what is the gcf of 140 and 180

Answer:

A: AC/AE = BC/BD

About 20% of the time Aaron tunes in to his favored station, there will be a commercial playing.

Given info;

The assumption is that over a significant number of days, 20% of the time he tunes in to his favorite station, an ad will be playing. This is based on the idea of relative frequency.

The relative frequency of event A, which is calculated by dividing the number of desired outcomes by the total outcomes, will be off over a large number of experiments, according to the likelihood of an outcome A of a%.

When he dials into his preferred station, there is a 0.2 probability that a commercial will start playing.

The conclusion is that over a long number of days, an advertisement will be playing about 20% of the time he tunes in to his preferred station.

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Through proportionality, we find out that the value of [tex]y[/tex] is 25/4 when [tex]x[/tex] is doubled, 25/9 when [tex]x[/tex] is tripled, 25/36 when [tex]x[/tex] is increased to 5 times its original value, 1 when [tex]x[/tex] is increased by 5 times its original value, and 400 when [tex]x[/tex] is reduced by 75%.

It is given to us that -

[tex]y[/tex] is inversely proportional to [tex]x^{2}[/tex]

This implies that -

[tex]y[/tex] ∝ [tex]\frac{1}{x^{2} }[/tex]

[tex]= > y=\frac{k}{x^{2} }[/tex] ----- (1)

where, [tex]k[/tex] = Constant of proportionality

It is also given to us that for a particular value of [tex]x[/tex], [tex]y[/tex] is 25.

From equation (1) and from the above statement, it can be said that -

[tex]x^{2} =\frac{k}{y} \\= > x^{2} =\frac{k}{25}\\= > x=\frac{\sqrt{k} }{5}[/tex] ------ (2)

Now, we have to find out the value of [tex]y[/tex] when [tex]x[/tex] -

a) is doubled

=> [tex]x_{1} = 2x[/tex] ---- (3)

Using equation (3) in equation (1),

[tex]= > y=\frac{k}{(x_{1}) ^{2} }\\= > y=\frac{k}{(2x)^{2} }\\= > y=\frac{k}{4x^{2} }[/tex]---- (4)

Substituting the value of [tex]x[/tex] from equation (2) in equation (4), we have

[tex]y=\frac{k}{4x^{2} }\\= > y=\frac{k}{4(\frac{\sqrt{k} }{5} )^{2} } \\= > y=\frac{25k}{4k}\\ = > y=\frac{25}{4}[/tex]

Thus, the value of [tex]y[/tex] is 25/4 when [tex]x[/tex] is doubled.

b) is tripled

=> [tex]x_{2}=3x[/tex] ---- (5)

Using equation (5) in equation (1),

[tex]= > y=\frac{k}{(x_{2} )^{2} } \\= > y=\frac{k}{(3x)^{2} } \\= > y=\frac{k}{9x^{2} }[/tex]------ (6)

Substituting the value of [tex]x[/tex] from equation (2) in equation (6), we have

[tex]y=\frac{k}{9x^{2} }\\= > y=\frac{k}{9(\frac{\sqrt{k} }{5} )^{2} } \\= > y=\frac{25k}{9k} \\= > y=\frac{25}{9}[/tex]

Thus, the value of [tex]y[/tex] is 25/9 when [tex]x[/tex] is tripled.

c) increased to 5 times its original value

[tex]x_{3}= x+5x\\= > x_{3}=6x[/tex]

From equation (2),

[tex]x_{3}=6x\\= > x_{3}=6(\frac{\sqrt{k} }{5} )\\= > x_{3}=\frac{6\sqrt{k} }{5}[/tex]----- (7)

Using equation (7) in equation (1),

[tex]y=\frac{k}{(x_{3}) ^{2} } \\= > y=\frac{k}{(\frac{6\sqrt{k} }{5} )^{2} } \\= > y=\frac{25k}{36k} \\= > y = \frac{25}{36}[/tex]

Thus, the value of [tex]y[/tex] is 25/36 when [tex]x[/tex] is increased to 5 times its original value.

