Which expression is equivalent to startfraction (2 m n) superscript 4 baseline over 6 m superscript negative 3 baseline n superscript negative 2 baseline endfraction? assume m not-equals 0, n not-equals 0.

The only plane shape in which every point on the figure is the exact same distance from the center is; The Circle

There are different types of plane shapes such as Square, rectangle, Circle, Trapezoid, Parallelogram, Rhombus, Kite, Triangle e.t.c.

Now, Except for the circle and Triangle, every other listed plane shape above is a quadrilateral because they have 4 sides. Now, no quadrilateral has all its' sides equal from the center. Likewise, no triangle has all its' sides equal from the center.

The only plane shape with all its' sides equal from the center is the circle because the radius is equal all through.

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Answer:

[tex]\boxed{\sf \dfrac{14}{95}}[/tex]

Explanation:

Black ribbons = 8 ribbons

Green ribbons = 12 ribbons

Total ribbons: 12 + 8 = 20 ribbons

[tex]\sf Probability = \dfrac{Favorable \ Outcomes}{Total \ Possible \ Outcomes}[/tex]

For Lila:

[tex]\sf Lila \ picks \ black \ : \ \dfrac{8}{20}[/tex]

Left black ribbons: 8 - 1 = 7 black ribbons

Left total ribbons: 20 -1 = 19 total ribbons

For Jessica:

[tex]\sf Jessica \ picks \ black \ : \ \dfrac{7}{19}[/tex]

Probability that they both pick black ribbons:

[tex]\sf \rightarrow \dfrac{8}{20} \ x \ \dfrac{7}{19}[/tex]

[tex]\sf \rightarrow \dfrac{14}{95}[/tex]

Answer:

Step-by-step explanation:

Answer:

i agree with the other anwser!!

Step-by-step explanation:

An expression is defined as a set of numbers, variables, and mathematical operations. The solution of the division of x³y by x⁴y is equal to 1/x.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The division of x³y by x⁴y can be done as,

x³y/x⁴y

= x⁽³⁻⁴⁾ y⁽¹⁻¹⁾

= x⁻¹

= 1/x

Hence, the solution of the division of x³y by x⁴y is equal to 1/x.

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Expand 13 as 10 + 3.

10 = 2×5, so

13 = 2×5 + 3×1

or

13 = 2×5¹ + 3×5⁰ = 23₅

Answer:

1/2 this is the correct answer to the question

Answer:

question is not correct

Step-by-step explanation:

3(x+2)=11+3x+5

3x+6=11+3x+5, once 3x is subjected from both sides it becomes unsolvable

Answer: Infinite solution

Step-by-step explanation: 3x + 6 = 11 + 3x - 5

                                             -3x

6 = 11 - 5

6 = 6

Answer:

Step-by-step explanation:

9x-2=4x+9

1. 9x-4x-2=4x-4x+9 always isolate a variable which means move 4x to the other side to get 9 by its self.

2. 5x-2+2=9+2

3. 5x=11

4. 5x/5=11/5 get x by itself.

5. x=2.2

check work.

9(2.2)-2=4(2.2)+9

17.8=17.8

Answer:

4^5

Step-by-step explanation:

When we are multiplying expressions with the same base, we add the exponents

a^b * a^c = a^(b+c)

4^2 * 4^3 = 4^(2+3) = 4^5

The interquartile range = upper quartile - lower quartile = 18 - 15 = 3 (option A).

The interquartile range (IQR) of a data = upper quartile - lower quartile.

In the box-and-whisker plot given:

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Answer:

1. Find the prime factorization of each number.

2. Write each number as a product of primes, matching primes vertically when possible.

3. Bring down the same numbers in each column and the remaining numbers in each column.

4. Multiply the factors to get the LCM.

for example the lcm of 24 and 36

= 24 = (2 × 2 × 2 × 3) = 2^3 × 3^1

 and 36 = (2 × 2 × 3 × 3) = 2^2 × 3^2

LCM(24, 36) = 2^2 × 3 × 2 × = 72

i hope my answer was helpful and please mark me as brainliest

The measure of each angle is 43.25 and 46.75

The attached image represents the missing piece in the question.

