The binding energy of a mole of nuclei with a mass defect of 0.00084kg/mol is 7.56 x 10¹³ J/mol (option B).
How to calculate binding energy?Binding energy is the energy needed to separate the constituent parts of an atom or nucleus; equivalent to the mass defect.
The binding energy of a nucleus can be calculated as follows:
Binding Energy = mass defect x c²
where;
c = speed of light in vacuum (2.9979 x 10⁸ m/s)According to this question, a nuclei with a mass defect of 0.00084kg/mol is given. The binding energy can be calculated as follows:
Binding energy = 0.00084 kg/mol × (2.9979 x 10⁸ )²
= 8.94e16 × 8.4 × 10-⁴
= 7.51 × 10¹³J
Therefore, 7.51 × 10¹³J/mol is the binding energy of the nuclei.
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Consider the reaction: 2Al + 3S = Al2S3If you have 45 grams of aluminum...a. How many grams of aluminum sulfide are produced? (Theoretical)b. When the rxn is performed in the lab, 114 grams of aluminum sulfide is produced. What is the percent yield?
The reaction they give us is balanced. We must determine the moles of aluminum that are equivalent to that 45 g, for this, we will use the molar mass of aluminum equal to 26.98g/mol
[tex]\begin{gathered} \text{Mol of Al}=GivengAl\times\frac{1molAl}{MolarMass,gAl} \\ \text{Mol of Al}=45gAl\times\frac{1molAl}{26.98gAl}=1.67molAl \end{gathered}[/tex]Now, in the reaction, we can see that for every 2 moles of aluminum, 1 mole of aluminum sulfate is produced. We can also use the molar mass of aluminum sulfate (101.96g/mol) to calculate the grams of aluminum sulfide produced.
[tex]\begin{gathered} gAl_2O_3=GivenMolAl\times\frac{1molAl_2O_3}{2molAl}\times\frac{MolarMass,gAl_2O_3}{1molAl_2O_3} \\ gAl_2O_3=1.67molAl\times\frac{1molAl_2O_3}{2molAl}\times\frac{101.96gAl_2O_3}{1molAl_2O_3}=85gAl_2O_3 \end{gathered}[/tex]The grams of aluminum sulfate produced is 85g
The percent yield is calculated with the next equation:
[tex]\begin{gathered} \text{Percent yield=}\frac{\text{Actual yield}}{Theoretical\text{ yield}}\times100\% \\ \text{Percent yield=}\frac{\text{1}14g}{85g}\times100\%=134\% \end{gathered}[/tex]Percent yield=134%
This is not experimentally possible
Please assist with following definitionsSystem and surroundings Specific heat function Entalpy changes Standard enthalpy of formation
System and surroundings:
A system is defined as a matter or region on which analysis is done. The system is separated from the surroundings by the boundary. Everything external to the system is surrounding.
Specific heat function:
The amount of heat that must be added to one unit of mass of the substance in order to cause an increase of one unit in temperature.
Enthalpy changes:
We could say that it is equal to the difference between the energy used to break bonds in a chemical reaction and the energy gained by the formation of new chemical bonds in the reaction.
Standard enthalpy of formation:
It is a measure of the energy released or consumed when one mole of a substance is created under conditions from its pure elements.
When Tabitha was testing a substance she thought might be heroin, she added the Marquis reagent chemical to the substance. It turned purple, so she was able to verify it was heroin. What does this BEST demonstrate?
A.
demonstrative evidence
B.
individual characteristics
C.
physical properties
D.
chemical properties
Answer:
Demonstrative evidence
a chemist measures the enthalpy change deltaH during the following reaction: COCl2(g)+4NH3(g)--->CO(NH2)2(s)+2NH4Cl(s) deltaH=-559. kJ use this information to complete the table below.
A chemist measures the enthalpy change ∆H during the reaction COCl2(g)+4NH3(g)--->CO(NH2)2(s)+2NH4Cl(s). Then ∆H = -140 KJ.
Enthalpy ChangeThe amount of heat that gets released or absorbed during a reaction and that takes place under constant pressure is referred to as the enthalpy change. The sign for it is H, which can be read as “∆H.”
Note that only reactions carried out under constant pressure are covered by the phrase “enthalpy change.”
What distinguishes entropy change from enthalpy?The main distinction that comes in between enthalpy and entropy, which exists despite the fact that they are both components of a thermodynamic system, is that the enthalpy is expressed as the total amount of heat content whereas altogether the entropy is the level of disorder.
Simply put, what is enthalpy?The whole internal energy is represented by enthalpy. And volume times pressure. The enthalpy of a system cannot be measured, although enthalpy variations can be observed.
