Which equation can we use to find the length of the side labeled x?

Answer:

x = 67 *272    = 364.48 = 364 (rounded as requested).  

Step-by-step explanation:

Use the proportion

   50 = 272  

    67      x

Number line equality to -5< =< -1

The area of the walkway that is painted with the 12 arrows will be 840 cm². Then the correct option is C.

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

This figure represents an arrow painted on a walkway 12 times.

The figure is given below.

The figure is the combination of a triangle and a rectangle. Then the area of the figure will be

Area = 1/2 x 8 x 5 + 10 x 5

Area = 20 + 50

Area = 70 cm²

Then the area of the walkway that is painted with the 12 arrows will be

Area of the walkway = 70 x 12

Area of the walkway = 840 cm²

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Answer:

3:2.

Step-by-step explanation:

They have 15 - 6 = 9 problems to do, so it is:

9:6

= 3:2.

Answer:

9/15

Step-by-step explanation:

15 - 6 = 9 as a fraction would be 9 meaning what is left and 15 as meaning how much they started with so it is 9/15 also called 9 over 15

Hope This Helped

Answer: 12

Step By Step Explanation:

Answer:

except c all

Step-by-step explanation:

because

5(2+4)=10+20

30=30

9(3+2)=27+18

45=45

2(5+6)=10+12

22=22

Answer:

except c all

Step-by-step explanation:

because

5(2+4)=10+20

30=30

9(3+2)=27+18

45=45

2(5+6)=10+12

22=22

Answer:

  A.  200 packages

Step-by-step explanation:

The number of packages per roll can be found by dividing the length of a roll by the length of tape needed for each package.

__

For each package:

  (2.375 in/piece)×(4 piece/package) = 9.5 in/package

Per roll:

  (1900 in/roll) / (9.5 in/package) = (1900/9.5) packages/roll

  = 200 packages/roll

The machine can seal 200 packages with a roll of tape 1900 inches long.

Then the two solutions of the quadratic equation are 4/5 and 3.

Here we want to solve the quadratic equation:

(-5x + 4)*(x - 3) = 0

The two solutions are the values of x for which each parenthesis becomes equal to zero, so the two solutions are given by:

-5x + 4 = 0

x - 3 = 0

If we solve these two equations we get:

x = -4/-5 = 4/5

x = 3

Then the two solutions are 4/5 and 3.

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Answer:

17.2 is 17.2 units to the right of zero on the number line.

Step-by-step explanation:

On a number line positive numbers are on the right of 0 and negative numbers are one the left of 0.

Please mark brainliest :)

Answer: Right

Step-by-step explanation:

    All positive numbers are to the right of zero on the number line.

   All negative numbers are to the left of zero on the number line.

        17.2 is a positive number, so;

17.2 is 17.2 units to the (right/left) of zero on the number line.

Answer:

yo dude dont be upset im doing what you did lol!

The proofing of Fermat's last theorem shows that y = a² - b², z = a² + b² and x = 2ab.

The equation x² + y² = z². We can assume that x, y, and z are positive and relatively prime. Suppose that x is even. Then:

(z - y/2)(z + y/2) = (x/2)²

Hence,

(z - y)/2 = b²

(z + y)/2 = a²

Then, y = a² - b², z = a² + b² and x = 2ab.

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Answer:

[tex]\displaystyle \int {x^{-11}(1 + x^4)^\Big{- \frac{1}{2}}} \, dx = \boxed{ - \frac{\sqrt{x^4 + 1} (8x^8 - 4x^4 + 3)}{30x^{10}} + C }[/tex]

General Formulas and Concepts:

Calculus

Differentiation

Derivative Rule [Basic Power Rule]:

Integration

Integration Rule [Reverse Power Rule]:
[tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Multiplied Constant]:
[tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:
[tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Methods: U-Substitution, U-Solve, Trigonometric Substitution

Step-by-step explanation:

*Note:

The problem is too big to fit all work. I will assume that you know how to do basic calculus.

Step 1: Define

Identify given.

