Which fraction is represented by point A on the number line?
0
А
-0 -1
о
IT
os
O 1

Answer:

56

Step-by-step explanation:

7×8=56

Hope this helps! :)

Answer:

C

Step-by-step explanation:

The probability Ryan will pick a red marble on the first try is 33%. If he keeps this marble and picks another from the bag, that % will decrease.

The probability of picking a red marble on the first try is 33%, and if Ryan keeps this marble and picks another from the bag, the probability of picking a green marble decreases.

Thus, option (C) is correct.

In this case, there are 20 red marbles out of a total of 60 marbles.

So the probability of picking a red marble on the first try is 20/60, which simplifies to 1/3 or 33%.

If Ryan keeps the red marble and picks another one from the bag, the total number of marbles becomes 59.

The number of green marbles remains the same at 40.

Therefore, the probability of picking a green marble on the second try is 40/59, which is less than the probability of picking a green marble on the first try.

Hence, the probability of picking a red marble on the first try is 33%.

Thus, option (C) is correct.

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Step-by-step explanation:

answer is in the above photo

there are 29 boys total

Answer:

[tex]\frac{1}{8}[/tex]

Step-by-step explanation:

This question may be relatively tricky. Since no specific order is stated or implied, it does not matter whether the vendor chooses vanilla or strawberry first, as long as the vendor chooses both.

Therefore, for the first flavor the vendor can either choose vanilla or strawberry. There is a [tex]\frac{2}{4}=\frac{1}{2}[/tex] chance of this happening.

For the second flavor, the vendor must choose the one they didn't pick for the first flavor (either strawberry or vanilla). There is a [tex]\frac{1}{4}[/tex] chance they do so.

Therefore, there is a [tex]\frac{1}{2}\cdot \frac{1}{4}=\boxed{\frac{1}{8}}[/tex] chance that vanilla and strawberry are chosen.

9514 1404 393

Answer:

  7x^3y^4z^2

Step-by-step explanation:

  [tex]\displaystyle\sqrt[3]{343x^9y^12z^6}=\sqrt[3]{(7x^3y^4z^2)^3}=\boxed{7x^3y^4z^2}[/tex]

Answer:

[tex] \small \sf \leadsto \: 7x {}^{3}y {}^{6}z {}^{2} [/tex]

Step-by-step explanation:

[tex] \small \sf \leadsto \: \sqrt[3]{343 \: x {}^{9} \: y{}^{12} \: z {}^{6} }[/tex]

[tex] \small \sf \leadsto \: \sqrt[3]{7x {}^{3}y {}^{6}z {}^{2} } [/tex]

[tex] \small \sf \leadsto \: 7x {}^{3}y {}^{6}z {}^{2} [/tex]

Answer:

z is greater than 27/14

z € ( 37/14 ∞)

Answer:

Step-by-step explanation:

Given Question,

8b - 5a + 4

Given Values:

a = -4 and b = 7

Solution,

8(7) - 5(-4) + 4

= 56 + 20 + 4

= 80 (Ans)

Answer:

80

Step-by-step explanation:

8b - 5a + 4

a = - 4

b = 7

8(7) - 5(- 4) + 4

56 - (- 20) + 4

56 + 20 + 4

60 + 20

80

Answer:

Explain to me how you expect anyone to do this,

as you haven't provided the graph or the inequalities.

Step-by-step explanation:

Answer:

A.// He has the side lengths in the wrong place in the cosine ratio.

Step-by-step explanation:

Answer:

Your answer should be 647.51

Explanation : the price was 215.949 in December, 2009.

the price was 233.049 in December, 2013.

divide 233.049 by 235.949 and got 1.079185363.

multiply that by 600 and got 647.5112179.

The cost of the TV in 2010 is $647.5

Given that the complete information contains the Consumer Price Index values:

To find the CPI,

CPI= [tex]\frac{C_t}{C_0}[/tex]

Where C_t= cost of the market basket in the current period

C_0 = cost of the market basket in the base period

In December 2009, the price was 215. 949

In December 2013, the price was 233.049

Hence,

215. 949/233.049

= 1.079185363.

Then we would multiply by the base selling price

[tex]1.079185363 * 600 = 647.5112179.[/tex].

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Answer:

The best was to display a set of data with a wide range would be

a histogram.

