What is the solubility of KNO3 at 50°C?
45 grams
63 grams
70 grams
83 grams

Answers

Answer 1
I need this answer too , can someone please help , I have a time limit , please
Answer 2

Answer:

The solubility of KNO3 at 50 degrees C is 83 g/100 g water.

Explanation:

when u see the graph and by using graph reading techniques then u find the solubility.


Related Questions

A negative charge of 4.0 x 10 C and a positive charge of 7.0 x 10 C are separated by 0.15 m. What is the force between the two charges?

Answers

1117.51N/C hope this helps

One example of angular momentum is someone (like Bill Nye, the Science Guy) on a rotating platform. In a regular year we would have done this in lab ourselves, but since we can't - have a video instead. Assume for now we are talking about when he has his arms pulled in towards his torso and not stretched out. Bill Nye has a mass of 84.0 kg, a height of 1.50 m and a radius of 16.0 cm. He is spinning at a rate of 5.00 rpm (revolutions / minute) by the end of the video. What is his angular momentum based on these numbers

Answers

Answer:

‭0.563 kg-m²/s

Explanation:

Bill Nye's angular momentum L = Iω where I = rotational inertia = 1/2MR² (since we are considering him to be cylinder with his axis of rotation from is top to bottom- that is vertical through his height) where M = his mass = 84.0 kg and R = his radius = 16.0 cm = 0.16 m and ω = angular speed = 5.00 rpm = 5.00 × 2π/60 = π/6 rad/s = 0.524 rad/s

L = Iω

L = 1/2MR²ω

Substituting the values of the variables into the equation, we have

L = 1/2MR²ω

L = 1/2 × 84.0 kg × (0.16 m)² × 0.524 rad/s

L = 1/2 × 84.0 kg × ‭0.0256‬ m² × 0.524 rad/s

L = 1/2 × ‭1.12681 kg-m²rad/s

L = ‭0.5634 kg-m²rad/s

L ≅ ‭0.563 kg-m²/s

A rabbit dashes across a field in a zig-zag pattern trying to outrun a fox. If the rabbit’s average is speed is 9.8 m/s it reaches the hole in 8.5 s what is the total distance it ran?

Answers

Answer:

83.3 m

Explanation:

From the question,

Applying on of the formula of velocity

V = d/t.................. Equation 1

Where V = average velocity, d = distance, t = time.

make d the subject of the equation

d = V×t................. Equation 2

Given: V = 9.8 m/s, t = 8.5 s

Substitute these values into equation 2

d = 9.8×8.5

d = 83.3 m

Hence the total distance covered by the rabbit is 83.3 m

1. A group of students were trying to find the greatest
rebounded height of a rubber ball dropped on a basketball
court. They dropped from 3 different heights. The chart
below has their data.
26 cm
Drop Height Chart
Trials Drop height Rebound height
Trial 12 meters 103 cm
Trial 2% meter
Trial 31 meter 58 cm
Which explanation is the best reason for why trial 1 has the
greatest rebound height?
A. The speed of the ball is determined by the distance it
travels.
B. The force applied to the ball is a balanced force.
C) The greater the force applied to the ball the greater the
change in motion.
D. The closer the ball is to the ground the more gravity it
has.

Answers

Answer:

D th

Explanation:

D B. The force applied to the ball is a balanced force.

Which best labels the chart?

Title 1 is “Longitudinal Waves,” and Title 2 is “Transverse Waves.”
Title 1 is “Transverse Waves,” and Title 2 is “Longitudinal Waves.”
Title 1 is “Electromagnetic Waves,” and Title 2 is “Mechanical Waves.”
Title 1 is “Mechanical Waves,” and Title 2 is “Electromagnetic Waves.”

Answers

Answer:

the answer is b!!!!

Explanation:

just took the test

The best labeling for the chart would be Title 1 is "Transverse Waves," and Title 2 is "Longitudinal Waves." Therefore, the correct option is B.

The two types of waves that are the subject of the chart under consideration are transverse waves and longitudinal waves. While longitudinal waves have vibrations parallel to the path of wave travel, transverse waves have vibrations perpendicular to the direction of wave propagation.

The graphic distinguishes between these wave types by designating title 1 as "transverse wave" and title 2 as "longitudinal wave". Using this labeling, viewers can understand and differentiate the two wave ranges based on their unique characteristics.

So, the correct option is B.

