Answer:
The distance is 0.96m
Explanation:
Given
m1= 900kg
m2= 1600kg
Force F= 0.0001nN
G=6.67430*10^-11 Nm^2/kg^2
Required
The distance r
Step two:
the formula for the force is given as
F = Gm1m2/r2
make r subject of the formula
[tex]r= \sqrt{\frac{Gm1m2}{F} }[/tex]
[tex]r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m[/tex]
Answer:
The distance is 0.96m
Explanation:
Given
m1= 900kg
m2= 1600kg
Force F= 0.0001nN
G=6.67430*10^-11 Nm^2/kg^2
Required:
The distance r
Step two:
the formula for the force is given as
F = Gm1m2/r2
make r subject of the formula
[tex]r= \sqrt{\frac{Gm1m2}{F} }[/tex]
[tex]r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m[/tex]
Answer:
The distance between the compact car and pickup truck is 0.96048 m
Explanation:
The gravitational force is directly proportional to the product of the masses of the interacting object, it is also inversely proportional to the square of the distance between them. This is shown in equation 1;
[tex]F =G \frac{m_{1} X m_{2} }{d^{2} }[/tex]............ 1
Where F is the gravitational force = 0.0001 N
G is the gravitational constant = 6.673 x [tex]10^{-11} Nm^{2} kg^{-2}[/tex]
[tex]m_{1}[/tex] is the mass of the compact car = 900kg
[tex]m_{2}[/tex] is the mass of the pickup truck = 1600kg
d is the distance and its unknown ?
Let us make d the subject formula in equation 1
[tex]d = \sqrt{G\frac{m_{1} m_{2} }{F } }[/tex] .... 2
Substituting into equation 2 we have
[tex]d = \sqrt{\frac{6.673x10^{-11} x 900 x 1600}{0.0001N} }[/tex]
d = 0.96048m
Therefore the distance between the compact car and pickup truck is 0.96048 m
Paco pulls a 67 kg crate with 738 N and of force across a frictionless floor 9.0 M how much work does he do in moving the crate
Answer:
W = 6642 J
Explanation:
Given that,
Mass of a crate, m = 67 kg
Force with which the crate is pulled, F = 738 N
It is moved 9 m across a frictionless floor
We need to find the work done in moving the crate. Let the work done is W. It is given by :
W = F d
W = 738 N × 9 m
= 6642 J
So, the work done is 6642 J.
Introduction to Simple Machines
This activity will help you meet this educational goal:
You will compare and contrast information from a video with information from a text.
Directions
Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write a brief evaluation of your work.
Activity
Watch this video and then answer the following questions based on what you learned.
Part A
How does a bicycle make work easier?
Part B
Which two examples of levers are mentioned in the video?
The picture shows a bicycle’s pedals. Look at the shaft that the pedals are attached to. Do you think the shaft is a lever? Why or why not?
Answer:
word for word answers!
Explanation:
1) Part A: By pedaling a bicycle lightly, the rider can go a long way
2) Part B: The two examples mentioned in the video are the handlebars and the brakes
3) Yes, it’s a type of lever because the two pedals rotate around a fixed point
The voltage provided by the battery of a circuit was 12 V, if the total
resistance in the circuit was 6 ohms, calculate the total current present.
options:
72 A
2A
0.5 A
7.2 A
Answer:
2 Amps
which agrees with the second option in the list of answers
Explanation:
Use Ohm's law:
V = R * I
which with the information given to us becomes:
12 = 6 * I
then solving for I we get:
I = 12 V / 6 Ω = 2 Amps
Two ice-skaters are skating in circles on a frozen pond. Maria is making large circles with a radius of 12 m and skating 4.5 m/s. Her friend, Samantha, is making smaller circles with a radius of 6 m but is not skating as quickly, going only 3.8 m/s. ii. How could each skater increase her centripetal acceleration without changing the size of her path? Explain your reasoning.
