The coefficient is needed in front of NaNO3 to balance the equation is 2.
What is balanced equation?When in a chemical reaction, both the product elements or compounds should have number of moles equal to that of the elements or compounds of reactants.
In the given chemical reaction equation,
Na2S + Zn(NO3)2 → ZnS + _NaNO3
Number of moles of S is 1 on both the product and reactant side. Zn has 1 mole on both side. NO3 has 2 mole and Na has 2 mole on reactant side. So to balance the equation, Na and NO3 both must have 2 moles on product side.
Thus, the coefficient is needed in front of NaNO3 to balance the equation is 2.
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which vector has an x component with a length of 3?
Answer:
A) b.
Explanation:
all the details are in the attached picture.
When the ultrasound beam strikes the surface at or nearly at right angles, the fraction of sound energy that is reflected (R) at the interface between two materials of acoustic impedance Z1 and Z2, respectively, is given by:
Explanation:
the expression of x= -4t+2t^2 where x is displecement?Conservation efforts have been effective in _______.
a.
increasing the number of endangered species
b.
reducing all the negative impacts of human activity
c.
preserving wildlife habitats
d.
all of the above
Answer:
The answer is D. All of the above.
Explanation:
All of these were efforts and been effective.
Answer:
c
Explanation:
If 20 coulombs of charge move past a given point in 4 s, what is the current?
Answer:
5A
Explanation:
[tex]=> Current (I) = \frac{q}{t} [/tex]
Here q = 20 C and t = 4sec
=> I = 20/4 = 5A
Find the charge on the capacitor in an LRC-series circuit at t = 0.03 s when L = 0.05 h, R = 6 Ω, C = 0.005 f, E(t) = 0 V, q(0) = 4 C, and i(0) = 0 A. (Round your answer to four decimal places.)
Determine the first time at which the charge on the capacitor is equal to zero. (Round your answer to four decimal places.)
The charge on the capacitor in an LRC-series circuit is 2.8907 C.
The first time at which the charge on the capacitor is equal to zero is 0.1409s.
What is capacitor?The capacitor consists of two parallel plates used to store the charge when current flows through it, and provides energy when shuts off.
By the Kirchoff's second law,
Lq'' +Lq' +q/C =E(t)
Where, L =0.05h, R = 6 Ω, C = 0.005 f, E(t) = 0 V, q(0) = 4 C, and i(0) = 0 A.
Equations becomes q''+120q' +4000 =0
The auxiliary equation is m² +120m+4000 =0
Solving this quadratic equation, we have
m =-6± 20i
Then , q(t) = Ae^(-60t)cos 20t + Be^(-60t)sin 20t where, A and B are constants.
At t=0, q(0) =7 =A
and q'(t) = A [ -20e^(-60t)sin 20t - 60e^(-60t)cos 20t ] +B [ 20e^(-60t)cos 20t - 60e^(-60t)sin 20t ]
So, i(0)= q'(0) =0 =-60A +20 B
Putting the value of A=7 above, we have B =21.
So, q(t) = 7e^(-60t)cos 20t + 21e^(-60t)sin 20t
The charge on the capacitor at time t =0.015
q(0.015) = 2.8907 C
Thus the charge on capacitor is 2.8907 C.
q(t) = 7e^(-60t)cos 20t + 21e^(-60t)sin 20t =0
Solve for t, we get
e^(-60t)cos 20t + 3e^(-60t)sin 20t\
-1/3 = sin 20t /cos20t
t =1/20 arctan(-1/3)
As, arctan is defined within -90 to +90,
So, 20t = -0.3218 +π =2.8197
t =0.1409s
Thus the first time at which the charge is zero is 0.1409s.
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Before Schwarzschild, the understanding of relativity to gravitational force was unknown.
t or f
Answer:
False
Explanation:
Help
Light helps you in so many ways. But, if it is not used properly, it can also be harmful to you. How can you use light safely? Provide at least five (5) ways how you will protect yourself from light energy.
Determine the CM of the uniform thin L-shaped construction brace shown in (Figure 1) . Suppose that a = 2.20 m and b = 1.63 m Determine the x coordinate of the CM
By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is [tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex] meters.
How to determine the coordinates of the center of mass of a compound figure
Let suppose that the entire construction has a uniform mass, then the coordinates of the center of mass can be determined by definition of weighted average:
[tex]\bar x = \frac{\sum \limits_{i = 1}^{n}x_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}[/tex] (1)
[tex]\bar y = \frac{\sum \limits_{i = 1}^{n}y_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}[/tex] (2)
If we know that a = 2.20 m and b = 1.63 m, then the x-coordinates of the center of mass of the compound figure is:
[tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex]
By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is [tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex] meters.
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a toy car needs a source of energy to move. how could you give gravitational potential energy to a toy car so that it will move when you let it go?
