What is the shape of this distribution

Answer:

1.B,C,D

2.A,D,E

I don't really know how to explain it to you but thats your answer :D

Answer:

He bought about 176 ounces or 22 cups, or 5.2 liters.

Step-by-step explanation:

1.) 4 * 28 = 112

2.) 112 + 64 = 176 (answer in ounces)

3.) 8 ounces in a cup

4.) 176 ÷ 8 = 22 (answer in cups)

5.) About 4.227 cups in a liter

6.) 22 ÷ 4.227 = 5.204636858

7.) Round to the nearest tenth = 5.2 (answer in liters)

Answer:

312ft

Step-by-step explanation:

LETS GOOOOOOOOOOOOOOO

Answer:

A train ticket costs $42

Step-by-step explanation:

5x + 30 = 240 (6 * 5 = 30, cost of lunch times 5 members of family)

5x = 240 - 30

5x = 210

x = 42

A train ticket costs $42.

Answer:

Tad ran 6 miles while Elaine ran 4 miles.

Step-by-step explanation:

Since Tad runs one-half mile for every one-third mile that Elaine runs, to determine, if together they run a total of 10 miles, how far does Tad run, the following calculation must be performed:

0.5 x 2 = 1

0.333 x 2 = 0.666

10 / 1.666 = X

6 = X

6 x 1 = 6

6 x 0.666 = 4

Therefore, Tad ran 6 miles while Elaine ran 4 miles.

Answer:

x=5

Step-by-step explanation:

(2)^x/2 = 16

Multiply both sides by 2

(2)^x/2 *2 = 16*2

2^x = 32

Rewrite 32 as a power of 2

2^x = 2^5

x=5

Answer:

x=5

Step-by-step explanation:

(2)^x/2 = 16

Multiply both sides by 2

(2)^x/2 *2 = 16*2

2^x = 32

Rewrite 32 as a power of 2

2^x = 2^5

x=5

Answer:

Is the annual dividend 1 dollar per share? Because if so, that means you would get 500 dollars yearly, and then divide that by 4 to get quarterly, making the answer 125 dollars in the quarterly check.

The amount that you receive on a quarterly dividend check will be $125.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

PEMDAS rule means the Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to solve the equation in a proper and correct manner.

Barnes and Noble had a $1.00 annual dividend in 2008. If you owned 500 shares of Barnes and Noble. Then the cost of the 500 shares will be

⇒ 500 x $1

⇒ $500

Then the amount that you receive on a quarterly dividend check will be

⇒ $500 / 4

⇒ $125

The amount that you receive on a quarterly dividend check will be $125.

More about the Algebra link is given below.

https://brainly.com/question/953809

#SPJ2

Answer:

girly

Step-by-step explanation:

I'd tell u to go with c I could be wrong tho but that's my guess and tell me if I got it right okay?

Step-by-step explanation:

the answer is n²

n plus n is 2n

and we have 2n as option b.. pls the answer is 2n

Answer:  a is 21 b is 45 and c is yes more people are going above because the median is above the speed limit

Step-by-step explanation:

9514 1404 393

Answer:

  $351

Step-by-step explanation:

Use the simple interest formula for this.

  I = Prt

where P is the invested amount at annual rate r for t years.

Using your values, we find the interest to be ...

  I = $300·0.13·9 = $351

The account will earn #351 in interest over 9 years.

Answer:

75o

Step-by-step explanation:

2x+5 = 155 (parallel lines)

x=(155-5)/2=75 deg

[tex]n^2 +6n-27 = n^2+6n-27+0\\~\\n^2+6n-27+0 = n^2+6n-27+(3n-3n) \\~\\n^2+6n-27+(3n-3n) = n^2+9n-3n-27\\~\\n^2+9n-3n-27 = n\cdot(n+9)-3\cdot(n+9) \\~\\n\cdot(n+9)-3\cdot(n+9) = (n+9)(n-3)[/tex]

The other side is n-3

Answer:

Hi again:

77 square millimetres

Step-by-step explanation:

Have a good day :)

Answer:

56 mm²

Step-by-step explanation:

12 - 4 = 8

8 · 7 = 56

56 ÷ 2 = 28

28 mm²

28 mm² + 28 mm²

56 mm²

Answer:

[tex]-2 -\sqrt{3}[/tex]

Step-by-step explanation:

First consider numerator

[tex]sin \frac{\frac{7\pi}{6}}{2} = sin \frac{7\pi}{12}= sin (\frac{\pi}{4} + \frac{\pi}{3})[/tex]

Using the formula : sin (A + B) = sin A cos B + cos A sin B

[tex]sin \frac{\pi}{4} = \frac{\sqrt{2} }{2}, \ cos \frac{\pi}{4} = \frac{\sqrt{2} }{2}\\\\sin \frac{\pi}{3} = \frac{\sqrt{2} }{2}, \ cos \frac{\pi}{3} = \frac{1}{2}[/tex]

[tex]sin(\frac{\pi}{4} + \frac{\pi}{3}) = sin \frac{\pi}{4} \cdot cos \frac{\pi}{3} + cos \frac{\pi}{4} \cdot sin \frac{\pi}{3}[/tex]

                [tex]=\frac{\sqrt{2} }{2} \cdot \frac{1}{2} + \frac{\sqrt{2} }{2} \cdot \frac{\sqrt{3} }{2} \\\\= \frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}\\\\=\frac{\sqrt{2} +\sqrt{6} }{4}[/tex]

