The object with a mass of 2.3 kg that is the rock will have a weight of 22.5 N.
W = m * g
W = Weight
m = Mass
g = Acceleration due to gravity
g = 9.8 m / s²
For the book,
m = 1.1 kg
W = 1.1 * 9.8
W = 10.78 N
For the Box,
m = 4.5 kg
W = 4.5 * 9.8
W = 44.1 N
For the Rock,
m = 2.3 kg
W = 2.3 * 9.8
W = 22.5 N
Therefore, the object that has a weight of about 22.5 N is the rock
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I need help finding the solution
The potential energy of an object of mass m at a height h from the ground on the Earth, where the gravitational acceleration is g, is:
[tex]U=\text{mgh}[/tex]As we can see, the velocity of the object is not a variable that needs to be taken into account to find the potential energy,
Then, the answer is:
[tex]\text{Velocity of the object}[/tex]Every second, the Sun converts 4 million tons of matter to energy. How long will it take the Sun to reduce its mass by 1% (the mass of the Sun is 2×10^30kg)? Compare your answer with the lifetime of the Sun so far.
I need this as soon as possible thanks.
Answer:
That is human_scale thinking and understanding
Explanation..
If you are going to consider stars(sun's), then you have to thik on a more cosmological scale stars are prodigiously immense which means they can burn 4 million tons of their fuel per second and not even realize it.
Consider this_if the life of our sun is of the order of 8 billion years, then it takes two billion years to bum only a quit of its fuel.
The universe is a very large place and if you are going to understand it, you have to think large.
What is the mass of an object that needs a force of 5,500 N to accelerate it at a
rate of 5 m/s/s?
THE MASS OF AN OBJECT IS 1100
module 2 question 16
(a) Calculate the tension in a vertical strand of spiderweb if a spider of mass 7.00 ✕ 10-5 kg hangs motionless on it.
N
(b) Calculate the tension in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in Figure 4.13. The strand sags at an angle of 13.0° below the horizontal.
N
Compare this with the tension in the vertical strand (find their ratio).
(tension in horizontal strand / tension in vertical strand)
a ) The tension in a vertical strand = 68.6 * [tex]10^{-5}[/tex] N
b ) The tension in a horizontal strand = 149.13 * [tex]10^{-5}[/tex] N
c ) Tension in horizontal strand / Tension in vertical strand = 2.17
a ) The tension in a vertical strand,
m = 7 * [tex]10^{-5}[/tex] kg
g = 9.8 m / s²
Since the strand is vertical and the spider is motionless,
∑ [tex]F_{y}[/tex] = 0
T - mg = 0
T = 7 * [tex]10^{-5}[/tex] * 9.8
T = 68.6 * [tex]10^{-5}[/tex] N
b ) The tension in a horizontal strand,
θ = 13.0°
The strands left and right have same magnitude and makes the same angle with the horizontal. Resolving,
sin θ = [tex]T_{y}[/tex] / T
[tex]T_{y}[/tex] = T sin 13.0°
∑ [tex]F_{y}[/tex] = 0
[tex]T_{y}[/tex] + [tex]T_{y}[/tex] - mg = 0
T sin 13.0° + T sin 13.0° = 7 * [tex]10^{-5}[/tex] * 9.8
2 T sin 13.0° = 68.6 * [tex]10^{-5}[/tex]
T = 68.6 * [tex]10^{-5}[/tex] / 0.46
T = 149.13 * [tex]10^{-5}[/tex] N
c ) Ratio of strands,
Tension in horizontal strand / Tension in vertical strand = 149.13 * [tex]10^{-5}[/tex] / 68.6 * [tex]10^{-5}[/tex]
Tension in horizontal strand / Tension in vertical strand = 2.17
Therefore,
a ) The tension in a vertical strand = 68.6 * [tex]10^{-5}[/tex] N
b ) The tension in a horizontal strand = 149.13 * [tex]10^{-5}[/tex] N
c ) Tension in horizontal strand / Tension in vertical strand = 2.17
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Which of the following describes how deforestation impacts the climate in areas where trees once stood?The elimination of a protective covering causes the sun to dry out the ground.The lack of carbon in the atmosphere causes radical temperature fluctuations.The decrease in plants to absorb water causes a greater level of water precipitation.The change in covered areas causes winds to be stronger and colder weather results.