Step-by-step explanation:

It's a graphical display of bars which will help you measure the central tendency.

Answer:

The correct answer is choice C.

Step-by-step explanation:

To find the area of the arrow, we must add together the areas of the rectangle and the triangle that make up the arrow.  The rectangle has a length of 10 inches and a width of 4 inches, and the triangle has a base of 8 inches and a height of 2 inches.  Using this information, we can plug numbers into the following formula:

Area of arrow = area of rectangle + area of triangle

Area of arrow = (10*4)+(1/2*8*2)

Area of arrow = 40 inches squared + 8 inches squared

Area of arrow = 48 inches squared

Therefore, the correct answer is option C, 48 square units (in this case, inches).

Hope this helps!

Answer:

[tex]Total = 4.8 * 10^{10}[/tex]

Step-by-step explanation:

Given

[tex]h = 1.2 * 10^8[/tex] --- households

[tex]g = 400[/tex] --- gallons

Required

The number of households

To do this, we simply multiply the average households by the gallons.

[tex]Total = g* h[/tex]

[tex]Total = 400 * 1.2 * 10^8[/tex]

[tex]Total = 480 * 10^8[/tex]

Rewrite as:

[tex]Total = 4.8 * 10^2 * 10^8[/tex]

[tex]Total = 4.8 * 10^{10}[/tex]

Answer:

It is D...........nnnnnnn

Answer:

x = 50 + 95 = 145

.........

Answer:

x = 145°

Step-by-step explanation:

Given,

Measure of the first angle = 50°

Measure of the second angle = 95°

We know,

Sum of 3 angles of a triangle is equals to 180°

∴ The third angle = 180° - (50+95)°

                             = 180° - 145°

                             = 35°

Again,

Straight angle = 180°

∴ x = 180° - 35°

      = 145°

∴x = 145°

Answer:

[tex]\frac{1}{cos^2x}[/tex]

Step-by-step explanation:

[tex]y'=\frac{(sinx)'*cosx-(cosx)'*sinx}{cos^2x}=\frac{1}{cos^2x}.[/tex]

Answer:

C. The probability of choosing a blue marble after a red marble has been removed is 0.6.

Step-by-step explanation:

P(B|A)

P(B|A) states the probability of event B happening, given that event A has happened.

In this question:

Event A: First marble is red.

Event B: Second marble is blue.

P(B|A) = 0.6

This means that the probability that the second marble is blue, considering that the first marble was red, is of 0.6, and thus, the correct answer is given by option C.

Answer:

measure of 4=360-(100+120)

=360-220

=140

so option C is the answer

Answer:

D. 80 is your answer

Step-by-step explanation:

If ∠6 is 120 and ∠5 is 100 we see a pattern forming for example, if we divide 120 by 6 we get 20 this is the same for if we divide 100 by 5, we get 20. Now all we need to do for ∠4 is to multiply it by 20 = 80, which is your answer!

Have a great day and I hope this helps!

Answer:

The third one down

Step-by-step explanation:

m, Slope is negative

b, Y-intercept is positive

Answer:

a = 2

Step-by-step explanation:

Use Pythagorean Theorem:

[tex]a^2+b^2=c^2\\a^2+2.1^2=2.9^2\\a^2+4.41=8.41\\a^2=4\\\sqrt{a^2}=\sqrt{4}\\a=2[/tex]

Therefore, a is 2 meters.

Answer:

We count across to 4 on y axis = 2

and count down from 4 to  -2 on x axis = -6

-6/2 = -3

m = -3

We know its minus because the reciprocal is the perpendicular imaginary line and if -3 is for the descending line then any ascending perpendicular line would show m = -1/-3 = 3

Step-by-step explanation:

Three consecutive integers that add up to 27 are 8, 9, and 10

Hope this helps =)

First represent your 3 consecutive integers as x, x + 1, and x + 2.

Since their sum is 27, our equation reads x + (x + 1) + (x + 2) = 27.

Now simplifying on the left side we get 3x + 3 = 27.

You should be able to easily solve for x and find that x = 8.

Make sure you list all your answers.

If x is 8, then x + 1 is 9 and x + 2 is 10.

There are two solutions for the triangle DEF: ∠ D₁ ≈ 68.3°, ∠ D₂ ≈ 111.7°.

