What is the formula for the carboxylic acid functional group?
OA. -CH3
OB. -COH
0 с. -соон
OD. -CO-

When investigative officers get to a crime scene, they do not need to collect water samples.

A crime scene is a place where an offence has been committed. It is usually cordoned off to enable investigation of the crime and the collection of samples.

When investigative officers get to a crime scene, they do not need to collect water samples.

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Answer:A

Explanation:.

Answer:

c. one must have a higher kinetic energy than the other system

Answer:

Explanation:

Comment

A: is in group 1. The properties are quite similar

B: the choices for answer B are in column or group 2. They too will have similar properties.

C: the choices there are in group 18. They do have similar properties.

The answer is D.

Note: group means the same thing as column. They are vertical.

Answer:

Burning of paper and log of wood.

Digestion of food.

Boiling an egg.

Explanation:

The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.

The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is calculated as follows;

H₂CO3 ⇄ 2H⁺  + CO₃²⁻

x         :      2x        x

ksp = (2x)²x

ksp = 4x³

(1.8 x 10⁻¹⁴) = 4x³

(1.8 x 10⁻¹⁴) /4 = x³

4.5 x 10⁻¹⁵ = x³

x = (4.5 x 10⁻¹⁵)^¹/₃

x = 1.65 x 10⁻⁵ mol/dm³

Thus, the equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.

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The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.

Solubility is defined as the maximum amount of a substance that will dissolve in a given amount of solvent at a specified temperature.

The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is calculated as follows;

H₂CO3 ⇄ 2H⁺  + CO₃²⁻

x         :      2x        x

ksp = (2x)²x

ksp = 4x³

(1.8 x 10⁻¹⁴) = 4x³

(1.8 x 10⁻¹⁴) /4 = x³

4.5 x 10⁻¹⁵ = x³

x = [tex](4.5 X 10^{-15})^{\frac{1}{3} }[/tex]

x = 1.65 x 10⁻⁵ mol/dm³

Thus, the equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.

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Refraction is caused due to the change in speed of light when it enters from one medium to another. Hence, option B is correct.

Refraction happens when light changes direction, or bends when it moves from one material to another.

The cause of the refraction of light is that light travels at different speeds in different media.

This change in the speed of light when it moves from one medium to another causes it to bend.

Thus, refraction is caused due to the change in speed of light when it enters from one medium to another. Hence, option B is correct.

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Answer:

Discussion: Red cabbage is useful as a pH indicator because the leaves contain a pigment molecule from the family of anthocyanins (shown below) which are responsible for many of the red/purple/blue colors observed in fruits and vegetables. In neutral solutions, the color observed is purple.

hope this helps:3

Answer:

Because the brain is connected.

Explanation:

The molecular formula of the compound is C₄H₈O₄.

The molecular formula is the exact whole number ratio of the compound's elements. The empirical formula, as well as the molecular mass, are combined to generate the molecular formula.

Let's assume that the compound contains:

The empirical formula of the compound is:

C               H           O

40.6/12    5.1/1         54.2/16

3.38          5.1           3.38

Divide by the smallest value

3.38/3.38  5.1/3.38  3.38/3.38

1                  1.5≅ 2       1

= C₁H₂O₁

The empirical formula weight = (1 × 12) + (2 × 1) + (1 × 16)

The empirical formula weight = 30 g/mol

Molecular formula = (118.084 g/mol)/30 g/mol

Molecular formula = 3.94 ≅ 4

Therefore, the molecular formula for the compound is C₄H₈O₄.

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5.1434 contains 5 significant figures and 4 decimals.

All zeros that occur between any two non-zero digits are significant. For example, 108.0097 contains seven significant digits.

Calculation:

5.1234 + 0.033÷ 1.650 = 5.1434

5.1434 contains 5 significant figures and 4 decimals. 5.1434 rounded to 4 sig figs is 5.143, to 3 sig figs is 5.14, and to 2 sig figs is 5.1.

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Answer:

10.41 g

Explanation:

ml and   cm^3   are generally interchangeable

15 cm^3     *   . 694  g/cm^3 =  10.41 g

Answer:

Copper (Cu2) , Iron (Fe2+ Fe3 +) , and Hydrogen ion (H+)

Explanation:

I hope it helps u dear! ^_^

Answer:

When sodium metal is dropped in water, hydrogen gas is evolved. Thus, the reaction is, 2Na+2H2O→H2+2NaOH. In the reaction, sodium hydroxide is formed and hydrogen gas is evolved.

Explanation:

Answer:

4.87 g

Explanation:

The formula between the number of moles, mass and Mr can be used to find the mass of barium.

Number of moles = mass ÷ Mr

So, mass = number of moles × Mr

  Mr of Ba = 137.3

∴ Mass = (3.55 × 10⁻²)  × 137.3 = 4.87 g

Answer:

 hydrogen gas will occupy 0.0374 liters when is cooled to 83 °C.

Explanation:

• T1 =602 °C = 875 K

• V1 =92 mL = 0.092 L

0.092L/875K= 1.05×10-⁴L/K

vf =nR/P T f= 1.05×10-⁴L/K ×356K

=0.0374 L

Answer:

0.0315 moles CH₂OH

Explanation:

You can find the amount of moles using the molarity equation. This equation looks like this:

Molarity (M) = moles / volume (L)

Once you convert mL to L (by dividing by 1,000), you can plug the molarity and volume into the equation and isolate to find moles. The final answer should have 3 sig figs because the given value with the lowest amount of sig figs (0.210 M) has this amount.