Learn more about longitudinal wave, here:

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fule cells have been developed that can generate a large amount of energy. for example, a hydrogen fuel cell works by combining hydrogen and oxogen gas to produce water and electrical energy. if a fuel cell can generate 10.0 kilowatts of power and the current is 15.8 amps, what is the voltage of the electricity?​

Answers

Answer:

Where are fuel cells used?

Fuel cells are used for primary and backup power for commercial, industrial and residential buildings and in remote or inaccessible areas. They are also used to power fuel cell vehicles, including forklifts, automobiles, buses, boats, motorcycles and submarines

Explanation:

Kilowatts should be converted to watts. Simply just move the decimal place to the right three times.
10,000 W / 15.8 A = V
632.9, or 633.
Hope this helps!

A negative point charge - is at the center of a hollow insulating spherical shell, which has an inner radius R1 and an outer radius R2. There is a total charge of +7Q spread uniformly throughout the volume of the insulating shell, not just on its surface. Determine the electric field for the following. (Use any variable or symbol stated above along with the following as necessary: r and E
(a) r < R1
(b) R1 (c) R2

Answers

The Explanation is Below

If the acceleration of the body is towards the center, what is the direction of the unbalanced force ? Using a complete sentence , describe the direction of the net force that causes the body to travel in a circle at a constant speed.

Answers

Accelerating objects are changing their velocity. Velocity is often thought of as an object's speed with a direction. Thus, objects which are accelerating are either changing their speed or changing their direction. They are either speeding up, slowing down or changing directions. Changing the velocity in any one of these three ways would be an example of an accelerated motion.

what is the period of motion of an hour hand on a clock face

Answers

Answer:

Reading a modern clock face

Explanation:

In the analog clock, the minute hand is on "14" minutes, and the hour hand is moving from "12" to "1" - this indicates a time of 12:14.

6. If an object accelerates at 3m/s/s, how long does it take for the object to travel at a speed of 12 m/s. ​

Answers

Answer:

4 seconds

Explanation:

Assuming that the object started from rest,

v = at

--> t = v/a = (12 m/s) / (3 m/s^2)

= 4 seconds

Electric Charge and Current Quiz CP ( fill in blank)

Answers

Answer:

1. Positive

2. Negative

3. induction

4. Insulator

5. Voltage

6. Static energy

7. Positive, Negative

8. Resistance

9. Increase

Would appreciate if you mark me as brainliest answer

1. Protons have positive electric charge and electrons have negative electric charge.

2. Opposite charges attract and like charges repel.

3. Charging by induction is the rearrangement of electrons on a neutral object caused by a nearby charged object.

4. Insulator are materials that do not allow electric current to pass through easily.

5. Voltage is the accumulation of electrical charges on on object.

6.Current is usually the flow of static electricity.

7. Charges flow from positive voltage to negative voltage.

8. The tendency of material to oppose the flow of electron is called resistance.

9. Making wires thinner, longer or hotter Increase the resistance.

What is current?

The current is the stream of charges which flow from positive to negative terminal of voltage source.  

Voltage is the collection or storage of charges. Resistance of the circuit is the opposition to the flow of current.

Charging a neutral object is done by induction. Like charges repel each other and unlike charges attract each other. The electron are positive charged and proton are positive charged.

Learn more about current.

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g A high-speed flywheel in a motor is spinning at 500 rpm when a power failure suddenly occurs. The flywheel has mass 39.0kg and diameter 78.0cm. The power is off for 34.0s, and during this time the flywheel slows due to friction in its axle bearings. During the time the power is off, the flywheel makes 170 complete revolutions.At what rate is the flywheel spinning when the power comes back on?

Answers

Answer:

[tex]10.54\ \text{rad/s}[/tex]

Explanation:

[tex]\omega_i[/tex] = Initial angular velocity = 500 rpm = [tex]500\times \dfrac{2\pi}{60}\ \text{rad/s}[/tex]

[tex]\omega_f[/tex] = Final angular velocity

t = Time = 34 s

[tex]\theta[/tex] = Angular displacement = 170 revs = [tex]170\times 2\pi\ \text{rad}[/tex]

[tex]\alpha[/tex] = Angulr acceleration

From the kinematic equations of angular motion we have

[tex]\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \alpha=\dfrac{\theta-\omega_it}{\dfrac{1}{2}t^2}\\\Rightarrow \alpha=\dfrac{170\times 2\pi-500\times \dfrac{2\pi}{60}\times 34}{\dfrac{1}{2}\times 34^2}\\\Rightarrow \alpha=-1.23\ \text{rad/s}^2[/tex]

