What mass of Ca(OH), is present in a sample if it is titrated to its equivalence point with 44.02 mL of 0.0885 M HNO3? The balanced chemical equation is as follows:

2HNO3+Ca(OH)2 ➠Ca(NO3)2+2H20​

The five systems that helps us grow from a child to adult are excretory, integumentary, digestive, respiratory and cardiovascular system.

The body systems are the combination two or more systems located in the body that helps in the maintenance of hemostasis of the body.

Examples of body systems include the following:

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A buffer solution with a pH of 4.23 is prepared with the same volumes of 0.90 M HC₂H₂O₂ and O 1.2x10-9 M NaC₂H₂O₂ is 0.37.

A buffer answer is an aqueous answer along with an aggregate of a weak acid and its conjugate base, or vice versa. Its pH adjustments little or no when a small amount of sturdy acid or base is introduced to it.

Buffer solution is a water solvent based totally answer which includes a combination containing a vulnerable acid and the conjugate base of the vulnerable acid, or a vulnerable base and the conjugate acid of the vulnerable base. They withstand a trade-in pH upon dilution or upon the addition of small amounts of acid/alkali to them.

Buffer solutions resist an exchange in pH whilst small amounts of a robust acid or a strong base are added. a solution of acetic acid and sodium acetate CH3COOH + CH3COONa is an example of a buffer that includes a susceptible acid and its salt.

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The theoretical yield of aluminum iodide according to the reaction would be 276.5 grams.

We are looking to get the theoretical yield of aluminum iodide. This can be achieved by first getting the balanced equation of the reaction:

[tex]2Al + 3I_2 --- > 2AlI_3[/tex]

The mole ratio of Al that reacts and the [tex]AlI_3[/tex] that is produced is 1:1.

Recall that: mole = mass/molar mass.

18.3 grams of aluminum completely reacts:

Molar weight of aluminum = 26.98 g/mol

Mole of 18.3 g aluminum = 18.3/26.98

                                         = 0.6782 mole

Since the mole ratio of Al and  [tex]AlI_3[/tex] is 1:1, the equivalent mole of  [tex]AlI_3[/tex] will also be 0.6782 mole.

Recall that: mass = mole x molar mass

Molar mass of [tex]AlI_3[/tex] = 407.695 g/mol

Mass of 0.6782 [tex]AlI_3[/tex] = 0.6782 x 407.695

                                 = 276.5 grams

In other words, the theoretical yield of  [tex]AlI_3[/tex] according to the reaction is 276.5 grams.

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The molal saturation of the moist entering air is 10.96 mol, molal saturation of the exiting air at 21 C is 0.560 mol and 187.2g of water condenses in the cooler.

The Antoine equation can be stated as a class of semi-empirical correlations describing the exact relation between vapor pressure and temperature for pure substances.

it is seen that

humidity = 44%

Ptotal = 1 atm = 760 mm Hg

[tex]P_{H2O}[/tex] = RH/100 X [tex]P^{*} _{H2O}[/tex] = 52/100 X 567.09

= 294.88 mmHg

Molal saturation = [tex]\frac{P_{H2O} }{P_{T} -P_{H2O} }[/tex]

= 294.88/ (760 - 294.88)

= 0.6361

Exit air = 100% (after cooling)

[tex]P_{H2O}[/tex] =  [tex]P^{*} _{H2O}[/tex] at 21°C = 18.65

Hm2 = 18.67/ (760 - 18.65)

= 0.025

Mole of water that enters = mole of total moist - mole of total dry

= 33.39 - 22.43

= 10.96

mole of water exits after cooling

n2 = Hm2 x (mole of dry air)

= 0.025 x 22.43

= 0.560

water condenses = n1 - n2

=10.96 - 0.560

=10.4 mol

=10.4 x 18 g

= 187.2 g

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Answer: a physical change is something we can see, but a chemical change is not always something that we can see.

Explanation:  Physical changes show a change in appearance.

There are chemical changes when two aqueous solutions are added together and the product is still two aqueous solutions, so we would not see any change and no precipitate is formed.  

So a physical change is something we can see, but a chemical change is not always something that we can see.  

The molarity of 245.0 g of H₂SO4 dissolved in 1.00 L of solution is 2.498M. the molarity of 5.00 g of NaOH in 750.0 mL of solution is 0.167M.

A chemical species' concentration in a solution, specifically the amount of a solute per unit volume of solution, is measured by its molar concentration.

The number of moles per liter when denoted by the unit symbol mol/L or mol/dm3 in SI units, is the mostly used unit used for denoting molarity in chemistry. The secret to determining molarity is to keep in mind that it is measured in moles per liter (M).

