331.29 metres (1,086.9 feet) per
A wave has a wavelength of 1.5 m and a frequency of 6.0 Hz. What is the
speed of the wave?
Answer:
9 m/sExplanation:
The speed of the wave given only it's frequency and wavelength can be found by using the formula
[tex]c = f \times \lambda[/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in m
f is the frequency in Hz
From the question we have
c = 6 × 1.5 = 9
We have the final answer as
9 m/sHope this helps you
The magnitude of acceleration due to gravity is
Select one:
a. 9.8 m/s
b. 8.9 m/s?
c. 4.6 m/s?
d. 9.8 m/s2
Answer:
The magnitude of acceleration is 9.8 m/s
Explanation:
Its not always in m/s^2 but in m/s due to the unit of distance and time
please help quick i’ll mark you brainly
The equation below shows how to calculate work done by an applied force. W equals the work done in joules (J), F equals the applied force in newtons (N), and d equals the distance in meters (m) over which the force is applied.
W = F × d
This equation can be arranged to calculate the applied force instead:
F = W ÷ d
A scientist was performing some experiments to test the designs of some simple machines. One of her experiments involved a pulley. During the experiment, a total of 2,000 J of work was done to lift a crate 5 m straight up off the floor.
Ignoring the effects of friction, determine the applied force needed to lift the crate.
A.
2,005 N
B.
400 N
C.
10,000 N
D.
1,995 N
Answer:
The solutions to this exercise is B. 400N
Question 5. One 1,5V battery runs a portable MP3 player that draws 5,7mA of current
for about six hours before it runs out.
a) What is the resistance If the portable MP3 player?
b) How much power is dissipated in the portable MP3 player?
c) Find the energy delivered by the portable MP3 player?
The International Space Station (ISS) orbits Earth at an altitude of 4.08 × 105 m above the surface of the planet. At what velocity must the ISS be moving in order to stay in its orbit?(1 point)
A) 7.91 × 10^3 m/s
B) 3.12 × 10^4 m/s
C) 7.66 × 10^3 m/s
D) 8.17 × 10^3 m/s
Satellite A is orbiting Earth at an altitude of 500 km and Satellite B is orbiting 800 km above the surface. How does the velocity of Satellite A compare to the velocity of Satellite B?(1 point)
A) It depends on the masses of the satellites.
B) The velocity of Satellite A is greater than the velocity of Satellite B.
C) The velocity of Satellite B is equal to the velocity of Satellite A.
D) The velocity of Satellite A is less than the velocity of Satellite B.
What is the direction of the net force acting on a satellite as it orbits Earth at a constant speed?(1 point)
A) in the direction the satellite is moving
B) toward the center of Earth
C) away from the center of Earth
D) opposite the direction the satellite is moving
What happens to the gravitational force and orbital velocity of a satellite as the satellite transfers to an orbit that is closer to Earth?(1 point)
A) The gravitational force decreases and the velocity increases.
B) The gravitational force increases and the velocity increases.
C) The gravitational force decreases and the velocity decreases.
D) The gravitational force increases and the velocity decreases.
Newton's second law and universal gravitation law allow to find the results for questions about the motion of satellites in orbit are:
1) The correct answer is D: v = 8.17 10³ m/s
2) The correct answer is B
The velocity of Satellite A is greater than the velocity of Satellite B.
3) The correct answer is B
Toward the center of Earth
4) The correct answer is B
The gravitational force increases and the velocity increases.
Newton's second law establishes a relationship between force, mass, and the acceleration of bodies.
F = m a
In the case of the satellite the force is given by the law of universal gravitation.
[tex]F = - G \frac{Mm}{r^2 }[/tex]
Where G is the constant of universal gravitation. M and m the mass of each object and r the distance between them.
In this case the satellite is in a circular orbit, therefore the acceleration is centripetal.
[tex]a = \frac{v^2}{r}[/tex]
We substitute.
[tex]G \frac{Mm}{r^2} = m \frac{v^2}{r}[/tex]
[tex]\frac{GM}{r} = v^2[/tex]
Let's analyze the answers to find the correct one.
1) They indicate the height of the space station r = 4.08 10⁵ m and ask the speed.
[tex]v= \sqrt{ \frac{6.67 \ 10 ^{-11} 5.9 \ 10^{24}}{4.08 \ 10^6 } }[/tex]
v = 9.82 10³ m / s
The correct answer is D.