d) increased by 5 times its original value

[tex]x_{4}=5x\\= > x_{4}=5(\frac{\sqrt{k} }{5}) \\= > x_{4}=\sqrt{k}\\[/tex]------ (8)

Using equation (8) in equation (1),

[tex]= > y=\frac{k}{(x_{4}) ^{2} }\\= > y=\frac{k}{(\sqrt{k} )^{2} } \\= > y=1\\[/tex]

Thus, the value of [tex]y[/tex] is 1 when [tex]x[/tex] is increased by 5 times its original value.

e) reduced by 75%

[tex]= > x_{5}= x-(\frac{75}{100} )x\\= > x_{5}=\frac{100x-75x}{100}\\ = > x_{5}=\frac{25x}{100} \\= > x_{5}=0.25x[/tex]

Substituting the value of [tex]x[/tex] from equation (2) in the above equation,

[tex]x_{5}=0.25x\\= > x_{5}=0.25(\frac{\sqrt{k} }{5} )\\= > x_{5}=0.05\sqrt{k}[/tex]----- (9)

Using equation (9) in equation (1),

[tex]= > y=\frac{k}{(x_{5}) ^{2} }\\= > y=\frac{k}{(0.05\sqrt{k}) ^{2} } \\= > y= \frac{1}{0.0025}\\ = > y= 400[/tex]

Thus, the value of [tex]y[/tex] is 400 when [tex]x[/tex] is reduced by 75%.

Therefore, through proportionality, we find out that the [tex]y[/tex] is 25/4 when [tex]x[/tex] is doubled, 25/9 when [tex]x[/tex] is tripled, 25/36 when [tex]x[/tex] is increased to 5 times its original value, 1 when [tex]x[/tex] is increased by 5 times its original value, and 400 when [tex]x[/tex] is reduced by 75%.

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The correct statement regarding the sentence square root of 49 = 7 is given as follows:

C. 7 is the length of the side of a square whose area is 49.

Considering a square of side length s, we have that the area and the perimeter of the square are given as follows:

In the context of this problem, the expression is given as follows:

square root of 49 = 7.

For a square with area of 49 units squared, the side length is obtained as follows:

s² = 49

s = square root of 49

s = 7.

Which means that option C is the correct option.

The problem is given by the image shown at the end of the answer.

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Answer: Angles 1, 3, 7

Step-by-step explanation:

∠7 is vertical to ∠5

∠1 is corresponding to ∠5

∠3 is opposite interior angle of ∠5, it is also vertical to ∠1

The null and alternative hypothesis are H0 : μ = 444; Ha : μ < 444.

In the given question we have to determine the decision rule for rejecting the null hypothesis.

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 444 gram setting.

[tex]\mu_{0}[/tex] = 444

A 9 bag sample had a mean of 441 grams with a standard deviation of 25.

A level of significance of 0.025 will be used.

There have claim that the machine is underfilling the bags.

So , the null and alternative hypothesis are

H0 : μ = 444

Ha : μ < 444

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The side lengths of the triangle is 17, 144, 145

Let x be the length of the short leg

The length of the longer leg of a right triangle is 25 cm more than seven times the length of the shorter leg

The length of the long leg is 25 + 7x

The length of the hypotenuse is 26 cm more than seven times the length of the shorter leg.

The length of the hypotenuse is 26 + 7x

(26 + 7x)² = (25 + 7x)² + x²

676 + 364x + 49x² = 625 + 350x + 49x² + x²

0 = x² -14x - 51

0 = (x - 17)(x + 3)

{-3, 17}

Length cannot be negative.

The length of the long leg is 25 + 7x = 25 + 7(17) = 144

The length of the hypotenuse is 26 + 7x = 26 + 7(17) = 145

Therefore, the side lengths of the triangle is 17, 144, 145

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Answer: B: -4

Step-by-step explanation: -168/-14 = 12

12/-3 = -4

Answer:

blood vessels

Step-by-step explanation:

Blood vessels carry nutrients throughout your body

Answer:

Step-by-step explanation:

the answer is blood vessels.

