Which is the CORRECT description of the sequence of energy transformations occurring in this system?

The magnitude and direction of the total momentum of the system is 6 kg m/s to the left.

The total momentum of the system if the two carts have the same speed is 0 kgm/s

The magnitude and direction of the total momentum of the system is calculated as follows;

Pi = m1u1 + m2u2

where;

Pi = (1.5 x 6) - (1.5 x 10)

Pi = - 6 kg m/s

The total momentum of the system if the two carts have the same speed is calculated as follows;

Pf = (1.5 x 6) - (1.5 x 6)

Pf = 0 kg m/s

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The statement that is most likely true about the locations is that location A is farther from the equator than location B ( A )

The average temperature throughout the year is higher in location B then that of location A. The temperature is typically warmer near the equator and is typically cooler near the polar regions.

But some factors such as elevation, precipitation and ocean currents might affect the climate pattern. This change in temperature between equator and polar regions is due to the fact that equatorial regions receive more light and energy from the Sun than the polar regions.

Therefore, the statement that is most likely true about the locations is that location A is farther from the equator than location B ( A )

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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: v = 13 \:\: m/s[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

By third equation of motion :

[tex]\qquad \tt \rightarrow \: {v}^{2} = {u}^{2} + 2as[/tex]

[tex]\qquad \tt \rightarrow \: {v}^{2} = (3) {}^{2} + 2(2)(40) [/tex]

[tex]\qquad \tt \rightarrow \: {v}^{2} = 9 + 160[/tex]

[tex]\qquad \tt \rightarrow \: {v}^{2} = 169[/tex]

[tex]\qquad \tt \rightarrow \: v = 169[/tex]

[tex]\qquad \tt \rightarrow \: v = 13[/tex]

so, speed of the car after that time is : 13 m/s

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

Acceleration (a) = 0.5 mp[tex]s^{2}[/tex]

Explanation:

Given,

Object starts from rest, hence the initial velocity of the object is said to be 0

Velocity in the next 8 seconds is 4.0 m/s

u = 0 m/s

v = 4 m/s

t = 8 secs

We know,

a = (v-u)/t

=> a = (4-0)/8

=> a = 4/8 = 0.5 m/[tex]s^{2}[/tex]

Answer:

Time interval

Explanation:

The amount of time it takes to wake up is a time interval because it has a start and stop time. For example, if someone's alarm goes off at 7AM and they fully wake up at 7:15AM, then the period from 7AM-7:15AM is a time interval.

Answer:

65 meters for 5 seconds at a time

Explanation:

The most extreme sum of weight that can hang from the conclusion of the pole is 8.66 N.

The most extreme sum of weight that can hang from the conclusion of the bar is calculated as follows.

Apply the equation for pressure utilizing Newton's moment law of movement.

Newton's moment law of movement states that the constrain experienced by a question is specifically relative to the item of the mass and speeding up of the question.

T sinθ = W

Where T is maximum tension in cable

θ is angle of inclination of cable

W is weight of cable

10 sin (60) = W

8.66 N = W

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The force exerted on the post by the roller,

The equilibrium for bracket,

∑ [tex]F_{y}[/tex] = 0

T sin 20° - 270 = 0

T = 789.43 N

[tex]T_{x}[/tex] = ( 789.43 ) cos 20°

[tex]T_{x}[/tex] = 741.82 N

[tex]T_{y}[/tex] = ( 789.43 ) sin 20°

[tex]T_{y}[/tex] = 270 N

The 270 N force and [tex]T_{y}[/tex] forms a couple

τ = ( 270 ) 0.25

τ =  67.5 N m Clockwise

∑ [tex]M_{B}[/tex] = 0

( 741.82 * 0.125 ) - 67.5 + [tex]F_{CD}[/tex] ( 0.2 ) = 0

[tex]F_{CD}[/tex] = - 126.138 N

∑ [tex]F_{y}[/tex] = 0

[tex]F_{AB}[/tex] - 126.138 - 741.82 = 0

[tex]F_{AB}[/tex] = 867.96 N

The direction of force [tex]F_{CD}[/tex] is towards left and the direction of force [tex]F_{AB}[/tex] is towards right. The force [tex]F_{CD}[/tex] is exerted by roller B and the force [tex]F_{AB}[/tex] is exerted by roller C. Rollers A and D exert no force. The force exerted by the rollers exert oppositely on the post. So the force exerted by roller C is 126.1 N and the force exerted by roller B is 867.96 N.