[tex]\displaystyle \int {x^{-11}(1 + x^4)^\Big{- \frac{1}{2}}} \, dx[/tex]

Step 2: Integrate Pt. 1

Step 3: Integrate Pt. 2

Identify variables for u-substitution/u-solve.

Step 4: Integrate Pt. 3

Start solving the integral using u-solve:

[tex]\displaystyle \begin{aligned}\int {x^{-11}(1 + x^4)^\Big{- \frac{1}{2}}} \, dx & = \int {\frac{1}{x^{11}\sqrt{x^4 + 1}}} \, dx \\& = \int {\frac{1}{2u^6 \sqrt{u^2 + 1}}} \, du \\& = \frac{1}{2} \int {\frac{1}{u^6 \sqrt{u^2 + 1}}} \, du \\\end{aligned}[/tex]

Step 5: Integrate Pt. 4

Identify variables for trigonometric substitution.

Step 6: Integrate Pt. 5

Let's focus on just the integral itself. Apply the Trigonometric Substitution Integration Method and other basic integration techniques listed under "Calculus":

[tex]\displaystyle \begin{aligned}\int {\frac{1}{u^6 \sqrt{u^2 + 1} }} \, du & = \int {\frac{\sec^2 v}{\tan^6 v \sqrt{\tan^2 v + 1} }} \, dv \\& = \int {\frac{\sec v}{\tan^6 v}} \, dv \\& = \int {\cot v \csc v (\csc^2 v - 1)^2} \, dv \\\end{aligned}[/tex]

Step 7: Integrate Pt. 6

Identify variables for u-substitution/u-solve again.

Use another variable besides u to avoid confusion with earlier substitutions:

Step 8: Integrate Pt. 7

Reduce the integral using the U-Solve Integration Method and other basic integration techniques listed under "Calculus":

[tex]\displaystyle \begin{aligned}\int {\frac{1}{u^6 \sqrt{u^2 + 1} }} \, du & = \int {\frac{\sec^2 v}{\tan^6 v \sqrt{\tan^2 v + 1} }} \, dv \\& = \int {\frac{\sec v}{\tan^6 v}} \, dv \\& = \int {\cot v \csc v (\csc^2 v - 1)^2} \, dv \\& = \int {-(w^2 - 1)^2} \, dw \\& = - \int {(w^2 - 1)^2} \, dw \\& = - \int {\bigg( w^4 - 2w^2 + 1 \bigg)} \, dw \\\end{aligned}[/tex]

Step 9: Integrate Pt. 8

Solve the integral using basic integration techniques listed under "Calculus":

[tex]\displaystyle\begin{aligned}- \int {\bigg( w^4 - 2w^2 + 1 \bigg)} \, dw & = - \Bigg[ \int {w^4} \, dx - \int {2w^2} \, dx + \int {} \, dx \Bigg] \\& = - \Bigg[ \int {w^4} \, dx - 2 \int {w^2} \, dx + \int {} \, dx \Bigg] \\& = - \Bigg[ \frac{w^5}{5} - \frac{2w^3}{3} + w + C \Bigg] \\& = - \frac{w^5}{5} + \frac{2w^3}{3} - w + C \\& = - \frac{\csc^5 v}{5} + \frac{2\csc^3 v}{3} - \csc v + C \\\end{aligned}[/tex]

[tex]\displaystyle\begin{aligned}- \int {\bigg( w^4 - 2w^2 + 1 \bigg)} \, dw & = - \frac{(u^2 + 1)^\Big{\frac{5}{2}}}{5u^5} + \frac{2(u^2 + 1)^\Big{\frac{3}{2}}}{3u^3} - \frac{\sqrt{u^2 + 1}}{u} + C \\\end{aligned}[/tex]

Step 10: Integrate Pt. 9

Let's substitute our integral value into our integral from "Step 4":

[tex]\displaystyle\begin{aligned}\frac{1}{2} \int {\frac{1}{u^6 \sqrt{u^2 + 1}}} \, du & = - \frac{(u^2 + 1)^\Big{\frac{5}{2}}}{10u^5} + \frac{(u^2 + 1)^\Big{\frac{3}{2}}}{3u^3} - \frac{\sqrt{u^2 + 1}}{2u} + C \\& = - \frac{(x^4 + 1)^\Big{\frac{5}{2}}}{10x^{10}} + \frac{(x^4 + 1)^\Big{\frac{3}{2}}}{3x^6} - \frac{\sqrt{x^4 + 1}}{2x^2} + C \\& = \boxed{ - \frac{\sqrt{x^4 + 1}(8x^8 - 4x^4 + 3)}{30x^{10}} + C } \\\end{aligned}[/tex]

∴ we have found the indefinite integral.

