The term mole concept is used here to determine the molar mass of an element. The molar mass of the element is 80.62 g/ mol.
What is a mole?One mole of a substance is that quantity of it which contains as many particles or entities as there are atoms in exactly 12 g of carbon -12. The equation which is used to calculate the number of moles is:
The mass of one mole of molecules of a substance is defined as the molar mass. It is generally expressed in g mol⁻¹
Number of moles = Given mass / Molar mass
Here the given mass of the element is 10.4 g. The number of moles of the element is 0.129 mole. Then the molar mass is:
Molar mass = Given mass / Number of moles
= 10.4 g / 0.129 mol
= 80.62 g/ mol
Thus the molar mass of element is 80.62 g/ mol.
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Law of conservation of mass 21 g of A and 21 g of b produce 17 g of c
The fact that 21 g of A and 21 g of B produce 17 g of C does not obey the law of conservation of mass.
What is the law of conservation of mass?The law of conservation of mass states that the mass of a substance can neither be created nor destroyed.
This law further explains that in a chemical reaction, the amount of reactants must be equal to the amount of products in the reaction.
For example, if a substance A of mass 21g reacts with another substance B of mass 21g, the mass of the product C should be 21g + 21g = 42g in order to align with the law of conservation of mass.
However, according to this question, the product C has a mass of 17g, which shows that the law of conservation of mass is not obeyed.
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A certain quantity of helium gas is at a temperature of 27°C and a pressure of 1.00 atm. What will the new temperature be if its volume is doubled at the same time that its pressure is decreased to one-half its original value? (Hint: Three variables have been given so what equation will you use?)
The new temperature of certain quantity of helium gas is at a temperature of 27°C and a pressure of 1.00 atm will be 300 K if its volume is doubled at the same time that its pressure is decreased to one-half its original value.
We will use combined gas law equation to find the new temperature.
We know that
Initial temperature T₁ = 27°c +273 K = 300 K
Initial pressure P₁ = 1.00 ATM
Initial volume V₁ = V
Final volume V₂ = 2 V
Final pressure P₂ = P/2 = 1/2 = 0.5 atm
Now, using the combined gas law equation, which is given as -
P₁V₁ = P₂V₂
T₁ T₂
where,
P₁ = Initial pressure
P₂ = Final pressure
V₁ = Initial volume
V₂ = Final volume
T₁ = Initial temperature
T₂= Final temperature
Avogadro's law states that equal volumes of gases contains equal number of molecules at same temperature and pressure.
P₁V₁T₂ = P₂V₂T₁
Dividing P₁V₁ on both the sides
P₁V₁T₂ = P₂V₂T₁
P₁V₁ P₁V₁
We get,
T₂ = P₂V₂T₁
P₁V₁
Substituting values,
T₂ = 0.5 × 2V × 300 × V
1
T₂ = 300K
Hence, the new temperature is 300 K.
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I need help with the following question
The right answer is (KP)-1/2. Option A.
An expression of the equilibrium constant in terms of partial pressure is denoted as Kp. The equilibrium constant Kp is equal to the partial pressure of the product divided by the partial pressure of the reactant, and the partial pressure increases with a force equal to the coefficient of the substance in the equilibrium equation.
Kp is the equilibrium constant used to express equilibrium concentrations at atmospheric pressure and Kc is the equilibrium constant used to express equilibrium concentrations in molar terms. The relationship between Kp and Kc depends on the change in the number of moles of gaseous reactants and products. Kp has exactly the same form as Kc but partial pressure is used instead of concentration. Gases to the right of the formula are at the top of the print, and gases to the left are at the bottom.
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What is the volume if 58.41g of o2 are pumped into a balloon that is at a pressure of 1183.mmHg and 151.4 degrees F?
The volume of the oxygen into a balloon is, V = 1.70 ml.
Equation :To calculate the volume of the oxygen using the formula
PV = nRT
where,
P is pressure
V is volume
n is number of moles
R is gas constant
T is temperature
So, the known values are :
P = 1183 mmHg
R = 8.314 J/mol
T = 151.4°F = 66.33°C
mass = 58.41g
n = ?
V = ?