From the image, we can see that:

3x - 13 + 5x - 47 = 90 ---- complementary angles

Evaluate the like terms

8x = 150

Divide by 8

x = 18.75

Substitute x = 18.75 in the given angles

3x-13 = 3 * 18,75 - 13 = 43.25

5x -47 = 5 * 18.75 - 47 = 46.75

Hence, the measure of each angle is 43.25 and 46.75

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The answer is C.

Step-by-step explanation:

I can't explain but I literally just did this question and I got it right

The answer will be option D which is to Assign the homework questions the numbers 0–9. Use a random number table to select the first three unique numbers between 0 and 9.

Randomization allows a sample or small groups with similar characteristics to determine a probability or to hypothesize an event, that is why this type of sample is important in an experiment, that is, to carry it out in a random way.

Given that:-

A teacher assigns 10 questions for homework and wants to randomly pick 3 questions to be graded.

Assign the homework questions the numbers 0–9. Use a random number table to select the first three unique numbers between 0 and 9. These represent the questions that will be graded.

Hence the answer will be option D which is to Assign the homework questions to the numbers 0–9. Use a random number table to select the first three unique numbers between 0 and 9.

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Answer: 1 What???

Step-by-step explanation:

Since Sally replaces the card after each draw, there are 52 choices for each card that can be drawn.

In a standard deck of cards, there are 4 aces. Then the probability of drawing an ace is 4/52 = 1/13. The same reasoning applies to drawing a queen or a six. Then the probability of drawing an ace, queen, and six (in that particular order) is 1/13³.

But Sally can also draw these 3 specific cards in any order to end up with the same hand. There are 3! = 6 ways of doing so:

AQ6, A6Q, QA6, Q6A, 6AQ, 6QA

That is, 3 choices for the first card; 2 choices for the second; and 1 for the third, so a total of 3 • 2 • 1 = 3! = 6 hands.

Then the probability of getting a hand consisting of an ace, queen, and six is

3! • 1/13³ = 6/2197 ≈ 0.002731

Answer:

See below ~

Step-by-step explanation:

Perimeter

Area

The relative frequency table is:

Class         Frequency  Relative frequency

40 - 50         4                     0.1

50 - 60          6                     0.15

60 - 70           11                     0.18

70 - 80            9                     0.23

80 - 90              7                    0.18

90 - 100             3                   0.08

The relative frequency measures how often a value appears relative to the sum of the total values. The class width is 10. The class width is the difference between the upper and lower boundary (e.g. 100 - 90).

Frequency is the number of times the numbers in the class interval appear in the data set. Relative frequency is the frequency of a class interval divided by the total frequency of the data set.

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Answer:

the answer will be 1 7/3 I believe

The distribution of y is [tex]P(y) = ^5C_y * (60\%)^y * (1 - 60\%)^{5-y}[/tex]

The given parameters are:

Probability of success, p = 60%

Sample size, n = 5

The distribution of y is represented as:

[tex]P(y) = ^nC_y * p^y * (1 - p)^{n-y}[/tex]

So, we have:

[tex]P(y) = ^5C_y * (60\%)^y * (1 - 60\%)^{5-y}[/tex]

Hence, the distribution of y is [tex]P(y) = ^5C_y * (60\%)^y * (1 - 60\%)^{5-y}[/tex]

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Answer:

52

Step-by-step explanation:

[tex]\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}[/tex]

Given expression ,

[tex] \frac{1}{8} . \frac{1}{8} .y.y.y \\ [/tex]

this can also be written as ,

[tex] \frac{1}{8} \times \frac{1}{8} \times y \times y \times y \\ \\ \longrightarrow \: \frac{y {}^{3} }{64} [/tex]

hope helpful ~

Answer:

P(king or diamond) = P(king) + P(diamond) - P(king and diamond) P(king or diamond) = (4/52) + (13/52) - (1/52) P(king or diamond) = 16/52 Page 5 P(king or diamond) = 4/13.