Answers
Mechanical efficiency: the comparison of the machine's work output with it's work input
Mechanical advantage: the number of times that the machine multiplies the force
Explained:
Related Questions
A block of mass m = 3.0 kg is pushed a distance d = 2.0 m along a frictionless horizontal table by
a constant applied force of magnitude F= 20.0 N directed at an angle 0= 30.0° below the horizontal
as shown in Figure. Determine the work done by (a) the applied force, (b) the normal force exerted
by the table, and (d) the net force on the block.
Answers
Explanation:
We apply the definition of work by a constant force in the first three parts, but then in the fourth part we add up the answers. The total (net) work is the sum of the amounts of work done by the individual forces, and is the work done by the total (net) force. This identification is not represented by an equation in the chapter text, but is something you know by thinking about it, without relying on an equation in a list.
The definition of work by a constant force is W=FΔrcosθ.
(a) The applied force does work given by
W=FΔrcosθ=(16.0N)(2.20m)cos25.00=31.9J
(b), (c) The normal force and the weight are both at 900 to the displacement in any time interval. Both do 0 work.
(d) ∑W=31.9J+0+0=31.9J
A 60.0 kg person jumps onto the floor from a height of 3.0m. Find
the KE of the jumper when she hits the ground.
Answers
Answer:
1800 J
Explanation:
GPE= mgh
60*3*10
=1800 J
An object of mass 6.36 kg is released from rest and drops 2.05 m to the floor. The collision is completely inelastic. How much kinetic energy is lost during the collision
Answers
Answer:
Essentially all of it
Explanation:
The potential energy was
PE = mgh = 6.36(9.81)(2.05) = 127.90278 = 128 J
ignoring air resistance, this PE converts to KE
With no rebound final velocity is zero, so Kinetic energy lost = 128 J
What are sound detectors?
Answers
Answer:
A sound detector comes in the shape of a rectangular board which comprises a microphone as well as a processing circuitry.
Answer:
Sound detection sensor works similarly to our Ears, having diaphragm which converts vibration into signals.
A gazelle is grazing while standing in a fixed location. When it's startled by a predator, the gazelle accelerates uniformly for 16.8 s until it reaches a speed of 21.9 m/s. The gazelle then runs in a straight line at constant speed for an additional 16.4 s. Finally, it uniformly slows to a stop at a rate of 1.8 m/s/s. What is the total distance traveled by the gazelle in meters
Answers
Answer:
Explanation:
acceleration phase
average speed was 21.9/2 = 10.95 m/s
distance covered is 10.95 m/s(16.8 s) = 183.96 m
distance at top speed 21.9 m/s(16.4 s) = 359.16 m
distance while decelerating (0² - 21.9²)/(2(-1.8)) = 133.225 m
total = 183.96 + 359.16 + 133.225 = 676.345 = 676 m
How much tension must a rope withstand if it is used to accelerate a 1710-kgkg car horizontally along a frictionless surface at 1.30 m/s 2 m/s2
Answers
Answer:
Explanation:
Lowest tension will occur when the rope is also horizontal.
F = ma
F = 1710(1.30)
F = 2223 N
Section 1: Basic Energy Relationships
1. Click/tap the Start button and observe the motion. View the bar
charts and the velocity value as the coaster car moves. Complete
the following paragraph by entering total mechanical energy
(ME), kinetic energy (KE), and potential energy (PE). The
labeled locations refer to the graphic at the right.
As the coaster car rolls down the track from A to E, the
________ values decrease and the _______ value
increase and the ________ values remain constant. The
_______ is greatest at point A and smallest at point E.
However, the _______ is smallest at point A and largest
at point E.
Section 2: Hill Design
2. Click/tap on the Bumps tab at the top of the
Interactive. Then drag the grey circles to modify the
track so that it looks like the track design at the right.
Pay attention to the background grid to help with the
design. Note that Dot G is at the same height as Dot E;
make sure that the same is true of your final design.
3. Run the simulation. Does the coaster car travel as high
as point H? ___________ Give an explanation for why
it does or doesn't reach point H.
Answers
As the coaster car rolls down the track from A to E, the potential energy values decrease and the kinetic energy value increase and the total mechanical energy values remain constant. The potential energy is greatest at point A and smallest at point E. However, the kinetic energy is smallest at point A and largest at point E.
According the principle of conservation of mechanical energy, as the potential energy decreases, the kinetic energy increases.