Take into accouint that the regions that suffer deforestation tend to generate soil erosion to eventually become non-productive land.
Then, from the given choices you have that deforestation impacts in the following way:
The elimination of a protective covering causes the sun to dry out the ground.
Problem 7(a) Two different heavy objects are dropped from the same height. State
a) the acceleration of free fall of each object.
b) State any assumptions made.
The acceleration of free fall of each object will be the same.
An assumption made is that both objects must be on Earth.
What is acceleration of free fall?
The acceleration of free fall of every object is the acceleration experienced by the freely falling object as a result of the effect of gravitation of earth alone.
Mathematically, the formula for acceleration of free fall of every object on earth is given as;
g = GM/R²
where;
G is universal gravitation constantM is mass of the objectR is radius of the objectg is acceleration due to gravityThe value of acceleration due to gravity on Earth is 9.8 m/s².
Since both objects are dropped from same height on Earth, they will experience equal acceleration of free fall.
The assumptions made are;
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A ball is thrown vertically upward with a speed of
25.0 m/s from a height of 2.0 m.
a. How high does the ball rise?
b. How long does it take to reach its highest point?
c. How long does the ball take to hit the ground
after it reaches its highest point?
d. What is the ball's velocity when it returns to
the level from which it started?
a.) the ball rises to a height of 31.88m
b.) It takes the ball 2.55 seconds to reach its highest point
c.) It takes the ball 2.55 seconds to hit the ground
d.) The ball's velocity is -24.99 m/s in the negative direction which is downwards.
What is velocity?Velocity is the directional speed of a object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.
From the given question, we have that
b.) At highest point velocity of the ball will become zero so v=0m/s.
So using equation
v = u + gt
0 = 25 - 9.8t
t = 25/9.8 s =2.551 s
Time taken by the ball to reach its highest point will be 2.551 seconds .
a.) The height the ball rises is given by
v²-u²=2gh
=> 0-(25.0)²=-2*9.8*h
=> 19.6h= (25.0)²
=> h= 31.88m.
c.) It will take the ball 2.55 seconds to hit the ground
after it reaches its highest point because it will take the ball same time for the ball to reach its highest point or fall to the ground.
d.) velocity = u - gt
V = 0 - 9.8 * 2.55
V= -24.99 m/s in the negative direction which is downwards.
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A group of students must design an egg-carrying device that will prevent a raw egg from breaking when it is dropped from a two-story
window The diagram shows one group's design. How does the parachute help to minimize the force on the egg upon impact with the
ground?
how do zou plan your day
Answer: i usually use the calendar on my phone to set my day or i make plans with other people.
The Italian greyhound jumps 0.85 m in the air to catch a frisbee. How much potential energy does the dog have at the height of its jump?
Answer:
U = 41.65 J
Explanation:
We have just to calculate it with the following expression of gravitational potential energy:
U = m*g*h
Where:
m: mass
g: gravity acceleration;
h: height.
So:
U = m * 9.8 * 0.85
U = 8.33 * m
Then, it is just putting the mass value of the dog in that equation to obtain the value of potential energy acquired by the dog when jumping.
