What is the common difference between successive terms in the sequence? 2, 8, 14, 20, 26,. –6 –4 4 6.

Answer:

0.09

.............................

The shopkeeper had brought the fan at Rs.1350

Answer:

89

Step-by-step explanation:

8, 8, 12, 41, 64, 97

We can clearly see that our highest value is 97, and our lowest in 8.

Answer:

it's c

Step-by-step explanation:

Answer: it is c

Step-by-step explanation:

i took the test it was right<3

brainiest please and thx :)

The equivalent function of f(x) = 16x^2 - 1 is f(x) = (4x  + 1)(4x -1)

The function is given as:

f(x) = 16x^2 - 1

Express 16 as 4^2 and 1 as 1^2

f(x) = (4x)^2 - 1^2

Apply the difference of two squares

f(x) = (4x  + 1)(4x -1)

Hence, the equivalent function of f(x) = 16x^2 - 1 is f(x) = (4x  + 1)(4x -1)

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Answer:

17 games

Step-by-step explanation:

There are 68 games in total. Assuming that the number of games watched are equally divided between 4 people, then each person watches 68/4 = 17 games.

Answer:

ai = 190.0

Step-by-step explanation:

I'll presume the sequence is arithmetic, simply because assuming the series is mathematical, there is more than one solution.

Assuming the series is comprised of numbers in an arithmetic progression, you will have...  (see attachment for better explanation and step by step.)

Answer:

y = -x/2 + 2

what are those mutli choice answers?

if that point is (6,1)

y = -x/2 + 4

Step-by-step explanation:

the perpendicular line has a gradient which is the negative inverse, that is -1/m

so the equation will be of the form y = -x/2 + c

substituting in the point (6, -1)

-1 = -6/2 + c

c = 2

so y = -x/2 + 2

i could say you are correct.

 kaii~ <3

The perimeter of the cross section formed is 44.22 in.

The area of the cross section formed is 72.44 in.²

From the question, we are to determine the perimeter and area of the cross section formed by the cut

As indicated in the diagram,

If the wood is cut along the indicated diagonal, the cross section formed is a rectangle whose length will be the length of the diagonal and its width will be 4 in.

Now, we will calculate the length of the diagonal,

Let the diagonal be d

Then, we can write that

d² = 2² + 18²

d² = 4 + 324

d² = 328

d = 18.11 in.

Thus,

The length of the rectangular cross-section is 18.11 in.

Now, using the formula for calculating the perimeter of a rectangle

P = 2(l +w)

Where P is the perimeter

l is the length

and w is the width

For the rectangular cross-section

l = 18.11 in.

w = 4 in.

Putting the parameters into the formula,

P = 2(18.11 + 4)

P = 2(22.11)

P = 44.22 in.

∴ The perimeter of the cross section formed is 44.22 in.

For the area of the cross section

Using the formula for calculating the area of a rectangle,

A = l × w

∴ Area of the cross section formed = 18.11 × 4

Area of the cross section formed = 72.44 in.²

Hence, the area of the cross section formed is 72.44 in.²

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The percentage of 4c in the expression 0.2c is 2000%

The expression is given as:

0.2c

The percentage of 4c is then calculated as:

4c/0.2c

Evaluate the quotient

20

Express as percentage

2000%

Hence, the percentage of 4c in 0.2c is 2000%

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Answer:

250 $3 tickets and 100 $2 tickets were sold.

Step-by-step explanation:

easy :)

Answer:

See below ~

Step-by-step explanation:

Using translation concepts, it is found that the following rule is applied to each point:

(x,y) -> (x,-y).

The point that is does not result from this transformation will not be one of the new coordinates.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

When a function is reflected over the x-axis, it's output is multiplied by -1, hence the rule is given by:

(x,y) -> (x,-y).

Thus, this rule is applied to all points, which are A, B, C and D, and the point that is does not result from this transformation will not be one of the new coordinates.

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Step-by-step explanation:

I assume the 2 vertical lines are parallel.

then the 2 angles 5x and 4x are around the intersection point of both lines (since parallel lines simply mimic the behavior of each other, the angles must be the same).

that means 4x is also the angle under the indicated 5x angle, and 5x is also the angle under the indicated 4x angle.

and that simply means that 5x and 4x supplement each other to 180° (as all angles around a single point on one side of a line represent a half-circle and therefore 180°).

so,

5x + 4x = 180

9x = 180

x = 20

Answer:

a. sides BC & EF

b. <A & <D

2a. A / B, not that sure

Answer:

∠1 and ∠8 are alternate exterior angles which is when two parallel lines are intersected by a transversal, then the exterior angles formed on either side of the transversal are (their measures are) equal.

Simple terms: 1 and 8 are the same angle

Answer:

n-p for the first, p-n for the second

Step-by-step explanation:

Answer:

[tex]y=2x+3[/tex]

Step-by-step explanation:

Sure hope this helps you

Answer:

$ 10 021 . 65

Step-by-step explanation:

The equation for continuous compounding is   e^(i * t)

   where i = decimal yearly  interest      t = years

   FV  = 5500 e^(.12 * 5) = 10 021 .65

Answer:

The range of the function is [0 , ∞) ⇒ answer B. Step-by-step explanation: * lets revise the meaning of the domain and the range - The domain is the values of x - The domain is all the values of x which make the function is defined - If there are some values of x make the function undefined, we exclude these values from the domain

Step-by-step explanation:

For the form [tex]y = a(x-h)^2 + k[/tex], the vertex has coordinates (h, k). The vertex is found by (x, y).