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Topic: Calculus

Answer:

First Number=9

Second number=18

Third Number=72

Step-by-step explanation:

let's take the first number as X

X+(9+X)+[4(9+X)]=99

X+9+X+36+4=99

6X=99-45

X=54/6

X=9

Answer:

Step-by-step explanation:

Given :

f(x) = x − 3

g(x) = x² − x

Note : (f+g)(x) = f(x) + g(x)

then

(f+g)(2) = f(2) + g(2)

           = (2 - 3) + (2² - 2)

           = -1  +  2

           = 1

another method:

(f+g)(x) = f(x) + g(x) =  x − 3 + x² − x = x² - 3

then

(f+g)(2) = 2² - 3 = 4 - 3 = 1

Answer:

32

Step-by-step explanation:

4 ÷ 1/8

make 4 into a fraction

4/1 ÷ 1/8

when dividing a fraction you change the divide into multiply and you flip the second fraction:

4/1 × 8/1 = 32

Answer:

32

Step-by-step explanation:

1/8 = 1 / 8 = 0.125        4 / 0.125 = 32

mad skillz gl cheating on your I-ready test

Answer:

∠ AOC = 124°

Step-by-step explanation:

the 3 angles lie on a straight line and sum to 180°

sum the 3 angles and equate to 180

3x + 94 + x + 30 + 2x - 4 = 180

6x + 120 = 180 ( subtract 120 from both sides )

6x = 60 ( divide both sides by 6 )

x = 10

Then

∠ AOC = 3x + 94 = 3(10) + 94 = 30 + 94 = 124°

Elena should go to the south market because there is 0.52 probability of both cherries and asparagus being available.

The table is given as:

                   North market     South market

Cherries          0.96                   0.8

Asparagus       0.5                   0.65

The probability of buying both produce at both markets is calculated as:

P(North) = 0.96 * 0.5 = 0.48

P(South) = 0.8 * 0.65 = 0.52

0.52 is greater than 0.48

Hence, Elena should go to the south market because there is 0.52 probability of both cherries and asparagus being available.

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Answer:

42 sq ft.

Step-by-step explanation:

[tex]A=w *l[/tex]

[tex]A=14 *3=42[/tex]

=42 sq ft

(note: i dont think it matters how you put the numbers, they still mulitply up to 42)

Hope this helped

~rere

Answer:

[tex]x \leqslant 4[/tex]

Goodluck

Step-by-step explanation:

X is smaller than or equal to 4

Answer:

B I just got that question it was B

Answer:f^8

Step-by-step explanation:

F^7 multiplied by F^1 =f (7+6+1)= f^8F

Answer:

B. light

Step-by-step explanation:

When specific frequencies of light are absorbed by a material, it forms an absorption spectrum.

Answer:

  C = 25°, b = 62.3, c = 32.1

Step-by-step explanation:

The Law of Sines can be used to solve a triangle when two angles and a side opposite one of them is given.

__

The angle sum theorem can be used to find the third angle.

  C = 180° -A -B = 180° -30° -125° = 25°

__

The Law of Sines tells you ...

  a/sin(A) = b/sin(B) = c/sin(C)

  b = a(sin(B)/sin(A)) = 38·sin(125°)/sin(30°) ≈ 62.3

  c = a(sin(C)/sin(A)) = 38·sin(25°)/sin(30°) ≈ 32.1

The solution is ...

  C = 25°, b = 62.3, c = 32.1

Answer:

f^-1(x)=[tex]\sqrt[3]{x-3}[/tex]