Which of the following materials used by plants to make food can be found in the air?
A) pollen
B) soil
C) oxygen
D) carbon dioxide
Answer:
number d
Explanation:
because plant need carbondioxide
Water can rise from the roots to the tops of trees due to _____.
A. capillary action
B. solubility
C. surface tension
D. homonuclear bonding
E. All of the above
Water can rise from the roots to the tops of trees due to capillary action. The correct option is A.
What is capillary action?It is the phenomenon by which the liquid rises or falls in a very small diameter tube.
In plants. its roots have very thin diameter tubes which are not visible to the eye. But the water reached to the plants through these tube to every single part of the plant i.e. from root to the fruits.
So, water can rise from the roots to the tops of trees due to capillary action.
Thus, the correct option is A.
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Ph11_UnitPacket2019
Page 30 of 38
3. A ray of light travels from air into a liquid. The ray is incident upon the liquid at an angle of 30.0 degrees
The angle of refraction is 19.9º.
a. What is the index of refraction for the liquid? 1901
1999
thin liquid could be.
Let's see
Use snells law
[tex]\\ \rm\Rrightarrow \dfrac{n_1}{n_2}=\dfrac{sini}{sinr}[/tex]
[tex]\\ \rm\Rrightarrow \mu=\dfrac{sin30}{sin19.9}[/tex]
[tex]\\ \rm\Rrightarrow \mu=0.5/0.34[/tex]
[tex]\\ \rm\Rrightarrow \mu=1.47[/tex]
It may be glass
Which of the following is NOT true in terms of what to consider when judging eye witness accounts?
the type of crime and how the witness saw the incident
interviewing techniques can affect eye witness accounts
open-ended questions do not often get better answers
The statement that is not true about in
terms of what to consider when judging eye witness accounts is the type of crime and how the witness saw the incident.
What is Judgement?Judgement is a decree, or decision or conclusion on a subject matter when there is an offence or someone did wat is wrong . It can be to vindicate and to punish for a crime.
Therefore, The statement that is not true about in terms of what to consider when judging eye witness accounts is the type of crime and how the witness saw the incident
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how is newton’s first law of motion used for a person in a stationary car during a car crash
Answer:
When the car crashes, there is no unbalanced force acting on the person, so they continue forward (Newton's First Law). The person moves against the seat belt, exerting a force on it.
The products of nuclear fission have slightly less mass than the original atom that undergoes fission. During the process, a very large amount of energy is produced. What do you think happens to the "missing" mass in a fission reaction?
Answer:
missing mass has been converted to energy according to Einstein mass energy equation
An object moves 4 meters north, then 3 meters east. What is the displacement of the object?
Answer:
5 meters
Explanation:
4 and 3 are legs of a right triangle with the hypotenuse = displacement
Use Pythagorean theorem
4 ^2 + 3^2 = (displacement)^2
displacement = 5 m
The displacement of the object that moved 4 meters north, then 3 meters east is 5 meters.
What is displacement?
Displacement is change in the position of an object. It can be described as the shortest distance between the initial and final position of an object.
The displacement of the object is calculated as follows;
d² = 4² + 3²
d² = 25
d = 5 m
Thus, the displacement of the object that moved 4 meters north, then 3 meters east is 5 meters.
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an iceberg melting slowly
firing a clay pot in a hot kiln
Both are chemical changes.
Both are caused by cooling.
Both involve chemical bonds breaking.
Both are caused by heating.
Select all that apply.
Submit
PLS ANSWER ASAPPPP will give brainiest or whatever it’s called
Answer:
Both are caused by heating
A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. Find its usual speed.
Answer:
Usual speed: [tex]500\; {\rm km \cdot h^{-1}}[/tex].
Explanation:
Let the usual duration of the trip be [tex]t[/tex] hours ([tex]t > 0[/tex].) The actual duration of this trip would be [tex](t - (1/2))[/tex] hours.
The usual speed would be:
[tex]\begin{aligned}\frac{1500}{t}\end{aligned}[/tex].
The actual speed would be:
[tex]\begin{aligned}\frac{1500}{t - (1/2)}\end{aligned}[/tex].
