What type of wave is illustrated below?

Longitudinal

Transverse

Surface wave

Seismic wave

Answer:

bs angle will move in 1.5

The final temperature of the water and steel mixture after the steel is dropped is determined as 7.12 ⁰C.

From the principle of conservation of energy, the energy lost by the steel ball is equal to the energy gained by the water.

P.E(steel) - Thermal(steel) = Thermal(water)

mgh - mcΔθ = mcΔθ

where;

(6.2)(9.8)(21.7) - (6.2)(450)(27.7 - T) = (4.5)(4186)(T - 10.1)

1,318.492 - 77,283 + 2790T = 18,837T - 190,253.7

114,289.192 = 16,047T

T = 7.12 ⁰C

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Answer:

the detection of the equivalence point, the point at which chemically equivalent amounts of the reactants have been mixed.

Answer:

5A

Explanation:

[tex]=> Current (I) = \frac{q}{t} [/tex]

Here q = 20 C and t = 4sec

=> I = 20/4 = 5A

Answer:

1600 joules

Explanation:

Potential Energy = m * g * h

                           = 20 kg  *  10 m/s^2  * 8 m = 1600 J

Answer:

es lo que es

Explanation:

es lo que es es que slep vaka vee

the angle ϕ= will be equal to angle of refraction and it is equal to 49.4°C.

When a light is going from medium 1 to medium 2. The refractive index is defined as a ratio of velocity of light in medium 1 to velocity of light in medium 2. Refractive index is the factor which deals with the amount of bending of light. More refractive index means more it will bend in the medium 2. When it is 1 we can say that light has not been bent.

By Snell's law, Refractive index is given by,

sin (i) ÷ sin (r) = μ₂÷μ₁

where i is the the angle of incidence

r is the angle of refraction

μ₂ & μ₁ are refractive index of medium 2 and 1 resp.

Hence it is due to Refractive index.

In this problem the light is going from prism to air, the refractive index of air is 1. From figure it is clear that the angle of incidence is 30°C.

From snell's law,

sin (30) ÷ sin (r) = μ₂÷1.52

0.5 ÷ sin (r) = 1÷1.52

0.5×1.52 = 1×sin (r)

0.76 = sin (r)

The angle of refraction r = sin⁻¹(0.76) =49.4°C

Hence angle ∅ = 49.4°C.

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Taking into account the definition of calorimetry, sensible heat and latent heat, the amount of heat required is 463.28 kJ.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

In firts place, the melting point of water (temperature at which it changes state from solid to liquid) is 0°C.

So, first of all you must increase the temperature from -25 ° C (in solid state) to 0 ° C, in order to supply heat without changing state (sensible heat).

The amount of heat a body receives or transmits is determined by:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Replacing:

Q1= 2050 [tex]\frac{J}{kgC}[/tex]  × 0.845 kg× 25 °C

Solving:

Q1= 43,306.25 = 43.3 kJ

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

In this case, you know:

Replacing:

Q2= 0.845 kg× 334[tex]\frac{kJ}{kg}[/tex]

Solving:

Q2= 282.23  KJ

Similar to sensible heat previously calculated, you know:

Replacing:

Q3= 4180 [tex]\frac{J}{kgC}[/tex] × 0.845 kg× 39 °C

Solving:

Q3= 137,751.9 J= 137.75 kJ

The total heat required is calculated as:  

Total heat required= 43.3 kJ + 282.23 kJ + 137.75 kJ

Total heat required= 463.28 kJ

In summary, the amount of heat required is 463.28 kJ.

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The amount of energy required if the final temperature of the system is to reach 39 °C is 463288.15 J

Q = MCΔT

Q₁ = 0.845 × 2050 × 25

Q₁ = 43306.25 J

Q = mL

Q₂ = 0.845 × 334000

Q₂ = 282230 J

Q = MCΔT

Q₃ = 0.845 × 4180 × 39

Q₃ = 137751.9 J

Qₜ = Q₁ + Q₂ + Q₃

Qₜ = 43306.25 + 282230 + 137751.9

Qₜ = 463288.15 J

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Answer:

4 mph

Explanation:

velocity =   miles divided by time =  miles/time

             =   1 mile / .25 hr   = 4 mph

Answer:

4060 km

Explanation:

580 km/hr   *  7 hr   = 4060 km

rate * time = distance

Answer:

10 amps   10 ohms      ( 100 v)

Explanation:

Voltage = current * ohm

  the smallest of those listed is    10 amps   10 ohms

Answer:

Assume a node at the left end and the right end

N-A-N-A-N-A-N-A-N-A-N    shows nodes and anti-nodes

10 quarter wavelengths are shown  (or 2.5 wavelengths)

30 / 2.5 = 12 cm wavelength      since there is 1/4 wavelength between node and anti-node

Nodes and anti-nodes are displayed in N-A-N-A-N-A-N-A-N.

The difference between the node and the anti-node exists 12 cm wavelength.

Standing waves are created when two identical waves move in opposition to one another along a line. Despite being composed of two waves that are moving in opposition to one another, standing waves do not travel through space or along a string.

A wave that is stationary is one that is not moving, is at a standstill, or is in a relaxed position. A standing wave is created whenever two waves with nearly identical frequencies, wavelengths, and amplitudes that are traveling in opposite directions collide.

A waveform signal that is carried in space or down a wire has a wavelength, This is the distance between two identical locations (contiguous crests) in the following cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm).

The distance over which a periodic wave's shape repeats is known as the wavelength in physics.

Assume that there exists a node at both the left and right ends.

Nodes and anti-nodes are displayed in N-A-N-A-N-A-N-A-N.

it displays 10 quarter wavelengths.

