Answer:
Newton's second law
Explanation:
An electrician reads a resistance of 65 ohms and when energize the circuit runs 1.77 amps. what voltage to the system run on?
Answer:
115.05 Volts
Explanation:
We can use Ohm's Law!
V=IR
V= 1.77 * 65
V=115.05 Volts
what are the applications of triangle law of forces
Answer:
The triangle law of forces can also be stated as. if a body is in equilibrium under the action of three forces acting at a point, then the three forces can be completely represented by the three sides of a triangle taken in order. A body might be subjected to further than one force at a similar time.
Explanation:
Hope it's help
I need help with this question!
Answer:
Explanation:
Conservation of momentum
In the x direction
2(15) + 2(-10) = 2(-5) + 2(vBfx)
vBfx = 10 m/s
In the y direction
2(30) + 2(5) = 2(20) + 2(vBfy)
vBfy = 15 m/s
vBf = 10i + 15j
KEi = ½(2)(15² + 30²) + ½(2)(-10² + 5²) = 1250 J
KEf = ½(2)(-5² + 20²) + ½(2)(10² + 15²) = 750 J
KEf - KEi = 750 - 1250 = -500 J
The range of a Cannon ball fired horizontally from a laboratory table equals to 8/ 3 times the height of the table . what is the direction of the velocity of the projectile as it strikes the ground?
A,450 from the horizontal
B,600 from the horizontal
C,530 from the horizontal
D,370 from the horizontal
Theprojectile launch allows to find the correct answer for the question about the direction of the ball when it hits the ground is:
D) θ = 37º measured clockwise from the x-axis.
projectile launch is an application of kinematics where there is no acceleration on the horizontal axis and the acceleration on the vertical axis is the gravity acceleration.
The horizontal distance traveled until it reaches the ground is
x = v₀ₓ t
The height of the bullet is
y = y₀ + [tex]v_o_y[/tex] t - ½ g t²
The initial vertical velocity is zero and when it reaches the ground its height is zero.
0 = y₀ - ½ g t²
t = [tex]\sqrt{\frac{2y_o}{g} }[/tex]
We substitute
[tex]x = v_{ox} \ \sqrt{\frac{2y_o}{g} }[/tex]
They indicate that the distance is:
x = [tex]\frac{8}{3} \ y_o[/tex]
We substitute
[tex]\frac{8}{3} y_o = v_{ox} \sqrt{\frac{2y_o}{g} }[/tex]
[tex]v_{ox} = \frac{8}{3} \sqrt{\frac{y_o g}{2} }[/tex]
The vertical speed when reaching the ground is:
[tex]v_y = v_{oy} - g t \\v_y = - g t \\v_y = - g \sqrt{\frac{2y_o}{g} }[/tex]
Let's use trigonometry for the direction at the point of hitting the ground.
tan θ = [tex]\frac{v_y}{v_x}[/tex]
θ = tan⁻¹ ( [tex]- \frac{3}{8} \ \frac{\sqrt{2y_o/g}}{\sqrt{y_o g /2} }[/tex] )
θ = tan⁻¹ ( [tex]tan ^{-1} (- \frac{3}{8} \sqrt{4} )= tan^{-1 } \ (- \frac{3}{4} )[/tex]
θ = -36.9º
The negative sign indicates that the angle is clockwise from the x-axis.
In conclusion, using the projectile launch we can find the correct answer for the question about the direction of the bullet when it hits the ground is:
D) θ = 37º measured clockwise from the x-axis.
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Use words in the box to complete the diagram, and the definitions below it. Some words will be used
more than once and some words may not be used at all
Hertz
period
metros
dip
seconds
peak
wavelength trough
crest
frequency
amplitudo
oscillation equilibrium line
- the top of a wave
the bottom of a wave
the level if the wave flattened out
a repeated action back and forth or up and down
the number of waves that pass every second (measured in
the time it takes for one complete wave to pass (measured in
Answer:
There ya go
Explanation:
The correct words to fill the given blanks would be as follows:
- Peak
- Trough
- Equilibrium Line
- Oscillation
- Frequency, Hertz
- Period, seconds
The "peak" is denoted as the highest or maximum point that the wave attains while 'Trough' is characterized as the base of the wave. The 'equilibrium line' is characterized as the extent to which the wave flattens or compresses.Oscillation is defined as the process in which an object moves in the "back and forth motion."Frequency is the amount of occurrences that waves travel in a second which is denoted in the terms of Hertz.Lastly, period is the duration required by wave to accomplish one motion is denoted in terms of seconds.Amplitude is the breadth or magnitude of the waves.Learn more about "Oscillation" here:
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According to Hebrews 11, what did Abraham believe God would do if Isaac was slain as a sacrifice?