[tex]\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=500\times \dfrac{2\pi}{60}+(-1.23)\times 34\\\Rightarrow \omega_f=10.54\ \text{rad/s}[/tex]

The rate at which the wheel is spinning when the power comes back on is [tex]10.54\ \text{rad/s}[/tex].

ou are making a clock out of a solid disk with a radius of 0.2m and mass of 0.1 kg that will be attached at its center of mass to the end of a uniform thin rod with a mass of 0.3 kg. Calculate The length of the rod such that the period of the system is 1 second.The distance from the pivot to theCOM of the system must be expressed in terms of L. The parallel axis theorem must be used for both therod and the solid disk in terms of L as well. There will be a quadratic equation to be solved

Answers

Answer:

the correct result is L = 0.319 m

Explanation:

This system is a physical pendulum whose angular velocity is

         w² = [tex]\frac{M \ g \ d}{I}[/tex]

where d is the distance from the center of mass to the point of rotation and I is the moment of inertia of the system

The Moment of Inertia is a scalar, therefore an additive quantity

          I = I_bar + I_disk

the moment of inertia of each element with respect to the pivot point can be found with the parallel axes theorem

let's use M for the mass of the bar and m for the mass of the disk

Bar

          I_bar = I_{cm} + Md²

the moment of inertia of the center of mass is

          I_{cm} = [tex]\frac{1}{12}[/tex] M L²

the distance from the center of mass

           d = L / 2

we substitute

         I_bar = [tex]\frac{1}{12}[/tex] M L² + M ([tex]\frac{L^2}{4}[/tex])

Disk

          I_disk = I_{cm} + m d²

moment of inertia of the center of mass

          I_{cm} = ½ m R²

the distance d is

         d = L

we substitute

          I_disk = 1/2 m R² + m L²

the total moment of inertia is

          I = [tex]\frac{1}{12}[/tex] M L² +[tex]\frac{1}{4}[/tex] M L² + [tex]\frac{1}{2}[/tex] m r² + m L²

          I = [tex]\frac{1}{4}[/tex] M L² + m L² + ½ m r²

          I = L² (m + [tex]\frac{1}{4}[/tex] M) + ½ m r²

The position of the center of mass of the system can be found with the expressions

         d_{cm} = [tex]\frac{1}{M} \sum r_i m_i[/tex]

         d_{cm} = [tex]\frac{1}{m+M} \ ( M \frac{L}{2} + m L)[/tex]

         d_{cm} = [tex]L \frac{m + M/2}{m +M }[/tex]

now we can substitute in the expression for the angular velocity

         w² = (m + M) g  L  [tex]\frac{m + \frac{M}{2} }{m+M}[/tex]   [tex]\frac{1}{L^2 (m+ \frac{M}{4} ) + \frac{1}{2} m r^2 }[/tex]

         w² = g (m + [tex]\frac{1}{2}[/tex] M)   [tex]\frac{L}{ L^2 ( m +\frac{1}{4} M ) + \frac{1}{2} m r^2}[/tex]

angular velocity and period are related

         w = 2π/T

sustitute

        4π²/T² =   g (m + [tex]\frac{1}{2}[/tex] M)   [tex]\frac{L}{ L^2 ( m +\frac{1}{4} M ) + \frac{1}{2} m r^2}[/tex]  

         L² (m + [tex]\frac{1}{4}[/tex] M)  + ½ m r² =  [tex]\frac{T^2}{4 \pi ^2 } \ g ( m + \frac{1}{2} M ) \ \ L[/tex]

we substitute the values ​​and solve the second grade equation

          L² (0.1 + [tex]\frac{1}{4}[/tex] 0.3) - [[tex]\frac{1^2}{4\pi ^2}[/tex]  9.8 (0.1 + 0.3/2) ]  L + ½ 0.1 0.2² = 0

          L² 0.175 - 0.06206 L + 0.002 = 0

       

the equation remains after simplifying

          L² - 0.3546 La + 0.01143 = 0

solve us

           L = [tex]\frac{0.3546 \ \pm \sqrt{ 0.3546^2 - 4 \ 0.01143 }}{2}[/tex]

           L = [tex]\frac{0.3546 \ \pm \ 0.28288 }{2}[/tex]

           L₁ = 0.319 m

           L₂ = 0.036m

the correct result must have a value greater than the radius of the disk.  The correct result is L = 0.319 m

Why would the kinetic energy at the bottom of the track be less than the potential energy at the top of the track?