Table 1[tex]CoCl_{2}[/tex] + [tex]4NH_{3}[/tex] →[tex]CO(NH_{2} )_{2} + 2 NH_{4}Cl\\[/tex]
∆H = -559 Kj
Then reverse the above reaction and multiply with 2 as sign of ∆H changes from -ve to +ve
[tex]2CO(NH_{2})_{2} + 4NH_{4}Cl[/tex] → [tex]2COCl_{2} + 8NH_{3}[/tex]
∆H = -559 x 2
= 1118 Kj
Table 2[tex]CoCl_{2}[/tex] + [tex]4NH_{3}[/tex] →[tex]CO(NH_{2} )_{2} + 2 NH_{4}Cl\\[/tex]
∆H = -559 Kj
Reverse the above reaction ∆H changes from -ve to +ve
[tex]CO(NH_{2})_{2} + 2NH_{4}Cl[/tex] → [tex]COCl_{2} + 4NH_{3}[/tex]
∆H = +559 Kj
Table 3[tex]CoCl_{2}[/tex] + [tex]4NH_{3}[/tex] → [tex]CO(NH_{2} )_{2} + 2 NH_{4}Cl\\[/tex]
∆H = -559 Kj
Above equation is divided with 4
[tex]\frac{1}{4}[/tex][tex]CoCl_{2}[/tex] + [tex]NH_{3}[/tex] → [tex]\frac{1}{4}[/tex] [tex]CO(NH_{2} )_{2} + \frac{1}{2} NH_{4}Cl\\[/tex]
∆H = -559/4 KJ
= -139.8 KJ
≈ -140 KJ
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The radius of a nickel atom is 125 pm. How many nickel atoms would have to be laid side by side to span a distance of 2.65 mm?
The number of nickel atoms that would be laid side by side to span a distance of 2.65 mm is 1.06 x 10⁷ atoms of nickel.
What is the diameter of the nickel atom?The diameter of the nickel atom is the line that divides the nickel atom into two equal halves. The diameter of an object is always double of the radius when the radius of the atom is known.
The diameter of the nickel atom is calculated as follows;
d = 2r
where;
d is the diameter of the nickel atomr is the radius of the nickel atomd = 2 x 125 pm
d = 250 pm
d = 2.5 x 10⁻¹⁰ m
The number of nickel atoms that would be laid side by side to span a distance of 2.65 mm is calculated as follows;
n(2.5 x 10⁻¹⁰ m) = 2.65 mm
n(2.5 x 10⁻¹⁰ m) = 2.65 x 10⁻³ m
n = (2.65 x 10⁻³) / (2.5 x 10⁻¹⁰)
n = 1.06 x 10⁷ atoms of nickel
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Calcium carbonate can undergo a chemical reaction to produc calcium oxide (CaO) and carbon dioxide (CO₂). Which possible masses of calcium oxide and carbon dioxide can form when 400g of calcium carbonate undergoes this chemical reaction?
*
1 point
400g CaO and 0g CO₂
224g CaO and 176g CO₂
40g CaO and 10g CO₂
The atomic mass of the element neon (Ne) is 20.180 amu. Which measurement is correct?
1 point
1 gram Ne = 20.180 moles = 1.215×1025 atoms
1 gram Ne = 20.180 moles = 6.022×1023 atoms
1 mole Ne = 20.180 grams = 1.215×1025 atoms
1 mole Ne = 20.180 grams = 6.022×1023 atoms
When reactants of a reaction are known, which fact can always be deduced about the products?
*
1 point
the state of the products
the number of atoms in the products
the number of products
the mass of each product
The atomic mass of carbon (C) is 12.01amu and oxygen (O) is 16.00amu. Which molar mass is correct for carbon dioxide (CO₂)?
*
1 point
28.01 g/mol
44.01 g/mol
192.16 g/mol
268.01 g/mol
How many moles is in 43g of CO₂?
*
1 point
1204 mol
1.54 mol
2.59 x 10²⁵
According to the law of conservation of matter, which statement best describes a balanced chemical equation?
1 point
The number of moles of atoms of each element must be the same in the reactants and in the products.
The total number of moles of atoms must be the same in the reactants and in the products.
The total number of molecules must be the same in the reactants and in the products.
The number of moles of each molecule must be the same in the reactants and in the products.
Nitrogen gas combines with hydrogen gas to produce ammonia (N₂+3H₂⟶Ammonia). Based on the law of conservation of mass, which could be the product of the reaction?
*
1 point
NH₂
NH₃
2NH₃
3NH₂
How do you calculate the number of moles from mass?