Answer:
wait one second im about to go get some milk im thirsty
Explanation:
do you want any chicken on your salad
When you are making cold calls while job hunting, be
o 20 minutes early
O on time
O prepared with a résumé and cover letter
O casual
Answer:
The answer is O prepared with a résumé and cover letter
Explanation:
That will get you very far if you are prepared with a résumé and cover letter
The horizontal surface on which the block slides is frictionless. The speed of the block before it touches the spring is 5.0 m/s. How fast is the block moving at the instant the spring has been compressed 15 cm? The spring constant k = 2000 N/m.
The block moving at instant the spring is compressed 15cm is √[(25m - 45)/m]
What is conservation of energy principle?When there is no external force acting on the system, the total mechanical energy remains conserved.
K.E i = K.E f + SPE
1/2 mu² =1/2 mv² + 1/2 kx²
Substitute u = 5m/s, k =2000N.m and x =0.15m, we get the final velocity
1/2 mu² =1/2 mv² + 1/2 kx²
v =√[(25m - 45)/m]
Thus, the block moving at the instant the spring has been compressed 15 cm is √[(25m - 45)/m]
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The Venus flytrap is known for which of these behaviors?
closing its flower buds at night
snapping a leaf shut around an insect
closing its leaves when touched by a finger
screeching when in danger
calculate the work done 36 kg boxes lifted onto a shelf 1.5 m high
Answer:
529.2 joules
Explanation:
Work done = force x distance = mass x gravity x distance
= 36x9.8 x1.5 =529.2 joules

Which of the following is a physical change?
sawing a piece of wood in half
O burning a piece of wood
O a copper statue turning from red to green
Orust forming on an iron fence
Answer:
I think its 'sawing a piece of wood in half'
Explanation:
sry if its wrong
Vhat are you looking for when you research a potential employer?
personal information about the managers
company history
related industry news
what its product or service is
pleaseeee help mehhhh
a car weighting, 14500 N skids on ice, which has a kinetic coefficient of friction 0.2. It then hits a patch of dry road area which has a Kinetic coefficient of friction of 0.8. What is the change in friction force experienced by the car?
The change in friction force experienced by the car is
What is friction?The friction is caused between two uneven contacting surfaces.
When car is on ice, the friction force is
f = μ N
f₁ = 0.2 x 14500 = 2900N
When the car is on dry road, the friction force is
f₂ = 0.8 x 14500 =11,600 N
The change in friction force =11600 - 2900 = 8700N
Thus, the change in friction force experienced by the car is 8700N.
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.......................................
.
Explanation:
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Using the formula below, determine how
many seconds it would take for a satellite
traveling at 4 miles per second to travel
11,000 miles across the Pacific Ocean.
speed=
A 27.5 seconds
B 45 seconds
C 2,750 seconds
D 3,000 seconds
BRAINLIEST IF ITS CORRECT HEPL
Answer: C.
Explanation: They describe the direction of the magnetic force on a north monopole at any given position.
What is the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b?
The energy emitted by a photon when it falls from level f to energy level b is 2.84 eV.
Energy of photon at level f and level b
The energy of a photon at level F is given as -268 eV and the energy photon at level b is given as -5.52 eV.
Energy emitted by a photon when it falls from level f to energy level b is calculated as follows;
ΔE = -2.68 eV - (-5.52 eV)
ΔE = -2.68 eV + 5.52 eV
ΔE = 2.84 eV
Thus, the energy emitted by a photon when it falls from level f to energy level b is 2.84 eV.
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Why is nuclear energy able to be used for practical purposes? the reactions are controlled to regulate energy output. the reactions are uncontrolled for maximum energy output. all of the products are fed back into the reaction to keep it going. all of the products are immediately removed to inhibit more reactions.
Nuclear energy is able to be used for practical purposes because ; ( A ) The reactions are controlled to regulate energy output
Nuclear energy generationNuclear energy is a clean energy source which has a zero-emission, nuclear energy is used to generate electricity/power following a controlled reaction known as fission of uranium atoms to produce heat energy required to drive a turbine to produce electricity
Hence we can conclude that Nuclear energy is able to be used for practical purposes because ; ( A ) The reactions are controlled to regulate energy output.
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Answer:
option A
Explanation:
A metallic axle with a diameter of 20mm has to be fitted into a wheel which has a circular hole at its center with diameter of 18.5mm
The coefficient of linear expansion of the metal at the given length is determined as 3.75 x 10⁻⁴/⁰C.