MV = grams / molar mass

(x)*(1.000 L) = (245.0 g) / (98.0768 g mol¯1)

x = 2.49804235 M

So, calculating it to 4 significant figures, x = 2.498 M

For 2nd question

Applying the same formula, MV = grams / molar mass

(x) (0.7500 L) = 5.00 g / 39.9969 g mol¯1

(x) (0.7500 L) = 0.1250097 mol

x = 0.1666796 M

x = 0.167 M (when calculated to three Significant figures)

For 3rd question,

using variation of the same formula,

0.200 M = x / 0.1000 L

x = 0.0200 mol

For the 4th question,

MV = moles of solute

no of moles x = (0.415 mol L¯1) (0.01600 L)

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Display data associated with the ID such as age and other information.

Glassy unfocused eyes slow speech and movement or difficulty with small motor skills indicate a slow reaction. State ID cards, passports military ID cards, and driver's licenses are acceptable forms of ID in most states. Permanent Resident Cards may be accepted in some areas, but check with your administrator.

When a liquor store has carefully examined the identity of a customer before serving alcoholic beverages and reached a reasonable conclusion. Even if it turns out to be a fake ID and the appearance of the minor suggests the minor may be over the age of 21 or doing things she normally wouldn't. It is legally permissible even if it suggests that it is sexual. This can be a behavioral sign of addiction. Delayed reaction time Your body reacts and acts slower.

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The smooth ER differs from the rough ER in that the smooth ER produces carbohydrates and lipids, whereas the rough ER produces proteins. (Option B)

The manufacture, folding, quality assurance, and shipment of some proteins take place in the rough ER, which is dotted with millions of membrane-bound ribosomes.

The production of steroid hormones, lipid (fat) synthesis, and metabolism are all heavily correlated with SER. It also serves as a detoxifier. The production of proteins is greatly aided by the rough endoplasmic reticulum.

The fundamental distinction between the rough endoplasmic reticulum and the smooth endoplasmic reticulum is that the RER contains ribosomes, which give it its rough appearance and enable protein synthesis.

Ribosomes cover the rough endoplasmic reticulum, which is important in the synthesis and creation of proteins.

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Answer:

There would be 4 atoms in a tetrahedral molecule.

Explanation:

Answer: 4 atoms

Explanation:

Answer:

The law of Universal Gravitation.

If you dissolved 54 grams of ammonia in 100 grams of water at 400°C then the solution is saturated

A saturated solution is a solution that has dissolved as much solute as it is capable of dissolving and in a saturated solution no more solute can be dissolved at a given temperature and we can make an saturated solution by keep on dissolving solute until no more solute can be dissolved

Here given data is dissolved 54 grams of ammonia in 100 grams of water at 400°C then the ammonia is totally dissolved in this 100 ml water

NH₃ + H₂O → NH₄OH

So, here ammonium hydroxide are formed which is saturated solution and when ammonia is dissolved in water the water molecule donate the proton to the NH₃ molecule and the solubility of ammonia decreases with the increases in of water solvent that's why when we dissolved  54 grams of ammonia in 100 grams of water at 400°C the solution is saturated

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The percentage of methane is 12.9% and percentage of water is 87.09% in methyl hydrate.

It is given that for every methane molecule, 6 moles of water is present. Then the chemical formula of methane hydrate would be CH₄.6H₂O.The molecular mass of CH₄.6H₂O would be,

Molecular mass of CH₄.6H₂O = 12 + 4 + 6(2 +16)

                                                 = 124g/mol

To find the mass percentage of Methane, the following formula is to be used:

Mass percentage of CH₄ = (Mass of methane / Molecular mass of methane hydrate)x100

On substituting the values of mass of CH₄ and mass of CH₄.6H₂O we get,

Mass percentage = (16/124)100

Mass percentage of CH₄ = 12.9%

Therefore the mass percentage of CH₄ in CH₄.6H₂O is 12.9%

Similarly, to find the mass percentage of 6H₂O in methyl hydrate, the following formula is used:

Mass percentage of water = (Mass of 6H₂O/Molecular mass of CH₄.6H₂O)x100

On substituting the values of mass of 6.H₂O and CH₄.6H₂O we get,

Mass percentage of 6H₂O = (108/124)x100

Mass percentage of 6H₂O = 87.09%

Therefore the mass percentage of water in methyl hydrate is 87.09%

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Answer: 1.4 mol A2B is produced.  

Explanation:  2A + B = A2B, so there are 2 moles of A to every one mole of B.  

So if 2.8 mol of A is present 1/2 that amount is made in A2B (and there will be extra B left over because A is the limiting reactant and you can't make more product than the least amount of reactant allows.  

