When lithium chloride, LiCl, dissolves in water, it forms lithium ions, [tex]Li^{+}[/tex], in aqueous solution with water, [tex]H_{2}O[/tex].
Water has a higher solubility for lithium chloride than non-polar solvents. The LiCl crystal is destroyed as a result of the interactions between the ions and the polar water molecules, and the hydrogen bonding structure of the H2O molecules in the liquid water is also disrupted, allowing the ions to be incorporated among the water molecules.
The ions in the crystal lattice would not be attracted to non-polar molecules very strongly. LiCl would continue to be in the crystal structure while the non-polar molecules would continue to be attracted to one another by the weak London force.
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According to the following balanced reaction, how many moles of NO are formed from 3.75 moles of NO2 if there is plenty of water present? 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)
Taking into account the reaction stoichiometry, 1.25 moles of NO are formed from 3.75 moles of NO₂ if there is plenty of water present.
Reaction stoichiometryIn first place, the balanced reaction is:
3 NO₂ + H₂O → 2 HNO₃ + NO
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
NO₂: 3 molesH₂O: 1 molesHNO₃: 2 molesNO: 1 moleAmount of moles of NO formed
The following rule of three can be applied: if by reaction stoichiometry 3 moles of NO₂ form 1 mole of NO, 3.75 moles of NO₂ form how many moles of NO?
amount of moles of NO= (3.75 moles of NO₂× 1 mole of NO)÷ 3 moles of NO₂
amount of moles of NO= 1.25 moles
Finally, 1.25 moles of NO are formed.
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Why is crystal of oxalic acid regarded as a primary standard solution ?
Answer:
dwn
Explanation:
Oxalic acid solution is a primary standard because it is highly pure, stable and does not change its concentration with environmental factors. > Coming to option B, Sodium thiosulphate, it is a secondary standard reagent. Sodium thiosulphate is also called hypo.
The energy diagram shown represents the chemical reaction between solid ammonium chloride and solid barium hydroxide octahydrate:2NH4Cl(s)+Ba(OH)2⋅8H2O(s)→2NH3(aq)+BaCl2(aq)+10H2O(l)The ΔH for this reaction is 54.8 kJ . How much energy would be absorbed if 27.1 g of NH4Cl reacts?Express your answer with the appropriate units.Answer= (value)/(units)
According to the chemical equation, the reaction absorbs 54.8 kJ per 2 moles of NH4Cl because that's the stoichiometry coefficient of this molecule.
Now, we need to find the number of moles in each mole of NH4Cl.
[tex]\begin{gathered} N=14.0067 \\ H_4=4\cdot(1.00784)=4.03136 \\ Cl=35.453 \end{gathered}[/tex]Then, we add them to find the molar mass.
[tex]NH_4Cl=53.49\cdot\frac{g}{\text{mol}}[/tex]This means that 1 mole of NH4Cl equals 53.49 grams.
At last, we multiply the mass of NH4Cl (27.1 g) by two ratios, the first ratio is about the molar mass, and the second ratio is about the amount of heat per moles.
[tex]27.1g\cdot\frac{1\text{mol}}{53.49g}\cdot\frac{54.8kJ}{2\text{mol}}=\frac{1485.08}{106.98}kJ=13.88kJ[/tex]Therefore, the amount of energy that would be absorbed is 13.88 kJ.
PEASE HELP PLEASE!? List and describe the substrates and products of TCA cycle
Acetyl group, oxaloacetic acid, coA, citric acid, and other elements are the substates and products required to initiate and finish the TCA cycle.