The actual speed is [tex]100\; {\rm km \cdot h^{-1}}[/tex] greater than the usual speed. In other words:
[tex]\begin{aligned}\frac{1500}{t - (1/2)} - \frac{1500}{t} = 100\end{aligned}[/tex].
Simplify this equation and solve for [tex]t[/tex] ([tex]t > 0[/tex]):
[tex]\begin{aligned}\frac{15}{t - (1/2)} - \frac{15}{t} = 1\end{aligned}[/tex].
[tex]\begin{aligned}15\, t - 15\, \left(t - \frac{1}{2}\right) = t^{2} - \frac{1}{2}\, t\end{aligned}[/tex].
[tex]\begin{aligned}t^{2} - \frac{1}{2}\, t - \frac{15}{2} = 0\end{aligned}[/tex].
[tex]2\, t^{2} - t - 15 = 0[/tex].
[tex](2\, t + 5)\, (t - 3) = 0[/tex].
Since [tex]t > 0[/tex], the only possible value for [tex]t[/tex] would be [tex]t = 3[/tex].
Thus, the usual duration of this trip would be [tex]3\; {\rm h}[/tex]. The usual speed of this trip would be:
[tex]\begin{aligned}v &= \frac{s}{t} = \frac{1500\; {\rm km}}{3\; {\rm h}} = 500\; {\rm km \cdot h^{-1}}\end{aligned}[/tex].
A year is the time it takes a planet to complete one orbit. use your data to estimate the year length for each planet. use time units of earth years or earth months. why does it take the outer planets so long to orbit the sun? try to come up with 2 reasons.
The planets of the solar system has the orbiting time.
Mercury- 88 days, Venus-225 days, Earth- 365 days, Mars-687 days, Jupiter- 12 years, Saturn- 29 years, Uranus- 84 years, Neptune- 165 years, Pluto- 248 years.
What is solar system?Solar system consists of all the planets and the most importantly the center of the solar system is Sun.
Sun is the main focus of the solar system. It emits high temperature light rays on the planets which in turn emit lights and be visible.
Outer planets take longer to orbit the sun because the gravitational pull is weaker as shown in the inverse square law.
The outer planets very far away from the Sun, means that they have more distance to cover in their orbit.
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Unguarded live parts operating at 30,000 volts located above a working space must be elevated at least _____ above the working space.
Unguarded live parts operating at 30,000 volts located above a working space must be elevated at least 9.5' above the working space.
What is voltage?The voltage is the potential difference between the end of the conductor.
The place where electricity supply wires and power stations are present, the lives must protected. They must live far above the working space.
Thus, it must be 9.5' above the working space.
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A hot air balloon pilot is choosing a day and time to launch her new balloon. Table 1 shows the weather forecast for the next three days.
Temperature at 6 a.m. (°C). Temperature at 12 p.m. (°C). Temperature at 6 p.m. (°C)
Monday. 4. 18. 22
Tuesday. 6. 19. 24
Wednesday. 10. 20. 25
If the pilot wants to rise as high as possible while using as little fuel as possible, on which day should she launch her balloon? Explain your answer.
The balloon will rise the most on Wednesday due to high temperature that will increase the thermal energy of the balloon and cause it to rise higher.
Average daily temperatureThe average daily temperature of the different days is calculated as follows;
Monday = (4 + 18 + 22)/3 = 14.67 ⁰C
Tuesday = (6 + 19 + 24)/3 = 16.3 ⁰C
Wednesday = (10 + 20 + 25)/3 = 18.3 ⁰C
The average daily temperature of Wednesday is the greatest.
The balloon will rise the most on Wednesday due to high temperature that will increase the thermal energy of the balloon and cause it to rise higher.
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In classical physics, relative motion is absolute. For example, consider an object moving in a straight line with speed v0 on a platform. If the platform is moving with speed vp in the same direction relative to the ground, the object will be moving with speed v0 + vp relative to the ground. However, it is known that the speed of light is the same for all observers regardless of reference frame, which contradicts the classical model of relative motion. Which of the following statements is a conclusion that could be drawn from this contradiction?А. There are no absoluta celerence frames.B. All physical quantities are the same in al reference frames.C. Light can be described by a wave model and a particle model.D. Observers in different reference frames will measure time and distance differently.
Answer:
d) observers in different reference frames will measure time and distance differently
The shortest distance between the initial position and the final position of moving body is called .............