Therefore, the force exerted on the post by the roller,

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The ball will rise back to a height equal to the initial height multiplied by the amount of kinetic energy it had before it started to ascend again (1-fraction of energy lost).

All of the ball’s kinetic energy must be dissipated when it strikes the ground. The bounce increases with potential energy, kinetic energy, and kinetic energy alone, thus the more energy that returns to the ball and gives it more power to spring back into the air, the higher the bounce.

The height from which a ball is dropped, the material of the ball (and, if it is inflated, the pressure at which it is inflated), and the material of the surface from which the ball bounces determine the height to which it will rebound.

If you are measuring the height of the ball from its bottom to the ground, the radius of the ball doesn't actually matter.

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Friction comes in two flavors: kinetic and static. Static friction affects a system or an object at rest, whereas kinetic friction affects an object in motion.

Typically, the maximal static friction between the objects is greater than the kinetic friction. Consider attempting to move a large crate across a concrete floor. The crate might not budge no matter how much you push on it. In other words, the static friction reacts to your actions by increasing to match and move in the opposite direction of your push.

However, if you exert enough force, the crate eventually looks to slip and begin to move. The kinetic friction force is lower than the static friction force, making it simpler to maintain motion once it is underway.

You would have to push more harder to initiate and maintain motion if you added mass to the crate (by, say, stacking a box on top of it). On the other hand, if you greased the concrete, it would be simpler to start and maintain the box.

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The minimum speed you should drive over the cliff so that the car can cross the river is 15 m/s

we'll begin by obtainig the time taken for the car to cross the river. This can be obtained as follow:

h = ½gt²

20 = ½ × 9.8 × t²

20 = 4.9 × t²

Divide both side by 4.9

t² = 20 / 4.9

Take the square root of both side

t = √(20/ 4.9)

t = 2 s

Finally, we shall determine the minimum speed as follow:

s = ut

30 = u × 2

Divide both sides by 2

u = 30 / 2

u = 15 m/s

Thus, we can conclude that the minimum speed needed is 15 m/s

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The minimum speed should be 15 m/s to drive over the cliff so that the car will cross the river.

The speed of an item, which is a scalar quantity in everyday usage and kinematics, can be defined as the size of the change in position per unit of time or the size of the change in position over time for an object.

The given values in the question are :

Height of the cliff, h = 20 m

The acceleration due to gravity, g = 9.8 m/s².

Use the formula,

h = 1/2gt²

20 = 1/2(9.8)t²

20 = 4.9 t²

t = 2 seconds.

Now, calculate the minimum speed,

s = ut

30 = u × 2

u = 30/2

u = 15 m/s.

Hence, the minimum speed required by the car to cross the river is 15 m/s.

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A capacitor acts as a low-pass filter to increase damping and temporarily store energy, much like a spring-loaded shock absorber, to reduce vibrations when driving on washboard roads.

A battery with voltage v is connected to a chain of three capacitors in series each with a capacitance of , after a long time has passed each capacitor has a charge of q

Since there is only one channel for the charging current (iC) to take when capacitors are connected in series, the charging current (iC) going through all capacitors is the SAME.

Then, as iT = i1 = i2 = i3 etc., all capacitors connected in series have the same current flowing through them. As a result, regardless of capacitance, each capacitor will store the same quantity of electrical charge, Q, on its plates.

As we know,

Q = C*V

Applying Kirchhoff’s Voltage Law,

V = Qt/C1 + Qt/C2 + Qt/C3

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The force applied by the person is 2587.5N. The energy approach is by far and away the easiest. Earlier work equals potential energy (after).

Most issues involving forces and velocities can be solved using energy formulas like Ek = EP or W = Ep or W = Ek.

Always consider using an energy formula first; they frequently work and prevent the need for many steps to solve for one thing before moving on to another. It would take a while to find a solution if you approached it the way you did since you would have to tackle several problems as you went along. You must determine the initial takeoff speed using F = ma the way you did since you would have to tackle several problems as you went along. You must determine the initial takeoff speed using F = ma before utilizing V2f=V2i + 2ad then, given that Vf is zero, get Vi. You would then factor that into the same equation using that as your takeoff speed V2f = V2i + 2ad but this time it would be Vf. Vi would be 0, therefore the answer to the equation would be "a." The energy approach is by far and away the easiest.