Answer:
v_maria > 4.5 m/s
v_samantha > 3.8 m/s
Explanation:
Formula for centripetal acceleration is;
a_c = v²/r
Where;
v is speed
r is radius
For Maria;
r = 12 m
v = 4.5 m/s
Thus;
a_c = 4.5²/12
a_c = 1.6875 m/s²
For Samantha;
r = 6
v = 3.8 m/s
Thus;
a_c = 3.8²/6
a_c = 2.41 m/s²
We want to find how could each skater increase her centripetal acceleration without changing the size of her path.
From the centripetal acceleration formula, since the size of path can't be changed it means the radius can't be changed and so the only thing that can now increase the centripetal acceleration is when the speed increases.
Thus;
For Maria, she has to move with a faster speed. Thus: v_maria > 4.5 m/s
For Samantha, she also has to move with a faster speed. Thus; v_samantha > 3.8 m/s
Object A has a mass of 2 kg; object B’s mass is 10 kg. If object B is at rest and object A runs into it at low speed, object B:
A. Will move off at high speed.
B. Cannot move off with high speed.
C. Will loose speed in the collision.
D. Will remain at rest.
Answer:
Cannot move off with high speed
Explanation:
Just did it
A 100 kg man stands still. Gravity pushes on him with an acceleration of 9.8 m/s^2. What it the force the man feels from gravity? *
0 N
98 N
90 N
980 N
Answer:
980 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 100 × 9.8
We have the final answer as
980 NHope this helps you
The glowing dot represents the transmission of a nerve impulse along the nerves that make up the neural pathway. A nerve impulse is an electrical signal that travels from one nerve cell to another.
Which part of the brain processes this signal?
Answer:
The answer is "Cerebral Cortex"
Explanation:
The neurotransmitter diffuses across the short distance of the synapse and ties to a receptor protein of the objective neuron. At the point when the sub-atomic sign ties to the receptor, the cell film of the objective neuron changes its electrical state and another evaluated expected starts. On the off chance that that evaluated potential is sufficiently able to arrive at limit, the subsequent neuron produces an activity potential at its axon hillock. The objective of this neuron is another neuron in the thalamus of the mind, the piece of the CNS that goes about as a transfer for tactile data.
At another neurotransmitter, synapse is delivered and ties to its receptor. The thalamus at that point sends the sensory information to the cerebral cortex, the furthest layer of dark issue in the brain, where cognizant view of that water temperature starts.
A region of the cortex is particular for imparting signs down to the spinal cord for development. The upper engine neuron is in this area, called the precentral gyrus of the frontal cortex, which has an axon that broadens right down the spinal cord. At the degree of the spinal cord at which this axon makes a neurotransmitter, a reviewed potential happens in the cell membrane of a lower engine neuron.
Describe how radiant energy, light energy, and solar energy are related. ( Please ❤️ )
Answer:
L’énergie solaire récolte l’énergie radiante portée par la lumière de notre soleil en la convertissant en électricité.Biomasse des plantes. Les plantes sont capables d’exploiter et d’utiliser l’énergie lumineuse dans un processus appelé photosynthèse.
Answer:
Radiant energy, light energy, and solar energy are related because The Sun produces a lot of radiant energy that is transmitted to Earth as light. Plants convert the electromagnetic energy in sunlight into chemical energy for their food, through a process called photosynthesis. Waves of radiant electromagnetic energy can be visible or invisible.
Explanation:
Students had two batteries and two different resistors. During four trials, they build four different circuits and measure the circuit’s current in Amps according to the following table.
Trial Number
Voltage (V)
Resistance (Ω)
Current (A)
1
1.5
200
2
1.5
100
3
3.0
200
4
3.0
100
For which trial would the students measure the smallest current in the circuit? (AKS 10a)
A.
Trial 1
B.
Trial 2
C.
Trial 3
D.
Trial 4
Answer:
bhi jo bhi of gp oh oh gi IG 7u to uff do if goo td to yd do FP ae rt 7g hi pic vo icon
Explanation:
bh hi h bhi vc di oh x At jb jo iv hp of di of dr hi o hc x gh ki vc hi jo
Under state law, what is the blood-alcohol limit for legally operating a motor vehicle?