What are the the substrates and products of TCA cycle?Oxaloacetate and acetyl CoA undergo an enzymatic aldol addition reaction to form citrate at the start of the TCA cycle.To produce (2R,3S)-isocitrate, a dehydration-hydration sequence is used to isomerize the citrate.Ketoglutarate is produced by additional enzymatic oxidation and decarboxylation.The enzyme decarboxylates and oxidises 2-ketoglutarate once more to produce succinyl-CoAGuanosine diphosphate (GDP) is phosphorylated to guanosine triphosphate in conjunction with the hydrolysis of this metabolite to succinate (GTP).Fumarate is produced by succinate dehydrogenase, an enzyme that is dependent on the flavin adenine dinucleotide (FAD).Fumarate, catalysed by fumarase, is converted to L-malate following stereospecific hydration.Finally, malate dehydrogenase catalyses the TCA cycle's closing step, which is the NAD-coupled oxidation of L-malate to oxaloacetate. This completes the cycle.Learn more about TCA cycle
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Help me indicate whether OXYGEN will gain or lose electrons to get a full outer shell and how many electrons they will need to gain or lose
Oxygen have 6 valence electrons. It needs only two electrons to get a full outer shell.
Thus, oxygen will gain two electrons.
HELP!!!!!!! Calculating the average atomic mass from Isotope data
The relative atomic masses of the elements are:
Lead = 206.96 amu
Magnesium = 24.62 amu
Silicon = 28.08 amu
What is the relative atomic mass of the isotopes?The relative atomic masses of the given elements from their isotopes is determined as follows:
1. Lead:
Relative atomic mass = (203.973 * 0.014) + (205.974 * 0.236) + (206.759 * 0.226) + (207.9766 * 0.523)
Relative atomic mass = 206.96 amu
2. Magnesium:
Relative atomic mass = (23.985 * 79.99) + (24.986 * 10%) + (25.983 * 11.01%)
Relative atomic mass = 24.62 amu
3. Silicon:
Relative atomic mass = (27.977 * 92.21%) + (28.976 * 4.70%) + (29.973 * 3.09%)
Relative atomic mass = 28.08 amu
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The heat of vaporization of water is 540 calories per gram. Based on your calculations in
question 13, how many calories would be required to raise the same mass of water and
convert it from water liquid (95 0C) to water gas (1000C)?
Show your work for partial credit.
Step 1: Water raises from 95°C to 1000C
To convert 100.0 g of water at 20.0 °C to steam at 100.0 °C requires 259.5 kJ of energy.
For this problem, there are only two heats to consider:
q
1
= heat required to warm the water from 20.0 °C to 100.0 °C.
q
2
= heat required to vapourize the water to steam at 100 °C.
q
1
=
m
c
Δ
T
=
100.0 g × 4.184 J
∘
C
−
1
g
−
1
×
80.0
∘
C
=
33 472 J
q
2
=
m
Δ
H
vap
=
100.0 g × 2260 J⋅g
−
1
=
226 000 J
q
1
+
q
2
=
( 33 472 + 226 000) J = 259 472 J = 259.5 kJ
(4 significant figures)
Which best defines color?(1 point) Responses a chemical property of matter related to how a material interacts with different wavelengths of light a chemical property of matter related to how a material interacts with different wavelengths of light a physical property of matter related to a material’s ability to reflect light a physical property of matter related to a material’s ability to reflect light a chemical property of matter related to a material’s ability to reflect light a chemical property of matter related to a material’s ability to reflect light a physical property of matter related to how a material interacts with different wavelengths of light
Color is a physical property of matter related to a material’s ability to reflect light.
What is color?Color is a physical property of chemicals that in most cases comes from the excitation of electrons due to an absorption of energy performed by the chemical.
Color is that portion of the visible spectrum of light that is reflected back from a surface. A color can only be observed in the presence of light.
When light hits a surface, the particles of the object absorbs the colors in the light. However, not all colours are absorbed by the surface as some are reflected. The reflected color is seen as the color of that object.
The color of light coming from an object is what gives it color. Light travels into the eye to the retina located on the back of the eye. The human eye and brain work together to translate light into color.
Therefore, it can be said that a substance's ability to reflect light is color.