Second consider denominator

[tex]cos \frac{\frac{7\pi}{6}}{2} = cos \frac{7\pi}{12}= cos (\frac{\pi}{4} + \frac{\pi}{3})[/tex]

Using the formula : cos (A + B) = cos A cos B - sin A sin B

[tex]sin \frac{\pi}{4} = \frac{\sqrt{2} }{2}, \ cos \frac{\pi}{4} = \frac{\sqrt{2} }{2}\\\\sin \frac{\pi}{3} = \frac{\sqrt{2} }{2}, \ cos \frac{\pi}{3} = \frac{1}{2}[/tex]

[tex]cos(\frac{\pi}{4} + \frac{\pi}{3}) = cos \frac{\pi}{4} \cdot cos \frac{\pi}{3} -sin \frac{\pi}{4} \cdot sin \frac{\pi}{3}[/tex]

[tex]=\frac{\sqrt{2} }{2} \cdot \frac{1}{2} - \frac{\sqrt{2} }{2} \cdot \frac{\sqrt{3} }{2}\\\\=\frac{\sqrt{2}}{4} - \frac{\sqrt{6}}{4}\\\\= \frac{\sqrt{2} -\sqrt{6} }{4}[/tex]

Therefore,

           [tex]tan \frac{7\pi}{12} = \frac{sin \frac{7\pi}{12}}{cos\frac{7\pi}{12}}[/tex]

                     [tex]= \frac{\frac{\sqrt{2} +\sqrt{6} }{4}} {\frac{\sqrt{2} -\sqrt{6} }{4} }\\\\=\frac{\sqrt{2} +\sqrt{6} }{4} \times \frac{4 }{\sqrt{2} -\sqrt{6}}\\\\=\frac{\sqrt{2} +\sqrt{6} }{\sqrt{2} -\sqrt{6}}[/tex]

Either we can stop here or Rationalize the denominator:

[tex]\frac{\sqrt{2} +\sqrt{6} }{\sqrt{2} -\sqrt{6}} \times \frac{\sqrt{2} +\sqrt{6} }{\sqrt{2} +\sqrt{6}} = \frac{(\sqrt{2} +\sqrt{6})^{2} }{(\sqrt{2})^2 -(\sqrt{6})^2} = \frac{2 + 6 +2\sqrt{12} }{2-6} = \frac{8+2\sqrt{12} }{-4} = \frac{8+ 4\sqrt{3} }{-4} = -2-\sqrt{3}[/tex]

Given:

[tex]f(y)=e^{9y}+e^{-9y}[/tex]

To find:

The f'(y).

Solution:

Chain rule of differentiation:

[tex][f(g(x))]'=f'(g(x))g'(x)[/tex]

Differentiation of exponential:

[tex]\dfrac{d}{dx}e^x=e^x[/tex]

We have,

[tex]f(y)=e^{9y}+e^{-9y}[/tex]

Differentiate with respect to y.

[tex]f'(y)=e^{9y}\dfrac{d}{dx}(9y)+e^{-9y}\dfrac{d}{dx}(-9y)[/tex]

[tex]f'(y)=e^{9y}\cdot 9(1)+e^{-9y}\cdot (-9)(1)[/tex]

[tex]f'(y)=9e^{9y}-9e^{-9y}[/tex]

Therefore, the differentiation of the given function is [tex]f'(y)=9e^{9y}-9e^{-9y}[/tex].

Answer:

this is the answer Hope's it helps

Answer:

72 ft^2

Step-by-step explanation:

A = bh

A = 12 ft * 6 ft

A = 72 ft^2

Answer:

72

Step-by-step explanation:

you have to do base times height

Answer:

a. (-4,8)

Step-by-step explanation:

the two lines intersect at this point

Answer:

Mean=2.53

median=2

mode=2

range=3

Step-by-step explanation:

1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4

MEAN

Add up all data values to get the sum

Count the number of values in your data set

Divide the sum by the count

38/15=2.53

MEDIAN

Arrange data values from lowest to the highest value

The median is the data value in the middle of the set

If there are 2 data values in the middle the median is the mean of those 2 values.

MODE

Mode is the value or values in the data set that occur most frequently.

RANGE

18-15=3

Answer:

18.5 - - - - NO

24.3 ____ NO

21.6 __ YES

26.5 ___No

23.3 ___ YES

Step-by-step explanation:

Estimate = 22.5 gallons

Error margin = 4%

Hence ;

4% of 22.5 = 0.9

Actual usage :

(22.5 - 0.9) = 21.6

(22.5 + 0.9) = 23.4

Actual usage is within (21.6 ; 23.4)

Hence,

18.5 - - - - NO

24.3 ____ NO

21.6 __ YES

26.5 ___No

23.3 ___ YES

Answer:

f has no critical points.

Step-by-step explanation:

We are given:

[tex]f(x)=\cos(x)+2x[/tex]

A function has critical points whenever its derivative equals 0 or is undefined.

Differentiate the function:

[tex]f'(x)=-\sin(x)+2[/tex]

Since this will never be undefined, solve for its zeros:

[tex]0=-\sin(x)+2[/tex]

Hence:

[tex]\displaystyle \sin(x)=2[/tex]

Recall that the value of sine is always between -1 and 1.

Thus, no real solutions exist.

Therefore, f has no critical points.

Answer:

option B

Step-by-step explanation:

Answer:

Step-by-step explanation: hope u like that cus i sike that C?

Answer:

B looks like a 180 degree angle cause its js a straight line and isnt curved or bent. Brainliest plz?

Step-by-step explanation: