What is the average speed of a race car that moved 20 kilometers in 10 minutes?

Answers

Answer 1

Answer:21

Explanation:every body said


Related Questions

How much heat in kcal is required to change 0.5 kg of ice, originally at - 10 0 * C into steam at 110 C?Constants needed in the problemLatent heat of fusion=79.7 kcal/kg Specific heat of ice=0.5 kcal/kg/K ; Latent heat of vaporization ation = 539 kcal/kg ; Specific heat of water 1.0 kcal/kg/K Specific heat of ieam=0.480 kcal/kg

Answers

Answer:

Q = 364.25 kcal

Explanation:

In this question, we will have to calculate the heat absorptions for different steps of temperature rise and phase change. And then we will ad them to calculate total heat absorbed.

1. RISE IN TEMPERATURE OF ICE:

First, the temperature of ice will be increased from - 10°C to 0 °C. Heat absorbed during this process will be given as:

Q₁ = mC₁ΔT₁

where,

Q₁ = Heat absorbed while increasing temperature of ice = ?

m = mass of ice = 0.5 kg

C₁ = specific heat of ice = 0.5 kcal/kg k

ΔT₁ = change in temperature of ice = 0 - (-10) = 10 k

Therefore,

Q₁ = (0.5 kg)(0.5 kcal/kg.k)(10)

Q₁ = 2.5 kcal

2. MELTING OF ICE:

Now, the melting of ice will occur at 0°C and the heat absorbed during this process will be:

Q₂ = m(Latent Heat of Fusion of Ice)

where,

Q₂ = heat Absorbed during melting of ice = ?

Therefore,

Q₂ = (0.5 kg)(79.7 kcal/kg)

Q₂ = 39.85 kcal

3. RISE IN TEMPERATURE OF WATER:

Now, the temperature of water will be increased from 0°C to 100 °C. Heat absorbed during this process will be given as:

Q₃ = mC₃ΔT₃

where,

Q₃ = Heat absorbed while increasing temperature of water = ?

m = mass of water = 0.5 kg

C₃ = specific heat of water = 1 kcal/kg k

ΔT₃ = change in temperature of ice = 100 - 0 = 100 k

Therefore,

Q₃ = (0.5 kg)(1 kcal/kg.k)(100 k)

Q₃ = 50 kcal

4. VAPORIZATION OF WATER:

Now, the vaporization of water will occur at 100°C and the heat absorbed during this process will be:

Q₄ = m(Latent Heat of Vaporization of Water)

where,

Q₄ = heat Absorbed during vaporization of water = ?

Therefore,

Q₄ = (0.5 kg)(539 kcal/kg)

Q₄ = 269.5 kcal

5. RISE IN TEMPERATURE OF STEAM:

Now, the temperature of steam will be increased from 100°C to 110 °C. Heat absorbed during this process will be given as:

Q₅ = mC₅ΔT₅

where,

Q₅ = Heat absorbed while increasing temperature of steam = ?

m = mass of steam = 0.5 kg

C₅ = specific heat of steam = 0.48 kcal/kg k

ΔT₅ = change in temperature of ice = 110 - 100 = 10 k

Therefore,

Q₅ = (0.5 kg)(0.48 kcal/kg.k)(10 k)

Q₅ = 2.4 kcal

Hence, the total heat absorbed to change 0.5 kg of ice at - 10°C into steam at 110°C will be:

Q = Q₁ + Q₂ + Q₃ + Q₄ + Q₅

Q = 2.5 kcal + 39.85 kcal + 50 kcal + 269.5 kcal + 2.4 kcal

Q = 364.25 kcal

An object that is experiencing two vertical forces (upwards and a downwards) is moving downward with a constant speed. What can be concluded about the strength of the two forces?

Answers

Answer:

Both upward and downward forces are equal

Explanation:

When an object is acted upon by two vertical forces ; upward and downward, and the object moved at a constant speed, then the net force acting upon the object is zero(upward force + downward force = 0). This is because an object will only move at a constant velocity if the opposing forces cancels each other out. Since the falling object is already in motion, and maintaining a constant velocity, there is no for required to keep the body in motion and as such the Velocity at which the body is moving remains constant.