[tex]P.E + K.E = M.A[/tex]
At point A, the coater has maximum potential energy.
At point E, the coaster has maximum kinetic energy.
We can fill the blanks as follows;
As the coaster car rolls down the track from A to E, the potential energy values decrease and the kinetic energy value increase and the total mechanical energy values remain constant. The potential energy is greatest at point A and smallest at point E. However, the kinetic energy is smallest at point A and largest at point E.
Based on the principle of conservation of mechanical energy, if the second simulation occurs at the same condition as the first, the height reached by coaster will be same.
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What is work? A. What happens when energy is destroyed B. The number of molecules in a substance C. The total size of an object divided by its mass D. What happens when a force causes an object to move
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Answer:
Which extended definition would be most helpful to add to this body paragraph?
Laughter Yoga, a new form of yoga, is becoming increasingly popular.
Laughter Yoga, which is becoming more and more popular, was created in the 1990s.
Laughter Yoga is modeled after traditional yoga but includes laughter exercises.
Laughter Yoga is a form of yoga that was created by Dr. Madan Kataria in the 1990s.
Explanation:
c
A child on ice skates is given a small push from behind by a parent. How are forces used to describe the resulting motion?(1 point)
Because of equal and opposite reactions, there will be a force opposing the push from the parent, and they will not move.
Because of equal and opposite reactions, there will be a force opposing the push from the parent, and they will not move.
There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.
There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.
There is a balanced force on the child, and the child’s motion will change direction or increase speed.
There is a balanced force on the child, and the child’s motion will change direction or increase speed.
Because of equal and opposite reactions, the child will move in the opposite direction to the force.
Answers
A child on ice skates is given a small push from behind by a parent. There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.
A child on ice skates is given a small push from behind by a parent. How are forces used to describe the resulting motion?
Because of equal and opposite reactions, there will be a force opposing the push from the parent, and they will not move. FALSE. According to Newton's third law of motion, if the parent applies force on the child, there will be a reaction applied by the child on the parent. These forces are applied to different objects so they will not cancel and the child will move. There is an unbalanced force on the child, and the child’s motion will change direction or increase speed. TRUE. The child will have an acceleration as a consequence of the unbalanced force. The acceleration will be responsible for the change in the direction or speed of the child. There is a balanced force on the child, and the child’s motion will change direction or increase speed. FALSE. If the forces were balanced, that is, there was no net force, the movement of the child would not change, as stated by Newton's first law of motion. Because of equal and opposite reactions, the child will move in the opposite direction to the force. FALSE. The child will move in the direction of the net force.A child on ice skates is given a small push from behind by a parent. There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.
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Are these a Chemical or Physical Change??
1. Sodium Bicarbonate breaks down into sodium carbonate and water.
A. Chemical Change
B. Physical Change
2. Mercury is cooled until it is in the solid state.
A. Chemical Change
B. Physical Change
Answers
2. physical change, as it is a change in temperature
The change of sodium bicarbonate breaking down into sodium carbonate and water is a chemical change. The cooling of mercury until it is in the solid state is physical change. The correct option for 1 is A and for 2 is B.
What is chemical and physical change?A chemical change occurs as a consequence of a reaction, whereas a physical change occurs when transformation occurs forms but retains its chemical identity.
Chemical changes include burning, cooking, rusting, and rotting. Physical changes include boiling, melting, freezing, and shredding.
A physical change is required to a specimen of matter in which some of the material's properties change but the matter's identity does not.
Physical changes can be classified as either reversible or irreversible. Melting is a reversible physical change because the melted ice cube can be refrozen.
In the first case, sodium bicarbonate is breaking down and forming sodium carbonate and water, this implies a chemical change.
In the second case, mercury is just cooling down, changing its physical shape. So it is physical change.
Thus, the correct option for 1 is A and for 2 is B.
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The density of water is 1000 kg/m the pressure pf water at 10 m depth is about
Answers
Answer:
pressure in liquids is given as:
P= hpg
where h is the depth
where p is the density
where g is 10
Explanation:
From the formula above
p = 10 X 1000 X 10
p = 100000N/m
PLEASE HELP FOR PHYSICS!
All objects exert a gravitational force on all other objects. This force is given by, F = GMm r2 , where the value of G = 6.673 × 10–11 N–m2/kg2 , M is the mass of the heavier object, m is the mass of the lighter object, and r is the distance between the two objects.
