When Logan opens a new bottle of carbonated beverage, the sudden release of pressure causes the beverage to bubble up and overflow. What could Logan do in the future to prevent the next bottle from overflowing when he opens it

Answers

Answer 1

Answer:

When Logan opens a new bottle of carbonated beverage, the sudden release of pressure causes the beverage to bubble up and overflow. What could Logan do in the future to prevent the next bottle from overflowing when he opens it.

Explanation:

This is an application of Boyle's law.

According to Boyle's law:

the volume of a fixed amount of gas is inversely proportional to its pressure at a constant temperature.

[tex]V \alpha \frac{1}{P}[/tex]

So, if pressure reduces all of a sudden, the volume increases and this causes an overflow of the beverage from the bottle.

To avoid this situation, the pressure inside the bottle should not be released at once. The bottle cap should be opened slowly in such a way that opens a little and then close again open a little and then close like that many times if we do, then pressure inside the bottle goes slowly then, the volume will not increase all of a sudden.


Related Questions

Three acid samples are prepared for titration by 0.01 M NaOH:

1. Sample 1 is prepared by dissolving 0.01 mol of HCl in 50 mL of water.
2. Sample 2 is prepared by dissolving 0.01 mol of HCl in 60 mL of water.
3. Sample 3 is prepared by dissolving 0.01 mol of HCl in 70 mL of water.

a. Without performing a formal calculation, compare the concentrations of the three acid samples (rank them from highest to lowest).
b. When the titration is performed, which sample, if any, will require the largest volume of the 0.01 M NaOH for neutralization?

Answers

B is the correct answer

A) The average molecular speed in a sample of Ar gas at a certain temperature is 391 m/s. The average molecular speed in a sample of Ne gas is ______ m/s at the same temperature.
B) The rate of effusion of Xe gas through a porous barrier is observed to be 7.03×10-4 mol / h. Under the same conditions, the rate of effusion of SO2 gas would be ______ mol / h

Answers

Answer:

For A: The average molecular speed of Ne gas is 553 m/s at the same temperature.

For B: The rate of effusion of [tex]SO_2[/tex] gas is [tex]1.006\times 10^{-3}mol/hr[/tex]

Explanation:

For A:

The average molecular speed of the gas is calculated by using the formula:

[tex]V_{gas}=\sqrt{\frac{8RT}{\pi M}}[/tex]

     OR

[tex]V_{gas}\propto \sqrt{\frac{1}{M}}[/tex]

where, M is the molar mass of gas

Forming an equation for the two gases:

[tex]\frac{V_{Ar}}{V_{Ne}}=\sqrt{\frac{M_{Ne}}{M_{Ar}}}[/tex]          .....(1)

Given values:

[tex]V_{Ar}=391m/s\\M_{Ar}=40g/mol\\M_{Ne}=20g/mol[/tex]

Plugging values in equation 1:

[tex]\frac{391m/s}{V_{Ne}}=\sqrt{\frac{20}{40}}\\\\V_{Ne}=391\times \sqrt{2}=553m/s[/tex]

Hence, the average molecular speed of Ne gas is 553 m/s at the same temperature.

For B:

Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation for this follows:

[tex]Rate\propto \frac{1}{\sqrt{M}}[/tex]

Where, M is the molar mass of the gas

Forming an equation for the two gases:

[tex]\frac{Rate_{SO_2}}{Rate_{Xe}}=\sqrt{\frac{M_{Xe}}{M_{SO_2}}}[/tex]          .....(2)

Given values:

[tex]Rate_{Xe}=7.03\times 10^{-4}mol/hr\\M_{Xe}=131g/mol\\M_{SO_2}=64g/mol[/tex]

Plugging values in equation 2:

[tex]\frac{Rate_{SO_2}}{7.03\times 10^{-4}}=\sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=7.03\times 10^{-4}\times \sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=1.006\times 10^{-3}mol/hr[/tex]

Hence, the rate of effusion of [tex]SO_2[/tex] gas is [tex]1.006\times 10^{-3}mol/hr[/tex]

Guanidine is a neutral compound but is an extremely powerful base. In fact, it is almost as strong a base as a hydroxide ion. Identify which nitrogen atom in guanidine is so basic, and explain why guanidine is a much stronger base than most other amines.

