The mass of the rock is, m = 24 kg
The velocity of the rock is, v = 2 m/s
The kinetic energy of the rock can be given by the formula
[tex]K\mathrm{}E\mathrm{}=\frac{1}{2}mv^2[/tex]Substituting the values, the kinetic energy will be
[tex]\begin{gathered} K\mathrm{}E.=\frac{1}{2}\times24\times(2)^2 \\ =48\text{ J} \end{gathered}[/tex]a fast moving object has/ a potential energy \ b or more kinetic energy
Answer:
Faster-moving objects have more kinetic energy than slower objects.
Explanation:
A faster-moving object has:
a. more potential energy
b. more kinetic energy
c. equal kinetic and potential energies
d. energy based on the weight of the object
Hope this helps.
Answer with explanation pls
Car moves 3m after 5 seconds.
What is a Straight Line Motion?If an object's location changes over time in respect to its surroundings, it is said to be in motion. An object's position changes over time. There is just one kind of motion, and that is linear motion.
Immediately Speed and Immediately Velocity:Immediately Speed. Instantaneous speed is the velocity of an item at a certain instant in time.
A particle's instantaneous velocity is its speed at any given moment in time or location along its route.
Final velocity: 0 m/s
Initially moving at 15 m/s
Acceleration equals 2 m/s^2.
Arrange to address the time problem:
t = 5 seconds
Use the following to calculate an distance at a constant rate:
Distance is equal to ( Vf +Vo)/ Time
Distance: (0 + 15 m/s)/ 5 sec
d=3-meter distance
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The character laying on the ground has just been burnt by a chemical known as potassium hydroxide, made from a potassium atom, an oxygen atom, and a hydrogen atom. This means that potassium hydroxide (like most substances) is a _____.
This means that potassium hydroxide is a Compound. Option A.
Water is formed from the chemical combination of hydrogen and oxygen. A water molecule is a chemical bond of two hydrogen atoms and one oxygen atom. Hydrogen polyoxides, also called oxidants oxyhydrogen or explosive gases, are composed only of hydrogen and oxygen atoms, joined only by single bonds, are saturated and acyclic, and have a molecular structure containing no rings or loops increase.
Hydrogen is an element consisting of a group of hydrogen atoms, and oxygen is an element consisting of oxygen atoms. But water is a compound of water molecules. Molecules that make up a compound are made up of different types of atoms, but molecules can also be made up of the same type of atoms. Two hydrogen atoms and one oxygen atom combine to form water. two hydrogen atoms and two oxygen atoms combine to form hydrogen peroxide,
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a person stands at the base of a hill that is a straight incline making an angle with the horizontal (fig. 3-48). for a given initial speed vq, at what angle 0 (to the hori- zontal) should objects be thrown so that the distance d they land up the hill is as large as possible?
θ = sin⁻¹√2gd
V2 = u2 + 2as is derived from one of the equations of motion, which is equation 1.
The initial velocity u would change to V0 sin because the item is moving at an angle of to the horizontal and the acceleration a would change to -g since the object is going against gravity.
Equation 1 would yield the following results if we entered all these parameters:
(u sin )2 - 2gd = v2
(u sin )2 equals 2gd
(u sin )2/2g = d
sin² θ = 2gd
sin θ = √2gd
θ = sin⁻¹ √2gd
The rate at which the velocity of an object changes in relation to time is known as acceleration. They are accelerations and vector quantities. The object's acceleration is determined by the direction of the net force acting on it.
All objects with mass or energy are attracted to one another by gravity, which is a fundamental interaction.
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A blimp is travelling above the surface of Jupiter at a height of 3.9km. Assuming g on Jupiter is 24.5N/kg, find the mass of the blimp if its gravitational potential energy store is 2.8MJ.
Explanation:
what does kinetic theory of matter state
a block with mass m1 is placed on an inclined plane with slope angle α and is connected to a second hanging block that has mass m2 by a cord passing over a small, frictionless pulley. the coefficient of static friction is μs and the coefficient of kinetic friction is μk
The mass m2 for which block m1 moves up the plane at constant speed once it is set in motion is:
m2 = m1 (sinα + μkcosα)
The tension in the cord should be [tex]m_{2}[/tex]g so the that the hanging block over a frictionless pulley can move at constant speed. This tension in the cord should the component of gravitational force and the force of friction.
