Answer:
I dont know to be honest
Explanation:
i dont know to be honest
Which identifies the energy transformations that take place in Anna’s body as this process takes place?
Mechanical energy is converted to kinetic energy, which is then converted to potential energy.
Chemical energy is converted to thermal energy and electrical energy.
Electrical energy is converted to chemical energy and thermal energy.
Mechanical energy is converted to potential energy which is then converted to kinetic energy.
Answer:
Chemical energy is converted to thermal energy and electrical energy.
Explanation:
Answer:
Which identifies the energy transformations that take place in Anna’s body as this process takes place?
Mechanical energy is converted to kinetic energy, which is then converted to potential energy.
*******Chemical energy is converted to thermal energy and electrical energy. *******CORRECT*******
Electrical energy is converted to chemical energy and thermal energy.
Mechanical energy is converted to potential energy which is then converted to kinetic energy.
Explanation:
Feb 2021 Edge 100% test
Which type of matter is likely to absorb the most sound waves? A. Metal door B. Loudspeaker C. Hot air O D. Foam wall
Answer:
its either A or D
Explanation:
They use foam walls in like asylums but in the movies all the bad guys say "They can't hear you the metal is too thick" so its either one of those, hope it helped
Sound absorbing foams are typically softer and more lightweight than their sound blocking counterparts. This open and flexible cell structure acts as a natural soundwave absorber and prevents noises from reverberating off hard surfaces like walls, floors and ceilings.
What are sound waves ?"A sound wave is the pattern of disturbance caused by the movement of energy traveling through a medium (such as air, water, or any other liquid or solid matter) as it propagates away from the source of the sound. The source is some object that causes a vibration, such as a ringing telephone, or a person's vocal chords."
What is sound ?"Sound is a vibration that propagates as an acoustic wave, through a transmission medium such as a gas, liquid or solid. In human physiology and psychology, sound is the reception of such waves and their perception by the brain."
What is noise ?Sound is defined as vibrations that travel through air or another medium that can be heard when they reach a person's or animal's ears. Noise is defined as unwanted sound. In engineering, noise has the additional connotation of signals varying over time without meaning, whereas sound connotes meaningful signals.
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A dependent variable is associated mainly with:
O A. the result of an experiment.
O B. the treatment group.
O C. the treatment in an experiment.
O D. the experimental group.
The experimental group and treatment group are the same group. It's just two different names for the same thing. If you apply a treatment to a group, then that's where you're performing the experiment.
For instance, if you are testing a fertilizer, then the independent variable would be "use of fertilizer or not using fertilizer". So that means the control group doesn't get any fertilizer. The dependent variable would be the heights of the plants between the two groups, so we can see if the fertilizer has an effect or not. This is the result of the experiment. So in other words, the input is the fertilizer (or no fertilizer), and the output is measuring the heights of the plants. The output is the result we analyze.
Keep in mind that the heights of the plants are likely to be randomly distributed. So this is where statistics comes into play. If the plants grow due to some random chance, and not necessarily the fertilizer, then you can use the control group to determine if that's the case or not. The control group helps you do this comparison.
As the name implies, "dependent" means it relies on something else. The height of the plant relies on if you used fertilizer or not. The independent variable is able to change without relying on any other variable.
A bowling ball of 35.2kg, generates 218 kg.m/s units of momentum. What is the velocity of the bowling ball?
Answer:
[tex]6.18\:\mathrm{m/s}[/tex]
Explanation:
The momentum of an object is given by [tex]p=mv[/tex].
Plugging in values, we have:
[tex]218=35.2v,\\v=\frac{218}{35.2}=\fbox{$6.18\:\mathrm{m/s}$}[/tex].
Please help I’ll give you brain
Answer:
Explanation:
distance (km)
a) As near as I can tell from the graph, the distance travelled was 4km
b) I would answer 40 minutes, but don't be surprised if your instructor says 30 minutes.
c) The average speed is 4 km/40 minutes = 0.1 km/minute
From the poem Black woman what does it mean by Savannah stretching to clear horizons, Savannah shuddering beneath the East wind's eager caresses.
Answer:
From the poem Black woman what does it mean by Savannah stretching to clear horizons, Savannah shuddering beneath the East wind's eager caresses.