Answers

Answer:

See explanation

Explanation:

The molecule called guanidine is shown in the image attached to this answer. It contains three nitrogen atoms. Two among them are sp3 hybridized while one of them is sp2 hybridized.

Guanidine is more basic than other amines because its protonanation leads to the formation of three equivalent resonance structures thereby making its protonated form quite stable. This effect is not observed in other amines.

Also, the sp2 hybridized nitrogen atom is more basic and more easily protonated because when it is protonated, three equivalent resonance structures are obtained.

If we have 1.23 mol of NaOH in solution and 0.85 mol of Cl2 gas is available to react, which one is the limiting reactant? Give your reason.​

Answers

Answer:

NaOH is the limiting reactant.

Explanation:

Hello there!

In this case, since the reaction taking place between sodium hydroxide and chlorine has is:

[tex]NaOH+Cl_2\rightarrow NaCl+NaClO+H_2O[/tex]

Which must be balanced according to the law of conservation of mass:

[tex]2NaOH+Cl_2\rightarrow NaCl+NaClO+H_2O[/tex]

Whereas there is a 2:1 mole ratio of NaOH to Cl2, which means that the moles of the former that are consumed by 0.85 moles of the latter are:

[tex]n_{NaOH}=0.85molCl_2*\frac{2molNaOH}{1molCl_2}\\\\n_{ NaOH}=1.7molNaOH[/tex]

Therefore, since we just have 1.23 moles out of 1.70 moles of NaOH, we infer this is the limiting reactant.

Regards!

The value of ΔH° for the reaction below is -6535 kJ. ________ kJ of heat are released in the combustion of 16.0 g of C6H6 (l)?

2C6H6 (l) + 15O2 (g) → 12CO2 (g) + 6H2O (l)

Answers

Answer:

the value of H° is below -6535 kj. +6H2O

Explanation:

6H2O answer solved

For the given reaction, 2 moles of C₆H₆ the heat energy released is - 6535 KJ. Then, for 16 g of the compound or 0.205 moles needs 669.83 KJ of heat released in combustion.

What is combustion ?

Combustion is a chemical reaction that occurs between a fuel and an oxidizing agent, typically oxygen, resulting in the release of heat, light, and various combustion products, such as carbon dioxide and water vapor.

The process of combustion involves a rapid and exothermic (heat-releasing) oxidation reaction that produces a flame, which is visible in many cases.

Here, 2 moles of the hydrocarbon releases - 6535 KJ of energy.

molar mass of C₆H₆ = 78 g/mol

then no.of moles in 16 g = 16 /78 = 0.205 moles.

then energy released by 0.205 moles  = 0.205 moles × 6535 KJ /2 moles = 669.83 kJ

Therefore, the heat energy released by 16 g of the compound in combustion is 669.83 kJ.

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can yall please help im very slow

Answers

Answer:

turtle

Explanation:

they are slow and they take there time

Plutonium-238 is a radioactive element that decays over time into a less harmful element at a rate of 0.8 % per year. A power plant has 50 pounds of plutonium-238 to dispose of. How much plutonium-238 will be left after 10 years

Answers

Answer:

46 pounds

Explanation:

Let the amount of Plutonium-238 left after 10 years be P

Let the initial mass of Plutonium-238 be Po

Let the rate of decay be r

Let the time taken be t

Hence;

P = Poe^-rt

P= 50e^-0.008×10

P= 46 pounds

An unknown organic compound composed of carbon, hydrogen and oxygen was analyzed and found to be 50.84% C, 8.53% H and the rest being oxygen. Which of the following represents the correct empirical formula for the compound?
(a) CH2O
(b) C3H602
(c) C4H803
(d) C2H40
(e) C5H1003

Answers

Answer:

e) C5H10O3

Explanation:

According to the information given in this question;

50.84% represents C

8.53% represents H

[100% - (50.84 + 8.53)]

= 100 - 59.37

= 40.63% of Oxygen (O)

This percentage means that;

Carbon = 50.84g

Hydrogen = 8.53g

Oxygen = 40.63g

By dividing by their respective atomic masses, we convert to moles:

C = 50.84g ÷ 12 = 4.24mol

H = 8.53g ÷ 1 = 8.53mol

O = 40.63g ÷ 16 = 2.54mol

Next we divide by the smallest no of the values (2.54mol)

C = 4.24 ÷ 2.54 = 1.669

H = 8.53 ÷ 2.54 = 3.358

O = 2.54 ÷ 2.54 = 1

To get a simple whole number ratio, we multiply the results by 3

C = 1.669 × 3 = 5.007

H = 3.358 × 3 = 10.074

O = 1 × 3 = 3

Simple whole number ratio of carbon, hydrogen and oxygen is 5:10:3. Hence, the empirical formula is C5H10O3.