Earlier work equals potential energy (after)

Fd = mghF = mgh/dF = (66)(9.81)(0.8)/0.2F= 2587.5N

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The simplest type of capacitor is the parallel plate capacitor. The capacitance value in Farads is fixed by the surface area of the conductive plates and the space between them, and it can be built using two metal or metallized foil plates placed parallel to one another at a distance.

Chloroprene is polymerized to create the family of synthetic rubbers known as neoprene. Good chemical stability and flexibility are displayed by neoprene over a broad temperature range.

A parallel-plate capacitor's capacitance is calculated by multiplying the dielectric constant by the permittivity of free space, the area of the plates, and the distance between them.

The generalised formula for a parallel plate capacitor's capacitance is given as C = ε(A/d), where stands for the absolute permittivity of the material being utilised as the dielectric. The value of the dielectric constant, commonly referred to as the "permittivity of open space," is 8.854 x 10-12 Farads per metre.

Therefore, Capacitance = ε x (area of plates / thickness of rubber)

                                        = 8.854 x 10^-12 *(1700 / 0.022)

                                        = 68.4173 farads

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The homogeneity of Einstein’s mass-energy relation  E = mc² can be proved by maxwell’s equation of electromagnetism.

According to maxwell’s equation of electromagnetism, light travels at a speed (c) of 3 x [tex]10^8[/tex] m/s.

The momentum(p) of electromagnetic waves is proportional to the energy(E).

So, we can write it as

p = E / c                       -(i)

By cross multiplication

E = pc                          -(ii)

As we know

From newton’s second law, momentum (p) is the product of mass (m) and velocity (v)

p = mv                          -(iii)

since light travels with a speed (c) of 3 x 10^8 m/s

p = mc                         -(iv)

From the equations (ii) and (iv)

E / c = mc

Hence,

E = mc²

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Average force that her hands exert on the ball while catching basketball whose mass is 600g = 29N

Given

clock t=0.1 s

ball mass m=0.6 kilogram

The previous distance traveled (measured in meters) was 1.2.

Net Force Exerted = 29N

Total Force used:

F= △P/△t

F= m△u/△t

F= m√2gd/△t

F= 0.6.√2.9.8.1.2/0.1

F= 0.6.4.849/0.1

F= 2.90/0.1

Force = 29N

What does force mean?

Power is an effect that can physically change the movement of an object. When an object with mass changes speed, it can be accelerated by a force. B. When leaving a stationary state. The obvious way to describe force is pushing or pulling. Force is a vector quantity because it has both magnitude and direction. It is calculated using Newton SI units (N). Force is represented by the letter F (formerly P).

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The question was incomplete. Check below the full question.

Your friend is catching a falling basketball after it has passed through the basket. Her hands move straight down while catching the ball. It takes about 0.10 s for the player to lower her hands to stop the ball. Assume the mass of the ball is 0.60 kg, and that the ball has fallen a vertical distance of 1.2 m before reaching the player's hand. Determine the average force that her hands exert on the ball while catching it.

The total energy of the roller coaster car at the top of the track is 392,000 J.

The total energy of the system at the base of the rollercoaster track is 392,000 J.

The velocity of the car at a height 30 m above the base is 25.53 m/s.

The velocity of the car at the base of the roller coaster track is 40.4 m/s.

The total energy of the roller coaster car at the top of the track is calculated as follows;

P.E = mgh

where;

P.E = (500 kg) x (9.8 m/s²) x (80 m)

P.E = 392,000 J

Based on the law of conservation of energy, the total energy of the rollercoaster at the top of the track is the same as that at the bottom of the track.

Thus, total energy of the system at the base of the rollercoaster track = 392,000 J.