Explanation:
Please help i will give brainliest
Answer:
Answers below--
Explanation:
1. F/Force
2.H/Contact force
3.A/Non-contact force
4.C/electric force
5.D/gravity
6.I(i)/magnetic force
7.J/kilogram
8.G/newton
9.B/friction
10.E/lubricant
1. Which of these is not a property of a soun wave? A. Elasticity B. Loudness C. Pitch
Answer:
A
Explanation:
A patient arrives at an emergency room complaining of pain in her ankle. The nurse examines the patient’s ankle, looking for skin discoloration or swelling. The nurse is relying mostly on his knowledge of
Answer:
Superficial anatomy.
Explanation:
Superficial anatomy can be defined as the physical examination of the external parts of a living organism such as ankle, nose, skin, knee, toes, fingers, cornea etc.
Hence, superficial anatomy is also popularly referred to as surface anatomy.
In this scenario, a patient arrives at an emergency room complaining of pain in her ankle. The nurse examines the patient’s ankle, looking for skin discoloration or swelling. The nurse is relying mostly on his knowledge of superficial anatomy by studying or examining the patient's ankle for any sign of decoration or swelling on the skin.
An airplane is traveling at a speed of 200 m/s relative to the Earth. A person walks toward the front of the plane at a speed of 1 m/s. How fast is that person traveling in reference to the other people on the plane?
Answer:
1 m/s
Explanation:
This is because, everybody in the plane including the person walking is moving at the speed of the plane which is 200 m/s. Now, when the person starts to walk with a speed of 1 m/s, his relative velocity to the other passengers is 1 m/s since he is already moving at the speed of the plane before starting to walk.
His velocity relative to the ground V' = velocity of plane relative to ground, V + velocity of person relative to plane, v
V = 200 m/s and v = 1 m/s
So, V' = 200 m/s + 1 m/s = 201 m/s
Since the velocity of the other passengers is the velocity of the plane, V = 200 m/s. The velocity of the person traveling in reference to the other people on the plane is V" = V' - V = 201 m/s - 200 m/s = 1 m/s
how is velocity ratio of wheel and axle calculated
Answer:
VR = [tex]\frac{Radius of the wheel}{Radius of the axle}[/tex]
Explanation:
Velocity ratio (VR) of a machine is a term that compares the distance moved by effort put into the machine to the distance moved by the load.
A wheel and axle is a device for lifting of a load through a height. It is made up of two circular parts called wheel and axle. Its velocity ratio (VR) can be determined by:
VR = [tex]\frac{Radius of the wheel}{Radius of the axle}[/tex]
For a practical wheel and axle, the diameter of the wheel is greater than the diameter of the axle.
What is common between transverse waves and longitudinal waves?
Both include an amplitude, crest, and rarefactions
Both move faster at higher temperatures
Both move slower through densely packed molecules
Both include a wavelength from compression to compression
Answer:
b
Explanation:
i took the quiz
Both the transverse and longitudinal waves move faster at higher temperatures.
What is meant by transverse wave?A wave in which the motion of the particles is perpendicular to the direction of the wave propagation is referred to as a transverse wave.
Here,
As a result of the shear stress that is produced, transverse waves are frequently observed in elastic materials.
In this situation, the oscillations are caused by the displacement of the solid particles from their relaxed state in directions perpendicular to the wave's propagation.
The wave in which the particles of the medium oscillate parallel to the direction of propagation of the wave is called a longitudinal wave.
Sound waves similarly oscillate parallel to the direction of propagation, forming the compressions and rarefactions. Hence sound waves are called longitudinal waves.
Hence,
Both the transverse and longitudinal waves move faster at higher temperatures.
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2200 kg semi truck driving down the highway has lost control. The truck rolls across the median and into oncoming traffic. The truck collides with a 2000 kg car that is traveling north at 45 m/s. The two vehicles stick together creating a single wreck that travels south at 15 m/s. what was the initial speed and direction of the semi truck?
Answer:
The semi truck travels at an initial speed of 69.545 meters per second downwards.
