What’s the solution to 2x - 2 > 2x + 4 ?

Answer/Step-by-step explanation:

[tex]\frac{1-\cos \left(x\right)}{\sin \left(x\right)}=\frac{\sin \left(x\right)}{1+\cos \left(x\right)}[/tex]

When you have an equation like this, you can start from either side. So, let us start from the left side.

[tex]\underline{\mathrm{Left\:side:}} \quad\frac{1-\cos \left(x\right)}{\sin \left(x\right)}[/tex]

[tex]\sf{Rewrite\: using \:Trig \:identities=\frac{\sin \left(x\right)}{1+\cos \left(x\right)}}\\\\\mathrm{Therefore,\: it \:is \:true}[/tex]

Answer:

9 units²

Step-by-step explanation:

Parallelogram area = base × height

Base = 3 units

Height = 3 units

Area = 3 × 3

Area = 9

The area of the parallelogram is 9 units².

Here, we have,

We know that,

Parallelogram area = base × height

here, from the given figure we get,

Base = 3 units

Height = 3 units

so, we get,

Parallelogram area = base × height

Area = 3 × 3

Area = 9

Hence, The area of the parallelogram is 9 units².

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35.6 355⅝5555555555555555555545455555555

Answer:

5 hours

Step-by-step explanation:

One, two, three, four, five, six, seven, eight, nine, ten, eleven, twelve, thirteen, fourteen, fifteen, sixteen, seventeen, eighteen, and nineteen/Uno, dos, tres, cuatro, cinco, seis, siete, ocho, nueve, diez, once, doce, trece, catorce, quince, dieciséis, diecisiete, dieciocho y diecinueve

Step-by-step explanation:

Number 1

Number of spoons= no of boxes × individual no of spoons

= 100 × 8 = 800 spoons.

Number of cones = no of cones in a box × no of boxes

= 60 × 8 = 480

Number of cup = no of cups in a box × no of boxes

= 80 × 8 = 640.

Total = 800 + 480 + 640 = 1920

Number 2

If everyone needs a cup, spoon and cones, it means they all need 3 items.

no of people you can serve = 1920 ÷ 3

= 640 people.

Answer:

-115/69

Step-by-step explanation:

12(6x + 10) + x = 9x + 5(1 - x)

72x + 120 + x = 9x + 5 - 5x

73x + 120 = 4x + 5

69x = 5 - 120

69x = -115

x = -115/69

Answer:

-1

sorry if this is wrong I really am

Answer:

m= -1

Step-by-step explanation:

Have a nice day

Balance the reaction:

a FeS₂ + b O₂   =>   c Fe₂O₃ + d SO₂

Matching up the atoms on either side gives the system of equations

• Fe: a = 2c

• S: 2a = d

• O: 2b = 3c + 2d

We have 3 equations with 4 unknowns. Suppose we fix one of the variables, say a = 2. Then

2 = 2c   ===>   c = 1

2•2 = d   ===>   d = 4

2b = 3•1 + 2•4   ===>   b = 11/2

and so the balanced reaction is

2 FeS₂ + 11/2 O₂   =>   Fe₂O₃ + 4 SO₂

or

4 FeS₂ + 11 O₂   =>   2 Fe₂O₃ + 8 SO₂

Look up the molar masses of each component element:

• Fe: 55.845 g/mol

• S: 32.06 g/mol

• O: 15.999 g/mol

Then the molar masses of the reactants are

• FeS₂: 119.965 g/mol

• O₂: 31.998 g/mol

Convert the given masses to moles:

• (882 g FeS₂) (1/119.965 mol/g) ≈ 7.35 mol FeS₂

• (528 g O₂) (1/31.998 mol/g) ≈ 16.5 mol O₂

In the balanced reaction, 4 moles of FeS₂ combine with 11 moles of O₂, or equivalently 1 mol FeS₂ is needed for every 11/4 = 2.75 mol O₂. Now,

(16.5 mol O₂) / (2.75 mol O₂) = 6

while

(7.35 mol FeS₂) / (1 mol FeS₂) = 7.35

which means the reaction consumes all of the available O₂ and we're left with 7.35 - 6 = 1.35 mol FeS₂.

