Which feature of a balanced chemical equation demonstrates the law of
conservation of mass?
O A. It has the same types of atoms on both sides of the reaction
arrow.
O B. It shows the reactants of a chemical reaction to the left of the
reaction arrow.
O C. It has coefficients to show how much of each substance a
chemical reaction uses.
Thing
D. It shows the products of a chemical reaction to the right of the
reaction arrow.

Answers

Answer 1

Answer:  A) It has the same types of atoms on both sides of the reaction

arrow.

Explanation:  A balanced equation demonstrates the conservation of mass by having the same number of each type of atom on both sides of the arrow.


Related Questions

In order to create a charged object, you need to ________.

Answers

In order to create a charged object you need to transfer electrons either away or to the object by induction, conduction, or friction

Induction is without contact(like bringing a charged object to a electroscope charges the leaves at the bottom)
Conduction is with contact(like the previous answer, wore touching transfers the charge from a source to the object)
Friction(rubbing a balloon on wool)

Colloid - well ______ together but not ______________

Answers

Answer:Colloid - well compacted together but not one

20 . A car of mass 2000 kg is moving with a constant velocity of 10 m/s due east. What is the momentum of the car

Answers

Answer:

P=mv

Explanation:

m = 2000kg

v = 10m/s

2000×10=20000

Answer: 2000kgm/s

The momentum will be =  2 * [tex]10^{4}[/tex] kg m/s

What is momentum ?

Momentum is a property of a moving body that the body has by virtue of its mass and motion and that is equal to the product of the body's mass and velocity

momentum = mass * velocity

mass = 2000 kg

velocity = 10 m/s

momentum = 2000 * 10 = 2 * [tex]10^{4}[/tex] kg m/s

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A spring in a dart gun is compresscht a distance of 0.05 m. The spring has a spring constant
of 1,115 N/m. If the dart has a mass of 0.025 kg, determine the velocity of the dart as it
leaves the dart gun.

Answers

Answer:

Explanation:

ASSUMING that the dart is fired horizontally so that gravity potential energy considerations are not needed. Also ignoring friction work.

The spring potential will convert to kinetic.

KE = PS

½mv² = ½kx²

     v = [tex]\sqrt{kx^2/m}[/tex]

     v = [tex]\sqrt{1115(0.05^2)/0.025}[/tex]

     v = 10.55935...

     v = 11 m/s

There is a bell at the top of a tower that is 45 m high. The bell weighs 15 kg. The bell has energy. Calculate it.

Answers

Answer:

6621.75J

Explanation:

In this case, the bell is not in motion. So we are going to calculate its potential energy rather than its kinetic energy since kinetic energy is the energy a body possesses in motion.

The formula for the potential energy is m*g*h, meaning the mass * acceleration due to gravity * height. Here the mass, m = 15kg, the acceleration due to gravity = 9.81m/s^2, and the height, h = 45m

Substituting our values, the answer becomes 15 * 9.81 * 45 = 6621.75J. Hope you understood my explanation?

The density of water is 1000 kg/m the pressure pf water at 10 m depth is about

Answers

Answer:

pressure in liquids is given as:

P= hpg

where h is the depth

where p is the density

where g is 10

Explanation:

From the formula above

p = 10 X 1000 X 10

p = 100000N/m

What is the approximate value of k when 30 = e^5k?

Answers

Answer:

Explanation:

30 = e^5k

ln30 = lne^5k

ln30 = 5k

k = ln30/5

k = 0.68023947...

round to your heart's content.


A 12-kg block on a horizontal frictionless surface is attached to a light
spring (force constant = 0.80 kN/m). The block is initially at rest at its
equilibrium position when a force (magnitude P = 80 N) acting parallel to
the surface is applied to the block, as shown. What is the speed of the
block when it is 13 cm from its equilibrium position?"


Answers

The speed of the block at the displacement from the equilibrium position is 1.062 m/s.

The given parameters:

Mass of the block, m = 12 kgSpring constant, k = 0.8 kN/mExtension of the spring, x = 13 cm = 0.13 mApplied parallel force, F = 80 N

The speed of the block is calculated by applying the principle of conservation of mechanical energy as shown below;

[tex]\frac{1}{2} mv^2 = \frac{1}{2}kx^2\\\\mv^2 = kx^2\\\\v^2 = \frac{kx^2}{m} \\\\v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{800 \times 0.13^2}{12} } \\\\v = 1.062 \ m/s[/tex]

Thus, the speed of the block at the displacement from the equilibrium position is 1.062 m/s.