Since there exists a 1/4 wavelength difference between the node and the anti-node, 30 / 2.5 = 12 cm wavelength.

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Answer:

Seventy-five percent of Earth's volcanoes—more than 450 volcanoes—are located along the Ring of Fire. Ninety percent of Earth's earthquakes occur along its path, including the planet's most violent and dramatic seismic events.

please mark brainliest :)

Answer: B. On the right side

Explanation: Metals are located on the left of the periodic table, and nonmetals are located on the upper right.

When you receive prescriptions that contain some abbreviations, you have to translate it into plain language that the patient can understand.

A pharmacy technician is a skilled personnel who assists a pharmacist in a health facility. The pharmacy technician usually writes out prescriptions for patients.

When you receive prescriptions that contain some abbreviations, you have to translate it into plain language that the patient can understand. If you are not clear about the abbreviation you can ask the pharmacist for help or the doctor.

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Answer:

B. Increasing the temperature increases the reaction rate.

Explanation:

This is as with a higher temperature the particles have more kinetic energy, this is the consequece of the increase in reaction rate as the frequency of particles colliding is increased.

Answer: B

Explanation:

Answer:

D

Explanation:

it is because when the thermal energy increases the particles move faster and the temperature increases.

Answer:

which picture please,I don't get you

Answer:

Here is the answer

Here is the answerExplanation:

Here is the answerExplanation:Bay of Pigs Invasion is the answer

Answer:

What is Bohr’s Model of an Atom?

The Bohr model of the atom was proposed by Neil Bohr in 1915. It came into existence with the modification of Rutherford’s model of an atom. Rutherford’s model introduced the nuclear model of an atom, in which he explained that a nucleus (positively charged) is surrounded by negatively charged electrons.

The approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is 5. 35N

The universal law of gravitation states that the particle of matter in the universe attracts another particle with a force directly proportional to the  product of their masses and inversely proportional to the square of the distance between them.

It is written thus;

F = G MIM2÷ r∧2

Where

F = Gravitational force

G = Gravitational constant

M1 and M2 are the masses of the object

r = radius

Formula:

F = G MIM2 ÷ r∧2

Given M1 = 150kg, M2 = 5.97 x 1024 kg, r = 7.5 x 106 m, G =  6.67 x 10-11 N-m²/kg²

For the first orbit, substitute the values

F = 6.67 x 10∧-11 × 150 ×  5.97 x 10∧24 ÷ (7.5 x 10∧6)²

F = 5.95 × 10∧16 ÷ 56.25 × 10∧12 =  105.77 N

For the second orbit of radius 7.7 x 106 m

F =  6.67 x 10∧-11 × 150 ×  5.97 x 10∧24 ÷ (7.7 x 10∧6)²

F = 5.95 × 10∧16 ÷ 59.25 × 10∧12 = 100. 42 N

The approximate change = 105. 77 - 100.42 = 5. 35N

Hence, the approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is 5. 35N

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With the use of formula, The plane should rotate at the speed of 3 m/s

When a body is moving rotationally at a point, the motion is said to be a circular motion. There are two types of motion in a circle

Given that a 3 kg toy plane is attached to a 1.8 m string that it can be whirled around in a horizontal circle above the users head rotates.

The given parameters are:

mass m = 3 kg

Length L = 1.8 m = radius

Force F = 10 N

Velocity V = ?

If one’s exerts a force of 10 N on the string, The speed the plane should have can be calculated by using the below formula

F = M[tex]V^{2}[/tex] / r

Substitute all the parameters into the formula

10 = 3 x [tex]V^{2}[/tex]  / 1.8

Cross multiply

18 = 3[tex]V^{2}[/tex]

[tex]V^{2}[/tex] = 18/3

[tex]V^{2}[/tex] = 9

V = [tex]\sqrt{9}[/tex]

V = 3 m/s

Therefore, The plane should rotate at the speed of 3 m/s

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A 95 kg fullback was running downfield at 8 m/s. A defensive player (110 kg) was running upfield at 6 m/s straight at the fullback. The momentum of each player before they impacted Fullback 760 kgm/s, Defender: 660 kgm/s.

In classical mechanics, the integral of a force, F, over the time period over which it acts, t, is referred to as the "impulse." Impulse is a vector quantity because force is one as well. When an item receives an impulse, it experiences an equivalent vector change in its linear momentum and also in the direction that results.

momentum = mass *velocity

momentum = 95*8 = 760 kg-m/sec Fullback

momentum = 110*6 = 660 kg-m/sec Defender

A 95 kg fullback was running downfield at 8 m/s. A defensive player (110 kg) was running upfield at 6 m/s straight at the fullback. The momentum of each player before they impacted Fullback 760 kgm/s, Defender: 660 kgm/s.

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Answer:

M g - T =  M a     acceleration of hanging block   (M = 2)

2 g - T = 2 a        where M = 2

T = 2 g - 2 a

T = 8 * a + 12 N       acceleration of blocks on table

2 g - 2 a = 8 a + 12

10 a = 2 g - 12  

a = .8 m/s^2   (assuming g = 10 m/s^2)

T = 2 g - 2 a = 2 * 10 - 2 * .8 = 20 - 1.6 = 18.4 N

Check: For blocks on table

a = (18.4 - 12) / 8 = 6.4 / 8 = .8 m/s^2

Explanation:

The unit of energy is a derived unit because it is expressed with the help of fundamental units (kg) unit of mass and four basic units meter (m), meter (m) unit of length second (s), second (s) unit of time.

Answer:

The answer is Less.

Explanation:

The further you are away from a light source, the less intense the light appears.

Answer:

The answer is O prepared with a résumé and cover letter

Explanation:

That will get you very far if you are prepared with a résumé and cover letter