What is the importance of a special habitat?

Answer: 5150 J

Explanation:

[tex]Q=mc \Delta T\\\\Q=(283.5)(0.222)(107.5-25.6)\\\\Q \approx \boxed{5150 \text{ J}}[/tex]

The moles of unknown weak acid (HA) in a 100L solution are required to produce a solution with pH 2 is 0.002 moles.

The acid dissociation constant of an acid is given by the formula below:

[tex]K_a= \frac{[A^{-}][H_3O^{-}]}{[HA]}[/tex]

Where

Since, the Ka is given at equilibrium concentrations, [H3O+] = [A-]

[A-] = 10^-2

Making [HA] subject of the formula:

[tex][HA]= \frac{[10^{-2}][10^{-2}]}{5 \times 10^{ - 3} } = 0.02[/tex]

Moles of acid = 0.1 × 0.02 = 0.002 moles

Therefore, the moles of unknown weak acid (HA) in a 100L solution are required to produce a solution with pH 2 is 0.002 moles.

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If the enthalpy is positive and the entropy is positive, the Gibbs energy will always be positive, and the reaction will never be feasible.

The Gibb Free Energy is used to obtain the feasibility of a reaction. If the Gibbs free energy is positive the reaction is not spontaneous. If the value is negative, the reaction is spontaneous while a zero values indicates equilibrium.

From the equation;

ΔG = ΔH - TΔS, it follows that if the enthalpy is positive and the entropy is positive, the Gibbs energy will always be positive, and the reaction will never be feasible.

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Answer: 1.57 M

Explanation:

[tex]M_{A}V_{A}=M_{B}V_{B}\\(33.9)M_{A}-=(23.4)(2.28)\\M_{A}=\frac{(23.4)(2.28)}{33.9}=\boxed{1.57 \text{ M}}[/tex]

If the engineers are trying to increase the acceleration of the car, they have to decrease the mass of the car.

The Newtons laws of motion form the basis of the discussion about motion. We know that from the second law of Newton F = ma

Thus, if the engineers are trying to increase the acceleration of the car, they have to decrease the mass of the car.

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Answer:

1.) Anaphase ------> D.) The chromosomes are separated and move to opposite sides of the cell.

2.) Prophase -------> B.) The DNA is organized into connected rods called chromosomes.

3.) Metaphase -------> A.) Chromosomes line up at the center of the cell.

4.) Telophase ------> C.) New cells begin to form.

125 g/mol is the molar mass of unknown gas. Hence, option C is correct.

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 2 atm

V= 15 L

n=?

R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]

T=300 K

Putting value in the given equation:

[tex]\frac{PV}{RT}[/tex]=n

n= [tex]\frac{2 \;atm\; X \;15 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 300}[/tex]

Moles = 1.21866 moles

Now,

Moles =[tex]\frac{mass}{molar \;mass}[/tex]

1.21866 =[tex]\frac{153 g}{molar \;mass}[/tex]

Molar mass= 125.54 mole/gram

125 g/mol is the molar mass of unknown gas. Hence, option C is correct.

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Answer:

Ok so I assume they gave u a reaction before asking this question. Look at that reaction and try to figure out what substances are changing in valency, if there is a substance(s) that doesn't change its valency then it's a spectator ion.

The rock will be 200 years old if there have been two half-lives.

The half-life  of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.

In this question (t½) of rock is 100 years, which means that after 100 years half of the sample would have decayed and half would be left as it is.

after two half lives or 200 years , the rock will be 200 years old.

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Answer:Hereditary information is contained in genes, located in the chromosomes of each cell. Each gene carries a single unit of information. An inherited trait of an individual can be determined by one or many genes, and a single gene can influence more than one trait.

Explanation:

According to table N, the isotopes uranium-238 and uranium-235 have different half lives.

Radioactive nuclides are those nuclides that are able to undergo radioactive decay. They have specific modes of decay that is peculiar to each isotope.

Hence, according to table N, the isotopes uranium-238 and uranium-235 have different half lives.

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Combined gas equation: P1V1/T1 = P2V2/T2

Solving for V2:

V2 = P1V1T2/P2T1

T1 = 20 °C = 293.15 K

T2 = 30 °C = 303.15 K

V2 = (1.5 × 3.0 × 303.15)/(2.5 × 293.15)

V2 = 1.86 L

Answer:

Explanation:

I have only answered the blue boxed parts:

Amines are weak bases because they can accept protons from other things.

Sugars is neither acidic nor basic (cuz its not ionic)

Carboxylic acid are weak acids (not bases) cuz they donate protons to other things.

Answer:

Y E S

Explanation:

Hibiscus tea has plenty of skin care qualities, from helping your natural levels of collagen and elastin to reducing breakouts to balancing oil production. Hibiscus is known for its rich level of antioxidants, including vitamin C and beta-carotene.

I hope this helps ✍(◔◡◔)

Energy is the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other forms.

The detonation of an atomic bomb releases enormous amounts of thermal energy, or heat, achieving temperatures of several million degrees in the exploding bomb itself. This thermal energy creates a large fireball, the heat of which can ignite ground fires that can incinerate an entire small city.