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Balance the following equation MnO2(s) + HCI(aq) = Cl2(g) + MnCl2(aq) + H2O(I)
195 ml of 0.355 m nacl is added to a 0.500 l volumetric flask and the flask is filled with water. calculate the [na⁺] concentration in the diluted solution.
Answer:
0.286 M
Explanation:
This is a great example of a practice problem that requires you to use the formula for dilution calculations.
To make it more interesting, let's assume that you're not familiar with that problem.
The most important thing to remember about a dilution is the the number of moles of solute must remain constant.
That is, the number of moles of solute present in the initial solution must be equal to the number of moles of solute present in the diluted solution.
Since molarity is defined as moles of solute per liter of solution, keeping the number of moles of solute constant allows you to decrease concentration by increasing the total volume of the solution.
195 ml of 0.355 ml NaCl is added to a 0.500 ml volumetric flask and the flask is filled with water. The [ Na⁺ ] concentration in the diluted solution is 138.45 M
What is concentration ?Concentration is calculated by dividing a constituent's abundance by the mixture's total volume. Mass concentration, molar concentration, number concentration, and volume concentration are four different categories of mathematical description.
Molarity is the number of moles of solute per liter of solution and mole fraction is the proportion of solute moles to all other moles of substances present. Parts per thousand grams, mass percentage, the ratio of the solute's mass to the solution's mass multiplied by 100.
M₁ V₁ = M₂ V₂
0.355 × 195 = M₂ × 0.500
M₂ = 0.355 × 195 ÷ 0.500
138.45 M
Thus, The [ Na⁺ ] concentration in the diluted solution is 138.45 M
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Calculate the molarity of a carbonic acid solution given the following titration results: 47.00 mL of the carbonic acid solution was neutralized to a phenolphthalein endpoint with 23.82 mL of 0.1250 M ammonium hydroxide.
The molarity of carbonic acid is 0.063M when titration is done between 47.00mL carbonic acid and 23.82mL of 0.1250M ammonium hydroxide.
What is titration?Titration is a technique by which we know the concentration of unknown solution using titration of this solution with solution whose concentration is known. To know the end point we use phenolphthalein as indicator. End point is a point where completion of reaction happen
Mathematically
moles or carbonic acid =moles of ammonium hydroxide
[tex]M_{1} V_{1} =M_{2} V_{2} \\M_{1} =Molarity of carbonic acid\\V_{1} =Volume of carbonic acid\\M_{2} =Molarity of ammonium hydroxide\\V_{2} =Volume of ammonium hydroxide[/tex]
Substituting all values
[tex]M_{1}[/tex]=(0.1250×23.82)÷47.00
[tex]M_{1}[/tex]=0.063M
Thus the molarity of carbonic acid is 0.063M
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Which diagram correctly shades the f-block of the periodic table in blue?
Answer
B.
Explanation
The diagram shown below correctly shades the S, P, D, F-block of the periodic table:
Comparing the above with the given options, the diagram which correctly shades the f-block of the periodic table in blue will be option B:
Calculate the mass of forsterite Mg2SiO4 that contains a million ×1.00106 oxygen atoms. Be sure your answer has a unit symbol if necessary, and round it to 4 significant digits.
The mass of forsterite Mg₂SiO₄ that contains a million, 1×10⁶ oxygen atoms is 5.819×10⁻¹⁷ g
How to determine the mass of Mg₂SiO₄We'll begin by obtinig the mass of oxygen that contains 1×10⁶ atoms. This can be obtained as follow:
From Avogadro's hypothesis,
6.02×10²³ atoms = 1 mole of oxygen.
But
1 mole of oxygen = 16 g
Thus,
6.02×10²³ atoms = 16 g of oxygen.