The mass of this kind of dog is between 3.6kg - 5kg, so, the maximum value of the potential energy can be like this:
U = 5 * 9.8 * 0.85
U = 41.65 J
D-A6 kg cart moving at 2 m/s hits another car that has a mass of 3 kg. What is the velocity of the second car after impact?(Use the conservation of momentum equation)
The conservation of momentum states that the total intiial momentum is equal to the total final momentum. In this cae this will mean that:
[tex]p_{1i}+p_{2i}=p_{1f}+p_{2f}[/tex]pls help me with my question
In astronomy, luminosity is the power (amount of energy per unit of time) emitted in all directions by a celestial body. It is directly related to the absolute magnitude of the star. The luminosity of the Sun, L☉ is the classical unit used in astronomy to compare the luminosity of other stars. Its approximate value is:
[tex]L=3.827\times10^{26}W[/tex]From the options, the correct one is:
A. Sun
A gas is compressed at constant pressure of 0.8atm from 9litre to 2 litre in the process, 400J of a energy leves the gas by heat.
a. what is work done on the gas?
b, What is the change in its internal energy?
According to the give statement:
a)Work done on the gas is 567 J.
b)The change in its internal energy is 167J.
What is an example of internal energy?The temperature and condition of a substance are examples of internal energy. For instance, the internal energy of water is influenced by its temperature as well as whether it is in a solid, liquid, or gas state. Due to its condition, liquid water has greater stored energy than copper metal at the same temperatures.
Briefing:The work done on the gas is evaluated using formulas:
W = -p * ΔV
Only the large volumes which is signified by large data Substituting the known values we obtain
W= 0.8 * 1.01325 * 10⁵ Pa * -1 (-7) * 10⁻³ m³
W = 567 J
Change in Internal energy is given by
ΔU=W - Q
=567−400)
=167J
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module 2 question 7
An owl is carrying a mouse to the chicks in its nest. It is 4.00 m west and 12.0 m above the center of the 30 cm diameter nest and is flying east at 4.50 m/s at an angle 27° below the horizontal when it accidentally drops the mouse. Will it fall into the nest? Find out by solving for the horizontal position of the mouse (measured from the point of release) when it has fallen the 12.0 m.
m (from the point of release)
Answer:
the mouse will overshoot and will not land in the nest.
A Student Bends Her Knees 15 Cm And Jumps Up 80 Cm Off The Ground. Find The A.) The Velocity With Which The Student Leaves ground
The initial velocity of the student as he leaves the ground is 3.57 m/s.
What is the velocity of the student as he leaves the ground?The velocity of the student as he leaves the ground can be calculated using the following kinematic equation for upward motion.
v² = u² - 2gh
where;
v is the final velocity of the studentu is the initial velocity of the studenth is the maximum height jumped by the student = 80 cm - 15 cm = 65 cm = 0.65 mAt the maximum height, the final velocity of the student = 0
0 = u² - 2gh
u² = 2gh
u = √2gh
u = √(2 x 9.8 x 0.65)
u = 3.57 m/s
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A vehicle of mass 1,084 kg is traveling in the +y-direction along a straight, horizontal road at a speed of 18.2 m/s when the driver applies the brakes, stopping the car in a distance of 244 m. Find the y-component of the constant net force applied to the car to bring it to a stop.
[Note: Remember that vector components can be positive or negative.]
The y-component of the constant net force applied to the car to bring it to a stop is mathematically given as
F_y =666.38N
This is further explained below.
What is force?Generally, In the field of physics, an influence that may alter the motion of an object is referred to as a force.
An object having mass may experience a change in its velocity, often known as acceleration, when subjected to a force.
Intuitively, force may also be conceptualized as either a push or a pull. Because it may be measured in both magnitude and direction, a force is considered a vector quantity.
When considering coplanar force of a point or a body we tend to consider the x components and the y components of force as they come together to give the Net Force or the resultant for and directions of force.
But for this case we shall strictly consider the y company of force as it pertains to this body and its force independent of the x components force as regards to Resultant force
In conclusion,
v^2 =2 a s
[tex]a &=\frac{v^2}{25}=\frac{(18.4)^2}{2 \times 268} \\\\[/tex]
a =0.631ms^2
F_y =m a
F_y=1055* 0.631
F_y =666.38N
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Figure 3 shows a 40 kg crate that is being pushed with constant velocity at a distance 8.0 m along a 30° incline plane by the horizontal force of 500N. The coefficient of kinetic friction between the crate and the incline, µk is 0.42. Assuming the crate is moving upwards towards the right, calculate the work done by the applied force, the frictional force and the gravitational force and the net work done on the crate.