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Answer:

The speed of the block at the displacement from the equilibrium position is 1.1266 m/s.

Step-by-step explanation:

Solution :

Using principle of conservation of mechanical energy formula to find the speed of the block :

[tex]\begin{gathered} \longrightarrow{\pmb{\sf{\frac{1}{2} mv^2 = \frac{1}{2}kx^2}}}\end{gathered}[/tex]

»» m = Mass of the block, »» k = Spring constant,»» x = Extension of the spring»» F = Applied parallel force

As per given data information in the question we have :

✧ Mass of the block = 12 kg✧ Spring constant = 0.8 kN/m✧ Extension of the spring = 0.13 m✧ Applied parallel force = 80 N

Substituting all the given values in the formula to find the speed of the block

[tex]\longrightarrow{\sf{ \: \:\dfrac{1}{2} mv^2 = \dfrac{1}{2}kx^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: \cancel{\dfrac{1}{2}}mv^2 = \cancel{\dfrac{1}{2}}kx^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: mv^2 = kx^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: v^2 = \dfrac{kx^2}{m}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: \sqrt{{v}^{2} } = \sqrt{ \dfrac{kx^2}{m}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: v = \sqrt{ \dfrac{kx^2}{m}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: v = \sqrt{ \dfrac{800 \times {0.13}^{2}}{12}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: v = \sqrt{ \dfrac{800 \times {0.13} \times 0.13}{12}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: v = \sqrt{ \dfrac{800 \times 0.0169}{12}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: v = \sqrt{ \dfrac{13.52}{12}}}}[/tex]

[tex]{\star{\underline{\boxed{\rm{\red{ v \approx 1.1266 \: m/s}}}}}}[/tex]

Hence, the speed of block is 1.1266 m/s.

[tex] \rule{300}{1.5}[/tex]

A 60.0 kg person jumps onto the floor from a height of 3.0m. Find
the KE of the jumper when she hits the ground.

Answers

Answer:

1800 J

Explanation:

GPE= mgh

60*3*10

=1800 J

Grain is pouring into a silo to be stored for later use. Due to the friction between pieces of grain as they rub against each other during the pouring process, one piece of grain picks up a charge of 6.0 E -10 C and another piece of grain picks up a charge of 2.3 E -15 C. What is the electric force between them if the pieces of grain are 2 cm apart?

Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits to receive full credit.

Answers

Answer:

3.1×10⁻¹¹ N is

Explanation:

is the answer

Imagine that there is a small rocky body caught by Earth’s gravity. Draw a comic-strip cartoon

to illustrate its journey as it travels through space toward Earth, enters Earth’s atmosphere, and

lands on Earth. Describe your illustration with narration or speech/thought bubbles. Include the

use of these key terms: atmosphere, meteor, meteoroid, meteorite.

Answers

To create this comic strip you can use a narration describing each step and illustrate each one with one image or drawing.

Creating a comic strip involves using images and short texts to explain a specific idea or phenomenon. In the case of the process for a meteor to enter Earth you can use the following ideas.

A meteoroid approaches the Earth at high speed and draw a meteor traveling near to different planets and approaching Earth.What is that? and draw the Earth wondering who or what is approaching.The meteoroid enters the atmosphere of the Earth and becomes a meteor and draw the rocky body burningThe rocky body crashes with the surface becoming a meteorite and draw the zone where the meteorite crashed.

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A 20 metric ton train moves toward the south at 50 m/s. At what speed must it travel to have four times its original momentum

Answers

Answer:

200 m/s

Explanation:

as momentum is a product of mass and speed, and mass is not changing, four times the speed will result in four times the momentum.

p = mv

4p = m(4v)

At 200m/s velocity of the train, the momentum of the train will be four times its original momentum. This is because the velocity is directly proportional to the momentum of an object.

What is Momentum?

Momentum is the tendency of an object to remain in motion. It is the product of the mass of the object and the velocity of the object. It is denoted by "p". Momentum is a vector quantity because it has both the magnitude and direction. The unit of Momentum is g.m/s.

The momentum can be calculated with the formula:

p = m × v

where, p = momentum of the object,

m = mass of the object,

v = velocity of the object.

The momentum is directly proportional to the mass and velocity of the object. Hence, to increase the momentum of the train by four times the mass or velocity of the train needs to be increased by four times.

The increase in the velocity of the train by four times will increase the momentum of the train.

