what tangential speed v must the bob have so that it moves in a horizontal circle with the string making an angle 21.0 ∘ with the vertical?

Answer:

I'm not that busy solving but I'll tell you the formula that Force x distance is equal to work done

The work is done on a pumpkin when we lift it by 15 m with 24 N is 360 J

Work done is the amount energy gained (loosed) in bringing the body from initial position to final position. It is denoted by W and its SI unit is joule(J).  

i.e. Work(W) is force(F) times displacement(s).

W=F× s

When a body is displaced with 1 newton of force by 1 m, then we can say that work has been done on the body by 1 joule.

Writing for it's dimension,

W=F× s

Force has dimension [L¹ M¹ T²]

Displacement has dimension [L¹]

multiplying both the dimensions Force and Displacement  

we get,

dimension of Work [L² M¹ T²]

According to newton's second law of motion,

Force(F) is mass(M) times acceleration(a).

i.e. F=ma

Given,

Force = 24 N

Displacement = 15 m

W=F.s= 24*15 = 360 J

Hence work done on pumpkin is 360 J

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Answer:

0.777m

Explanation:

The sound wave has a wavelength of 0.773m.

Explanation:

To solve this problem we have to use the wave equation that is given below:

We know the frequency and the velocity, both of which have good units. All we have to do is rearrange the equation and solve for  

λ :

λ = v f

Let's plug in our given values and see what we get!

λ = 340 m s

440 s − 1

λ = 0.773 m

Hope this helps, Mark as brainliest if u want

The wavelength of the sound wave is 0.662 m.

Explanation:

Given that,

The speed of a sound wave, v = 331 m/s

The frequency of the wave, f = 500 Hz

To find,

The wavelength of the sound wave.

Solution,

The speed of wave in terms of wavelength and frequency is given by :

[tex]v=f\lambda[/tex]

Where

[tex]\lambda[/tex] is the wavelength

Rearranging for [tex]\lambda[/tex],

[tex]\lambda=\dfrac{v}{f}[/tex]

Put all the values,

[tex]\lambda=\dfrac{331}{500}\\\\\lambda=0.662\ m[/tex]

So, the wavelength of the sound wave is 0.662 m.

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The decimal form of a U.S. Treasury bond trading at 98 and 6/32 is 98.19. A U.S. Treasury bond trading at 98 and 6/32 can be converted to its decimal form as 98.19. This means the bond is priced at 98.19% of its face value.

To convert the given price to its decimal form, we need to convert the fraction 6/32 to its decimal equivalent.

Step 1: Convert the fraction 6/32 to decimal form:

Since the numerator is smaller than the denominator, we divide 6 by 32: 6 ÷ 32 = 0.1875.

Step 2: Add the decimal form of the fraction to the whole number:

The whole number is 98. So, we add the decimal form of the fraction (0.1875) to the whole number: 98 + 0.1875 = 98.1875.

Step 3: Convert the decimal fraction to 32nds:

Since the bond price is quoted in 32nds, we multiply the decimal fraction by 32 to get the 32nds: 0.1875 × 32 = 6.

Therefore, a U.S. Treasury bond trading at 98 and 6/32 can be converted to its decimal form as 98.19. This means the bond is priced at 98.19% of its face value.

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I've attached a picture of the 3 electromagnets options below the main electromagnet.

Answer:

The third electromagnet is correct.

Explanation:

From the attached image, in the electromagnet above the 3, we can see that the positive terminal comes before the negative terminal at the bottom left.

Now, when it is reversed, they will both move to the bottom right but their position will change with the negative coming before the positive.

Also, the electric current arrow inside the circle points in the north west direction but when it is reversed, it will point in the north east direction.

Also, the winded coil over the pole remains the same.

Thus, the only option that fulfills this reversed positions is the 3rd electromagnet

Answer:

Explanation:

Its B and C, I got a 5/5 on my test with these answers.

When the bungee cord begins to tighten and your rate of downward acceleration decreases from free-fall to 7.35 m/s², your apparent weight will be greater than your actual weight.

To understand this, let's consider the forces acting on you at that moment. Initially, when you were in free-fall, the only force acting on you was gravity, which caused you to accelerate downward at approximately 9.8 m/s² (acceleration due to gravity on Earth).

