Answer:
To find the mean of a given data set, add up all the values then divide by how many numbers ...
Step-by-step explanation:
Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4x and y = 2x−2 intersect are the solutions of the equation 4x = 2x−2. (4 points)
Part B: Make tables to find the solution to 4x = 2x−2. Take the integer values of x between −3 and 3. (4 points)
Part C: How can you solve the equation 4x = 2x−2 graphically? (2 points)
(10 points)
Answer:
Step-by-step explanation:
A: The expression 4x = 2x - 2 reduces to x = -1. This is true for all values of y, since y is not a factor in this expression.
The two other equations intersect at point (-1, -4). See the attached graph (Solutions2)
y = 4x
y = 2x−2
============
Mathematically, we can substitute the value of y from the first equation into the second:
y = 2x−2
(4x) = 2x−2
2x = -2
x = -1
The intersection of this two lines is (-1,-4). Since x=-1, this is also the solution to 4x=2x-2, as per the above.
B: See attached Result Table
C: See GraphEquation2
On the set of axes below, graph f(x) = |x - 3| + 2.
The attached graph represents the graph of the function f(x) = |x - 3| + 2
How to graph the function?The equation of the function is given as:
f(x) = |x - 3| + 2
The above equation is an absolute value function, and it has the following parameter:
Vertex = (3,2)
Next, we plot the graph of the function (see attachment)
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Use the information below for 6 and 7. Data was collected on hours per week spent doing homework by the students in two classes.
Answer:
A its becuase im rewlly smart
Please Help I Don't Understand!
Answer:
D) None of the choices are correct.
Explanation:
Given triangles AHL and NKG
Sides which are congruent:
AH and NKHL and KGAL and NGSo, AHL ≅ NKG. There are no such options.
What are the roots of the polynomial equation x superscript 4 baseline x cubed = 4 x squared 4 x? use a graphing calculator and a system of equations. –2, –1, 0, 2 –2, 0, 1, 2 –1, 0 0, 1
Polynomial is an expression that consists of indeterminate(variable) and coefficients. The roots of the given polynomial are -2, -1, 0, and 2.
What are polynomials?Polynomial is an expression that consists of indeterminate(variable) and coefficient, it involves mathematical operations such as addition, subtraction, multiplication, etc, and non-negative integer exponential.
The roots of the given polynomial when plotted on graph are the point at which the graph intersect the x-axis. Therefore, the roots of the given polynomial is,
x = -2, -1, 0, 2
Hence, the roots of the given polynomial are -2, -1, 0, and 2.
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Answer:
It's A. -2, -1, 0, 2
Step-by-step explanation:
Answer gets brainlist
If x=3 and y=-2, the value of -2xy³ is
A 10
B -48
C -96
D 40
Answer:
B
Step-by-step explanation:
if
x=3
y=2
-2xy²
3
2³=8
-2×3×8
= -48
Which choice is it down below?
Answer:
B. AC > AB
Step-by-step explanation:
AC is the longest line and AB is shorter than AC
Write the equation in slope - point form using the following information.
m = [tex]\frac{2}{5}[/tex] and point (-10, 1). Then, convert it to general form.
Answer:
[tex]\sf 2 x-5y +25=0[/tex]
Explanation:
Given points: (-10, 1)slope: 2/5Equation:
[tex]\dashrightarrow \sf y - y_1 =m(x - x_1)[/tex]
[tex]\dashrightarrow \sf y - 1 = \dfrac{2}{5} (x - (-10))[/tex]
[tex]\dashrightarrow \sf y = \dfrac{2}{5} x +4 + 1[/tex]
[tex]\dashrightarrow \sf y = \dfrac{2}{5} x +5[/tex]
[tex]\dashrightarrow \sf 5y = 2 x +25[/tex]
[tex]\dashrightarrow \sf 2 x-5y +25=0[/tex] General form: ax + by + c = 0Please Help I Don't Understand
Step-by-step explanation:
please Mark me brainlist!!
What is the measure of angle B in the figure below?
A
3
B
D
3√√2
C
O 30°
O 45°
O 60°
O 90°
In triangle ABC, points D and E are on sides AB and BC, respectively,
such that DE | AC, and AD:DB = 3:5.
If DB = 6.3 and AC = 9.4, what is the length of DE, to the nearest
tenth?