Explanation:
In this exercise we see a case of an entirely inellastic collision between the semi truck and the car, which can be described by the following equation derived from Principle of Linear Momentum Conservation: (We assume that velocity oriented northwards is positive)
[tex]m_{S}\cdot v_{S}+m_{C}\cdot v_{C} = (m_{S}+m_{C})\cdot v[/tex] (1)
Where:
[tex]m_{S}[/tex], [tex]m_{C}[/tex] - Masses of the semi truck and the car, measured in kilograms.
[tex]v_{S}[/tex], [tex]v_{C}[/tex] - Initial velocities of the semi truck and the car, measured in meters per second.
[tex]v[/tex] - Final speed of the system after collision, measured in meters per second.
If we know that [tex]m_{S} = 2200\,kg[/tex], [tex]m_{C} = 2000\,kg[/tex], [tex]v_{C} = 45\,\frac{m}{s}[/tex] and [tex]v = -15\,\frac{m}{s}[/tex], then the initial velocity of the semi truck is:
[tex]m_{S}\cdot v_{S} = (m_{S}+m_{C})\cdot v -m_{C}\cdot v_{C}[/tex]
[tex]v_{S} = \frac{(m_{S}+m_{C})\cdot v - m_{C}\cdot v_{C}}{m_{S}}[/tex]
[tex]v_{S} = \left(1+\frac{m_{C}}{m_{S}} \right)\cdot v - \frac{m_{C}}{m_{S}} \cdot v_{C}[/tex]
[tex]v_{S} = v +\frac{m_{C}}{m_{S}}\cdot (v-v_{C})[/tex]
[tex]v_{S} = -15\,\frac{m}{s}+\left(\frac{2000\,kg}{2200\,kg} \right) \cdot \left(-15\,\frac{m}{s}-45\,\frac{m}{s} \right)[/tex]
[tex]v_{S} = -69.545\,\frac{m}{s}[/tex]
The semi truck travels at an initial speed of 69.545 meters per second downwards.
I need help please I will give points
Answer:
-5 N of force
Explanation:
Hope it helps!
Determine the force of gravitational attraction between the earth (m = 5.98 x 1024 kg) and a 70-kg physics student if the student is in an airplane at 40000 feet above earth's surface. This would place the student a distance of 6.39 x 106 m from earth's center.
Answer:
[tex]F=683.790939[/tex]N
Explanation:
From the Question we are told that
Earth mass [tex]m_1= 5.98 * 10^2^4 kg[/tex]
Students mass [tex]m_2=70kg[/tex]
Distance of student from earth center Radius [tex]r=6.39 * 10^6 m[/tex]
Generally the equation for Force of attraction b/w the earth and the boy is mathematically given by
[tex]F=\frac{Gm_1m_2}{r^2}[/tex]
[tex]F=\frac{6.67.10^-^1^1*( 5.98 x 10^2^4)(70)}{(6.39 *10^6)^2}[/tex]
Therefore the force of attraction b/w the student and the earth is
[tex]F=683.790939N[/tex]
[tex]F\approx 684N[/tex]
When can a high speed velocity cause damage?'
Answer:
50 Mph.
Explanation:
According to the National Severe Storms Laboratory, winds can really begin to cause damage when they reach 50 mph. But here’s what happens before and after they reach that threshold, according to the Beaufort Wind Scale (showing estimated wind speeds): - at 19 to 24 mph, smaller trees begin to sway.
Electric potential energy is the energy of a charge based on
A.
the magnitude of its charge and its position in an electric field.
B.
the magnitude of its charge, its mass, and its speed.
C.
its mass and height above a given reference point in an electric field.
D.
its speed and the direction of its motion relative to a second charge.
Answer:
EPE is the ability to provide a charge within a circuit. It can be represented as a vector quantity, which has magnitude and direction.Hence A is correctIdentify the state of matter.
A)The molecules are a great distance apart, moving
very rapidly, with negligible interaction. The
substance occupies all the space available.
B)The molecules are only able to vibrate rapidly about
fixed positions. The substance does not need a
container to maintain its shape.
C)The molecules move about amongst each other,
with attractive forces between them. The substance
does not necessarily fill its container
Answer:
Gases
Solids
Liquids
Explanation:
A)The molecules are a great distance apart, moving very rapidly, with negligible interaction. The substance occupies all the space available.
