What is the first step to cutting internal threads on an engine lathe?

Solution :

Given :

Dry bulb temperature, T = 30 degree C

Absolute pressure, P = 102 kPa

Partial pressure of water vapor, [tex]$P_v$[/tex] = 1.5 kPa

a). Relative humidity is given by

[tex]$\phi = \frac{P_v}{P_{sat}}$[/tex]

At T = 30 degree C, from the steam table, we have saturation temperature as 4.2469 kPa.

[tex]$\phi = \frac{1.5}{4.2469}$[/tex]

  = 0.35319

  = 35.31 %

b). Humidity ratio,  

[tex]$w= 0.622 \times \frac{P_v}{P-P_v}$[/tex]

[tex]$w= 0.622 \times \frac{1.5}{102-1.5}$[/tex]

w = 0.009283 kg per kg of dry air

c). Dew point temperature is the saturation temperature at vapor pressure of air (can be found from steam table)

At [tex]$P_v$[/tex] = 1.5 kPa, saturation temperature = 1.02 degree C

∴ Dew point temperature = 13.02 °C

d). Humidity ratio can be be defined as the ratio of mass of water vapor to the mass of dry air.

i.e. [tex]$w=\frac{m_v}{m_a}$[/tex]

[tex]$0.009283 =\frac{10}{m_a}$[/tex]

∴ [tex]m_{a}[/tex] = 1077.170 kg of dry air

Answer:

Cost per cubic yard to place concrete using each of the following alternatives:

Alternative a = $14.04

Alternative b = $14.71

Explanation:

a) Data and Calculations:

Work of concrete in footings = 140 cubic yards

a. Price of using crane and bucket = $225 per hour

Number of hours required for this setup = 7 hours

Transportation of the crane = $390

Therefore, total cost under this alternative = $1,965 (($225*7) + $390)

Cost per cubic yard = $14.04 ($1,965/140)

b. Price of using a concrete pump = $295 per hour

Number of hours required for this setup = 6 hours

Transportation of the pump = $290

Therefore, total cost under this alternative = $2,060 (($295*6) + $290)

Cost per cubic yard = $14.71 ($2,060/140)

Answer:

Subcritical

Explanation:

To compute the grouse number

We use this formula

F = v/√gy

From this question

V = 1 m

G = 9.81m/sec²

Y = 0.5

When we insert this into the grouse formula

F = 1m/s / √ 9.8m/sec² x 0.5m

= 0.451< 1

Therefore we conclude that the grouse is less than 1 and so the flow is subcritical.

Answer:

3.4 inches

Explanation:

Determine the diameter required to protect the vessel from a regulator failure ( relief diameter )

A = [tex]\frac{\pi d^2}{4}[/tex]

Hence d = [tex]\sqrt{\frac{4A}{\pi } }[/tex]  =  [tex]\sqrt{\frac{4 * 9.08}{\pi } }[/tex]  = 3.4 inches

attached below is the remaining part of the solution

Answer: the reflection loss is 4%

Explanation:

Given that;

n for window glass is 1.5

we know that

Reflection Loss rλ = (nλ - 1)² / (nλ + 1)²

the reflection of loss rλ at normal incidence between two media with different refractive indexes rλ = n'/n, the ratio indices

where n is index of refraction of air ( 1 )

and n' is the refraction of window glass ( 1.5 )

our nλ is 1.5

so we substitute into the equation

rλ =[ (1.5 - 1)² / (1.5 + 1)²] × 100

= [0.25 / 6.25] × 100

= 0.04 × 100

= 4%

Therefore the reflection loss is 4%

Answer:

Contactors can be field mounted easily and are compact in size. Generally, these electrical devices feature multiple contacts. These contacts are in most cases normally open and provide operating power to the load when the contactor coil is energized. Contactors are most commonly used for controlling electric motors.

Explanation:

Answer:

A) complex power = apparent  power =  ( 108.253 + 62.5 i ) VA  

    active power = 108.25 watts

   reactive power = 62.5 VAR'S

    power factor = cos ∅ = cos 30° = 0.866 ( lagging )

also ; current lags voltage by 30°

B) your question is not well written hence no answer

Explanation:

A) v(t) = 100 cos (377t - 30° ) v

    Vrms = [tex]\frac{100}{\sqrt{2} }[/tex] ∠ -30°

    I(t) = 2.5cos(377t- 60°) A

  Irms = [tex]\frac{2.5}{\sqrt{2} }[/tex] ∠ -60°

determine complex power apparent power . ......  power factor

Note : complex power = apparent power

=( Irms ) * Vrms

=  ( [tex]\frac{2.5}{\sqrt{2} }[/tex] ∠ -60° ) * ( [tex]\frac{100}{\sqrt{2} }[/tex] ∠ -30° )  

= 125 ∠ 30°

= ( 108.253 + 62.5 i ) VA   ( complex power )

active power = 108.25 watts

reactive power = 62.5 VAR'S

power factor = cos ∅ = cos 30° = 0.866 ( lagging )

current lags voltage by 30°

Answer:

This shows that the technological designs are similar to the scientific investigation processes.

