Answer:
See below
Explanation:
Is that 600 WATT lamp ? If so:
power = I V
600 w = 2 A * v
v = 300 v
The rate at which goods and services can be produced is called
a)capital investment.
b)productivity.
c)producer price output.
d)human capital.
Answer:
productivity
Explanation:
it's the efficiency of production of goods or services
Answer:
Explanation:
The rate at which goods and services can be produced is called
b) productivity.
I need help with question 5
uestion 5.
iven:
Mass, m = 25 kg
Tension = 47 N
Let's find the maximum acceleration the truck can have before the crate breaks.
Let the magnitude of the force be expressed as:
= m x a
efore the cord breaks , the maximum tension, T, in the string is:
= ma
Where:
T is the maximum tension
m is the mass
a is the maximum acceleration
ence, to findt he maximmum acceleration, rewrite the equation for a.
We have:
[tex]a=\frac{T}{m}[/tex]Now, input 47N for T and 25 kg for m to solve for a:
[tex]\begin{gathered} a=\frac{47\text{ N}}{25\operatorname{kg}} \\ \\ a=1.88m/s^2 \end{gathered}[/tex]herrefore, the maximum acceleration of the truck before the cord breakes is 1.88 m/s²
Find the velocity of a 1000kg car with 50,000J of KE.
Answer:
10 m/2²
Explanation:
v=t/d
blah blah blah
Answer:
10 m/s
Explanation:
Kinetic Energy = 1/2 m v^2
KE / ( 1/2 m) = v^2
then v = sqrt ( KE / (1/2 m ) = 10 m/s
We will be changing one variable at a time to see how it affects the value of the forces. Set the variables listed in the table and document the force and determine if the charges are attracted to each other or repelled.
Answer:
Explanation:
The coulombs law is expressed as
F = kq1q2/r^2
where
F is the force
k is the coulomb constant and its value is 9 x 10^9 N/m^2C^2
q1 and q2 are the magnitude of the charges
r is the distance between them
From the information given,
r = 4 cm = 4/100 = 0.04m
For trial 1,
q1 = - 2μC
q2 = 8μC
Recall,
1 μC = 1 x 10^- 9 C
q1 = - 2 x 1 x 10^- 9 C
q2 = 8 x 1 x 10^- 9 C
F = (9 x 10^9 x 2 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2
F = 9 x 10^-5 N
There is an attraction
For trial 2,
q1 = - 4μC
q2 = 8μC
q1 = - 4 x 1 x 10^- 9 C
q2 = 8 x 1 x 10^- 9 C
F = (9 x 10^9 x 4 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2
F = 1.8 x 10^-4N
There is an attraction
For trial 3,
q1 = - 6μC
q2 = 8μC
q1 = - 6 x 1 x 10^- 9 C
q2 = 8 x 1 x 10^- 9 C
F = (9 x 10^9 x 6 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2
F = 2.7 x 10^-4N
There is an attraction
For trial 4,
q1 = - 8μC
q2 = 8μC
q1 = - 8 x 1 x 10^- 9 C
q2 = 8 x 1 x 10^- 9 C
F = (9 x 10^9 x 6 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2
F = 3.6 x 10^-4N
There is an attraction
The change in the value of the charge is proportional to the force
What does the amount of refraction of a wave depend on?
A. change in wave speed
B. Location of normal line
C. Size of the object
D. Size of the opening between objects
plsss 15 pointsss!
A) change in wave speed
Option A is correct
Philippe, Maurice’s draft horse, is pulling his 6000N cart using a 745N force on a bridle that is at a 15o angle. If the friction force on the cart is 100N, how long will it take Philippe to go 1000m?
The time taken for Philippe to go 1000 m is 44.5 s.
What is the net force on cart?The net force on the cart is calculated as follows;
F(net) = F - Ff
where;
F is the applied forceFf is the frictional forceF(net) = 745 cos(15) - 100
F(net) = 619.6 N
The mass of the cart is calculated as follows;
W = mg
m = W/g
m = (6000) / (9.8)
m = 612.24 kg
The acceleration of the cart is calculated as follows;
a = F(net) / m
a = (619.6) / (612.24)
a = 1.01 m/s²
The time taken for Philippe to go 1000 m is calculated as follows;
s = vt + ¹/₂at²
s = 0 + ¹/₂at²
2s = at²
t² = 2s/a
t = √(2s/a)
t = √(2 x 1000 / 1.01)
t = 44.5 seconds
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. What is the resulting acceleration when an unbalanced force of 100. N is applied to a 500 g object?