While we don't know the value of n but we know mass so we can calculate number of mole by using formula,
n = m / M
That is,
n is number of mole
m is mass
M is molecular mass
Now, putting values in this
n = 58.41 / 15.99
n = 3.65 mol
Thus, now we know the value of n
Put the value in formula
PV =nRT
1183 mmHg x V = 3.65 mol x 8.314 J/mol x 66.33°C
V = 2012.86 / 1183
V = 1.70 ml
Hence, the volume of the oxygen into a balloon is 1.70 ml.
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13. What are the 3 main types of radiation and what does each emit?
Answer:
[tex]\begin{gathered} a)\text{ Alpha Radiation (emits helium atom)} \\ b)\text{ Beta Particle (emits electron)} \\ c)\text{ Gamma Ray (has no charge, nor mass, are by-products of radiation)} \end{gathered}[/tex]Explanation:
The three main radiation types are:
a) Alpha particles
b) Beta Particles
c) Gamma rays
Alpha Particles
Alpha particles are essentially helium atoms. When radiated, the value 4 is subtracted from the parent's molecule mass number while the value 2 is subtracted from the parent's molecule atomic number. Due to their heaviness, they are less penetrative, compared to other radiation types. They are positively charged.
[tex]\alpha^{\text{ }}particle=^4_2He[/tex]Beta Particles
Beta particles are more energetic radiation emission with a charge equal to -1. They are negatively charged. They are high energetic electrons which can be represented generally as follows:
[tex]\beta^{\text{ }}particle=^{_{}0_{}}_{-1}e[/tex]They weigh much more less and have a higher penetrating power when compared to alpha particles
Gamma Rays
These are the lightest and are simply radiation by products. They have more penetrating power than both beta particles and alpha particles. They are neutrally charged. They have no charge nor mass:
[tex]^0_0\gamma\text{ }[/tex]They have low ionizing power
Which of the following is an isotope of Carbon (atomic number 6)?
A 7 protons, 6 neutrons, 8 electrons
B 7 protons, 8 neutrons, 6 electrons
C 8 protons, 6 neutrons, 7 electrons
D 6 protons, 8 neutrons, 7 electrons
Answer:
D
Explanation:
Carbon has atomic number of 6 so it has 6 protons.
Liquid octane (CH₂(CH₂)6 CH₂) reacts with gaseous oxygen gas (₂) to produce gaseous carbon dioxide (CO₂) & gaseous water (H₂O). If 85.8g of carbon dioxide is produced from the reaction of 31.98g of octane. & 190.4g of oxygen gas, calculate the percent yield of carbon dioxide.
The percent yield of carbon dioxide is 87%.
The balanced chemical equation for reaction of octane with oxygen,
CH₂(CH₂)₆CH₂+ 12O₂ → 8CO₂ + 8H₂O
We can use the mole concept here,
Mole = Given mass/molar mass.
From the reaction,
1 mole of Octane = 8 moles of carbon dioxide.
Now, moles of octane N,
N = 31.98/114.23
N = 0.2799
Moles of Carbon dioxide = 8 x 0.2799
Moles of Carbon dioxide = 2.239
Mass of CO₂ formed,
2.239 = Mass of CO₂/44
Mass of CO₂ = 98.54 grams/mole.
Percentage yield = theoretical mass/experimental mass x 100
Theoretical mass = 98.54 grams/mole.
Experimental mass = 85.8 grams/mole.
Percentage yield of CO₂ = 85.8/98.54 x 100
Percentage yield of CO₂ = 87%
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i need help with chemistry equation
Answer:
86400
Explanation:
24*24*69seconds
molar mass of rhodonite mnsio3
The molar mass of rhodonite MnSiO₃ is 131.0 g.
What is the molar mass of a substance?The molar mass of a substance is the mass of 1 mole of that substance.
The molar mass of a compound is obtained from the sum of the product of the number of moles of atoms and the molar masses of the elements in the compound.
The molar mass of rhodonite MnSiO₃ is calculated as follows:
Molar mass of Mn = 55 g
Molar mass of Si = 28 g
Molar mass of O = 16.0 g
Molar mass of MnSiO₃ = 55 + 28 + 16 * 3
Molar mass of MnSiO₃ = 131.0 g
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A bicyclist is stopped at the entrance to a valley, as sketched below. Where would the bicyclist have the highest potential energy? Where would The bicyclist have the lowest potential energy? Where would bicyclist have the highest kinetic energy? Where would the bicyclist have the highest speed winning? Conversation with the bicyclist’s Kinetic energy be higher at A or B? With a bicycle is potential energy be higher at A or B? What’s a bicyclist total energy we hire at A or B? Supposed to bicyclist lets off the brakes and coast down into the valley without peddling. Even if there was no friction or air resistance to slow her down, what is the farthest point the bicyclist could reach without peddling?
