When the equation
Na +
H2O → __H, +
NaOH
is correctly balanced using the smallest whole-number coefficients, what is the coefficient for H2O?

Answers

Answer 1
The coefficient is 2.
Full equation is
2Na + 2H2O = 2NaOH + H2
Answer 2

The balanced equation is 2Na + 2H[tex]_2[/tex]O [tex]\rightarrow[/tex] 2NaOH + H[tex]_2[/tex] and the coefficient of H[tex]_2[/tex]O is 2. Stoichiometry represents the number of coefficients.

What is balanced equation?

An equation for just a chemical reaction is said to be balanced if both the reactants as well as the products have the same number of atoms and total charge for each component of the reaction. In other words, each sides of both the reaction have an equal balance of mass and charge.

It is typical that balancing chemical formulas for both charge and mass in aqueous solutions. Equal numbers and types of atoms are produced on both aspects of the equation when balancing for mass. When the charge is balanced, there is no net charge on either side of the equation.

The balanced equation can be written as

2Na + 2H[tex]_2[/tex]O = 2NaOH + H[tex]_2[/tex]

The coefficient of H[tex]_2[/tex]O is 2.

Therefore, the balanced equation is 2Na + 2H[tex]_2[/tex]O [tex]\rightarrow[/tex] 2NaOH + H[tex]_2[/tex] and the coefficient of H[tex]_2[/tex]O is 2.

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A sample of oxygen gas occupies a volume of 229.5 mL at 762.7 torr pressure. What volume in mL will it occupy at 704.5 torr pressure?

Answers

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Explanation:

In order to answer this problem we can use Boyle's law, which states that at a constant composition:

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A. 2 g/cm3
B. 0.5 g/cm
C. 5.0 g/cm3
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Answers

[tex]\large \mathfrak{Solution : }[/tex]

volume = 12 ml = 0.012 litres = 0.012 cm³

mass = 6 g

And the relationship between mass, volume and density can be depicted by :

[tex] \boxed{density = \dfrac{mass}{volume} }[/tex]

[tex]density = \dfrac{6}{0.012} [/tex]

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therefore, density = 500 g/cm³

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Answers

The answers are;
2H2+O2===>2H2O
N2+3H2==>2NH3
C3H8+5O2==>4H20+3CO2
CH4+2O2===>CO2+2H2O
2HBr +Fe==>FeBr2 +H2
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Answers

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10 moles of potassium hydroxide in 5.16 L of solution

Answers

Answer:

The molarity is 8.52M

Explanation:

molality = moles of solute/kg of solvent = 5.2mol/kg

moles of solute = 5.2mole

mass of solute = moles of solute × MW = 5.2 × 56.106 = 291.8g

mass of solvent = 1kg = 1000g

Mass of solution = mass of solute + mass of solvent = 291.8g + 1000g = 1291.8g

Density of KOH = 2120g/L

Volume of solution = mass/density = 1291.8/2120 = 0.61L

Molarity = number of moles of solute/volume of solution = 5.2/0.61 = 8.52M

The concentration in the solution is 1.94 mol/L

From the question,

We are to determine the concentration of 10 moles of potassium hydroxide in 5.16 L of solution.

From the formula

Number of moles = Concentration × Volume

Then, we can write that

[tex]Concentration = \frac{Number\ of\ moles}{Volume}[/tex]

From the question,

Number of moles of potassium hydroxide (KOH) = 10 moles

Volume of solution = 5.16 L

∴ Concentration of the solution = [tex]\frac{10}{5.16}[/tex]

Concentration of the solution = 1.94 mol/L

Hence, the concentration in the solution is 1.94 mol/L

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Here is the complete question:

Calculate the concentration in each of the following solutions:

1. 10 moles of potassium hydroxide in 5.16 L of solution

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Answer:

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Answer:

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Answers

Answer:

pH=2

Explanation:

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Answer:

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Answers


The number of protons in an atom is called its atomic number. This number is very important because it is unique for atoms of a given element. All atoms of an element have the same number of protons, and every element has a different number of protons in its atoms

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Answers

Answer:

177.1 L

Explanation:

The excersise can be solved, by the Ideal Gases Law.

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We convert T° from, C° to K → 20°C + 273 = 293K

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V = (n . R .T) / P

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Answers

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Answers

Answer:

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What is the percent composition (by mass) of MgBr2?

Answers

Answer:

13.2% Mg, 86.8% Br

Explanation:

Mg has a molar mass of 24.31g/mol.

Bromine has a molar mass of 79.90 g/mol.

There is one mole of Mg and two moles of Br in the compound:

79.90x2 + 24.31 = 184.11

So the total molar mass of MgBr2 is 184.11.

A percent tells us a part of a whole, so we will divide each part of the mass into the whole mass.

24.31g Mg / 184.11g MgBr2 = .132

159.8g Br / 184.11g MgBr2 = .868

Multiply these decimals by 100 to make them into a percent.

.132 x 100 = 13.2% Mg

.868 x 100 = 86.8% Br

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Answers

Answer:

gases

Explanation:

Answer:

the Carbondioxed and oxygen are both a gass found in the air


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Answers

Answer:

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Explanation:

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Use the Boyle's Law equation to determine the answer.

Answers

Answer:

b

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Answers

Lithium is atomic number 3, so it has valency 1

While, Bromine is atomic number 35, and has valency 1

Lithium has an extra electron while Bromine need an electron, since they both need and have one electron, the form

LiBr (Lithium Bromide) where Li is +ve charged and Br is -ve charged

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Based on what you have learned about the units for measuring thermal energy, complete the following passage.



The unit often used in chemistry and physics to measure energy, such as for work or electrical current, is the
. We can also use this unit, as we did in this lab, for measuring
. This is a property that is quantified by the energy needed per
of material to raise the temperature by one
. The unit for this measure is therefore
.

Answers

Answer:

1.joule 2.specific heat 3.gram 4.degree Celsius 5.J/g°C

Explanation:

I did the lab

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Heat capacity of a substance is the heat energy required to raise the temperature of the substance by one degree celsius.

If the heat capacity is measure per one mole of a substance it is called specific heat capacity. It is an intensive property whereas heat capacity is an extensive property.

The given passage can be completed as follows:

The unit often used in chemistry and physics to measure energy, such as for work or electrical current, is Joule (J). We can also use this unit, as we did in this lab, for measuring  heat capacity.  

This is a property that is quantified by the energy needed per one gram of material to raise the temperature by one degree celsius.The unit for this measure is therefore J/°Cg.

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