Xylem and phloem constitute the vascular bundle. Xylem distribute and store water. Phloem is responsible for transporting sugars, proteins, and other organic material. Similarly blood vessels in humans perform the function of delivering blood that contains gases, nutrients, waste, cells and hormones throughout the body.

Answer:

55x+36y

Step-by-step explanation:

1. Group similar terms: 14x+41x+9y+27y
2. Add: 55x+36y

Answer:

11:8

3:11

Step-by-step explanation:

The total is 11 (3+ 8)

Answer: y = 4x + 7

Step-by-step explanation:

It's a line, so the formula is y = mx + b.

Slope(m): [tex]\frac{y_{2} - y_{1}}{x_{2} - x_{1}} =\frac{-1-3}{-2-(-1)} =\frac{-4}{-1} =4[/tex]

Y-intercept(b):

[tex]y=4x+b\\3=4(-1)+b\\3=-4+b\\b=3+4=7\\[/tex]

Therefore, y = mx + b = 4x + 7.

From given information,

6]  the reason for line 2 of the proof: Given

7] the statement for line 4 of the proof:  BL ≅ LK  

8]  the reason for line 4 of the proof:  Definition of midpoint

9] the statement of line 5 of the proof: Δ BWL ≅ ΔKTL

10] the reason for line 5 of the proof: SAS postulate of triangle congruence

In this question, we have been given two triangles BWL and KTL.

We need to complete the proof.

A point L is the midpoint of line segment BK

Also, LW ≅ LT,

∠WLB ≅ ∠TLK

Consider,

             Statement                                         Reason

1)            LW ≅ LT                                             Given

2)        ∠WLB ≅ ∠TLK                                      Given

3)   L is the midpoint of BK                              Given

4)         BL ≅ LK                                           Definition of midpoint

5)       Δ BWL ≅ ΔKTL                      SAS postulate of triangle congruence

Therefore, from given information,

6]  the reason for line 2 of the proof: Given

7] the statement for line 4 of the proof:  BL ≅ LK  

8]  the reason for line 4 of the proof:  Definition of midpoint

9] the statement of line 5 of the proof: Δ BWL ≅ ΔKTL

10] the reason for line 5 of the proof: SAS postulate of triangle congruence

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Answer:

Step-by-step explanation:

The given translates as:

Use given x - intercepts to get the equation:

Use the coordinates of P to find the value of a:

The equation of this parabola is:

Answer:

[tex]\textsf{Intercept form}: \quad y=\dfrac{2}{5}(x-5)(x-12)[/tex]

[tex]\textsf{Standard form}: \quad y=\dfrac{2}{5}x^2-\dfrac{34}{5}x+24[/tex]

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{6 cm}\underline{Intercept form of a quadratic equation}\\\\$y=a(x-p)(x-q)$\\\\where:\\ \phantom{ww}$\bullet$ $p$ and $q$ are the $x$-intercepts. \\ \phantom{ww}$\bullet$ $a$ is some constant.\\\end{minipage}}[/tex]

If the x-intercepts are (5, 0) and (12, 0) then:

Substitute the values of p and q into the formula:

[tex]\implies y=a(x-5)(x-12)[/tex]

To find a, substitute the given point on the curve P (7, -4) into the equation:

[tex]\implies -4=a(7-5)(7-12)[/tex]

[tex]\implies -4=a(2)(-5)[/tex]

[tex]\implies -4=-10a[/tex]

[tex]\implies a=\dfrac{-4}{-10}[/tex]

[tex]\implies a=\dfrac{2}{5}[/tex]

Substitute the found value of a into the equation:

[tex]\implies y=\dfrac{2}{5}(x-5)(x-12)[/tex]

Expand to write the equation in standard form:

[tex]\implies y=\dfrac{2}{5}(x^2-17x+60)[/tex]

[tex]\implies y=\dfrac{2}{5}x^2-\dfrac{34}{5}x+24[/tex]

According to algebra, we can break 12 into parts such that each X value when multiplied by 6 gives a total of 72. Thus, the 2nd option is correct.