Explanation:

Scientists carry out scientific investigations and discoveries. They learn from their environment by investigating the natural world. The scientist investigates by problem identification, research the related information, designing and conceptualizing, investigating and analyzing the results and deriving out conclusions.

Similarly the engineers follow the same step and provide solutions to the problems of the society through their products and technological designs. The engineers first identify the need of the product, design and implement the design to provide solution and then evaluate the solution. These are the similar steps that an engineer follow in a technological design of a product or a solution.

Answer:

NG=64 teeth

dG=384mm

dP=96mm

C=240mm

Explanation:

step one:

given data

module m=6mm

velocity ratio VR=4

number of teeth of pinion Np=16

Step two:

Required

1. Number of teeth on the driven gear

[tex]N_G=N_P*V_R\\\\N_G=16*4\\\\N_G=64[/tex]

The driven gear has 64 teeth

2.  The pitch diameters

The driven gear diameter

[tex]d_G=N_G*m\\\\d_G=64*6\\\\d_G=384[/tex]

The driven gear diameter is 384mm

The pinion diameter

[tex]d_P=N_P*m\\\\d_P=16*6\\\\d_P=96[/tex]

Pinion diameter is 96mm

3. Theoretical center-to-center distance

[tex]C=\frac{d_G+d_P}{2} \\\\C=\frac{384+96}{2} \\\\C=\frac{480}{2}\\\\C=240[/tex]

The theoretical center-to-center distance is 240mm

The results are listed below:

First, we proceed to find the number of teeth of each gear ([tex]N_{D}, N_{P}[/tex]) based on the fact that gear only fit when they have the same module ([tex]m[/tex]). The velocity ratio ([tex]r_{v}[/tex]) is defined by the following relationship:

[tex]r_{v} = \frac{N_{D}}{N_{P}}[/tex] (1)

If we know that [tex]r_{v} = 4[/tex] and [tex]N_{P} = 16[/tex], then the number of teeth of the driven gear is:

[tex]N_{D} = r_{v}\cdot N_{P}[/tex]

[tex]N_{D} = 4\cdot (16)[/tex]

[tex]N_{D} = 64[/tex]

The driven gear has 64 teeth.

The pitch diameter ([tex]D[/tex]) is obtained by multiplying the number of teeth ([tex]N[/tex]) by module ([tex]m[/tex]), in milimeters.

Pinion

[tex]D_{P} = m\cdot N_{P}[/tex] (2)

([tex]m = 6\,mm[/tex], [tex]N_{P} = 16[/tex])

[tex]D_{P} = (6\,mm)\cdot (16)[/tex]

[tex]D_{P} = 96\,mm[/tex]

Driven gear

[tex]D_{D} = m\cdot N_{D}[/tex] (3)

([tex]m = 6\,mm[/tex], [tex]N_{D} = 64[/tex])

[tex]D_{D} = (6\,mm)\cdot (64)[/tex]

[tex]D_{D} = 384\,mm[/tex]

The pinion has a diameter of 96 millimeters and the driven gear has a diameter of 384 millimeters.

Lastly, the theoretical center-to-center distance is calculated by the following formula:

[tex]d = \frac{1}{2}\cdot (D_{P}+D_{D})[/tex]  (4)

([tex]D_{P} = 96\,mm[/tex], [tex]D_{D} = 384\,mm[/tex])

[tex]d = \frac{1}{2}\cdot (96\,mm + 384\,mm)[/tex]

[tex]d = 240\,mm[/tex]

The theoretical center-to-center distance is 240 millimeters.

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Answer:

num_count = 0

while num_count < 25:

   print(num_count)

   num_count += 3

Explanation:

A while loop statement is defined in the python source code above. An integer variable 'num_count' is defined and continuously incremented by three in the loop until it is greater than 25. the output of the while loop between 1 and 25 is print on the screen.

Answer:

10

Explanation:

The speed of the chain is the same for both sprockets.

vᵢ = vₒ

ωᵢ rᵢ = ωₒ rₒ

The sprockets have the same pitch, so the radius is proportional to the number of teeth.  So we can say:

ωᵢ nᵢ = ωₒ nₒ

Plugging in values:

(60 rpm) (40) = (240 rpm) nₒ

nₒ = 10

The output sprocket has 10 teeth.  This makes sense, if the output sprocket is 4 times smaller, it will turn 4 times faster than the input sprocket.