For every 11 mol O₂ among the reactants, 2 mol Fe₂O₃ are produced. Then 16.5 mol O₂ makes for

(11 mol O₂) / (2 mol Fe₂O₃) = (16.5 mol O₂) / x

===>   x = 3.00 mol Fe₂O₃

which has a mass of

(3.00 mol Fe₂O₃) (160. g/mol) ≈ 479 g Fe₂O₃

To find the mass of Fe2O3 produced, we convert the given masses of FeS2 and O2 into moles and use the molar ratio in the balanced chemical equation. The mass of Fe2O3 produced is 1170.68 grams.

To solve this problem, we need to convert the given masses of FeS2 and O2 into moles. From the balanced chemical equation, we can see that the molar ratio between FeS2 and Fe2O3 is 1:1.

This means that the number of moles of Fe2O3 produced will be equal to the number of moles of FeS2. We can use the molar mass of Fe2O3 to convert moles to grams.

First, we calculate the number of moles of FeS2 and O2:

Moles of FeS2 = 882 g / 120.17 g/mol = 7.34 mol

Moles of O2 = 528 g / 32 g/mol = 16.5 mol

Since the molar ratio between FeS2 and Fe2O3 is 1:1, we know that 7.34 moles of FeS2 will produce 7.34 moles of Fe2O3.

Now, we can calculate the mass of Fe2O3:

Mass of Fe2O3 = Moles of Fe2O3 x Molar mass of Fe2O3

Mass of Fe2O3 = 7.34 mol x 159.69 g/mol = 1170.68 g

Therefore, 1170.68 grams of Fe2O3 are produced.

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Answer:

a) 2400m on the 20th day for Charlie.

1) 728.41m of 20th day for Daniella.

Didn't find n, sorry.

Charlie ran 2400m on day 20 of his fitness program and Daniella ran 728m on day 20 of her fitness program.

It is given that Charlie and Daniella on day one both ran 500m on each subsequent day.

Charlie ran 100m more than the previous day.

Daniella increased her distance by 2% of the distance run on the previous day.

It is required to calculate how far Charlie and Daniella ran on day 20 and the value of n.

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

Charlie ran 500m on the first day:

[tex]\rm a_1 = 500[/tex]

[tex]\rm a_2 =600[/tex] ( because charlie ran 100m more than the previous day)

It is an arithmetic progression in which the difference between two consecutive terms:

d = 600 - 500 ⇒ 100

and [tex]\rm a_n = a+d(n-1)[/tex]

[tex]\rm a_2_0 = 500+100(20-1)\\\\\rm a_2_0 = 2400m[/tex]( ∵ n = 20 )

Daniella ran 500m on the first day:

[tex]\rm b_1 = 500[/tex]

[tex]\rm b_2 = 500+ 500\times2 \%[/tex]  (because Daniella increased her distance by 2% of the distance run on the previous day)

We can write [tex]\rm n^t^h[/tex] terms:

[tex]\rm b_n= 500(1+2\%)^n^-^1[/tex]

[tex]\rm b_2_0= 500(1+2\%)^2^0^-^1[/tex]

[tex]\rm b_2_0= 500(1+0.02)^1^9\\\\\rm b_2_0 = 500\times 1.02^1^9\\\\\rm b_2_0 = 500\times1.456 \Rightarrow 728.40 \approx 728 m[/tex]

[tex]\rm b_n > a_n[/tex]  (given in the question)

[tex]\rm500(1+2\%)^n^-^1 > 500+100(n-1) \ \ or \\\\\rm500(1+2\%)^n^-^1 > 100n+400[/tex]

The above expression is not true for all the values of 'n' ie. 'n' can not be determined.

Thus, Charlie ran 2400m on day 20 of his fitness program and Daniella ran 728m on day 20 of her fitness programme.

