Explanation:
The sulphur atom has 6 electrons in the outermost shell, and its valency could be 6. But it is easier for sulphur to gain two electrons instead of losing six electrons. Hence, its valency is determined by subtracting six electrons from the octet and this gives a valency of two for sulphur.
A horizontal force of 15N is needed to keep a box sliding on a horizontal floor at a constant speed of 0.5m/s. The speed of the box is increased to 1.5m/s by some means (which is not the concern of this question). What horizontal force would be needed to keep the same box sliding on the same horizontal floor at a constant speed of 1.5m/s?
The horizontal force needed to keep the same box sliding on the same horizontal floor at a given constant speed is 45 N.
Horizontal forceThe horizontal force needed to keep the same box sliding on the same horizontal floor at a given constant speed is calculated as follows;
[tex]F= \frac{mv}{t} \\\\mv = Ft\\\\m = \frac{Ft}{v} \\\\\frac{F_1}{v_1} = \frac{F_2}{v_2}[/tex]
where;
v1 is the initial velocityv2 is the final velocity[tex]F_2 = \frac{F_1v_2}{v_1} \\\\F_2 = \frac{15 \times 1.5}{0.5} \\\\F_2 = 45 \ N[/tex]
Thus, the horizontal force needed to keep the same box sliding on the same horizontal floor at a given constant speed is 45 N.
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Find the charge on capacitor, C2 , in the diagram below if V_ab=24.0 volts,〖 C〗_1=6.00 μF,〖 C〗_2= 3.00 μF,and C_3=10.0 μF.
The charge on the capacitor 2 (C₂) is 48μF.
Explanation of the circuit diagram
In the circuit diagram, C₁ and C₂ are in series connection, while C₃ is parallel to C₁ and C₂.
Same charge flows in a series arrangement (charge on C₁ = charge on C₂).Same voltage flows in a parallel arrangement (voltage on C₁, C₂ = voltage on C₃).Charge on capacitor C₁ and C₂[tex]Q_1 = Q_2 = Q\\\\V = \frac{Q}{C_1} + \frac{Q}{C_2} \\\\V = Q(\frac{1}{C_1} + \frac{1}{C_2} )\\\\Q = V (\frac{C_1C_2}{C_1 + C_2} )\\\\Q = 24 \times (\frac{6 \times 10^{-6} \times 3 \times 10^{-6}}{6\times 10^{-6} \ + \ 3 \times 10^{-6}} )\\\\Q = \frac{4.32 \times 10^{-10}}{9\times 10^{-6}} \\\\Q = 48 \ \mu C[/tex]
Thus, the charge on the capacitor 2 (C₂) is 48μF.
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A Hunter points his gun at a squirrel on a branch of a tree away from him. Assume he lies on the ground and that the moment he fires his gun the squirrel drops off the branch. Show that the squirrel should not have dropped if it was to avoid being shot.(neglect air resistance).
Answer:
well if it wasn't shot then it shouldn't have been affected
Explanation:
What type of energy is stored in the food we eat?
Answer:
chemical energy
Explanation:
hope this helps
A fighter jet is being tested before it is delivered. The jet took off and had its initial velocity of 280 m/s. As the pilot ask permission from the flight control to test its capacity the jet reached its final velocity of 1250 m/s in just 20 seconds. What is the acceleration of the fighter jet?
Answer:
48.5 m/s².
Explanation:
We can use the following kinematic equation:
[tex]\displaystyle v_f = v_i + at[/tex]
Substitute in the appropriate values and solve for acceleration a:
[tex]\displaystyle \begin{aligned} (1250\text{ m/s}) & = (280\text{ m/s}) + a(20\text{ s}) \\ \\ a & = 48.5\text{ m/s$^2$} \end{aligned}[/tex]
Therefore, the acceleration of the fighter jet was 48.5 m/s².
Why do lunar and solar eclipses not happen every month
Answer:
A lunar eclipse occurs when the Moon enters the Earth’s shadow. A solar eclipse occurs when the Moon’s shadow falls on the Earth. They do not happen every month because the Earth’s orbit around the sun is not in the same plane as the Moon’s orbit around the Earth.
Explanation:
You are a passenger in a car, holding a cup of water in one hand. The driver is
forced to stop suddenly, causing the water in your cup to spill out in front of
you. The water likely spilled because:
A. every force is balanced by an opposing force.
B. an object in motion tends to stay in motion.
C. rapid changes in direction cause deceleration,
D. a force is exerted by a change in acceleration.
Answer:
the answer is b because an object in motion stays in motion
The water likely spilled because of inertia of motion such that an object in motion tends to stay in motion. So, option B is correct.