Therefore,
1×10⁶ atoms = (1×10⁶ atoms × 16 g) / 6.02×10²³ atoms
1×10⁶ atoms = 2.66×10⁻¹⁷ g of oxygen
Finally, we shall determine the mass of Mg₂SiO₄ that contains 1×10⁶ atoms (i.e 2.66×10⁻¹⁷ g) of oxygen. This can be obtained as follow:
1 mole of Mg₂SiO₄ = (24 × 2) + 28 + (16 × 4) = 140 gmass of O in 1 mole of Mg₂SiO₄ = 16 × 4 = 64 gThus, we can say:
64 g of oxygen is present in 140 g of Mg₂SiO₄.
Therefore,
2.66×10⁻¹⁷ g of oxygen will be present in = (2.66×10⁻¹⁷ × 140) / 64 = 5.819×10⁻¹⁷ g of Mg₂SiO₄
Thus, the mass of Mg₂SiO₄ is 5.819×10⁻¹⁷ g
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How many grams of magnesium (Mg, 24.30g/mol) are in 7.43 x 1022 atoms of Mg?7.43x 1022 atoms Mg| 1 mole Mg 24.30 g Mg16.02x 1023 atoms Mg/ 1 mole Mg[?] grams Mg
To calculate this, we can use fractions for equivalent amounts.
So, we have the number of atoms, using the Avogadro's Constant, we know that 1 mol of Mg is approximately 6.02 x 10^23, so:
[tex]\frac{1\text{mol Mg}}{6.02\times10^{23}\text{atoms Mg}}=1[/tex]And since we have the number of atoms of Mg, we can convert to mol of Mg by multiplying by this fraction.
Now, from mol of Mg we can convert to mass using the molar mass of 24.30 g/mol. It says that 24.30 g og Mg is equivalent to 1 mol, so:
[tex]\frac{24.30\text{g Mg}}{1\text{mol Mg}}=1[/tex]So, we have:
[tex]7.43\times10^{22}\text{atom Mg}\cdot\frac{1\text{mol Mg}}{6.02\times10^{23}\text{atom Mg}}\cdot\frac{24.30\text{g Mg}}{1\text{mol Mg}}[/tex]Notice that this is presented in a table in the question, so we can now just multiply all of them:
[tex]7.43\times10^{22}\text{atom Mg}\cdot\frac{1\text{mol Mg}}{6.02\times10^{23}\text{atom Mg}}\cdot\frac{24.30\text{g Mg}}{1\text{mol Mg}}=\frac{7.43\times10^{22}\cdot24.30\text{g Mg}}{6.02\times10^{23}}=2.999\text{g Mg}\approx3.00\text{g Mg}[/tex]Thus, this is equivalent of approximately 3.00 g of Mg.
calculate the net force acting on the box in the following. refer to the screenshot below.
Answer:
6 N to the left, or -6 N
unbalanced
Explanation:
The forces are two 3 N forces. The forces are additive, so 3+3 = 6, so the answer is 6 N to the left.
Since the net force isn't 0, the forces are unbalanced (aka the block will move since there is a force pushing the block)
Ca(s) + 2H₂O(l) → Ca(OH)₂(aq) + H₂(g) 14. Calcium reacts with water according to the above reaction. What volume of hydrogen gas, at standard temperature and pressure, is produced from 0.200 moles of calcium?
According to the stoichiometry, 0.4 ml of hydrogen gas is produced from 0.2 moles of calcium .
What is stoichiometry?It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.
In the given problem, 1 mole of calcium produces 1 mole of hydrogen gas.
Given 0.2 moles of calcium , so mass of calcium by number of moles formula,mass=number of moles×molar mass=0.2×40.07=8.014 g
As 40.07 g of calcium produces 2 g hydrogen
∴8.014 g calcium produces 8.014×2/40.07=0.4 ml.
Thus, the volume of hydrogen gas produced from 0.2 moles of calcium at standard temperature and pressure is 0.4 ml.