*
1 point
it is the product of moles and molar mass
it is the quotient of mass and molar mass
it is the product of mass and molar mass
it is the quotient of avogadro's number and molar mass
Sugar reacts with oxygen gas to produce carbon dioxide and water (C₆H₁₂O₆ + 6O₂⟶6CO₂+6H₂O). Which ratio of components is correct?
*
1 point
For every 12 moles of CO₂ produced, 2 moles of C₆H₁₂O₆ is needed.
For each mole of O₂, 1 mole of C₆H₁₂O₆ is needed.
For every 5 moles of water produced, 6 moles of oxygen is needed.
What is the molar mass of NH₄Cl?
*
1 point
53.5 g/mol
50.5 g/mol
497.0 g/mol
Answer:
400CaO and 0g C02
Explanation: 400 has more moiul
look at the picture
Answer:
I believe it is the last choice
Explanation:
Isotopes of a certain element must have the same atomic number(the # of protons). This is what differentiates the different elements. However, isotopes could have varying amounts of neutrons, therefore the atomic mass could vary as well.
hope this helps :)
please crown me brainliest!!!
Hydrazine, N2H4 , reacts with oxygen to form nitrogen gas and water.
N2H4(aq)+O2(g)⟶N2(g)+2H2O(l)
If 3.35 g of N2H4 reacts with excess oxygen and produces 0.350 L of N2 , at 295 K and 1.00 atm, what is the percent yield of the reaction?
Taking into account definition of percent yield, the percent yield of the reaction if 3.35 g of N₂H₄ reacts with excess oxygen and produces 0.350 L of N₂ is 13.82%.
Reaction stoichiometryIn first place, the balanced reaction is:
N₂H₄ + O₂ → N₂ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
N₂H₄: 1 moleO₂: 1 moleN₂: 1 moleH₂O: 2 molesThe molar mass of the compounds is:
N₂H₄: 32 g/moleO₂: 32 g/moleN₂: 28 g/moleH₂O: 18 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
N₂H₄: 1 mole ×32 g/mole= 32 gramsO₂: 1 mole ×32 g/mole= 32 gramsN₂: 1 mole ×28 g/mole= 28 gramsH₂O: 2 moles ×18 g/mole= 36 gramsIdeal gas lawThe pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where:
P is the gas pressure.V is the volume that occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances. n is the number of moles of the gas. Percent yieldThe percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.
The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:
percent yield= (actual yield÷ theoretical yield)× 100%
where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.
Actual yield of N₂In this case, you know:
P= 1 atmV= 0.350 LT= 295 KR= 0.082 [tex]\frac{atmL}{molK}[/tex]n= ?Replacing in the ideal gas law:
1 atm×0.350 L = n×0.082 [tex]\frac{atmL}{molK}[/tex]× 295 K
Solving:
n= (1 atm×0.350 L) ÷ (0.082 [tex]\frac{atmL}{molK}[/tex]× 295 K)
n= 0.01447 moles
Finally, the actual yield of N₂ is 0.01447 moles.
Theoretical yield of N₂Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 32 grams of N₂H₄ form 1 mole of N₂, 3.35 grams of N₂H₄ form how many moles of N₂?
moles of N₂= (3.35 grams of N₂H₄× 1 moles of N₂)÷ 32 grams of N₂H₄
moles of N₂= 0.1047 moles
Finally, the theoretical yield of N₂ is 0.1047 moles.
Percent yield for the reaction in this caseIn this case, you know:
actual yield= 0.01447 molestheorical yield= 0.1047 molesReplacing in the definition of percent yield:
percent yield= (actual yield÷ theoretical yield)× 100%
Solving:
percent yield= (0.01447 moles÷ 0.1047 moles)× 100%
percent yield= 13.82%
Finally, the percent yield for the reaction is 13.82%.
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According to the below equation, how many moles of P2H4 will be required to generate 1.76×1023 molecules of P4?
6P2H4→8PH3+P4
The number of the moles of the P₂H₄ is equal to 1.734 moles, which will generate 1.76×10²³ molecules of P₄.
What is the balanced chemical equation?The equation in which the total mass of substances on the reactant side is equal to the total mass of substances on the product side is known as a balanced chemical equation.
The law of conservation of mass must obey by a balanced chemical equation. The given balanced chemical reaction of the reaction of P₂H₄ is :
6 P₂H₄ → 8 PH₃ + P₄
The number of molecules of the phosphorous P₄ formed = 1.76 × 10²³
The number of moles of P₄ = 1.76 × 10²³/(6.022 × 10²³) = 0.292 mol
One of the phosphorous P₄ is formed from P₂H₄ = 6 mol
Then 0.292 mol of P₄ will form from P₂H₄ = 6× 0.292 = 1.734 mol
Therefore, the 1.734 moles of P₄ are required to form 1.76×10²³ molecules of P₂H₄.