Now
[tex]m_{2}[/tex]g = ([tex]m_{1}[/tex]g(sinα) +μk([tex]m_{1}[/tex]g)cosα)
[tex]m_{2}[/tex]g = [tex]m_{1}[/tex]g(sinα +μkcosα)
[tex]m_{2}[/tex] = [tex]m_{1}[/tex] (sinα + μkcosα)
So the mass [tex]m_{2}[/tex] for which m1 moves up the plane at constant speed once it is set in motion is:
m2 = m1 (sinα + μkcosα)
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I will gib brainlyest or whatever.
A cannonball is launched from the top of a 35m cliff at an angle of 11.2 degrees above the horizontal with a velocity of 153m/s. Find:
a. How far it goes
b. How high it goes
c. How long it's in the air
d. Its final velocity
Answer:
Range of the projectile: approximately [tex]1.06 \times 10^{3}\; {\rm m}[/tex].
Maximum height of the projectile: approximately [tex]80\; {\rm m}[/tex] (approximately [tex]45.0\; {\rm m}[/tex] above the top of the cliff.)
The projectile was in the air for approximately [tex]7.07\; {\rm s}[/tex].
The speed of the projectile would be approximately [tex]155\; {\rm m \cdot s^{-1}}[/tex] right before landing.
(Assumptions: drag is negligible, and that [tex]g = 9.81\; {\rm m\cdot s^{-1}}[/tex].)
Explanation:
If drag is negligible, the vertical acceleration of this projectile will be constantly [tex]a_{y} = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}[/tex]. The SUVAT equations will apply.
Let [tex]\theta[/tex] denote the initial angle of elevation of this projectile.
Initial velocity of the projectile:
vertical component: [tex]u_{y} = u\, \sin(\theta) = 153\, \sin(11.2^{\circ}) \approx 29.71786\; {\rm m\cdot s^{-1}}[/tex]horizontal component: [tex]u_{x} = u\, \cos(\theta) = 153\, \cos(11.2^{\circ}) \approx 150.086\; {\rm m\cdot s^{-1}}[/tex].Final vertical displacement of the projectile: [tex]x_{y} = (-35)\; {\rm m}[/tex] (the projectile landed [tex]35\: {\rm m}[/tex] below the top of the cliff.)
Apply the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find the final vertical velocity [tex]v_{y}[/tex] of this projectile:
[tex]{v_{y}}^{2} - {u_{y}}^{2} = 2\, a_{y}\, x_{y}[/tex].
[tex]\begin{aligned} v_{y} &= -\sqrt{{u_{y}}^{2} + 2\, a_{y} \, x_{y}} \\ &= -\sqrt{(29.71786)^{2} + 2\, (-9.81)\, (-35)} \\ &\approx (-39.621)\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
(Negative since the projectile will be travelling downward towards the ground.)
Since drag is negligible, the horizontal velocity of this projectile will be a constant value. Thus, the final horizontal velocity of this projectile will be equal to the initial horizontal velocity: [tex]v_{x} = u_{x}[/tex].
The overall final velocity of this projectile will be:
[tex]\begin{aligned}v &= \sqrt{(v_{x})^{2} + (v_{y})^{2}} \\ &= \sqrt{(150.086)^{2} + (-39.621)^{2}} \\ &\approx 155\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].
Change in the vertical component of the velocity of this projectile:
[tex]\begin{aligned} \Delta v_{y} &= v_{y} - u_{y} \\ &\approx (-39.621) - 29.71786 \\ &\approx 69.3386 \end{aligned}[/tex].
Divide the change in velocity by acceleration (rate of change in velocity) to find the time required to achieve such change:
[tex]\begin{aligned}t &= \frac{\Delta v_{y}}{a_{y}} \\ &\approx \frac{69.3386}{(-9.81)} \\ &\approx 7.0682\; {\rm s}\end{aligned}[/tex].
Hence, the projectile would be in the air for approximately [tex]7.07\; {\rm s}[/tex].
Also the horizontal velocity of this projectile is [tex]u_{x} \approx 150.086\; {\rm m\cdot s^{-1}}[/tex] throughout the flight, the range of this projectile will be:
[tex]\begin{aligned}x_{x} &= u_{x}\, t \\ &\approx (150.086)\, (7.0682) \\ &\approx 1.06 \times 10^{3}\; {\rm m} \end{aligned}[/tex].
When this projectile is at maximum height, its vertical velocity will be [tex]0[/tex]. Apply the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find the maximum height of the projectile (relative to the top of the [tex]35\; {\rm m}[/tex] cliff.)