Based on the given figure, you have that the components of the forces on the direction of the incline are:
applied force:
Fa = 500N*cos(-30°) = 433.01N
friction force:
Fr = µk*N = µk*m*g*cos(30°) = (0.42)(40kg)(9.8 m/s^2)cos(30°) = 142.58N
gravitational force:
Fg = m*g*sin(30°) = (40kg)(9.8)sin(30°) = 196.0N
Next, consider that the work done by a force is equal to the product of the force and the distance at which the force is applied. In this case, such distance is 8m.
Then, you have:
Work done by the applied force:
WFa = (433.01N)(8.0m) = 3464.08 J
Work done by the friction force:
WFr = (142.58N)(8.0m) = 1140.64 J
Work done by the gravitational force:
WFg = (196.0N)(8.0m) = 1568.0 J
Finally, the net work, based on the direction of the forces, is:
Net work = WFa - WFr - WFg = 3464.08J - 1140.64J - 1568.0J = 755.44J
Hence, the net work is 755.44 J
Answer: Wfr = -1883.25 J
Explanation:
1) In the x direction (direction of motion of the crate):
Fcos(30^o) - f_fr - mgsin(30^o ) = 0 (because a_x = 0)
f_fr = Fcos(30^o ) - mgsin(30^o)
f_fr = (498)(√3/2) - (40)(9.81) (1/2) = 235.28 N
⇒ W_fr = f_fr.s.cos(180^o) = -(235.28)(8.0) = -1882.25 J (1)
2) In the y direction (perpendicular to the motion of the crate):
n - Fsin(30^o) - mgcos(30^o) = 0 (because a_y = 0)
⇒ n = Fsin(30^o) + mgcos(30^o) = (498)(1/2) + (40)(9.81)(√3/2) = 588.83 N
⇒ f_fr = μ_k.n = (0.40)(588.83) = 235.53 N
⇒ W_fr = f_fr.s.cos(180^o ) = -(235.53)(8.0) = -1884.24 J (2)
Average of calculations (1) & (2): W_fr = -1883.25 J
Why are the accelerations due to gravitational force on the moon and the Earth different? Do you think you could shield a gravitational field in a vacuum?
The difference in the acceleration due to gravity on the moon and the Earth are different due to the difference in their masses and radius.
Yes, can shield a gravitational field in a vacuum by coming in between the mass and gravitational source.
What is Newton's law of universal gravitation?
Newton's law of universal gravitation states that every two objects in the universe attracts each other with a force directly proportional to the product of the masses and inversely proportional to the distance between the two objects.
F = GmM/R²
where;
G is universal gravitation constantm and M are the massesR is the distance between the two objectsFrom Newton's second law of motion,
F = mg
where;
g is acceleration due to gravitymg = GmM/R²
g = GM/R²
Thus, the acceleration due to gravity on the moon and the Earth are different because of difference in their masses and radius.
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the angular velocity of a rotating rigid body is -4+j-2k.find the linear velocity if a point p(5,1,3) on the body relative to a point Q(3,4,2) on the axis of rotation
The linear velocity of a point p(5,1,3) on the body relative to a point Q(3,4,2) on the axis of rotation is 17.13 m/s.
What is linear velocity?
Linear velocity is defined as the rate of change of displacement with respect to time when the object moves along a straight path.