Answer:
That he would be happy,for he had ordered him to be sacrificed
what is the speed of a boy moving around a circular park of radius 6m if he goes around the park in 20s
Answer:
1.884 meters per second
Explanation:
s = d/t
d = C = 2πr = 2π(6) = 37.68 m
t = 20 s
s = (37.68 m)/(20 s)
s = 1.884 m/s
The speed of the boy is 1.88 m/s while he is moving around a circular park of radius 6m and taking time 20 seconds.
What is speed?Speed can be defined as a measurement of how quickly the distance an object traveled changes with time. Speed is a scalar quantity as it has magnitude but no direction as a unit of measurement.
An object that moves quickly and with high speed, traveling a lot of ground in a lesser time.
Given, the radius of the circular park, r = 6m,
The time taken to cover one round of the park, t = 20 s
The total distance traveled by the boy is equal to the circumference of the circular park, so
Circumference of park, C = d = 2πr = 2× 3.14 × 6 =37.68 m
The speed of the boy, S = d/t
S = 37.68 /20
S = 1.88 m/s
Therefore, the speed of the boy is equal to 1.88 m/s.
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An object falls through the air, gaining speed as it falls. A student claims th
new energy, and so it breaks the law of conservation of energy. Which stat
why the student is incorrect? (1 point)
Energy can be created without breaking the law of conservation
Energy is converted from other forms, not created.
O Equal and opposite amounts of other energy are also created.
O Speed is not related to energy in any way.
Answer:
Energy is converted from other forms, not created
Explanation:
The ball has a decrease in potential energy which allows the kinetic energy, and therefore speed, to increase
a bicycle uniformly from rest at time t the velocity of the bicycle is v at what time will the bicycle have a velocity of 4v
Here
Acceleration and initial velocities are constant.According to first equation of kinematics.
[tex]\\ \sf\longmapsto v=u+at[/tex]
[tex]\\ \sf\longmapsto v=0+at[/tex]
[tex]\\ \sf\longmapsto v=at[/tex]
[tex]\\ \sf\longmapsto v\propto t[/tex]
Time was t at velocity vTime will be 4t at velocity 4vA model shows a machine that works using electric fields. What would this machine need for the electrical field to function properly
Two students run a race. Student A is 50 kg and runs at 5 m/s. Student B is 30 kg and runs at 2 m/s. Which
student has more Kinetic energy?
Answer:
Explanation:
KEA = ½(50)5² = 625 J
KEB = ½(30)2² = 60 J
Student A has more kinetic energy.
More than ten times more kinetic energy due to both larger mass and higher velocity.
Define faith in your own words.
Answer:
Faith, to me is almost like hope but for faith you need to believe. Some people associate the word faith with religion. But that's not it. Faith is really just a stronger term than believing someone. Like you can believe in someone but not have faith in that same person. You can have faith in someone but to do that you have to believe and trust them.
Explanation:
Wtz the answer to this question? I need to get it right
Answer: Next time you create a question, add an image or PDF. Because I do not know the question. So, may you please create a new question?
What net force acting on a 6 kg car produces an acceleration of 6 m/s2?
Explanation:
Mass (m) = 6 kgAcceleration (a) = 6 m/s²Force (F) = ?We know that,
• F = ma→ F = (6 × 6) N
→ F = 36 N
Therefore, the net force is 36N.
True or False. What makes faith genuine is its object.
Answer:true
Explanation:
Do you think the rider in the above figure is really in danger? What If people below were removed?
The rider will be in danger when the people below are removed, because they initially helped to maintain equilibrium.
A system subjected to different forces is said to be in equilibrium when all the forces applied to the system are equal.
For a system subject to two opposite forces, the following exists;
If the upward force and the downward forces are equal, the system will remain in equilibrium positionIf the upward or downward force is greater than the other, the system will move in the direction of the greater force.Thus, we can conclude that the rider will be in danger when the people below are removed, because they initially helped to maintain equilibrium. Once these people are removed, the rider tends to move at a greater speed and possibly fall from the initial position.
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an electron moves in a circular path in a region os space filled with a uniform magnetic field B= 0.4 T. to double the radius of the electron’s path, the magnitude of the magnetic field must become:
a. 0.8 T
b. 0.2 T
c. 0.1 T
d. 0.3 T
e. zero
Answer:
[tex]0.2\; {\rm T}[/tex], assuming that the speed of the electron stays the same.