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Calculate the volume in milliliters of 8.7 % (v/v) ethanol solution that contains 34.2 mL of ethanol.
v/v Concentration is a type of concentration in which we use to determine what would be the percentage of a certain volume of solute (the one with the least volume) by a certain volume of solution (the one with the most volume). The formula for this will be:
%v/v = volume of solute/volume of solution
In this question, we have:
%v/v = 8.7%, which is 0.087
volume of solute = 34.2 mL
Now we add these values into the formula:
0.087 = 34.2/v
v * 0.087 = 34.2
v = 34.2/0.087
v = 393 mL of ethanol solution that contains 34.2 mL of ethanol
What is the correct name for AIN?a. Aluminum nitrideb. Aluminum nitratec. Aluminum mononitrided. Aluminum mononitrate
Answer:
a. Aluminum nitride
Explanation:
The compound AlN is a salt made up of Al and N.
Analyzing the oxidation states of each element, we can see that Aluminum acts with 3+ (because it has only one oxidation state), so Nitrogen need to interact with an oxidation state of 3-, for the molecule to be neutral.
Due to the nitrogen acts with 3- the name of the salt will be Aluminum nitride.
3. Calculate the equilibrium constant ( Ke ) for the reaction below if the equilibrium mixture for the reaction was found o contain [ H₂S ] 0.25 M. [ H₂ ] = 1 M , and [ S₂ ] -0.2 M. 2H₂S ( g ) 2H₂ ( g ) + S2 ( g )
The equilibrium constant relates the concentrations of the products and reactants in the chemical equilibrium. To calculate it we can apply the following equation.
For the reaction: aA + bB ---> cC + dD
Equlibrium constant (Ke) will be:
[tex]K=\frac{\lbrack C\rbrack^c\times\lbrack D\rbrack^d}{\lbrack A\rbrack^a\times\lbrack B\rbrack^b}[/tex]The letters in square brackets refer to the concentration raised to the respective coefficient. Now we replace the known values:
[tex]\begin{gathered} K=\text{ }\frac{\lbrack H_2\rbrack^2\times\lbrack S_2\rbrack^1}{\lbrack H_2S\rbrack^2} \\ K=\frac{\lbrack1M\rbrack^2\times\lbrack0.2M\rbrack^1}{\lbrack0.25M\rbrack^2} \\ K=\frac{1M^2\times0.2M}{0.0625M^2} \\ K=3.2M \end{gathered}[/tex]So, the equilibrium constant (Ke) will be 3.2M
A 25.0 mL solution of HBr is neutralized with 13.7 mL of 0.230 M Ba(OH)₂. What is the concentration of the original HBr solution?
The concentration of the original HBr solution that has 25.0 mL solution neutralized with 13.7 mL of 0.230 M Ba(OH)₂ is 0.126M.
How to calculate concentration?Molarity is the concentration of a substance in solution, expressed as the number moles of solute per litre of solution.
Molarity can be calculated by using the following formula;
C₁V₁ = C₂V₂
Where;
C₁ = initial concentrationV₁ = initial volumeC₂ = final concentrationV₂ = final volumeAccording to this question, 25.0 mL solution of HBr is neutralized with 13.7 mL of 0.230 M Ba(OH)₂. The original concentration can be calculated as follows:
25 × x = 0.230 × 13.7
25x = 3.151
x = 0.126M
Therefore, 0.126M is the concentration of HBr solution.
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2HC2H3O2 + Na2CO3 = h20 + co3 + 2nac2h3o2
Answer:
Na2CO3 + 2HC2H3O2 → CO2 + H2O + 2NaC2H3O2
Explanation:
Label Each Compound With a VariableLabel each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.aNa2CO3 + bHC2H3O2 = cCO2 + dH2O + fNaC2H3O2Create a System of EquationsCreate an equation for each element (Na, C, O, H) where each term represents the number of atoms of the element in each reactant or product.Na: 2a + 0b = 0c + 0d + 1f
C: 1a + 2b = 1c + 0d + 2f
O: 3a + 2b = 2c + 1d + 2f
H: 0a + 4b = 0c + 2d + 3f
Solve For All VariablesUse substitution, gauss elimination, or a calculator to solve for each variable.