The velocity of the car at a height 30 m above the base is calculated as follows;

v² = u² + 2gh

v² = (8)²  +  2(9.8)(30)

v² = 652

v = √652

v = 25.53 m/s

The velocity of the car at the base of the roller coaster track is calculated as follows;

v² = u² + 2gh

v² = (8)²  +  2(9.8)(80)

v² = 1632

v = √1632

v = 40.4 m/s

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The electromagnetic (EM) spectrum is the set of all EM radiation types. Electromagnetic radiation includes, for instance, radio waves from a radio station and visible light from a lightbulb in your home. Energy that flows and spreads out as it does is called radiation.

The electromagnetic spectrum is the set of frequencies of electromagnetic radiation and the related photon energies and wavelengths.

The seven regions of the electromagnetic spectrum are often arranged with wavelength decreasing and energy and frequency increasing.

are a few of the common names for these energy forms.

Electromagnetic waves have a wide range of useful, everyday applications, including WiFi, cooking, kitchen appliances, eyesight, medical imaging, and cancer treatment.

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Answer:

1.A

2.A

3.A

4.A

5.C

6.B

Explanation:

that's

The gravitational force between them will change by a factor 1/9.

We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses objects. The magnitude of gravitational force can be determined as

F = G.m1.m2 / R²

where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.

From the question above, we know that

R2 = 3R1

By substituting the following parameters, we get

F2/F1 = G.m1.m2 / R2² / G.m1.m2 / R1²

F2/F1 = G.m1.m2 / (3R1)² / G.m1.m2 / R1²

F2/F1 = 1/9

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v ^2f-v^2i= 2a  Replace the known values,

0-16^2=2 (-4.2)S, S= 256/8.4, S= 30.4m. The maximum distance a snowboarder could travel on a 25o slope was 30.4 meters.

The snowboarder travels a distance of H=50 meters on the hill. The hill slopes at a 15 degree slant. snowboarder's horizontal distance traveled after passing a slope, S=10m Crossing a horizontal distance, there is a 25-degree rising slope.

The snowboarder's initial speed at location A is u = 0 m/s. Let v be the representation of the final velocity. G = 10m/s2 is the acceleration caused by gravity. The snowboarder's acceleration at the incline is = a = 10 sin (15 degree)

The snowboarder moved 10 meters horizontally after reaching the bottom of the hill. Before she reaches the steep slope, as depicted in the illustration, her pace is unchanged. Now, at the top of the hill, where she could go the farthest, S

Vf = 0 m/sec would be the final speed.

To calculate the furthest she could go, write the equation of motion,

v ^2f-v^2i= 2a  Replace the known values,

0-16^2=2 (-4.2)S, S= 256/8.4, S= 30.4m. The maximum distance a snowboarder could travel on a 25o slope was 30.4 meters.

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Answer:

C

Explanation:

Average velocity =  (10+30) / 2 = 20 m/s

80 m / 20 m/s = 4 seconds

It would take a truck to increase its speed from 10 m/s to 30 m/s in 2.0 s. Option D is the correct answer.

To determine how long it would take for the truck to increase its speed from 10 m/s to 30 m/s, we can use the equations of motion. Option D is the correct answer.

The first equation we will use is: v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Given:

Initial velocity, u = 10 m/s

Final velocity, v = 30 m/s

We need to find the time, t. Since the truck is accelerating uniformly, we can assume a constant acceleration. Next, we use another equation of motion: v² = u² + 2as, where s is the distance traveled.

Given:

Distance, s = 80 m

Initial velocity, u = 10 m/s

Final velocity, v = 30 m/s

Rearranging the equation, we get: s = (v² - u²) ÷ (2a)

Substituting the given values, we have: 80 = (30² - 10²) ÷ (2a)

Simplifying the equation, we find:

80 = (900 - 100) / (2a)

80 = 800 / (2a)

2a = 800 / 80

a = 10 m/s²

Now, we can go back to the first equation: v = u + at

Substituting the known values: 30 = 10 + 10t

Simplifying, we find: 10t = 20

t = 2 seconds

Therefore, it would take the truck 2.0 seconds to increase its speed from 10 m/s to 30 m/s.

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Materials required for the experiment of limiting force borne by string:-

Steps of procedure for for the experiment of limiting force borne by string:-

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Since both rats get the tranquilizer and there is no control condition, the experiment is not accurate.

An experiment would be carried out by a scientist in search of data and knowledge. We are aware that in an experiment, the impact of the independent variable on the dependent variable must be determined.