2) Satellite A has an orbit of hₐ = 500 km and satellite b an orbit of
h_b = 800 km
The distance from the center of the earth to each satellite is:
rₐ = R + hₐ
r_b = R + h_b
rₐ = 6.37 106 + 500 10³ = 6.87 10⁶ m
r_b = 6.37 10⁶ + 800 10³ = 7.17 10⁶ m
Let's find the ratio of the speeds
[tex]\frac{v_a}{v_b} = \sqrt{ \frac{r_b}{r_a} } \\\frac{v_a}{v_b} = \sqrt{ \frac{7.17}{6.87} }[/tex]
[tex]\frac{v_a}{v_b}[/tex] = 1,022
we see that the speed of satellite a is slightly greater than the speed of satellite b.
Let's analyze the claims.
A) False. The speed does not depend on the mass of the satellites.
B) True. The velocity of a is slightly greater than the velocity of b.
C) False. The speed of a is greater.
D) False. The speed of a is greater.
3) As the orbit is circular, the force must be radial, that is, it points towards the center of the earth.
Let's analyze the claims.
A) False. The speed modulus does not change, therefore there is no acceleration in the direction of the satellite.
B) True. Aim for the center of the Earth, change the direction of the velocity.
C) False. Aim for the scepter of the earth.
D) false. The modulus of velocity is constant and the direction changes towards the center of the earth, therefore the force must go towards the center of the earth.
4) The force in the law of universal gravitation increased as the distance decreased.
When a satellite approaches the earth its speed must increase since the speed is proportional in inverse of the square root of the distance.
Let's examine the claims.
A) False. The attraction force increases.
B) True. You agree with the explanation.
C) False. The gravitational force increases.
D) False. Speed increases.
In conclusion, using Newton's second law and the universal law of gravitation we can find the results for the questions about the movement of satellites in orbit are:
1) The correct answer is D: v = 8.17 10³ m/s
2) The correct answer is B
The velocity of Satellite A is greater than the velocity of Satellite B.
3) The correct answer is B
Toward the center of Earth
4) The correct answer is B
The gravitational force increases and the velocity increases.
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Answer:
1. 7.66 × 10^3 m/s
2. The velocity of Satellite A is greater than the velocity of Satellite B.
3. toward the center of Earth
4. The gravitational force increases and the velocity increases.
Explanation:
What would be the difference in your welght if you were four times farther from the center of Earth than you are now?
you would die.
the core of the earth is as hot as the sun surface so you would be dead
7. A drag car takes off at the green light heading in a straight line. The car goes
from a complete stop to 45m/s in 9 seconds. What is its acceleration?
Answer:
405
Explanation:
If the car stops at 45m/s in 9 seconds then it took the car 405 meters to stop
How long does it take a car traveling at 45km/h to travel 100.0 m?
Answer:
8 seconds
Explanation:
Since the carspeed is in km/h, we need equal units, so we will make 100.0m 0.1000km.
Then we need to find how long it takes the car to travel 0.1km
We can use the formula distance=speed * time and get
0.1=45 * time
Therefore we get .002222... hours
Multiplying this by 3600 (to get seconds, 60x60), we get 8 seconds
Answer:
8m/s
Explanation:
speed = 45km/h
Distance = 100m
we have to find time = ?
Formula for speed is = Distance/ Time
Here Distance is given in 'm' so we need to convert speed value in 'm'
So to convert km/h in m formula is divide 45km/h by 3.6 then the km/h value gets converted in m so now the value is 12.5 m/s
So now,
speed = Distance/Time
we have to find Time
Then,
Time = Distance/ Speed
= 100/12.5
= 8m/s
Is mechanical energy the result of both kinetic and potential energy?
Answer:
Yes
Explanation:
Because putting them together would make a type of energy making the answer yes
is atmosphere pressure at high altitudes is less than the pressure at ground, true or false
Answer:
The answer is true I guess!!!
This is because the more you go up to less air it is and the pressure also gets less!!!!!!!!
Explanation:
I HOPE THAT I WAS HELPFUL TO YOU!
1. A student adds water and sugar to a jar and seals the jar so that nothing can get in or out. The
student then finds the mass of the jar containing the water and sugar. After some sugar dissolves, the
student finds the mass of the jar and its contents again.