The length of DE in the triangles is 5.9
How to determine the length of DE?The given parameters are:
DB = 6.3
AC = 9.4
AD : DB = 3 : 5
Substitute DB = 6.3 in AD : DB = 3 : 5
AD : 6.3 = 3 : 5
Express as fraction
AD / 6.3 = 3 / 5
Multiply both sides by 6.3
AD = 3.78
The length DE is then calculated using the following ratio:
BD : DE = BA : AC
Where:
BA = BD + AD
This gives
BD : DE = BD + AD : AC
Substitute known values
6.3 : DE = 6.3 + 3.78 : 9.4
Simplify
6.3 : DE = 10.08 : 9.4
Express as fraction
DE/6.3 = 9.4/10.08
Multiply both sides by 6.3
DE = 5.9
Hence, the length of DE is 5.9
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8x+72.8=5x+84.5 solve for x
8x+72.8=5x+84.5
8x-5x = 84.5-72.8
3x = 11.7
x = 3.9
x = {3.9}
3. Jean rides her horse twice a week at Free-
and-Bold Stables. One Monday, she goes
for a horseback ride. She leaves the barn
on her horse at 2:10 PM, and comes back at 2:50 PM. How long was her ride?
the answer is 40 minute's 250-210 is 40
Yusuf and some friends are going to the movies. At the theater, they sell a bag of popcorn for $4 and a drink for $3.25. How much would it cost if they bought 4 bags of popcorn and 8 drinks? How much would it cost if they bought p bags of popcorn and d drinks? Total cost, 4 bags of popcorn and 8 drinks: Total cost, p bags of popcorn and d drinks:
Answer:
$42 would be the correct answer.
need help pls
thank you in advance
Answer:
Mean[tex]\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}[/tex]
[tex]\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10[/tex]
[tex]\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10[/tex]
Standard Deviation[tex]\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}[/tex]
[tex]\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}[/tex]
[tex]\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}[/tex]
SummaryNilo has a mean score of 10 and a standard deviation of 5.23.
Lisa has a mean score of 10 and a standard deviation of 1.83.
The mean scores are the same.
Nilo's standard deviation is higher than Lisa's. Therefore, Nilo's test scores are more spread out that Lisa's, which means Lisa's test scores are more consistent.
Please help me I literally suck at algebra
Answer:
4
Step-by-step explanation:
Given :
f(x) = x² - 6x + 8
=============================================================
Solving :
Splitting the middle term :
⇒ f(x) = x² - 6x + 8
⇒ f(x) = x² - 2x - 4x + 8
⇒ f(x) = x (x - 2) - 4 (x - 2)
⇒ f(x) = (x - 4)(x - 2)
============================================================
Solutions :
⇒ x - 4 = 0 ⇒ x = 4
⇒ x - 2 = 0 ⇒ x = 2
Tom has 12 candies and
eats 2 each minute. sue
has 6 candies and eats 1
every minute. after how
many minutes will they have
the same number of
candies?
Answer: once tom eats 6 candys he will have the same number as sue
Step-by-step explanation:
Answer:
After 6 minutes they will both have 0 candies.
100 PTS PLEASE ANSWER ASAP! <3
[tex]\\ \rm\Rrightarrow g(x)=6(\dfrac{3}{2})^x[/tex]
[tex]\\ \rm\Rrightarrow g(-1)=6(\dfrac{3}{2})^{-1}=6(\dfrac{2}{3})=2(2)=4[/tex]
[tex]\\ \rm\Rrightarrow g(0)=6[/tex]
[tex]\\ \rm\Rrightarrow g(1)=6(\dfrac{3}{2})=3(3)=9[/tex]
[tex]\\ \rm\Rrightarrow g(2)=6\times\dfrac{9}{4}=13.2[/tex]
Attached the graph
Answer:
Given function:
[tex]g(x)=6\left(\dfrac{3}{2}\right)^x[/tex]
To find each of the points, substitute the given values of x into the function:
[tex]x=-1 \implies g(-1)=6\left(\dfrac{3}{2}\right)^{-1}=4[/tex]
[tex]x=0 \implies g(0)=6\left(\dfrac{3}{2}\right)^{0}=6[/tex]
[tex]x=1 \implies g(1)=6\left(\dfrac{3}{2}\right)^{1}=9[/tex]
[tex]x=2 \implies g(2)=6\left(\dfrac{3}{2}\right)^{2}=13.5[/tex]
Therefore:
[tex]\large \begin{array}{| c | c | c | c | c |}\cline{1-5} x & -1 & 0 & 1 & 2 \\\cline{1-5} g(x) & 4 & 6 & 9 & 13.5 \\\cline{1-5} \end{array}[/tex]
As the function is exponential, there is a horizontal asymptote at [tex]y=0[/tex].