The relationship between linear velocity and angular velocity is given as;
v = ωr
where;
ω is angular speed of the objectr is the radius of the circular pathv is the linear speed of the objectThe magnitude of the radius is calculated as follows;
r = √[(5-3)² + (1-4)² + (3-2)²]
r = 3.74 m
The magnitude of the angular speed is calculated as;
ω = √[(-4)² + (1)² + (-2)²]
ω = 4.58 rad/s
The linear speed of the object is calculated as follows;
v = ωr
v = (4.58 rad/s) x (3.74 m)
v = 17.13 m/s
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procidure for tapping a blind hole
Answer:
HOW TO DO IT…
Use the correct cutting oil on the tap when cutting threads.
Turn the tap clockwise one-quarter to one-half turn, then turn back three-quarters of a turn to break the chip.
When tapping a blind hole, use the taps. in the order starting, plug, and then bottoming.
What kinematics equation would i use for this ? Btw one of those are the answers
Given that the time taken to reach the ground is t = 6 s
The final velocity is v = 0m/s
We have to find the height of the monument, h.
The initial velocity can be calculated by the formula
[tex]u=gt[/tex]Here, g is the acceleration is due to gravity whose value is 9.81 m/s^2
Substituting the values, the initial velocity will be
[tex]\begin{gathered} u=9.81\times6 \\ =58.86\text{ m/s} \end{gathered}[/tex]The formula to find height is
[tex]h=\frac{u^2}{2g}[/tex]Substituting the values, the height will be
[tex]\begin{gathered} h=\frac{(58.86)^2}{2\times9.81} \\ =176.58 \\ \approx177\text{ m} \end{gathered}[/tex]Thus, the correct option is 177 m.
Ms. Cast's husband calculates the height of their house as 10.0 meters. The actual height is 11.0
meters. What is the experimental (%) error?
Answer:
mrs.casts
Explanation:
she's married
A hot air balloon with a mass of 371 kg is flying 615 m above the ground. How much gravitational potential energy does the balloon have?
The formula for determining the gravitational potential energy of the balloon is expressed as
Energy = mgh
where
m is the mass of the ballon
g is the accelaration due to gravity and the value is 9.8m/s^2
h is the height of the balloon above the ground
From the information given,
m = 371
h = 615
Thus,
= 371 x 89.8 x615 = 22316017 NKJoulesJoules8298.651
Calculate the mass of the Sun using Venus.
Venus is 1.08 x 1011 meters from the Sun and has a period of 224.7 days.
Show your computations.
The mass of the Sun is 1.98 * 10³⁰ kg.
What is the mass of the Sun?The mass of the Sun is calculated from the data given about Venus as follows:
radius of Venus from the Sun = 1.08 x 10¹¹ meters
Period of rotation of Venus around the Sun, T = 224.7 days.
T in seconds = 224.7 * 24 * 3600 = 1.94 * 10⁷ s
Force of gravity = Centripetal force
GMm/r₂ = mv²/r
M = mass of Sun
m = mss of Venus
M = rv²/G
G = 6.67 * 10⁻¹¹ m³kg⁻¹s⁻²
But v = 2πr/T
v = 2 * 3.14 * 1.08 x 10¹¹ / 1.94 * 10⁷
v = 3.496 * 10⁴ m/s
Hence;
M = 1.08 x 10¹¹ * (3.496 * 10⁴)² / 6.67 * 10⁻¹¹
M = 1.98 * 10³⁰ kg
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plane, starting from rest, accelerates at a rate of a = 5 m/s2 for a distance of 250 m. At this distance, calculate the plane's FINAL VELOCITY to the nearest 1 m/s.
The final velocity of the plane at 250 m distance is 50 m/s.
Equation :To calculate the final velocity of plane we need to use the formula from equation of motion,
In equation of motion we will use the formula,
v² = u² + 2as
where,
v is final velocity
u is initial velocity
a is the acceleration of plane
s is the distance
In this given data are,
s = 250 m
a = 5 m/s²
u = 0 m/s ( as the initial of plane is resting )
v = ?