A car’s brakes decelerate it at a rate of -2.20 m/s2. If the car is originally travelling at 17 m/s and comes to a stop, then how far, in meters, will the car travel during that time?

Answers

Answer:

x = 65.68 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}^{2}=v_{o}^{2}-2*a*x[/tex]

where:

Vf = final velocity = 0 (comes to stop)

Vo = initial velocity = 17 [m/s]

a = desaceleration = -2.2 [m/s²]

x = displacement [m]

Now replacing, we have:

[tex](0)^{2}=(17)^{2}-2*(2.2)*x\\4.4*x = 289\\x = 65.68 [m][/tex]

A :-) for this question , we should apply
2as = v^2 - u ^2
Given - u = 17 m/s
v = 0 m/s
a = -2.20 m/s^2
Solution -
2as = v^2 - u^2
2 x -2.20 x s = 0^2 - 17^2
s = 0^2 - 17^2 by 2 x -2.20
s = -( 17 x 17 ) by 2 x -2.20
( Cut minus ( - ) and ( - ) )
s = 17 x 17 by 2 x 2.20
s = 289 by 4.4
s = 65.6

.:. The car travelled 65.6 meters.

Charges are of two kinds—negative charges and ________________ charges. __________ amounts of both kinds of charges are found in every piece of matter.

Answers

Answer: the first is positive and second is equal

Explanation:

Answer: 1. Positive

Explanation:

Because there is negative charges and positive charges

A book that weighs 5 N sits on a table. What force does the table apply to the book?

Answers

Answer:

E =F.d =[1/2]mv^2

mad = [1/2]mv^2

d= v^2/2a ,v=u+at , v^2 = [at]^2 since u=0

So d = at^2/2

F = ma= 20a= 50 , a=5/2 and t=2

so d = [5/2][2^2]/2=5

Explanation:

Every action has an equal and opposite reaction. It is an action-reaction principle. Therefore the table exerts a force of 5 N on the book in order to be in stable condition.

What is Newton's third law of motion?

Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.

Therefore the table exerts a force of 5 N on the book in order to be in stable condition.

The given data in the problem is ;

W is the weight of the book sits on table = 5N

N is the normal force on the book

From the equilibrium equation ;

Weight -Normal force on the book  =0

Weight =Normal force on the book

The normal force on the book =5N

Hence the table exerts a force of 5 N on the book in order to be in stable condition.

To learn more about Newton's third law of motion refer to the link;

https://brainly.com/question/1077877

Which of the following are possible non-SI units to describe the rate of
acceleration? (Choose all that apply)

1) meters per second per minute

2) miles per kilometer per
second

3) miles per hour per second

4) kilometers per hour squared

5) meters per hour per kilometer

6) kilometers per minute

Answers

The possible non-SI units to describe the rate of acceleration is the kilometers per hour squared. That is option 4.

What is acceleration?

Acceleration is the relationship that exists between velocity and time. It is defined as the change of velocity in both speed and direction with respect to time.

The formula for acceleration is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt.

Velocity is defined as the rate of objects position with time.

The SI units of velocity = meter/seconds

Substitute for velocity in first equation:

a = meter/sec/sec

a = meter/sec²

But 1000meters = 1 Km

3600 secs = 1 hour

Therefore, the possible non-SI units to describe the rate of acceleration is the kilometers per hour squared.

Learn more about acceleration here:

https://brainly.com/question/14344386

#SPJ1

PLEASE HELP ME! IM TIMED

Answers

Answer:

Toothpaste

Because it is viscous

Please help! Will mark brainliest!

Answers

Answer:

im pretty sure its d

Explanation:

What is the speed of an eagle that travels 200 meters in 4 seconds? A. 800 m/s2 B. 800 m/s C. 50 m/s2 D. 50 m/s​

Answers

Answer:

The answer is D.