A sample of titrations of 0.200 M sodium hydroxide (NaOH) being added to 30.0 mL of hydrochloric acid (HCl) of unknown concentration. Measure the volume of sodium hydroxide needed to neutralize the HCl, and calculate the concentration of the HCl.

Answers

Answer:

Assuming 20.0 mL of 0.2 M NaOH is used to neutralize 30 mL of the HCl of unknown concentration, the concentration of the hydrochloric acid is 0.133 M.

Note: The volume of NaOH used isnot given and issp to be determined by titration.

Explanation:

The question is a lab activity. Therefore, the volume of 0.2 M NaOH required for the neutralization of 30.0 mL of hydrochloric acid of unknown concentration is to be determined from titration. However, assuming a certain volume of the base is used for the complete neutralization of the acid, the concentration of the acid can be calculated.

Assuming 20.0 mL of 0.2 M NaOH is used to neutralize 30 mL of the HCl of unknown concentration, the concentration of the hydrochloric acid can be calculated thus:

Step 1: Balanced chemical equation of reaction:

HCl + NaOH ---> NaCl + H₂O

From the equation of the reaction, 1 mole of NaOH reacts with 1 mole of HCl to produce 1 mole of NaCl and water.

Step 2: Determine the number of moles of NaOH in 20.0 mL of 0.200 M solution

Molarity = number of moles/volume in Litres

Number of moles = molarity × volume in litres

Volume of NaOH in litres = 20 ml × 1 litre/1000ml = 0.02 litres

Number of moles NaOH = 0.02 L × 0.2 M = 0.004 moles

Therefore, 0.00 M of NaOH reacted with 0.004 moles of HCl

Step 3: Determine concentration of HCl

Molarity or concentration = number of moles / volume in litres

Number of moles of HCl = 0.004 moles

Volume of HCl in litres = 30.0 mL × 1 L/1000 mL = 0.03 L

Concentration of HCl = 0.004 moles / 0.03 L = 0.133 M

Therefore, assuming 20.0 mL of 0.2 M NaOH is used to neutralize 30 mL of the HCl of unknown concentration, the concentration of the hydrochloric acid is 0.133 M.

How many grams of KCl solid do I need to make 500 ml of 8% KCl solution

Answers

Answer:

40 grams of KCI are required to make 500 ml of 8% solution.

Why is the reaction between potassium (K) and chlorine (Cl) considered an oxidation-reduction reaction? (4 points) K(s) + Cl2(g) → 2KCl(s) Select one: a. Chlorine reduces in size when it reacts with potassium. b. Chlorine takes electrons from potassium in the reaction. c. Potassium reduces in strength when it bonds with chlorine. d. Potassium takes chlorine's place in the reaction.

Answers

Answer:

(b) Chlorine takes electrons from potassium in the reaction.

Explanation:

Oxidation-Reduction: A reaction in which electrons are exchanged from one substance to another, also called redox.

In K(s) + Cl2(g) → 2KCl(s) , the electrons are being exchanged between one another. In this case, Chlorine atoms are taking electrons from potassium.

you're welcome

The reaction has been termed the oxidation-reduction reaction, as Chlorine takes electrons from potassium. Thus, option C is correct.

The reaction between Chlorine and Potassium has resulted in the formation of Potassium Chloride. The reaction has been termed the ionic redox reaction.

The redox reaction can be described as the oxidation-reduction reaction in which the oxidation of an atom by the loss of electrons, results in the reduction of another atom by the gain of the electron.

In the reaction of Chlorine and Potassium, there has been the loss of electron potassium and the gain of electrons by Chlorine. Thereby Potassium is getting oxidized, and Chlorine is getting reduced.

Thus, the reaction has been termed the oxidation-reduction reaction, as Chlorine takes electrons from potassium. Thus, option C is correct.

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HELPP!
how many grams are in 1.50 x 10(24) atoms of copper?

