using the methos of dimensions derive an expression for the centripetal force f acting on a particle of mass m mivingv with velocity v in a circle of radius r?
According to the Question:
[tex]\footnotesize\implies F \propto [m]^x [v]^y [r]^z[/tex]
[tex]\footnotesize\implies F =k [m]^x [v]^y [r]^z \:...(i)[/tex]
K = Dimensionless ConstantNow, substituting Dimensions of each physical quantity in equation (I):
[tex]\footnotesize\implies [M^1L^1T^{-2}] =[M^1L^0T^0]^x [M^0L^1T^{-1}]^y [M^0L^1T^0]^z[/tex]
[tex]\footnotesize\implies [M^1L^1T^{-2}] =[M]^x [L]^{y + z} [T]^{ - y}[/tex]
On comparing the powers of LHS and RHS:
[tex]\implies \bf x = 1[/tex]
[tex]\implies - y = - 2[/tex]
[tex] \implies \bf y = 2[/tex]
[tex]\implies y + z = 1[/tex]
[tex]\implies z = 1 - 2[/tex]
[tex]\implies \bf z = - 1[/tex]
[tex]\footnotesize\implies F = [m]^x [v]^y [r]^z[/tex]
[tex]\footnotesize\implies F = [m]^1 [v]^2 [r]^{ - 1}[/tex]
[tex]\implies\footnotesize \underline{ \boxed{ \bf \red{ F = \frac{m {v}^{2} }{r} }}}[/tex]
NO LINKS! What are the definitions of initial horizontal velocity and initial vertical velocity? Please help! This like is my 10th time asking this question because many people have been scamming me...
Answer:
Additionally, the initial horizontal velocity may be calculated by measuring the diameter d of the ball and dividing the result by the amount of time t required for the ball to pass across the photogate. Vo = d/t is the formula.
Initial vertical velocity is the vertical component of the initial velocity: v 0 y = sin 0 sin 0 = (30.0 m/s) sin 45° = 21.2 m/s
Explanation:
Hope it helps:)
The rate at which work is done is called
a. efficiency
b. effort time
c.
force
d. power
Please select the best answer from the choices provided
Ο Α
ОВ
ОС
Answer:
The rate at which work is done is power
What is the difference between a low tide and a high tide
Answer:
High water level during a tide is called High tide.
Low water level during a tide is called Low tide.
Wire coils spinning between two magnets will produce …?
A: cold
B : electricity
C: chemicals
D: Steam
Answer:
B
Explanation:
I don't know but its b
In fish BB-blue, BW-blue with white stripes, WW-white. Cross a white fish with a fish with blue and white stripes. What is the probability of having white fish offspring?
Answer: Juvenile fish go through various stages between birth and adulthood. When they have developed to the point where they are capable of feeding themselves, the fish are called fry. When, in addition, they have developed scales and working fins, the transition to a juvenile fish is complete and it is called a fingerling.
A car weighs 14500 N. What is its mass?
Answer:
w = mg
14500 = m ×10 [g=10m/s2]
m =14500/10
m=1450kg
In a car race, the average speed of the car was 90 km/hr where the total
covered distance was 450 km.
1. Calculate the average speed of the car in SI unit.
Explanation:
The speedometer of a motor car showed the following speeds in km per hour at the ends of successive intervals of 3 secs. 38.9, 52.8, 64.4. 73.6, 80.9, 86.1, 90.0, 92.5 Plot the velocity – time graph in convenient units and find from the graph, (a) The distance covered while the speed increased from 80
weight of 1 kg becomes 1/6 on moon. If radius of moon is 1.76×10^6 m, then the mass of moon will be
Answer:
7.65 x 10^22kg
sorry if im wrong!
An escalator in a busy shopping centre lifts people up from one floor to another. This takes 1.2 MJ every minute. What is the power output of the escalator motor? Give your answer in kW.
An escalator that takes 1.2 MJ every minute has a power output of 1200 kW.
An escalator used to lift people up from one floor to another, exerts a work (w) of 1.2 MJ in 1 minute (t).
In physics, power (P) is the amount of energy (w) transferred or converted per unit time (t).
[tex]P = \frac{w}{t} = \frac{1.2 \times 10^{6} J }{1min} = 1.2 \times 10^{6} W[/tex]
We can convert 1.2 × 10⁶ W to kW using the conversion factor 1 kW = 1000 W.
[tex]1.2 \times 10^{6} W \times \frac{1kW}{1000W} = 1200kW[/tex]
An escalator that takes 1.2 MJ every minute has a power output of 1200 kW.
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If the acceleration of an object increases, what effect does this have on the Force and Mass?
A Force Increases, Mass Increases
B Force Decreases, Mass Decreases
C Force increases, Mass remains the same
D Force Decreases, Mass remains the same
Answer:
Force Increases and Mass remains the same.
Explanation:
b. Ron bicycles forward with an acceleration of 2.1 m/s2. If he is applying a forward force of 195 N, what is his mass?
