Which is the graph of x-y=1?

Parent function is general modulus function

Now

x is increased by +3 so change in x axis and vertex.

The vertex shifted 3 units leftwards .

Means compression factor is 2

Both graphs attached

Answer:

Step-by-step explanation:

Translations

For [tex]a > 0[/tex]

[tex]f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}[/tex]

[tex]y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis by a factor of}\:a[/tex]

Parent function:  [tex]f(x) = |x|[/tex]

Translated 3 units left:  [tex]f(x+3)=|x+3|[/tex]

Stretched parallel to the y-axis by a factor of 2:  [tex]2f(x+3)=2|x+3|[/tex]

Therefore, the function has been:

Attachments

Green graph - parent function   [tex]f(x) = |x|[/tex]

Red graph - Translated 3 units left   [tex]f(x)=|x+3|[/tex]

Blue graph - Stretched   [tex]f(x)=2|x+3|[/tex]

Answer:

Right Angle.

Step-by-step explanation:

A right angle (90°; /2 radians) exists between a tangent to a circle and the radius across the point of contact. To put it another way, the tangent and radius are perpendicular to one another.

Answer:

I would day right angle. It sounds like the best answer

Step-by-step explanation:

The points (2, -2) and (0, -1) lies on the inverse of the function y = (-x -2)/2 if the function is y = -2x - 2 option (C) and (E) are correct.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

In the graph, a linear equation is represented.

We can find the function of linear equation from the two points:

(-1, 0) and (0, -2)

x/-1  + y/-2  = 1

2x  + y  = -2

y = -2x - 2 ..(1)

From the equation, first take subject as x and find the value of x

2x = -y -2

x = (-y -2)/2

Replacing x→y and y →x

y = (-x -2)/2

The inverse of a function:

y = (-x -2)/2

Points (2, -2) and  (0, -1) lies on the inverse of the function(refer to attached picture)

Thus, the points (2, -2) and (0, -1) lies on the inverse of the function y = (-x -2)/2 if the function is y = -2x - 2 option (C) and (E) are correct.

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now, we don't have a compounding period above, so we're assuming the amount is compounding annually.

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill &\pounds 8112\\ P=\textit{original amount deposited}\\ r=rate\to 30\%\to \frac{30}{100}\dotfill &0.30\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}[/tex]

[tex]8112=P\left(1+\frac{0.30}{1}\right)^{1\cdot 2}\implies 8112=P(1.3)^2\implies \cfrac{8112}{1.3^2}=P\implies 4800=P[/tex]

Answer:

Below in bold.

Step-by-step explanation:

The mean is 55 therefore, by definition:

On average the students are 55 inches tall.

The median is the middle ( or the average of 2 middle) value when the data is arranged in order.

So as the media is 46 inches about half are more than 46 ins tall.

Answer:

100

Step-by-step explanation:

-100 is always going to be 100 units away from 0 no mater what

Answer:

p - 14.5 = 53

Step-by-step explanation:

The original price is p.

The discounted price is $14.50 less than p, or $14.50 subtracted from p. The discounted price is p - 14.5.

The discounted price is $53

Equation:

p - 14.5 = 53

Answer:

the person earned one summer = $3,600

We have to show the amount in fraction that Paula spent during the following semester,

they spent for tuition = $2,500 =  × 100

=0.6944 × 100

=  69.44%  

they spent for rent = $650 =   × 100

= 0.1806 × 100

= 18.06%

they spent for food = $430 =   × 100

=0.1194 × 100

= 11.94%

they Spent in tuition, rent and food = 2,500 + 650 + 430 = $3580

Now they spent in miscellaneous expenses = 3600 - 3580 = $20.00   × 100

= 0.056 × 100

= 0.56%

The pool must have been the same depth at the start of the interval as it was at the end of the interval, option second is correct.

Finding out how much something changes over time is what the average rate of change is all about.

We have Lionel computed the average rate of change in the depth of a pool over a two-week interval to be zero.

As we know that the average rate of change can be calculated using:

= (Last quantity - starting quantity)/Time interval

The average rate of change, on the other hand, does not account for intermediate values, therefore you can't draw any conclusions about them.

In the given problem:

The average rate of change in depth = (Last quantity - starting quantity)/2

0= (Last quantity - starting quantity)

Final depth = Initial depth

Thus, the pool must have been the same depth at the start of the interval as it was at the end of the interval, option second is correct.

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The rate of change is $27 per month if the change in y values is 54 and change in x values is 2.

It is defined as the change in values of a dependent variable with respect to the independent variables.

From the data given in the table, we can find the rate of change per month:

To find the rate of change:

= change in y/ change in x

= (138-84)/(4-2)

= 54/2

= 27 per month

Thus, the rate of change is $27 per month if the change in y values is 54 and change in x values is 2.

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answer : 13

steps:

its asking

subtract 8 from 60 which is 56

subtract 10 from 75 which is 65

then its asking

find the largest number that can divide 56 and 65

that number is

13

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The letter A represents where the amount of $158.29 should be written.

The letter D represents where the amount of $250 should be written.

This refers to the automated machine that is used to handle cash transactions and also for making calculations.

Hence, we can see that from the complete information, Ivan has a cash register where he records the amount he spends on groceries which is $158.29, and also the transaction of sending $250 to his savings account.