Answer:
HOPE IT HELPS.....
Explanation:
The legal standard for drunkenness across the United States ranges from 0.10 to 0.08. If a person's BAC measures 0.08, it means that there are 0.08 grams (i.e., 80 mg) of alcohol per 100 ml of blood. The American Medical Association says that a person can become impaired when the blood alcohol level hits 0.05.
Answer: 0.08
Driving While Intoxicated or Impaired is Illegal
Under Michigan law, it is illegal to drive: While intoxicated, or impaired, by alcohol, controlled substance, or other intoxicating substance. With a bodily alcohol content of 0.08 or more. (This crime is one of the driving while intoxicated offenses.)
Hope this helps... Stay safe and have a Merry Christmas!!!!!!!! :D
which of the following is true of phototsythesis but not of cellular respiration.
A- Photosynthesis releases oxygen gas as a product
B- Photosynthesis occurs in all organisms
C- Photo synthesis is a process in which glucose i broken down
D- Photosynthesis requires glucose as a reactant
Answer:
B. Photosynthesis occurs in all organisms
Hope this helps!! :)
A string with mass per unit length of 0.003 kg/m is plucked with an amplitude of 2 cm. The string is 30 cm long, and under a tension of 30 newtons. What are the frequencies of the first 5 harmonics?
Answer:
First harmonics = 333.33N
Second harmonics = 500.01N
Third harmonics = 666.68N
Fourth harmonics = 833.35N
Fifth harmonics = 1000.02N
Explanation:
The formula for calculating the fundamental frequency in string is expressed as;
[tex]F_0 = \frac{1}{2L}\sqrt{\frac{T}{m} }[/tex] where;
L is the length of the string = 30cm = 0.3m
T is the tension in the string = 30N
m is the mass per unit length of the string = 0.003kg/m
Get the fundamental frequency first by substituting the given values into the formula;
[tex]F_0 = \frac{1}{2(0.3)}\sqrt{\frac{30}{0.003} }\\F_0 = \frac{1}{0.6}\sqrt{10,000}}\\F_0 = \frac{1}{0.6} * 100\\[/tex]
F0 = 166.67N
Harmonics are the integral multiples of the fundamental frequency.
First harmonics F1 = 2F0 = 2(166.67) = 333.33N
Second harmonics F2 = 3F0 = 3(166.67) = 500.01N
Third harmonics F3 = 4F0 = 4(166.67) = 666.68N
Fourth harmonics F4 = 5f0 = 5(166.67) = 833.35N
Fifth harmonics F5 = 6f0 = 6(166.67) = 1000.02N
What is the minimum work done by the heart to pump 130 g of blood from a person's foot to his heart 1.5 m away?
A. 0J.B. 4.7J.C. .47J.D. 4700J.
Answer:
The minimum work done by the heart is 1.911 J
Explanation:
Given;
mass of the blood, m = 130 g = 0.13 kg
height the blood is pumped, h = 1.5 m
Apply work energy theorem, the gravitational potential energy of the height in which the blood is pumped to, is equal to the work done in pumping the blood form the foot to the heart.
E = mgh = W
where;
g is acceleration due to gravity = 9.8 m/s²
W = (0.13)(9.8)(1.5)
W = 1.911 J
Thus, the minimum work done by the heart is 1.911 J
Pretty simple physics :) will give brainliest
pls dont just use me for points
Answer:
meter per second(m/s)
Explanation:
If a body having mass 40kg started moving initially with rest and it takes a velocity of 20m/sec in time 4 seconds. Find the value of force
[tex]{\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{Mass \ of \ the \ body \ (m) = 40 \ kg}[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{Final \ velocity \ of \ the \ body \ (v) = 20 \ m/s}[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{Initial \ velocity \ of \ the \ body \ (u) = 0}[/tex]
[tex]\\[/tex]
[tex]{\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{Force \ exerted \ by \ the \ body \ ( F)}[/tex]
[tex]\\[/tex]
[tex]{\mathfrak{\underline{\purple{\:\:\: Solution:-\:\:\:}}}} \\ \\[/tex]
☯ Using 1st equation of motion
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{v = u + at}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{20 = 0 + a(4)}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{20 = 4a}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{\dfrac{\cancel{20}}{\cancel{4}} = a}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{a = 5}[/tex]
[tex]\\[/tex]
☯ Now, Finding the force exerted
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{F = ma}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{F = 40 \times 5}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{F = 200 \ N}[/tex]
[tex]\\[/tex]
☯ Hence, [tex]\\[/tex]
[tex]\:\:\:\:\star\:\:\:\sf{The \ force \ exerted \ by \ the \ body \ is \ 200N}[/tex]
on the moon which object would fall with the same acceleration?