Water
Sugar
and
Water
Sugar
Sugar
Before
After
Vhat will happen to the mass of the jar containing the water and sugar after some of the sugar
issolves?
a. The mass will stay the same
b. The mass will increase
c. The mass will decrease
The moon will donend on how much sunar dissolves
Answer:
The mass will stay the same throughout time
an object has a kinetic energy of 14 j and a mass of 17 kg how fast is the object moving
[tex]\\ \sf\Rrightarrow kE=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\Rrightarrow 14=\dfrac{1}{2}17v^2[/tex]
[tex]\\ \sf\Rrightarrow 17v^2=28[/tex]
[tex]\\ \sf\Rrightarrow v^2=28/17[/tex]
[tex]\\ \sf\Rrightarrow v^2=1.64[/tex]
[tex]\\ \sf\Rrightarrow v\approx 0.13m/s[/tex]
Physicists call any change in energy an impulse true or false?
How would you explain conduction?
Answer:
the meaning of conduction is the process by which heat or electricity is directly transmitted through a substance when there is a difference of temperature or of electrical potential between adjoining regions, without movement of the material.
Explanation:
Answer:
the process by which heat or electricity is directly transmitted through a substance when there is a difference of temperature or of electrical potential between adjoining regions, without movement of the material.
Explanation:
What is the distance traveled by the elevator between 8 s and 24 s?
m
The distance is equal to 6 m traveled by elevator between 8 s and 24 s.
What are distance and displacement?The distance is described as the total length covered by an object. Distance is a scalar parameter with no direction. The distance covered by an object is always +ve, it can never be zero.
The displacement is described as the shortest length between two points by the object. The displacement is a vector parameter with direction & magnitude. The displacement can be +ve, -ve, or zero and can increase or decrease over time.
Given the position of the elevator at time t = 8 s at d = 9 m
The position of the elevator at time t = 24 s at d = 15 m
The distance covered by the elevator = 15 - (9) = 15 - 9 = 6 m
Therefore, the distance traveled by an elevator between 8 s and 24 s is equal to 6 m.
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on which principle does a thermometer is based
Answer:
thermal expansion
hope it helps
A loaded truck collides with a car causing huge damage to the car. Which of the following is true about the collision? *
A. The force on the truck is greater than the force on the car
B. The force on the car is greater than the force on the truck
C. The force on the truck is the same in magnitude as the force on the car
D. During the collision the truck makes greater displacement than the car
E. During the collision the truck has greater acceleration than the car
The force on the truck is the same in magnitude as the force on the car.
The impulse experienced by an object during collision is directly proportional to the applied force and time of collision of the objects.
J = Ft
where;
J is the impulse experienced by the objectt is the timeThe increase in the force applied to an object causes an increase in the impulse experienced by the object.
Also, according to Newton's third law of motion, the force exerted on the loaded truck and the car are equal in magnitude but opposite in direction.
Thus, we can conclude that, the force on the truck is the same in magnitude as the force on the car.
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[tex] \huge \rm༆ question ༄[/tex]
Calculus proof of second equation of motion ~
Newton's second equation of motion :-
S=ut+1/2at^2 [where, u is the initial velocity, a is the acceleration and t is the time interval]
This Equation simply finds a relation between distance travelled by a particle (classically) under uniform acceleration.
So let's see what pieces of information (bundles of equations) do we have with us, initially.
We have, a very primary equation with us,
dS/dt = v… (I)
(Considering motion in a straight line only)
And we also have the equation
dv/dt = a…(II)
Simply replacing the v in eqn (II) by eqn (I), we find
d2S/dt^2 = a…(III)
This is what we need to solve. It's easy.
You know,
d2S/dt^2 = d/dt(dS/dt) = a
⟹ dS/dt = ∫adt = at+c1
Since, dS/dt is the velocity of the particle,
Therefore, at t = 0, dS/dt|t = 0 = u
⟹ u = a∗0 + c1 = c1
⟹ c1 = u
Therefore, dS/dt = u + at
Thus, S = ∫(udt + atdt)
⟹ S = ut + 1/2at^2 +c^2
If say, the particle is already having a displacement S0 the moment you start measuring it's motion. Then, at t = 0, S = S0
This makes S = S0 +ut + 1/2at^2
Since, in most of the practical cases, we start measuring a motion when the particle starts displacing (i.e., when S0=0 ),
We get
S = ut + 1/2at^2
Hope it helps :)
a 1.0 kg ball falls from rest a distance of 15 m. what was its change in potential energy?
Answer:
147 J
Explanation:
PE = mgh
PE = (1.0)(9.8)(15)
PE = 147 joules
A go cart with a mass of 60 kg is moving at a rate of 10 m/s. How much Kinetic Energy does the go cart have?