What is the force of gravity between two balls of mass 50 kg each if the distance between them is 25 m. Assume that there is no interference from any other gravitational field.
Answers
Hi there!
Recall Newton's Law of Universal Gravitation:
[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]
Where:
Fg = Force of gravity (N)
G = Gravitational Constant
m1, m2 = masses of objects (kg)
r = distance between objects (m)
Plug in the given values stated in the problem:
[tex]F_g = (6.673*10^{-11})\frac{50 * 50}{25^2} = \boxed{2.669 * 10^{-10} N}[/tex]
Which car is experiencing negative acceleration?
A. a car sitting at a red light
B. a car slowing down as it approaches a red light
C. a car driving in a circle at a constant speed
D. a car changing its speed from 0 km/hr to 10 km/hr
Answers
Answer:B
Explanation:
Answer: b
Explanation: b as it slows down and decelerates
3. A 1500 kg car moving at 30 m/s strikes a 6000 kg van initially at rest. If the car
comes to a complete stop after the collision, what is the final velocity of the van?
Answers
Answer:
7.5m/s
Explanation:
Force= mass × velocity
Energy is conserved, the car and van should have the same overall force.
1500kg × 30m/s= 6000kg × final velocity
Final velocity = 7.5m/s
If a 35 kg box collides with a stationary 120 kg box with a force of 90 N, what must be true of the magnitude of the reaction force?
Answers
Newton's third law allows to find the result for the value of the reaction force during the collision is:
The reaction force is F = 90 N and is applied to the lighter body.Newton's third law stable that the forces appear in pairs or ea that when two bodies interact, the interaction forces appear in the two bodies simultaneously, in general they are called action and reaction forces.
These furas are of the same magnitude, but in the opposite direction, each one applied to one of the bodies.
They indicate that the most lighter body collides with the one with the greatest mass with a force of F = 90 N. If we call this the action, the larger body must react with a force of equal magnitude on the lighter body.
Consequently, the reaction force is F = 90 N directed towards the lighter body.
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A 20 metric ton train moves toward the south at 50 m/s. At what speed must it travel to have four times its original momentum
Answers
Answer:
200 m/s
Explanation:
as momentum is a product of mass and speed, and mass is not changing, four times the speed will result in four times the momentum.
p = mv
4p = m(4v)
At 200m/s velocity of the train, the momentum of the train will be four times its original momentum. This is because the velocity is directly proportional to the momentum of an object.
What is Momentum?Momentum is the tendency of an object to remain in motion. It is the product of the mass of the object and the velocity of the object. It is denoted by "p". Momentum is a vector quantity because it has both the magnitude and direction. The unit of Momentum is g.m/s.
The momentum can be calculated with the formula:
p = m × v
where, p = momentum of the object,
m = mass of the object,
v = velocity of the object.
The momentum is directly proportional to the mass and velocity of the object. Hence, to increase the momentum of the train by four times the mass or velocity of the train needs to be increased by four times.
The increase in the velocity of the train by four times will increase the momentum of the train.
Original Velocity of the train = 50 m/s
Increased Velocity of the train = 50 × 4 = 200 m/s
Increased new Momentum of the train = mass × new velocity
Increased Momentum = 20 metric ton × 200m/s
Increased Momentum = 4000 metric ton. m/s
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How much work does an elephant do while moving a circus wagon 60 meters with a pulling force of 240N
Answers
Answer:
14,400
Explanation:
You need to do 240x60 and you would get the answer as 14,000
what type of data do you need to collect in a ADI
Answers
address.
driving licence number.
email address.
telephone number.
ethnicity (optional)
website address.
convictions (motoring and non-motoring)
……………….
PLEASE ANSWER THIS, I'LL MARK YOU AS BRAINLIEST
Carlito was observing an an that crawled along a table. With a piece of chalk, he followed his path. He determined the ant’s displacements by using a ruler and protractor. The displacements were as follows: 2 cm east, 3.5 cm, 32° north of east and 2.4 cm, 22° west of north. Find the resultant vector using graphical method.
Answers
Answer:
this is the answer
Explanation:
hope it's clear
pls Mark me as the brainliest pls
Can someone please help me? Please answer the question in the screenshot. Thank you! I need this answered!
Answers
Answer:
Explanation:
Photosynthesis is needed to store energy for the growth of the plant. It is like a factory that uses sunlight energy to convert 6CO₂ and 6H₂O into C₆H₁₂O₆ and 6O₂
Cell respiration is the process of breaking down the glucose and converting it into the other needed components of life. It's the engine that's fueled by the sugar of photosynthesis.