Answer:
92.86 kgExplanation:
lThe mass of an object given only it's force and acceleration can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question
f = 195 N
a = 2.1 m/s
We have
[tex]m = \frac{195}{2.1 } = 92.857142... \\ [/tex]
We have the final answer as
92.86 kgHope this helps you
Guys plz i need those answers as soon as possible
9) a) formula = h(ρ)g by default g=9.8m/s²
Pressure = 2×1000×9.8 = 19600Pa
b)
given. force of 88N and an acceleration of 4 m/s 2 what is the mass?
What is thermal energy.
Explanation:
thermal energy refers to the energy contained within a system that is responsible for its temperature. Heat the flow of thermal energy
If 40 N force is exerted by a box covering 2 metre square area, calculate pressure.
[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]
[tex]\\ \sf\longmapsto Pressure=\dfrac{40}{2}[/tex]
[tex]\\ \sf\longmapsto Pressure=20Pa[/tex]
[tex] \sf \huge \red {\dag} Given[/tex]
[tex]\sf \longmapsto \: Force \: = 40 \: Newtons[/tex]
[tex]\sf \longmapsto \: Area \: = \: 2m \: Square \: ( {2m}^{2} )[/tex]
We know that the formula of Pressure is
[tex]\sf \longmapsto \: Force/Area[/tex]
Let's start.
Put the values[tex]\sf \longmapsto \: \: P = 40 \: newtons(force)/2(Area)[/tex]
[tex]\sf \longmapsto Pressure \: 20 \: N/m^2[/tex]
[tex]\boxed{\sf\red{\boxed{ \sf Pressure ≈ \: 20 \: N/m^2}}}[/tex]
A girl pushes her little brother on his sled with a force of 300 N for 750 m.
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
A 30 kg boy stands on rough horizontal ground. The coefficient of
static friction,
us is 0.8. The present static friction between the boy and the ground is
?
Answer:
0n
Explanation:
Two 4 kg blocks hang from a rope that passes over two frictionless pulleys . What is the tension in the horizontal portion of the rope if the blocks are not moving and the rope and the two pulleys have negligible mass?
The tension in the horizontal portion of the rope provided the blocks are not moving and the rope has negligible mass is 40 N
The tension in the rope is a pulling force that acts on the rope when the mass of 4kg is placed on each side of the two frictionless pulley.
According to Newton's second Law;
Force = (Tension) = mass × acceleration due to gravity
∴
We can say:
Tension = 4kg × 9.81 m/s²
Tension = 39.24 N
Tension = 40 N (to the nearest whole number)
Therefore, we can conclude that the tension in the horizontal portion of the rope is 40 N
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State a hypothesis about your estimated daily water use.
Answer
Estimates vary, but, on average, each person uses about 80-100 gallons of water per day, for indoor home uses.
Explanation:
Please help :[ Hold a flat piece of paper horizontally. Lift it high in front of you, and drop it. Then crumple a piece of paper into a tight ball, hold it high in front of you, and drop it from the same height. Compare the motion of the two pieces of paper.
The one you lifted in front of you ( the flat piece of paper being holded horizontally ) goes down so slow. While the one being crumpled into a ball goes down fast. Subscribe to DreamfanBG for support.
Answer:
Answer below
Explanation:
The flat piece of paper just gently glided to the ground, as if it were a feather. It didn’t go down in a straight line, it swayed from side to side. The crumpled piece of paper seemed like it had more weight to it (although I know that it didn’t), and it fell way quicker than the flat piece of paper.
_____________________________________________________
(Hope this helps can I pls have brainlist (crown)☺️)
What is the centripetal force acting on a 1.5 kg mass moving in a circular path with a centripetal
acceleration of 18 m/s2
The centripetal force acting on a 1.5 kg mass moving in a circular path is 27N
A centripetal force is a net force acting on an object in order to maintain the object's movement in a circular motion.
According to Newton's first law, it states an object will continue to proceed its movement in a straight line unless acted upon by an external force.
The centripetal force is the external force at work here and It's the net force that propels the object in a circular motion.
Using the formula for calculating centripetal force:
[tex]\mathbf{F_c = mass (m) \times acceleration (a)}[/tex]
[tex]\mathbf{F_c = 1.5 \ kg \times18 \ m/s^2}[/tex]
[tex]\mathbf{F_c = 27 \ N}[/tex]
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Dark matter is inferred to exist because it explains the abundance of helium in the universe today. we can observe its gravitational influence on visible matter. it explains how the expansion of the universe can be accelerating. we see lots of dark patches in the sky
we can observe its gravitational influence on visible matter.
Dark matter is a term used in astrophysics to refer to matter that corresponds to approximately 80% of the matter in the universe.
Dark matter is related to the motion of galaxies because visible matter makes up only a small part of the cluster and the galaxies show signs of being composed mainly of a halo of dark matter concentrated in their center.