Original Velocity of the train = 50 m/s

Increased Velocity of the train = 50 × 4 = 200 m/s

Increased new Momentum of the train = mass × new velocity

Increased Momentum = 20 metric ton × 200m/s

Increased Momentum = 4000 metric ton. m/s

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what type of data do you need to collect in a ADI​

Answers

full name.
address.
driving licence number.
email address.
telephone number.
ethnicity (optional)
website address.
convictions (motoring and non-motoring)
……………….

Can someone please help me? Please answer the question in the screenshot. Thank you! I need this answered!

Answers

Answer:

Explanation:

Photosynthesis is needed to store energy for the growth of the plant. It is like a factory that uses sunlight energy to convert 6CO₂ and 6H₂O into C₆H₁₂O₆ and 6O₂

Cell respiration is the process of breaking down the glucose and converting it into the other needed components of life. It's the engine that's fueled by the sugar of photosynthesis.

How much potential energy does an 8 kg flower pot hanging 5 m above the ground have

Answers

Answer:

Explanation:

Relative to ground level it has

PE = mgh = 8(10)(5) = 400 J

PE = mgh => 8x5x9.81 => PE = 392.4 N

A gazelle is grazing while standing in a fixed location. When it's startled by a predator, the gazelle accelerates uniformly for 16.8 s until it reaches a speed of 21.9 m/s. The gazelle then runs in a straight line at constant speed for an additional 16.4 s. Finally, it uniformly slows to a stop at a rate of 1.8 m/s/s. What is the total distance traveled by the gazelle in meters

Answers

Answer:

Explanation:

acceleration phase

average speed was 21.9/2 = 10.95 m/s

distance covered is 10.95 m/s(16.8 s) = 183.96 m

distance at top speed 21.9 m/s(16.4 s) = 359.16 m

distance while decelerating (0² - 21.9²)/(2(-1.8)) = 133.225 m

total = 183.96 + 359.16 + 133.225 = 676.345 = 676 m

What are the three major types of severe weather? Describe at least two characteristics of each type

Answers

Answer:

High winds, hail, excessive precipitation, and wildfires are forms and effects of severe weather, as are thunderstorms, downbursts, tornadoes, waterspouts, tropical cyclones, and extratropical cyclones. Regional and seasonal severe weather phenomena include blizzards (snowstorms), ice storms, and duststorms.

Explanation:High winds-  wind speeds as low as 23 knots (43 km/h) may lead to power outages when tree branches fall and disrupt power lines. Once wind exceed 135 knots (250 km/h) within strong tropical cyclones and tornadoes, homes  completely collapse,  and significant damage is done to larger buildings. Total disruption occurs once wind exceeds 175 knots (324 km/h)

Tornado- Typically look like a narrow funnel reaching from the clouds to the ground. Their wind speed goes from 65 to 250 miles per hour.

"An extreme weather condition in which we face the high speed wind in combination with heavy snow."

As for any blizzard has the normal wind speed of about 40 mph, and the visibility range reduces to less then 500 ft.

Answer: High winds, hail, excessive precipitation, and wildfires are forms and effects of severe weather, as are thunderstorms, downbursts, tornadoes, waterspouts, tropical cyclones, and extratropical cyclones. Regional and seasonal severe weather phenomena include blizzards (snowstorms), ice storms, and duststorms.

Explanation:

a plane crashes with a deceleration of 185 m/s. How many g’s is this?

Answers

Answer:

26 g's

Explanation:

Hope this helps~

Have a great day

Zero

An object of mass 6.36 kg is released from rest and drops 2.05 m to the floor. The collision is completely inelastic. How much kinetic energy is lost during the collision

Answers

Answer:

Essentially all of it

Explanation:

The potential energy was

PE = mgh = 6.36(9.81)(2.05) = 127.90278 = 128 J

ignoring air resistance, this PE converts to KE

With no rebound final velocity is zero, so Kinetic energy lost = 128 J

Compare the time it
takes the light to travel from your
teacher to your eye with the time
it takes sound to travel the same
distance.

Answers

Answer:

Light takes less time than sound.

Explanation:

Let's say, the teacher and the student are at a distance "d" from each other.

The medium around them would be air.

And,

The speed of light in air is approx. 3× 10 m/s

while, the speed of sound in air is approx. 330 m/s

We have a formula that establishes the relation between speed, distance and time.

[tex] \boxed{ \mathsf{speed = \frac{distance}{time} }}[/tex]

Our hunt for time — Speed in both the scenarios is known to us whereas the distance is same.