Step 1 - Understanding the relation of potential energy, kinectic energy and the conservation of energy
The potential energy is the energy related to a body that can start moving under the influence of a force anytime soon.
The kinf of potential energy depends on the force that could act on the body. When a body is lifted, because gravity can pull it back, we say that this body has gravitational potential energy
Kinetic energy, on the other hand, is related to actual movement. It depends on the mass as well as on the velocity of the body. When we lift an object and drop it next, all the potential energy will be converted to kinetic energy, i.e., the velocity of the object we dropped will be also proportional to the height. It cannot gain more energy.
Step 2 - Interpreting the problem
Now that we know how potential and kinetic energy work, we can start working on the problem. Since potential energy is directly proportional to height, the highest potential energy would be attained at F.
The lowest potential energy, on the other hand, woud be attained at D, i.e., the smaller height.
The highest kinetic energy would be attained when all the potential energy is converted to kinetic energy, i.e., when the bicyclist, starting at A, loses its potential energy reaching D
The speed is directly proportional to the kinetic energy: the higher the speed, the higher the kinetic energy. Since the kinetic energy, as we saw, is the greatest at D, the velocity will also be the greatest at this point.
Solid/liquid/gas
Element/mix/compound
Because........
Answer:
why alkali metal are called as most reactive elements?
write out step by step explanation of the process of fission
A bigger atom fission when a neutron smashes against it, causing it to excite and split into two smaller atoms known as fission products. A chain reaction may be initiated by other neutrons that are also released.
What examples of fission?By dissolving large, heavy atoms, like uranium, into smaller ones, like iodine, cesium, strontium, xenon, and barium, to name just a few, fission produces energy. To create the heavier helium, fusion combines light atoms, such as the two hydrogen isotopes deuterium and tritium.
Why is fusion so important?Nuclear fission fuels the explosion of nuclear weapons and creates energy for nuclear power. Due to the fact that certain compounds known as nuclear fuels undergo fission when impacted by fission neutrons and then break apart, both uses are feasible.
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Sulfur and fluorine react in a combination reaction to produce sulfur hexafluoride:
S (s) + 3F2(g) → SF6 (g)
The maximum amount of SF6 that can be produced from the reaction of 32.1 g of sulfur with 114g of fluorine is ________ g.
Taking into account the reaction stoichiometry, the maximum amount of SF₆ that can be produced from the reaction of 32.1 g of sulfur with 114 g of fluorine is 146.46 grams.
Reaction stoichiometryIn first place, the balanced reaction is:
S + 3 F₂ → SF₆
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
S: 1 molesF₂: 3 molesSF₆: 1 moleThe molar mass of the compounds is:
S: 32 g/moleF₂: 19 g/moleSF₆: 146 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
S: 1 mole ×32 g/mole= 32 gramsF₂: 3 moles ×19 g/mole= 57 gramsSF₆: 1 mole ×146 g/mole= 146 gramsLimiting reagentThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction.
Limiting reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 57 grams of F₂ reacts with 32 grams of S, 114 grams of F₂ reacts with how much mass of S?
mass of F₂= (114 grams of F₂× 32 grams of S)÷ 57 grams of F₂
mass of F₂= 64 grams
But 64 grams of F₂ are not available, 32.1 grams are available. Since you have less mass than you need to react with 114 grams of F₂, S will be the limiting reagent.
Mass of SF₆ formedConsidering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 32 grams of S form 146 grams of SF₆, 32.1 grams of S form how much mass of SF₆?
mass of SF₆= (32.1 grams of S× 146 grams of SF₆)÷ 32 grams of S
mass of SF₆= 146.46 grams
Finally, 146.46 grams of SF₆ can be produced from the reaction of 32.1 g of S with 114 g of F₂.
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Match the particle with its charge.
neutron
proton
electron
positive (+)
neutral ( )
negative (-)
Answer:
electron(negative)
neutron(neutral)
proton(positive)
The investigators were able to determine that the footprints were made by a Nike, size 10 tennis shoe; however, they couldn’t match it exactly to the suspect’s shoe. What is TRUE about this piece of evidence?
A.
They were unable to find class nor individual characteristics.
B.
They were only able to find class characteristics.