What is meant by inertia ?Inertia is defined as the property of matter by which it tends to continue its state of rest or uniform motion.
Here,
When you are travelling in a car, holding a cup of water in one hand and the driver of the car is forced to stop suddenly so that the water in the cup gets spilled out.
When the car was moving, the water in the cup was actually at the same speed relative to the car and cup. When the car is tend to stop suddenly, this causes a sudden change in acceleration of the car and thus the cup. As a result, the water in the cup spills out. This is due to the property of inertia that the water got spilled out.
According to the law of inertia, a body will preserve its state of rest or uniform motion unless an external force acts on it.
Here, the spilling out of water is the application of inertia of motion. That means the the water inside the cup which was moving forward and when the change in acceleration occurred, it got spilled in front of you thus tending to continue its state of motion.
Hence,
The water likely spilled because of inertia of motion such that an object in motion tends to stay in motion.
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Two objects are placed touching each other. Object A has a temperature of 1 T and Object B has a temperature of 2 T. What will be true after some time has passed?
A. Object A will possess more heat than it did at the beginning.
B. Object B will lose more heat than Object A gains.
C. Heat will flow from Object A to Object B.
D. Heat will flow from Object B to Object A.
Answer:
im pretty sure its D
Explanation:
Answer:
D
Explanation:
Heat will flow from object B to object A
24 volts is applied to a series circuit that has a 160, 100, 82, and 120 ohm resistors within the circuit. What is the current flow through the circuit
Answer:
0.0519480519 A
Explanation:
First find equivalent resistance:
R series = R1 + R2 + R3 ...
[tex]R_{eq} = 160+100+82+120=462ohms[/tex]
Now calculate current:
V = IR
[tex]I = \frac{V}{R}[/tex]
[tex]I= \frac{24}{462} = 0.0519480519 A[/tex]
If each pull-up requires 300 J and Dan does a pull-up in 1.5 seconds, what is his power? 1000 watts 800 watts 400 watts 200 watts
Please urgent
7. The average force applied by the engine of a 1200 kg car is 900 N. If the car is
initially traveling at 15 m/s, how fast will it be traveling 300 m farther down the road?
final speed will be 25.98 m/s Explanation Force applied by the engine on the car is We have to find final speed of the car after travelling 300 m , so displacement of car is given as so wor done by the engines on the car
Answer:
[tex]F=ma \\ 900 = 1200a \\ a = \frac{3}{4} m. {s}^{ - 2} \\ {v}^{2} = {u}^{2} +2 as \\ {v}^{2} = {(15)}^{2} + 2( \frac{3}{4} )(300) \\ = 675 \\ v = \sqrt{675} \: m. {s}^{ - 1} [/tex]
the question is on he attachment
Answer:
A. put water in a container under the pot water will disappear from the container .
Explain how the amount of acceleration will change if the net force or the mass of the object increases?
Answer:
The acceleration of an item is proportional to the net force exerted on it and inversely proportional to its mass. When the force pushing on an item rises, so does the object's acceleration. The acceleration of an item decreases as the mass of the thing increases.
If the force on an object remains constant, increasing mass will decrease acceleration. In other words, force and acceleration are directly proportional, while mass and acceleration are inversely proportional. ( How Newton's Laws of Motion Work" 29 July 2008.)
If the mass of an object is held constant, increasing force will increase acceleration. If the force on an object remains constant, increasing mass will decrease acceleration.
This net force is the resultant force of all forces acting on the body at any given instant. The larger the magnitude of this net force, the larger the acceleration of the body. One of the definitions of mass is the resistance of a body to motion in general and acceleration in particular due to the application of force.
Explanation:
When you apply a horizontal force of 51 N to a block, the block moves across the floor at a constant speed. (a) When you apply a force of 40 N to the block initially at rest, what is the magnitude of the horizontal component of the force that the floor exerts on the block? (b) When you apply a force of 59 N, what is the magnitude of the horizontal component of the force that the floor exerts on the block?
(a) When you apply a force of 40 N, the magnitude of the horizontal component of the force that the floor exerts on the block is 51 N.
(b) When you apply a force of 59 N, the magnitude of the horizontal component of the force that the floor exerts on the block is 51 N.