Explanation:

You have to apply distance formula :

[tex]distance = speed \times time[/tex]

[tex]let \: d = 200,t = 4[/tex]

[tex]200 = s \times 4[/tex]

[tex]4s = 200[/tex]

[tex]s = 200 \div 4[/tex]

[tex]s = 50 \: m {s}^{ - 1} [/tex]

Given:-

An eagle travels 200 meters in 4 seconds

To find:-

Speed of the eagle

Solution:-Here

Distance=d=200m

Time=t=4s

As we know

[tex]{\boxed{\sf Speed ={\dfrac{Distance{}_{(d)}}{Time{}_{(t)}}}}}[/tex]

Substitute the values

[tex]\qquad\quad {:}\longmapsto\sf Speed=\dfrac {200}{4}[/tex]

[tex]\qquad\quad {:}\longmapsto\sf Speed=50m/s [/tex]

[tex]\therefore{\underline{\boxed{\bf Speed\:of\:eagle=50m/s}}}[/tex]

Hence Correct option is D


An object starts at 16 m/s with an acceleration of 4.5 m/s? How far does it go in 9.0 seconds?

Answers

648 because 16 times 4.5 is 72 and that times 9 is 648

6th grade science I mark as brainliest.​

Answers

Answer:

Solution:-

Distance =400m

Time=20s

We need to find speed

As we know that

[tex]{\boxed{\sf speed \dfrac {Distance {}_{(d)}}{Time {}_{(t)}}}}[/tex]

Substitute the values

[tex]\LARGE\leadsto\sf speed=\dfrac {400}{20}[/tex]

[tex]\LARGE\leadsto\sf 20m/s[/tex]

a motorbike can travel 1000 meters in 10 minutes calculate how car it can travel in 1 sec. ​

Answers

Answer:

1.67meter

Explanation:

if it can travel 1000 meters in 10 minutes, 10 minutes are 600 secs (10×60), 1000÷600 is 1.67

Answer:

HI

Explanation:

A warehouse worker pushed a cart weighing 4.50 kg to the top of an inclined plane. Initially, the cart was 0.670 m above the floor. If the top of the inclined plane is 2.70 m above the floor, calculate the work done by gravity as the worker pushed the cart to the top of the plane.

Answers

Answer:

- 89.523J

Explanation:

We solve the above question using work done(Potential Energy) formula

The formula =

-(mgh)

Where m = Mass = 4.50J

g = Acceleration due to gravity = 9.8m/s²

We are told in the question:

Initially, the cart was 0.670 m above the floor. If the top of the inclined plane is 2.70 m above the floor

Hence, the height =

2.70m - 0.670m = 2.03m

Work done = -(2.03m × 4.5kg× 9.8m/s²)

= - 89.523J

The normal force of a parked car is 15,000 Newtons. The coefficient of static friction between the rubber of the tires and the asphalt of the road is 0.75. What is the maximum static friction force?

Answers

Answer:

11250 N

Explanation:

From the question given above, the following data were obtained:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

Friction and normal force are related by the following equation:

F = μR

Where:

F is the frictional force.

μ is the coefficient of static friction.

R is the normal force.

With the above formula, we can calculate the frictional force acting on the car as follow:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

F = μR

F = 0.75 × 15000

F = 11250 N

Therefore, the frictional force acting on the car is 11250 N

Find the kinetic energy of a 3.5 kg cat that has a momentum of 0.22 kg • m/s.
A) 3.98 x 10^-5 J
B) 4.32 x 10^-4 J
C) 6.91 x 10^-3 J
D) 7.22 x 10^-2 J

Answers

Answer:

6.19*10^-3 J

Explanation:

Just took the test. Kiss me

A 52 kg person is running 2.5 m/s. What is their momentum?

Answers

Answer:

130kg/ms

Explanation:

given data mass,52kgvelocity,2.5m/smomentum?from momentumM=mv

Mass=52kg

Velocity=2.5m/s

Momentum=?

We know that,

Momentum=Mass × velocity

Or,momentum=52kg× 2.5m/s

Or,momentum=130 kgm/s

So,the momentum is 130 kgm/s.

When you mix a solution, the mass of the substances before and after you mix them should be the same.true or false

Answers

Answer:

True

Explanation:

The mixing substances can be taken to be the reactants and the resulting mixture as the product. When the substances change state during mixing, the mass of the substances does not change meaning that the mass of the product will equal the mass of the reactants .This is true due to the law of conservation of mass.

Answer:

TRUE

Explanation:

because blablablabla blablolbleep scientific talk

what is the KE of a 1.00 kg hammer swinging at 20.0 m/s? 200 Joules
I know the answer I just need help understanding it.