C.
They were only able to find individual characteristics.
D.
They were able to find both class and individual characteristics.
Answer
the correct answer would be A
Explanation:
They were unable to find class nor individual characteristics.
If 3.05 mol of an ideal gas at 273 K has a volume of 208 L, what will its pressure be in kPa?
Use one of the following values:
R=0.0821 atm. L/mol. K
R= 8.31 kPa L/mol K
R= 62.4 torr. L/mol K
kPa
Ideal gas equation PV =nRT
The parameters are given in problem : moles (n) = 2.55 Volume (V) = 205L:Temperature(T) = 273K Pressure = ?kPa
Universal Gas constant R = 8.31kPa.L/mol.K substitue all these values in ideal gas equation in PV = nRT
PV = nRT
Px205 = (2.55)x(8.31)x(273)
P = (3.05)x(8.31)x(273) /205 kPa
P = 33.75 kPa.
The volume of gas particles is negligible. Gas particles are the same size and have no intermolecular forces as other gas particles. Gas particles move randomly according to Newton's laws of motion. An ideal gas is one that obeys the law pv=RT at all pressures and temperatures. At high temperatures and low pressure, the potential energy due to intermolecular forces becomes almost insignificant compared to the kinetic energy of the particles, and the size of the molecules increases compared to the intermolecular voids.
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If a population consist of large portion of reproductive Indvidual's, how would you expect the future population size to respond?
If a population consist of large portion of reproductive Indvidual's, then the future population size is also increase .
As previously said, populations with early reproduction have the ability to increase far more quickly than populations with later reproduction. The life tables for a certain species show how the age of first reproduction affects population growth.
Preoperative people make up a large amount of the triangular age pyramid, whereas reproductive people make up a more moderate number and post-reproductive people make up less of it. It signifies a young or populace that is expanding quickly.
In an age pyramid with an urn shape, there are more reproductive people than pre-reproductive people. It symbolises population loss or reduction and negative growth.
The proportion of pre-reproductive and reproductive people in the age pyramid has a bell shape. Comparatively fewer people are post-reproductive. It indicates a population that is steady or stationary and is neither increasing nor decreasing.
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What is the percent by mass of carbon in Al(CO3)3
The percent by mass of carbon in Al₂(CO₃)₃ is 15.38%.
Mass number(A) of various elements of molecule,
A of Aluminum(Al) = 27
A of Carbon(C) = 12
A of Oxygen(O) = 16
Total molecular mass or molecular weight is the sum of individual atomic masses of each atom in a molecule.
Thus, total molecular mass of molecule Al₂(CO₃)₃ is:
= 27×2 + (12 + 16 × 3)3
= 54 + 180
= 234
Hence, percent % of Carbon = (12×3/ 234)× 100
= (36/ 234 )× 100
= 15.38 %
Thus, the percent by mass of carbon is 15.38 %.
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The atomic radius of carbon is 77 pm, and the atomic radius of sulfur is 103 pm. What is the circumference of each atom?
Answer:
Circumference of carbon = 483.56 pm
Circumference of sulphur = 1111.56 pm
Explanation:
The circumference is the length of any great circle, the intersection of the sphere with any plane passing through its centre.
For carbon atom:
Atomic radius = 77 pm
Circumference = 2πr
=2 X 3.14 X 77
=154 X 3.14
Circumference of C = 483.56 pm
For sulphur:
Atomic radius = 177 pm
Circumference = 2πr
=2 X 3.14 X 177 pm
=1111.56 pm
Circumference of sulphur = 1111.56 pm
Hence,
The circumference of Carbon is 483.56 and the circumference of sulphur is 1111.56 pm.
[tex]c \: = 2\pi\:r[/tex]
CARBONC = 2(3.14)(77)
C = 6.28 × 77
= 483.56SULFURC = 2(3.14)(103)
C = 6.28 × 103
= 646.84hello, can someone please help me with this problem
In order of degreasing Size :
O2- > O > Ne.
Br- > Cl- > F-
Mg > Al > S
what are factors affects the radius of the atom? How many protons are in the nucleus (called the nuclear charge). The number of electron-carrying energy levels (and the number of electrons in the outer energy level). a measure of how many electrons are kept between the nucleus and its outermost electrons (called the shielding effect).The separation between an ion's nucleus and its furthest-reaching electrons is known as the ionic radius. However, the atomic radius measures the separation between an atom's outermost shell and its nucleus.To learn more about : Atomic radius
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A solution is made by mixing 84. g of water and 100. g of hexane ()Calculate the mole fraction of water solution .