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How to solve this problem
The 1.662 × 10¹⁸ protons per second will shine on the chemistry text from a 250 W bulb.
What is the photon?A photon or light quantum, is an energy packet of electromagnetic radiation. Einstein suggested the presence of discrete energy packets during the transmission of light and deduced that the light quantum is associated with momentum (hν/c).
A photon is defined as a discrete bundle of electromagnetic energy that also moves at the speed of light (3 × 10⁸ m/s).
The energy of a single photon with a wavelength (λ) of 550 nm can be calculated from the following equation:
E = hc/λ
Where h is Planck's constant has a value equal to 6.626*10⁻³⁴ J·s.
E = (6.626 × 10⁻³⁴ J·s × 3×10⁸ m/s) / (550 ×10⁻⁹m)
E = 3.614 × 10⁻¹⁹ J.
It means that the energy of one photon is equal to 3.614 × 10⁻¹⁹ J.
[tex]1J/s \times \frac{1photon}{3.614 \times 10^{-19} J.}[/tex]
= 2.77 × 10¹⁸ proton/s = 1 Watt
Given, a 200 W bulb converts 5% of its output into light, therefore
200* 5/100 = 6 W
Then 6 watts has photons = [ 2.77 ×10¹⁸ proton/s * 6 ] = 16.62 × 10¹⁸ proton/s
If only 10% of the light will shine on year chemistry textbook, Then
16.62 × 10¹⁸ proton/s × 10/100 = 1.662 × 10¹⁸ protons/s
The number of photons shining on chemistry text = 1.662 × 10¹⁸ protons
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A weather balloon is designed to burst when the volume reaches
250.0 L. The balloon is filled with 32.0 L helium at sea level where the
pressure is 1.00 atm at 20.0 °C. The balloon expands and bursts after
ascending until the temperature is -35.0 °C. Determine the pressure
(in psi) at which the balloon bursts.
The pressure at which balloon bursts is 3.07 psi , when expands and bursts after ascending until the temperature is -35 degree celsius.
What is pressure and it is calculated out to be 3.07 psi?As we have already studied in earlier classes pressure is the force per unit perpendicular area.Here , is given initial volume 32 L and the initial pressure 1 atm , initial temperature 20 degree celsius and final temperature -35 degree celsius. The balloon burst when the volume of gas reaches 250 L, so final volume is 250 L .According to combined gas law : P1V1/T1 = P2V2/T2 , where P1 is the initial pressure , we know that T1 = 20+ 273 K = 293 K.T2 = -35 + 273 = 238 K , now using equation , 1 atm x 32/29 = P2 x 25/238, P2 = 0.209 atm , 1 atm = 14.69 psi , so 0.209 atm = 14.6956 x 0.209 = 3.07 psi.So the balloon bursts at 3.07 psi.To know more about pressure visit:
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PLEASE HELP I DON’T GET THIS :(
Answer:
1.06
Explanation:
One mole of nitrogen is 14.009, or the mass number and you divide 14.9 by 14.009 and get 1.06 for the amount of moles
Answer:
1.063753837 mol
Explanation:
14.9 * (1/14.007) = 1.063753837
Original grams * (1 mol/atomic weight of nitrogen) = 1.063753837
look at the picture
Answer: The correct option is ○ O₂
Explanation:
All the other options denote that they are not a single element theyare
in compound form. Only the oxygen is in element form.
Example 1: A gas is expanded from an initial volume of 20.5 L at 0.92 atm at room temperature (23.0°C) to a
final volume of 340.6L. During this expansion, the gas cools to 12.0°C. What is the new pressure?
The new pressure is .67 atm (atmospheric pressure at sea level)
What is pressure?
The force applied perpendicularly to an object's surface per unit area over which that force is distributed is known as pressure (symbol: p or P). : 445 The pressure relative to the surrounding air is known as gauge pressure, also spelled gauge pressure. Pressure is expressed using a variety of units. Some of these come from dividing a unit of force by a unit of area; the traditional unit of pressure in the imperial and U.S. customary systems is the pound-force per square inch (psi), which is equivalent to one newton per square metre (N/m²) in the SI. The atmosphere (atm), which is equal to this pressure, can also be used to describe pressure. The torr is defined as 1/760 of this.
PV = nRT
P₁V₁ = P₁V₁
P₁ = 0.92 atm
V₁ = 20.5 L
T₁ = 23.0°C
P₂ = ?