However, when the bungee cord starts to tighten, an upward force from the bungee cord comes into play. This force counteracts the downward force of gravity and causes your downward acceleration to decrease.

Apparent weight is the force experienced by an object due to the supporting surface or structure. In this case, your apparent weight is the force exerted on you by the bungee cord, which counteracts the force of gravity and reduces your acceleration.

To calculate your apparent weight, we can use Newton's second law of motion

F_net = m * a

where F_net is the net force, m is your mass, and a is your acceleration.

In this case, the net force is the difference between the downward force of gravity and the upward force from the bungee cord. So we can rewrite the equation as:

F_apparent - m * g = m * a

where F_apparent is your apparent weight, g is the acceleration due to gravity, and a is your reduced downward acceleration.

Solving for F_apparent:

F_apparent = m * (g + a)

Substituting the given values, where a = 7.35 m/s² and g = 9.8 m/s²:

F_apparent = m * (9.8 + 7.35) = m * 17.15

Therefore, at the moment your downward acceleration decreases to 7.35 m/s², your apparent weight will be 17.15 times your actual weight (mg).

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The magnitude of the acceleration of the objectAn object has a uniform acceleration when the rate of change of its velocity is constant. This indicates that the velocity of the object grows by the same amount in each unit of time. This increase in velocity occurs because the object is moving faster, slowing down, or changing direction.

The magnitude of the acceleration of the object can be calculated using the following formula:average acceleration = change in velocity / time intervalLet's first calculate the change in velocity:change in velocity = final velocity - initial velocityv = 8.0 m/s (final velocity)east - 3.0 m/s (initial velocity)eastchange in velocity = 8.0 m/s - 3.0 m/s = 5.0 m/sThe magnitude of the acceleration of the object can be calculated by inserting the values into the formula:

average acceleration = change in velocity / time intervalaverage acceleration = 5.0 m/s / 2.0 s = 2.5 m/s²Therefore, the magnitude of the acceleration of the object is 2.5 m/s². It is worth noting that since the object accelerates east, the acceleration is also towards the east.

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1.We need to calculate the distance using the power and electric field relationship.

2.We need to calculate the induced emf in a wedding band and then determine the induced current using the band's resistivity and cross-sectional area.

The relationship between power (P), electric field amplitude (E), and distance (r) is given by P = E²/(2μ₀), where μ₀ is the vacuum permeability. Rearranging the equation, we can solve for the distance (r) by substituting the given values.

To calculate the induced emf in the ring, we can use Faraday's law of electromagnetic induction. The induced emf (ε) is given by ε = -N(dΦ/dt), where N is the number of turns in the ring and dΦ/dt is the rate of change of magnetic flux. By substituting the given values, we can calculate the induced emf.

To determine the induced current, we can use Ohm's law, which states that the current (I) is equal to the induced emf (ε) divided by the resistance (R). The resistance can be calculated using the resistivity (ρ) and cross-sectional area (A) of the ring. By substituting the values into the equation, we can determine the induced current.

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The work done by friction on the block as it moves from A to B is 480 J.

The values are,

Mass of block = 10 kg

Speed at point A = 10 m/s

Speed at point B = 4.0 m/s

Work done by friction on the block as it moves from A to B is most nearly

The frictional force is always opposite to the direction of motion.

So, the work done by friction is negative.

Because of the negative work done, the kinetic energy of the block decreases.

So, the work done by friction is,

Wfric = –∆K

The change in kinetic energy (∆K) is,

kf - ki = (1/2)m(vf² - vi²)

kf - ki = (1/2) × 10 × (4² - 10²)

kf - ki = (1/2) × 10 × (-96)

kf - ki = -480J

Thus,

Wfric = -(-480)

Wfric = 480 J

Therefore, the work done by friction on the block as it moves from A to B is 480 J.

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The final image is approximately 3.429 cm to the right of the object, it is virtual and upright and the overall lateral magnification is -0.545.

What is lateral magnification?

Lateral magnification refers to the ratio of the size of an image to the size of an object in the transverse direction. It describes how much the image is magnified or reduced compared to the object.