Answers

Answer:

2266g

Explanation:

mass = no.of molecules /6.o23*1o(23) * molar mass

molar mass of co2= 44g /mol

1.5 .10^25/6.023 .10^23 =51.5 moles of co2

51.5 .44g/mol =2266 g

1 mole is equal to 6.023 × 10 ²³ molecules. 2266 grams are in 1.50 x 10²⁴ atoms of copper.

What do you mean by mole ?

The term mole is defined as the amount of substance of a system which contains as many elementary entities.

One mole of any substance is equal to 6.023 × 10²³ units of that substance such as atoms, molecules, or ions. The number 6.023 × 10²³ is called as Avogadro's number or Avogadro's constant.

The mole concept can be used to convert between mass and number of particles.

mass = number of molecules / 6.023 × 10²³ × molar mass

molar mass of CO2 = 44g /mol

1.5 .10^25 / 6.023 × 10^23

= 51.5 moles of CO2

= 51.5 .44g/mol

= 2266 g

Thus, 2266 grams are in 1.50 x 10²⁴ atoms of copper.

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To determine the freezing point depression of a LiCl solution, Toni adds 0.411 g of LiCl to the sample test tube along with 19.7 mL of distilled water. Determine the molal concentration (m) of the resulting solution. MWLiCl

Answers

Answer:

LiCl = 0.492 m

Explanation:

Molal concentration is the one that indicates the moles of solute that are contained in 1kg of solvent.

Our solute is lithium chloride, LiCl.

Our solvent is distilled water.

We do not have the mass of water, but we know the volume, so we should apply density to determine mass.

Density = mass / volume

Density . volume = mass

1 g/mL . 19.7 mL = 19.7 g

We convert g to kg → 19.7 g . 1 kg / 1000g = 0.0197 kg

Let's determine the moles of LiCl

0.411 g . 1 mol / 42.394 g = 9.69×10⁻³ moles

Molal concentration (m) = 9.69×10⁻³ mol / 0.0197 kg → 0.492 m

The molal concentration of the resulting solution is 0.492 m. The concentration number of moles of solute in one kg of solvent.

What is Molal concentration?

It is the measure of the concentration number of moles of solute in one kg of solvent.

To calculate the molal concentration first calculated the mass of [tex]\bold {LiCl}[/tex],

[tex]\rm \ mass = density \times volume[/tex]

Put the values,

m = 1 g/mL x  19.7 mL

m = 19.7 g     or

m = 0.0197 kg

Calculate the moles of LiCl:

[tex]n =\rm \dfrac { 0.411 \ g \times 1 mol }{ 42.394 \ g }\\\\n = 9.69\times 10^{-3} \ moles[/tex]

So, now the molal concentration,

[tex]m = \rm \dfrac { 9.69\times 10^{-3}\ mol} {0.0197 \ kg} \\\\m = 0.492[/tex]

Therefore, the molal concentration of the resulting solution is 0.492 m.

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How many grams in 3.75 x 1024 atoms of F?​

Answers

Answer:

96 grams

Explanation:

Which is an example of poor safety practices when working outdoors

Answers

Answer:

C

Explanation:

u can't touch a chemical with bare skin

Answer:

touching a chemical with his or her bare skin.

The information below describes a redox reaction.
Ag+ (aq) + Al(s) — Ag(s) + Al3+ (aq)
Ag+ (aq) + -> Ag(s)
Al(s)->A3+ (aq) + 3e-
What is the coefficient of silver in the final, balanced equation for this reaction?

Answers

Answer:

Al°(s)  + 3Ag⁺(aq) => Al⁺³(aq) + 3Ag(s)

Explanation:

Oxidation:                            Al°(s) =>   Al⁺³(aq) + 3e⁻

Reduction:           3Ag⁺(aq) + 3e⁻ => 3Ag°(s)

_________________________________________

Net Rxn:           Al°(s)  + 3Ag⁺(aq) => Al⁺³(aq) + 3Ag(s)

One mole of neutral aluminum atoms (Al°(s)) undergo oxidation delivering 3 moles  of electrons to 3 moles silver ions (3Ag⁺³(aq)) that are reduced to 3 moles of neutral silver atoms (3Ag°(s)) in basic standard state 25°C; 1atm.