In this instance, the dosage of the medication is the independent variable, and the duration of sleep time for the pet rats is the dependent variable.

Let's notice that a controlled setting is required for every experiment.

We can observe that this experiment lacks a controlled environment, proving that it is not reliable.

A control setting should be introduced, and this experiment would need to be evaluated.

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John will take 0.6 min or 36 seconds more faster during uniform motion than before.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

s = v . t

where v is velocity, t is time and s is displacement.

From the question above, we know that

v1 = 350 m/min

v2 = 375 m/min

s = 3150 m

Find the initial time

s = v1 . t

3150 = 350 . t

t = 9 min

Find second time

s = v2 . t

3150 = 375 .t

t = 8.4 min

John will take 0.6 min or 36 seconds more faster than before

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According to the given statement the initial temperature of the water is 54.171°C

The SI unit of temperature is Kelvin, which is represented by the letter K. Kelvin is part of the International System of Units.

Mass of water

= 2290 g

= 2.29 Kg

Heat absorbed (Q) = 5.11 x 10⁵ J = 511 KJ

Water is boiling, final temperature of water

= 100°C = 373 K

When water is getting warmed, the amount of heat absorbed to increase the temperature of water by 1°C is given by heat capacity.

Specific heat capacity of water

= 4.87 KJ/Kg

Mathematically,

Q = mCΔT

where

Q = Heat absorbed

m= mass of the water

C = specific heat capacity of water

ΔT = Temperature change

= Final temperature - initial temperature

Putting numerical values

511 = 2.29 x 4.87 x ΔT

⇒ΔT = 45.829

⇒Final temperature - Initial temperature = 45.829°C

⇒100°C - Initial temperature = 45.829°C

⇒ Initial temperature = 100 - 45.829 = 54.171°C

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Answer:

50    sixty watt bulbs max

Explanation:

Watts = amps * volts

               30 a * 100 v / 60 w/bulb = 50 bulbs

This given statement about uniform circular motion and distance is proved.

The distance between two points is how long it is.

Okay, so the first three components of this issue include more physics and math. Um Ds equals R. D. Data was thus provided for section A. We have to track down S. Therefore, we just integrate both sides equally using R. D. data. Our data are provided. Therefore, the upon integration over our data is only R 0 Santa + 12 beta zeta squared for part B. We'll make sure S = V T. We combine these two by using the above equation as an equal. In order to allow it to reach its roots once positive, we can see that this is Justin's equation for data. The other drawback, of course, is

Standard units are 247 times zero, therefore switch to the nature radio at a negative six. Additionally, we are given the time, which is 74 minutes, or 4440 seconds. Thus, clogging everything. Injecting R 0 and data mm hmm into the formula for data. Therefore, we enter better Data. V also appears. Everything is therefore known. We may confidently conclude that the data is, hmm, 1.337 x 10-5 bright. or 2.13 x 10 to 4 revolutions, in terms of turns. Okay. We simply re-insert the figures for beta and tr zero V into the earlier formulae for omega and alpha in the last section of the problem. You can take pleasure in utilizing math, even by hand, or perhaps he

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The sound has greater intensity if the string is attached to the guitar body as the sound power is spread over a larger area at the listener's position.  

A sound wave is  basically  delivered by a vibrating object. As a guitar string vibrates, it sets encompassing air particles into vibrational movement. The frequency at which these air particles vibrate is rise to the frequency of vibration of the guitar string. The back and forward vibrations of the surrounding air particles make a pressure wave that voyages outward from its source. This pressure wave comprises compressions and rarefactions. The compressions are regions of high pressure, where the air particles are compressed into a little region of space. The rarefactions are districts of low pressure, where the air particles are spread and separated. This substituting design of compressions and rarefactions is known as a sound wave. A guitar string vibrating by itself does not deliver a really loud sound. The string itself disturbs exceptionally small air since its little surface zone makes exceptionally small contact with encompassing air particles. In any case, in case the guitar string is joined to a bigger object, such as a wooden sound box, at that point more air is aggravated. The guitar string forces the sound box to start vibrating at the same frequency as the string. The sound box in turn powers surrounding air particles into vibrational movement. Since of the huge surface range of the sound box, more discuss particles are set into vibrational movement. This produces a more capability of hearing a sound.

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