In this question we have a triangle with two known sides and a known angle. By the law of sines we find the possible values of the angle D:

410/sin 120° = 440/sin D

Please notice that the sum of the internal angles of triangles equals 180°. Then,

sin D = (440/410) · sin 120°

sin D ≈ 0.929

There are two solutions for the triangle DEF: ∠ D₁ ≈ 68.3°, ∠ D₂ ≈ 111.7°.

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Answer:

The sum converges at: [tex]\frac{10}{3}[/tex]

Step-by-step explanation:

Given

[tex]\sum\limits^{\infty}_{n =2} \frac{8}{n^2 - 1}[/tex]

Express the denominator as difference of two squares

[tex]\sum\limits^{\infty}_{n =2} \frac{8}{(n - 1)(n+1)}[/tex]

Express 8 as 4 * 2

[tex]\sum\limits^{\infty}_{n =2} \frac{4 * 2}{(n - 1)(n+1)}[/tex]

Rewrite as:

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{2}{(n - 1)(n+1)}[/tex]

Express 2 as 1 + 1 + 0

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{1+1+0}{(n - 1)(n+1)}[/tex]

Express 0 as n - n

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{1+1+n - n}{(n - 1)(n+1)}[/tex]

Rewrite as:

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{(n + 1)-(n - 1)}{(n - 1)(n+1)}[/tex]

Split

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{(n + 1)}{(n - 1)(n+1)}-\frac{(n - 1)}{(n - 1)(n+1)}[/tex]

Cancel out like terms

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{1}{(n - 1)}-\frac{1}{(n+1)}[/tex]

In the above statement, we have:

[tex]a_3 + a_5 = 4[(\frac{1}{2} - \frac{1}{4}) + (\frac{1}{4} - \frac{1}{6})][/tex]

[tex]a_3 + a_5 = 4[(\frac{1}{2} - \frac{1}{6})][/tex]

Add [tex]a_7[/tex]

[tex]a_3 + a_5 + a_7= 4[(\frac{1}{2} - \frac{1}{6}) + (\frac{1}{7 - 1} - \frac{1}{7+1})][/tex]

[tex]a_3 + a_5 + a_7= 4[(\frac{1}{2} - \frac{1}{6}) + (\frac{1}{6} - \frac{1}{8})][/tex]

[tex]a_3 + a_5 + a_7= 4[(\frac{1}{2} - \frac{1}{8})][/tex]

Notice that the pattern follows:

[tex]a_3 + a_5 + a_7 + ...... + a_{k}= 4[(\frac{1}{2} - \frac{1}{k+1})][/tex]

The above represent the odd sums (say S1)

For the even sums, we have:

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{1}{(n - 1)}-\frac{1}{(n+1)}[/tex]

In the above statement, we have:

[tex]a_4 + a_6 = 4[(\frac{1}{3} - \frac{1}{5}) + (\frac{1}{5} - \frac{1}{7})][/tex]

[tex]a_4 + a_6 = 4[(\frac{1}{3} - \frac{1}{7})][/tex]

Add [tex]a_8[/tex] to both sides

[tex]a_4 + a_6 +a_8 = 4[(\frac{1}{3} - \frac{1}{7}) + \frac{1}{7} - \frac{1}{9}][/tex]

[tex]a_4 + a_6 +a_8 = 4[\frac{1}{3} - \frac{1}{9}][/tex]

Notice that the pattern follows:

[tex]a_4 + a_6 + a_8 + ...... + a_{k}= 4[(\frac{1}{3} - \frac{1}{k+1})][/tex]

The above represent the even sums (say S2)

The total sum (S) is:

[tex]S = S_1 + S_2[/tex]

[tex]S =4[(\frac{1}{2} - \frac{1}{k+1})] + 4[(\frac{1}{3} - \frac{1}{k+1})][/tex]

Remove all k terms

[tex]S =4[(\frac{1}{2}] + 4[(\frac{1}{3}][/tex]

Open bracket

[tex]S =\frac{4}{2} + \frac{4}{3}[/tex]

[tex]S =\frac{12 + 8}{6}[/tex]

[tex]S =\frac{20}{6}[/tex]

[tex]S =\frac{10}{3}[/tex]

The sum converges at: [tex]\frac{10}{3}[/tex]