Explanation:
Let [tex]v[/tex] denote the speed of this electron. Let [tex]q[/tex] denote the electric charge on this electron. Let [tex]m[/tex] denote the mass of this electron.
Since the path of this electron is a circle (not a helix,) this path would be in a plane normal to the magnetic field.
Let [tex]B[/tex] denote the strength of this magnetic field. The size of the magnetic force on this electron would be:
[tex]F = q\, v\, B[/tex].
Assuming that there is no other force on this electron. The net force on this electron would be [tex]F = q\, v\, B[/tex]. By Newton's Second Law of motion, the acceleration of this electron would be:
[tex]\begin{aligned}a &= \frac{F}{m} \\ &= \frac{q\, v\, B}{m}\end{aligned}[/tex].
On the other hand, since this electron is in a circular motion with a constant speed:
[tex]\begin{aligned} a = \frac{v^{2}}{r} \end{aligned}[/tex].
Combine the two equations to obtain a relationship between [tex]r[/tex] (radius of the path of the electron) and [tex]B[/tex] (strength of the magnetic field:)
[tex]\begin{aligned}\frac{q\, v\, B}{m} = \frac{v^{2}}{r}\end{aligned}[/tex].
Simplify to obtain:
[tex]\begin{aligned}r &= \frac{m\, v^{2}}{q\, v\, B} \\ &= \frac{m\, v}{q\, B} \\ &= \left(\frac{m\, v}{q}\right)\, \frac{1}{B}\end{aligned}[/tex].
In other words, if the speed [tex]v[/tex] of this electron stays the same, the radius [tex]r[/tex] of the path of this electron would be inversely proportional to the strength [tex]B[/tex] of the magnetic field. Doubling the radius of this path would require halving the strength of the magnetic field (to [tex]0.2\; {\rm T}[/tex].)
Please answer the question in the picture
A ball rolling down a hill with a speed of 8 m/s has 139 J of kinetic energy. What is it's mass in kg?
Explanation:
Velocity of ball (v) = 8 m/sKinetic Energy (K.E) = 139 JMass (m) = ?We know that,
• K.E = ½mv²→ 139 = ½ × m × (8)²
→ 139 = ½ × m × 64
→ 139 = 1 × m × 32
→ 139 ÷ 32 = m
→ 4.34 kg = m
Therefore, mass in kg is 4.34 kg.
Zoe is setting up a track for a toy car. The track has a ramp that is 32° above horizontal. If Zoe wants the car to travel as a projectile for 1.0 seconds, how fast does the toy car need to be moving as it leaves the ramp?
4.9 m/s
1.0 m/s
9.2 m/s
7.4 m/s m
Answer:
Explanation:
Not enough information.
IF we ASSUME she wants the car to be at LAUNCH LEVEL after 1 second of flight.
THEN
The highest point will have zero vertical velocity and will have taken ½ second to get there. This means that the initial vertical velocity was
v = gt
vy₀ = 9.8(0.5)
vy₀ = 4.9 m/s
vsinθ = vy₀
v = vy₀/sinθ
v = 4.9/sin32
v = 9.2466...
v = 9.2 m/s
A 25.0kg boy is sliding on a frictionless frozen lake at 5.00m/s to the north when he is struck by a 1.00kg
snowball moving at 15.0m/s from the west. If the snowball sticks to him, how fast, and in what direction,
does the boy move after the collision?
The final velocity of the boy after the collision with snowball is 4.84 m/s at 18.4⁰ north-east
The given parameters;
Mass of the boy, m₁ = 25 kgSpeed of the boy, u₁ = 5 m/sMass of the snowball, m₂ = 1.0 kgSpeed of the snow ball, u₂ = 15 m/sThe initial momentum of the boy is calculated as follows;
[tex]P_y = m_1 u_1\\\\P_y = 25 \times 5\\\\P_y = 125 \ kgm/s \ \ north[/tex]
The initial momentum of the snowball is calculated as follows;
[tex]P_x = m_2 u_2\\\\P_x = 1 \times 15 \ \\\\P_x = 15 \ kgm/s \ \ west[/tex]
The resultant momentum of the boy and the snowball after collision is calculate as follows;
[tex]P_f = \sqrt{P_y^2 + P_x^2} \\\\P_f = \sqrt{125^2 + 15^2} \\\\P_f = 125 .9 \ kgm/s[/tex]
The final velocity of the system boy-snowball system is calculated as;
[tex]v_f(m_1 + m_2)= P_f\\\\v_f = \frac{P_f}{m_1 + m_2} \\\\v_f = \frac{125.9}{25 + 1} \\\\v_f = 4.84 \ m/s[/tex]
The direction of the boy after the collision is calculated as follows;
[tex]\theta = tan^{-1}(\frac{v_y}{v_x} )\\\\\theta = tan^{-1} (\frac{5}{15} )\\\\\theta = 18.4 \ ^0[/tex]
Thus, the final velocity of the boy after the collision with snowball is 4.84 m/s at 18.4⁰ north-east
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Select the correct answer.