Answers

Answer:

This is because of friction and heat lost.

Explanation:

A nuclear power plant generates a total of 3 GW of power at an efficiency of 33%. The nuclear reactor has a recoverable energy per fission of 210 MeV. Approximately 65% of the plant's power comes from fissions in 235U, the remainder from fissions in plutonium, 239Pu. calculate: (a) the net electric power output, (b) the rate of fission events (per second) in the reactor core, (c) the mass of 235U used up in one year (hint: every fission event consumes one 235U nucleus and in the reactor core about 1.0 (1020) nuclei of U 235 are consumed every second. (d) If the plant were operated at full power for 1 year, how many

Answers

Answer:

Explanation:

From the question we are told that:

Plant Generates [tex]P=3GW[/tex]

Efficiency [tex]\eta =33\%[/tex]

Recoverable energy per fission [tex]\mu=210MeV \approx 336.42*18^{-7}J[/tex]

Fission Power [tex]F_p=235U[/tex] [tex](65\% of Plant\ power)[/tex]

Fission in plutonium [tex]F_{pl}=239Pu[/tex]

a)

Generally the equation for net electric power output [tex]P_o[/tex] is mathematically given by

[tex]P_o=P*\frac{1}{\eta}[/tex]

[tex]P_o=3*\frac{100}{3}[/tex]

[tex]P_o=9.0GW[/tex]

b)

Generally the equation for Rate of Fission [tex]F_{rate}[/tex] is mathematically given by

[tex]F_{rate}=\frac{P_o}{\mu}}[/tex]

[tex]F_{rate}=\frac{9*10^{9}}{336.42*18^{-7}}}[/tex]

[tex]F_{rate}=27.02*10^{13}[/tex]

c)

Generally the equation for  Mass of [tex]^{235} U[/tex] used in a yr [tex]M_{U/yr}[/tex] is mathematically given by

[tex]M_{U/yr}=P_o*\frac{65}{100}[/tex]

[tex]M_{U/yr}=5.91GW[/tex]

A particle cannot generally be localized to distances much smaller than its de Broglie wavelength. This means that a slow neutron appears to be larger to a target particle than does a fast neutron, in the sense that the slow neutron will probably be found over a large volume of space. For a thermal neutron at room temperature (300 K), find (a) the linear momentum and (b) the de Broglie wavelength. Compare this effective neutron size with both nuclear and atomic dimensions.

Answers

Answer:

a)   p = 1.381 10⁻²⁹ kg m / s, b)  λ = 4.80 10⁻⁵ m,

c)  λ/a₀ = 9.6 10⁴ = 10⁵,   λ/aₙ = 4.80 10⁹

Explanation:

a) as the neutral goes at speeds much lower than the speed of light we can use the classical relationships, as the neutral all the thermal energy is the energy of the neutron

           E = p c

           K T = pc

           p = k T / c

           p = [tex]\frac{ 1.381 \ 10^{-23} \ 300}{3 \ 10^8}[/tex]

           p = 1.381 10⁻²⁹ kg m / s

b) the expression for the de Broglie wavelength

          p = h / λ

          λ = h / p

          λ =[tex]\frac{ 6.63 \ 10^{-34} }{1.381 \ 10^{-29}}[/tex]

          λ = 4.80 10⁻⁵ m

c) let's compare this size with the size of atoms a₀ = 0.5 10⁻⁹ m

         λ/a₀ = [tex]\frac{ 4.80 \ 10^{-5} }{0.5 \ 10^{-9}}[/tex]

         λ/a₀ = 9.6 10⁴ = 10⁵

c) let's compare with the atomic nucleus size aₙ = 10⁻¹⁴ m

          λ/aₙ = [tex]\frac{4.80 \ 10^{-5} }{10^{-14} }[/tex]

          λ/aₙ = 4.80 10⁹

4. Speedy leaves the ground with an initial vertical velocity of 53 m/s and a horizontal velocity of 42 m/s.
How much time does he spend in the air?
How far (horizontally) does he travel during this time?
5. The Angry Bird is fired at an angle of 35 above the horizontal at a speed of 72 m/s.
Draw the initial velocity vector
Determine the initial horizontal velocity
Determine the initial vertical velocity
How much time does it spend in the air?
What horizontal distance does it go?