Now, since we know the values, putting them into the formula,
v² = ( 0 )² m/s + 2 x (5 m/s²) x 250 m
v² = 2 x (5 m/s²) x 250 m
v² = 2,500 m/s
v = √2,500 m/s
v = 50 m/s
Hence, the final velocity of the plane at 250 m is 50 m/s.
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What helped Northwest Coast tribes develop complex societies? Choose three correct answers.
having to travel to search for resources
being able to plant and harvest crops
having an abundant supply of fish
being able to save and store food
having a wealth of resources
The development of complex societies depends of the Northwest Coast tribes on;
having a wealth of resourceshaving an abundant supply of fishbeing able to plant and harvest cropsWhat are complex societies?The term society just has to do with people that are found to live around a give geographical area. This is the way the people tend to live along with the civilization that they may tend to have actually created over a long period of time as we can see.
Having said thus, the people of the are the people that there originally found around the west of which the original native Americans also formed a huge part of. These were the people that tend to be found around the Americas before the onset of modern civilization as we can se.
The factors that helped Northwest Coast tribes develop complex societies are found in the section above. These factors saw to the development of the region.
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A 227.1 g sample of water at 12.2°C is heated to steam at 115.6°C. How much heat was absorbed?
??? kcal
According to the given statement the heat absorbed is 43676.78 J .
How do you calculate heat absorbed?The water's specific heat and the formula Q= mcΔT are used to compute the amount of heat absorbed. At 100°C, water vaporizes into steam. Calculating the amount of heat absorbed requires multiplying the number of moles of water by the molar heat of vaporization.
Briefing:Mass, m = 227.1grams
To find how much heat is absorbed when 227.1 grams of steam is heated from 115.6°C to 12.2°C.
Heat absorbed is given by :
Q= mcΔT
c is specific heat of water
Put all the values, we get :
Q = 227.1 * 1.86 * (115.6 - 12.2)
Q = 43676.78 J
43676.78 J heat is absorbed.
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Hydraulic systems utilize Bernoulli’s principle. T. F.
its FALSE
The answer is true, that the hydraulic press utilizes Bernoulli's principle.
It can be derived from the Principle of conservation of energy.
What is Bernoulli's Principle?According to Bernoulli's principle, which governs fluid dynamics, a fluid's speed increases concurrently with a reduction in pressure or potential energy. The mathematical concept is named after Swiss mathematician Daniel Bernoulli, who first published it in his book Hydrodynamics in 1738.
The venturi tube is a real-world example of Bernoulli's Principle in action. The venturi tube has an air intake that constricts to a throat and an exit segment that widens as it moves backward. The entrance and outflow both have the same diameter.
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What is a 65 kg
k
g
rider's apparent weight as the ride is coming to rest?
The weight of the rider will remain the same that is 65 kg after the ride is finished because the weight does not depend on speed.
What is Weight?It gauges how much gravity is pulling on a body.
Weight being a force, the SI unit of weight is the Newton, which is also the same as the SI unit of force (N). When we look at how weight is expressed, we can see that it depends on both mass and the acceleration caused by gravity; while the mass may not change from one location to another, the acceleration caused by gravity does.
According to the question, the weight will remain same because weight depends on mass and gravity but not the speed. As per the definition of weight it is the product of mass and gravity, it means for different plants the weight will be different but for the same planet the weight will be the same everywhere.
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A parallel plate capacitor is connected to a battery that maintains a constant potential difference. How will the magnitude of the charge on the plates change if the separation between the plates is doubled?It will be cut in half.It will not change.It will double.It will quadruple.
A parallel plate capacitor is connected to a battery that maintains a constant potential difference.
As we know,
[tex]\begin{gathered} Q=CV \\ Q=\frac{A\epsilon_0V}{d} \end{gathered}[/tex]Here, Q is the charge which is inversely proportional to the separation between the plates.
[tex]Q\propto\frac{1}{d}[/tex]That means if the separation between the plates increases the magnitude of the charge on the plates decreases.
Thus, if the separation between the plates is doubled the magnitude of the charge will be cut in half.