What is the force that can cause two pieces of iron to attract each other?
A.
gravitational force
B.
magnetic force
C.
elastic force
D.
electrostatic force
Answer:
A. gravitational force always true.
B, C and D could be true under the correct conditions
1. A 1.30 kg ball strikes a wall with a velocity of -10.5 m/s. The ball bounces off with a velocity of 6.50 m/s. If the ball is in contact with the wall for 0.0210 seconds, what is the force exerted
on the ball by the wall?
O 1050 N
22.1 N
0 402 N
0 651 N
CAN SOMEONE PLS PLS ACTUALLY HELP ME
Let F be the magnitude of the force. The impulse of this force while the ball is in contact with the wall is
Ft = F (0.0210 s)
and this impulse is equal to the change in the ball's momentum,
m ∆v = (1.30 kg) (6.50 m/s - (-10.5 m/s)) = (1.30 kg) (17.0 m/s)
Solve for F :
F (0.0210 s) = (1.30 kg) (17.0 m/s)
F = (1.30 kg) (17.0 m/s) / (0.0210 s)
F ≈ 1050 N
7. Cellular respiration that uses oxygen is called
Answer:
Cellular respiration that uses oxygen is called Cellular respiration
Explanation:
Without oxygen, it's call fermentation.
A train travels at 40m/s. Calculate the time it takes to travel:
A) 30,000 m
B) 50 km
Answer:
a is 750 second
b is 2 hour
The time it takes for the train to travel 30,000m and 50,000m is 750seconds and 1250 seconds, respectively.
What is speed?The speed is the distance covered by an object at a particular time. Therefore, it is the ratio of distance and time.
[tex]\rm{Speed = \dfrac{Distance}{Time}[/tex]
A train travels at 40m/s. Now, the time it takes to travel the given distance is,
A.) 30,000m
Speed = Distance / Time
Time = Distance / Speed
Time = 30,000m / 40m/s
Time = 750 seconds
B.) 50 km
1 km = 1000m
50 km = 50 × 1000m = 50,000 m
Speed = Distance / Time
Time = Distance / Speed
Time = 50,000m / 40m/s
Time = 1250 seconds
Hence, the time it takes for the train to travel 30,000m and 50,000m is 750seconds and 1250 seconds, respectively.
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state all kinds of errors
Answer:
Instrumental error
Environmental error
Observational error
Theoritical error
What can happen when untreated sewage water contaminates water?
Answer:
Health Effects ↯Life-threatening human pathogens carried by sewage include cholera, typhoid and dysentery. Other diseases resulting from sewage contamination of water include schistosomiasis, hepatitis A, intestinal nematode infections, and numerous others.
Explanation:
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____
What is an element?
1. A substance made of more than one type of atom.
2. A substance that is made of water.
3. A substance that is made of no atoms.
4. A substance made of only one type of atom.
Answer:
Hey Friend...
Explanation:
This is ur answer.....
4. A substance made of only one type of atom.Hope it helps!
Brainliest pls!
Follow me! :)
Answer:
4
Explanation:
element is a substance that cannot be broken down into any other substance which means every element is made up of its own type of atom
As a truck rounds a curve, a box in the bed of the truck slides to the side farthest from the center of the curve. This movement of the box is a result of
Answer:
inertia
Explanation:
the mass of the box will want to continue on its straight line motion.
As centripetal force on the wheel treads causes the truck to turn, frictional force between the box and truck bed is insufficient to keep the box turning at the same rate that the truck turns, so relative velocity occurs between box and bed until the centripetal force is increased by contact with the truck side wall farthest from the center of curvature.
Physical Science A 2021-2022
Why does increasing the number of trials increase confidence in the results of the experiment?
Answer:
Increasing the number of trials reduces the impact of any one imprecise measurement. … To increase the number of attempts, you can find an average result for the experiment, as well as find and discrepancies as human error if you perform an experiment several times.
Explanation:
hope it helps :)
Answer:
It is because the increase in the number of trials reduces the impact of any one imprecise measurement. Using an average value for data points provides a better representation of the true value.