Therefore, as [tex]x[/tex] approaches -∞ the curve approaches [tex]y=0[/tex] but never crosses it.
So the end behaviors of the graph are:
[tex]\textsf{As }x \rightarrow - \infty, \:\:g(x) \rightarrow 0[/tex][tex]\textsf{As }x \rightarrow \infty, \:\:g(x) \rightarrow \infty[/tex]Plot the points on the graph and draw a curve through them.
please help, i'm having trouble with this
Answer:
(2,11)
Step-by-step explanation:
What is substitution method?
The substitution method is where you plug in an expression that defines a variable into the other equation so you are left with one variable in which you can solve for.
In order to use the substitution method, one of the variables must be defined by an expression (e.g. x = 8y + 2 , the x is defined by the expression 8y + 2. )
Rearranging terms to define x or y
We have the two equations 2x + y = 15 and 7x - 2y = -8
The equation we would rearrange would likely be 2x + y = 15 as the y is by itself meaning we could easily change a few things to define it.
2x + y = 15
==> subtract 2x from both sides
2x - 2x + y = 15 - 2x
==> simplify
y = 15 - 2x
Plugging ( or substituting ) y's defined expression into the other equation.
Now that we have rearranged the equation to where "y" is being defined we can plug in the expression defined by y into the other equation and then solve for x.
2nd equation : 7x - 2y = -8
==> plug in y = 15 - 2x
7x - 2(15-2x) = -8
==> distribute the 2
7x - 30 + 4x = -8
==> combine like terms
11x - 30 = -8
==> add 30 to both sides
11x = 22
==> divide both sides by 11
x = 2
Substituing the value of x into one of the equations and then solving for y.
Now that we have calculated the value of x we can calculate the value of y by plugging in the value of x into one of the equations and solving for y.
2x + y = 15
==> plug in x = 2
2(2) + y = 15
==> multiply 2 and 2
4 + y = 15
==> subtract 4 from both sides
y = 11
The solution is (2,11)
Checking our work:
To check our work we can plug in the value of x and y into both equations. If both are true then the solution is correct but if one or both are false then the solution is incorrect.
First equation; 2x + y = 15
==> plug in x = 2 and y = 11
2(2) + 11 = 15
==> multiply 2 and 2
4 + 11 = 15
==> add 4 and 11
15 = 15
Second equation; 7x - 2y = -8
==> plug in x = 2 and y = 11
7(2) - 2(11) = -8
==> multiply 7 by 2 and 11 by -2
14 - 22 = -8
==> subtract 22 from 14
-8 = -8
Both are correct therefore (2,11) is the correct solution
Which segment does NOT intersect line AG? Please help.
Answer:
line BC
Step-by-step explanation:
Line BC is the only line that doesn’t touch line AG
For the function h defined by h(x) = 2x² - 2, find h(-1/2).
Answer:
-1.5
Step-by-step explanation:
h(-1/2)=2 [tex](\frac{-1}{2})^{2}[/tex] -2
h(-1/2)= [tex]\frac{1}{2} -2\\[/tex]
h(-1/2)=-1.5
15c² - 5c. Factorise completely
Looking at the problem, what we must do to complete this question is to completely factor the expression that was provided. The expression that was provided is [tex]15c^2 - 5c[/tex].
The first step that we must do is to take a look at the expression and see what the two pieces of the expression have in common. We can see that both [tex]15c^2[/tex] and [tex]-5c[/tex] have the number 5 and the variable c associated with them so we can factor out those two.
Factor out 5c
[tex]15c^2 - 5c[/tex][tex]5c(\frac{15c^2}{5c}) - 5c(\frac{5c}{5c})[/tex][tex]5c(3c) - 5c(1)[/tex][tex]5c(3c - 1)[/tex]Now we have completely factored out the expression that was provided in the problem statement and we came to final answer of [tex]5c(3c - 1)[/tex].