Gases
The state of matter described above is for gases. The distances between gases are far apart and they have very weak intermolecular attraction. They have no fixed volume as they occupy any volume of space they are introduced into.
B)The molecules are only able to vibrate rapidly about fixed positions. The substance does not need a container to maintain its shape.
Solids
Solids have fixed shape and volume. They are held together in their fixed lattice and are only able to rapidly vibrate about their fixed positions.
C)The molecules move about amongst each other, with attractive forces between them. The substance does not necessarily fill its container.
Liquids
The state of matter described here are the liquids. Liquids flow amongst each other. The attractive force between them is greater than that of gases but lesser than those of solids.
Electromagnetic waves are classified as longitudinal waves.
Please select the best answer from the choices provided
T
F
Answer:
False
Explanation:
Electromagnetic waves are transverse waves. That means that the electric and magnetic fields oscillate in a plane that is perpendicular to the direction of wave propagation.
Answer:
false electromagnetic waves are not classified as longitudinal waves
If a 1000 kg car is traveling at 3
meters per second, what is its
kinetic energy?
A car traveled 1,215 km West from El Paso to Dallas in 13.5 hours. What was its velocity? A: 90 m/s west B. 90km/h C. .09km/h West D. 90km/h West
Answer:
B. 90km/hr
Explanation:
The formula for finding velocity =
Displacement/time
The displacement of the car has been given to be = 1215 km West
Time it took to go from Dallas to Paso = 13.5 hours
Then velocity = 1215/13.5
= 90
Therefore velocity = 90km/hour
Option B is the correct answer to this question.
Thank you!
Q2. An initially stationary 18-kg curling rock has a force applied to it over 2.0s. Its released with a velocity of 8.3 m/s [forward]. Determine the magnitude and direction of the applied force. Try solving this problem two different ways.
Answer: 74.7 N
Explanation:
Both approaches yield the same result: the magnitude of the applied force is approximately 74.7 N, and its direction is forward.
To solve this problem, we'll use two different approaches: Newton's second law and the work-energy principle.
Approach 1: Newton's Second Law
Newton's second law states that the force applied to an object is equal to the change in momentum of the object over time.
Step 1: Calculate the initial momentum (pinitial) of the curling rock.
pinitial = m * vinitial
pinitial = 18 kg * 0 m/s (since it's initially stationary)
pinitial = 0 kg m/s
Step 2: Calculate the final momentum (pfinal) of the curling rock.
pfinal = m * vfinal
pfinal = 18 kg * 8.3 m/s
pfinal = 149.4 kg m/s
Step 3: Calculate the change in momentum (Δp).
Δp = pfinal - pinitial
Δp = 149.4 kg m/s - 0 kg m/s
Δp = 149.4 kg m/s
Step 4: Calculate the magnitude of the applied force (Fapplied).
Fapplied = Δp / Δt
Fapplied = 149.4 kg m/s / 2.0 s
Fapplied = 74.7 N
Step 5: Determine the direction of the applied force.
The direction of the applied force is forward since the curling rock is released with a velocity of 8.3 m/s forward.
So, according to Newton's second law, the magnitude of the applied force is 74.7 N, and its direction is forward.
Approach 2: Work-Energy Principle
The work-energy principle states that the work done on an object is equal to the change in its kinetic energy.
Step 1: Calculate the initial kinetic energy (KEinitial) of the curling rock.
KEinitial = 0.5 * m * [tex]vinitial^2[/tex]
KEinitial = 0.5 * 18 kg * (0 [tex]m/s)^2[/tex]
KEinitial = 0 J
Step 2: Calculate the final kinetic energy (KEfinal) of the curling rock.
KEfinal = 0.5 * m * [tex]vfinal^2[/tex]
KEfinal = 0.5 * 18 kg * (8.3 [tex]m/s)^2[/tex]
KEfinal = 0.5 * 18 kg * 69.0 [tex]m^2/s^2[/tex]
KEfinal = 621.0 J
Step 3: Calculate the work done on the curling rock (W).
W = KEfinal - KEinitial
W = 621.0 J - 0 J
W = 621.0 J
Step 4: Calculate the magnitude of the applied force (Fapplied) using the work done.
Fapplied = W / d
Fapplied = 621.0 J / 2.0 s
Fapplied = 310.5 N
Step 5: Determine the direction of the applied force.