When the circuit is complete, there is a flow of charge (electric current). The electrons moving through the wire transfer energy to the wire in the form of heat. The particles in the wire, therefore, have more kinetic energy and so the temperature increases.

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Answer:ss

Explanation:ss

111 cchuyttrfgh

tyujklkjhgt

Answer:

[tex]\displaystyle \text{p} K_a \approx 3.856[/tex]

Explanation:

Because 3.005 grams of potassium lactate is added to 100. mL of solution, its concentration is:

[tex]\displaystyle \begin{aligned} \left[ \text{KC$_3$H_$_5$O$_3$}\right] & = \frac{3.005\text{ g KC$_3$H_$_5$O$_3$}}{100.\text{ mL}} \cdot \frac{1\text{ mol KC$_3$H_$_5$O$_3$}}{128.17 \text{ g KC$_3$H_$_5$O$_3$}} \cdot \frac{1000\text{ mL}}{1\text{ L}} \\ \\ &= 0.234\text{ M}\end{aligned}[/tex]

By solubility rules, potassium is completely soluble, so the compound will dissociate completely into potassium and lactate ions. Therefore, [KC₃H₅O₃] = [C₃H₅O₃⁺]. Note that lactate is the conjugate base of lactic acid.

Recall the Henderson-Hasselbalch equation:

[tex]\displaystyle \begin{aligned}\text{pH} = \text{p}K_a + \log \frac{\left[\text{Base}\right]}{\left[\text{Acid}\right]} \end{aligned}[/tex]

[Base] = 0.234 M and [Acid] = 0.500 M. We are given that the resulting pH is 3.526. Substitute and solve for pKₐ:

[tex]\displaystyle \begin{aligned} (3.526) & = \text{p}K_a + \log \frac{(0.234)}{(0.500)} \\ \\ 3.526 & = \text{p}K_a + (-0.330) \\ \\ \text{p}K_a & = 3.856\end{aligned}[/tex]

In conclusion, the pKₐ value of lactic acid is about 3.856.

Answer: 0.01 M

Explanation:

[tex]M_{A}V_{A}=M_{B}V_{B}\\(26.1)(0.505)=(1950)M_{B}\\M_{B}=\frac{(26.1)(0.505)}{1950} \approx \boxed{0.01 \text{ M}}[/tex]

The  properties which keep the water temperature from changing much are;

The specific heat capacity is the property of a substance that shows how much its temperature changes when it is exposed to heat.

Thus, the  properties which keep the water temperature from changing much are;

Missing parts:

A red-hot iron nail is immersed in a large bucket of water. Although the nail cools down sufficiently to be held bare-handed, the temperature of the water barely increases. Which properties keep the water temperature from changing much?

A.) water's high heat conductivity

B.) water's high specific heat capacity

C.) the iron nail's high heat conductivity

D.) the large mass of water

E.) the iron nail's high specific heat capacity

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Answer: waters high specific heat capacity the large mass of water

Explanation:

i got it right

Answer:

A chemical property example is fire.

Explanation:

Hope this helps!

Answer:

Chemical properties because if it was physical property then it will glow in dark

0.4 atm pressure exerted by oxygen if 80% of the gas pressure is exerted by the nitrogen.

Pressure is defined to be the amount of force exerted per area

80% of pressure is exerted by nitrogen gas.

So, 20% of pressure will be exerted by oxygen gas.

20% of 2.0 atm = 0.4 atm

Hence, 0.4 atm pressure exerted by oxygen if 80% of the gas pressure is exerted by the nitrogen.

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Answer:

See below ~

Explanation:

A to B

⇒ Solid Phase

==========================================================

B to C

⇒ Melting

==========================================================

C to D

⇒ Liquid Phase

==========================================================

D to E

⇒ Vaporizing

============================================================

E to F and beyond

⇒ Gas Phase

Answer: nitrogen

Explanation:

From the equation, we know that for every 3 moles of hydrogen consumed, 1 mole of nitrogen is consumed.

Therefore, nitrogen is the limiting reactant.

The name of CuO is Copper(II) oxide have the two most common oxidation states of copper are +2 and +1.

Copper oxide is a trace element for the zootechnical and agricultural sector. Cupric oxide is also used as a raw material for the production of catalysts and pigments in the field of ceramics, glass and plastics.

This compound makes two different types of bonds being the hydrogen bond when it's a hydrogen and covalent bond when we have an oxygen or a nitrogen.

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Taking into account definition of percent yield, the percent yield for the reaction is 82.56%.

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

[tex]percent yield= \frac{actual yield}{theorical yield}x100[/tex]

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Percent yield for the reaction in this case

In this case, you know:

Replacing in the definition of percent yields:

[tex]percent yield= \frac{0.71 g}{0.86 g}x100[/tex]

Solving:

percent yield= 82.56%

Finally, the percent yield for the reaction is 82.56%.

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From the calculations, we can see that, the change in the freezing point is -0.634°C.

The term freezing point refers to the temperature at which a liquid is changed to solid.

Given that;

ΔT = K  m i

Number of moles sucrose = 35.0 g/ 342.30 g/mol = 0.1 moles

molality =  0.1 moles/ 300.0 * 10^-3 Kg

= 0.33 m

Thus;

ΔT = -1.86°C/mol *  0.33 m * 1

= -0.634°C

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