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If force F, volume V and density D are taken as fundamental quantities, then the representation of pressure P will be
Using the principle of dimensional analysis, the representation of Pressure would be [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]
Pressure is related to Force, Volume and Density thus :
[tex] Pressure, P = F^{a}V^{b}D^{c}[/tex]
Using dimensional analysis :
Pressure, P = ML¯¹T¯²Substituting the dimension into the relation :
[tex] ML^{-1}T^{-2}= [MLT¯²]^{a} [L³]^{b} [ML¯³]^{c} [/tex]
[tex] ML^{-1}T^{-2} = M^{a+c}L^{a+3b-3c}T^{-2a} [/tex]
Equating the power ;
a + c = 1 - - - (1)
a + 3b - 3c = - 1 - - - (2)
-2a = - 2
a = - 2/-2
a = 1
From (1)
1 + c = 1
c = 1 - 1 = 0
c = 0
From (2) :
1 + 3b - 3(0) = - 1
1 + 3b = - 1
3b = - 2
b = - 2/3
Hence, [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]
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The representation of pressure is:
[tex]P=FV^{-\frac{2}{3} }[/tex]
Given that:
Force F, volume V and density D are taken as fundamental quantities, hence pressure P is:
[tex]P=F^aV^bD^c\\\\(ML^{-1}T^{-2})=(MLT^{-2})^a(L^3)^b(ML^{-3})^c\\\\\\(ML^{-1}T^{-2})=(M)^{a+c}(L)^{a+3b-3c}(T)^{-2a}[/tex]
Hence:-
2 = -2a
a = 1
a + c = 1
1 + c = 1
c = 0
a + 3b - 3c = -1
1 + 3b - 3(0) = -1
3b = -2b = -2/3
Hence the representation of pressure is:
[tex]P=FV^{\frac{-2}{3} }D^{0}\\\\P=FV^{\frac{-2}{3} }[/tex]
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A mass of 5.00 kg in a gravitational field of 7.00 n/kg. What force acts on the mass?
Answer:
35N
Explanation:
force=mass×gravity
the mass is 5 and the gravity is 7 therefore:
force=7×5
=35N
I hope this helps
An object weighs 15 N in air and 13 N when submerged in mineral spirits, which has a density of 788 kg/m3. Determine the density of the object
The density of the object is 5911.94 kg/m³
An object's buoyancy is the upward force produced by a fluid in opposition to the weight of a partly or totally submerged object.
The buoyancy = weight of the object - weight in water
= 15 N - 13N
= 2 N
The buoyancy force can also be determined by using the expressed:
[tex]\mathbf{F_B = Volume (V) \times density ( \rho) \times g}[/tex]
[tex]\mathbf{2 = Volume (V) \times788 \ kg/m^3 \times9.8 }[/tex]
[tex]\mathbf{ Volume (V) = \dfrac{2}{ 788 \ kg/m^3 \times9.8 }}[/tex]
volume (v) = 2.589 × 10⁻⁴m³
Recall that:
The mass of an object can be estimated by using the formula:
Weight = mass × gravity
mass = Weight / gravity
mass = 15/9.8
mass = 1.5306 kg
The density of the object can now be calculated using the relation
Density = mass/volume
Density = 1.5306 kg / 2.589 × 10⁻⁴m³
Density = 5911.94 kg/m³
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A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm. A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
We have that for the Question, it can be said that the amount by which the length of the stack decreases is
[tex]dl'=3.621*10^{-4}m[/tex]
From the question we are told
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.
A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
Generally the equation for copper cylinder is mathematically given as
[tex]dl=\frac{Flo}{yA}[/tex]
[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=1.19064778*10^-^4[/tex]
Generally the equation for brass cylinder is mathematically given as
[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=2.43*10^{-4}[/tex]
Therefore Total change in length
[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]
[tex]dl'=3.621*10^{-4}m[/tex]
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In a hydraulic press a force of 200N is applied to a master piston of area 25Cm2.if the press produces 500N determine the area of the piston.
Answer:
625 GIVE ME BRAINLIEST ANSWER PLEASE
Explanation:
This question is based on pascal's Law.
So By Pascal's Law
=
therefore =force on input piston =200N
= Force on output piston = 5000N
therefore after putting the values we get,
a) = (25x 5000)/200
= 625
b) area of the salve piston = = 625
so = 625/3.14 = 199
so r = = 14.10 cm
Of the Three elements listed, which element is NOT present in the mixture?
Element D
Element A
Element Z
Answer:
element ammmkkkv was a very good
A state government wants to increase the taxes on cigarettes to increase tax revenue. Because cigarettes are addictive, we would expect its demand to be: ______________
a. Elastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
b. Elastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.
c. Inelastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
d. Inelastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.
The demand of cigarette is elastic so the government's cigarette-tax revenues would rise with a tax increase.
The demand of cigarette is elastic because of the addiction the people can buy the cigarette even at high prices and the government's cigarette-tax revenues would rise.
The demand for cigarettes is unitary elastic (−1.06) means that a 1% increase in the price of cigarette would reduce its consumption by 1.06% so we can conclude that the demand of the cigarette is elastic and the government revenues increases.
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