Answer:
3000 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass in kg
v is the velocity in m/s
From the question
m = 60 kg
v = 10 m/s
We have
[tex]k = \frac{1}{2} \times 60 \times {10}^{2} \\ = 30 \times 100 \\ = 3000[/tex]
We have the final answer as
3000 JHope this helps you
Answer:
[tex]\boxed {\boxed {\sf 3000 \ J}}[/tex]
Explanation:
Kinetic energy is the energy an object has due to motion. It is calculated using the following formula:
[tex]KE=\frac{1}{2} mv^2[/tex]
The mass of the go-cart is 60 kilograms and the velocity is 10 meters per second.
m= 60 kg v= 10 m/sSubstitute the values into the formula.
[tex]KE= \frac{1}{2} (60 \ kg)(10 \ m/s)^2[/tex]
Solve the exponent.
(10 m/s)² = 10 m/s * 10 m/s = 100 m²/s²[tex]KE = \frac{ 1}{2} (60 \ kg)(100 \ m^2/s^2)[/tex]
Multiply the numbers together.
[tex]KE= 30 \ kg * 100 \ m^2/s^2[/tex]
[tex]KE= 3000 \ kg*m^2/s^2[/tex]
Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer of 3000 kg*m²/s² equals 3000 Joules.
[tex]KE= 3000 \ J[/tex]
The go-cart has 3000 Joules of kinetic energy.
HELP ASAP WHOEVER ANSWERS FIRST WITH BE BRAINIEST PLEASE HELP!
The answer is : A₃ = A₁ - A₂ = 3.0 - 2.0 = 1.0A
Ok done. Thank to me :>
mrs. knight drops her briefcase. when the briefcase lands on the floor, what is the reaction force to the action force of the briefcase on the floor?
Answer:
The force of the floor on the briefcase
Explanation:
The briefcase hits the floor and stops the falling which is reacting to the briefcase that was falling and hits the floor.
The falling briefcase would be the action force because it is moving downward
and
The reaction force would be the floor because it will react on the briefcase.
Hope this Helps
When the briefcase lands on the floor, the reaction force to the action force of the briefcase on the floor is force of the floor on the briefcase.
What are action force and reaction force?
It might be difficult to distinguish between action and reaction forces. This is due to the fact that both forces are always present.
One might argue that there are an equal number of forces in the universe if one were to count them all. However, the definition of the action force is provided by the perspective of the interaction analysis in order to help the argument.
A force that is applied to an object is known as an action force.
An action force with an opposite direction has an effect called a reaction force.
These two forces—also referred to as action and reaction forces—are covered by Newton's third law of motion.
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The distance between adjacent nodes in a standing wave pattern is 25.0 cm. What is the
wavelength? If the frequency is 200. Hz, what is the speed of the wave?
Answer:
Answer:
Speed of the wave in the string will be 3.2 m/sec
Explanation:
We have given frequency in the string fixed at both ends is 80 Hz
Distance between adjacent antipodes is 20 cm
We know that distance between two adjacent anti nodes is equal to half of the wavelength
So \frac{\lambda }{2}=20cm
2
λ
=20cm
\lambda =40cmλ=40cm
We have to find the speed of the wave in the string
Speed is equal to v=\lambda f=0.04\times 80=3.2m/secv=λf=0.04×80=3.2m/sec
So speed of the wave in the string will be 3.2 m/sec
Which car will experience a greater KE, a car traveling at 16 m/s or a half as massive car traveling at 32 m/s
Answer:
The car that is hald as massive
Explanation:
We can use the eqation for kinetic energy to solve this problem
KE = 1/2mv^2 (where m is mass and v is velocity/speed)
Lets give the original car a mass of 100kg and use the equation
KE = 1/2(100kg)(16m/s)^2 = 12800J
and now lets find kinetic energy of the half as massive car
KE2 = 1/2(50kg)(32m/s)^2 = 25600J
From this, we find that the hald as massive car will experience a greater kinetic energy while travling at double the velocity
4. Marcia consumes 8.4 X 10.J (2000 food calories) of energy per day while maintaining a constant weight.
What is the average power she produces in a day? 97 Watts
Answer:
8.40 is your answer.
Explanation:
The average power she produces in a day be 97.22 Watts.
What is power?The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.
Marcia consumes total amount of energy per day = 2000 calories = 8.4 × 10⁶ joule.