V₂ = 340.6L
T₂ = 12.0°C
P₂ = (P₁V₁/T₁)(T₂/V₂)
P₂ = .92(20.5/23)(12/340.6)
P₂ = .67 atm
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What is the name of the molecule below?
• A. 2-pentyne
B. pentane
• C. 2-pentene
O D. 2-pentane
The molecule described below is known as :
2-pentene.
What exactly are alkenes?Alkenes are organic compounds that contain a double bond and are composed of carbon and hydrogen atoms.They can be used as starting materials in the synthesis of alcohols, plastics, lacquers, detergents, and fuels.In the diagram below:
Each corner and joint displays the carbon atoms, and the total number of carbon atoms is 5.In the second position, there is one double bond.As a result, the compound is 2 pentene.
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Based on the balanced chemical equation shown below, what volume of 0.250 M K2S2O3(aq), is needed to completely react with 37.32 mL of 0.125 M KI3(aq)?
Based on the balanced chemical equation, the volume of 0.250 M K₂S₂O₃ (aq) needed to completely react with 37.32 mL of 0.125 M KI₃ (aq) is 37.32 mL.
What is the balanced equation for the reaction of K₂S₂O₃ (aq) and KI₃ (aq)?The reaction between K₂S₂O₃ (aq) and KI₃ (aq) is a redox reaction.
The balanced chemical equation of the reaction is given as follows:
2 S₂O₃²⁻ (aq) + I₃⁻ (aq) ---> S₄O₆²⁻ (aq) + 3 I⁻ (aq)
Based on the balanced equation of the reaction:
2 moles of K₂S₂O₃ (aq) are required to react with one mole KI₃ (aq).
Moles of KI₃ (aq) in 37.32 mL of 0.125 M solution;
moles = molarity * volumeMoles of KI₃ (aq) = 37.32 * 0.125 M
Moles of KI₃ (aq) = 4.665 mmoles
Moles of K₂S₂O₃ (aq) required = 2 * 4.665 mmoles
Moles of K₂S₂O₃ (aq) required = 9.33 mmoles
Volume of K₂S₂O₃ (aq) required =moles / molarity
The volume of K₂S₂O₃ (aq) required = 9.33 / 0.25
The volume of K₂S₂O₃ (aq) required = 37.32 mL
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x gm of metal (E=12) was completely dissolved in 100 ml of N/2 HCl. The solution was then made upto 500 ml. 2.5 ml of this diluted acid required 12.5 ml of N/10 NaOH for complete neutralization. Find the valency of x.
When a potent acid, like hydrochloric acid, HCl, is combined with a potent base, such sodium hydroxide, NaOH, the result can be complete neutralization. Strong bases and acids dissociate entirely into their individual ions when they dissolve in water.
An element's valency is its capacity for combination. The periodic table groups have identical elements with the same valency.. How many electrons make up the outer shell of an element determines its valency. The group number.
Valency is simply the amount of electrons that an element's atom gains, loses, or shares to obtain the closest configuration to that of a noble gas. The valency of sodium (Na), magnesium (Mg), chlorine (Cl), and other elements, for instance, is 1.
When there are equal moles of strong acid and strong base, the strong acid and strong base completely neutralize one another. An aqueous solution with a pH of 7 is the end product.
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A 27.7 mL sample of a H3PO4 (triprotic) solution is titrated with a 0.609 M NaOH solution. The equivalence point is reached when 44.1 mL of NaOH solution is added. What is the concentration of the H3PO4 solution?
The concentration of the 27.7 mL H₃PO₄ solution is 0.323 M
We'll begin by writing the balanced equation for the reaction. This is given below:
H₃PO₄ + 3NaOH —> Na₃PO₄ + 3H₂O
From the balanced equation above, we obatined:
The mole ratio of the acid, H₃PO₄ (nA) = 1The mole ratio of the base, NaOH (nB) = 3How to determine the concentrationThe concentration of the H₃PO₄ can be obtained as follow:Volume of acid, H₃PO₄ (Va) = 27.7 mLConcentration of base, NaOH (Cb) = 0.609 M Volume of base, NaOH (Vb) = 44.1 mLConcentration of acid, H₃PO₄ (Ca) =?CaVa / CbVb = nA / nB
(Ca × 27.7) / (0.609 × 44.1) = 1 / 3
(Ca × 27.7) / 26.8569 = 1 / 3
Cross multiply
Ca × 27.7 × 3 = 26.8569
Ca × 83.1 = 26.8569
Divide both side by 83.1
Ca = 26.8569 / 83.1
Ca = 0.323 M
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Please help me with question 6!!The neutralization of a weak base and a strong acid should product a solution that is:a. basicb. neutralc. all of aboved. acidic
INFORMATION:
We have the neutralization of a weak base and a strong acid, and we must determine what should be the product of the reaction
STEP BY STEP EXPLANATION:
To determine it, we need to know that:
- The neutralization of a strong acid and strong base has a pH equal to 7. The neutralization of a strong acid and weak base will have a pH of less than 7, and conversely, the resulting pH when a strong base neutralizes a weak acid will be greater than 7.