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Answer:

(4) 1/4x = 3/4 (4)

1x=3

Step-by-step explanation:

3/4 x

÷ = ÷

1/4 1

(4) 1/4x = 3/4 (4)

1x=3

Answer:

no its not a proportion

Step-by-step explanation:

because the line has to be straight unless the graph is scrap

Answer:

"Yes, it is a proportional relationship because the graph is a straight line"

Step-by-step explanation:

Your welcome ^^

Answer:

4f+4g

Step-by-step explanation:

Check the picture below.

and let's not forget that the midsegment of a triangle is always half its parallel base.

[tex]\stackrel{midsegment}{AB}=\cfrac{\stackrel{base}{QS}}{2}\implies 16=\cfrac{QS}{2}\implies 32=QS[/tex]

The distance Pilar's bike travel when the wheel makes  10 complete rotations is 753.6 inches

Since the wheel is circular in nature, we will take the circumference to determine the distance travelled for 1 revolution

Circumference of a circle = πr²

r is the radius of the wheel.

Given that d = 24 in, r = 24/2 = 12in

C = 2(3.14)(12)

C = 75.36 in

Hence the distance completed by 1 revolution is 75.36. If Pilar's bike makes 10 revolutions, hence the required distance will be:

D = 10 * 75.36

D = 753.6in

Hence the distance Pilar's bike travel when the wheel makes  10 complete rotations is 753.6 inches

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Using the normal distribution and the central limit theorem, it is found that there is a 0% probability of a sample of 50 cars recording an average speed of 66 mph or higher.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem:

The probability of a sample of 50 cars recording an average speed of 66 mph or higher is 1 subtracted by the p-value of Z when X = 66, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{66 - 62}{0.7071}[/tex]

[tex]Z = 5.66[/tex]

[tex]Z = 5.66[/tex] has a p-value of 1.

1 - 1 = 0.

There is a 0% probability of a sample of 50 cars recording an average speed of 66 mph or higher.

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Answer:

Step-by-step explanation:

Assuming the string is straight (it will not be so due to gravity and wind load)

θ arcsin(354 / (200(3)) = 36°

Answer:

  A) 20 pounds

  B.2) (increasing) 60 pounds per minute

Step-by-step explanation:

A) The graph shows the container has 20 pounds in it at x=0 minutes.

__

B) The graph goes up to the right (is increasing).

At minute 0, the container has 20 pounds.

At minute 1, the container has 80 pounds.

The increase in one minute is 80-20 = 60 pounds per minute.

The initial amount of candy in the container is 2 pounds.  As time increases, the amount of candy in the container decreases at a rate of 1 pound per minute.

A.) The amount of candy in the container at 0 minutes is 2 pounds.

B1.) As time increases, the amount of candy in the container decreases. The rate at which the amount of candy is decreasing is 1 pound per minute.

B2.) As time increases, the amount of candy in the container increases. However, this option is not applicable in this case as the graph shows a decreasing trend.

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Answer:

x < -6

Step-by-step explanation:

-2x - 4 > 8

the first step is to add 4 to both sides since we need to get x alone on one side

-2x - 4 > 8

      +4  +4

so we are left with -2x > 12

we still need to get x alone so we have to divide -2 from both sides

always remember that if you divide by a negative number the inequality flips!! so instead of > it will be <.

-2x/-2 = x

12/-2 = -6

so the answer is x < -6

Usando técnicas de conteo, se encuentra que

1. Un cliente puede ordenar una comida de 784 formas.

2. 420 grupos de 4 letras se pueden formar con las letras de la palabra TECNICA.

3. 840 números de 4 dígitos se pueden formar con los primeros 7 números naturales.

4. 10 partidos distintos se pueden realizar.

5. Pueden colocarse de 3,628,800 formas.

6. 1260 señales distintas pueden indicarse.

Item 1:

La técnica usada es el principio fundamental de conteo, que afirma que si hay n cosas, cada una con [tex]n_1, n_2, \cdots, n_n[/tex] maneras de seren realizadas, el número total de maneras de ser realizadas es:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

En este problema, [tex]n_1 = 14, n_2 = 8, n_3 = 7[/tex], por eso:

[tex]T = 14 \times 8 \times 7 = 784[/tex]

Un cliente puede ordenar una comida de 784 formas.