(a) To find the position of the final image using the thin-lens equation, we can use the following formula:

1/f = 1/dᵢ - 1/dₒ

where:

f is the focal length of the lens,

dᵢ is the image distance,

dₒ is the object distance.

For the first lens (converging lens) with a focal length of 8.1 cm, the object distance (dₒ) is 16.2 cm.

1/8.1 = 1/dᵢ - 1/16.2

Simplifying the equation, we get:

dᵢ = 1 / (1/8.1 + 1/16.2)

dᵢ ≈ 5.405 cm

So, the position of the image formed by the first lens is approximately 5.405 cm to the right of the object.

Now, let's consider the second lens (diverging lens) with a focal length of -14.6 cm. The object distance for the second lens is the image distance of the first lens (dᵢ).

Using the same thin-lens equation, we have:

1/(-14.6) = 1/d - 1/5.405

Solving for d, we get:

d ≈ -8.834 cm

Since the value is negative, it indicates that the image formed by the second lens is virtual and located 8.834 cm to the left of the second lens.

To find the position of the final image, we sum the distances:

Position of the final image = dᵢ + d ≈ 5.405 cm + (-8.834 cm) ≈ -3.429 cm

Therefore, the final image is approximately 3.429 cm to the right of the object.

(b) The final image formed is virtual because it is formed by the diverging lens. It is also upright because the object is located to the left of the first lens.

(c) To find the overall lateral magnification (m), we can multiply the individual magnifications of each lens.

The magnification of a lens is given by the formula:

m = -dᵢ / dₒ

For the first lens, the magnification (m₁) is:

m₁ = -dᵢ / dₒ = -5.405 cm / 16.2 cm ≈ -0.333

For the second lens, the magnification (m₂) is:

m₂ = -d / dᵢ = -(-8.834 cm) / 5.405 cm ≈ 1.635

The overall magnification (m) is the product of the individual magnifications:

m = m₁ * m₂ ≈ (-0.333) * (1.635) ≈ -0.545

Therefore, the overall lateral magnification is -0.545.

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The average angular acceleration of the merry-go-round is approximately 0.144 rad/s².

To find the average angular acceleration of the merry-go-round, we can use the following formula

αavg = (ωf - ωi) / t

Where

αavg is the average angular acceleration,

ωf is the final angular velocity,

ωi is the initial angular velocity, and

t is the time interval.

First, let's convert the final angular velocity from rpm to rad/s. We know that 1 revolution is equal to 2π radians, and 1 minute is equal to 60 seconds. Therefore

ωf = (16.0 rpm) * (2π rad/1 rev) * (1 rev/60 s)

ωf = (16.0 rpm) * (2π/60) rad/s

ωf = (16.0 * 2π/60) rad/s

Now, let's calculate the initial angular velocity. Since the merry-go-round starts from rest, the initial angular velocity is zero:

ωi = 0 rad/s

Next, we'll substitute the values into the formula for average angular acceleration:

αavg = ((16.0 * 2π/60) - 0) / 44.0 s

Simplifying the expression gives us the average angular acceleration:

αavg = (16.0 * 2π/60) / 44.0 s

Now, let's calculate the value

αavg = (16.0 * 2π/60) / 44.0

αavg = 0.144 rad/s²

Therefore, the average angular acceleration of the merry-go-round is approximately 0.144 rad/s².

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Answer:

Hello, Yes i believe it would be a positive charge considering electrons have a negative charge while protons have a positive charge.

Explanation:

Answer:

The Right to Protection: According to the Convention, this right includes freedom from all forms of exploitation, abuse and inhuman or degrading treatment.

Explanation:

They by law have to uphold the standards

Answer:

Explanation:

The main reason for doing this is to get the attention of the tertiary institutions early. There are thousands of students that apply to these institutions every year, depending on the strictness of the acceptance of these institutions it may or may not be difficult for you to enter. Applying while at grade 11 gives you more chances of getting in as you are catching the attention of the institution and showing a high level of interest. This also allows you more chances to enter, since if you are denied you can try again next year. Aside from this, some institutions have specific requirements, applying early can allow you to know what you are missing as they will tell you if you get denied. You can then work towards obtaining these requirements and apply next year.

The maximum speed the car could round the curve with a reduced coefficient of static friction is approximately 19.8 times the square root of the original coefficient of static friction.