Answer:
F=ma
100=0,5a
a=200m.s^2
What is the mass of an airplane accelerating at 35 m/s2 if 27,000N of force is being applied?
ill give brainleist
Answer:
771 .4 kg
Explanation:
Remember F = ma so F/a = m
m = 27000 N / 35 m/s^2 = 771 .4 kg
module 2 question 17
Figure 4.25
(a) What is the mass of the child and basket if a scale reading of 100 N is observed?
kg
(b) What is the tension T in the cord attaching the child to the scale?
N
(c) What is the tension T' in the cord attaching the scale to the ceiling, if the scale has a mass of 0.300 kg?
N
(d) Draw a sketch of the situation indicating the system of interest used to solve each part. The masses of the cords are negligible. (Do this on paper. Your instructor may ask you to turn in this work.)
a ) The mass of the child and basket = 5.61 kg
b ) The tension T in the cord attaching the child to the scale = 55 N
c ) The tension T' in the cord attaching the scale to the ceiling = 57.94 N
a ) The mass of the child and basket,
[tex]W_{b}[/tex] = 55 N
g = 9.8 m / s²
W = m g
[tex]m_{b}[/tex] = [tex]W_{b}[/tex] / g
[tex]m_{b}[/tex] = 55 / 9.8
[tex]m_{b}[/tex] = 5.61 kg
b ) In the cord attaching the child to the scale,
∑ [tex]F_{y}[/tex] = 0
T - W = 0
T = W
T = 55 N
c ) In the cord attaching the scale to the ceiling,
[tex]m_{s}[/tex] = 0.3 kg
[tex]W_{s}[/tex] = [tex]m_{s}[/tex] * g
[tex]W_{s}[/tex] = 0.3 * 9.8
[tex]W_{s}[/tex] = 2.94 kg
∑ [tex]F_{y}[/tex] = 0
T - [tex]W_{s}[/tex] - [tex]W_{b}[/tex] = 0
T = 2.94 + 55
T = 57.94 N
Therefore,
a ) The mass of the child and basket = 5.61 kg
b ) The tension T in the cord attaching the child to the scale = 55 N
c ) The tension T' in the cord attaching the scale to the ceiling = 57.94 N
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Evan performed an experiment testing how different wind speeds affect how fast a small cart will roll down a ramp. His data from the experiment is shown in the graph below.
-0.25x + 9
By looking at the graph, we can see that the y-intercept is between 8 and 10.
Slope intercept equation:
y=mx+b
Where;
b= y-intercept ( where the line crosses the y axis )
m= slope ( rise / run)
The diagram above shows the angle of an sentence from a light source what will be the angle of reflection?
A 1
B 2
C 3
D 4
Answer:
B 2
Explanation:
Angle of reflection is the measure of the angle taken from the normal.
A microwave antenna with a mass of 78 kg sits atop a tower that is 45 m tall. What is the antenna's potential energy?
PLEASE HELP!!!
The potential energy of the microwave antenna with a mass of 78 kg sitting atop a tower that is 45 m tall is 36.69 KJ
U = m g h
U = Potential energy
m = Mass
g = Acceleration due to gravity
h = Height
m = 78 kg
h = 48 m
g = 9.8 m / s²
U = 78 * 9.8 * 48
U = 36691.2 J
U = 36.69 KJ
Potential energy is also called a stored energy. Because an object at rest have high potential energy. Also the higher above the ground the object is placed, higher will be its potential energy.
Therefore, the potential energy of the microwave antenna is 36.69 KJ
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Erica throws a tennis ball against a wall, and it bounces back. Which force is responsible for sending the ball back to Erica.
Answer:
The frictional force between the wall and the ball
When solving projectile motion problems where the projectile is launched at an angle, the first step is to find the x- and y-component of the initial velocity. Why is this helpful in solving these types of problems?
The projectile motion is a 2-D motion. Therefore, if we make the component of the given velocity into x- and y-component, we can solve each component by using all 1-D motion equations. Now it will become very easy to solve projectile motion problems.
Projectile movement is a shape of movement experienced by an object or particle this is projected close to Earth's surface and moves along a curved path under the movement of gravity handiest.
Projectile movement is the movement of an item thrown (projected) into the air. After the preliminary pressure that launches the item, it best reviews the force of gravity. The object is called a projectile, and its direction is known as its trajectory.