Sound

[tex] \mathsf{330 = \frac{d}{time_{s}} }[/tex]

[tex] \underline{\mathsf{time _{s} = \frac{d}{330} }}[/tex]

Light

[tex] \mathsf{3 \times {10}^{8} = \frac{d}{time _{l} } }[/tex]

[tex] \underline{ \mathsf{ time _{l} = \frac{d}{3 \times {10}^{8}} }}[/tex]

The best way of comparison is finding their ratio.

[tex] \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{ \frac{d}{330} }{ \frac{d}{3 \times {10}^{8} } } }[/tex]

simplifying the fraction

[tex] \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{d \times (3 \times {10}^{8} )}{330 \times d}}[/tex]

d gets canceled and we're left with the following expression

[tex] \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{ (3 \times10 \times {10}^{7} )}{330}}[/tex]

30, being a common factor in the numerator as well as denominator, gets canceled out. and in its place remains 1/ 11

(why?

=> 30÷330 = 1÷11)

[tex] \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{ 1\times {10}^{7} }{11}}[/tex]

taking time to the numerator on the other side.

[tex] \implies \mathsf{time_{s} = \frac{ 1\times {10}^{7} }{11}\times time_{l}}[/tex]

Therefore, we get timeₛ is approx. 10⁶ times the timeₗ.

That's a big difference, no wonder light's way much faster than sound.

As lesser the time taken to cover a distance, faster is the wave.

The sound takes about 874,000 times MORE time than the light takes.

Telescopes work by using optics with true or false

Answers

Answer: true

its making me add 20 word so here they are g g  g g g g g gg g t

Answer: its FALSE

Explanation:

Telescopes work by using optics with light is false, just took the quiz.

1. In Newton's cannonball experiment, if the velocity is larger than the orbital velocity the Cannon
ball will
1. stay in orbit
2. fall to the earth
3. escape the earth
4. none of the above

Answers

Answer:

escape the earth I think

In Newton's cannonball experiment, is the velocity is larger than the orbital velocity the Cannon ball will escape the Earth. Thus, the correct option is 3.

What was Newton's Cannonball experiment?

In this experiment, Newton visualizes a stone that is a cannonball which is being projected on top of a very high mountain. And, if there were no gravitational force or air resistance in that area, the body should follow a straight line path away from the Earth, in the direction in which it was projected.

If the cannonball is launched at a velocity that matches the orbital velocity of the planet, then it will not be able to be drawn in by gravitational force due to the Earth which results into moving away from the cannonball at the same speed at which the cannonball itself is falling.

If the velocity of the cannonball is larger than the orbital velocity than the ball will escape the Earth.

Therefore, the correct option is 3.

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halp me please i will give brainly

Answers

Answer: It should be the 3rd option down!

Explanation:

Answer: C

Explanation:

What are sound detectors?

Answers

Answer:

A sound detector comes in the shape of a rectangular board which comprises a microphone as well as a processing circuitry.

Answer:

Sound detection sensor works similarly to our Ears, having diaphragm which converts vibration into signals.

If a 35 kg box collides with a stationary 120 kg box with a force of 90 N, what must be true of the magnitude of the reaction force?

Answers

Newton's third law allows to find the result for the value of the reaction force during the collision is:

The reaction force is F = 90 N and is applied to the lighter body.

Newton's third law stable that the forces appear in pairs or ea that when two bodies interact, the interaction forces appear in the two bodies simultaneously, in general they are called action and reaction forces.

These furas are of the same magnitude, but in the opposite direction, each one applied to one of the bodies.

They indicate that the most lighter body collides with the one with the greatest mass with a force of F = 90 N. If we call this the action, the larger body must react with a force of equal magnitude on the lighter body.

Consequently, the reaction force is F = 90 N directed towards the lighter body.

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PLEASE ANSWER THIS, I'LL MARK YOU AS BRAINLIEST

Carlito was observing an an that crawled along a table. With a piece of chalk, he followed his path. He determined the ant’s displacements by using a ruler and protractor. The displacements were as follows: 2 cm east, 3.5 cm, 32° north of east and 2.4 cm, 22° west of north. Find the resultant vector using graphical method.​

Answers

Answer:

this is the answer

Explanation:

hope it's clear

pls Mark me as the brainliest pls

A 200-kg, 2.0-m-radius, merry-go-round in the shape of a flat, uniform, circular disk parallel to level ground is rotating at 1.2 cycles/second about an axis through its center of mass and perpendicular to the ground. A 50-kg boy jumps onto the edge of the merry-go round and lands at a fixed point. What is the angular velocity of the merry-go-round after the boy lands on it

Answers

Answer:

Explanation:

Conservation of angular momentum.