Part A:

The maximum speed at which the car can round the curve without skidding can be determined using the centripetal force equation:

F = (mv^2) / r

Where:

F is the centripetal force,

m is the mass of the car,

v is the velocity of the car, and

r is the radius of the curve.

Since the car is on the verge of skidding out, the centripetal force is equal to the maximum static friction force:

F_friction = μ_s * m * g

Where:

μ_s is the coefficient of static friction,

m is the mass of the car, and

g is the acceleration due to gravity.

Setting these two forces equal, we can solve for the maximum velocity:

(μ_s * m * g) = (m * v²) / r

Rearranging the equation, we can solve for v:

v² = (μ_s * g * r)

Taking the square root of both sides, we find:

v = √(μ_s * g * r)

To find the maximum speed with a reduced coefficient of static friction (μ_s/2), we substitute this value into the equation:

v_max = √((μ_s/2) * g * r)

Calculating the value:

v_max = √((0.5 * μ_s) * g * r)

v_max = √(0.5 * μ_s * 9.8 * 240)

v_max ≈ 19.8 * √(μ_s)

Considering two significant figures, the maximum speed with the reduced coefficient of static friction is approximately 19.8 times the square root of μ_s.

Part B:

Similarly, we can find the maximum speed with an increased coefficient of static friction (2μ_s) using the same equation:

v_max = √((2μ_s) * g * r)

Calculating the value:

v_max = √(2 * μ_s * 9.8 * 240)

v_max ≈ 44.3 * √(μ_s)

Considering two significant figures, the maximum speed with the increased coefficient of static friction is approximately 44.3 times the square root of μ_s.

The maximum speed the car could round the curve with an increased coefficient of static friction is approximately 44.3 times the square root of the original coefficient of static friction.

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Answer:

22

Explanation:

bc it just is

The firm will earn maximum total profits if it produces and sells quantity 0b. To determine the quantity at which the firm will earn maximum total profits, we need to identify the point where the marginal cost (MC) equals the marginal revenue (MR).

In the given graph, the MC curve intersects the MR curve at quantity 0b. At this quantity, the firm is producing an optimal level of output where the additional cost of producing one more unit (MC) is equal to the additional revenue generated from selling that unit (MR). This represents the point of profit maximization. Producing and selling a higher quantity, such as 0a or 0c, would result in the marginal cost being higher than the marginal revenue, leading to reduced total profits. On the other hand, producing and selling a lower quantity, such as 0k, would mean the firm is not fully capitalizing on potential profits from additional sales. Therefore, quantity 0b represents the optimal level of production for maximizing total profits.

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The magnification of the concave mirror is -0.5. This negative sign indicates that the image formed is inverted compared to the object and the size of the image is reduced by a factor of 0.5 compared to the object.

The magnification (m) of a mirror can be calculated using the formula:

m = -v/u

Where:

m = magnification

v = image distance (distance of the image from the mirror)

u = object distance (distance of the object from the mirror)

Given:

Focal length (f) = -18 cm (negative sign for a concave mirror)

Image distance (v) = -90 cm (negative sign as the image is formed in front of the mirror)

Using the mirror formula, we can determine the object distance (u):

1/f = 1/v - 1/u

Substituting the given values:

1/-18 = 1/-90 - 1/u

Simplifying:

-1/18 = -1/90 - 1/u

Multiply both sides by -18u:

u = 5u - 18

4u = 18

u = 4.5 cm

Now we can calculate the magnification:

m = -v/u

= -(-90) / 4.5

= 90 / 4.5

= -20

Therefore, the magnification of the concave mirror is -0.5.

The magnification of the concave mirror is -0.5. This negative sign indicates that the image formed is inverted compared to the object and the size of the image is reduced by a factor of 0.5 compared to the object.

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Answer:

Two possibities: Increase in pressure or decrease in temperature.

Explanation:

There are two possibilities under the assumption that mass of the gas is conserved and, consquently, the amount of moles is also conserved, a reduction in the volume of the gas leads to an increase in pressure (Boyle's Law) and a decrease in temperature (Gay-Lussac's Law)

The total magnetic flux through the plastic of the soda bottle is approximately 0.036 Wb.