1 day = 24 × 60 × 60 second = 86400 second
So, average power she produces in a day = energy/time
= 8.4 × 10⁶ joule/86400 second
= 97.22 Watts
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10. What do you think the effect is of jet airplanes on global warming?
Answer:
Like other emissions resulting from fossil fuel combustion, aircraft engines produce gases, noise, and particulates, raising environmental concerns over their global effects and their effects on local air quality.[2]Jet airliners contribute to climate change by emitting carbon dioxide (CO2), the best understood greenhouse gas, and, with less scientific understanding, nitrogen oxides, contrails and particulates. Their radiative forcing is estimated at 1.3–1.4 that of CO2 alone, excluding induced cirrus cloud with a very low level of scientific understanding. In 2018, global commercial operations generated 2.4% of all CO2 emissions.
Between 1940 and 2018, aviation CO2 emissions grew from 0.7% to 2.65% of all CO2 emissions.[1]
Jet airliners have become 70% more fuel efficient between 1967 and 2007, and CO2 emissions per Revenue Ton-kilometer (RTK) in 2018 were 47% of those in 1990. In 2018, CO2 emissions averaged 88 grams of CO2 per revenue passenger per km. While the aviation industry is more fuel efficient, overall emissions have risen as the volume of air travel has increased. By 2020, aviation emissions were 70% higher than in 2005 and they could grow by 300% by 2050.
Aircraft noise pollution disrupts sleep, children's education and could increase cardiovascular risk. Airports can generate water pollution due to their extensive handling of jet fuel and deicing chemicals if not contained, contaminating nearby water bodies. Aviation activities emit ozone and ultrafine particles, both of which are health hazards. Piston engines used in general aviation burn Avgas, releasing toxic lead.
Aviation's environmental footprint can be reduced by better fuel economy in aircraft or Air Traffic Control and flight routes can be optimised to lower non-CO2 effects on climate from NO
x, particulates or contrails. Aviation biofuel, emissions trading and carbon offsetting, part of the ICAO's CORSIA, can lower CO2 emissions. Aviation usage can be lowered by short-haul flight bans, train connections, personal choices and aviation taxation and subsidies. Fuel-powered aircraft may be replaced by hybrid electric aircraft and electric aircraft or by hydrogen-powered aircraft.
It requires a 70.4 N force (parallel to the inclined plane) to pull a 5.86 kg box up a 58.1° inclined plane with a rope at a constant speed. (a) What is the coefficient of kinetic friction between the inclined plane and the box?
(b) If the rope were to break, what acceleration would the box experience as it slid down the ramp?
Answer:
0.667; 4.965
Explanation:
Look at the picture I attached for the force analysis.
a) The coefficient=Friction/Normal Force. Because it's at constant speed, the force of friction + mgsin58.1° (because it's on an inclined plane and has split forces) is equal to the applied force (70.4N). Normal force is not equal to weight force though, because the box is on an inclined plane; it's equal to mgcos58.1°.
b) If it were to break, then the box no longer has an applied force, and the direction of friction has changed to up the inclined plane. F=m/a, so acceleration = mgsin58.1°- Friction/mass
astronauts appear weightless while working in the international space station because
cause there's no gravity therefore they appear weightless
i. a A ball is released from a height of 45 m top of the building. If it strikes the ground surface after 5 seconds, calculate the acceleration and final velocity of the ball. [18 m/s, 3.6 m/s²].
Answer:
3.6m/s², 18m/s
Explanation:
So according to h=1/2at², 45=1/2a*25, a=3.6m/s² (which means that it didn't happen on Earth?)
Final velocity = at = 3.6*5 = 18 m/s
A log has a density of. 8 g/cmÂł. What will happen to this log in freshwater, which has a density of 1. 0 g/cmÂł? It will sink. It will float. It will move deeper. It will decrease in density.
When a log of wood is put over the freshwater, the log start to float. Option B is correct.
Density:
It can be defined as the amount of substance per unit volume. It is usually denoted by D. It is measured in the [tex]\bold { kg/m^3}[/tex].
The less dense object always floats over the more dense substance.
For example- Here, The density of the log is 0.8 [tex]\bold{ cm^3}[/tex] and the density of the of water is 1.0 [tex]\bold{ cm^3}[/tex] .
Since, the density of the log is lesser than the density of the water.
Therefore, when a log of wood is put over the freshwater, the log start to float.
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