[tex]\begin{aligned}x &= \frac{{v_{y}}^{2} - {u_{y}}^{2}}{2\, a} \\ &\approx \frac{0^{2} - 29.71786^{2}}{2\, (-9.81)} \\ &\approx 45.0\; {\rm m}\end{aligned}[/tex].
Thus, the maximum height of the projectile relative to the ground will be approximately [tex]45.0\; {\rm m} + 35\; {\rm m} = 80\; {\rm m}[/tex].
Give an example of periods (periodic table)
Answer:
helium, hydrogen, nitrogen, oxygen,iron,uranium,
Explanation:
there are 118 elements but here are some
This is easy but help
1. Distance covered 200 Meters
2. Displacement 100 Meters
3. Displacement from starting position 0 Meters
What is Distance?Distance is the sum of an object's movements, regardless of direction. Regardless of an object's starting or ending position, distance can be defined as the amount of ground it has covered.
Displacement: What is it?Displacement refers to the idea that something has moved or been shifted. The term "displacement" refers to a shift in an object's position.
According to the given information;Solution.1 -Natasha sprints 100m and walks back to the starting position 100m. 100m+-100m= - 200m
Therefore, the answer is 200
Solution.2 - Natasha sprints towards finishing line 100m then her displacement is 100m from starting line.
Solution.3 -Natasha sprints 100m towards Finishing line then walked back to starting line then her displacement is
100m - 100m =0 meters
Therefore the answer is 0 meters
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If you apply a force of 10 N to a box and push it 10 min 10 s. how much power didyou deliver?
10 watt power will be delivered to push the box for 10 min 10 seconds by applying force of 10N to a box .
What is power and how much is delivered to push the box for 10 minutes 10 second?Power is the energy we exert per unit time. Also power is the product of voltage supply and current.Though power have lots of definitions in its own way , here we talk about the power which is the work unit time.Given is the force which is 10 N and the time that is 10 min 10 second .Now applying the formula P= work/time , that is 100Nm/10s = 10 watt.Work have been calculated as the product of force and displacement = 10N X10m =100Nm.To know more about power visit:
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neglecting air resistance, after a rock thrown straight up reaches the top of its path and then falls a short distance, its acceleration is group of answer choices more than at the top of its path. the same as at the top of its path. less than at the top of its path.
if a rock is thrown straight up and falls, then its acceleration is the same as at the top of its path and it is equal to g, the gravitational acceleration.
If an object is moving straight vertically, the acceleration is constant along its trajectory, either it moves upward or downward. It is the velocity that changes.
If the object is moving upward, the velocity decreases, until at the top position, the velocity is equal to zero. The acceleration is constant and it is equal to g, the gravitational acceleration.
v(t) = vo - gt
Where:
v(t) is the velocity at time t
vo is the initial velocity
If the object is moving downward, the velocity increases. Again, the acceleration is constant and it is equal to g, the gravitational acceleration.
v(t) = vo + gt
This situation is depicted on the attaches picture.
Hence, if a rock is thrown straight up and falls, then its acceleration is the same as at the top of its path and it is equal to g, the gravitational acceleration.
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A cannon ball is fired horizontally from a cannon sitting on a cliff with a velocity of 30 m/s. The cannon ball lands 533 meters away. How long (t) was the cannon ball in the air?
The time that the cannon ball spends in the air is 17.7 seconds.
What time does the cannon ball spend in the air?The cannon ball in flight is a projectile.
Projectiles are objects that follow a parabolic path during their motion.
The time that the cannon ball spends in the air is calculated as follows:
The cannon ball is released with a horizontal velocity, u = 30 m/s
The cannon ball travels a horizontal distance, d = 533 m
When the cannonball was fired, it undergoes two types of motion:
a vertical downward motion at constant acceleration due to gravitya horizontal motion with initial velocity, u = 30 m/s and final velocity, v = 0 m/sThe time spent in the air or time of flight, t, is the same for both the horizontal and vertical motion of the cannonball.
Horizontal distance = velocity * timetime = Horizontal distance / velocityTime = 533 / 30
Times spent in the air = 17.7 seconds.
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Is sonic faster than flash
Answer: Flash
Explanation:
sonic can run 767mph
the flash can run roughly 8.3 million mph
Answer:
Sonic.
Explanation:
There is no direct answer, but Sonic leaves a bigger trail behind him than flash and Sonic has a boost and power-ups.
8. Which statements are true about why wind tends to blow from over the water to over the land on a sunny day? Highlight all the statements that apply.