In our case, we have the neutralization of a weak base and a strong acid, so our product would have a pH of less than 7. Then, knowing that a pH less than 7 represents an acidic, we can state that the product of the reaction will be an acidic.
A strong acid and a weak base yield a weakly acidic solution, not because of the strong acid involved, but because of the conjugate acid of the weak base.
ANSWER:
d. acidic
Pb(C₂H3O2)2 (s) + H₂S (g) --> PbS (s) + HC₂H302 (8)
[unbalanced equation]
Balance this equation, and then calculate how many grams of lead (II) sulfide form when you use 55.11
g of lead (II) acetate and excess (an unlimited amount of) H₂S?
40.4417g of PbS is formed from 55.11g of Pb(C2H3O2)2 and excess amount of H2S .
Given,
balanced chemical equation is ,
Pb(C2H3O2)2 (s) + H2S (g) ⇒ PbS (s) + HC2H3O2 (g)
to making the chemical equation balanced , we have to make sure that all the molecules on the left hand side and in the right hand side should be equal .
thus to making it equal 1st see that the number of carbon , oxygen and hydrogen is doubled in the left side than that of right side .
so we have to multiply HC2H302 by 2 .
Pb(C2H3O2)2 (s) +H2S(g) ⇒ PbS(s) + 2 HC2H3O2 (g)
so now the given chemical equation is balanced that we can say , 1 mol of Pb(C2H3O2)2 produces 1 mol of PbS .
It is given that , we can take H2S is in excess means the Pb(C2H3O2 )2 acts as limiting agent .
We know , molecular mass of Pb(C2H3O2)2 is 325.29g
325.29g contains 1mole
55.11g contains 55.11/325.29 = 0.169 moles
thus ,the mole of PbS formed from 55.11g of Pb(C2H3O2)2 is 0.169moles.
We know ,
molecular mass of PbS is 239.3g
1mole of PbS is 239.3g
0.169moles pf PbS is 239.3×0.169 = 40.4417 g
Hence , 40.4417g of PbS is formed from 55.11g of Pb(C2H3O2)2 and excess amount of H2S .
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A 56.0 mL sample of a 0.116 M potassium sulfate solution is mixed with 38.5 mL of a 0.102 M lead(II) acetate solution and
the following precipitation reaction occurs
K₂SO₂ (aq) + Pb(C₂H₂O₂)2(aq) 2KC₂H₂O₂(aq) + PbSO₂ (s)
The solid PbSO4 is collected, dried, and found to have a mass of 0.997 g
Determine the limiting reactant, the theoretical yield, and the percent yield
The limiting reactant is lead(II) acetate the theoretical yield is 1.1909 g and the percent yield is 83.71 %.
What is a molarity ?The amount of the sample in a specific solution volume is known as its molarity (M). The molarity of a solute per liter of the a solution is known as molar ratio. The molar concentration in a solution is another name for molarity.
Briefing:Molarity
= moles of solute/volume of the solution
or Moles
= Molarity * volume of solution
For potassium sulfate :
Molarity = 0.116 M
Volume = 56.0 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 56.0×10⁻³ L
Thus, moles of potassium sulfate:
Moles = 0.116 M * 56.0 * 10-3 moles
Moles of potassium sulfate = 0.006496 moles
For lead(II) acetate :
Molarity = 0.102 M
Volume = 38.5 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 38.5×10⁻³ L
Thus, moles of lead(II) acetate :
Moles = 0.102 * 38.5 *10-3 moles
Moles of lead(II) acetate = 0.003927 moles
According to the given reaction:
[tex]$\mathrm{K}_2 \mathrm{SO}_{4(a q)}+\mathrm{Pb}\left(\mathrm{C}_2 \mathrm{H}_3 \mathrm{O}_2\right)_{2(a q)} \rightarrow 2 \mathrm{KC}_2 \mathrm{H}_3 \mathrm{O}_{2(s)}+\mathrm{PbSO}_{4(a q)}$[/tex]
1 mole of potassium sulfate react with 1 mole of lead(II) acetate
0.006496 moles potassium sulfate react with 0.006496 mole of lead(II) acetate
Moles of lead(II) acetate = 0.003927 moles
Lead(II) acetate is limiting reagent. ( 0.003927 < 0.006496)
0.003927 mole of lead(II) acetate gives 0.003927 mole of lead(II) sulfate
Molar mass of lead(II) sulfate = 303.26 g/mol
Mass of lead(II) sulfate = Moles × Molar mass = 0.003927 × 303.26 g = 1.1909 g
Theoretical yield = 1.1909 g
Given experimental yield = 0.997 g
% yield = (Experimental yield / Theoretical yield) × 100 = (0.997/1.1909 g) × 100 = 83.71 %
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hexasilicion phosphide chemical formula
Si3P4 this is the answer i beleive!