Answer:
Since there is no air resistance on the Moon, all objects would be in free fall at 1.6 m/s2. This means that they would all hit the ground at the same time if released simultaneously from the same height, but at a slower speed compared to objects free falling in a vacuum on Earth.
Explanation:
You throw a baseball (mass 0.145 kg) vertically upward. It leaves your hand moving at 12.0 m/s. Air resistance can be neglected.
A. At what height above your hand does the ball have half as much upward velocity?
B. At what height above your hand does the ball have half as much kinetic energy as when it left your hand?
Answer:
Explanation:
A ) initial velocity u = 12 m /s
final velocity v = 6 m /s
height = h
acceleration = - g = - 9.8 m /s²
v² = u² - 2gh
6² = 12² - 2 x 9.8 x h
h = 5.51 m
B )
Let the final velocity when energy becomes half be V at height H
kinetic energy at height h = 1/2 m V²
Given ,
.5 x 1 / 2 m x 12² = 1/2 m x V²
V² = 12² / 2
V = 8.486 m /s
V² = u² - 2 gH
8.486² = 12² - 2 x 9.8 x H
H = 3.67 m .
find the vector parallel to the resultant of the vector A=i +4j-2k and B=3i-5j+k
Answer:
2008
Explanation:
2000+3+5======2008
Answer:
[tex]8\hat i-2\hat j-2\hat k[/tex]
Explanation:
Vectors in 3D
Given a vector
[tex]\vec P = P_x\hat i+P_y\hat j+P_z\hat k[/tex]
A vector [tex]\vec Q[/tex] parallel to [tex]\vec P[/tex] is:
[tex]\vec Q = k.\vec P[/tex]
Where k is any constant different from zero.
We are given the vectors:
[tex]\vec A = \hat i+4\hat j-2\hat k[/tex]
[tex]\vec B = 3\hat i-5\hat j+\hat k[/tex]
It's not specified what the 'resultant' is about, we'll assume it's the result of the sum of both vectors, thus:
[tex]\vec A +\vec B = \hat i+4\hat j-2\hat k + 3\hat i-5\hat j+\hat k[/tex]
Adding each component separately:
[tex]\vec A +\vec B = 4\hat i-\hat j-\hat k[/tex]
To find a vector parallel to the sum, we select k=2:
[tex]2(\vec A +\vec B )= 8\hat i-2\hat j-2\hat k[/tex]
Thus one vector parallel to the resultant of both vectors is:
[tex]\mathbf{8\hat i-2\hat j-2\hat k}[/tex]
Which of the following statements are true of cancer types? Check all that apply. --
- Cancer is named according to the color the cells turn.
- Skin cancer is considered a very common type of cancer.
- Cancer is often named according to what body type it affects.
- Skin cancer is the least common type of cancer.
the answer is cancer is often named according to what body type it affects
Answer:
B,C
Explanation:
skin cancer is considered a very common type of cancer. Cancer is often named accordingly to a body type it affects.
A fluid of density rho = 900 kg/m3 flows along a pipe of constant diameter from point A to point B. Gauge pressure at point A is equal to zero, and absolute pressure at point B is 30% lower than pressure at point A. What is the height difference, Δh, between points A and B?
a. Δh = 8.09 m with point A above point B.
b. Δh = 344 m with point B above point A.
c. Δh = 303 m with point B above point A.
d. Δh = 3.44 m with point A above point B.