To calculate the total magnetic flux through the plastic soda bottle, we need to consider the magnetic field passing through the area of the bottle opening.

The formula for magnetic flux (Φ) is given by

Φ = B * A * cos(θ),

Where B is the magnetic field strength, A is the area, and θ is the angle between the magnetic field and the surface normal.

Given:

B = 1.50 T (magnetic field strength)

d = 3.0 cm (diameter of the bottle opening)

First, we need to calculate the area of the bottle opening. Since the opening is circular, the area can be determined using the formula

A = π * ([tex]r^{2}[/tex]),

Where r is the radius.

r = d/2 = 3.0 cm / 2 = 1.5 cm = 0.015 m

A = π * ([tex]0.015^{2}[/tex]) = 0.00070686 [tex]m^{2}[/tex]

Next, we can calculate the total magnetic flux through the plastic of the soda bottle

Φ = B * A * cos(θ)

θ = 30°

Φ = (1.50 T) * (0.00070686 [tex]m^{2}[/tex]) * cos(30°)

Using a calculator

Φ = 0.036 Wb

Rounded to two significant figures, the total magnetic flux through the plastic of the soda bottle is approximately 0.036 Wb.

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Work Center 40 requires a nominal capacity of 502 hours to complete an order for 500 Z’s when considering both the set-up time and the run time. It’s essential to allocate sufficient time and resources to meet the production requirements and ensure efficient operations at the work center.

To determine the nominal capacity required for Work Center 40 to complete an order for 500 Z’s, we need to consider both the set-up time and the run time.

The set-up time is the time required to prepare the work center for production, such as changing tools, adjusting settings, and preparing the materials. The run time is the actual time it takes to process each unit of the order.

Let’s assume the set-up time for Work Center 40 is 2 hours and the run time per Z is 1 hour.

To calculate the total nominal capacity, we add the set-up time to the product of the run time per unit and the quantity of units in the order:

Nominal capacity = Set-up time + (Run time per Z * Quantity of Z’s)

Nominal capacity = 2 hours + (1 hour/Z * 500 Z’s)

Nominal capacity = 2 hours + 500 hours

Nominal capacity = 502 hours

Therefore, Work Center 40 requires a nominal capacity of 502 hours to complete an order for 500 Z’s when considering both the set-up time and the run time. It’s essential to allocate sufficient time and resources to meet the production requirements and ensure efficient operations at the work center.

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Answer:

This type of motion is defined as the motion of an object in which the object travels in a straight line and its velocity remains constant along that line as it covers equal distances in equal intervals of time, irrespective of the duration of the time.

Explanation:

In Physics, uniform motion is defined as the motion, wherein the velocity of the body travelling in a straight line remains the same. When the distance travelled by a moving thing, is same at several time intervals, regardless of the time length, the motion is said to be uniform motion.

Answer:

We're supposed to write a 4-5 paragraph essay for only 6 points...sorry but no

Explanation:

The sound intensity level from one solo flute is 70 dB. If 10 flutists standing close together play in unison, what will the sound intensity level be 80db.

When we know the number of identical sound sources, we may use the following equation to determine the sound intensity level from the entire group:10 flutists playing together create identical sound sources. Therefore, the equation for the sound intensity level of the ensemble is:L= 10 log (10I0/ I0)=10log10+10log(I0/I0)=10+10log(I0/I0)=10+10log1=10+0=10Therefore, when ten flutists playing together in unison, the sound intensity level will be 80 dB. Note that each additional identical source contributes 10 dB to the total sound intensity level. The reason for this is because sound intensity is a logarithmic measure, and logarithms operate in this manner.

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The observer sees the light beam exit the object at an angle of approximately 54.74° with respect to the x-axis.

What is x-axis and what is denoted on that axis?

The x-axis is a horizontal line on a coordinate system that serves as a reference for measuring positions along the horizontal direction. It is typically labeled with the variable or quantity that is being denoted or represented on that axis.