How many moles of NO2 form when 10.2 mol NO3 completely reacts.
NO(g)+NO3(g)-->NO2(g)
The number of moles of NO₂ formed when 10.2 moles of NO₃ reacts is 20.4moles.
How to calculate number of moles?According to this question, nitrogen IV oxide (NO₂) reacts with nitrogen II oxide (NO) to form nitrogen VI oxide (NO₃) as follows:
NO₃ + NO → 2NO₂
The number of moles of either the reactants or the products can be calculated stoichiometrically as follows:
Based on the above chemical equation, 1 moles of NO₃ reacts to form 2 moles of NO₂.
This means that if 10.2 moles of NO₃ reacts, 10.2 × 2 = 20.4 moles of NO2 will be produced.
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IF 23 g of FeCl2 reacts with 41g Na3PO4 what is the limiting reactant?
First, we need to figure the reaction out.
Both reactants are ionic compounds, so their reaction is probably a double displacemente reaction.
The Cl has a charge of 1-, so Fe has a charge of 2+. Na has a charge of +1 and PO₄ has a charge of 3-.
To combine Fe²⁺ with PO₄³⁻, we will need 3 Fe²⁺ and 2 PO₄³⁻, so the compound becomes neutral.
Both Na and Cl have single charge, so their combination is simply 1 Na and 1 Cl.
So, the products are Fe₃(PO₄)₂ and NaCl, so the unbalanced reaction is:
[tex]FeCl_2+Na_3PO_4\to Fe_3(PO_4)_2+NaCl[/tex]To balance it, We can start by putting a coefficient of 2 on Na₃PO₄, so we have two PO₄³⁻ anions on both sides:
[tex]FeCl_2+2Na_3PO_4\to Fe_3(PO_4)_2+NaCl[/tex]Now, we put a coefficient of 3 on FeCl₂ and 6 on NaCl to get the balanced equation:
[tex]3FeCl_2+2Na_3PO_4\to Fe_3(PO_4)_2+6NaCl[/tex]Now, we first need to calculate the number of moles of each reactant, using their molar masses:
[tex]\begin{gathered} M_{FeCl_2}=1\cdot M_{Fe}+2\cdot M_{Cl}=(1\cdot55.845+2\cdot35.453)g/mol=126.751g/mol \\ M_{Na_3PO_4}=3\cdot M_{Na}+1\cdot M_P+4\cdot M_O=(3\cdot22.98976928+1\cdot30.973762+4\cdot15.9994)g/mol=163.94066984g/mol \end{gathered}[/tex]So:
[tex]\begin{gathered} M_{FeCl_{2}}=\frac{m_{FeCl_2}}{n_{FeCl_{2}}} \\ n_{FeCl_2}=\frac{m_{FeCl_2}}{M_{FeCl_{2}}}=\frac{23g}{126.751g/mol}=0.181458\ldots mol \end{gathered}[/tex][tex]\begin{gathered} M_{Na_3PO_4}=\frac{m_{Na_3PO_4}}{n_{Na_{3}PO_{4}}} \\ n_{Na_3PO_4}=\frac{m_{Na_3PO_4}}{M_{Na_{3}PO_{4}}}=\frac{41g}{163.9406698g/mol}=0.250090\ldots mol \end{gathered}[/tex]Now, if the coefficient of FeCl₂ is 3, for each 3 FeCl₂ that reacts, one reaction occurs, so the number of reactions that will need to occur to consume all its number of moles is that amount over 3:
[tex]n_{\text{reaction}}=\frac{n_{FeCl_2}}{3}=\frac{0.181458\ldots mol}{3}=0.060486\ldots mol[/tex]Similarly, we get the number of reactions that would occur if all Na₃PO₄ reacts by dividing its number of moles by its coefficient, that is 2:
[tex]n_{\text{reaction}}=\frac{n_{Na_3PO_4}}{2}=\frac{0.250090\ldots mol}{2}=0.125045\ldots mol[/tex]This means that the amount we have of FeCl₂ is enough for only about 0.0605 mol of reactions while the amount we have of Na₃PO₄ is enought for about 0.1250 mol of reactions, which is more than the other reactant.