Answers

Answer:

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

Kinetic energy (K.E) =?

Kinetic energy is simply defined as energy possed by a body in motion. Mathematically, it is expressed as:

K.E = ½mv²

Where:

K.E is the kinetic energy

m is the mass of the object

v is the velocity of the object.

Thus, we can obtain the kinetic energy of the automobile by using the above formula as illustrated below:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

Kinetic energy (K.E) =?

K.E = ½mv²

K.E = ½ × 1250 × 20²

K.E = 625 × 400

K.E = 250000 J

Therefore, the kinetic energy of the automobile is 250000 J

what is the mass and volume of 1000kg/m3 of water?​

Answers

Answer: The mass would be 1000m3 and the volume would be 1000kg

Explanation:

Two ice-skaters are skating in circles on a frozen pond. Maria is making large circles with a radius of 12 m and skating 4.5 m/s. Her friend, Samantha, is making smaller circles with a radius of 6 m but is not skating as quickly, going only 3.8 m/s.

How could each skater increase her centripetal acceleration without changing the size of her path? Explain your reasoning.

Answers

Answer: Samantha has the largest centripetal acceleration of 2.4 m/s^2. Maria has only 1.69 m/s^2.

Explanation:

Select three effective methods for helping a friend who is showing self harming behavior

Answers

Answer:

Avoid judging or criticizing your friend.

Let your friend know that you care and want to help

Share the ways you cope with stress and other problems in your life

I had this question

tarzans mass is 75kg. calculate his weight

Answers

Answer:

75kg=165.346697lbs

Explanation: F A T

a cannon launches a 3.0 kg pumpkin with 110J of kinetic energy. what is the pumpkin’s speed?

Answers

Answer:

v = 8.56 [m/s]

Explanation:

The kinetic energy can be calculated by means of the following equation.

[tex]E_{k}=\frac{1}{2}*m*v^{2}[/tex]

where:

m = mass = 3 [kg]

v = velocity [m/s]

Ek = kinetic energy [J]

[tex]110 = \frac{1}{2} *3*(v^{2} )\\v^{2} = 220/3\\v=\sqrt{73.333}\\v=8.56[m/s][/tex]

PLEASE HELP ASAP 2. Two rocks with a mass of 5 kilograms and 10 kilograms, respectively, fall freely from rest near
the Earth's surface. After 3 seconds of free-fall, compared to the 5-kg rock, the 10-kg rock has
greater...
a. acceleration
b. momentum
c. height
d. velocity
e displacement

Answers

Answer:

i Think momentum

Explanation:

Donny, who has a mass of 75.0 kg, is riding at 25.0 m/s in his truck when he suddenly slams on the brakes to avoid hitting a squirrel crossing the road. His seatbelt brings his body to a stop in 0.500 seconds. What force does the seatbelt exert on him?

Answers

Answer:

F = 3750  N

Explanation:

Given that,

Mass of Donny, m = 75 kg

Initial speed, u = 25 m/s

He suddenly slams on the brakes to avoid hitting a squirrel crossing the road, final speed = 0

Time, t = 0.5 s

We need to find the force the seatbelt exert on him. The force is given by :

F = ma

a is acceleration

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{75\times (0-25)}{0.5}\\\\=-3750\ N[/tex]

So, the force is 3750  N.

The force the seatbelt exert on him is 3750 N

Using Newton's third law

f = ma

where

m = mass

a = acceleration

a = v - u / t

where

v = final velocity

u = initial velocity

t = time

Therefore,

f = m(v - u / t)

m = 75 kg

u = 25 m/s

t = 0.500 secs

v = 0 m/s (The car will stop because he applied a brake)

f = 75 × (0 - 25 / 0.5)

f = 75 × -25 / 0.5

f = 75 × -50

f = - 3750

f = 3750 N

read more: https://brainly.com/question/17372829?referrer=searchResults

Two students are studying for a Science Test. On the table, they had a glass of water and identical cell phones. Both of their phones had run out of battery, therefore they were both charging in the same wall outlet. One student’s charging cord was 3ft and the other student’s charging cord was 9ft. which of the phones charged the fastest using Ohm’s Law. Cite evidence to support your theory.

