What is the value of X?

Answer:

x = - 1

Step by step explanation:

The rational expression will be undefined if  the denominator is zero.

x+1 = 0

x =  -1

Hence, for x = -1, the given expression will be undefined.

Answer:

See the attached graph.

Step-by-step explanation:

The value of x in the triangle is 20

From the triangle, we have the following equivalent ratios:

5x+ 10 : 121 = 10 : 11

Express as fraction

5x  + 10/121 = 10/11

Multiply both sides by 121

5x + 10 = 110

Subtract 10 from both sides

5x  = 100

Divide both sides by 5

x = 20

Hence, the value of x in the triangle is 20

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Answer: B

Explanation: Key word: Atleast. This shows that you can still get 16 but it's the lowest you can get. Meaning, if you were to say, atleast get a 16% done. It'll mean that getting 16% is good but also, you'll want to get a higher number of course.

The number of hours it will take to burn 4 1/4 inches of candle is 8.5 hours in decimal.

Using ratio to solve, find the ratio of candle length to the time taken to burn down

let

4 1/2 : 9 = 4 1/4 : x

9/2 ÷ 9 = 17/4 ÷ x

9/2 × 1/9 = 17/4 × 1/x

1/2 = 17/4x

1 × 4x = 2 × 17

4x = 34

x = 34/4

x = 8.5 hours

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Answer:

0, 3 , 8

Step-by-step explanation:

substitute n = 1, 2, 3 into the pattern rule

T₁ = 1² - 1 = 1 - 1 = 0

T₂ = 2² - 1 = 4 - 1 = 3

T₃ = 3² - 1 = 9 - 1 = 8

The equivalent expression of [tex]18x^2\sqrt{14x^8} \div 6\sqrt{7x^4}[/tex] is [tex]3x^4\sqrt{2}[/tex]

The expression is given as:

[tex]18x^2\sqrt{14x^8} \div 6\sqrt{7x^4}[/tex]

Start by dividing 18 by 6

[tex]3x^2\sqrt{14x^8} \div \sqrt{7x^4}[/tex]

Next, divide 14 by 7

[tex]3x^2\sqrt{2x^8} \div \sqrt{x^4}[/tex]

Take the square root of x^8 and x^4

[tex]3x^2 * x^4\sqrt{2} \div x^2[/tex]

Divide x^2 by x^2

[tex]3* x^4\sqrt{2}[/tex]

Evaluate

[tex]3x^4\sqrt{2}[/tex]

Hence, the equivalent expression of [tex]18x^2\sqrt{14x^8} \div 6\sqrt{7x^4}[/tex] is [tex]3x^4\sqrt{2}[/tex]

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Answer: B or 3x^4 sqrt 2

explanation: only simplified answer above

The equation c = 64 - d is a linear equation, and the value of c in the equation is 64 1/6

The equation is given as:

c = 64 - d

The value of d is given as:

d = -1/6

Substitute -1/6 for d in c = 64 - d

c = 64 - -1/6

Evaluate the difference

c = 64 1/6

Hence, the value of c in the equation is 64 1/6

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The half life of the radioactive isotope to the nearest tenth is  0.83 days.

The rate of radioactive decay is the rate at which a radioactive isotope is disintegrated. The half life is the time taken for half of the original amount of radioactive isotope to remain.

Given that;

t/12 = 0.693/k

Where;

t1/2 - half life

k =decay constant

t/12 = 0.693/0.84

t/12 = 0.83 days

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For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.

111 = 1 + 1 + 1 = 3  (the sum is multiple of 3 = 3 x 1)  (111/3 = 37)

222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2)  (222/3 = 74)

213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2)  (213/3 = 71)

27 = 2 + 7 = 9  (the sum is multiple of 3 = 3 x 3)  (27/3 = 9)

Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

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Answer:

7ft; 8 minutes

Step-by-step explanation:

a. to find the height the person boarded at, plug in t=0 since this is right when the person got on the Ferris wheel. we then get:

h(0) = -45 * cos ((pi/4)*0) + 52 = 7 ft

b. to find the period, we have pi/4 * t = 2*pi, solve for t to get t=8

Answer:

  B.  The function is nonlinear.

Step-by-step explanation:

A linear function graphs as a straight line. It is a polynomial function of degree 1. Any function that is not a linear function is a nonlinear function.