Simplify the result to get the lowest, whole integer values.
a = 1 (Na2CO3)
b = 2 (HC2H3O2)
c = 1 (CO2)
d = 1 (H2O)
f = 2 (NaC2H3O2)
Substitute Coefficients and Verify Result
Na2CO3 + 2HC2H3O2 = CO2 + H2O + 2NaC2H3O2
Reactants Products
Na 2 2 ✔️
C 5 5 ✔️
O 7 7 ✔️
H 8 8 ✔️
Since there is an equal number of each element in the reactants and products of Na2CO3 + 2HC2H3O2 = CO2 + H2O + 2NaC2H3O2, the equation is balanced.
Choose the words to finish the sentence.
The sinking of ocean crust back into the mantle when it meets continental crust is
Choose...
, and this occurs at
Choose...
.
The sinking of the ocean crust back into the mantle when it meets continental crust is referred to as subduction , and this process occurs at the ocean trenches.
What is Subduction?This is referred to as a geological process which occurs when there is collision between two tectonic plates in the earth in which one of the plate sinks into the mantle underneath the other plate.
During this process of subduction, the ocean crust sinks back into the mantle when it meets continental crust and it occurs mainly at the ocean trenches thereby making the options provided the correct choice.
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How many grams of gold will be produced from 213.46g AuPO4? At. Wt.: Sn = 119g/mol; Au
= 197g/mol; P = 31g/mol; O = 16g/mol
The amount of gold that can be produced from 213.46g AuPO₄ is equal to 143.7g.
What is a mole?A mole is a standard unit that can be used to determine the huge number of quantities of ions, atoms, molecules, or other particular particles. The mass of the 1 mole of any element is known as atomic mass (in grams) and the mass of one mole of any compound is called molar mass.
The number of units in one mole was found to be approximately 6.023 × 10 ²³ also called Avogadro’s constant.
Given, the mass of the AuPO₄ = 213.46 g
The molar mass of the AuPO₄ = 197 + 31 + 4(16) = 292 g/mol
The number of moles of the AuPO₄ = 213/292 = 0.729 mol
If the mole of AuPO₄ will produce one mole of the Au.
Then 0.729 mol of the AuPO₄ will produce Au = 0.729 mol
The mass of the Au (in grams) = 0.729 ×197 = 143.7 g/mol
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Calculations of Ksp
a) calculate the concentrations of dissolved PbI2, Pb+2 and I-1 ions when Ksp = 1.35 x 10-9
b) calculate the Ksp of Ag3CrO4 when the concentration of silver cations is 4.16 x 10-6 mol/L when you know that this dissociation occurs: Ag3CrO4 ↔ 3 Ag+ + CrO4-3
1) The solubility of the ions are;
lead II ions = 6.96 * 10^-4 M
iodide ions = 3.48 * 10^-4 M
2) The Ksp of silver chromate is 8.98 * 10^-22
What is the concentration of the solution?We know that the Ksp has to do with the equilibrium constant that shows the extent to which a substance dissolves in water. We can see that the equation of the dissolution can be written for each of the reactants.
a) [tex]PbI2 (s) --- > Pb^{2+} (aq) + 2I^{-} (aq)[/tex]
Now we can see that the Ksp is obtained from;
Ksp = [[tex]Pb^{2+}[/tex]] [2[tex]I^{-}[/tex]]^2
Let the solubility be x
Ksp = 4x^3
x = ∛ 1.35 x 10^-9/4
x = 6.96 * 10^-4 M
Hence;
Concentration of lead II ions = 6.96 * 10^-4 M
Concentration of iodide ions = 6.96 * 10^-4 /2 = 3.48 * 10^-4 M
b) In order to obtain the solubility product of the silver chromate solution;
Let the solubility of each of the ions be x
We can see that;
Ksp = [3x]^3 [x]
Ksp = 3x^4
Ksp = 3(4.16 x 10^-6)^4
Ksp = 8.98 * 10^-22
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A molecule of CH four consist of blank carbon atoms in blank hydrogen atoms
The correct way of presenting the given molecule is CH₄, with the number subscripted.