The Answer Is Displacement
The coefficient of dynamic friction between the grass and a 200 kg football blocking sled is 0.20. If a football player only pushes horizontally against the sled, how large must the horizontal force be to keep the sled moving at constant velocity
The horizontal force be to keep the sled moving at constant velocity is 392 N.
Horizontal force applied to the sled
The horizontal force applied to the sled to prevent it from moving is calculated from Newton's second law of motion.
F - Ff = ma
where;
a is acceleration of the sledat constant velocity, a = 0
F - μmg = m(0)
F - μmg = 0
F = μmg
F = 0.2 x 200 x 9.8
F = 392 N
Thus, the horizontal force be to keep the sled moving at constant velocity is 392 N.
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Clouds are formed when water vapor in the atmosphere becomes a liquid and condenses. Condensation is a result of the difference in which of the following?
A.
air temperature and dew point temperature
B.
air pressure and air temperature
C.
dew point temperature and ocean temperature
D.
air pressure and wind speed
Answer:
B temperature and dew point temperature
What is the de Broglie wavelength of a 2.89 x 10-28 kg particle moving
at 3.00 x 108 m/s? (h = 6.626 x 10-34 J-s)
Explanation:
formula is given by
h/mv
where h is 6.626 × 10 ^-34
and c = 3 × 10^8
m = mass
by plugging in the values in the formula, the de Brogile wavelength is equal to 7.6424 × 10^(-15)
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Active energy is a characteristic of _______ energy.
Answer:
Active energy is a characteristic of Kinetic energy
derive a relation between critical angle and refractive index
Answer:
At the critical angle the angle of refraction (outside the medium) is 90°
Ni sin θ = Na sin 90° = 1 assuming outside medium is air
sin θ = 1 / Ni where Ni is the refractive of the medium involved
Transverse waves travel at in a string that is subjected to a tension of if the string is long, what is its mass?
The mass of the string is 0.515 kg.
Calculations and Parameters:Given that:
Tension= 60.5NLength of string= 15.9mv= 43.2 m/sm=?To solve for the mass of the string,
v=√(T/ρ) ,(v=43.2m/s , T=60.5N , L=15.9m )43.2= √(60.5/ρ)60.5/ρ= 1866.24ρ= 0.032418Therefore, the mass would be[tex]15.9*0.03242= 0.515448= 0.515[kg][/tex]
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Question 1
A bus travels 5 km east. Then it travels 3 km west by the same path and stops.
What is the bus's displacement?
O 10 km
O2 km
O3km
O 8 km
Types of Forces Lab Report
Instructions: In the Types of Forces lab, you will experiment with the contact force friction. Use the following lab report to record your hypothesis, materials, procedures, observations, and conclusion. You will submit your completed report.
Name and Title
Name of Lab:
Student Name:
Instructor:
Date:
Objective
The purpose is to test whether the surface texture of the ground affects the distance an object can roll.
Hypothesis
If an object rolls over _______________ (type of material), then it will _____________ (describe the prediction of distance it will travel).
Materials
For this lab, I used the following items:
Procedure
Short summary of what I did:
I experienced the following errors while doing my experiment:
Test (independent) variable (What was different about my test groups?):
Outcome (dependent) variable (What was I measuring?):
Data
Record the distance traveled for each of the trials for the three floor surfaces in the table below.
Distance Object Traveled
Floor Surface Trial 1 Trial 2 Trial 3
Data Analysis
Calculate the average distance traveled for each floor surface. Use the following guidelines for calculating averages, and show your work.
Floor Covering Calculation of the Average Average Distance Traveled
Example (trial 1 measurement + trial 2 measurement + trial 3 measurement) / 3 (number of trials) Your answer from the calculation, showing the average distance the ball rolled for that floor covering.
Frictional force is reduced in smooth surfaces but is large in rough surfaces.
What is Force?Force is defined as an agent which causes a change in the motion or state of an object.
Forces are of two types:
Contact forces and Non-contact forcesContact forces include frictional force.
Frictional forces refers to the force which acts between two surfaces in contact by opposing the relative motion of one over the other
Frictional force depends on the nature of surfaces in contact where rough surfaces produce greater frictional force than smooth surfaces.