__

The function given is a polynomial function of degree 2. (Its highest-degree term is x^2, which has an exponent of 2.)

Since the degree is not 1, the function is nonlinear.

_____

Additional comment

A polynomial function will never be "linear at some points and nonlinear at other points." Such a description might apply to a piecewise-defined function.

The number of values x for which the square root of 48/x a whole number are two.

The square root of a number can be described as number that when multiplied with itself yields the number.

The first step is to determine the factors of 48. Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.

The factors of 48 that will yield a perfect square when divided by 48: 3 and 12.

48 divided by 3 would give a value of 16.

48 divided by 12 would give a value of 4.

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Answer:

i can't see the question i would love to help though

Step-by-step explanation:

Answer:

y=-2x+8

Step-by-step explanation:

We want an equation of the form y=mx + b, where m is the slope and b is the value of y when x=0.

The slope of a line through the two given points:

(4,0) and (0,8)

Rise = (8-0) = 8

Run = (0-4) = -4

Slope = 8/-4 = -2

The y-intercept is given by the point (0,8), which tells us that b=8.

The equation is y = -2x + 8

Answer:

Which is the equation of the line passing through (0, 8) and (4, 0)?

The one that you are on is correct

Step-by-step explanation:

You're welcome.

Outlet A sold the greatest number of copies of album x in July and August

The tables of values are given as:

July

Album X Album Y Album Z

Outlet A 14 8 6

Outlet B 7 13 4

Outlet C 2 11 1

August

Album X Album Y Album Z

Outlet A 12 14 10

Outlet B 5 12 8

Outlet C 16 12 7

In July, the total sales of album x are:

Outlet A  = 14

Outlet B = 7

Outlet C = 2

In August, the total sales of album x are:

Outlet A  = 12

Outlet B = 5

Outlet C = 16

Add both sales

A = 14 + 12 = 26

B = 7 + 5 = 12

C = 2 + 16 = 18

26 (in outlet A) is greater than 12 and 18

Hence, outlet A sold the greatest number of copies of album x in July and August

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Answer:

Outlet D

Step-by-step explanation:

they sold 28 of album x

outlet a only sold 26

Answer:

  rule: f(n) = n³

  missing numbers: 125, 216, 343, 512, 729

Step-by-step explanation:

Your familiarity with the cubes of small integers helps you recognize each of these numbers is a cube. Their sequence is the sequence of cubes of increasing natural numbers.

  1 = 1·1·1 = 1³

  8 = 2·2·2 = 2³

  27 = 3·3·3 = 3³

  64 = 4·4·4 = 4³

__

The rule is ...

  f(n) = n³

The cubes of 5 through 9 will complete the set of numbers ...

  1, 8, 27, 64, 125, 216, 343, 512, 729

The attached image represents the triangle after it has been enlarged

The given parameters are:

From the graph, the coordinates of the triangle are:

A = (-4,2)

B = (-4,-4)

C = (-1,-4)

The rule of dilation is calculated using:

[tex](x,y) \to (k(x - a) + a, k(y - b) + b)[/tex]

So, we have:

[tex]A' = (-\frac 13(-4 +1) - 1, -\frac 13(2 - 2) + 2)[/tex]

A' = (0, 2)

[tex]B' = (-\frac 13(-4 +1) - 1, -\frac 13(-4 - 2) + 2)[/tex]

B' = (0, 4)

[tex]C' = (-\frac 13(-1 +1) - 1, -\frac 13(-4 - 2) + 2)[/tex]

C' = (-1, 4)

See attachment for the image of the triangle, after it has been enlarged

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Answer:

- 8

Step-by-step explanation:

substitute q = - 14 and r = - 6 into the expression

q - r

= - 14 - (- 6)

= - 14 + 6

= - 8

The length of the diagonal shown in the rectangular prism is; 9.5 ft

First of all, we have to find the length of the diagonal base to get;

x = √(4² + 7²)

x = √65

Thus;

Length of the diagonal shown = √(5² + (√65)²)

Length of the diagonal shown = √90

Length of diagonal shown = 9.4868

Length of diagonal shown ≈ 9.5 ft

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Answer:

got 100% on Plato

Step-by-step explanation:

Answer:

Pentagon

Step-by-step explanation:

Because as you can see, a regular pentagon is bigger than then the hexagon. If it's both in the circle below, the pentagon will most likely have an big advantage in this.