Disk            I = ½MR²

Point mass I = mR²  (boy)

Initial angular momentum

L₀ = Iω = ½MR²ω₀

Final angular momentum

L₁ = Iω = (½MR² + mR²)ω₁

as momentum is conserved, these are equal

(½MR² + mR²)ω₁ = ½MR²ω₀

                       ω₁ = ω₀(½MR²/ (½MR² + mR²))

                       ω₁ = ω₀(½M/ (½M + m))

                       ω₁ = 1.2(½(200)/ (½(200) + 50))

                       ω₁ = 1.2(⅔)

                      ω₁ = 0.8 cycles/second or 0.8(2π) = 1.6π rad/s

A child on ice skates is given a small push from behind by a parent. How are forces used to describe the resulting motion?(1 point)

Because of equal and opposite reactions, there will be a force opposing the push from the parent, and they will not move.
Because of equal and opposite reactions, there will be a force opposing the push from the parent, and they will not move.

There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.
There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.

There is a balanced force on the child, and the child’s motion will change direction or increase speed.
There is a balanced force on the child, and the child’s motion will change direction or increase speed.

Because of equal and opposite reactions, the child will move in the opposite direction to the force.

Answers

A child on ice skates is given a small push from behind by a parent. There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.

A child on ice skates is given a small push from behind by a parent. How are forces used to describe the resulting motion?

Because of equal and opposite reactions, there will be a force opposing the push from the parent, and they will not move. FALSE. According to Newton's third law of motion, if the parent applies force on the child, there will be a reaction applied by the child on the parent. These forces are applied to different objects so they will not cancel and the child will move. There is an unbalanced force on the child, and the child’s motion will change direction or increase speed. TRUE. The child will have an acceleration as a consequence of the unbalanced force. The acceleration will be responsible for the change in the direction or speed of the child. There is a balanced force on the child, and the child’s motion will change direction or increase speed. FALSE. If the forces were balanced, that is, there was no net force, the movement of the child would not change, as stated by Newton's first law of motion. Because of equal and opposite reactions, the child will move in the opposite direction to the force. FALSE. The child will move in the direction of the net force.

A child on ice skates is given a small push from behind by a parent. There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.

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The energy transfer diagram for a piece of equipment is shown. You are using a hand-cranked flashlight. One minute of cranking typically provides about 30 to 60 minutes of light.
Describe ALL of the energy transformations that are taking place in this process.
A) mechanical energy to heat energy Eliminate
B) electrical energy to light energy
C) mechanical energy to light energy
D) chemical energy to mechanical energy
E) mechanical energy to electrical energy

Answers

Answer:

n/a

Explanation:

No diagram found. I am willing to help

In a hand-cranked flashlight first, mechanical energy produced with the hand is converted into electrical energy then the electrical energy is converted into light energy, therefore the correct answers are the option B and option E.

What is mechanical energy?

The sum of all the energy in motion (total kinetic energy) and all the energy that is stored in the system (total potential energy) is known as mechanical energy.

The expression for total mechanical energy can be given as follows

ME= PE + KE

As given in the problem, the energy transfer diagram for a piece of equipment is shown. You are using a hand-cranked flashlight. One minute of cranking typically provides about 30 to 60 minutes of light.

The transformation that is taking place is the mechanical energy to electrical energy and then electrical energy to light energy.

Thus, the correct options are option are B and E.

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The block slides down an inclined friction-less track to a infinite hill that the block begins to climb and slow down. Is energy conserved or not?

Answers

Answer:

Energy is conserved.

Explanation:

Without friction, kinetic energy and gravity potential energy are always swapping back and forth.

The block slides down an inclined friction-less track to a infinite hill that the block begins to climb and slow down, in which the energy is conserved.

What is friction?

Friction refers to the force that prevents hard surface, fluid layers, as well as material elements from sliding against each other.

There are various kinds of friction: Dry friction is the force that opposes the relative lateral motion of two in contact solid surfaces.

It is thought to be caused by the interactions of tiny bumps on surfaces rubbing against one another.

The bumps on each surface bend and exert force on one another, making it difficult for the surfaces to slide over one another.

A block's speed increases while its acceleration remains constant as it slides down a frictionless incline. After being placed on a ramp inclined at an angle with the horizontal, a crate remains stationary.

Thus, the block slides beneath an inclined friction-less track to an unlimited hill, where it commences to climb as well as slow down, preserving energy.

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