Net force on the blockThe horizontal component of the force that the floor exerts on the block is determined by applying Newton's second law of motion;
[tex]F = ma[/tex]
When the block moves at a constant speed[tex]\Sigma F = 0\\\\F - F_f = 0\\\\F = F_f[/tex]
[tex]F_f = F\\\\F_f = 51 \ N[/tex]
where;
[tex]F_f[/tex] is the frictional force exerted on the block by the floorSince the surface (floor) is constant, the frictional force (horizontal component of the force that the floor exerts on the block ) will be the same on the cases.
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Based on the definition of limiting frictional force;
the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 40 N when a force of 40 N is applied to the block, the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 51 N, the limiting frictional force, when a force of 59 N is applied to the block.What is force?Force is any push or pull effect which tends to cause a change in the motion or shape of an object.
Based on Newton's third law, every force produces an equal and opposite reaction.
Therefore, the force that the floor exerts on the block is oppositely direction to the force exerted by the horizontal force acting on the block.
Since a horizontal force of 51 N applied to the block is required to keep the block moving across the floor at a constant speed, this is the limiting frictional force.
a) when a force of 40 N is applied to the block, the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 40 N
b) when a force of 59 N is applied to the block, the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 51 N, the limiting frictional force.
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How far will 60J of work push a hockey puck if the applied force is 5N? Question 15 options: 0.1 meters 300 meters 12 meters 65 meters
The distance travelled by the hockey puck, given that 60 J of work was done by an applied force of 5 N is 12 meters
How do I determine the distance travelled by the hockey puck?We know already that work is the product of force and distance moved in the direction of the force:
Work done (Wd) = force (F) × distance (d)
Using the above formula, we can determine the distance travelled by the hockey puck. Details below:
Workdone (Wd) = 60 JForce applied (F) = 5 NDistance travelled (d) =?Work done (Wd) = force (F) × distance (d)
60 = 5 × distance travelled
Divide both sides by 5
Distance travelled = 60 / 5
Distance travelled = 12 meters
Thus, from the above calculation, we can conclude that the distance travelled is 12 meters
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Define the term Distance.
Maths :
The length between 2 points.
Physics =
Distance = speed × time
Distance is defined as the space between two points in space.
What is distance?Distance is defined as the space between two points in space.
The unit of distance is metres or kilometres.
Distance can be measured directly usind instruments such as metre rule and tape rule.
The formula for calculating distance is given below:
Distnce = velocity × time.
Therefore, distance is defined as the space between two points in space.
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Two objects collide and stick together. Kinetic energy
Answer:
its inertia.
Inertia is the tendency of an object to continue in the state of rest or of uniform motion
Help! Looking for the answers to this question!
The figure below shows three edge views of a square loop with sides of length ℓ = 0.240 m in a magnetic field of magnitude 1.25 T. Calculate the magnetic flux (in Wb) through the loop oriented perpendicular to the magnetic field, 60.0° from the magnetic field, and parallel to the magnetic field.
(a) perpendicular to the magnetic field? _____Wb
(b) 60.0° from the magnetic field? ____Wb
(c) parallel to the magnetic field? _____Wb
Answer:
0.072, 0.062, 0
Explanation:
Flux = magnetic field B * area A * cos(angle between B and normal of A)
= 1.25 * 0.24^2 * cos(angle) = 0.072 * cos(angle)
a) angle = 0°, flux = 0.072 Wb
b) angle = 30°, flux = 0.072*cos(30) = 0.062 Wb.
c) angle = 90°, flux = 0
A net force of 250 N is applied to a 20 kg object, what will it's acceleration be?
Answer:
1N is the same as 1kgm/s2. F= ma. For m and a, enter the numbers in the appropriate units.For m, solve F = ma: m=F/a. Plug in some numbers for F and a, with proper units, starting with m = F/a. Substitute what I said the N is equivalent to for the N. Cancel as much as you can until kg = kg. It's effective!*Good luck!
If I do 140j work in 7 seconds, how much did I produce
you produce about 20 W
Explanation:
Determine the time in which the work will be done. Here, we can take t = 60 s . Power is equal to work divided by time. In this example, P = 9000 J / 60 s = 150 W(example)
Answer:
Explanation:
To determine the power (or rate of work) produced, we can use the formula:
Power = Work / Time
Where:
Work = 140 J (joules)
Time = 7 seconds
So, we can plug in the values into the formula:
Power = 140 J / 7 s = 20 W (watts)
So, you produced 20 watts of power in 7 seconds.
It's important to note that work and power are different physical quantities. Work represents the amount of energy transferred, while power represents the rate at which that energy is transferred.
