defective:
[tex]\displaystyle P(X\geq4)=P(X=4)+P(X=5)+P(X=6)\\\\P(X\geq4)=\binom{6}{4}(0.8)^4(1-0.8)^{6-4}+\binom{6}{5}(0.8)^5(1-0.8)^{6-5}+\binom{6}{6}(0.8)^6(1-0.8)^{6-6}\\\\P(X\geq4)=\frac{6!}{4!(6-4)!}(0.8)^4(0.2)^2+\frac{6!}{5!(6-5)!}(0.8)^5(0.2)^1+\frac{6!}{6!(6-6)!}(0.8)^6(0.2)^0\\ \\P(X\geq4)=0.90112[/tex]
So, if 6 components are drawn at random from the container, the probability that at least 4 are not defective is 0.90112
Problem 2
[tex]\displaystyle P(X=3)=\binom{8}{3}(0.2)^3(1-0.2)^{8-3}\\\\P(X=3)=\frac{8!}{3!(8-3)!}(0.2)^3(0.8)^5\\ \\P(X=3)\approx0.1468[/tex]
So, if 8 components are drawn at random from the container, the probability that exactly 3 are defective is 0.1468
The probability of exactly 3 of the containers being defective is given as 0.1468
What is probability?Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.
here, we have,
to solve for the probability
We have to set p as the probability of container being non- defective
We have p as the probability of container being defective 50 - 10 = 40
p = 40/50
= 0.8
q = 10/50
= 0.2
P(3) = 8c3 * 0.2² * 0.8⁵
= 0.1468
Hence the probability that the container has exactly 3 defective containers is 0.1468
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At what distance above the ground was the shot fired? Show your work.
Answer:
51.63 ft
Step-by-step explanation:
Tangent 25 = opposite / adjacent
tan 25 = height/100
Height = 100 tan 25 = 46.63 feet ABOVE the head of the victim
victim head height = 5 ft
46.63 + 5 = 51.63 ft
match each pair of rational numbers with their sum
The matched pair of rational numbers are as follows;
[tex]\frac{-2}{a^{2}b }+\frac{2}{ab^{2} } = \frac{2(a-b)}{a^{2}b^{2} }[/tex]
[tex]\frac{1}{2ab} +\frac{-1}{4a^{2} b^{2} } =\frac{2ab-1}{4a^{2}b^{2} }[/tex]
[tex]\frac{2}{a^{2} b^{3} } +\frac{-2}{ab} =\frac{2(1-ab^{2} )}{a^{2} b^{3} }[/tex]
[tex]\frac{1}{ab^{3} } +\frac{-1}{a^{2} b} =\frac{a-b^{2} }{a^{2}b^{3} }[/tex]
How to simplify rational numbers?The matched pair of rational numbers are as follows:
[tex]\frac{-2}{a^{2}b }+\frac{2}{ab^{2} } = \frac{-2b+2a}{a^{2} b^{2} } = \frac{2(a-b)}{a^{2}b^{2} }[/tex]
[tex]\frac{1}{2ab} +\frac{-1}{4a^{2} b^{2} } =\frac{2ab-1}{4a^{2}b^{2} }[/tex]
[tex]\frac{2}{a^{2} b^{3} } +\frac{-2}{ab} =\frac{2 - 2ab^{2} }{a^{2}b^{3} } =\frac{2(1-ab^{2} )}{a^{2} b^{3} }[/tex]
[tex]\frac{1}{ab^{3} } +\frac{-1}{a^{2} b} =\frac{a-b^{2} }{a^{2}b^{3} }[/tex]
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Find the volume of the cylinders. (Use π=3.14)
A. Height= 9ft ; radius= 3ft
B. Radius=13yd; height=8yd
Question 1
h= 9 ftr= 3 ftQuestion 2
h= 8 ydr= 13 yd Note that:h= heightr= radius To find:The volume of the given cylinders.
Solution:[tex]\huge\boxed{Formula: V=\pi{r}^{2}h}[/tex]
[tex]\huge\boxed{\red \pi \red = \red 3 \red . \red 1 \red 4}[/tex]
Let's solve!
Substitute the values according to the formula.
[tex]V=3.14×{3}^{2}×9[/tex]
[tex]\large\boxed{V= 254.34 \: {ft}^{3}}[/tex]
Let's work on question 2
Substitute the values according to the formula.
[tex]V=3.14×{13}^{2}×8[/tex]
[tex]\large\boxed{V= 4245.28 \: {yd}^{3}}[/tex]
Find the length of AC
Find the length of DC
Step-by-step explanation:
Here is the solution...hope it helps:)
What is the volume of this sphere?
Use ≈ 3.14 and round your answer to the nearest
hundredth.
10 m
cubic meters
Step-by-step explanation:
volume of a sphere is given by 4/3 × pi × r³
hence, the answer is 523.33
comment if you have any doubts
Work Shown:
[tex]V = (4/3)*\pi*r^3\\\\V \approx (4/3)*3.14*5^3\\\\V \approx 523.33\\\\[/tex]
For the polynomial function, find the requested value: f (x) = 10x2 − 4x − 5; f (−2)
The value of f(-2) in the polynomial is 43
How to evaluate the polynomial?The polynomial function is given as:
f(x) = 10x^2 − 4x − 5;
To calculate f (−2), we substitute -2 for x in f(x).
So, we have:
f(-2) = 10(-2)^2 - 4(-2) - 5
Evaluate the expression
f(-2) = 43
Hence, the value of f(-2) in the polynomial is 43
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3
Select the correct answer from each drop-down menu.
A function is a relation where each input value is assigned to
The
of a function is the set of all input valu
The
of a function is the set of all output val
To write the equation y= ax + b in function notation, substitut at least
exactly
less than
one output value.
es, for which the function is defined.
ues, for which the function is defined.
or y.
Nex
The range of a function is the set of all output values.
How to illustrate the function?A function is a relation where each input value is assigned to only one output value.
The domain of a function is the set of all input values, or x-values, for which the function is defined.
The range of a function is the set of all output values, or y-values, for which the function is defined.
To write the equation y = ax + b in function notation, substitute f(x) for y.
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Howwwww????????
Howwwww
Answer:
How?
I don't know
haha
thanks for the points