If a quadratic equation is written in the form

[tex]y=a(x-h)^2 + k[/tex]

then it is called to be in vertex form.

It is called so because when you plot this equation's graph, you will see vertex point(peak point) is on (h,k)

First of all, we used this vertex formula thing since it is visible that there are quadratic functions.

Otherwise, you had to use calculus to get critical points, then a second derivative of functions to find the character of critical points as minima or maxima or saddle, etc to get the location of vertex point.

This point (h,k) is called the vertex of the parabola that the quadratic equation represents.

For the form

[tex]y = a(x-h)^2 + k[/tex], the vertex has coordinates (h, k)

Thus, for the obtained form, we get the coordinates of the vertex as:

[tex]h = -b/2a,, \\ k = c - a\times(b/2a)^2[/tex]

Thus, the coordinates of vertex of  [tex]y = ax^2 + bx + c[/tex]is:

[tex](h,k) = (-b/2a, c - a \times (b/2a)^2 )[/tex]

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Answer:

x = 15

Step-by-step explanation:

45/3 = 15

Answer:

The inequality for this diagram is x≥-1

Please the explanation... it always helpsssss....

Step-by-step explanation:

The first step is to look at the circle... is it filled in or not... in this case it is...

meaning the symbol is greater than or equal to  OR less than or equal to

next the arrow is pointing to the right meaning the symbol must be greater than or equal to

then look at the value at the filled in circle (which in this case is -1)

meaning the inequality must be x≥-1

i really hope this helps!!!!

Answer:

The formula for volume is V=l*w*h

(6×4×2)×2=96 cubic feet

Answer:

The winter evening settles down

With smell of steaks in passageways.

Six o'clock.

The burnt-out ends of smoky days.

And now a gusty shower wraps

The grimy scraps

Of withered leaves about your feet

And newspapers from vacant lots;

The showers beat

On broken blinds and chimney-pots,

And at the corner of the street

A lonely cab-horse steams and stamps.

And then the lighting of the lamps.

Alfred Tennyson - Summer Night

Alfred Tennyson was another poet who made great use of visual imagery. See if you can get a clear picture of the summer night he describes in this poem "Summer Night:"

Now sleeps the crimson petal, now the white;

Nor waves the cypress in the palace walk;

Nor winks the gold fin in the porphyry font:

The firefly wakens: waken thou with me.

Now droops the milk-white peacock like a ghost,

And like a ghost she glimmers on to me.

Now lies the Earth all Danaë to the stars,

And all thy heart lies open unto me.

Now slides the silent meteor on, and leaves

A shining furrow, as thy thoughts in me.

Now folds the lily all her sweetness up,

And slips into the bosom of the lake.

So fold thyself, my dearest, thou, and slip

Into my bosom and be lost in me.

William Wordsworth - I Wandered Lonely as a Cloud

Next is an excerpt from "I Wandered Lonely as a Cloud" by William Wordsworth. The first and last stanzas show a progression of the poet's emotions using visual imagery.

I wandered lonely as a cloud

That floats on high o'er vales and hills,

When all at once I saw a crowd,

A host, of golden daffodils;

Beside the lake, beneath the trees,

Fluttering and dancing in the breeze.

For oft, when on my couch I lie

In vacant or in pensive mood,

They flash upon that inward eye

Which is the bliss of solitude;

And then my heart with pleasure fills,

And dances with the daffodils.

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Theodore Rothke - My Papa’s Waltz

This famous poem by Theodore Rothke is an excellent example of olfactory and tactile imagery with plenty of visual imagery thrown in for good measure. The effect is powerful.

The whiskey on your breath

Could make a small boy dizzy;

But I hung on like death:

Such waltzing was not easy.

We romped until the pans

Slid from the kitchen shelf;

My mother’s countenance

Could not unfrown itself.

The hand that held my wrist

Was battered on one knuckle;

At every step you missed

My right ear scraped a buckle.

You beat time on my head

With a palm caked hard by dirt,

Then waltzed me off to bed

Still clinging to your shirt.

William Carlos Williams - This Is Just to Say

"This Is Just to Say" is an amazing example of gustatory imagery or imagery involving taste. There’s more going on beneath the surface of this poem, but the vivid description of taste draws the reader in.

I have eaten

the plums

that were in

the icebox

and which

you were probably

saving

for breakfast

Forgive me

they were delicious

so sweet

and so cold

Step-by-step explanation:

The computation of the word problem shows that the oranges that John will have in 12 weeks will be 70 oranges.

The word problem will be that John has 10 oranges and buys 5 more oranges every week. How many oranges will John have in 12 weeks?

The computation will be:

= 10 + 5x

where x= number of weeks.

= 10 + 5x

= 10 + 5(12)

= 10 + 60

= 70 oranges

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If donna didn't stop, her average speed for the final 30 miles to 2 dp is; 57.39 mph

We are given;

Distance travelled by Donna = 70 miles

Average Speed of Donna = 40 mph

Additional Distance travelled = 30 miles

Average speed for entire journey = 44 mph

We know that;

time = distance/speed

Thus

Total time = (70 + 30)/44

Total time = 100/44 h

Time 1 = 70/40 = 7/4 hr

Time 2 = 30/v

Thus;

30/v + 7/4 = 100/44

Multiply through by 44 to get;

1320/v = 100 - 77

v = 1320/23

v = 57.39 mph

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