A. Air over the water is cooler than air over the land is.
B. The air above the land has greater density.
C. The wind is caused by differences in density.
D. Cool, dense air from over the water flows toward the land, pushing warm air upward.
Wind tends to blow from over the water to over the land on a sunny day because air over the water is cooler than air over the land is, the wind is caused by differences in density and the cool, dense air from over the water flows toward the land, pushing warm air upward. Making option A, C, and D the right answer to the question.
What is sea breeze?
The phenomenon where wind tends to blow from over the water to over the land on a sunny day is referred to as sea breeze.
The heat from the sun heats up the faster than water. Subsequently, air over land heats up faster than air over water, thus air above land becomes lighter causing the pressure to decrease.
In summary, Option B is wrong because the air above the land has a lesser density compared to the air above the water, and this is due to the characteristics of the wind blowing from a higher pressure area to a lower pressure area.
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when trying to stop a car on icy pavement in as short a distance as possible, is it better to slam on the brakes and skid to a stop or apply the brakes more gently and roll to a stop?
Tapping the brakes is almost definitely going to be better than not tapping the brakes.
Using the brakes causes the static friction between your tires and the road to increase; which slows down the car more.
The issue is that when the grip between the brakes and the tire is too strong, the coefficient of friction between the tires isn't high enough to maintain that static contact. This is when the wheels "lock up" and begin to skid. As you mention, kinetic friction is less than static friction, so wheel lock and skidding should be avoided.
This means that tapping the brakes is generally the best braking method in these conditions, as compared to not braking at all.
When considering modern vehicles, your friend missed the mark even more. Most vehicles sold now (as far as I know) have an ABS, an Anti-lock Braking System which actually disengages the brakes when they reach the threshold when you start to lose traction. Basically, you can push down on the brake pedal as hard as you want, and you can feel the brakes start "tapping" on their own, to prevent skidding, increase traction, and allow you to brake in the lowest space possible. Tapping is the method most cars automatically employ on icy surfaces, and if you try it for yourself (in a controlled environment), you will find that tapping the brakes should slow you down a lot faster than not pressing it at all; especially if you avoid skidding.
Hence,
Tapping the brakes is almost definitely going to be better than not tapping the brakes.
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3. Alice and Kai were playing air hockey, which is a game where players hit a puck with paddles so the puck slides across
a table. After the game, they were crashing the puck and two different paddles. The puck was the same in both crashes,
but the paddles were different: the red paddle had less mass, while the purple paddle had more mass. Use the
information in the diagram to answer.
In which crash did the puck experience a stronger force? Why?
The crash in which the puck experience a stronger force is Crash 2 because the force on the purple paddle was stronger in this crash, so the force on the puck was also stronger. That is option B.
What is force?Force is defined as the pull or a push that is experienced by an object when it passes through a distance.
According to Newton's second law of motion that states that the force on an object is equal to its mass times its acceleration.
Therefore, force can also be defined as the product of mass and acceleration. That is, F = mass× acceleration.
This shows that force is directly proportional to mass. Therefore increase in the mass of an object will require more force to bring about its movement.
Therefore, the purple paddle has a greater mass with a stronger force leading to a stronger crash.
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Complete question's options:
The puck did not experience a force; only the paddles experienced a force in the crashes.
Crash 2; the force on the purple paddle was stronger in this crash, so the force on the puck was also stronger.
The diagram doesn’t tell you anything about the force on the puck. It only gives information about the force on the paddles.
The puck experienced the same force in both crashes. The paddles changed speed by the same amount in each crash, so the force on the puck was the same each time.
Iridium is a substance found only in asteroids and other space objects. This graph shows the amount of Iridium found in different sediment layers of Earth. They are marked off into 17 sections representing time.
Iridium Levels graph shows Iridium levels in sediment layers. Beginning at sediment layer 1, iridium levels remain between 0 and 5, jumping to a level of 23 between layers 5 and 6, and decreasing to near starting levels at layers 14 through 17.
What most likely happened in sediment layer 5?
A massive volcano erupted, causing global warming and lava flow, which in turn caused mass extinction.
More iridium was produced by space objects and dumped by local factories.
The impact of a space object led to the deposit of a layer of sediment high in iridium.
Fewer impacts lead to a drop in iridium levels and a mass extinction caused by a lack of sunshine.
The most likely thing that happened in the sediment layer 5 is that A. The massive volcano erupted, causing global warming and lava flow, which in turn caused mass extinction.
What is the information about?The element iridium is only present in asteroids and other outer space objects. The amount of iridium present in various Earthly sediment layers is depicted an divided into 17 portions to illustrate the passage of time.