The subscripted numbers indicates how many of the previous element are in the molecule.
If there are no subscripted number after a given element, it means it is a implicit 1.
So, in CH₄, there is no number after C, so it is implicit it is a 1, and after the H there are a 4. This means that we have 1 C atom and 4 H atoms.
C is carbon and H is hydrogen, so:
A molecule of CH₄ consists of 1 carbon atom and 4 hydrogen atoms.
Which of the following elements belong to the s-block of the periodic table?
The 14 elements that make up the S-block are hydrogen (H), lithium (Li), helium (He), sodium (Na), beryllium (Be), potassium (K), magnesium (Mg), rubidium (Rb), calcium (Ca), cesium (Cs), strontium (Sr), francium (Fr), barium (Ba), and radium (Ra).
S-block, what is it?The Periodic Table's s-block elements are those in which the final electron enters the most outer s-orbital. Only two groups (1 & 2) are found in the s-block of the Periodic Table because the s-orbital can only hold two electrons.
What is the s-block formula?S block elements' common outer electrical configuration is ns(1-2).
Given that it contains sodium, beryllium, magnesium, and lithium, I am rather certain that it contains alkaline metals.
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Helppppppppppppppppppp
Answer:
See my photo. I promise it's right.
A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spherical air tank that measures 75.0cm wide. The biologist estimates she will need 3700.L of air for the dive. Calculate the pressure to which this volume of air must be compressed in order to fit into the air tank.
The pressure inside a tank with a volume can be calculated using Boyle's law. The pressure needed to compress gas of 3700 L is 16.75 atm.
What is Boyle's law.According to Boyle's law the pressure of a system is inversely proportional to its volume. The mathematical expression for a system with pressure Pa and volume V1 with its final pressure and volume P2 and V2 is written as follows:
P1V1 = P2V2.
The volume of the gas is 3700 L. Assume that it is measured in the atmospheric pressure 1 atm. The width of the spherical tank is 75 cm thus its radius is 37.5 cm.
Volume of the sphere = 4/3 πr³
= 4/3 × 3.14 × (37.5)³
= 220781 cm³ = 220.78 L.
Now the law can be applied as follows:
3700 L × 1 atm = 220.78 L × P2
P2 = 3700 / 220.78
= 16.75 atm.
Hence, the pressure needed to fill the air is 16.75 atm.
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Solid calcium phosphate and aqueous sulfuric acid solution react to give calcium sulfate, which comes out of solution as a solid. The other product is phosphoric acid, which remains in solution. Write an equilibrium equation for the reaction using complete formulas for the compounds with phase labels.
Answer: i also need help on the same question :(
Explanation:
The LD50 for Allura Red ingested for rats and rabbits is 10,000 mg/kg ( 10,00,g of Allura Red consumed per kg of a rats's or rabbit's mass proves lethal for 50% of test subject). Assuming the LD50 would be about the same for humans, use the results of your experiment to calculate how many candies if consumed in quick succession by a 150-lb.person could potentially kill the person.
The amount that could cause death in a 150 pound person is 675000 mg.
What is the LD 50?We define the LD 50 as the amount of the substance that could be used to cause mortality in about 50 percent of the population that is undergoing the test. In this case, we have been told that the LD50 for Allura Red ingested for rats and rabbits is 10,000 mg/kg an now we are asked for the LD 50 in a person that has a weight of 150-lb.
The first step in the work is to convert the mass of the person from pound to kilogram from here;
Given that
1 pound = 0.45 kilo gram
150 pounds = 150 pounds * 0.45 kilo gram/1 pound
= 67.5 Kg
Now, If
10,000 mg causes mortality in 1 Kg
x mg would cause mortality in 67.5 Kg
x = 675000 mg
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