The mole fraction of the water solution is 0.77.
The mole fraction or molar fraction is defined as a unit of the quantity of a constituent, nᵢ, divided by the total quantity of all parts in a combination.
Moles of water = given mass/ molar mass
Moles of water = 84/18
Moles of water = 4.6
Moles of hexane = given mass/ molar mass
Moles of hexane = 100/76
Moles of hexane = 1.3
Total moles = Moles of water + Moles of hexane
Total moles = 4.6 + 1.3 = 5.9
Mole fraction of water = Moles of water / Total moles
Mole fraction of water = 4.6/5.9
Mole fraction of water = 0.77
Hence, the Mole fraction of water is 0.77.
The mole fraction is the same as the mole percent however in a specific shape in chemistry. Inside the given combination, the range of moles of one constituent is divided by the total number of moles is referred to as the mole fraction. Multiplying the mole fraction of the thing by then we gain the mole percentage of the aspect.
Mole fraction is a unit of awareness, described to be equal to the range of moles of an aspect divided through the whole wide variety of moles of a solution. Because it's miles a ratio, the mole fraction is a unitless expression.
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Hello, can you give me a concept of what anhydrides are and examples, please?
Anhydrides are binary substances or compounds that are the result of a nonmetal with oxygen.
I leave you 2 steps to make the anhydrides:
1: To make anhydrides, write your nonmetal symbol followed by oxygen.
2: The oxidation numbers must be the same and for this the exchange of oxidation numbers or valence between its non-metallic element and Oxygen is used.
Examples of anhydrides:
1: Chlorous anhydride
[tex]\bold{ \: Cl + O₂ \rightarrow \: Cl₂ O₃}[/tex]
Keep in mind that when it ends in OSO we look for its valence, which in this case would be +3.
2: Iodic anhydride
[tex]\bold{ \: I + O₂ \rightarrow \: I₂ \: O₅}[/tex]
We take into account its symbol that in this would be me and to solve it we must look for its valence that in this case ends in ICO which is already known that its ICO valence is +5.
3: Per bromic anhydride
[tex]\bold{\:Br + O₂ \rightarrow \:Br₂ \:O₇}[/tex]
We take into account its symbol, which in this case would be Br, and to solve it we must find its valence, which in this case ends in ICO, which is already known to have an ICO valence of +7.
The Table of metals and non-metals is attached.
You need a 9.0% NaCl solution for an IV drip. If your IV bag can hold 239 grams of total solution, how many grams of NaCl are in the IV bag?
The 12.5 g of NaCl is required to make 9.0% of the NaCl solution.
How the percentage is related to grams in terms of Chemistry?
Both percentages and grams both are units or parameters used to express the concentrations in chemistry.
Given:
The % of NaCl = 9.0% or = 9/10 = 0.9
The weight of the solution = 239 grams
The molar mass of the NaCl = 58.44 g/mol
Here, we use formula = 0.9 = (Mass of the solute*1000)/(Mass of the solvent)
Let us assume the mass of the solute = x = mass in the gram/ molecular mass of the solute.
Now, by using the above formula, we get
X= 0.9*239*58.44/1000
X = 12.5 grams
Hence, 12.5 grams is the answer
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What is TRUE about soil used as evidence in forensic science?
A.
It only includes dirt.
B.
It may include pieces of asphalt.
C.
It only includes natural substances.
D.
It cannot be used in a criminal case.
The statement 'It may include pieces of asphalt' is TRUE about soil used as evidence in forensic science (Option B).
What is forensic science?Forensic science is a sub-discipline aimed at solving police cases based on evidence found at the crime scene, thereby being a key part of a police investigation. in this sense, pavement structural evaluation may result very useful in forensic science.
Therefore, we can conclude that forensic science is based on evidence found in the crime scene, which may include evidence in the asphalt ([pavement) that is collected by investigators in order to analyze it.
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Answer: B
Explanation:
How many atoms are there in 10 g of Kr?
From the periodic table, we know that 1 mole of Krypton has a molar mass of 83.798 grams/mole.
So 10 grams would have (10/83.798) which is 0.1193345903 moles.
If we multiply this by Avogadro's number, we get the amount of Krypton atoms in 10 grams.