This means that the reactant that limits the amount of reaction that can occur is FeCl₂, so the limiting reactant is FeCl₂.
This is the correct Lewis structure for the molecule C2H2Cl2?
True or false
Answer: It is false
Explanation:
Calculate the gram molecular masses of the following species and label those that are compounds: H2O (water), C12H22O11 (table sugar), ---(C3H6)1000--- (polypropylene plastic), S6 (sulfur powder), Al2O3 (aluminum oxide), CHCl3 (chloroform).
The gram molecular masses of the following species are
H₂O is a compound.
molecular mass H₂O :
mass of hydrogen = 1 g/mol
mass of oxygen = 16 g/mol
molecular mass of H₂O = 2 × 1 + 16
= 18 g/mol
C₁₂H₂₂O₁₁ is a compound.
mass of carbon = 12 g/mol
mass of hydrogen = 1 g/mol
mass of oxygen = 16 g/mol
molecular mass of C₁₂H₂₂O₁₁ = 12 × 12 + 22 × 1 + 11 × 16
= 144 + 22 + 176
= 342 g/mol
-----(C₃H₆)₁₀₀----- Polypropylene is a compound.
mass of carbon = 12 g/mol
mass of hydrogen = 1 g/mol
molecular mass of -----(C₃H₆)₁₀₀₀----- = (3 × 12 + 6 × 1 ) × 1000
= 42000 g/mol
Al₂O₃ ( aluminum oxide ) is chemical compound.
mass of aluminum = 27 g/mol
mass of oxygen = 16 g/mol
molecular mass = 2 × 27 + 3 × 16
= 102 g/mol
S₆ (sulfur powder)
mass of sulfur = 32 g/mol
molar mass of = 6 × 32
= 192 g/mol
CHCl₃ ( chloroform) is a compound
mass of carbon = 12 g/mol
mass of hydrogen = 1 g/mol
mass of chlorine = 35 g/mol
molar mass of CHCl₃ = 12 + 1 + 3 × 35
= 119 g/mol
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Phillip wants to teach his brother that the Sun gives off heat energy. What can Phillip tell his brother to demonstrate that the Sun has heat energy?
Responses
A It easier to see during the day than at night.It easier to see during the day than at night.
B Ice cream melts faster outside on a sunny day.Ice cream melts faster outside on a sunny day.
C It is warmer inside the house than outside.It is warmer inside the house than outside.
D Sunglasses help keep the light out of your eyes.
Draw the Lewis structure of Ch3Br. Include lone pairs of electrons
For a structure of the CH3Br structure, see attached image.
A covalent compound is represented by a lewis structure structure, in which valence electrons, lone pairs, and bonding electrons are represented by dots. Sir G.N. Lewis first described the method in his 1916 article "Atom and Molecule."
They are also known as molecular dot electron diagrams. The CH3Br molecule has fourteen electrons in total. As may be plainly seen in the attached image, each element's atom is surrounded by dots to represent its valence electrons.
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Is crude oil and fossil fuel same?
Answer:
yess Petroleum—or crude oil—is a fossil fuel that is found in large quantities beneath the Earth's surface and is often used as a fuel or raw material in the chemical industry.
hey bro how are you??
Aqueous hydrochloric acid (HCI) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H₂O).Suppose 1.46 g of hydrochloric acid is mixed with 2.9 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 3 significant digits.
PLEASE HELP SOLVE
The balanced chemical equation for this reaction is:
HCl + NaOH = NaCl + H2O
1.46 g of HCl is equal to 0.0400 moles of HCl. (1.46/36.458). (36.485 being the molar mass of HCl in grams/mole).
2.9 g of NaOH is equal to 0.0725 moles of NaOH. (2.9/39.997). (39.997 being the molar mass of NaOH in grams/mole).
- From the reaction we can infer that it takes one mole of HCl and one mole of NaOH to form one mole of water. Therefore the limiting reactant in this case will simply be the one that we have the least amount of. So HCl is the limiting reactant.
- As stated previously, it takes one mole of HCl to produce one mole of H2O so that would mean that 0.0400 moles of HCl would produce 0.0400 moles of H2O.
0.0400*18.01 (18.01 being the molar mass of water in grams/mole) will give you the grams of H2O produced in this reaction.
Answer: 0.720 grams of H2O