Therefore, frictional force is reduced in smooth surfaces but is large in rough surfaces.
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EDGE— Sometimes doctors have difficulty seeing tumors on images of the brain when they are very small. Which form of nanotechnology is most likely to help improve brain imaging?
Dendrimers are the form of nanotechnology is most likely to help improve brain imaging.
What is nanotechnology?Nanotechnology is the near-atomic manipulation of matter to create new structures, materials, and gadgets.
The technique offers scientific improvement in a variety of fields, including medical, consumer goods, energy, materials, and manufacturing.
Dendrites are a kind of nanoparticle that has been studied extensively for a variety of medicinal applications, including medication administration, imaging, and diagnostics in the brain.
Hence,dendrimers are the form of nanotechnology is most likely to help improve brain imaging.
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Answer:
B. Quantum Dots
Explanation:
Nanotechnology with quantum dots allows for better imaging while examining the body.
how does this experiment help us understand their behavior? stanford prison experiment
This experiment help us understand their behavior as well as how the people will cop up with the rules and regulation the society wants to apply on them
What is Stanford prison experiment ?In a two-week simulation of a prison setting, the Stanford prison experiment was meant to look at the impact of situational factors on participants' responses and behaviors.
Hence, this experiment allows us to better understand their behavior, as well as how individuals will respond to the laws and regulations imposed by society.
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A stone is thrown horizontally at 15 m/s from the top of a cliff. It takes it 2.4 s to hit the ground. How far from the base of the cliff does the stone hit the ground
You want to design a rollercoaster that will be able to go around a loop-the-loop on earth (where the value of g is 10 N/kg). If the mass of the rollercoaster is 6,000 kg and it is going 40 m/s at the bottom of the loop, calculate the maximum height of the top of the loop. Assume there is no energy input (motors, etc) or friction or any other energy waste in this system.
Answer:
[tex]64\; {\rm m}[/tex], assuming that the rollercoaster is not attached to the track.
Explanation:
Let [tex]r[/tex] denote the radius of the loop. The height of the top of the loop would be [tex]2\, r[/tex].
Let [tex]a[/tex] denote the acceleration of the rollercoaster. At any position in the loop, if the speed of the rollercoaster is [tex]v[/tex], the (centripetal) acceleration of the rollercoaster would be:
[tex]\displaystyle a = \frac{v^{2}}{r}[/tex].
Let [tex]m[/tex] denote the mass of the rollercoaster. The net force on the rollercoaster would then be:
[tex]\displaystyle F_\text{net} = m\, a = \frac{m\, v^{2}}{r}[/tex].
The rollercoaster would stay on the track (and goes around the loop without falling off) only if the normal force [tex]F_\text{normal}[/tex] between the track and the rollercoaster is non-negative. In other words: it is necessary that [tex]F_\text{normal} > 0[/tex] for the rollercoaster to stay on the track.
At the top of the loop, [tex]F_\text{normal}[/tex] and the weight of the rollercoaster [tex]m\, g[/tex] are in the same direction as the centripetal acceleration (downwards towards the center of the loop.) Hence:
[tex]F_\text{net} = F_\text{normal} + m\, g[/tex].
Let [tex]v_\text{top}[/tex] denote the speed of the rollercoaster at the top of the loop.
[tex]\begin{aligned} F_\text{normal} &= F_\text{net} - m\, g \\ &= \frac{m\, v_\text{top}^{2}}{r} - m\, g\end{aligned}[/tex].
If [tex]F_\text{normal} > 0[/tex] at the top of the loop, then:
[tex]\displaystyle \frac{m\, v_\text{top}^{2}}{r} - m\, g > 0[/tex].
[tex]\displaystyle v_{\text{top}}^{2} > g\, r[/tex].
At the same time, by the conservation of energy, the sum of the kinetic energy [tex]\text{KE}[/tex] and gravitational potential energy [tex]\text{GPE}[/tex] of the rollercoaster should stay the same during the entire ride. Assuming that [tex]\text{GPE}\![/tex] is [tex]0[/tex] at the bottom of the loop:
[tex]\begin{aligned}& \text{KE at the bottom}\\ &= \text{KE at the top} + \text{GPE at the top}\end{aligned}[/tex].