Coefficient of linear expansion of the metalThe coeffcient of linear expansion of the metal is calculated as follows;
ΔL = αLΔT
α = ΔL/LΔT
Where;
α is the coefficient of linear expansionΔL is change in length = 20 mm - 18.5 mm = 1.5 mmΔT is change in temperature = 0 - (-200) = 200°CL is the original length = 20 mmα = (1.5)/(20 x 200)
α = 3.75 x 10⁻⁴/⁰C
The complete question is below:
A metallic axle with a diameter of 20mm has to be fitted into a wheel which has a circular hole at its center with diameter of 18.5mm. To fit the axle into the hole, the axle is dipped into liquid nitrogen at a temperature of -200°C. Calculate the coefficient of linear expansion of the metal.
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Please help!! Look at pic
Answer:
Explanation:
Voltage and Current relation is given by V=IR
I=9A
R=4Ohm
V=IR
V=9x4=36Volts
Resistance = 4 Ohm
Current = 9 Ampere
Voltage = 36 Volts
HELP MEEE!!!!!!!!!
A series circuit is made up of a battery and 4 Resistors.
The Resistors are:
R1 = 10 ohms
R2 = 20 ohms
R3= 5 ohms
R4= 10 ohms
What is the total resistance in the circuit is...
ohms
A satellite with a mass of 150 kg fires its engines to increase velocity, thereby
increasing the size of its orbit about Earth. As a result, it moves from a
circular orbit of radius 7.5 x 106 m to an orbit of radius 7.7 x 106 m. What is
the approximate change in gravitational force from Earth as a result of this
change in the satellite's orbit? (Recall that Earth has a mass of 5.97 x 1024 kg
and G = 6.67 x 10-11 N-m²/kg².)
OA. -113 N
OB. -148 N
O C. -216 N
D. -54 N
The approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is 5. 35N
What is the universal law of gravitation?The universal law of gravitation states that the particle of matter in the universe attracts another particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
It is written thus;
F = G MIM2÷ r∧2
Where
F = Gravitational force
G = Gravitational constant
M1 and M2 are the masses of the object
r = radius
How to calculate the gravitational forceFormula:
F = G MIM2 ÷ r∧2
Given M1 = 150kg, M2 = 5.97 x 1024 kg, r = 7.5 x 106 m, G = 6.67 x 10-11 N-m²/kg²
For the first orbit, substitute the values
F = 6.67 x 10∧-11 × 150 × 5.97 x 10∧24 ÷ (7.5 x 10∧6)²
F = 5.95 × 10∧16 ÷ 56.25 × 10∧12 = 105.77 N
For the second orbit of radius 7.7 x 106 m
F = 6.67 x 10∧-11 × 150 × 5.97 x 10∧24 ÷ (7.7 x 10∧6)²
F = 5.95 × 10∧16 ÷ 59.25 × 10∧12 = 100. 42 N
The approximate change = 105. 77 - 100.42 = 5. 35N
Hence, the approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is 5. 35N
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What kind of object are the light rays interacting with in the model below?
Convex mirror
Convex lens
Concave mirror
Concave lens
Answer:
Concave lens
.............
A copper atom has an atomic number of 29 and an atomic mass of 64. What
is the structure of this atom?
OA. It has a central nucleus composed of 29 protons and 64 neutrons,
surrounded by an electron cloud containing 29 electrons.
B. It has a central nucleus composed of 29 protons and 35 neutrons,
surrounded by an electron cloud containing 29 electrons.
OC. It has a central nucleus composed of 29 protons and 29 neutrons,
surrounded by an electron cloud containing 35 electrons.
D. It has a central nucleus composed of 35 protons and 29 neutrons,
surrounded by an electron cloud containing 29 electrons.
Answer:
It has a central nucleus composed of 29 protons and 35 neutrons, surrounded by an electron cloud containing 29 electrons
Explanation:
Atoms Composition:
A atom is mainly composed of a centrally-placed nucleus. A nucleus consists of protons and neutrons with a cloud of electrons surrounding the outside. A proton is a nuclear particle having a positive charge equal to that of an electron and a mass more than 1800 times the electron. A neutron is a nuclear particle having a mass almost identical to that of an electron, but no electric charge.Calculation:
Mass number = Proton + Neutron64 = 29 + NeutronCollect like termsNeutron = 64 – 29Neutron = 35when an Earthquake occurs energy radiates in all direction from its source called the
Answer:
[tex]\huge\boxed{\sf Focus}[/tex]
Explanation:
Focus:The point at which Earthquake occurs is called Focus.It is also called hypocenter.Epicenter:Epicenter is the point on the Earth surface which is just above the focus.Most of the times, epicenter is confused with focus. However, epicenter lies on the Earth surface and focus is the exact point from where the Earthquake originates.
[tex]\rule[225]{225}{2}[/tex]
The magnetic field lines of a bar magnet spread out from the
A. north end to the south end.
B. south end to the north end.
C. edges to the center.
D. center to the edges.
Answer:
I think the letter B. But I'm not sure pero I try mo Lang po baka Yan po ang tamang sagot kac Yan po Yung nilagay na sagot saakin e Kaya try mo Lang po