0.1193345903 x 6.02 x 10^23 = 7.184 x 10^22 atoms
Accounting for significant figures, the answer would be: 7 x 10^22 atoms
This is a part of the antihistamines in pharmaceutical chemistry
The classification of Rupatadine is H-1 receptor antagonists or H-1 blockers.
What is rupatadine?As a platelet-activating factor antagonist and second-generation antihistamine, rupatadine is used to treat allergies. It was found and developed by Uriach [es][2], and it is sold under the trade names Rupafin and a few other names as well. For the treatment of chronic urticaria and allergic rhinitis in adults and children older than 12 years, rutadine fumarate has been approved. It is offered as round, light salmon-colored tablets to be taken orally once day that contain 10 mg of rupatadine (as fumarate).
Rupatadine's effectiveness as a treatment for allergic rhinitis (AR) and chronic idiopathic urticaria (CIU) has been examined in adults and adolescents (aged over 12 years) in several controlled studies, demonstrating a rapid action onset and a great safety characteristics even in long treatment durations of a year.
The drug rupatadine, a dual antagonist of the histamine H1 and platelet activating factor receptors, is used to treat the symptoms of chronic spontaneous urticaria and seasonal and perennial rhinitis. It is available in tablet and liquid formulations for adult and pediatric usage in Canada and has received marketing approval under the trade name Rupel.
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which hypothesis of thomson’s atomic model was later found to be not true by rutherford and why
The distribution of positive and negative particles was not uniform. This hypothesis of Thomson’s atomic model was later found to be not true by Rutherford.
Because positive charge particle is in center and the negative charge particle is surround to it.
J.J. Thomson proposed that an atom is a definitely charged sphere wherein negatively charged electrons are embedded in it. Neils Bohr proved it to be false as the mass of any atom is localized inside the middle of an atom which is positively charged even as negatively charged electrons revolve across the effective center.
Thomson was incorrect due to the fact he assumed that the positive charge of an atom become all one uniform blob of count number with the electrons transferring in orbits inside the nucleus. If Thomson's model had been accurate, the alpha particles could skip thru the atomic shape of the foil unimpeded.
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imagine you are given a piece of gold and piece of copper both pieces have a volume of 45 cm3,explain which piece of metal would have the larger mass
Out of gold and copper, gold metal would have larger mass.
What is molar mass?
The mass of any chemical substance divided by the volume of the material is known as the molar mass of that compound.
Given: The value of volume is same for both the metals = 45
The value of the volume is the same for both the metals = 45 cm3
By using formula of density i.e = mass/volume
Since the volume is the same
The density is directly proportional to the mass.
From the periodic table,
The mass of gold = 196.9 u
The mass of copper = 63.5 u
Since the volume is the same, we consider only the absolute masses value
Hence, gold is heavier than copper metal
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Water has a density of 2g/ml. What is the mass of the water if it fills a 10ml container
20 Grams of Water.
Grams : mL
2 : 1
4 : 2
6 : 3
8 : 4
10 : 5
12 : 6
14 : 7
16 : 8
18 : 9
20 : 10
Answer:
20 grams
Explanation:
mass = Density × Volume
= M = 2g/ml × 10ml
= 20g
10.00 moles of H2(g) react with 5.000 mol of O2(g) to form 10.00 mol of H2O(l) at 25°C and a constant pressure of 1.00 atm. If 683.0 kJ of heat are released during this reaction, and PΔV is equal to -37.00 kJ, then
10.00 moles of H₂(g) react with 5.000 mol of O₂(g) to form 10.00 mol of H₂O(l) at 25°C and a constant pressure of 1.00 atm. If 683.0 kJ of heat are released during this reaction, and PΔV is equal to -37.00 kJ, then ΔE° is 646.00kJ
Energy that is transferred from one body to another as the result of a difference in temperature called as heat
Here given data is
H₂(g) + O₂(g) → H₂O(l)
H₂(g) = 10.00 mole , O₂(g) = 5.000 mol , gives H₂O(l) = 10.00 mol and heat are released during this reaction are 683.0 kJ and PΔV is equal to -37.00 kJ then we have to find ΔE° = ?
ΔH° = 683.0 kJ
ΔE° = heat are released - PΔV
So, ΔE° = 683.0 kJ - 37.00 kJ
= 646.00kJ
And the calculated answer is the ΔE°
So, ΔE° = 646.00kJ
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