A projectile is any object that is cast, fired, flung, heaved, hurled, pitched, tossed, or thrown. you throw the ball directly upward, or you kick a ball and provide it a pace at an attitude to the horizontal otherwise you just drop matters and lead them to lose fall; most of these are examples of projectile movement.
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Can you help me with this question.
Given:
he initial velcicty of the runner is
[tex]v_{ir}=\text{ 0 m/s}[/tex]The final velocity of the runner is
[tex]v_{fr}=\text{ 2.6 m/s}[/tex]The time taken is t = 2.1 s
The initial velocity of the motorcycle is
[tex]v_{im}=\text{ 37 m/s}[/tex]The final velocity of the motorcycle is
[tex]v_{fm}=\text{ 44 m/s}[/tex]Required:
Acceleration of the motorcycle.
The difference in distance between runner and motorcycle.
Explanation:
cceleration of the runner is
[tex]\begin{gathered} a_r=\frac{v_{fr}-v_{ir}}{t} \\ =\frac{2.6-0}{2.1} \\ =1.238\text{ m/s}^2 \end{gathered}[/tex]Acceleration of the motorcycle is
[tex]\begin{gathered} a_m=\frac{v_{fm}-v_{im}}{t} \\ =\frac{44-37}{2.1} \\ =3.33\text{ m/s}^2 \end{gathered}[/tex]The distance travelled by the runner is
[tex]\begin{gathered} S_r=v_{ir}t+\frac{1}{2}a_rt^2 \\ =0\times2.1+\frac{1}{2}\times1.238\times(2.1)^2 \\ =2.73\text{ m} \end{gathered}[/tex]The distance travelled by motorcycle is
[tex]\begin{gathered} S_m=v_{im}t+\frac{1}{2}a_mt^2 \\ =37\times2.1+\frac{1}{2}\times3.33\times(2.1)^2 \\ =77.7+7.34 \\ =85.04\text{ m} \end{gathered}[/tex]Thus, the motorcycle travels more distance than the runner.
The
difference between the distance travelled is
[tex]\begin{gathered} \Delta S=S_m-S_r \\ =85.04-2.73 \\ =82.31\text{ m} \end{gathered}[/tex]Final Answer:
The acceleration of the runner is 1.238 m/s^2
The acceleration of the motorcycle is 3.33 m/s^2
The difference in distance between runner and motorcycle is 82.31 m.
Gravity is a theory because it is
ANSWER:
Gravity is a theory in that it is a comprehensive explanation of a natural phenomenon that has been tested in a variety of ways.
You have three identical, uniform, square pieces of wood, each with
side length L. You stack the three pieces of wood at the edge of
the horizontal top of a table. The first block extends a distance L/4
past the edge of the table. The next block extends a distance L/4
past the edge of the first block, so a distance L/2 past the edge of
the table. The third block extends a distance L/4 past the edge of
the block beneath it, so 3L/4 past the edge of the table. The stack
is unstable if the center of mass of the stack extends beyond the
edge of the table.
Centre of mass of the square piece at the middle of the stack is at x = 0 centre of mass of the bottom most square piece in the stack is at{ (l/4)^2 + (l/4)^2}^1/2 .
What is centre of mass and how it is calculated in the stack?Centre of mass in physics is a phenomenal discovery which states that the overall weight of the body distributed sums up to zero at the point central relative to other points.The point of centre of mass is the point where we may apply force and the linear acceleration will be on action but no angular acceleration would be seen.Here is given three identical square pieces of wood, each with length L . Now we are stacking the block three pieces at the edge of the horizontal.The centre of mass of the bottom most square piece in the stack is at {(l/4)^2 +(l/4)^2}^1/2= L/2(2)^1/2.To know more about centre of mass visit:
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7. Conceptual 03 04 10 pts possible Someone in a car going past you at the speed of 41 m/s drops a small rock from a height of 1.6 m. How far from the point of the drop will the rock hit the ground? The acceleration due to gravity is 9.8 m/s². Answer in units of m.