Answer:
5c(3c - 1)
Step-by-step explanation:
Take out the 5c to factor out completely
find the distance and displacement for the following figures :
The figure (i) have a distance of 15.996 meters and a displacement of 13.892 meters and (ii) a distance of 480 centimeters and a displacement of 339.411 centimeters
How to find the distance and displacement in each trajectory
The distance is the sum of the lengths that form a trajectory and the displacement is the distance between the initial and final point of a trajectory. Then, we have the following results for each case:
Case I
Distance
d = 5 m + 0.5π · (7 m)
d ≈ 15.996 m
Displacement
[tex]D = \sqrt{(12\,m)^{2}+(7 m)^{2}}[/tex]
D ≈ 13.892 m
Case II
Distance
d = 8 · (60 cm)
d = 480 cm
Displacement
[tex]D =\sqrt{(240\,cm)^{2}+(240\,cm)^{2}}[/tex]
D ≈ 339.411 cm
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A farmer creates a rectangular pen using part of the wall of a barn for one side of the pen and a total of 130 feet of fencing for the remaining 3 sides, as shown in the diagram. Write and equation which gives the area of the pen, A, as a function of x, the length of fence parallel to the barn
The equation that describes the which gives the area of the pen, A, as a function of x, the length of fence parallel to the barn is A = 130x - x²
How to find area of a rectangle?The pen is rectangular. Therefore,
area of a rectangle = lw
where
l = lengthw = widthTherefore,
perimeter = 2w + l
perimeter = 2w + x
130 = 2w + x
130 - x = 2w
w = 65 - 1/ 2 x
A = xw
A = x(65 - 1/ 2 x)
A = 65x - 1 / 2 x²
Therefore, the function that represents A, the area of the pen is as follows:
A = 130x - x²
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Jake owns stock in a high-tech firm. Each share is currently valued at $61 per share, which is 22% more than Jake paid to purchase it. What did Jake pay per share?
The price per share of the stock of the high-tech firm that was purchased by Jake is $50.
What is the price per share?Percentage is a measure of frequency that calculates the fraction of an amount out of hundred.
What is the price per share of the stock purchased by Jake = current value / ( 1 + percentage increase)
61 / 1.22 = $50
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80% of the sixth-grade students and 20% of the fifth-grade
students at a school went on a field trip. If there are 20 sixth-grade
students and 80 fifth-grade students, what percent of all the fifthgrade and sixth-grade students from this school went on the field
trip? I WILL MAKE U BRAINLISET
What is
5×5×5×5×5×5×5×5×5×5×5×5×5+5×5×5-78+67=
In brianna's homeroom class, 9% of the students were born in march and 40% of the students have a blood type of o+.
what is the probability of a student chosen at random from tania's homeroom class being born in march and having a blood type of o+?
(enter the answer as a percent)
Answer:
3.6%
Step-by-step explanation:
Because the two events are independent, their probabilities are multiplied, so the probability of a student being born in March and having a blood type of O+ is 9% * 40% = 0.09 * 0.40 = 0.036 = 3.6%
two angles forming a linear pair are
Answer:
Two angles forming a linear pair are always supplementary. Linear pair of angles are formed when two lines intersect each other at a single point, and the sum of angles of a linear pair is always equal to 180°.
Step-by-step explanation:
Two angles forming a linear pair are always supplementary. Linear pair of angles are formed when two lines intersect each other at a single point, and the sum of angles of a linear pair is always equal to 180°.
Question :
Two Angles Forming Linear pair are .…............ .Answer :
Two Angles Forming Linear pair are always supplementary ( sum of angles = 180⁰ ) .They are formed when two lines intersect each other at one point and the sum of angles is 180⁰ .
helppp quickkkkkkk enough points
Answer:
[tex]a=2\\\\ b = 20\\\\ c = 47[/tex]
Step by step explanation:
[tex]a(x) = 2(x+5)^2 -3\\\\~~~~~~~=2(x^2 +2 \cdot 5 \cdot x +5^2) -3\\\\~~~~~~~=2(x^2 +10x+25) -3\\\\~~~~~~~=2x^2 +20x +50 -3 \\\\~~~~~~~=2x^2 +20x +47\\\\\text{By comparing}~ 2x^2 +20x +47~ \text{with the standard form}~ ax^2 +bx+c,\\\\a=2,~ b = 20,~ c = 47[/tex]
Answer:
A or 57 7/9ft3
Step-by-step explanation:
13/3x10/3x4/1 = 520/9=57 7/9