Iridium is a plentiful element in outer space, especially in asteroids. The Alvarez Hypothesis provides support for this response. The most potent nuclear bomb ever exploded only released a fraction of the energy that a large asteroid that struck the earth would have.
Global flames caused by this heat made the earth completely dark.
The creation of a dust cloud was the cause of this obscurity. The lack of sunshine also caused the vegetation to disappear, which in turn led to a global extinction.
In conclusion, the correct option is A.
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Using energy considerations, calculate the average force a 60. 0-kg sprinter exerts backward on the track to accelerate from 2. 00 to 8. 00 m/s in a distance of 25. 0 m, if he encounters a headwind that exerts an average force of 30. 0 n against him.
Answer:
−102 N
Explanation:
Hope this helps.
What does mass of an object depend on
Answer:
the inertia of an object
What is the minimum wave amplitude amin such that the ant will become momentarily weightless at some point as the wave passes underneath it? assume that the mass of the ant is too small to have any effect on the wave propagation.
The ant will become weightless when the normal force between the string and the ant becomes zero .
What is the explanation?On the center of a tightrope used in circus acts, a sizable ant is standing. A rope has mass for every unit of length. A tightrope walker steps up and down at the end of the tightrope in an attempt to shake the ant off the rope, creating a sinusoidal transverse wave of wavelength and amplitude A.
Assume that g is the gravity-induced acceleration's force. What is the smallest wave amplitude Amin required for the ant to briefly lose its weight while the wave passes beneath it? Assume that the ant's bulk is insufficient to affect the wave's propagation in any way. In terms of Ts,, g, and the smallest wave amplitude, write the expression.
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URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS
The chemical equation shown below is not balanced (it does not follow the Law of Conservation of Matter).
The answer is 2 because the Hydrogen atom on the right needs 2 to balance with the one on the left
Students measured the temperature of the water at different depths in lake hale and found that the temperature varied
The independent variable in this condition of a varied temperature of the lake include the following:
DepthSun intensity.What is Independent variable?This is the type of variable which doesn't depend on the condition of others and is usually altered by scientists so as to causal effects on the other types of variables which are present in the experiment.
In this scenario, the independent variables are those which are responsible for the temperature difference of the Lake hale and they include the depth and sun intensity. An increase in depth means the temperature will be lower while an increase in sun intensity means increase in temperature.
The dependent variable is the temperature which is affected by the changes in the parameters listed above.
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The other part of the question is:
What is the independent variable?
based on law of conservation of mass: when you burn a candle, all that remains is a small puddle of wax. the puddle of wax has less mass than the original candle. the rest of the original candle’s mass was :
The rest of the original candle’s mass was changed to gases.
What is law of conservation of mass?The law of conservation of mass states that during a chemical reaction in an enclosed medium that there is neither generation or lost if it's mass but that it can be transformed.
Mass is defined as the scalar quantity that defines the quantity of matter found in a particular component or object.
The candle is made up of carbonic compounds that decreases in mass to form a puddle of wax when burnt.
The original mass of the candle was not lost but while some where converted to puddle of wax the rest escaped as gas to the atmosphere.
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3. Find the resultant of the following two displacements 2m at 30⁰ and 4m
at 120⁰. The angles are taken relative to X - axis.
2m
K.
30⁰
4m
600
120°
The resultant of the two displacements 2m at 30⁰ and 4m
at 120⁰ is 93.4 degree.
Describe displacement.Displacement is the process of removing something from its usual location or position and substituting another object in that space.
Given: The sum of the displacements at 30 degrees and 120 degrees, respectively, is 2 meters.
Currently, there are two displacements, which
R1 = 2 cos 30 – 4 cos 60
= 2 x √3 / 2 – 4 x 1 / 2
= √3 - 2
= 1.732 - 2
= - 0.268 m
R2 = 2 sin 30 + 4 sin 60
= 2 x 1/2 + 4 x √3 / 2
= 1 + 2 √3
= 1 + 2 (1.732)
= 1 + 3.464
= 4.464 m
Now R = √R 1^2 + R2^2
= √(-0.268)^2 + (4.464)^2
= √0.0718 + 19.927
= √19.999
= 4.472 m
Now tan Q = R 2 / R1
= 4.464 / - 0.268
= - 16.656
Or Q = - 86.6 degree
Now the outcome will be 180 – 86.6 = 93.4 degree
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A company is creating a new mosquito repellent, and needs to figure out how much is needed to stop mosquito bites. They find volunteers from the nearby college. Each person is given either 1mL, 2mL, or 3mL of the repellent to rub on their arm. Some volunteers are given no repellent. Each person is then put in a room with mosquitoes for 10 minutes. Numbers of bites are measured for each volunteer.