Answer:
See below
Explanation:
Find out how long the vertical velocity and accel cause the rock to ground out....then multiply this time by the horizontal speed....then use pythag theorem for the TOTAL distance
df = do + vo t + 1/2 a t^2 df = final height = 0 do = original = 1.6 m
v o = original velocity = 0 accel = - 9.81 m/s^2
0 = 1.6 + 0 + 1/2 ( - 9.8)(t^2) shows t = .5714 seconds to hit the ground
horizontal distance = .5711 seconds * 41 m/s = 23.43 m
vertical distance = 1.6 m
TOTAL distance = sqrt (( 23.42)^2 + (1.6)^2 ) = 23.48 m
If questioner wants horizontal disance <=====use first answer
if Q wants TOTAL distance <====== use second answer
A big weight *
Alice has picked up a big weight.
Her friends are talking about the forces that hold it steady.
What forces hold the big weight steady?
A It is not moving, so there are no forces.
OB The only force is gravity, pushing it onto Alice's hand.
C The only force is Alice pushing up, to hold it steady.
D Gravity pushes the weight down and Alice pushes it up.
1 point
Answer:
Gravity pushes the weight down and Alice pushes it up.
Explanation:
In this case, Gravity pushes the weight down and Alice pushes it up. The correct option is D.
Car A runs a red light and crashes into Car B, which is waiting to make a left turn. Car A has a mass of 2,000 kg. Car B has a mass of 1,500 kg. After the impact, the cars stick together and slide away at a speed of 9.1m/s. How fast was Car A going when it hit Car B? Show all of your work. (Law of Conservation of Momentum)
Answer:
The law of conservation of momentum tells us that momentum is conserved, therefore total initial momentum should be equal to total final momentum. In this case, we can expressed this mathematically as:
mA vA + mB vB = m v
where, m is the mass in kg, v is the velocity in m/s
since m is the total mass, m = mA + mB, we can write the equation as:
mA vA + mB vB = (mA + mB) v
furthermore, car B was at a stop signal therefore vB = 0, hence
mA vA + 0 = (mA + mB) v
1800 (vA) = (1800 + 1500) (7.1 m/s)
vA = 13.02 m/s
Explanation:
Using energy considerations, calculate the average force (in N) a 70.0 kg sprinter exerts backward on the track to accelerate from 2.00 to 8.00 m/s in a distance of 25.0 m, if he encounters a headwind that exerts an average force of 30.0 N against him.
The average force a 70.0 kg sprinter exerts backward on the track is 84 N.
What is law of conservation of energy?
The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.
E = Fd
where;
F is the applied forced is the displacement of the objectThe average force exerted by the sprinter is calculated as follows;
F = ma
where;
a is the acceleration of the sprinterm is mass of the sprinterThe acceleration of the sprinter is calculated as follows;
v² = u² + 2as
where;
v is the final velocityu is the initial velocitys is the distance(8)² = (2)² + (2x25)a
64 = 4 + 50a
60 = 50a
a = 60/50
a = 1.2 m/s²
Average force exerted by the sprinter;
F = ma
F = 70 kg x 1.2 m/s²
F = 84 N
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Determine the velocity of car A with respect to car B. Responses
A 20, km/hr
B -20, km/hr
C 80, km/hr
D -80 km/hr
A. The velocity of car A with respect to car B is 20 km/h
What is relative velocity?The velocity of an object A relative to another object B is the velocity that object A would appear to have to an observer moving with B.
The velocity of car A with respect to car B is calculated as follows;
Va/b = Va - Vb
where;
Va/b is the velocity of car A with respect to car BVa is the velocity of car AVb is the velocity of car BSubstitute the given parameters and solve for the the velocity of car A with respect to car B.
Va/b = 50 km/h - 30 km/h
Va/b = 20 km/h
Thus, we can conclude that the velocity of car A with respect to car B will appear to decrease since they are moving in the same direction.
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********
A student investigates whether a spring obeys Hooke's law
She uses the apparatus shown in the photograph
(a) Which additional measuring instrument does the student need for the investigation?
1
(b) Explain how the student can investigate whether the spring obeys Hooke's law.
(1)
(5)
The answers include the following below:
The additional measuring instrument the student needs for the investigation is a ruler or measuring tape.The student can investigate whether the spring obeys Hooke's law by adding masses to a spring and measuring the length of the spring when the weight of the masses is increased.What is Hooke's law?
This law states that the force which is needed to extend a spring is directly proportional to the distance in which the spring is extended from its rest or initial position.
The distance gotten is measured with the use of a ruler or a measuring tape so as to obtain an accurate result during the experimental procedures. Hooke'slaw is performed by adding some masses to a spring and taking note of the effect by measuring the length of the spring when the weight of the masses is increased.