Divide the quantity "12" into parts (the number of parts is not specified) and multiply each part by 6.

If you don't want to divide 12, the straight forward way is to simply multiply 12 by 6. 12 x 6 = 72

If we decompose 12 into 12 parts,

X₁, X₂, X₃, X₄, X₅, X₆, X₇, X₈, X₉, X₁₀, X₁₁, X₁₂

In this case X₁ represents the first unit of the number 12. X₂ represents the second unit of the number 12. X₁₂ represents the last unit of the number 12. Therefore, X₁ + X₂ + X₃ + X₄ + X5 + X₆ + X₇ + X₈ + X₉ + X₁₀ + X₁₁ + X₁₂ = 12

Each X value is the number 1. There are 12 locations and each case has its own identity. Multiplying each X value by 6 gives a total of 72.

According to algebra, we can break 12 into parts such that each X value when divided by 6 gives a total of 72. Thus, the 2nd option is correct.

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The correct option is option (C) .

Cluster Sampling is a type of probability sampling and other options are non- probability sampling examples .

Sampling :

Sampling is defined as a technique that selects individual members or subsets from a population to help determine characteristics of the population as a whole.

Croach and Housden postulate that a sample is a finite number taken from a large group for testing and analysis, and that the sample can be taken as representative of the group as a whole.

There are two main types of sampling:

i) probability sampling

ii) Non-probability sampling

A) probability sampling:

It is defined as the sampling technique which researchers use a related method to draw probability theory samples from a larger population.

The most important requirement for probabilistic sampling is that everyone in the population has a known equal chance of being selected.

Probability Samples:

1. Stratified Sampling: Stratified sampling is a type of sampling technique that divides the total population into smaller groups or strata to complete the sampling process. Hierarchies are formed based on some common characteristics of demographic data.

2. Cluster Sampling: Cluster sampling is a probabilistic sampling technique in which researchers divide a population into multiple groups (clusters) for research purposes. Researchers then select random groups using simple sampling techniques for data collection and data analysis.

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The domain and range of the function is given by D:{x|∞<x<∞} and

R:{y|∞<y<∞}

In the given graph we can see that the graph is of straight line .

We know that the straight line graph of the function is of the form

y = mx + c

Now we can say that the graph of the given function is of that form.

The graph passes through (-7,0) and (-5,3)

Slope of the line= 3 / 2

Equation of the line is

y-3 = -3/2(x+5)

or, 2y+3x+9 = 0

Here the domain will be all possible values of x and range will be all possible values of y.

Domain : {x|∞<x<∞}  

Range : {y|∞<y<∞}

A function's domain and range are its constituent parts. A function's range is its potential output, whereas its domain is the set of all possible input values.

A is the domain and B is the co-domain if a function f: A →B exists that maps every element in A to an element in B. 'b', where (a,b) R, provides the representation of an element 'a' under a relation R.

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The average of the given 5 equations is; x' = 2x - 1.6

In mathematics, average is also called the mean and it has the formula as;

x' = ∑fx/∑f

Now, we are given the equations as;

x + 3, 2x - 4, 3x - 6, 2x - 5, and 2x.

Thus;

∑fx = x + 3 + 2x - 4 + 3x - 6 + 2x - 5 + 2x

∑fx = 10x - 8

The number of expressions given is 5 and so ∑f = 5

Thus;

x' = (10x - 8)/5

x' = 2x - 1.6

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Answer:

Step-by-step explanation:

First Selling price is $360, after mark down.

The second's selling price is $403, after both mark downs

Joanne should buy the first, because of the selling price after mark downs.

The P∩V is {2,4,6,8}.

From the question, we have

P= {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

V= {2, 4, 6, 8, 10, 12, 14, 16, 18, 20}

P∩V = {2,4,6,8}

Intersection of Sets:

The set that contains all the elements that are shared by two given sets is the intersection of the two sets. The intersection of sets is represented by the symbol "∩". The intersection A∩ B (also written as A intersection B) lists all the elements that are shared by any two sets A and B that are present in both sets.