Answer:

25

Step-by-step explanation:

First we add 1 to both sides :

√x = 5

Now we square both sides :

x = 5²

x = 25

To check this answer we substitute our answer back into the original equation:

√25 - 1 = 4

5 - 1 = 4

4 = 4

✅

Hope this helped and brainliest please

Answer:

17.5%

Step-by-step explanation:

1879/10730=17.5%

Answer:

18%

Step-by-step explanation:

Locate the "receives aid" column and "graduate" row. The value 1879 is in this row and column combo.

There are 10730 students total as shown in the bottom right hand corner.

Roughly 1879/10730 = 0.1751 = 17.51% of the students are graduates who receive aid. This rounds to 18%

Answer:

the second option is correct.

Step-by-step explanation:

that is the solution above.

Answer:

13 and 30

Step-by-step explanation:

the smaller of the two numbers is 13.

If there is a 17 number difference, then that means that the second number is 30.

give brainliest, please!
hope this helps :)

Answer:

The probability is [tex]\frac{5}{9}[/tex]

Step-by-step explanation:

First we will find the probability of having a roll that is at least 3

1 2 3 4 5 6

this means there is a [tex]\frac{4}{6}[/tex] chance we will roll at least 3

Next we will find which months of the year are applicable

January February March April May June July August September October November December

This means there is a [tex]\frac{5}{6}[/tex] chance we will pick a month that does not begin with the letter M.

Now we can multiply these chances together to see what the total probability is.

[tex]\frac{4}{6} * \frac{5}{6} = \frac{20}{36} \rightarrow \boxed{\frac{5}{9}}[/tex]

That is the answer

- Kan Academy Advance

Answer:

x=60

Step-by-step explanation:

First get x all alone on 1 side of the equation. Add 14.5 to both sides of the equation to cancel out the negative. You will then be left with

x/5= 12

Multiply both sides of the equation by 5 to cancel out the division and you'll get x=60

Answer:

15

Step-by-step explanation:

To find the answer, plug the values of each variable into the equation and simplify. It may be easiest to plug one variable in at a time, simplify, then plug the next variable in. Remember, if the equation is asking you to subtract a negative number, the negatives cancel and you want to add the numbers.

b = 2          c = -4

3b - c + 5                                      <----- Original expression

3(2) - c + 5                                    <----- Plug 2 in for "b"

6 - c + 5                                        <----- Multiply 3 and 2

11 - c                                              <----- Add 6 and 5

11 - (-4)                                           <----- Plug -4 in for "c"

15                                                  <----- Add 11 and 4

[tex] \sqrt{29 \: - \: 12 \sqrt{5} } [/tex]

[tex] \sqrt{(3 \: - \: 2 \sqrt{5}) ^{2} } [/tex]

[tex] \boxed{ \bold{2 \sqrt{5} \: - \: 3}}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \sqrt{29-12\sqrt{5}} \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf =\sqrt{20-12\sqrt{5}+9} \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf =\sqrt{4\cdot \:5-12\sqrt{5}+9} \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf =\sqrt{\left(\sqrt{4}\right)^2\left(\sqrt{5}\right)^2-12\sqrt{5}+\left(\sqrt{9}\right)^2} \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \sqrt{4}=2 \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \sqrt{9}=3 \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf 2\cdot2\cdot3\sqrt{5}=12\sqrt{5} \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf =\sqrt{2^2\left(\sqrt{5}\right)^2-2\cdot \:2\cdot \:3\sqrt{5}+3^2} \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf Apply\:the\:formula\:from\:binomial\:to\:square:(a-b)^2=a^2-2ab+b^2 \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf 2^{2}(\sqrt{5})^{2}-2\cdot2\cdot3\sqrt{5}+3^{2}=(2\sqrt{5}-3)^{2} \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf =\sqrt{\left(2\sqrt{5}-3\right)^2} \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf Apply \ the \ laws \ of \ exponents:\sqrt[n]{a^{2} }=a \end{gathered}$}[/tex]

[tex]\sqrt{(2\sqrt{5}-3)^{2} } =2\sqrt{5 }-3.[/tex]

[tex]\red{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \red{=2\sqrt{5}-3 } \end{gathered}$}}} \ \ \red{\Rightarrow} \ \ \bf{\red{Answer}}[/tex]

↓

[tex]\red{\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\red{MyHeritage}} \end{gathered}$}}}}[/tex]