So 1.4 mole of A2B will be produced.  

Correct statement in the process of balance the equation CH₄+O₂ → CO₂+2H₂O then add coefficient 2 to O₂ on the left side of the equation

Balance reaction is the chemical reaction in which number atom is arranged specific manner which reaction is balanced means all elements in the reaction are balanced with specific number

And the given reaction is

CH₄+O₂ → CO₂+2H₂O then,

Place a coefficient of 2 in front of the O₂ we now have 4O atoms on both sides CH₄+2O₂ → CO₂+2H₂O

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Answer:

Explanation:

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When an airplane is in flight, the air pressure at the under drops.

Pressure is defined as the force applied perpendicular to an object's surface per unit area over which that force is dispersed. Gauge pressure is the pressure in relation to the surrounding atmosphere. Pressure is expressed using a variety of units.

As air flows over an airplane wing, the form of the wing creates a low pressure over the wing surface. The low pressure creates lift, which allows the plane to fly.

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a. The mass of MgSO₄ that can be produced in the given reaction is 1.985 grams.

b. The percent yield of MgSO₄ is 10.68%

The complete balanced chemical equation is,

Na₂SO₄(aq)+MgCl₂(aq)⟶MgSO₄(s)+2NaCl(aq)

We know,

Molarity(M) = number of moles(n)/per litres solution.

So,

Number of moles of Na₂SO₄ = Molarity × volume.

Moles of Na₂SO₄ = 0.190×0.0871

Moles of Na₂SO₄ = 0.016549 moles.

Moles of MgCl₂ = 0.311×0.144

Moles of MgCl₂ = 0.044473 moles.

As we can see, moles of Na₂SO₄ are present in less amount,

So Na₂SO₄ will be Limiting reagent and it will control the reaction.

So,

Moles of Na₂SO₄ = Moles of MgSO4

Moles of MgSO₄ = 0.016549 moles.

As we know,

Moles = Mass produced/molar mass

Molar mass of MgSO₄ = 120grams/mole

Putting the values,

0.016549 = mass of Mg produced/120

Mass of MgSO₄ produced = 1.985 grams.

b. Percentage yield formula,

Percentage yield = experimental mass/theoretical mass×100

Theoretical mass = 1.985 grams

Experimental mass = 0.212 grams.

Percentage yield = 0.212/1.985×100

Percentage yield of MgSO₄ = 10.68%

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Answer:

Each 2 ml ampoule contains 4 mmol Mg2+ (equivalent to 1 g magnesium sulfate heptahydrate). Each 10 ml ampoule contains 20 mmol Mg2+ (equivalent to 5 g magnesium sulfate heptahydrate). The concentrations of magnesium ions (Mg2+) in millimoles are given as approximate values.

Energy is added in the conversion of solid to liquids and then the conversion of liquids to gases.

We know that matter occurs in three states; Solid, liquid and gas. Now, we know that solid matter has its particles held together in place such that they do not move about from place to place. The particles of a liquid are not held so closely together hence they do not translate to a large extent. The molecules of a gas are very much free and move about freely from place to place.

Now, we know a solid can be converted to a liquid when it is heated such that the molecules of the solid receive more kinetic energy and move faster and the rigid intermolecular forces that hold them together are broken down thus heat is added.

When we add more heat to the liquid, the intermolecular forces also break down and the we have the gaseous state in which there are no bonds between the molecules.

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Answer:

OsBr2.

Explanation:

Osmium decobromide is the same as osmium bromide. This is the result of the reaction between osmium hydroxide (Os(OH)2) and hydrobromic acid (HBr) to form water and a salt (osmium bromide):

So, osmium bromide has the formula: OsBr2.

The question requires us to calculate the molarity (or molar concentration) of a HNO3 solution, given the volume and concentration of a KOH solution used to neutralize a given volume of the acid.

The following information was provided by the question:

molarity of KOH solution = M(KOH) = 0.01 M = 0.01 mol/L

volume of KOH solution = V(KOH) = 49.90 mL

volume of HNO3 solution = V(HNO3) = 20.00 mL

To answer this question, we need to take a look at the neutralization reaction between HNO3 and KOH:

HNO3 + KOH -> KNO3 + H2O

From the reaction, we have that 1 mol of HNO3 is necessary to neutralize 1 mol of KOH. With this information, we can write that, to achieve complete neutralization:

number of moles of HNO3 = number of moles of KOH

Since the molarity of a solution is given by the following equation:

We can rearrange it to:

And we can also write the equality between the number of moles of HNO3 and KOH as:

And, since the concentration of KOH was provided, as well as the volumes of HNO3 and KOH necessary to achieve neutralization, we can apply these values to calculate the molarity of HNO3 using the equation above:

Therefore, the molarity of the nitric acid solution is equal to 0.02495 mol/L.