A balanced equation obeys the law of conservation of mass. According to the law of conservation of mass, mass can neither be created nor be destroyed. The coefficient of silver is 3.

What is a balanced equation?

A balanced chemical equation can be defined as the chemical equation in which the number of reactants and products on both sides of the equation are equal. The amount of reactants and products on both sides of the equation will be equal in a balanced chemical equation.

The numbers which are used to balance the chemical equation are called the coefficients. The coefficients are the numbers which are added in front of the formula.

The balanced chemical equation for the given redox reaction is given as:

Al (s) + 3 Ag⁺ (aq)  → Al³⁺ (aq) + 3Ag (s)

Thus the coefficient of silver is 3.

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Chrysanthenone is an unsaturated ketone. If Chrysanthenone has M+ = 150 and contains 2 double bond(s) and 2 ring(s); what is its molecular formula? Enter the formula in the form CH first, then all other atoms in alphabetical order; do not use subscripts. The formula is case-sensitive.

Answers

Answer:

the Molecular formula will be; C10H14O

Explanation:

Given the data in the question;

Chrysanthenone is an unsaturated ketone,

it has M+ = 150 and contains 2 double bond(s) and 2 ring(s).

molecular formula = ?

we know that ketone contain 1 oxygen and mass of oxygen is 16

so mass of the C and H remaining will be;

⇒ 150 - 16 = 134

Now we determine the number of C atoms;

⇒ 134 / 13 = 10

hydrocarbon with 10 hydrogen atom have CnH2n+2 means

⇒ ( 10 × 2 ) +2 = 22 hydrogens

But then we have 3 unsaturation meaning 6 hydrogens less and also we have ring meaning 2 more hydrogens

⇒ 22 - 6 - 2 = 14

Hence the Molecular formula will be; C10H14O

chemistry please help​

Answers

a. Process: I think it’s the Haber Process.

b. The substance represented by the letter C is Hydrogen.

c. The conditions represented by Y and Z needed for the process are 450 degrees Celsius and 200 atm, respectively.

d. i. The catalyst used is a finely divided iron (Fe) catalyst.
ii. I think the main ore from which the catalyst is extracted is Iron.

e. Balanced chemical equation for the reaction shown in the diagram:
N2(g) + 3H2(g) ⇆ 2NH3 (g)

f. One use of Ammonia is as a fertilizer.

Write a word equation for
H2O2 + liver

Answers

Answer:

h2o2 and liver produce oxygen gas

What causes an ice cube to melt when removed from a freezer?

Answers

Answer:

the melting process begins right away because the air temperature around the ice cubes is warmer than the temperature in the freezer

The temperature in the room is higher than the temperature in the freezer, thus causing the melting state of the ice cube when it is removed from the freezer.

Gold is a precious metal that is chemically unreactive. It is used mainly in jewelry, dentistry, and electronic devices. A piece of gold ingot with a mass of 301 g has a volume of 15.6 cm3. Calculate the density of gold.

Answers

Answer:

Density = 19.3 g/cm³

Explanation:

In order to answer this question we need to keep in mind the following definition of density:

Density = Mass / Volume

As both the mass and the volume are given by the problem, we can proceed to calculate the density of gold:

Density = 301 g / 15.6 cm³Density = 19.3 g/cm³

QUESTIONS :
1.
Many of the flavours and smells of fruits are esters. A learner prepared an ester with a sme
Ilke banana in the school laboratory using pentanol and ethanoic acid. She set up the
apparatus as shown in the diagram below.
PAPER TOWEL DIPPED
-WATER BATH
IN COLD WATER
PEITANOL ETHANOIC
ACID+ 4 DROPS OF
SULPHURIC ACID
1.1 Which property of sulphuric acid makes it suitable to use as a catalyst for the
preparation of esters?
1.2 Why do we heat the test tube in a water bath and not directly over a flame?
1.3 With reference to the characteristic smells of esters, name TWO examples where
esters are used in different industries.
1.4 State ONE function of the wet paper towel in the opening of the test tube.
1.5 Write down the IUPAC name of an ester fomed.​

Answers

Answer:

See explanation

Explanation:

Esterification is a reaction that involves the combination of an alkanoic acid and an alkanol. The product is always a sweet smelling substance.

Sulphuric acid acts as a catalyst in this reaction because it is a dehydrating agent thereby pushing the equilibrium position towards the right by the removal of water molecules.