For instance, if Set A = 1, 2, 3, 4, and Set B = 3, 4, 6, then A ∩B = {3,4}.

Complete question:

Suppose P = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} and V = {2, 4, 6, 8, 10, 12, 14, 16, 18, 20}. what is P ∩ V ?

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The diameter of his circular field is 18miles

What is sprinkler?

A sprinkler irrigation system is a tool used to irrigate (water) lawns, gardens, golf courses, and other areas. They are also utilised for cooling and dust control in the air. Sprinkler irrigation is a technique for applying water in a way that is similar to rainfall: it is controlled. Pumps, valves, pipes, as well as sprinklers are just a few of the possible components of the network used to distribute the water. Sprinklers for irrigation can be used in residential, commercial, and agricultural settings. Both sandy soil and uneven terrain with insufficient water supply can benefit from it. The rotating nozzle-topped perpendicular pipes are linked to the main pipeline at regular intervals. Water leaks from the rotating nozzles when it is pressurised and forced through the main pipe.

The irrigation sprinkler in this instance is angled.

θ = 50 = 50 π/ 180 rad.

It mists a sphere-shaped area.

A = 2/(2 miles).

If the sprinkler's length is

miles, L. It will be watered within the circle's radius.

Hence,

L^2 = A when divided by two in radians.

⇒ L = √ (2 A / θ)

= √ [(2 x 2 x 180) /40 π]

≈ 18 miles

Hence, The diameter of his circular field is 18 miles

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A Paired t-test evaluates data from dependent samples in which the two treatments are applied to the same individual.

T-test is a statistical statistics mainly use when population variance is unknown and sample size is small.

In Paired t-test , we compare means of two dependent samples . It gives hypothesis examination on difference between of mean.

It uses same items or people in both sample that's why they are also known as dependent t-test

Paired t-test also increases the statistical power of our analysis.

Formula of paired t-test :

[tex]t = \frac{m}{s/\sqrt{n} }[/tex]  with (n-1) degree

where , m is mean difference

s is standard deviation

n is sample size

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Answer:

answer is 5

Step-by-step explanation:

Answer:

hundreds would say the hundreds because they're both in the 8000s and you want to look at the first different digits ihni so i hope this helps

Step-by-step explanation:

The reflection of the point K across the y-axis is (5, -5)

From the question, the point is given as:

Point K = (-5, -5)

Rewrite this point as

K = (-5, -5)

The transformation is given as

Reflection across the y-axis

Mathematically, this transformation can be represented as

(x, y) = (-x, y)

So, we have

K' = (5, -5)

Hence, the image of the reflection is (5, -5)

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Answer:

(5, -5)

Step-by-step explanation:

The other guy is 100% right!

Answer:

  A.  4.33 minutes

  B.  it will be about 11% less than the initial time (4.85 -0.54)

Step-by-step explanation:

You want to know the team's final time if it decreases by 5 1/2% on each of two runs after their initial run time of 4.85 minutes. And you want to know how to check the answer for reasonableness.

If the time decreases by 5.5% on each run, it is multiplied by (1 -5.5%) = 0.945 on each run. The time after 2 more runs will be ...

  (4.85 min)(0.945)(0.945) ≈ 4.33 min

The team's time on the final run was about 4.33 minutes.

For small percentages, the product of small percentage changes is nearly the same as the sum of the percentage changes. That is, two changes by -5.5% will be about the same as a change of 2 × (-5.5%) = -11%.

Of course a decrease of 11% is a decrease of 10% and another decrease of 1%. This makes the estimated time be ...

  4.85 -0.485 -0.0485 ≈ 4.85 -0.54 = 4.31

The estimate is a larger change than the actual change, so the computed value of 4.33 is judged to be reasonable. (The actual effect of two -5.5% changes is about a -10.7% change.)

__

Additional comment

This "add the percentages" is a suitable way to check the reasonableness of all sorts of problems involving percent changes, including problems involving investments or loan interest.

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