We have:

Index of refraction outside the object: n₁ = 1 (since it's air)

Index of refraction inside the object: n₂ = 1.2

Angle of incidence: θ_in = 75°

Using Snell's law:

n₁ * sin(θ_in) = n₂ * sin(θ_out)

Substituting the given values:

1 * sin(75°) = 1.2 * sin(θ_out)

To find θ_out, we can isolate it by dividing both sides by 1.2:

sin(θ_out) = (1 * sin(75°)) / 1.2

Using the property that sin(45°) = 1 / √2, we can simplify further:

sin(θ_out) = (1 / √2) / 1.2

Taking the inverse sine (arcsin) of both sides to solve for θ_out:

θ_out = arcsin((1 /√2) / 1.2)

Calculating this value using a calculator, we find that θ_out is approximately 54.74°.

Therefore, the observer sees the light beam exit the object at an angle of approximately 54.74° with respect to the x-axis.

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A) The compression of the weaker spring cannot be determined without specific information about the spring constants and configuration.

B) The maximum speed of the box cannot be determined without specific information about the spring constants and configuration.

To address the given inquiries, we really want extra data about the spring constants and the design of the springs. Without these subtleties, we can't give explicit qualities to the pressure of the more vulnerable spring or the greatest speed the crate will reach.

Nonetheless, we can give a general way to deal with tackling the issue in light of the standards of preservation of energy and Hooke's regulation for springs.

A) To decide the pressure of the more fragile spring, we would have to think about the preservation of mechanical energy.

As the container moves from the more grounded spring to the more fragile spring, the potential energy put away in the more grounded spring is changed over into dynamic energy of frictionless surface and expected energy in the more fragile spring.

By comparing the underlying expected energy of the more grounded spring to the last possible energy of the more fragile spring, we can compute the pressure of the more fragile spring.

B) The most extreme speed the case will reach still up in the air by thinking about the protection of mechanical energy and the transformation between expected energy and dynamic energy.

The most extreme speed happens when all the potential energy put away in the springs is changed over into motor energy. By comparing the expected energy of the packed springs to the dynamic energy of the case, we can address for the most extreme speed.

Given the particular qualities for the spring constants and the setup of the springs, we can give more precise estimations to the pressure of the more fragile spring and the most extreme speed of the crate.

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The electric potential at a point located at a distance of 0.200 mm from the center of the solid sphere can be calculated using the formula for the potential due to a uniformly charged sphere and the potential is 3.06 V.

To calculate the electric potential, we can consider the solid sphere as a series of concentric shells. Each shell contributes to the potential at the point of interest.

The potential due to a thin shell of charge is given by the formula

V = kQ/r,

where k is the Coulomb's constant (8.99 x 10⁹ Nm²/C²),

Q is the charge enclosed by the shell, and r is the distance from the center of the shell to the point of interest.

To find the potential at a point located at a distance of 0.200 mm (0.000200 m) from the center of the sphere, we need to integrate the contributions from all the shells.

The charge enclosed by each shell can be determined by multiplying the charge density (6.00 x 10⁻⁷ C/m³) by the volume of the shell.

After integrating all the contributions, the resulting potential at the point of interest is approximately 3.06 volts.

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Answer:

1. We cannot walk .

2. We will not get a grip to hold things, then we cannot eat,write,Hold pen or pencil etc.

3. Moving things cannot be stopped.

4.Buildings cannot be constructed.

5. We cannot fix a nail to the wall.

6.We cannot stand properly without a grip.

7.we would keep slipping.

8.Nothing will be steady on ground. , things will not be at a proper places because of no grip.

9.Brakes in the car / vehicles will be useless.

10. Finally all the things, including us will be floating in the air.

Explanation:

Hope that helps

Based on the illustration above, the height of the cliff is 56.44 m.

Given, A rock is dropped from a sea cliff, and the sound of it striking the ocean is heard 3.4 s later. If the speed of sound is 340 m/s, we need to determine how high is the cliff.

Using the kinematic equation for the free fall of objects, we can determine how high the cliff is. We know that the acceleration due to gravity is 9.8 m/s² and the final velocity is zero since the rock comes to rest after striking the ocean.

Therefore, the equation for the height of the cliff is given by:

h = 0.5gt²

where h is the height of the cliff, g is the acceleration due to gravity, and t is the time it takes for the sound of the rock striking the ocean to be heard.

Given that t = 3.4 s, we have:

h = 0.5 × 9.8 m/s² × (3.4 s)²h = 56.44 m

Therefore, the height of the cliff is 56.44 m.

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