Answer: it is 10 teeth and the guy under me already explained soo

Explanation:

Answer: Civil engineering is a branch in engineering which deals with design, construction, and building structures such as dam, bridges etc....

Explanation:

Answer:

I think is B

Explanation:

Answer:

Apalancamiento.

Explanation:

El apalancamiento es el uso de dinero prestado (deuda) para aumentar el rendimiento esperado del capital. El apalancamiento se mide como la relación entre la deuda que devenga intereses y los activos totales. Cuanto mayor sea la deuda que devenga intereses, mayor será el apalancamiento financiero o "aceleración". Esto puede tener un efecto positivo o negativo.

Los costos por intereses de este capital de préstamo suelen ser fijos y se deducen de los ingresos. Un préstamo permite que una organización genere más ingresos sin un aumento necesario en el capital. Como no es necesario recaudar ni mantener capital social adicional, no se requieren pagos de dividendos adicionales (que no se pueden deducir de las ganancias). Sin embargo, un alto apalancamiento puede ser beneficioso durante los tiempos de auge, pero puede conducir a serios problemas de flujo de efectivo durante una recesión, ya que es posible que no haya suficientes retornos para cubrir mayores costos de intereses y obligaciones de reembolso.

Answer:

maximum roll-off factor is 0.7

Explanation:

given data

rate of output data  = 1,000,000 bits/sec

cutoff frequency fc = 850 kHz

solution

we know bandwidth frequency is same as that of bandwidth

we apply here fc formula that is

fc = ω ( 1 + α )     ..........1

here

ω = data rate ÷ 2   .............2

ω = 1000  ÷ 2  

ω = 500000 Hz

so put now value in eq 1

fc = ω ( 1 + α )

850000= 500000  ( 1 + α )

solve it we get

α = 0.7

so, maximum roll-off factor is 0.7

Answer:

I think the answer is drop ceilings

Explanation:

Answer:

SIR IT IS D HOPE THIS HELPS (☞ﾟヮﾟ)☞☜(ﾟヮﾟ☜)

Explanation:

Answer:

Explanation:

EFFECT OF INCREASING THE BOLIER PRESSURE ON

The answer is explained in the picture. Thank you. Rate it

Answer:

b. American Society of Mechanical Engineers

Explanation:

The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.

The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.

Answer:

You'd need to know things like the weight of the car, the spring constant of the suspension springs.

Explanation:

Driving over the curb slowly does not have much of an "impact" because of the small potential energy it has but to find the force that results from going over the curb at a much higher speed, you would need to know the weight of the car since it directly impact the force that it applies. You also would need to know about the car's suspension, the spring material, how stiff the springs are and their spring constant to calculate the force they absorb.

I hope this answer helps.

Answer:

d

Explanation:

yea

Answer:

D

Explanation:

Answer:

5 multiply by 10 S/M

Based on the calculations, the incident wave would be down to 1 mV/m at a depth of 287.82 meters.

Since the medium is a wet soil, it is characterized by the following:

Next, we would determine loss tangent, so as to know if the wet soil is a low-loss medium:

For a low-loss medium; ε''/ε' = σ/ωε < 0.01.

[tex]\frac{\sigma}{\omega \epsilon} = \frac{5 \times 10^{-4} \;\times\; 36 \pi}{2\pi \;\times \;3 \times 10^9\; \times\; 10^{-9} \times \;9} \\\\\frac{\sigma}{\omega \epsilon} =3.32 \times 10^{-4}[/tex]

Therefore, the wet soil medium is a low-loss dielectric and its absorption (attenuation) coefficient is calculated by using this formula:

Note:

[tex]\alpha = \frac{\sigma}{2}\sqrt{\frac{\mu}{\epsilon}} \\\\\alpha = \frac{\sigma}{2} \times \frac{120\pi}{\sqrt{\epsilon_r} } \\\\\alpha =\frac{5 \times 10^{-4} \times 120\pi}{2 \times \sqrt{9} } \\\\[/tex]

α = 0.032 Np/m.

Now, we calculate the depth:

[tex]E(z) = E_oe^{-\alpha z} = 10e^{-\alpha z}\\\\10^{-3}=10e^{-0.032 z}\\\\ln(10^{-4})=-0.032 z\\\\-9.21 \times 10^9=-0.032z\\\\z=\frac{-92.1 0}{-0.032}[/tex]

z = 287.82 meters.

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Answer:A rear disc/drum parking brake uses the inside of each rear wheel hub and rotor assembly as a parking brake drum

Explanation:

The interior of each rear wheel hub and rotor assembly serves as a parking brake drum in a rear disc/drum parking brake.