However, in the cash register, Ivan uses the letter A to show where the amount of $158.29 should be written and the letter D represents where the amount of $250 should be written.

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Answer:

A and D

Edge 2022

Answer:

False

Step-by-step explanation:

the area (A) of a rectangle is calculated as

A = length × breadth

  = (x + 5)(x - 5) ← expand factors using FOIL

  = x² - 5x + 5x - 25

 = x² - 25 ≠ x² - x - 15

Answer:

[tex]\boxed{\sf x = -4 \pm 2\sqrt{6} }[/tex]

Explanation:

3x² + 24x - 24 = 0

factor the coefficient

3(x² + 8x) -24 = 0

Halve the second term and square it

3(x + 4)² -24 -3(4)² = 0

simplify the answer

3(x + 4)² -72 = 0

add 72 on both sides

3(x + 4)² = 72

divide both sides by 3

(x + 4)² = 24

square root both sides

x + 4 = ±√24

subtract both sides by 4

x = -4 ± 2√6

Answer:

[tex]x=-4\pm2\sqrt{6}[/tex]

Step-by-step explanation:

Completing the square for quadratic in the form  [tex]ax^2+bx+c=0[/tex]

Given equation:

[tex]3x^2+24x-24=0[/tex]

Factor out 3:

[tex]\implies 3(x^2+8x-8)=0[/tex]

Divide both sides by 3:

[tex]\implies x^2+8x-8=0[/tex]

Add 8 to both sides:

[tex]\implies x^2+8x=8[/tex]

[tex]\textsf{Add }\: \left(\dfrac{b}{2}\right)^2\: \textsf{ to both sides}:[/tex]

[tex]\implies x^2+8x+\left(\dfrac{8}{2}\right)^2=8+\left(\dfrac{8}{2}\right)^2[/tex]

[tex]\implies x^2+8x+16=8+16[/tex]

[tex]\implies x^2+8x+16=24[/tex]

Factor the left side:

[tex]\implies (x+4)^2=24[/tex]

Square root both sides:

[tex]\implies x+4=\pm2\sqrt{6}[/tex]

Subtract 4 from both sides:

[tex]\implies x=-4\pm2\sqrt{6}[/tex]

Answer:

Question 1: ∠V = 40° and MD = 17.62 and VD = 27.41 (work below)

Question 2: b. 60

Question 3: b. sinC

Step-by-step explanation:

Answer:A=hbb

2

Step-by-step explanation:

If the sides of a triangle are given along with an included angle, the area of the triangle can be calculated with the formula, Area = (ab × sin C)/2, where 'a' and 'b' are the two given sides and C is the included angle. This is also known as the "side angle side " method.

Answer: Horizontal means going through something like mainly through the middle, and verticle are the posts going up and down through the fence. All you have to do is combine them in figure 2 and slot them down in the boxes. Hope this helps <3

Step-by-step explanation:

Answer:

Here is the ans...hope it helps

Answer:

0.525 is the number.

X = Y/P%

X = 0.84/160%

p = 160%/100 = 1.6

X = 0.84/1.6

X = 0.525

Because there are no red marbles on the bag, we will see that the probability is zero.

We want to find the probability that the marble will be red. Viktoria knows that her bag has no red marbles, then it is impossible to get a red marble.

The probability of an impossible event is 0 (suppose that there are 10 marbles in the bag, we have a probability of 0 out of 10 of getting a red marble).

Then we can write the probability as P = 0.

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Answer: 0 enjoy

Step-by-step explanation:

Answer:

   46. (3) 29

   47. (1) y = -4x + 3

   48. (3) 3

   49. (3) -1/2

   50. (4) 25x - 75

Step-by-step explanation:

Question 46

Question 47

Question 48

Question 49

Question 50

Answer:

35.9 degrees

Step-by-step explanation:

the arctan of 0.724 is 35.9 degrees

Answer:

  (a)  452 m²

Step-by-step explanation:

The lateral area of a cylinder is given by the formula ...

  A = 2πrh . . . . radius r, height h

__

The given tube has an outside (or inside) area of ...

  A = 2(3.14)(5 m)(14.4 m) = (3.14)(144 m²) ≈ 452 m²

Each curved surface of the tube has an area of about 452 m².

Answer:

25

Step-by-step explanation:

12 x 100 = 1200

1200 / 48 = 25

Answer:

1.89 inch²

Explanation:

[tex]\sf \boxed{\sf \dfrac{pq}{2} } \ \ \ where \ p \ and \ q \ are \ the \ diagonals \ of \ the \ kite[/tex]

Here given:

Find the Area:

[tex]\rightarrow \sf \dfrac{2.7 \ x \ 1.4}{2} \ = \ 1.89 \ in^2[/tex]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

[tex]y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{3}}x-4\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]

so we're really looking for the equation of a line whose slope is 1/3 and passes through (-3 , 2)

[tex](\stackrel{x_1}{-3}~,~\stackrel{y_1}{2})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-3)}) \\\\\\ y-2=\cfrac{1}{3}(x+3)\implies y-2=\cfrac{1}{3}x+1\implies y=\cfrac{1}{3}x+3[/tex]

Step-by-step explanation:

here's the answer.......