The height difference between points A and B is : ( B ) Δh = 3.44 m with point B above point A.
Given data :
fluid density = 900 kg/m³
Diameter of pipe = constant
Gauge pressure at Point A = 0
Gauge pressure at point B = 30% lower
Determine the height difference between points A and Bfirst step : determine absolute pressure
Pa (absolute pressure )= gauge pressure + atmospheric pressure
= 0 + patm
Therefore : Pa = Patm
Also;
Pressure at point B ( Pb ) = Pa - 30%Pa
= 0.7 Patm
Hence ; Pa - Pb = 0.3 Patm ----- ( 1 )
Final step : Determine the height difference
we will apply the formula below from equation ( 1 )
p *g * Δh = 0.3 * 1.013 * 10⁵ ( note : Patm = 1.013 * 10⁵ )
900 * 9.81 * Δh = 0.3 * 1.013 * 10⁵
therefore :
Δh = ( 0.3 * 1.013 * 10⁵ ) / ( 900 * 9.81 )
= 3.44 m
Hence we can conclude that The height difference between points A and B is Δh = 3.44 m with point B above point A.
Learn more about height difference in fluids : https://brainly.com/question/17200230
A solid CUBE has a side of 4cm and is 192 grams in mass. What is the density?
Answer:
3g/cm³
Explanation:
Given parameters:
Length of the side = 4cm;
Volume of the cube = L³ = 4³ = 64cm³
Mass of the cube = 192g
Unknown:
Density = ?
Solution:
The density of a body is its mass per unit volume;
Density = [tex]\frac{mass}{volume}[/tex]
Insert parameters and solve;
Density = [tex]\frac{192}{64}[/tex] = 3g/cm³
_____ are group of tissue working together to perform a certain job.
Answer:
organ
Explanation:
Answer:
an organ
Explanation:
cell -> tissue -> organ -> organ system -> organism
What is the initial vertical velocity of the ball?
A.
0 m/s
B.
9.81 m/s
C.
20.0 m/s
D.
60.0 m/s
When liquid water gets into cracks of rock and freezes, it __ and ___.
When weather predictions are incorrect what is the most likely cause
A: measurements of the initial conditions may have been very in accurate
B: small differences in models can lead to large differences in complex systems
C: The person predicting the weather may have had a bias
D: The elevation of different landforms I have been significantly in accurate
Answer:small differences in models can lead to large differences in complex systems
Explanation: this is the most accurate phrase
A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. How high did the cannonball travel?
9935 m
11454 m
754 m
13200 m
A scientist who wants to study the affects of fertilizer on plants sets up an experiment. Plant A gets no fertilizer, Plant B gets 5 milligrams of fertilizer, and Plant C gets 10 milligrams of fertilizer. Which plant is the control group in this experiment?
Answer: Plant A
Explanation: The control group is participants who do not receive the experimental treatment.
What is the approximate distance from the sun to the astroid belt?
Answer:
The asteroid belt lies between 2.2 and 3.2 astronomical units (AU) from our sun. ( i looked this up because nobody of the top of their head knows this)
Explanation:
Changing which factor would NOT have an influence on the kinetic energy of a moving van loaded with 100 kg bags mulch of with a total mass of 1,500 kg. The vehicle is traveling across an open parking lot at a speed of 5 m/s.
Question 8 options:
A: direction the moving van is going across the parking lot.
B: increasing the rate of speed without altering the mass of the vehicle or its contents.
C: emptying the moving van one bag at a time at a constant rate.
D: adding more contents (increasing the overall mass) to the van while the van is in motion traveling 5 m
Answer:
A. The direction
Explanation:
I did the test lol
Answer:
A
Explanation:
i took the test
what is the need of force in our life
Answer:
A force is a push or a pull and it affects our daily lives because without force,people would not be able to open and close stuff or lift up our arms or legs .....or anything, for that matter.
Explanation:
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