150.0 mL / 1,000 = 0.1500 L

Molarity = moles / volume

0.210 M = moles / 0.1500 L

(0.210 M x 0.1500 L) = moles

0.0315 = moles

By convention, the standard enthalpy of formation of all elements in their standard states are assumed to be zero. Here the enthalpy value for the intermediate formation step is  -572 kJ. The correct option is D.

The standard enthalpy of formation of a compound is defined as the enthalpy change accompanying the formation of one mole of the compound from its constituent elements, all the substances being in their standard states.

The symbol used to represent the standard enthalpy of formation is ΔfH⁰.  The knowledge of standard enthalpies of various substances is useful for calculating the standard enthalpies of a reaction.

The overall energy difference between the reactants and products remains the same no matter how many intermediates there are in the reaction pathway.

The enthalpy value  = 2 × -286 = -572 kJ

Thus the correct option is D.

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Answer:

2H2O+O2-2H2O2

Explanation:

TO BALANCE equation both side should be equal

Answer:

1.90 M

Explanation:

To find the molarity of the solution, you need to use the molarity equation. This formula looks like this:

Molarity (M) = moles / volume (L)

To use this equation, you need to perform some conversions. You should (1) convert mL to L (by dividing by 1,000), then (2) convert grams NaNO₃ to moles (via molar mass), then (3) plug moles and volume into the molarity equation.

155 mL / 1,000 = 0.155 L

25.0 g NaNO₃           1 mole
---------------------  x  -----------------  = 0.294 moles NaNO₃
                                  85.0 g

Molarity = moles / volume

Molarity = 0.294 moles / 0.155 L

Molarity = 1.8975....

Molarity = 1.90 M

About 80g of KCl will dissolve in 200g of water at 50 degrees.

A saturated solution contains just as must solute as it can normally hold at a given temperature.

Looking at the table we can see that about 40 g of KCl dissolves in 100 g of water at 50 degrees hence about 80g of KCl will dissolve in 200g of water at 50 degrees.

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The AH for the reaction is -137 kJ

Enthalpy of formation is the energy required by reactants to convert into products . It value can be positive or negative depending on the type of reaction, Endothermic or Exothermic.

In the question 3 step reaction is given

C₂H4 (g) + 3 O₂ (g) → 2 CO₂ (g) + 2 H₂O (1)   AH = - 1411. KJ

2 C₂H6 (g) + 7 O₂ (g) → 4 CO₂ (g) + 6 H₂O (1)   AH = - 3120. KJ

2 H₂ (g) + O₂ (g) → 2 H₂O (1)     AH = -571.6 kJ

To determine the enthalpy of formation for

C₂H4 (9) + H₂ (9)→ C₂H6 (g)

Adding reaction 1 and (1/2) 3 will give

C₂H4 (g) + 7/2 O₂ (g) + H₂ (g) ----> 2 CO₂ (g) + 3H₂O AH = -1696.8

For the second reaction

We will reverse the reaction and multiply it by 1/2

2 CO₂ (g) + 3 H₂O (1) -->  C₂H6 (g) + 7/2 O₂ (g)  AH = +1560

Adding the two new reactions.

C₂H4 (9) + H₂ (9)→ C₂H6 (g)    AH = -137 kJ

Therefore The AH for the reaction is -137 kJ

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The heat that is released by the combustion of 3.5 moles of methane is 3115 kJ/mol.

A thermochemical equation is a reaction equation that incorporates the amount of heat lost/gained.

In this case, the reaction equation is; CH4 + O2 ----->CO2 + 2H2O dH = -890 kJ/mol

If 1 mole of methane releases 890 kJ/mol

3.5 moles of methane will release 3.5 moles * 890 kJ/mol/1 mole

= 3115 kJ/mol

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Answer:

4.041 moles C₂H₆

Explanation:

To convert from grams to moles, you first need to determine the molar mass of C₂H₆. The molar mass is the combination of the atomic masses times the quantity of each element present in the molecule. The atomic masses usually be found on the periodic table. They represent how much the element weighs per one mole.

Carbon (C) Atomic Mass: 12.01 g/mol

Hydrogen (H) Atomic Mass: 1.008 g/mol

Molar Mass (C₂H₆): 2(12.01 g/mol) + 6(1.008 g/mol)

Molar Mass (C₂H₆): 30.068 g/mol

Now that you have the molar mass, you can multiply this ratio to the given value. Keep in mind that in order to go from grams to moles, the numerical value should be place in the denominator of the molar mass ratio. This allows for the cancellation of the unit 'grams'. The final answer should have 4 significant figures because the given value also has 4 sig figs.

121.5 grams C₂H₆              1 mole
--------------------------  x  ------------------------  =  4.041 moles C₂H₆
                                     30.068 grams

Answer:

need more info

Explanation:

i think so we need more info

From the calculations, the equilibrium constant of the reaction is given as   0.050

The term equilibrium constant refers to the number that shows the extent to which reactants are converted into products.

The equilibrium constant of this reaction can be obtained from;

K = [0.050] [1.00]^4

K = 0.050

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Based on the dilution formula, 0.1 mL of the stock solution of the enzyme is required to prepare a 50-fold diluted enzyme in 0.01 M HCl.

The 50-fold dilution of the stock enzyme solution can be done by using the dilution formula to determine the given volume of the stock solution required.

The dilution formula is given below:

where:

From the given data for the enzyme dilution;

C1 = 1

C2 = 1/50 = 0.02

V1 = x

V2 = 5 ml

Making V1 subject of formula in the dilution formula:

V1 = C2V2/C1

V1 =  0.02 * 5/1 = 0.1 mL

Therefore, 0.1 mL of the stock solution of the enzyme is required to prepare a 50-fold diluted enzyme in 0.01 M HCl.

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