A drum brake is a type of brake that relies on friction created by a set of shoes or pads pressing outward against a rotating cylinder-shaped part known as a brake drum.

Drum brakes are commonly used to describe brakes in which shoes press against the inner surface of the drum.

Drum brakes provide consistent braking force regardless of whether the vehicle is moving forward or backward.

This is due to the fact that drum brakes produce the same braking force in both directions. This type is typically found on passenger car rear brakes.

Thus, in a rear disc/drum parking brake, the interior of each rear wheel hub and rotor assembly serves as a parking brake drum.

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Answer:

Answer: B) Scanning the computer and deleting any viruses.

Explanation:

Some of the feedback I hear from new developers working on a programming problem revolves around uncertainty of where to start. You understand the problem, the logic, basics of the syntax, etc. If you see someone else’s code or have someone to guide you, you can follow along. But maybe you feel uncertain about doing it yourself and have trouble turning your thoughts into code at first even though you understand the syntax or logic. Here’s my process and some tips to tackling a sample problem that hopefully some of you may find helpful in your journey.

If you need further expenation then:

Some of the feedback I hear from new developers working on a programming problem revolves around uncertainty of where to start. You understand the problem, the logic, basics of the syntax, etc. If you see someone else’s code or have someone to guide you, you can follow along. But maybe you feel uncertain about doing it yourself and have trouble turning your thoughts into code at first even though you understand the syntax or logic. Here’s my process and some tips to tackling a sample problem that hopefully some of you may find helpful in your journey.

May i please have brainliest

Answer:

B. scanning the computer and deleting any viruses

Explanation:

I took the test on edge, and this makes most sense to me. Good luck:)

Answer:

V = 50 ft³/s

H.P = 0.466

Explanation:

Given that

Diameter of the duct, D = 0.3 m

Vacuum Pressure of the duct, Z = 0.025 m

P(w) = pressure of water, 1000 kg/m³

P(a) = pressure of air, 1.22 kg/m³

To find the pressure change we use the formula

ΔP = P(w) * g * Z

ΔP = 1000 * 9.8 * 0.025

ΔP = 245 Pa.

We need the area, do we find that too

A = πd²/4

A = π * 0.3² * 1/4

A = 0.071 m²

Recall the energy equation to be

1/2v² = ΔP/p(a) , so that if we rearrange, we have

v² = 2ΔP/p(a)

v = √(2ΔP/p(a)), on substituting the values, we have

v = √(2 * 245)/1.22

v = √490/1.22

v = √401.64

v = 20.04

The volume flow rate is then equal to

Velocity * Area.

V = 20.04 * 0.071

V = 1.42 m³/s, converting to ft³/s, we have 50 ft³/s

Horsepower output is gotten using

P = ΔP * V

P = 245 * 1.42

P = 347.9 w, converting this to HP, we have 0.466 HP

Answer:

45

Explanation:

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Answer:

true ...............

Some refrigerants R11, R12, and R115 contain CFC. The statement is true.

Chlorofluorocarbons (CFCs), as the name suggests, are compounds made of the atoms of fluorine, chlorine, and carbon. Because they are neither hazardous nor combustible, they have a variety of uses, including in refrigeration. Refrigeration is the process of maintaining the temperature of the required space cooler than that of an atmosphere.

As the public learned in 1974 that CFCs were alarmingly destroying the ozone layer, most CFCs were outlawed, and by 1995, their manufacture of them had virtually ended worldwide.  CFCs were replaced with other products since they were no longer produced and the things they were used for required new products.

Therefore, some refrigerants R11, R12, and R115 contain CFC. The statement is true.

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This question is incomplete, the complete question is;

An individual eats fish from a river contaminated with benzene. What concentrations of benzene in water (mg/L) would produce a lifetime cancer risk of 10⁻⁶ to an individual who eats 2 meals of fish per week for 30 years if the BCF for benzene is 10⁺³?

Answer:

0.021 mg/L concentration of benzene in water  would produce a lifetime cancer risk 10⁻⁶ to an individual who eats 2 meals of fish per week for 30 years if the BCF for benzene is 10⁺³

Explanation:

Chronic daily intake (CDI) =(C/W) (Intake rate/ lifetime) ( Exposure)

values from EPA Exposure Factors Table)

CDI = [ (5.2 L/d × C mg/L  0.054 kg/d) / 70 kg] [30/70] [350/365]

CDI = 1.65 × 10⁻³C

Now concentration of benzene;  ( RISK) = CDI × pF

= 10⁻⁶ = [2.9× 10⁻² / (MG/kg-d)] ( 1.65 × 10⁻³C)

C = 0.021 mg/L

Therefore 0.021 mg/L concentration of benzene in water  would produce a lifetime cancer risk 10⁻⁶