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air around us exerts ____________
Explain why six accumulators each of elctromotive foce two volts connect in series can be used to start the engine of a car where as eight dry cell each of electromotive force 1.5v connected in series cannot be used
Electromotive force is the electrical activity produced by a non-electrical source and is measured in volts.. Electrical transducers, which include batteries and generators, transform other forms of energy into electrical energy to produce an emf.
Due to the high internal resistance of the 8-dry cells compared to the low internal resistance of the accumulators, the current generated by the dry cells is too low compared to the current generated by the accumulators. The accumulators will generate the bigger currents required to start the engine because the dry cells' internal resistance is far higher than that of the accumulators. NB. Generally speaking, accumulators have low internal resistance. mostly because the acid therein is a superb conductor.
The effort done by the battery to transform the chemical energy of the cell into electrical energy is what creates the voltage that the electromotive force (e.m.f.) of a battery correlates to (the current in the circuit).
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Find the resultant of the following vectors:
ASAPPPP
(7) The resultant vector is middle line which is the longest line representing the single effect of the two vectors at both ends.
(8) The resultant vector is any of the lines at the end of the vectors, since any of this line will effectively complete triangle formed by the vectors.
What is resultant vector?A resultant vector is defined as a single vector that produces the same effect as the two or more vectors combined together.
A resultant vector is usually, drawn to join the head of the first vector to the tail of the second in a triangle method of vector addition.
Also, a resultant vector can be determined by applying parallelogram law of vector addition.
Mathematically, a resultant vector can be determined using this formula,
R² = a² + b² - 2ab cosθ
where;
a is the first vectorb is the second vectorθ is the angle between vector a and vector bA resultant vector is always bigger than the two vectors acting together.
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7. The initial temperature of a jar of a juice is 80°C and the mass of the juice is 2kg. Susan adds ice cubes into jar in order to cool down the juice to 20°C. What is the minimum number of ice cubes at 0°C required? (Neglect the heat capacity of the jar and assume there is no heat exchange with the surrounding.) Given: Mass of each ice cube = 0.15Kg Specific heat capacity of juice = 4700 J kg¹ °C¹ Specific heat capacity of water = 4200 J kg-¹ °C-¹ Specific heat capacity of fusion of ice = 3.34 x 105 J kg E A. 9 B. 10 C. 11 D. 12
The minimum number of ice cubes at 0°C required to cool down the juice is 11 ice cubes (Option C)
We'll begin by obtainig the heat released by the juice. This can be obtained by
Initial temperature (T₁) = 80 °CFinal temperature (T₂) = 20 °CMass of juice (M) = 2KgChange in temperature (ΔT) = 20 - 80 = -60 °CSpecific heat capacity of juice (C) = 4700 J/KgºC Heat released (Q) =?Q = MCΔT
Q = 2 × 4700 × -60
Q = -564000 J
Next, we shall determin the mass of the total ice. This can be obtained as follow:
Heat capacity of fusion of ice (ΔHf) = 3.34×10⁵ J/kgHeat released = -564000 JHeat absorbed (Q) = 564000 JTotal mass of ice (M) = ?Q = m × ΔHf
564000 = m × 3.34×10⁵
Divide both sides by 3.34×10⁵
m = 564000 / 3.34×10⁵
m = 1.69 Kg
Finally, we shall determine the number of ice cubes. This can be stained as follow:
Total mass of cube = 1.69 KgMass of one cube = 0.15 KgNumber of ice =?Number of ice = total mass / mass of one cube
Number of ice = 1.69 / 0.15
Number of ice = 11 ice cubes
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4. What is stellar parallax?
Answer:
I don't k own what it is dad fjf f fjff
Answer:
Explanation:
Stellar parallax is the apparent shift of position of any nearby star against the background of distant objects
Gravity causes a ball to fall is an example of which Newton law?
Answer:
Newton's 2nd Law
Explanation:
First law concerns balanced forces, which result in either static equilibrium or dynamic equilibrium, where there is no acceleration. Gravity causes the ball to accelerate so it can't be the first law.
Second Law deals with unbalanced forces (F=ma).
Third law relates to "action-reaction" which is unrelated to the scenario.
if Ms. Avari is carrying a stack of books weighing 12 N up a flight of starts that is 10 meters high. How much work does Ms. Avari need to do to take the stack of books up the stairs? ( W = F x d )
F = force = 12 N
d = distance = 10 m
W= work
Apply:
W = F x d
Replacing:
W= 12 x 10 = 120 J