Telescopes work by using optics with true or false
Answers
Answer: true
its making me add 20 word so here they are g g g g g g g gg g t
Answer: its FALSE
Explanation:
Telescopes work by using optics with light is false, just took the quiz.
What is the approximate value of k when 30 = e^5k?
Answers
Answer:
Explanation:
30 = e^5k
ln30 = lne^5k
ln30 = 5k
k = ln30/5
k = 0.68023947...
round to your heart's content.
Grain is pouring into a silo to be stored for later use. Due to the friction between pieces of grain as they rub against each other during the pouring process, one piece of grain picks up a charge of 6.0 E -10 C and another piece of grain picks up a charge of 2.3 E -15 C. What is the electric force between them if the pieces of grain are 2 cm apart?
Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits to receive full credit.
Answers
Answer:
3.1×10⁻¹¹ N is
Explanation:
is the answer
A 200-kg, 2.0-m-radius, merry-go-round in the shape of a flat, uniform, circular disk parallel to level ground is rotating at 1.2 cycles/second about an axis through its center of mass and perpendicular to the ground. A 50-kg boy jumps onto the edge of the merry-go round and lands at a fixed point. What is the angular velocity of the merry-go-round after the boy lands on it
Answers
Answer:
Explanation:
Conservation of angular momentum.
Disk I = ½MR²
Point mass I = mR² (boy)
Initial angular momentum
L₀ = Iω = ½MR²ω₀
Final angular momentum
L₁ = Iω = (½MR² + mR²)ω₁
as momentum is conserved, these are equal
(½MR² + mR²)ω₁ = ½MR²ω₀
ω₁ = ω₀(½MR²/ (½MR² + mR²))
ω₁ = ω₀(½M/ (½M + m))
ω₁ = 1.2(½(200)/ (½(200) + 50))
ω₁ = 1.2(⅔)
ω₁ = 0.8 cycles/second or 0.8(2π) = 1.6π rad/s
a 4kg sample of water absorbs 500 joules of energy.How much did the water temp change.The specific heat of water is 4200 J/(kg C)
Answers
Answer:
0.02976°C
Explanation:
Heat Supplied = mcø
ø = 500/(4*4200)
ø = 0.02976 °C
halp me please i will give brainly
Answers
Answer: It should be the 3rd option down!
Explanation:
Answer: C
Explanation:
A wheel with radius 41.5 cm rotates 5.13 times every second.
Find the period of this motion.
What is the tangential speed of a wad of chewing gum stick to the rim of the wheel?
Answers
The tangential speed of a wad of chewing gum to the rim of the wheel is approximately 1337.659 centimeters per second.
Let suppose that the wheel rotates at constant angular speed ([tex]\omega[/tex]), in radians per second, the tangential speed of a wad of chewing gum to the rim of the wheel ([tex]v[/tex]), in centimeters per second, is:
[tex]v = 2\pi\cdot r\cdot f[/tex] (1)
Where:
[tex]r[/tex] - Radius of the wheel, in centimeters[tex]f[/tex] - Frequency, in hertzIf we know that [tex]f = 5.13\,hz[/tex] and [tex]r = 41.5\,cm[/tex], then the tangential speed of the chewing gum is:
[tex]v = 2\pi\cdot (41.5\,cm)\cdot (5.13\,hz)[/tex]
[tex]v \approx 1337.659\,\frac{cm}{s}[/tex]
The tangential speed of a wad of chewing gum to the rim of the wheel is approximately 1337.659 centimeters per second.
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half-life questionnnnn:
Answers
HELPPP!! Thanks!
If you only wanted to increase the particle motion of a gas without increasing any of its other properties, which would the most correct situation?
a. Keep the gas at a constant pressure and keep the temperature constant, but increase the volume of the gas
b. Keep the gas in a fixed container at constant pressure and increase the temperature
c. Keep the gas in a fixed container at constant pressure and decrease the temperature
d. Keep the gas at a constant volume and keep the temperature constant, but decrease the pressure of the gas
Answers
Answer:c i think
Explanation: not sure
Calculate the net force acting on a body of mass 20 kg moving with a
uniform velocity of 4 ms-1.
Answers
Answer:
0 N
Explanation:
Uniform velocity means no acceleration and therefore no net force.