In Experiment 1 above, what is the independent variable?
The independent variable is the different amount of repellent each person is given. This is because it does not depend on any variable. The dependent variable is what they are measuring, which would be the number of bites on each volunteer.
I hope this helps! :)
determine the minimum coefficient of static friction μs which will allow the drum with fixed inner hub to be rolled up the 15° incline at a steady speed without slipping. what are the corresponding values of the force p and the friction force f?
The ratio of the greatest static friction force (F) between the surfaces in contact before movement starts to the normal force (N) is known as the coefficient of static friction.
Create an inclination plane out of one of the materials, then place a body made of the other material on it to determine the minimum coefficient of static friction between the two. Up until the body begins to slide, steepen the incline. The coefficient of friction is the angle's tangent.
A body of mass m experiences both a horizontal and a vertical component of gravity when you increase the incline.
Applying Newton's Law to each of them right before the body begins to move reveals that Fx = max is the value for the horizontal component, which acts in the x-direction.
The same holds true for the y-axis: Fy = may.
F on one side and umg on the other will exert forces on the body of mass "m."
Write the formula as F-umg=ma.
In the direction F is acting, the force on mass "2m" will be umg. (Observe how the frictional force acts on mass "m" on the left side and mass "2m" on the opposite side.)
Formula: umg=2ma
The acceleration of both bodies should be the same for a no-slip condition; to find the solution, simply substitute the acceleration from equation (2) into number 1.
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a 1,900-kg pile driver is used to drive a steel i-beam into the ground. the pile driver falls 4.80 m before coming into contact with the top of the beam, and it drives the beam 13.4 cm farther into the ground as it comes to rest. using energy considerations, calculate the average force the beam exerts on the pile driver while the pile driver is brought to rest.
The average force of the beam expert is 648,365.
What is average force?The force delivered to a body traveling at a specific speed for a specific amount of time is known as the average force. Since it possesses both momentum and direction, it is primarily a vector quantity. It differs between momentum and net force.
Average force is the force exerted by a body moving at a specific speed for a specific amount of time.
mass of pile driver (m) = 1900 kg
distance of pile driver to steel beam (s) = 4.80m
depth of steel driven (d) = 13.4= 0.134 m
acceleration due to gravity (g0 = 9.8 m/s^{2}
calculate the average force exerted on the pile driver by the beam.
from work done = force x distance
work done = change in potential energy of the pile driver
equating the two equations above we have
force x distance = m x g x (s - d)
f x 0.134= 1900 x 9.8 x (4.80- (-0.134))
d = - 0.134because the steel beam went down at we are taking its
initial position to be an origin point which is 0
f = ( 1900x 9.8 x (4.80- (-0.134)) ) ÷ 0.134
=648,365
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little girl tosses an apple up toward a boy in a tree with an initial velocity of 8.50 m/s at 72o.
A. What is the maximum height reached by the apple
The maximum height reached by the apple thrown with an initial velocity of 8.50 m / s at 72° is 6.65 m
H = u² sin²θ / g
H = Maximum height
u = Initial velocity
g = Acceleration due to gravity
u = 8.5 m / s
g = 9.8 m / s²
θ = 72°
H = 8.5² sin² ( 72° ) / 9.8
H = 72.25 * 0.9 / 9.8
H = 6.65 m
If an object is thrown with an initial velocity at angle with the ground, it will move in a projectile motion. The object thrown is called as a projectile.
Therefore, the maximum height reached by the apple is 6.65 m
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a small button placed on a horizontal rotating platform with diameter 0.530 m will revolve with the platform when it is brought up to a speed of 39.0 rev/min , provided the button is no more than 0.230 m from the axis.
To begin, change the rotational speed () to rev/sec: 13/20 revs per second is equal to 39 revs per minute multiplied by 1 minute and 60 seconds.
The equation is then updated with all the values: = rw^2/g\s
=(0.230*13/20)/9.8
=0.015255
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#SPJ4
An engine of a train has to apply a force of 4000 newton to overcome friction. To run at a uniform rate of 60km/hr, What is the power developed by the engine?
Answer:
Power = 4000×60× 5/18
Explanation:
The reason for this result is because:
power=force × velocity.
This means that power = 400 × 60 × 5/18