The test tubs is heated in a water bath and not directly moved the flame because the alcohol is flammable. Also heating in a water bath helps to separate the reaction mixture from the newly formed ester.

Esters are used in industries that produces soaps and perfumes. There is a great need for the use of fragrances which are ester compounds in these industries.

The wet paper towel in the opening of the test tube cools the top of the test tube. It usually serves as a kind of condenser preventing an excess loss of vapour from the reaction mixture.

The reaction of pentanol and ethanoic acid yields pentyl ethanoate according to IUPAC nomenclature.

during the process of photosynthesis, green plants produce...

Answers

Answer: photosynthesis

Explanation:

they use carbon dioxide and energy from the sun to make sugar molecules and oxygen

All bases dissociate
True or false

Answers

Answer:

verdadero

Explanation:

porque esoo [tex]\lim_{n \to \infty} a_n x_{123} \frac{x}{y} \sqrt[n]{x} x^{2} \sqrt{x} \pi \neq \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right.[/tex] 

A sample of oxygen gas occupies a volume of 2.,0cm3 at pressure of 700K pa. what will be pressure of the same sample occupies a volume of 150cm, assume temperature remains constant​

Answers

Answer:

The pressure will be 933.33 Kpa

Explanation:

Given that:

Volume V₁ = 200 cm³  (note, there is a mistake in the volume. It is supposed to be 200 cm³)

Pressure P₁ = 700 Kpa

Pressure P₂ = ??? (unknown)

Volume V₂ = 150 cm³

Temperature = constant

Using Boyle's law:

PV = constant

i.e.

P₁V₁ = P₂V₂

700 Kpa × 200 cm³ = P₂ × 150 cm³

P₂ = (700 Kpa × 200 cm³)/150 cm³

P₂ = 933.33 Kpa

Calculate the molality of each of the following solutions:
(a) 14.3 g of sucrose (C12H22O11) in 685 g of water,
(b) 7.15 moles of ethylene glycol (C2H6O2) in 3505 g of water.

Answers

Answer:

(a) The molality of this solution is 0.0613[tex]\frac{moles}{kg}[/tex]

(b)The molality of this solution is 2.04[tex]\frac{moles}{kg}[/tex]

Explanation:

The molality (m) of a solution is defined as the number of moles of solute present per kg of solvent.

The Molality of a solution is determined by the expression:

[tex]Molality=\frac{number of moles of solute}{kilograms of solvent}[/tex]

Molality is expressed in units [tex]\frac{moles}{kg}[/tex]

(a) You have 14.3 g of sucrose (C₁₂H₂₂O₁₁), the solute. With the molar mass of sucrose being 342 [tex]\frac{g}{mole}[/tex], then 14.3 grams of the compound represents the following number of moles:

[tex]14.3 grams*\frac{1 mole}{342 grams} =[/tex] 0.042 moles

Having 685 g= 0.685 kg (being 1000 g= 1 kg) of water, the solvent, molality can be calculated as:

[tex]molality=\frac{0.042 moles}{0.685 kg}[/tex]

Solving:

molality= 0.0613[tex]\frac{moles}{kg}[/tex]

The molality of this solution is 0.0613[tex]\frac{moles}{kg}[/tex]

(b) In this case you have 7.15 moles of ethylene glycol (C₂H₆O₂), the solute, in 3505 g (equal to 3.505 kg) of water, the solvent, molality can be calculated as:

[tex]molality=\frac{7.15 moles}{3.505 kg}[/tex]

Solving:

molality= 2.04[tex]\frac{moles}{kg}[/tex]

The molality of this solution is 2.04[tex]\frac{moles}{kg}[/tex]

Guys! I need a long inforation about...

"Colloidal solutions
Types of colloids
Formation of colloids"

Please! And thank you ​

Answers

A colloid is a mixture in which one substance of microscopically dispersed insoluble particles are suspended throughout another substance. However, some definitions specify that the particles must be dispersed in a liquid, and others extend the definition to include substances like aerosols and gels.

The types of colloids includes sol, emulsion, foam, and aerosol.

Sol is a colloidal suspension with solid particles in a liquid.

Emulsion is between two liquids.

Foam is formed when many gas particles are trapped in a liquid or solid.