Answers

I know this answer I will be back

10 POINTS! SPACE QUESTION!!

Answers

Is there a p,if of the question?
Hdbsnanndmdndnsnvdmsksv fndksndndndndb Dbd be did d djbd f be d Dbd d f

Unpolarized light with intensity 370 W/m2 passes first through a polarizing filter with its axis vertical, then through a second polarizing filter. It emerges from the second filter with intensity 132 W/m2 . You may want to review (Pages 897 - 898) . Part A What is the angle from vertical of the axis of the second polarizing filter

Answers

Answer:

 θ = 32.4º

Explanation:

For this exercise let's use Malus's law

         I = Io cos² θ

in this case it indicates that the incident intensity is 370 W/m², when the first polarization passes, only the radiation with the same polarization of the polarizer emerges, that is, vertical

         I₀ = 370/2 = 185 W / m²

this is the radiation that affects the second polarizer, let's apply the expression of Maluz

         θ = cos⁻¹ ([tex]\sqrt{\frac{I}{I_o} }[/tex])

         θ = cos⁻¹ ([tex]\sqrt{132/185}[/tex])

         θ = cos⁻¹ (0.844697)

         θ = 32.4º

Can someone take there time and answer this:}

Answers

Answer:

number of tomatoes maybe?

Explanation:

it says "the number of tomatoes produced by one plant" i could be wrong

Answer:

the answer is number of tomato mark me brainiest and give me a thumb up

Explanation:

can someone please take there time and answer this for me :)

Answers

Answer:

number 1

Explanation:

they have common ancestors

the first one is correct!! the reason people study the similarities in embryos is to try and see which organisms have closer common ancestry, even if in life they are extremely different

What happens is a series circuit when you increase the number of bulbs?

Answers

The bulbs will produce lesser light than their capacity, In short they will be dimmer because the the energy will get divided in the number of bulbs.

what produces the distinctive flame color of different substances when they are ignited?

Answers

Answer:

Electrons in different metals

Explanation:

When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy.  The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.

how can we know that atmosphere exert pressure explain with figure​

Answers

Because gas particles in the air—like particles of all fluids—are constantly moving and bumping into things, they exert pressure. The pressure exerted by the air in the atmosphere is greater close to Earth's surface and decreases as you go higher above the surface. You can see this in the Figure below.

19. Using the formula V - IX R, find the voltage in an electrical component with a current of 2 A, and a resistance of 5 omega

O A 20 v
O 8.5v
O C. 2.5 V
O D. 10 v

Answers

Answer:

B

Explanation:

Answer:

B

Explanation:

BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB

Police radar guns measure the speed of moving vehicles by transmitting electromagnetic waves at a vehicle and detecting a Doppler shift in the reflected wave. Suppose police radar transmits at a frequency of 24.0 GHz and receives a wave reflected from a car moving toward the radar at 65.0 mph. Find the frequency shift Df 5 fO 2 fS between the observed (received) and source (transmitted) frequencies.

Answers

Answer:

[tex]4649.20\ \text{Hz}[/tex]

Explanation:

u = Speed of car = 65 mph

[tex]f_s[/tex] = Frequency of source = 24 GHz

c = Speed of light = [tex]3\times 10^8\ \text{m/s}[/tex]

Beat frequency or frequency shift between the observed (received) and source (transmitted) frequencies is given by

[tex]f_o-f_s=\dfrac{2uf_s}{c}\\\Rightarrow \Delta f=\dfrac{2\times 65\times \dfrac{1609.34}{3600}\times 24\times 10^9}{3\times 10^8}\\\Rightarrow \Delta f=4649.20\ \text{Hz}[/tex]

The difference between te required frequencies is [tex]4649.20\ \text{Hz}[/tex].

During transpiration, water goes from a _____ to a _____.

Answers

Answer:

WATER TO A VAPOR

Explanation:

Explanation:

During transpiration, water goes from a root to a stomata.

compute the distance and displacment of the puppy using visual analysis of the diagram?​

Answers

Answer:

Distance A:11km

B:10km

Explanation:

Displacement A and B is 9km

why are the nuclei of the heavier elements radioactive and not the lighter elements of nuclei?

Answers

Answer:

becouse most of nuclear elements are heave

Explanation:

Which of the following is an example of kinetic energy being converted to potential energy?

Answers

Of the following...?? Is there more to this question? :)

Answer:

not completed questions

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