Answers

Answer:

The student with the 3ft charger

Explanation:

Because the electricity from the 3ft charger has a shorter distance to mooves than the 9ft one

PLEASE HELP ME IM TIMED

Answers

Yeah it’s the mantle

What is the period of a rotating object if it spins 24 times in 13 seconds?

Answers

Answer:

The period is 0.54 seconds

Explanation:

Period (T)

Is the time required for a rotating object to make one complete revolution around a circular path.

If it takes a time t to complete n revolutions, the period is:

[tex]\displaystyle T=\frac{t}{n}[/tex]

The rotating object spins n=24 times in t=13 seconds, thus its period is:

[tex]\displaystyle T=\frac{13}{24}[/tex]

T = 0.54 sec

The period is 0.54 seconds

Why can humans float in space but not on Earth?

Answers

Answer/explanation: on earth there is a gravitational pull discovered by sir Isaac Newton when an apple fell on his head. However in space there isn’t any gravity to keep you from drifting off.

In how many ways can chemical reaction takes place? what are they?​

Answers

Answer:

Chemists classify chemical reactions in a number of ways: by type of product, by types of reactants, by reaction outcome, and by reaction mechanism. Often a given reaction can be placed in two or even three categories, including gas-forming and precipitation reactions.

Explanation:

mark me as brainliest thank you

Other Questions
1. Why did the United States and the Soviet Union become enemies!A. Differences in economics and governmentsB. Disagreement about the future of GermanyC. The threat of nuclear weapons (Arms Race)D. All of the above What is the name of the following chemical compound? how do i get over my fears??? Olivia is using 160 quilt squares to make a red, yellow, and blue quilt. If 25% of the quilt squares are red and 30% are yellow, how many quilt squares are blue? On a map scale, 2 inches represents 60 miles. Which graph best shows the relationship between x, the number of inches on the map, and y, the actual distance in miles? (zoom in if u can't see it) How did the crusades stimulate trade in Europe? Which of the following sets are disjoint?a) Men and uncles b) Aunts and uncles c) Women and Aunts d) They are all disjoint multipy (2c-1) (7c-5) An earthquake wave travels through 55 km of rock in 25 seconds . Which equation represents the relationship between t, the number of seconds, and d, the total distance the wave travels? plsssssss help 5/6 x 7/8 25 23 + 27 +2 9 Express in simplified radical What two European Nations lead early exploration? What was the function of the secret police in the Soviet Union help me, please reeeeeeeeeeeeeeeee Which best describes an incident command system (ICS)?a. A description of why disaster plans are essential to medical facilitiesb. An outline of how to keep a medical facility secure during a disasterc. A description of which supply should be utilized in a disasterd. An outline of who is responsible for different components of a disaster plan The use of alcohol and other drugs by the operator of a motor vehicle reduces then eliminates your abilityto safely operatea motor vehicle.Oa) trueOb) false When Geraldine looked to the sky, she was amazed by what she saw. The tail from a comet cut across the sky like a knife through butter. It was the first time she had seen one in real life. Every comet she had seen up until now came from a book. She almost didn't see it at first. The stars hung in the sky like a million eyes blinking and winking down at Geraldine. Geraldine wasn't even thinking about them or the campfire or the woods. Her mind was someplace else, and she had her mind on a lot of different things. She was thinking about how she was going to pay for college. She was thinking about graduation. She was thinking about everything but the sky. The last time that she was in the woods was when she was a little girl. It seemed so foreign to her. As her mind wandered, that's when the comet appeared. It was almost like it had read her thoughts. It passed over her head, and she traced its path with her finger like she was waving a magic wand.6Which phrase from the story offers the best visual description of Geraldine's reaction to the comet? A. Geraldine wasn't even thinking about them or the campfire or the woods. B. The last time that she was in the woods was when she was a little girl. C. It passed over her head, and she traced its path with her finger like she was waving a magic wand. D. Her mind was someplace else, and she had her mind on a lot of different things. What word in stanza 3 is a symbol and what does it represent?Indian Boy Love Song (#2)I never spokethe languageof the old womanvisiting my motherin winters so coldthey could freezethe tongue whole.I never held my headto their thin chestsbelieving in the heart.Indian women, forgive me.I grew up distantand always afraid Helppppppppppppppppppppppppppppp I really need help :(