Aerosol contains small particles of liquid or solid dispersed in a gas.

Explanation:

everything can be found in the picture

What happens to an electroscope when a negatively charged rod is brought close to the metal sphere at the top?

Answers

Answer:

When the negatively-charged rod is brought close to the electroscope, positive charges are attracted to it and negative charges are repelled away from it. The electroscope has a net neutral charge and the rubber rod has a net negative charge. If they are brought into contact, they will both take a net negative charge.

Explanation:

I looked it up

1.2.1. Name and explain the purpose of one law /legislation that protects citizens against cyberbullying ?​

Answers

Answer:

Federal law is a law that may protect people from digital attacks such as cyberbullying.

Explanation:

Although it is mostly based on the situation, federal law does protect those who suffer from cyberbullying. The attackers may be charged with defamation, since cyberbullying consists of spreading false information about someone on the internet, that's when the law comes in.

cấu hình electron của nguyên tử Ca

Answers

Explanation:

Do đó cấu hình electron của canxi là: 1s2 2s2 2p6 3s2 3p6 4s2.

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The compound sodium hydrogen sulfate is a strong electrolyte. Write the reaction when solid sodium hydrogen sulfate is put into water: which definition goes where idefk Ill give u brainlist biology teacher driving me nuts omfmsjajhahwahsn An elephant walks north from a watering hole for 1 mile. The elephantencounters a hill and turns east. The elephant continues to walk east until itreaches a tree. It stays near the tree for 1 hour before continuing on to agrassy field. Which point of reference should be used to describe theelephant's motion?A. The grassy areaB. The hillSTATelC. The treeD. The watering hole Which of these statements is NOT part of the Cell Theory?A. All living things are composed of one or more cells.B. The cell is the basic unit of life.C. All new cells arise from existing cells.D. They are all part of the Cell Theory.E. None of them are part of the Unified Cell Theory You have just signed a contract for your rental property and you will make monthly payments at the beginning of each month. Your monthly payments is $1000 and the monthly rate is 4% per month. Calculate the present value of your rental payments for the first year. a circle shown below, m AC = 89 and m BC = 153. Determine mACB. Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers. a) When x = 2 and y = 1, is Q(x, y). a. trueb. falseThe hypothesis of Q(2, 1) is__, which is___. The conclusion is___, which is____. Thus Q(2, 1) is a conditional statement with a____hypothesis and a_____conclusion. So Q(2, 1) is____. b) Give values different from those in part (a) for which Q(x, y) has the same truth value as in part. c) Give values different from those in part (c) for which Q(x, y) has the same truth values as in part. In the village where Fyokla and Danilka live, who are the people who know everything about nature? Help with math please earn 10 points An electron with a charge of -1.6 x 10-19 C experiences a force of 9.2 x 10-15 N. What is the intensity of the electric field? DNA is a A. lipidB. nucleic acidC. carbohydrateD. protein anyone know the answer to this question ? We use the tools to construct (Into Yes/No question) A flower bed is in the shape of a triangle, with a base of 11 feet and a height of 7 feet. What is the area of the flower bed?a. 38.5 square feet b. 42.5 square feet c. 72 square feet d. 77 square feet The more the lower-level personnel provide input or are actually given the discretion to make decisions, the ________ within that organization. identify the word being referred to choose your answer from the words below Which of the following statements is not true regarding North Korea under Kim Il Sung?A). The women of North Korea were given equality under the law.B). Kim Il Sung was replaced by Syngman Rhee.C). North Korea became economically successful.D). Two million acres of land were redistributed to the people. what are the step for distributive property to find the product for (a+8) (a-3)? Read the excerpt from The Dark Game.Which details in the text indicate a chronologicalstructure? Select 2 options.AbdThe first thingAlthoughThe first thing about the Zimmermann telegram that twoRoom 40 code breakers, Reverend William Montgomeryand Nigel de Grey, noticed was its length, more than athousand groups. Although the length itself was notsuspicious, it was out of the ordinary. Then de Greynoticed the top group of numbers in the message,13042, a variation of 13040, indicated a Germandiplomatic code. Since Room 40 had a copy of the13040 codebook, they began using it to decipher themessage.ThenSinceMarkedSave and ExitNextSuomi ABC was dilated to create A' B' C'. What is the center of dilation? And what is the scale factor of the dilation?