The direction of the applied force is forward since the curling rock is released with a velocity of 8.3 m/s forward.
So, according to the work-energy principle, the magnitude of the applied force is 310.5 N, and its direction is forward.
Both approaches yield the same result: the magnitude of the applied force is approximately 74.7 N, and its direction is forward.
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Can someone help pls
An object with a mass of 2.0 kg accelerates 2.0 m/s^2. What is the amount of force acting on the object?
Answer:
Explanation:
When the mass
m
is being accelerated with an acceleration of
a
,we can say the net force acting in the direction of acceleration is
F
=
m
a
here,it is given that only one force
F
was applied to cause this acceleration, and also given,
m
=
2
K
g
,
a
=
2
m
s
−
2
So,
F
=
2
⋅
2
=
4
N
Answer:
4N
Explanation:
given formula solution
m=2kg F=ma F=2kg×2m/s^2
a=2m/s^2 =4N
Determine the force required to accelerate a 2 kilogram ball to an
acceleration of 9.8 m/s2
Answer:
19.6 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 2 × 9.8
We have the final answer as
19.6 NHope this helps you
1. A kangaroo hops 84 m to the east in 7 seconds.
o What is the kangaroo's speed? 12 m/s
o What is the kangaroo's velocity?
Explanation:
Given parameters:
Distance hopped = 84m
Displacement = 84m due east
Time = 7s
Unknown:
Speed of kangaroo = ?
Velocity of kangaroo = ?
Solution:
To solve this problem,
Speed = [tex]\frac{distance}{time }[/tex] = [tex]\frac{84}{7}[/tex] = 12m/s
Velocity = [tex]\frac{displacement}{time}[/tex] = [tex]\frac{84}{7}[/tex] = 12m/s due east
Which of these pairs of atoms are isotpoes? (Physical Science) Pair A Pair B Pair C # protons 6 8 5 2 12 12 # neutrons 8 8 5 3 13 14
Answer:
I guess that the atoms are:
Protons: 6 8 5 2 12 12
Neutrons: 8 8 5 3 13 14
Now, two atoms are isotopes if they share the same number of protons (so both atoms are the same element) but they have a different number of neutrons.
From the given options, the only two that have the same number of protons but a different number of neutrons are:
Protons 12, neutrons 13
and
Protons 12, neutrons 14.
These two are isiotopes.
if an object is projected upwards with an angle 30 to the horizontal and its initial velocity is 20 m/s, its maximum height= ? ( consider g= 10m/s^2 )
Answer:
[tex]h_m=5 \ m[/tex]
Explanation:
Projectile Motion
It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path under the action of gravity.
The maximum height hm is reached when the vertical component of the velocity is 0. It can be calculated as follows:
[tex]\displaystyle h_m=\frac{v_o^2\cdot \sin^2\theta}{2g}[/tex]
Where:
vo = initial speed of the object
θ = initial launch angle
g = acceleration of gravity ([tex]10\ m/s^2[/tex])
The object is projected with an angle of θ=30° and an initial speed of vo=20 m/s. The maximum height is:
[tex]\displaystyle h_m=\frac{20^2\cdot \sin^2 30^\circ}{2*10}[/tex]
[tex]\displaystyle h_m=\frac{400\cdot 0.5^2}{20}[/tex]
[tex]\boxed{h_m=5 \ m}[/tex]
A cart falls from a track with an acceleration of 10 m/s2 (which is always the acceleration due to gravity). If it falls for 9 seconds before hitting the ground, what is it’s velocity at impact? (show work plz)
Answer:
90m/s
Explanation:
Given parameters:
Acceleration = 10m/s²
Time of fall = 9s
Unknown:
Final velocity = ?
Solution:
We can assume that the cart falls from rest.
Initial velocity = 0m/s
Using
v = u + gt
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
t is the time
v = 0 + 10 x 9 = 90m/s
Answer:
90m/s
Explanation:
A student pulls a block across the desk in physics class. He applies 14N of
tension in the string, but friction holds the box back with 4N. His partner
measures the acceleration of the box across the desk to be 2m/s2. What
must the mass of the box be?
100 Pointsss hellppp
can you please show a picture