The volume (in mL) of the 1.6 M NaHCO₃ solution that must be poured on the spill to react completely is 286 mL

We'll begin by writing the balanced equation for the reaction. This is given below:

H₂SO₄ + 2NaHCO₃ —> Na₂SO₄ + 2H₂O + 2CO₂

The volume of NaHCO₃ can be obtained as follow:

MaVa / MbVb = nA / nB

(2.6 × 88) / (1.6 × Vb) = 1  /2

228.8 / (1.6 × Vb) = 1 / 2

Cross multiply

1.6 × Vb = 228.8 × 2

1.6 × Vb = 457.6

Divide both side by 1.6

Vb = 457.6 / 1.6

Vb = 286 mL

Thus, the volume of the NaHCO₃ solution needed is 286 mL

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The volume of HCl is needed to completely neutralize is 81.25 ml.

Formula of neutralization, M₁V₁ = M₂V₂

M₁ = concentration of HCl

V₁ = volume of HCl

M₂ = concentration of NaOH

V₂ = volume of NaOH

Put the value in M₁V₁ = M₂V₂

0.100 × V₁ = 25 × 0.325

V₁ =  25 × 0.325/ 0.100

V₁ = 81.25 ml

Hence, the volume of HCl is 81.25 ml.

In chemistry, neutralization or neutralization is a chemical reaction wherein acid and a base react quantitatively with every other. In a reaction in water, neutralization results in there being no excess of hydrogen or hydroxide ions present inside the answer.

whilst a strong acid reacts with a strong base the ensuing salt is neither acidic nor primary in nature i.e. it's far impartial for instance whilst HCl, a strong acid, reacts with NaOH, a robust base, the resulting salt is sodium chloride and water.

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Acid-base reactions are reversible and which ones are irreversible then the 1st reaction is HA + H₂O ↔ A⁻ + H₃O⁺ is the reversible reaction and in the 2nd reaction MOH → M⁺ + OH⁻ is the reversible reaction and 3rd reaction is HA+H₂O → A⁻ + H₃O⁺ is the irreversible reaction

Acid base reaction is the chemical reaction that occur when acid and base are mixed together called acid base reaction and irreversible reaction means they can occur only in one direction the reactants can change to the products but the products cannot change back to the reactants and reversible reaction means chemical reaction occur in both direction the reactants can change to the products and the products can also change back to the reactants and in that given reactions

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Answer:

See image below

Explanation:

To convert the left structure to the right structure, one pair of electrons on the oxygen is pushed down onto the carbon-oxygen bond (resulting in a double bond). This results in too many electrons on the top carbon. The electrons from the adjacent double bond are subsequently pushed onto the second carbon.

If 22.2 g of iodine reacts with excess hydrogen gas, the amount, in grams, of hydrogen iodide that would be formed is 44.75 grams.

From the balanced equation of the reaction, as shown in the illustration, the mole ratio of the iodine that reacts and the hydrogen iodide that forms is 1:2.

22.2 g of iodine reacted.

Recall that: mole = mass/molar mass

Molar mass of iodine = 126.9 g/mol

Mole of iodine that reacted = 22.2/126.9

                                          = 0.1749 moles

From the mole ratio, the equivalent mole of hydrogen iodide that will be produced is:

           0.1749 x 2 = 0.3499 moles

Recall that: mass = mole x molar mass

Molar mass of hydrogen iodide = 127.9 g/mol

Mass of 0.3499 mole hydrogen iodide = 0.3499 x 127.9

                                                             = 44.75 grams

Thus, the amount of hydrogen iodide that will be produced is 44.75 grams.

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The hill is 1.7 metres high (Approx.)

Knowing that;

Energy potential = 1000 J

Weight = 60 kg

mgh = potential energy

1,000 = [60][9.8][h]

h = 1.7 m

The whole amount of energy will be in the form of potential energy since the ball's kinetic energy will be equal to zero. As a result, when the ball reaches the peak of its climb, its potential energy will be 450 J. As a result, the ball will soar as high as 45.91 metres.

An enormous amount of potential or stored energy exists in a rock that is at rest on a hill. The boulder's potential energy transforms into kinetic energy, the energy of motion, when it falls.

The automobile drives faster as it goes down the hill, which results in an increase in kinetic energy and a decrease in potential energy.

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Explanation:

We are given: volume = 2.55L

At STP: Temperature = 273.15 K

: Pressure = 1 atm

: R = 0.08205 L.atm/mol.K

Using the ideal gas law:

Answer:

n = 0.11 mol