Let [tex]v_{0}[/tex] denote the speed of the rollercoaster at the bottom of the loop.
[tex]\begin{aligned}\text{KE at the bottom} = \frac{1}{2}\, m\, {v_{0}}^{2}\end{aligned}[/tex].
The speed of the rollercoaster at the top of the loop [tex]v_\text{top}[/tex] is at least [tex](g/r)[/tex]. Therefore:
[tex]\begin{aligned}& \text{KE at the top}= \frac{1}{2}\, m\, {v_{\text{top}}}^{2} > \frac{1}{2} \, m\, g\, r\end{aligned}[/tex].
Since the height of the loop is [tex]2\, r[/tex], the [tex]\text{GPE}[/tex] of the rollercoaster at the top of the loop would be:
[tex]\text{GPE at the top} = m\, g\, h = 2\, m\, g\, r[/tex].
Thus:
[tex]\begin{aligned} \frac{1}{2}\, m\, {v_{0}}^{2} &= \text{KE at the bottom}\\ &= \text{KE at the top} + \text{GPE at the top} \\ & > \frac{1}{2}\, m\, g\, r + \text{GPE at the top}\\ & = \frac{1}{2}\, m\, g\, r+ 2\, m\, g\, r \\ &= \frac{5}{2}\, m\, g\, r\end{aligned}[/tex].
In other words:
[tex]\displaystyle \frac{1}{2}\, m\, {v_{0}}^{2} > \frac{5}{2}\, m\, g\, r[/tex].
Rearrange and simplify to obtain a bound on [tex]r[/tex]:
[tex]\begin{aligned} r < \frac{(1/2)\, m\, {v_{0}}^{2}}{(5/2)\, m\, g}\end{aligned}[/tex].
[tex]\begin{aligned} r < \frac{{v_{0}}^{2}}{5\, g}\end{aligned}[/tex].
Given that [tex]v_{0} = 40\; {\rm m\cdot s^{-1}[/tex] and [tex]g = 10\; {\rm N \cdot kg^{-1}} = 10\; {\rm m\cdot s^{-2}[/tex]:
[tex]\begin{aligned} r & < \frac{{v_{0}}^{2}}{5\, g} \\ &= \frac{(40\; {\rm m\cdot s^{-1}})^{2}}{5 \times (10\; {\rm m\cdot s^{-2}})} \\ &= 32\; {\rm m}\end{aligned}[/tex].
Hence, the radius of this loop is at most [tex]32\; {\rm m}[/tex], such that the height of the top of this loop is at most [tex]2 \times 32\; {\rm m} = 64\; {\rm m}[/tex].
Air masses that form over continents in ource regions that are cold are called __
Answers:
Continental polar Cp
Maritime Polar Mp
Continental tropical ct
Maritime tropical mp
Answer:
Continental polar Cp
Explanation:
According to Einstein's equation, if 3 kg of mass "disappears" during a
reaction, then
A. 5.4 x 1018. J of energy is produced.
OB. the law of conservation of momentum is also violated.
OC. 9 x 108 J of energy is produced.
D. 2.7 x 1017 J of energy is produced.
HELP NOW
The 2.7 x 10^17 J of energy is produced when 3.0 kg mass disappears.
What is the energy produced when 3 kg of mass is converted to energy?According to Einstein's equation, the energy produced when mass is converted to energy is proportional to the mass of the substance.
The Einstein equation is given as:
[tex]E = mc^{2}[/tex]
Mass = 3 kg
c = 3.0 × 10^8
[tex]E = 3 × (3.0 × 10^{8})^{2} = 2.7 \times 10^{17}[/tex]
Therefore, 2.7 x 10^17 J of energy is produced when 3.0 kg mass disappears.
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A car is travelled at 8m/s. The mass of the car is 750 kg.
Calculate the force required to stop the car in 8s
Answer:
F = 750N
Explanation:
We know that F(force) = mass(m) × acceleration(a)
And that Acceleration(a) = velocity(V) ÷ time(t)
So we'll first calculate the acceleration
a = V = 8m/s = 1m/s²
t 8
Next we'll calculate the force
F = ma = 750kg × 1m/s² = 750N
Compare the mass on neptune (68.11) to the weight on neptune (905.863). what is the difference? why is there a difference?