Item 2:

El orden es importante, ya que TECN es una palabra diferente de NCET, por lo tanto, la fórmula de permutaciones se usa para resolver este problema.

Fórmula de permutaciociones:

El número de permutaciones de x elementos en un conjunto de n elementos es dada por:

[tex]P_{n,x} = \frac{n!}{(n - x)!}[/tex]

En este problema, 4 letras de 7, enconteces:

[tex]P_{7,4} = \frac{7!}{3!} = 840[/tex]

La letra C se repite dos veces, o sea:

[tex]T = \frac{P_{7,4}}{2} = \frac{840}{2} = 420[/tex]

420 grupos de 4 letras se pueden formar con las letras de la palabra TECNICA.

Item 3:

Permutaciones de 4 dígitos de 7, sin repeticiones, o sea:

[tex]P_{7,4} = \frac{7!}{3!} = 840[/tex]

840 números de 4 dígitos se pueden formar con los primeros 7 números naturales.

Item 4:

El orden no es importante, ya que Time 1 x Time 2 es la misma partida de Time 2 x Time 1, por lo tanto, la fórmula de combinaciones se usa para resolver este problema.

Fórmula de combinaciones:

El número de combinaciones de x elementos en un conjunto de n elementos es dada por:

[tex]C_{n,x} = \frac{n!}{x!(n - x)!}[/tex]

En este problema, combinaciones de 2 elementos de un conjunto de 5, entonces:

[tex]C_{5,2} = \frac{5!}{2!3!} = 10[/tex]

10 partidos distintos se pueden realizar.

Item 5:

El número de arreglos de n elementos viene dado por

[tex]A_n = n![/tex]

En este problema, arreglo de 10 elementos, o sea:

[tex]A_{10} = 10! = 3628800[/tex]

Pueden colocarse de 3,628,800 formas.

Item 6:

El número de arreglos de n elementos, con repeticiones de [tex]n_1, n_2, \cdots n_n[/tex] elementos viene dado por

[tex]A_n^{n_1,n_2,\cdots,n_n} = \frac{n!}{n_1!n_2! \cdots n_n!}[/tex]

En este problema, [tex]n = 9, n_1 = 3, n_2 = 2, n_3 = 4[/tex], por eso:

[tex]A_9^{3,2,4} = \frac{9!}{3!2!4!} = 1260[/tex]

1260 señales distintas pueden indicarse.

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The number of Wildcat fans were at  the game is 3557.

The number of  bears fans at the game is 1269.

Let:

W = number of wildcats fans at the game

B = number of bears fans at the game.

The total number of fans at the game: W + B = 4826

This equation can be used to represent the number of wildcats fans at the game: W = 3b - 250

Replace for w in the above equation:

3b - 250 + b = 4826

To determine the value of b, take the following steps

Combine and add similar terms

4b = 5076

Divide both sides by 4

b = 1269

To determine the value of w, substitute for b in the first given equation.

W + 1269 = 4826

w = 4826 - 1269

w = 3557

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Answer:

11

Step-by-step explanation:

    f(12) means that we plug 12 into our x value since the function is f(x) which will be solved as the following:

2/3x + 3

2/3(12) + 3

8 + 3

11

Have a nice day!

    I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

Answer is C, 40

Step-by-step explanation:

(100)-(60)

Answer:

Just go to the 6 on the bottom line, and add a point

Answer:

see below

Step-by-step explanation:

(6,0)

 The first coordinate is the x coordinate.  Since it is positive we go to the right 6 units.  The second coordinate is the y coordinate.  We go up zero units

Answer:

2 hours and 31 minutes

Step-by-step explanation:

10:51 +9 =11:00

+ 2 hours = 1:00 +22 = end time

so added together 22+9= 31 + the 2 hours = 2 hours and 31 minutes

Answer:

54,400

Step-by-step explanation:

Answer:

she could spend up to $225 on more supplies

Step-by-step explanation:

the total amount of supplies and labor has to be less than or equal to $500. If she spent $150 and $125=$275 on supplies and labor, the equation would be 150+125+x≤ 500. Isolate x, to get x≤ $225. The value of x has to be less than or equal to $225.