A baseball leaves the bat of Henry Aaron with a speed of 34 m/s at an angle of 370 above the horizontal. The ball is 1.2 m off the ground when it leaves the bat. To be a home run, the ball must clear a fence that is 3.0 m high and 106 m from the batter. (a.) At what times after being hit will it reach the height of the fence? (b.) How far from the batter will the ball be at these times? (c.) Will Henry have a home run? Explain
(a) The time taken for the ball to reach the height of the fence is 4.1 s.
(b) The position of the ball from the batter at the time is 111.33 m.
(c) Henry will have a home run.
Time to reach the height of the fence
The time taken for the ball to reach the height of the fence is calculated as follows;
[tex]h = v_0_y t - \frac{1}{2} gt^2\\\\(3 - 1.2) = (34 \times sin37)t - \frac{1}{2} (9.8)t^2\\\\1.8 = 20.46t- 4.9t^2\\\\4.9t^2 - 20.46t+ 1.8 = 0\\\\a = 4.9, \ b = -20.46, \ c = 1.8\\\\t = \frac{-b\pm \sqrt{b^2 - 4ac} }{2a} \\\\t = 4.1 \ s[/tex]
Position of the ball at the timeThe position of the ball at the time is calculated as follows;
[tex]X = v_x t\\\\X = (34 \times cos37) \times 4.1\\\\X = 111.33 \ m[/tex]
Since, 111.33 m is greater than 106 m, Henry will have a home run.
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Please help me Thanks!
l will help and if you get it correctly I will say you are welcome
What is the answer please help
Answer:
I think c
Explanation:
cold air pushes warm air up and then the air mixes(im not sure)
A circular coin of radius R and mass M is placed so that it touches a step of length R as shown in figure. The minimum value of the horizontal force F required to pull the coin over the step Is?
When the force is applied normal to the circumference at point P, then it's zero.
What is a force?It should be noted that force simply means an influence that can change the position of an object.
In this case, when the force is applied normal to the circumference at point P, then it's zero.
Also, if the force is applied normal to the circumference at point X, then it's constant.
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What happen when the rest of the container is filled with water?
Answer:
the water will float over mercury and the steel ball will be in it's respected place
a rock with a mass of 10.0 kg is balanced on top of a large boulder. describe the forces acting on the rock, and use the concept of forces to explain why it stays on top the boulder.
Explanation:
The forces acting on the rock include Normal Force, Gravitational force & Friction force
It's possible for it to stay on the boulder because the normal force balances it's weight. also because static friction acts on the boulder up to it's limiting friction even if it were on an attempt to move as a result of air resistance. gravitational forces act upon it by mainly affecting it it's weight. as altitude increases, it's weight decreases since gravity varies from a height to another.
What is an independent variable?
Answer:
a variable (often denoted by x) whose variation does not depend on that of another.
Explanation:
Block A has mass 1.00 kg and block B has mass 3.00 kg. The blocks collide and stick together on a level, frictionless surface. After the collision, the kinetic energy (KE) of block A is
Answer:
1/2mv²=0
1/2(4kg)(v²)=0
2=-v²
square root -2=v
v=1.414
Block A of mass 1 kg and block B has a mass of 3 kg, then the blocks collide and stick together so the kinetic energy of block A is one-third of the kinetic energy of the block.
What is Kinetic energy?Kinetic energy is a type of power that an item or particle possesses as a result of motion. When an item undergoes work—the transfer of energy—by having subject to a net force, it accelerates and consequently obtains kinetic energy. An object in motion or particle's kinetic energy, which depends on both mass and speed, is one of its features. Any combination of motions, including translation, rotation about an axis, and vibration, may be used as the type of motion.
A body's translational kinetic energy is equal to 1/2mv², or one-half of the sum of its mass, m, and the square of its velocity, v.
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What is the minimum diameter necessary for a radio telescope working at f=1×10^10 Hz to be able to separate two objects 1 deg apart?
[a] 0.03 m
[b] 0.037 m
[c] 0.47 m
[d] 2.1 m
[e] 6.3 m
A man pulls a box with an applied force of 500N. He pulls the box 100.0 m. About how much work does he do? Question options: 0.5 J 50,000 J 5,000 J 2 J
Workdone:-
[tex]\\ \tt\longrightarrow Force\times Displacement [/tex]
[tex]\\ \tt\longrightarrow 500(100)[/tex]
[tex]\\ \tt\longrightarrow 50000J[/tex]